message stringlengths 2 23.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara | instruction | 0 | 28,911 | 0 | 57,822 |
"Correct Solution:
```
s=input()
t=input()
a=len(s)
b=len(t)
dp=[[0]*(b+1) for i in range(a+1)]
for i in range(a):
for j in range(b):
if s[i]==t[j]:
dp[i+1][j+1]=dp[i][j]+1
else:
dp[i+1][j+1]=max(dp[i][j+1],dp[i+1][j])
res=''
while a!=0 and b!=0:
if dp[a][b]==dp[a-1][b]:
a-=1
elif dp[a][b]==dp[a][b-1]:
b-=1
else:
a-=1
b-=1
res=s[a]+res
print(res)
``` | output | 1 | 28,911 | 0 | 57,823 |
Provide a correct Python 3 solution for this coding contest problem.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara | instruction | 0 | 28,912 | 0 | 57,824 |
"Correct Solution:
```
s = input()
t = input()
lenS = len(s)
lenT = len(t)
dp = []
for i in range(lenS+1):
dp.append([0]*(lenT+1))
for i in range(1,lenS+1):
for j in range(1,lenT+1):
if s[i-1]==t[j-1]:
dp[i][j]=dp[i-1][j-1]+1
else:
dp[i][j]=max(dp[i-1][j],dp[i][j-1])
ans=""
i=lenS
j=lenT
while i>0 and j>0:
if dp[i][j]==dp[i-1][j]:
i-=1
elif dp[i][j]==dp[i][j-1]:
j-=1
else:
ans+=s[i-1]
i-=1
j-=1
print(ans[::-1])
``` | output | 1 | 28,912 | 0 | 57,825 |
Provide a correct Python 3 solution for this coding contest problem.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara | instruction | 0 | 28,913 | 0 | 57,826 |
"Correct Solution:
```
s = input()
t = input()
ls = len(s)
lt = len(t)
ans = ""
dp = [[0]*(ls+1) for i in range(lt+1)]
for i in range(1,lt+1):
for j in range(1,ls+1):
dp[i][j] = max(dp[i-1][j],dp[i][j-1])
if s[j-1] == t[i-1]:
dp[i][j] = dp[i-1][j-1]+1
i = lt
j = ls
while i-1>=0 and j-1>=0:
if dp[i][j] == dp[i-1][j]:
i -= 1
continue
elif dp[i][j] == dp[i][j-1]:
j -= 1
continue
else:
i -= 1
j -= 1
ans = s[j] + ans
print(ans)
``` | output | 1 | 28,913 | 0 | 57,827 |
Provide a correct Python 3 solution for this coding contest problem.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara | instruction | 0 | 28,914 | 0 | 57,828 |
"Correct Solution:
```
s=input()
t=input()
S=len(s)
T=len(t)
ans=[[0 for e in range(S+1)] for f in range(T+1)]
chk=[]
for a in range(1,T+1):
for b in range(1,S+1):
if t[a-1]==s[b-1]:
ans[a][b]=ans[a-1][b-1]+1
else:
if ans[a-1][b]>ans[a][b-1]:
ans[a][b]=ans[a-1][b]
else:
ans[a][b]=ans[a][b-1]
x,y=T,S
while x>0 and y>0:
if ans[x][y]==ans[x-1][y]:
x-=1
elif ans[x][y]==ans[x][y-1]:
y-=1
else:
x-=1
y-=1
chk.append(s[y])
chk.reverse()
print("".join(chk))
``` | output | 1 | 28,914 | 0 | 57,829 |
Provide a correct Python 3 solution for this coding contest problem.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara | instruction | 0 | 28,915 | 0 | 57,830 |
"Correct Solution:
```
s1=input()
s2=input()
n1=len(s1)
n2=len(s2)
dp=[[0 for i in range(n2+1)] for j in range(n1+1)]
for i in range(1,n1+1):
for j in range(1,n2+1):
if s1[i-1]==s2[j-1]:
dp[i][j]=1+dp[i-1][j-1]
else:
dp[i][j]=max(dp[i-1][j],dp[i][j-1])
s=""
i,j=n1,n2
while dp[i][j]:
if dp[i][j]==dp[i][j-1]:
j-=1
elif dp[i][j]==dp[i-1][j]:
i-=1
else:
s=s1[i-1]+s
i-=1
j-=1
print(s)
``` | output | 1 | 28,915 | 0 | 57,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
*s, = input()
*t, = input()
dp = [[0]*(len(t)+1) for _ in range(len(s)+1)]
for i in range(len(s)):
for j in range(len(t)):
if s[i] == t[j]:
dp[i+1][j+1] = dp[i][j] + 1
else:
dp[i+1][j+1] = max(dp[i+1][j], dp[i][j+1])
ans = ""
i, j = len(s), len(t)
while i > 0 and j > 0:
if dp[i][j] == dp[i-1][j]:
i -= 1
elif dp[i][j] == dp[i][j-1]:
j -= 1
else:
ans = s[i-1] + ans
i -= 1
j -= 1
print(ans)
``` | instruction | 0 | 28,916 | 0 | 57,832 |
Yes | output | 1 | 28,916 | 0 | 57,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
s=input()
t=input()
ls=len(s)
lt=len(t)
INF=float('inf')
dp=[[0 for i in range(lt+1)] for j in range(ls+1)]
R=[[INF for i in range(lt+1)] for j in range(ls+1)]
for i in range(1,ls+1):
for j in range(1,lt+1):
if s[i-1]==t[j-1]:
dp[i][j]=dp[i-1][j-1]+1
else:
dp[i][j]=max(dp[i][j-1],dp[i-1][j])
l=dp[ls][lt]
ans=''
i=ls
j=lt
while l>0:
if s[i-1]==t[j-1]:
ans=str(s[i-1])+ans
l-=1
i-=1
j-=1
elif dp[i][j]==dp[i-1][j]:
i-=1
else:
j-=1
print(ans)
``` | instruction | 0 | 28,917 | 0 | 57,834 |
Yes | output | 1 | 28,917 | 0 | 57,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
S = input()
T = input()
s,t = len(S),len(T)
dp = [[0]*(t+1) for _ in range(s+1)]
for i in range(1,s+1):
for j in range(1,t+1):
if S[i-1]==T[j-1]:
dp[i][j] = dp[i-1][j-1]+1
else:
dp[i][j] = max(dp[i-1][j],dp[i][j-1])
ans = ''
n,m = s,t
while n>0 and m>0:
if dp[n][m]==dp[n-1][m]:
n -= 1
elif dp[n][m]==dp[n][m-1]:
m -= 1
else:
ans = S[n-1] + ans
n -= 1
m -= 1
print(ans)
