message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 219 108k | cluster float64 11 11 | __index_level_0__ int64 438 217k |
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Provide a correct Python 3 solution for this coding contest problem.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55 | instruction | 0 | 15,864 | 11 | 31,728 |
"Correct Solution:
```
s=[int(input()) for i in range(10)]
S=0
for i in range(10):
S=S+s[i]
print(S)
``` | output | 1 | 15,864 | 11 | 31,729 |
Provide a correct Python 3 solution for this coding contest problem.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55 | instruction | 0 | 15,865 | 11 | 31,730 |
"Correct Solution:
```
s = 0
for i in range(10):s += int(input());
print(s)
``` | output | 1 | 15,865 | 11 | 31,731 |
Provide a correct Python 3 solution for this coding contest problem.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55 | instruction | 0 | 15,866 | 11 | 31,732 |
"Correct Solution:
```
total=0
for i in range(10) :
s=int(input())
total += s
print(total)
``` | output | 1 | 15,866 | 11 | 31,733 |
Provide a correct Python 3 solution for this coding contest problem.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55 | instruction | 0 | 15,867 | 11 | 31,734 |
"Correct Solution:
```
s=[]
for i in range(1,11):
s1=int(input())
s.append(s1)
print(sum(s))
``` | output | 1 | 15,867 | 11 | 31,735 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
a = [int(input()) for i in range(10)]
print(a[0]+a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9])
``` | instruction | 0 | 15,868 | 11 | 31,736 |
Yes | output | 1 | 15,868 | 11 | 31,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
if __name__ == '__main__':
result = 0
for i in range(10):
result += int(input())
print(result)
``` | instruction | 0 | 15,869 | 11 | 31,738 |
Yes | output | 1 | 15,869 | 11 | 31,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
sum=0
for i in range(10):
x=int(input())
sum+=x
print(sum)
``` | instruction | 0 | 15,870 | 11 | 31,740 |
Yes | output | 1 | 15,870 | 11 | 31,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
total = 0
for i in range( 0, 10 ): # 繰り返し処理の範囲始まり
s = int( input() )
total += s
# 繰り返し処理の範囲終わり
print( total )
``` | instruction | 0 | 15,871 | 11 | 31,742 |
Yes | output | 1 | 15,871 | 11 | 31,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
print(sum([int(input()) for i in range(10)])
``` | instruction | 0 | 15,872 | 11 | 31,744 |
No | output | 1 | 15,872 | 11 | 31,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UncheckedIOException;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args) {
SC sc = new SC(System.in);
int sum=0;
for(int i=0; i<10; i++) {
sum+=sc.nextInt();
}
pl(sum);
}
static class SC {
private BufferedReader reader = null;
private StringTokenizer tokenizer = null;
public SC(InputStream in) {
reader = new BufferedReader(new InputStreamReader(in));
}
public String next() {
if (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e) {
throw new UncheckedIOException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
public long nextLong() {
return Long.parseLong(next());
}
public double nextDouble() {
return Double.parseDouble(next());
}
public String nextLine() {
try {
return reader.readLine();
} catch (IOException e) {
throw new UncheckedIOException(e);
}
}
}
public static void pl(Object o) {
System.out.println(o);
}
public static void pl() {
System.out.println();
}
public static void p(Object o) {
System.out.print(o);
}
static int root(int a) {
int ketasu=0;
int tmp=a;
while(tmp>0) {
ketasu++;
tmp/=10;
}
int constant=(ketasu+1)/2; //よく使うので定数化
if(ketasu>=1) {
int[] suuji=new int[constant];
tmp=a;
for(int i=0; i<constant; i++) {
suuji[constant-1-i]=a%100;
a/=100;
}
int ans=0;
int kai=0;
int mae=0;
if(constant<=1) {
for(int i=10; i>=0; i--) {
if(suuji[0]>=i*i) {
return i;
}
}
}
else {
for(int i=0; i<constant; i++) {
mae+=kai*2;
for(int j=9; j>=0; j--) {
if((mae*10+j)*j<=suuji[i]) {
ans=ans*10+j;
mae*=10;
kai=j;
if(i+1<constant) {
suuji[i+1]+=(suuji[i]-(mae+j)*j)*100;
}
break;
}
}
}
}
return ans;
}
else {
return 0;
}
}
}
``` | instruction | 0 | 15,873 | 11 | 31,746 |
No | output | 1 | 15,873 | 11 | 31,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Welcome to PC Koshien, players. This year marks the 10th anniversary of Computer Koshien, but the number of questions and the total score will vary from year to year. Scores are set for each question according to the difficulty level. When the number of questions is 10 and the score of each question is given, create a program that outputs the total of them.
input
The input is given in the following format.
s1
s2
..
..
s10
The input consists of 10 lines, and the i line is given the integer si (0 ≤ si ≤ 100) representing the score of problem i.
output
Output the total score on one line.
Example
Input
1
2
3
4
5
6
7
8
9
10
Output
55
Submitted Solution:
```
sum = 0
for i in range(10):sum = int(input());
print(sum)
``` | instruction | 0 | 15,874 | 11 | 31,748 |
No | output | 1 | 15,874 | 11 | 31,749 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,320 | 11 | 32,640 |
Tags: greedy, math, probabilities
Correct Solution:
```
n = int(input())
l = [float(x) for x in input().split()]
assert len(l) == n
l.sort()
if l[-1] == 1: print("%11.10f"%1)
else:
sig = 0
prod = 1
while sig < 1 and len(l) > 0:
x = l.pop()
sig += x/(1-x)
prod *= (1-x)
print("%11.10f"%(sig*prod))
``` | output | 1 | 16,320 | 11 | 32,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,321 | 11 | 32,642 |
Tags: greedy, math, probabilities
Correct Solution:
```
"""
Codeforces Round 253 Div 1 Problem B
Author : chaotic_iak
Language: Python 3.3.4
"""
def read(mode=2):
# 0: String
# 1: List of strings
# 2: List of integers
inputs = input().strip()
if mode == 0:
return inputs
if mode == 1:
return inputs.split()
if mode == 2:
return [int(x) for x in inputs.split()]
if mode == 3:
return [float(x) for x in inputs.split()]
def write(s="\n"):
if isinstance(s, list): s = " ".join(map(str,s))
s = str(s)
print(s, end="")
################################################### SOLUTION
n, = read()
s = read(3)
s.sort(reverse=True)
s = [int(10**6 * i + 0.5) for i in s]
onewin = s[0]
alllose = 10**6-s[0]
ct = 1
while alllose > onewin and ct < n:
onewin = onewin * (10**6-s[ct]) + alllose * s[ct]
alllose *= (10**6-s[ct])
ct += 1
print(onewin / 10**(6*ct))
``` | output | 1 | 16,321 | 11 | 32,643 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,322 | 11 | 32,644 |
Tags: greedy, math, probabilities
Correct Solution:
```
n=int(input())
from itertools import combinations
a = sorted(list(map(float, input().split())), reverse=True)
#a=[0.01]*100
if max(a) == 1:
print(1)
quit()
n=len(a)
pre = [1]*100
pre[0] = 1 - a[0]
for i in range(1, n):
pre[i] = pre[i-1] * (1-a[i])
ans = 0
for i in range(1,n+1):
anss=0
for j in range(i):
anss = anss + pre[i-1] / (1-a[j]) * a[j]
ans = max(ans, anss)
print(ans)
``` | output | 1 | 16,322 | 11 | 32,645 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,323 | 11 | 32,646 |
Tags: greedy, math, probabilities
Correct Solution:
```
k, p = int(input()), list(map(float, input().split()))
p.sort(reverse = True)
if p[0] == 1: print(1)
else:
a = 1
b = v = 0
for i in p:
a *= 1 - i
b += i / (1 - i)
u = a * b
if v > u: break
v = u
print(v)
``` | output | 1 | 16,323 | 11 | 32,647 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,324 | 11 | 32,648 |
Tags: greedy, math, probabilities
Correct Solution:
```
input()
p = sorted(map(float, input().split(' ')))
m = max(p)
p = [(1 - i, i) for i in p]
def konv(a, b):
return a[0] * b[0], a[0] * b[1] + a[1] * b[0]
while len(p) > 1:
p.append(konv(p.pop(), p.pop()))
m = max(m, p[-1][1])
print(m)
``` | output | 1 | 16,324 | 11 | 32,649 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,325 | 11 | 32,650 |
Tags: greedy, math, probabilities
Correct Solution:
```
from sys import stdin,stdout
from collections import defaultdict,Counter
from bisect import bisect,bisect_left
import math
from itertools import permutations
#stdin = open('input.txt','r')
I = stdin.readline
n = int(I())