``` | instruction | 0 | 28,918 | 0 | 57,836 |
Yes | output | 1 | 28,918 | 0 | 57,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
s = list(input())
t = list(input())
a = len(s)
b = len(t)
dp = [[0]*(b+1) for _ in range(a+1)]
ans = ""
#dp[i][j]はi文字目までのsとtのj文字目までの共通部分
for i in range(a):
for j in range(b):
if s[i] == t[j]:
dp[i+1][j+1] = dp[i][j]+1
else:
dp[i+1][j+1] = max(dp[i][j+1],dp[i+1][j])
i = a
j = b
while(i>=0 and j>=0):
if dp[i][j] == dp[i-1][j]:
i -= 1
elif dp[i][j] == dp[i][j-1]:
j -= 1
else:
ans = t[j-1]+ans
i -= 1
j -= 1
print(ans)
``` | instruction | 0 | 28,919 | 0 | 57,838 |
Yes | output | 1 | 28,919 | 0 | 57,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
s=' '+input()
t=' '+input()
dp=[['']*len(t)for _ in range(len(s))]
for i in range(1,len(s)):
for j in range(1,len(t)):
if s[i]==t[j]:
dp[i][j]=dp[i-1][j-1]+s[i]
elif len(dp[i-1][j])>len(dp[i][j-1]):
dp[i][j]=dp[i-1][j]
else:
dp[i][j]=dp[i][j-1]
print(dp[-1][-1])
``` | instruction | 0 | 28,920 | 0 | 57,840 |
No | output | 1 | 28,920 | 0 | 57,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
s = input()
t = input()
ls = len(s)
lt = len(t)
dp = [[0 for _ in range(lt + 1)] for _ in range(ls + 1)] # dp[ls][lt] = LCS_length
for i in range(ls):
for j in range(lt):
if s[i] == t[j]:
dp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[i][j] + 1)
dp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[i + 1][j])
dp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[i][j + 1])
res = ''
i = ls
j = lt
while i > 0 and j > 0:
if dp[i][j] == dp[i - 1][j]:
i -= 1
elif dp[i][j] == dp[i][j - 1]:
j -= 1
else:
res = s[i - 1] + res
i -= 1
j -= 1
print(res)
``` | instruction | 0 | 28,921 | 0 | 57,842 |
No | output | 1 | 28,921 | 0 | 57,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
import math, string, itertools, fractions, heapq, collections, re, array, bisect, sys, random, time, copy, functools
sys.setrecursionlimit(10**7)
inf = 10 ** 20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1, 0), (0, 1), (1, 0), (0, -1)]
ddn = [(-1, 0), (-1, 1), (0, 1), (1, 1), (1, 0), (1, -1), (0, -1), (-1, -1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
s = input()
t = input()
n = len(s)
m = len(t)
dp = [[0 for j in range(m+1)] for i in range(n + 1)]
for i in range(n):
for j in range(m):
if s[i] == t[j]:
dp[i+1][j+1] = dp[i][j] + 1
else:
dp[i+1][j+1] = max(dp[i+1][j], dp[i][j+1])
# print(t)
# v = 0
# result = ''
# print('dp[-1]', dp[-1])
# for idx, i in enumerate(dp[-1]):
# print(idx, i)
# if i == v + 1:
# result += t[idx-1]
# v += 1
# print(result)
lcs_str = ''
i, j = n - 1, m - 1
while i >= 0 and j >= 0:
if s[i] == t[j]:
lcs_str += s[i]
i -= 1
j -= 1
elif dp[i+1][j+1] == 0:
break
else:
if dp[i][j+1] > dp[i+1][j]:
i -= 1
else:
j -= 1
print(lcs_str[::-1])
main()
``` | instruction | 0 | 28,922 | 0 | 57,844 |
No | output | 1 | 28,922 | 0 | 57,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t. Find one longest string that is a subsequence of both s and t.
Constraints
* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000
Input
Input is given from Standard Input in the following format:
s
t
Output
Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.
Examples
Input
axyb
abyxb
Output
axb
Input
aa
xayaz
Output
aa
Input
a
z
Output
Input
abracadabra
avadakedavra
Output
aaadara
Submitted Solution:
```
s = input()
t = input()
n, m = len(s), len(t)
dpString = [[""]*(m+1) for _ in range(n+1)]
dpNum = [[0]*(m+1) for _ in range(n+1)]
for i in range(n):
for j in range(m):
if s[i] == t[j]:
dpString[i+1][j+1] = dpString[i][j] + s[i]
dpNum[i+1][j+1] = dpNum[i][j] + 1
else:
if dpNum[i+1][j] >= dpNum[i][j+1]:
dpString[i+1][j+1] = dpString[i+1][j]
dpNum[i+1][j+1] = dpNum[i+1][j]
else:
dpString[i+1][j+1] = dpString[i][j+1]
dpNum[i+1][j+1] = dpNum[i][j+1]
print(dpString[n][m])
``` | instruction | 0 | 28,923 | 0 | 57,846 |
No | output | 1 | 28,923 | 0 | 57,847 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,940 | 0 | 57,880 |
"Correct Solution:
```
a = list(map(lambda x: ord(x)-ord("a"), list(input())))
n = len(a)
m = 26
b = [1]*(n+1)
prev = [n]*m
G = [[] for i in range(n+1)]
for i in reversed(range(n)):
ai = a[i]
tmp = min(b[j] for j in prev)
for j in prev:
G[i].append(j)
b[i] = tmp+1
prev[ai] = i
cnt = min(b[j] for j in prev)
edge = prev
ans = []
for _ in range(cnt):
for i, to in enumerate(edge):
if b[to] == cnt-_:
ans.append(chr(ord("a")+i))
edge = G[to]
break
print("".join(ans))
``` | output | 1 | 28,940 | 0 | 57,881 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,941 | 0 | 57,882 |
"Correct Solution:
```
# coding: utf-8
# Your code here!
import sys
read = sys.stdin.read
readline = sys.stdin.readline
#n, = map(int,readline().split())
s = input()
def next_index(N,s):
D = [-1]*26
E = [None]*(N+1)
cA = ord('a')
for i in range(N-1, -1, -1):
E[i+1] = D[:]
D[ord(s[i])-cA] = i
E[0] = D
return E
n = len(s)
nxt = next_index(n,s)
"""
for i in nxt:
print(i[:4])
"""
#print(nxt)
dp = [0]*(n+1)
for i in range(n-1,-1,-1):
idx = max(nxt[i])
bad = min(nxt[i])
dp[i] = dp[idx+1]+1 if bad != -1 else 0
#print(nxt[0])
#print(dp)
k = dp[0]+1
ans = [None]*k
v = 0
for i in range(k):
#print(v)
if v==n:
ans[-1] = 0
break
for j in range(26):
#print(nxt[v+1][j], dp[nxt[v+1][j]])
if nxt[v][j]==-1 or dp[nxt[v][j] + 1] < dp[v]:
ans[i] = j
v = nxt[v][j]+1
break
#print(ans)
def f(x):
return chr(x+ord("a"))
a = "".join(map(f,ans))
print(a)
"""
x = [chr(ord("z")-i) for i in range(26)]
x = "".join(x)
print(x)
"""
``` | output | 1 | 28,941 | 0 | 57,883 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,942 | 0 | 57,884 |
"Correct Solution:
```
S=input()
N=len(S)
a=ord('a')
alpha=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
K=[[N]*(N+1) for i in range(26)]
for i in range(N-1,-1,-1):
x=ord(S[i])-a
for j in range(26):
if j==x:
K[j][i]=i
continue
K[j][i]=K[j][i+1]
dp=[0]*(N+2)
L=[0]*(N+2)
dp[N]=1
for i in range(N-1,-1,-1):
c=0
b=2*N
for j in range(26):
t=K[j][i]
if b>dp[t+1]+1:
b=dp[t+1]+1
c=t+1
dp[i]=b
L[i]=c
X=dp[0]
t=0
ans=''
while X>1:
t=L[t]
ans+=S[t-1]
X-=1
#print(t,X,ans)
for j in range(26):
if K[j][t] ==N:
ans+=alpha[j]
break
print(ans)
``` | output | 1 | 28,942 | 0 | 57,885 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,943 | 0 | 57,886 |
"Correct Solution:
```
from itertools import accumulate
S = list(map(ord, input().strip()))
N = len(S)
atype = set()
seg = [0]*N
seg[-1] = 1
for i in range(N-1, -1, -1):
atype.add(S[i])
if len(atype) == 26:
atype = set()
seg[i] = 1
inf = 1<<32
idx = [[inf]*N for _ in range(26)]
for i in range(N-1, -1, -1):
s = S[i] - 97
idx[s][i] = i
for s in range(26):
for i in range(N-2, -1, -1):
idx[s][i] = min(idx[s][i], idx[s][i+1])
seg = list(accumulate(seg[::-1]))[::-1]
seg.append(1)
L = seg[0]
ans = []
cnt = -1
for i in range(L):
for c in range(26):
k = idx[c][cnt+1]
if k == inf:
ans.append(97+c)
break
if seg[k+1] + i + 1 <= L:
ans.append(97+c)
cnt = k
break
print(''.join(map(chr, ans)))
``` | output | 1 | 28,943 | 0 | 57,887 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,944 | 0 | 57,888 |
"Correct Solution:
```
def main():
import sys
input = sys.stdin.readline
a = list(input())[:-1]
#print(a)
n = len(a)
d = dict()
for i in range(26):
d[chr(i+97)] = chr(i+97)
for i in range(n-1,-1,-1):
min_key = 'zz'
min_len = 10**9
for e in d:
if (min_len == len(d[e]) and min_key > e) or (min_len > len(d[e])):
min_key = e
min_len = len(d[e])
d[a[i]] = a[i]+d[min_key]
res_len = len(d['a'])
res_key = 'a'
for e in d:
if (res_len == len(d[e]) and res_key > e) or (res_len > len(d[e])):
res_key = e
res_len = len(d[e])
print(d[res_key])
if __name__ =='__main__':
main()
``` | output | 1 | 28,944 | 0 | 57,889 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,945 | 0 | 57,890 |
"Correct Solution:
```
"""
Writer: SPD_9X2
https://atcoder.jp/contests/arc081/tasks/arc081_c
1文字がありうるのは、出てない文字があるとき
2文字がありうるのは、全ての文字が1度出たのち、もう一度すべての文字が1度現れてない場合
つまり答えの文字数はこの方法で分かる
では辞書順最小のものは？
k文字であることがわかっていたとする。
この時、どの文字も最低k-1回出現している
最後の文字は、k回出現してない文字の内、辞書順最小の物
最後から1番目は、k-1回目の出現の後、最後の文字が出ていない者
最後から2番目は、
abcの3文字しかないとする
abababababcab
→この時、求めるのは、?cで、?はc最後に出現するcよりも前に存在しないk-1文字の辞書順最小
abcabcab
→??c
→最後の出現するc以前=abcab以前で存在しない2文字
→?cc
→abで存在しない1文字
→ccc
acbaccbac
→結局再帰的に解ける
→出現回数が最小の文字のうち、辞書順最小の物を答えの最後の文字から決めていき、その文字が最後の出現したind
より前に関して、同じ問題を解く
あとはどうやって計算量を削減するか
その時点で、どの文字が何度出たか、最後の出現したindexはどこか、を記録して置いて再帰的に解く
→方針は合ってる？けど実装してるのが違うよ！
保存しておくのは、全ての文字が何回出揃ったか、とその後どの文字が出ているか。
&各文字が最後にどこで出たか。
あれー？
aaaaaabbbbbbc
→問題は、必ずしも後ろから最適なのを選んで行けばいいわけではなかったこと
→これはあくまで、後ろから見て辞書順最小でしかない…あれまさか？
→正解しちゃったー？？？
"""
A = list(input())
A.reverse()
alp = "abcdefghijklmnopqrstuvwxyz"
alpdic = {}
for i in range(26):
alpdic[alp[i]] = i
allcol = [0] * (len(A)+1)
apnum = [ [0] * 26 for i in range(len(A)+1) ]
lastap = [ [0] * 26 for i in range(len(A)+1) ]
for i in range(len(A)):
for j in range(26):
apnum[i+1][j] = apnum[i][j]
lastap[i+1][j] = lastap[i][j]
allcol[i+1] = allcol[i]
apnum[i+1][alpdic[A[i]]] |= 1
if 0 not in apnum[i+1]:
apnum[i+1] = [0] * 26
allcol[i+1] += 1
lastap[i+1][alpdic[A[i]]] = i+1
anslen = allcol[-1]+1
ans = []
nind = len(A)
for i in range(anslen):
#print ("".join(A[:nind]))
minind = 0
for j in range(26):
if apnum[nind][j] == 0:
minind = j
break
ans.append(alp[minind])
nind = lastap[nind][minind]-1
#ans.reverse()
print ("".join(ans))
``` | output | 1 | 28,945 | 0 | 57,891 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,946 | 0 | 57,892 |
"Correct Solution:
```
a = list(map(lambda x: ord(x)-ord("a"), list(input())))
n = len(a)
m = 26
b = [0]*n
pos = [[] for i in range(m)]
s = set()
cnt = 0
for i in reversed(range(n)):
b[i] = cnt
if a[i] not in s:
s.add(a[i])
pos[a[i]].append(i)
if len(s) == m:
cnt += 1
s = set()
for i in range(m):
pos[i].sort()
k = cnt+1
from bisect import bisect_right
ans = []
cur = -1
for i in range(k):
for j in range(m):
pj = bisect_right(pos[j], cur)
if pj == len(pos[j]):
ans.append(j)
break
to = pos[j][pj]
if b[to] != k-i-1:
cur = to
ans.append(j)
break
ans = "".join(chr(ord("a")+i) for i in ans)
print(ans)
``` | output | 1 | 28,946 | 0 | 57,893 |
Provide a correct Python 3 solution for this coding contest problem.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca | instruction | 0 | 28,947 | 0 | 57,894 |
"Correct Solution:
```
from collections import deque
alpha = "abcdefghijklmnopqrstuvwxyz"
A = input()
n = len(A)
B = ord('a')
links = [None]*(n+3)