arr = [float(x) for x in I().split()]
arr.sort(reverse = True)
ma = arr[0]
#print(ma)
for i in range(1,n):
now = ma*(1-arr[i])
#print(now)
sec = 1
for j in range(i):
sec*=(1-arr[j])
# print(sec*arr[i],sec,arr[i])
now+=(arr[i]*sec)
#print(ma,now)
if(now>ma):
ma = now
else:
break
print(ma)
``` | output | 1 | 16,325 | 11 | 32,651 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,326 | 11 | 32,652 |
Tags: greedy, math, probabilities
Correct Solution:
```
# -*- coding: utf-8 -*-
import sys
f = sys.stdin
n = int(f.readline().strip())
p = [float(u) for u in f.readline().strip().split()]
p.sort(reverse=True)
#p.sort()
p0 = 1
p1 = 0
p2 = 0
for pi in p:
p0t, p1t = p0*(1-pi), p0*pi+p1*(1-pi)
#print(p1t)
if p1t > p1 :
p0, p1 = p0t, p1t
else:
break
#print(p, p0, p1, p1t)
print(p1)
``` | output | 1 | 16,326 | 11 | 32,653 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | instruction | 0 | 16,327 | 11 | 32,654 |
Tags: greedy, math, probabilities
Correct Solution:
```
n=int(input())
a=list(map(float,input().split()))
m=max(a)
if m>=0.5:
print(m)
elif len(a)==1:
print(a[0])
else:
a.sort()
b=[1-a[i] for i in range(len(a))]
m=0
for i in range(n):
sum=0
for k in range(n-i-1,n):
prod=1
for j in range(n-i-1,n):
if k!=j:
prod=prod*b[j]
else:
prod=prod*a[k]
sum=sum+prod
m=max(m,sum)
print(m)
``` | output | 1 | 16,327 | 11 | 32,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
#!/usr/bin/env python3
def main():
input()
ps = map(float, input().split())
ps = sorted(ps, reverse=True)
if ps[0] == 1:
print(1)
else:
p = 1 - ps[0]
s = ps[0] / (1 - ps[0])
for x in ps[1:]:
if s >= 1:
break
p *= (1 - x)
s += x / (1 - x)
print(p * s)
if __name__ == '__main__':
main()
``` | instruction | 0 | 16,328 | 11 | 32,656 |
Yes | output | 1 | 16,328 | 11 | 32,657 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
from functools import reduce
L0 = []
def getP():
return sum([reduce(lambda y, x: y*x, [(L0[j] if j == i else (1 - L0[j])) for j in range(len(L0))], 1) for i in range(len(L0))])
input()
L = [float(x) for x in input().split()]
#inp = open('input.txt')
#inp.readline()
#L = [float(x) for x in inp.readline().split()]
#inp.close()
L.sort(reverse=True)
if len(L) > 0 and L[0] == 1:
print(1)
else:
S = 0
for p in L:
if S < 1:
S += p/(1 - p)
L0.append(p)
else:
break
print(getP())
``` | instruction | 0 | 16,329 | 11 | 32,658 |
Yes | output | 1 | 16,329 | 11 | 32,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
n = input()
ans = tmp = 0.0
pd = 1.0
for i in reversed(sorted(map(float, input().split()))):
tmp = tmp * (1.0 - i) + pd * i
pd *= 1.0 - i
ans = max(ans, tmp)
print('%0.12f' % ans)
# Made By Mostafa_Khaled
``` | instruction | 0 | 16,330 | 11 | 32,660 |
Yes | output | 1 | 16,330 | 11 | 32,661 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
n=int(input())
l=list(map(float,input().split()))
l=sorted(l)
l=l[::-1]
ans=0
d=1
vze=0
for x in l :
vze=vze+x*(d-vze)
d*=(1-x)
ans=max(ans,vze)
print(ans)
``` | instruction | 0 | 16,331 | 11 | 32,662 |
Yes | output | 1 | 16,331 | 11 | 32,663 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
n = int(input())
numbers = [float(i) for i in input().split()]
complement = numbers[:]
for i in range(n):
complement[i] = 1-complement[i]
prod = []
for i in range(n):
temp = numbers[i]
for j in range(n):
if i != j:
temp *= complement[i]
prod.append(temp)
s = sum(prod)
if s > max(numbers):
print (s)
else:
print(max(numbers))
``` | instruction | 0 | 16,332 | 11 | 32,664 |
No | output | 1 | 16,332 | 11 | 32,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
from decimal import Decimal as fr
ans = 0
n = int(input())
a = []
for x in map(fr, input().split()):
ans = max(ans, x)
a.append(x)
ans2 = 0
for i in range(n):
cur = a[i]
for j in range(n):
if i != j:
cur *= 1 - a[j]
ans2 += cur
ans = max(ans, ans2)
print('{:.15f}'.format(ans))
``` | instruction | 0 | 16,333 | 11 | 32,666 |
No | output | 1 | 16,333 | 11 | 32,667 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
from decimal import Decimal
d=[Decimal('0.0000000000000000000000000')]*123
n=int(input())
a=[0]+[Decimal('0.00000000000000000000000000')+Decimal(x) for x in input().split()]
for i in range(1,n+1):
if a[i]<0.5:
d[i]=max(d[i-1],d[i-1]*(1-a[i])+(1-d[i-1])*a[i])
else:
d[i]=max(d[i-1],a[i])
print(d[n])
``` | instruction | 0 | 16,334 | 11 | 32,668 |
No | output | 1 | 16,334 | 11 | 32,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of Andrey's friends. The second line contains n real numbers pi (0.0 ≤ pi ≤ 1.0) — the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.
Examples
Input
4
0.1 0.2 0.3 0.8
Output
0.800000000000
Input
2
0.1 0.2
Output
0.260000000000
Note
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.
Submitted Solution:
```
from functools import reduce
def getP(L, ind):
return sum([reduce(lambda y, x: y*x, [(L[j] if j == i else (1 - L[j])) for j in range(len(L)) if j != ind], 1) for i in range(len(L)) if i != ind])
input()
L = [float(x) for x in input().split()]
p0 = getP(L, -1)
stp = False
while not stp:
for ind in range(len(L)):
p1 = getP(L, ind)
if p0 < p1:
L.pop(ind)
p0 = p1
break
else:
print(p0)
stp = True
``` | instruction | 0 | 16,335 | 11 | 32,670 |
No | output | 1 | 16,335 | 11 | 32,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sean is trying to save a large file to a USB flash drive. He has n USB flash drives with capacities equal to a1, a2, ..., an megabytes. The file size is equal to m megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input
The first line contains positive integer n (1 ≤ n ≤ 100) — the number of USB flash drives.
The second line contains positive integer m (1 ≤ m ≤ 105) — the size of Sean's file.
Each of the next n lines contains positive integer ai (1 ≤ ai ≤ 1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all ai is not less than m.
Output
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Examples
Input
3
5
2
1
3
Output
2
Input
3
6
2
3
2
Output
3
Input
2
5
5
10
Output
1
Note
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
Submitted Solution:
```
n = int(input())
size_file = int(input())
l = [0]*n
count = 0
for i in range(len(l)):
l[i] = int(input())
l.sort()
while size_file > 0:
size_file -= l[n-1-count]
count += 1
print(count)
``` | instruction | 0 | 16,416 | 11 | 32,832 |
Yes | output | 1 | 16,416 | 11 | 32,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sean is trying to save a large file to a USB flash drive. He has n USB flash drives with capacities equal to a1, a2, ..., an megabytes. The file size is equal to m megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input
The first line contains positive integer n (1 ≤ n ≤ 100) — the number of USB flash drives.
The second line contains positive integer m (1 ≤ m ≤ 105) — the size of Sean's file.
Each of the next n lines contains positive integer ai (1 ≤ ai ≤ 1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all ai is not less than m.