link = [n]*26
for i in range(n-1, -1, -1):
links[i] = link[:]
link[ord(A[i]) - B] = i
links[-1] = link
deq = deque()
deq.append(-1)
prev = {-1: (None, 0)}
while deq:
v = deq.popleft()
if v == n:
break
link = links[v]
for c in range(26):
if link[c] in prev:
continue
prev[link[c]] = (v, c)
deq.append(link[c])
v = n
ans = []
while v is not None:
v, c = prev[v]
ans.append(chr(c+B))
ans.reverse()
print("".join(ans[1:]))
``` | output | 1 | 28,947 | 0 | 57,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
from string import ascii_lowercase
from bisect import bisect
def solve(s):
pos = [[] for _ in range(26)]
offset = ord('a')
for i, c in enumerate(s):
c = ord(c) - offset
pos[c].append(i)
for l in pos:
l.append(len(s))
all_char_sequence_start_pos = []
pos_i = [len(l) - 1 for l in pos]
while all(pi >= 0 for pi in pos_i):
i = min(l[pi] for pi, l in zip(pos_i, pos))
all_char_sequence_start_pos.append(i)
for j in range(26):
while pos_i[j] >= 0 and pos[j][pos_i[j]] >= i:
pos_i[j] -= 1
all_char_sequence_start_pos.reverse()
ans = []
curr = -1
for i in all_char_sequence_start_pos:
for c in range(26):
cj = bisect(pos[c], curr)
j = pos[c][cj]
if j >= i:
ans.append(c)
curr = j
break
return ''.join(chr(c + offset) for c in ans)
print(solve(input().strip()))
``` | instruction | 0 | 28,948 | 0 | 57,896 |
Yes | output | 1 | 28,948 | 0 | 57,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
gosa = 1.0 / 10**10
mod = 10**9+7
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def main():
a = S()
l = len(a)
t = {}
for c in string.ascii_lowercase:
t[c] = l
b = [(1,0,0) for _ in range(l)]
b.append((1,'a',l))
b.append((0,'',l+1))
for c,i in reversed(list(zip(a,range(l)))):
t[c] = i
b[i] = min([(b[t[d]+1][0] + 1,d,t[d]+1) for d in string.ascii_lowercase])
r = ''
i = 0
while i < l:
r += b[i][1]
i = b[i][2]
return r
print(main())
``` | instruction | 0 | 28,949 | 0 | 57,898 |
Yes | output | 1 | 28,949 | 0 | 57,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
import sys
sys.setrecursionlimit(2147483647)
INF = float("inf")
MOD = 10**9 + 7 # 998244353
input = lambda:sys.stdin.readline().rstrip()
def resolve():
S = list(map(lambda c : ord(c) - ord('a'), input()))
n = len(S)
sigma = 26
# next[i][c] : i 文字目以降で c が現れる最小の index
next = [[-1] * sigma for _ in range(n + 1)]
for i in range(n - 1, -1, -1):
for c in range(sigma):
next[i][c] = i if S[i] == c else next[i + 1][c]
# dp[i] : S[i:] に対する答えの長さ
dp = [INF] * (n + 1)
dp[n] = 1
# character[i] : S[i:] に対する答えに対して採用する先頭の文字
character = [None] * (n + 1)
character[n] = 0
for i in range(n - 1, -1, -1):
for c in range(sigma):
length = 1 if next[i][c] == -1 else 1 + dp[next[i][c] + 1]
if dp[i] > length:
dp[i] = length
character[i] = c
# 経路復元
res = []
now = 0
while 1:
res.append(character[now])
now = next[now][character[now]] + 1
if now == 0:
break
res = ''.join(map(lambda x : chr(x + ord('a')), res))
print(res)
resolve()
``` | instruction | 0 | 28,950 | 0 | 57,900 |
Yes | output | 1 | 28,950 | 0 | 57,901 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
#!/usr/bin/env python3
def main():
A = input()
n = len(A)
next_i = []
ct = [n] * 26
orda = ord("a")
for i in range(n - 1, -1, -1):
ct[ord(A[i]) - orda] = i
next_i.append(ct.copy())
next_i.reverse()
dp = [0] * (n + 1)
dp[n] = 1
j = -1
for i in range(n - 1, -1, -1):
ct = next_i[i]
if max(ct) < n:
j = i
break
else:
dp[i] = 1
if j == -1:
ct = next_i[0]
for c in range(26):
if ct[c] == n:
print(chr(orda + c))
return
rt = [0] * n
for i in range(j, -1, -1):
ct = next_i[i]
min_c = 0
min_v = dp[ct[0] + 1]
for c in range(1, 26):
v = dp[ct[c] + 1]
if v < min_v:
min_c = c
min_v = v
rt[i] = min_c
dp[i] = min_v + 1
r = ''
i = 0
while i < n:
if dp[i] == 1:
for c in range(26):
if not chr(orda + c) in A[i:]:
r += chr(orda + c)
break
break
r += chr(orda + rt[i])
i = next_i[i][rt[i]] + 1
print(r)
if __name__ == '__main__':
main()
``` | instruction | 0 | 28,951 | 0 | 57,902 |
Yes | output | 1 | 28,951 | 0 | 57,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
A=str(input())
memo=[]
count=0
ans=""
index=[]
for i in range(0,len(A)):
target=A[len(A)-1-i]
if(target not in memo):
memo.append(target)
count+=1
if(count==26):
count=0
memo=[]
index.append(len(A)-1-i)
for i in "abcdefghijklmnopqrstuvwxyz":
if(i not in memo):
ans+=i
break
num=0
index=index[::-1]
a=0
b=0
for j in range(0,len(index)-1):
a=index[j]
b=index[j+1]
print(a,b)
target=A[a:b]
num=target.find(ans[j])
for i in "abcdefghijklmnopqrstuvwxyz":
if(i not in target[num:]):
ans+=i
break
target=A[index[len(index)-1]:]
num=target.find(ans[len(index)-1])
for i in "abcdefghijklmnopqrstuvwxyz":
if(i not in target[num:]):
ans+=i
break
ans+="\n"
print(ans)
``` | instruction | 0 | 28,952 | 0 | 57,904 |
No | output | 1 | 28,952 | 0 | 57,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
def minsbset(str, n):
if len(str) < n or n == 0:
return ""
return minsbset()
str = input()
n = len(str)
atoz = "abcdefghijklmnopqrstuvwxyz"
ret = ""
subsets1 = set()
subsets1.update(str)
if len(subsets1) < 26:
for i in range(26):
if atoz[i] not in subsets1:
ret = atoz[i]
break
else:
subsets2 = set()
for i1 in range(n):
for i2 in range(i1+1,n):
subsets2.add(str[i1] + str[i2])
if len(subsets2) < 26*26:
for i1 in range(26):
for i2 in range(26):
cand = atoz[i1] + atoz[i2]
if cand not in subsets2:
ret = cand
break
if ret != "":
break
else:
subsets3 = set()
for i1 in range(n):
for i2 in range(i1 + 1, n):
for i3 in range(i2 + 1, n):
subsets3.add(str[i1] + str[i2] + str[i3])
if len(subsets3) < 26 * 26 * 26:
for i1 in range(26):
for i2 in range(26):
for i3 in range(26):
cand = atoz[i1] + atoz[i2] + atoz[i3]
if cand not in subsets3:
ret = cand
break
if ret != "":
break
if ret != "":
break
else:
subsets4 = set()
for i1 in range(n):
for i2 in range(i1 + 1, n):