Output
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Examples
Input
3
5
2
1
3
Output
2
Input
3
6
2
3
2
Output
3
Input
2
5
5
10
Output
1
Note
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
Submitted Solution:
```
n = int(input())
m = int(input())
l = [int(input()) for _ in range(n)]
l.sort()
now = 0
cnt = 0
for i in l[::-1]:
if now<m:
now+=i
cnt+=1
print(cnt)
``` | instruction | 0 | 16,419 | 11 | 32,838 |
Yes | output | 1 | 16,419 | 11 | 32,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sean is trying to save a large file to a USB flash drive. He has n USB flash drives with capacities equal to a1, a2, ..., an megabytes. The file size is equal to m megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input
The first line contains positive integer n (1 ≤ n ≤ 100) — the number of USB flash drives.
The second line contains positive integer m (1 ≤ m ≤ 105) — the size of Sean's file.
Each of the next n lines contains positive integer ai (1 ≤ ai ≤ 1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all ai is not less than m.
Output
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Examples
Input
3
5
2
1
3
Output
2
Input
3
6
2
3
2
Output
3
Input
2
5
5
10
Output
1
Note
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
Submitted Solution:
```
n = int(input())
fsize = int(input())
p = []
sum, counter = 0, 0
for i in range (0, n):
p.append(int(input()))
p.sort()
for i in range (n-1, 0, -1):
sum += p[i]
counter += 1
if sum>=fsize:
print(counter)
exit()
``` | instruction | 0 | 16,421 | 11 | 32,842 |
No | output | 1 | 16,421 | 11 | 32,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sean is trying to save a large file to a USB flash drive. He has n USB flash drives with capacities equal to a1, a2, ..., an megabytes. The file size is equal to m megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input
The first line contains positive integer n (1 ≤ n ≤ 100) — the number of USB flash drives.
The second line contains positive integer m (1 ≤ m ≤ 105) — the size of Sean's file.
Each of the next n lines contains positive integer ai (1 ≤ ai ≤ 1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all ai is not less than m.
Output
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Examples
Input
3
5
2
1
3
Output
2
Input
3
6
2
3
2
Output
3
Input
2
5
5
10
Output
1
Note
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
Submitted Solution:
```
n=int(input())
m=int(input())
s =[]
for i in range(n):
s.append(int(input()))
s.sort()
count=0
if sum(s)>=m:
for i in (s[::-1]):
if m>=i and (m/i)>1:
count+=1
m-=i
elif m<i and m!=0:
count+=1
print(count)
``` | instruction | 0 | 16,422 | 11 | 32,844 |
No | output | 1 | 16,422 | 11 | 32,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sean is trying to save a large file to a USB flash drive. He has n USB flash drives with capacities equal to a1, a2, ..., an megabytes. The file size is equal to m megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input
The first line contains positive integer n (1 ≤ n ≤ 100) — the number of USB flash drives.
The second line contains positive integer m (1 ≤ m ≤ 105) — the size of Sean's file.
Each of the next n lines contains positive integer ai (1 ≤ ai ≤ 1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all ai is not less than m.
Output
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Examples
Input
3
5
2
1
3
Output
2
Input
3
6
2
3
2
Output
3
Input
2
5
5
10
Output
1
Note
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
Submitted Solution:
```
a = []
k = 0
n = int(input())
m = int(input())
z=m
for i in range(n):
a.append(int(input()))
a = sorted(a,reverse=True)
i=-1
while z>0:
i+=1
if a[i]<=m:
z=z-a[i]
k+=1
print(k)
``` | instruction | 0 | 16,423 | 11 | 32,846 |
No | output | 1 | 16,423 | 11 | 32,847 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,424 | 11 | 32,848 |
Tags: *special
Correct Solution:
```
def trans(n, base):
ans=[]
while n:
ans.append(n%base)
n = n//base
return ans
n=eval(input())
print(trans(n,8).count(1))
``` | output | 1 | 16,424 | 11 | 32,849 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,425 | 11 | 32,850 |
Tags: *special
Correct Solution:
```
print(sum(i == '1' for i in oct(int(input()))[2:]))
``` | output | 1 | 16,425 | 11 | 32,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,426 | 11 | 32,852 |
Tags: *special
Correct Solution:
```
a = int(input())
ans = 0
while a>0:
if a%8==1:
ans+=1
a//=8
print(ans)
``` | output | 1 | 16,426 | 11 | 32,853 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,427 | 11 | 32,854 |
Tags: *special
Correct Solution:
```
print ( "{:o}".format( int(input()) ).count("1") )
``` | output | 1 | 16,427 | 11 | 32,855 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,428 | 11 | 32,856 |
Tags: *special
Correct Solution:
```
n = int(input())
a = oct(n)
print(a.count('1'))
``` | output | 1 | 16,428 | 11 | 32,857 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,429 | 11 | 32,858 |
Tags: *special
Correct Solution:
```
A=int(input(""))
A=oct(A)
A=str(A)
a=A.count("1")
print(a)
``` | output | 1 | 16,429 | 11 | 32,859 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,430 | 11 | 32,860 |
Tags: *special
Correct Solution:
```
b=eval(input())
a=oct(b).replace('0o','')
print(a.count('1'))
``` | output | 1 | 16,430 | 11 | 32,861 |
Provide tags and a correct Python 3 solution for this coding contest problem.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1 | instruction | 0 | 16,431 | 11 | 32,862 |
Tags: *special
Correct Solution:
```
def represent(n):
m = oct(n)
return m.count('1')
print(represent(int(input())))
``` | output | 1 | 16,431 | 11 | 32,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
a = '%o' % int(input())
print(a.count('1'))
``` | instruction | 0 | 16,432 | 11 | 32,864 |
Yes | output | 1 | 16,432 | 11 | 32,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
A=eval(input())
def z(A):
a=''
while A>=8:
a=str(A%8)+a
A=A//8
a=str(A)+ a
return a
l=[]
a=z(A)
for i in range(len(a)):
if a[i]=='1':
l.append(1)
print(len(l))
``` | instruction | 0 | 16,433 | 11 | 32,866 |
Yes | output | 1 | 16,433 | 11 | 32,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
# coding: utf-8
a = oct(int(input()))
print(a.count('1'))
``` | instruction | 0 | 16,434 | 11 | 32,868 |
Yes | output | 1 | 16,434 | 11 | 32,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
#!/usr/bin/env python3
s = oct(int(input()))
counter = 0
for c in s:
if c == '1':
counter += 1
print(counter)
``` | instruction | 0 | 16,435 | 11 | 32,870 |
Yes | output | 1 | 16,435 | 11 | 32,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
print(129)
``` | instruction | 0 | 16,436 | 11 | 32,872 |
No | output | 1 | 16,436 | 11 | 32,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
n = int(input())
ans = 0
while n > 0:
last = n % 8
if last == 1:
ans += 1
n /= 8
print(ans)
``` | instruction | 0 | 16,437 | 11 | 32,874 |
No | output | 1 | 16,437 | 11 | 32,875 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
a=str(input())
print(a[0])
``` | instruction | 0 | 16,438 | 11 | 32,876 |
No | output | 1 | 16,438 | 11 | 32,877 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
++++++++[>+>++>+++>++++>+++++>++++++>+++++++>++++++++>+++++++++>++++++++++>+
++++++++++>++++++++++++>+++++++++++++>++++++++++++++>+++++++++++++++>+++++++
+++++++++<<<<<<<<<<<<<<<<-]>>>>>>>>>>.<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<<<<<<<
<<<<<>>>>>>>>>>>>>+.-<<<<<<<<<<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>>>>>>
>>>>>>----.++++<<<<<<<<<<<<<<<>>>>.<<<<>>>>>>>>>>>>>>--.++<<<<<<<<<<<<<<>>>>
>>>>>>>>>>>---.+++<<<<<<<<<<<<<<<>>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<<>>>>>>>>
>>>>++.--<<<<<<<<<<<<>>>>>>>>>>>>>---.+++<<<<<<<<<<<<<>>>>>>>>>>>>>>++.--<<<
<<<<<<<<<<<.
DCBA:^!~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHdcbD`Y^]\UZYRv
9876543210/.-,+*)('&%$#"!~}|{zyxwvutsrqponm+*)('&%$#cya`=^]\[ZYXWVUTSRQPONML
KJfe^cba`_X]VzTYRv98TSRQ3ONMLEi,+*)('&%$#"!~}|{zyxwvutsrqponmlkjihgfedcba`_^
]\[ZYXWVUTSonPlkjchg`ed]#DCBA@?>=<;:9876543OHGLKDIHGFE>b%$#"!~}|{zyxwvutsrqp
onmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMibafedcba`_X|?>Z<XWVUTSRKo\
<image>
v34*8+6+,78+9*3+,93+9*5+,28+9*1+,55+9*4+,23*6*2*,91,@,+7*9*25,*48,+3*9+38,+<
>62*9*2+,34*9*3+,66+9*8+,52*9*7+,75+9*8+,92+9*6+,48+9*3+,43*9*2+,84*,26*9*3^
Input
The input contains a single integer a (0 ≤ a ≤ 1 000 000).