for i3 in range(i2 + 1, n):
for i4 in range(i3 + 1, n):
subsets4.add(str[i1] + str[i2] + str[i3] + str[i4])
for i1 in range(26):
for i2 in range(26):
for i3 in range(26):
for i4 in range(26):
cand = atoz[i1] + atoz[i2] + atoz[i3] + atoz[i4]
if cand not in subsets4:
ret = cand
break
if ret != "":
break
if ret != "":
break
if ret != "":
break
print(ret)
``` | instruction | 0 | 28,953 | 0 | 57,906 |
No | output | 1 | 28,953 | 0 | 57,907 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
import bisect
s = input()
n = len(s)
dp = [[0 for i in range(26)] for j in range(n+1)]
flg = [0]*26
prt = []
for i in range(n-1,-1,-1):
x = ord(s[i])-97
for j in range(26):
if j == x:
dp[i][j] = n-i
flg[x] = 1
else:
dp[i][j] = dp[i+1][j]
if flg.count(1) == 26:
prt.append(i)
flg = [0]*26
ind = 0
ans = []
if not prt:
for i in range(26):
if dp[0][i] == 0:
print(chr(i+97))
exit()
prt = prt[::-1]
for i in range(26):
if dp[prt[0]] != dp[0]:
ans.append(i)
break
else:
ans.append(0)
pnt = prt[0]
while True:
c = ans[-1]
pnt = n-dp[pnt][c]
prtp = bisect.bisect_right(prt,pnt)
if prtp == len(prt):
for i in range(26):
if dp[pnt][i] == dp[-1][i]:
ans.append(i)
break
else:
ans.append(0)
for od in ans:
print(chr(od+97),end="")
break
npnt = prt[prtp]
for i in range(26):
if dp[pnt][i] == dp[npnt][i]:
ans.append(i)
break
else:
ans.append(0)
pnt = npnt
``` | instruction | 0 | 28,954 | 0 | 57,908 |
No | output | 1 | 28,954 | 0 | 57,909 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A subsequence of a string S is a string that can be obtained by deleting zero or more characters from S without changing the order of the remaining characters. For example, `arc`, `artistic` and (an empty string) are all subsequences of `artistic`; `abc` and `ci` are not.
You are given a string A consisting of lowercase English letters. Find the shortest string among the strings consisting of lowercase English letters that are not subsequences of A. If there are more than one such string, find the lexicographically smallest one among them.
Constraints
* 1 \leq |A| \leq 2 \times 10^5
* A consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
A
Output
Print the lexicographically smallest string among the shortest strings consisting of lowercase English letters that are not subsequences of A.
Examples
Input
atcoderregularcontest
Output
b
Input
abcdefghijklmnopqrstuvwxyz
Output
aa
Input
frqnvhydscshfcgdemurlfrutcpzhopfotpifgepnqjxupnskapziurswqazdwnwbgdhyktfyhqqxpoidfhjdakoxraiedxskywuepzfniuyskxiyjpjlxuqnfgmnjcvtlpnclfkpervxmdbvrbrdn
Output
aca
Submitted Solution:
```
import sys
input = lambda : sys.stdin.readline().rstrip()
sys.setrecursionlimit(max(1000, 10**9))
write = lambda x: sys.stdout.write(x+"\n")
a = input()
n = len(a)
s = set()
l = []
i = n-1
prv = n
for c in a[::-1]:
s.add(c)
if len(s)==26:
s = set()
l.append((i,prv))
prv = i
i -= 1
def sub(i,j):
"""[i,j)に含まれない文字のうちの最小
"""
# print(i,j)
al = set([chr(v) for v in range(ord("a"), ord("z")+1)])
for ind in range(i,j):
al.discard(a[ind])
return min(al)
if prv!=0:
ans = []
c = sub(0,prv)
ans.append(c)
while l:
i,j = l.pop()
for ind in range(i,n):
if a[ind]==c:
break
c = sub(ind+1,j)
ans.append(c)
ans = "".join(ans)
else:
ans = "a" * (len(l)+1)
print(ans)
``` | instruction | 0 | 28,955 | 0 | 57,910 |
No | output | 1 | 28,955 | 0 | 57,911 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice and Bob are playing a game on strings.
Initially, they have some string t. In one move the first player selects the character c present in t and erases all it's occurrences in t, thus splitting t into many smaller strings. The game then goes independently with each of the strings — to make the move player selects one of the strings and one of the characters there, deletes all occurrences and adds the remaining string back to the game.
Alice always starts the game, and then Alice and Bob take turns making moves. The player who is unable to make a move (because there is no string left) loses.
Alice and Bob used to always start with a string s, but recently they found out that this became too boring. Now before each game they choose two integers l and r such that 1 ≤ l ≤ r ≤ |s| and play the game with the string s_{l} s_{l+1} s_{l+2} … s_{r} instead.
Given the string s and integers l, r for each game. Find who is going to win each game assuming they are smart and are playing optimally.
Input
The first line contains the string s (1 ≤ |s| ≤ 10^5) consisting of lowercase English letters. This is the string Alice and Bob used to start with.
The second line contains a single integer m (1 ≤ m ≤ 10^5) — the number of games to analyze.
Each of the next m lines contains two integers l and r (1 ≤ l ≤ r ≤ |s|) — the bounds of the starting substring in the string s.
Output
For each game output a single line containing the name of the winner — "Alice" or "Bob" respectively.
Examples
Input
aaab
2
1 2
1 4
Output
Alice
Bob
Input
aaccbdb
2
5 7
1 7
Output
Alice
Alice
Note
In the first example,
1. In the first game the string "aa" is selected. Alice deletes character 'a' and Bob is unable to move.
2. In the second game the string "aaab" is selected. No matter what character Alice will delete, Bob deletes the other one and Alice is unable to move.
In the second example Alice wins both game "bdb" and "aaccbdb".
To win game "bdb" Alice can erase symbol 'd', the game then goes independently on strings "b" and "b". Bob deletes one of this strings and the Alice deletes the other one and Bob is unable to move.
To win game "aaccbdb" Alice can erase symbol 'd', the game then goes independently on strings "aaccb" and "b". It is possible to show, that no matter what are the moves, the remaining game can only finish in exactly 4 moves, so the Bob will be unable to move after that.
Submitted Solution:
```
def del_near(s):
del_s=''
for i in range(len(s)-1):
if s[i]!=s[i+1]:
del_s=del_s+s[i]
elif i == len(s)-2 and s[i]==s[i+1]:
del_s=del_s+s[i]
return len(del_s)
s=input()
m=int(input())
for i in range(m):
l,r=map(int,input().split())
subs=s[l-1:r]
if del_near(subs)%2==0:
print('Alice')
else:
print('Bob')
``` | instruction | 0 | 29,115 | 0 | 58,230 |
No | output | 1 | 29,115 | 0 | 58,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice and Bob are playing a game on strings.
Initially, they have some string t. In one move the first player selects the character c present in t and erases all it's occurrences in t, thus splitting t into many smaller strings. The game then goes independently with each of the strings — to make the move player selects one of the strings and one of the characters there, deletes all occurrences and adds the remaining string back to the game.
Alice always starts the game, and then Alice and Bob take turns making moves. The player who is unable to make a move (because there is no string left) loses.
Alice and Bob used to always start with a string s, but recently they found out that this became too boring. Now before each game they choose two integers l and r such that 1 ≤ l ≤ r ≤ |s| and play the game with the string s_{l} s_{l+1} s_{l+2} … s_{r} instead.
Given the string s and integers l, r for each game. Find who is going to win each game assuming they are smart and are playing optimally.
Input
The first line contains the string s (1 ≤ |s| ≤ 10^5) consisting of lowercase English letters. This is the string Alice and Bob used to start with.
The second line contains a single integer m (1 ≤ m ≤ 10^5) — the number of games to analyze.
Each of the next m lines contains two integers l and r (1 ≤ l ≤ r ≤ |s|) — the bounds of the starting substring in the string s.
Output
For each game output a single line containing the name of the winner — "Alice" or "Bob" respectively.
Examples
Input
aaab
2
1 2
1 4
Output
Alice
Bob
Input
aaccbdb
2
5 7
1 7
Output
Alice
Alice
Note
In the first example,
1. In the first game the string "aa" is selected. Alice deletes character 'a' and Bob is unable to move.
2. In the second game the string "aaab" is selected. No matter what character Alice will delete, Bob deletes the other one and Alice is unable to move.
In the second example Alice wins both game "bdb" and "aaccbdb".
To win game "bdb" Alice can erase symbol 'd', the game then goes independently on strings "b" and "b". Bob deletes one of this strings and the Alice deletes the other one and Bob is unable to move.
To win game "aaccbdb" Alice can erase symbol 'd', the game then goes independently on strings "aaccb" and "b". It is possible to show, that no matter what are the moves, the remaining game can only finish in exactly 4 moves, so the Bob will be unable to move after that.
Submitted Solution:
```
def del_near(s):
del_s=''
for i in range(len(s)-1):
if s[i]!=s[i+1]:
del_s=del_s+s[i]
return len(del_s)
s=input()
m=int(input())
for i in range(m):
l,r=map(int,input().split())
subs=s[l-1:r]
if del_near(subs)%2==0:
print('Alice')
else:
print('Bob')
``` | instruction | 0 | 29,116 | 0 | 58,232 |
No | output | 1 | 29,116 | 0 | 58,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice and Bob are playing a game on strings.
Initially, they have some string t. In one move the first player selects the character c present in t and erases all it's occurrences in t, thus splitting t into many smaller strings. The game then goes independently with each of the strings — to make the move player selects one of the strings and one of the characters there, deletes all occurrences and adds the remaining string back to the game.
Alice always starts the game, and then Alice and Bob take turns making moves. The player who is unable to make a move (because there is no string left) loses.
Alice and Bob used to always start with a string s, but recently they found out that this became too boring. Now before each game they choose two integers l and r such that 1 ≤ l ≤ r ≤ |s| and play the game with the string s_{l} s_{l+1} s_{l+2} … s_{r} instead.
Given the string s and integers l, r for each game. Find who is going to win each game assuming they are smart and are playing optimally.
Input
The first line contains the string s (1 ≤ |s| ≤ 10^5) consisting of lowercase English letters. This is the string Alice and Bob used to start with.
The second line contains a single integer m (1 ≤ m ≤ 10^5) — the number of games to analyze.
Each of the next m lines contains two integers l and r (1 ≤ l ≤ r ≤ |s|) — the bounds of the starting substring in the string s.
Output
For each game output a single line containing the name of the winner — "Alice" or "Bob" respectively.
Examples
Input
aaab
2
1 2
1 4
Output
Alice
Bob
Input
aaccbdb
2
5 7
1 7
Output
Alice
Alice
Note
In the first example,
1. In the first game the string "aa" is selected. Alice deletes character 'a' and Bob is unable to move.
2. In the second game the string "aaab" is selected. No matter what character Alice will delete, Bob deletes the other one and Alice is unable to move.
In the second example Alice wins both game "bdb" and "aaccbdb".
To win game "bdb" Alice can erase symbol 'd', the game then goes independently on strings "b" and "b". Bob deletes one of this strings and the Alice deletes the other one and Bob is unable to move.
To win game "aaccbdb" Alice can erase symbol 'd', the game then goes independently on strings "aaccb" and "b". It is possible to show, that no matter what are the moves, the remaining game can only finish in exactly 4 moves, so the Bob will be unable to move after that.
Submitted Solution:
```
n=input()
print('Alice')
if n=='aaab':
print('Bob')
else:
print('Alice')
``` | instruction | 0 | 29,117 | 0 | 58,234 |
No | output | 1 | 29,117 | 0 | 58,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice and Bob are playing a game on strings.
Initially, they have some string t. In one move the first player selects the character c present in t and erases all it's occurrences in t, thus splitting t into many smaller strings. The game then goes independently with each of the strings — to make the move player selects one of the strings and one of the characters there, deletes all occurrences and adds the remaining string back to the game.
Alice always starts the game, and then Alice and Bob take turns making moves. The player who is unable to make a move (because there is no string left) loses.
Alice and Bob used to always start with a string s, but recently they found out that this became too boring. Now before each game they choose two integers l and r such that 1 ≤ l ≤ r ≤ |s| and play the game with the string s_{l} s_{l+1} s_{l+2} … s_{r} instead.
Given the string s and integers l, r for each game. Find who is going to win each game assuming they are smart and are playing optimally.
Input
The first line contains the string s (1 ≤ |s| ≤ 10^5) consisting of lowercase English letters. This is the string Alice and Bob used to start with.
The second line contains a single integer m (1 ≤ m ≤ 10^5) — the number of games to analyze.
Each of the next m lines contains two integers l and r (1 ≤ l ≤ r ≤ |s|) — the bounds of the starting substring in the string s.
Output
For each game output a single line containing the name of the winner — "Alice" or "Bob" respectively.
Examples
Input
aaab
2
1 2
1 4
Output
Alice
Bob
Input
aaccbdb
2
5 7
1 7
Output
Alice
Alice
Note
In the first example,
1. In the first game the string "aa" is selected. Alice deletes character 'a' and Bob is unable to move.
2. In the second game the string "aaab" is selected. No matter what character Alice will delete, Bob deletes the other one and Alice is unable to move.
In the second example Alice wins both game "bdb" and "aaccbdb".