Output
Output a single integer.
Example
Input
129
Output
1
Submitted Solution:
```
n = int(input())
print(n % 32)
``` | instruction | 0 | 16,439 | 11 | 32,878 |
No | output | 1 | 16,439 | 11 | 32,879 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An example of a simple statement is assignment.
For statements are compound statements: they contain one or several other statements. For statement consists of a header written in a separate line which starts with "for" prefix, and loop body. Loop body is a block of statements indented one level further than the header of the loop. Loop body can contain both types of statements. Loop body can't be empty.
You are given a sequence of statements without indentation. Find the number of ways in which the statements can be indented to form a valid Python program.
Input
The first line contains a single integer N (1 ≤ N ≤ 5000) — the number of commands in the program. N lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement.
Output
Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109 + 7.
Examples
Input
4
s
f
f
s
Output
1
Input
4
f
s
f
s
Output
2
Note
In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
simple statement
for statement
for statement
simple statement
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one.
for statement
simple statement
for statement
simple statement
or
for statement
simple statement
for statement
simple statement
Submitted Solution:
```
M=10**9+7
n=int(input())
a=[]
for i in range(n):
a.append(input())
dp=[[0]*(n+5) for i in range(n+2)]
dp[0][0]=1
for i in range(1,n):
count=0
if a[i-1]=='f':
for j in range(n-2,-1,-1):
if dp[i-1][j]>0:
dp[i][j+1]=(dp[i][j+1]+dp[i-1][j])%M
else:
for j in range(n-2,-1,-1):
if dp[i-1][j]>0:
count=(count+dp[i-1][j])%M
dp[i][j]=(dp[i][j]+count)%M
print(sum(dp[n-1])%M)
``` | instruction | 0 | 16,540 | 11 | 33,080 |
Yes | output | 1 | 16,540 | 11 | 33,081 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An example of a simple statement is assignment.
For statements are compound statements: they contain one or several other statements. For statement consists of a header written in a separate line which starts with "for" prefix, and loop body. Loop body is a block of statements indented one level further than the header of the loop. Loop body can contain both types of statements. Loop body can't be empty.
You are given a sequence of statements without indentation. Find the number of ways in which the statements can be indented to form a valid Python program.
Input
The first line contains a single integer N (1 ≤ N ≤ 5000) — the number of commands in the program. N lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement.
Output
Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109 + 7.
Examples
Input
4
s
f
f
s
Output
1
Input
4
f
s
f
s
Output
2
Note
In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
simple statement
for statement
for statement
simple statement
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one.
for statement
simple statement
for statement
simple statement
or
for statement
simple statement
for statement
simple statement
Submitted Solution:
```
import sys
#dp[i][j] means ith statement indented 'j times'
def num_ways(arr):
dp = [[0 for _ in range(len(arr))] for _ in range(len(arr))]
dp[0][0] = 1
for i in range(1, len(arr)):
if arr[i-1] == 'f':
#if prev line i-1 is f, then all instructio
for j in range(i-1):
dp[i][j+1] = dp[i-1][j]
else:
#prev line is a statement -> the depths of s[i] and s[i-1] are equal, so the number of
#ways that s[i] can be at a certain depth d is simply s[i-1][d] + ... + s[i-1][len(arr)] max depth
temp_sum = 0
for j in range(i-1, -1, -1):
temp_sum += dp[i-1][j]
dp[i][j] = temp_sum
return sum(dp[-1])
def main():
n = int(sys.stdin.readline().strip())
inpt = []
for _ in range(n):
inpt.append(sys.stdin.readline().strip())
print(num_ways(inpt))
if __name__ == '__main__':
main()
``` | instruction | 0 | 16,545 | 11 | 33,090 |
No | output | 1 | 16,545 | 11 | 33,091 |
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