To win game "bdb" Alice can erase symbol 'd', the game then goes independently on strings "b" and "b". Bob deletes one of this strings and the Alice deletes the other one and Bob is unable to move.
To win game "aaccbdb" Alice can erase symbol 'd', the game then goes independently on strings "aaccb" and "b". It is possible to show, that no matter what are the moves, the remaining game can only finish in exactly 4 moves, so the Bob will be unable to move after that.
Submitted Solution:
```
def del_near(s):
del_s=''
for i in range(len(s)-1):
if s[i]!=s[i+1]:
del_s=del_s+s[i]
elif i>0 and i == len(s)-2 and s[i]==s[-1]:
del_s=del_s+s[i]
return len(del_s)
s=input()
m=int(input())
for i in range(m):
l,r=map(int,input().split())
subs=s[l-1:r]
if del_near(subs)%2==0:
print('Alice')
else:
print('Bob')
``` | instruction | 0 | 29,118 | 0 | 58,236 |
No | output | 1 | 29,118 | 0 | 58,237 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend | instruction | 0 | 29,220 | 0 | 58,440 |
Tags: binary search, dp, hashing, string suffix structures, strings
Correct Solution:
```
from sys import stdin,stdout,stderr
def lcp(string):
l=len(string)
lis=[0]*l
j=1
k=0
while j<l:
if string[j]==string[k]:
lis[j]=k+1
j+=1
k+=1
elif k>0:
k=lis[k-1]
else :j+=1
return lis
string=input()
lis=lcp(string)
if lis[-1]==0:
print("Just a legend")
exit()
for i in range(len(string)-1):
if lis[i]!=0 and lis[i]==lis[-1]:
print(string[:lis[-1]])
exit()
l=lis[-1]
if l==0:
print("Just a legend")
exit()
l=lis[lis[-1]-1]
if l:
print(string[:l])
exit()
print("Just a legend")
``` | output | 1 | 29,220 | 0 | 58,441 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend | instruction | 0 | 29,222 | 0 | 58,444 |
Tags: binary search, dp, hashing, string suffix structures, strings
Correct Solution:
```
## necessary imports
import sys
input = sys.stdin.readline
# from math import *
# swap_array function
def swaparr(arr, a,b):
temp = arr[a];
arr[a] = arr[b];
arr[b] = temp
## gcd function
def gcd(a,b):
if a == 0:
return b
return gcd(b%a, a)
## nCr function efficient using Binomial Cofficient
def nCr(n, k):
if(k > n - k):
k = n - k
res = 1
for i in range(k):
res = res * (n - i)
res = res / (i + 1)
return res
## upper bound function code -- such that e in a[:i] e < x;
def upper_bound(a, x, lo=0):
hi = len(a)
while lo < hi:
mid = (lo+hi)//2
if a[mid] < x:
lo = mid+1
else:
hi = mid
return lo
## prime factorization
def primefs(n):
## if n == 1 ## calculating primes
primes = {}
while(n%2 == 0):
primes[2] = primes.get(2, 0) + 1
n = n//2
for i in range(3, int(n**0.5)+2, 2):
while(n%i == 0):
primes[i] = primes.get(i, 0) + 1
n = n//i
if n > 2:
primes[n] = primes.get(n, 0) + 1
## prime factoriazation of n is stored in dictionary
## primes and can be accesed. O(sqrt n)
return primes
## MODULAR EXPONENTIATION FUNCTION
def power(x, y, p):
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1
x = (x * x) % p
return res
## DISJOINT SET UNINON FUNCTIONS
def swap(a,b):
temp = a
a = b
b = temp
return a,b
# find function with path compression included (recursive)
# def find(x, link):
# if link[x] == x:
# return x
# link[x] = find(link[x], link);
# return link[x];
# find function with path compression (ITERATIVE)
def find(x, link):
p = x;
while( p != link[p]):
p = link[p];
while( x != p):
nex = link[x];
link[x] = p;
x = nex;
return p;
# the union function which makes union(x,y)
# of two nodes x and y
def union(x, y, link, size):
x = find(x, link)
y = find(y, link)
if size[x] < size[y]:
x,y = swap(x,y)
if x != y:
size[x] += size[y]
link[y] = x
## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES
def sieve(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
#### PRIME FACTORIZATION IN O(log n) using Sieve ####
MAXN = int(1e6 + 5)
def spf_sieve():
spf[1] = 1;
for i in range(2, MAXN):
spf[i] = i;
for i in range(4, MAXN, 2):
spf[i] = 2;
for i in range(3, ceil(MAXN ** 0.5), 2):
if spf[i] == i:
for j in range(i*i, MAXN, i):
if spf[j] == j:
spf[j] = i;
## function for storing smallest prime factors (spf) in the array
################## un-comment below 2 lines when using factorization #################
# spf = [0 for i in range(MAXN)]
# spf_sieve()
def factoriazation(x):
ret = {};
while x != 1:
ret[spf[x]] = ret.get(spf[x], 0) + 1;
x = x//spf[x]
return ret
## this function is useful for multiple queries only, o/w use
## primefs function above. complexity O(log n)
## taking integer array input
def int_array():
return list(map(int, input().strip().split()))
## taking string array input
def str_array():
return input().strip().split();
#defining a couple constants
MOD = int(1e9)+7;
CMOD = 998244353;
INF = float('inf'); NINF = -float('inf');
################### ---------------- TEMPLATE ENDS HERE ---------------- ###################
def ComputeLPSArray(pat):
M = len(pat); lps = [0]*M;
length = 0; i = 1;
## lps[0] is already 0, so no need of lps[0] = 0;
while( i < M ):
if (pat[i] == pat[length]):
lps[i] = length + 1;
length += 1; i += 1;
else:
if length != 0:
length = lps[length - 1];
else:
lps[i] = 0;
i += 1;
return lps;
string = input().strip();
# string = 'aaaaabaaaa';
lps = ComputeLPSArray(string);
x = lps[ lps[-1] - 1 ];
if x <= 0:
x = -1;
k = lps[-1];
if lps.count(k) > 1 and k > 0:
pass;
else:
k = -1;
k = max(x, k);
if k > 0:
print(string[:k]);
else:
print('Just a legend');
``` | output | 1 | 29,222 | 0 | 58,445 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend | instruction | 0 | 29,223 | 0 | 58,446 |
Tags: binary search, dp, hashing, string suffix structures, strings
Correct Solution:
```
P=input()
m = len(P)
f=[0]*m
j=1
k=0
while j<m:
if P[j]==P[k]:
f[j]=k+1
j+=1
k+=1
elif k>0:
k=f[k-1]
else:
j+=1
l=f.pop()
if l:
if l in f:
print(P[:l])
elif f[l-1]:
print(P[:f[l-1]])
else:
print('Just a legend')
else:
print('Just a legend')
``` | output | 1 | 29,223 | 0 | 58,447 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
s = input()
n = len(s)
p = [0] * (n + 1)
i =0
j = 1
while j < n:
if s[j] == s[i]:
j += 1
i += 1
p[j] = i
elif i:
i = p[i]
else:
j += 1
a = p.pop()
b = p[a]
if (a) and (a in p):
print(s[:a])
elif (b):
print(s[:b])
else:
print('Just a legend')
``` | instruction | 0 | 29,227 | 0 | 58,454 |
Yes | output | 1 | 29,227 | 0 | 58,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
from typing import Tuple
def comp_z(s: str) -> Tuple[int]:
"""Computes the z-array for a given string s.
z[i] := the length of the longest substring of s, starting at index i, which is also a prefix of s.
0 <= i < len(s); z[0] = len(s).
"""
n = len(s)
z = [0] * n
z[0] = n
# left and right boundaries of the current right most z-box [L,R)
L, R = 0, 0
for i in range(1, n):
if i >= R:
L = i
R = i
while R < n and s[R] == s[R-L]:
R += 1
z[i] = R-L
else: # L < i < R
# len of [i,R)
x = R-i
if x > z[i-L]:
z[i] = z[i-L]
else: # x <= z[i-L] and we know s[i..R) matches prefix
L = i
# continue matching from R onwards
while R < n and s[R] == s[R-L]:
R += 1
z[i] = R-L
return tuple(z)
def run():
"""Solves https://codeforces.com/contest/126/problem/B."""
s = input()
n = len(s)
z = comp_z(s)
maxz = 0
res = 0
for i in range(1, n):
if z[i] == n-i and maxz >= n-i:
res = n-i
# break as we already found the longest one;
# as i increases, the length decreases
break
maxz = max(maxz, z[i])
if res == 0:
print('Just a legend')
else:
print(s[:res])
if __name__ == "__main__":
run()
``` | instruction | 0 | 29,228 | 0 | 58,456 |
Yes | output | 1 | 29,228 | 0 | 58,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
#!/usr/bin/env python3
# created : 2020. 12. 31. 23:59
import os
from sys import stdin, stdout
def getPrefixFunction(w):
m = len(w)
pf = [0 for i in range(m)]
j = 0
for i in range(1, m):
while j > 0 and w[i] != w[j]:
j = pf[j-1]
if w[i] == w[j]:
j += 1
pf[i] = j
return pf
def solve(tc):
s = stdin.readline().strip()
n = len(s)
pf = getPrefixFunction(s)
if pf[n-1] == 0:
print("Just a legend")
return
for i in range(1, n-1):
if pf[i] == pf[n-1]:
print(s[:pf[n-1]])
return
k = pf[pf[n-1]-1]
if k > 0:
print(s[:k])
return
print("Just a legend")
tcs = 1
# tcs = int(stdin.readline().strip())
tc = 1
while tc <= tcs:
solve(tc)
tc += 1
``` | instruction | 0 | 29,229 | 0 | 58,458 |
Yes | output | 1 | 29,229 | 0 | 58,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
def knuthMorrisonPreprocess(pattern , m ):
fail = [0]*m
i = 0
j= 1
fail[0]=0
while(j < m ):
if pattern[i] == pattern[j]:
fail[j]= i+1
i+=1
j+=1
elif i > 0:
i = fail[i-1]
else:
j+=1
return fail
string = input()
n = len(string)
properPrefixArrayL = knuthMorrisonPreprocess(string , n )
properPrefixArray =properPrefixArrayL[-1]
if properPrefixArray == 0:
print("Just a legend")
quit()
for i in range(0,n-1):
if properPrefixArrayL[i] == properPrefixArrayL[n-1]:
print(string[0:properPrefixArrayL[i]])
quit()
if properPrefixArrayL[properPrefixArrayL[n-1]-1] == 0:
print("Just a legend")
else:
print(string[0:properPrefixArrayL[properPrefixArrayL[n-1]-1]])
``` | instruction | 0 | 29,230 | 0 | 58,460 |
Yes | output | 1 | 29,230 | 0 | 58,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
from collections import Counter
'''
def fun(s):
a=Counter(s)
n=[]
for i in range(len(s)):
if s[i] not in a:
break
else:
if a[s[i]]<3:
break
else:
n.append(s[i])
a[s[i]]=a[s[i]]-1
if a[s[i]]<=1:
break
if len(n)>0:
ns="".join(n)
j=ns
sf=s[len(s)-len(ns):]
if(j==sf):
return ns
else:
return "Just a legend"
else:
return "Just a legend"
'''
def au(s):
p=len(s)
for l in reversed(range(0,p)):
two= s[l:].find(s[0:l])
if two>0:
#print("-->"+s[0:l])
rel=l+two
#print(rel)
tree=s[rel+len(s[0:l]):].find(s[0:l])
rel2=(tree+rel+len(s[0:l]))
if tree>0:
break
if rel2!=rel and rel!=0:
return s[0:l]
else:
return "Just a legend"
if __name__ == '__main__':
s=str(input())
print(au(s))
``` | instruction | 0 | 29,231 | 0 | 58,462 |
No | output | 1 | 29,231 | 0 | 58,463 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
#code
import sys
import math as mt
#input=sys.stdin.buffer.readline
#t=int(input())
#tot=0
t=1
def getZarr(string, z):
n = len(string)
# [L,R] make a window which matches
# with prefix of s
l, r, k = 0, 0, 0
for i in range(1, n):
# if i>R nothing matches so we will calculate.
# Z[i] using naive way.
if i > r:
l, r = i, i
# R-L = 0 in starting, so it will start
# checking from 0'th index. For example,
# for "ababab" and i = 1, the value of R
# remains 0 and Z[i] becomes 0. For string
# "aaaaaa" and i = 1, Z[i] and R become 5
while r < n and string[r - l] == string[r]:
r += 1
z[i] = r - l
r -= 1
else:
# k = i-L so k corresponds to number which
# matches in [L,R] interval.
k = i - l
# if Z[k] is less than remaining interval
# then Z[i] will be equal to Z[k].
# For example, str = "ababab", i = 3, R = 5
# and L = 2
if z[k] < r - i + 1:
z[i] = z[k]
# For example str = "aaaaaa" and i = 2,
# R is 5, L is 0
else:
# else start from R and check manually
l = i
while r < n and string[r - l] == string[r]:
r += 1
z[i] = r - l
r -= 1
for __ in range(t):
#n=int(input())
#l=list(map(int,input().split()))
#n,m=map(int,input().split())
#l=list(map(int,input().split()))
s=input()
z=[0]*(len(s)+1)
d={}
n=len(s)
getZarr(s, z)
#print(z)
d=[]
maxm=-1
for i in range(len(s)):
if i+z[i]!=n :
maxm=max(maxm,z[i])
else:
d.append(z[i])
maxi=-1
d.sort()
for i in range(len(s)):
if i+z[i]==n:
maxi=max(maxi,maxm)
if d[-1]!=z[i]:
maxi=max(maxi,z[i])
if maxi>0:
print(s[:maxi])
else:
print("Just a legend")
``` | instruction | 0 | 29,232 | 0 | 58,464 |
No | output | 1 | 29,232 | 0 | 58,465 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
## necessary imports
import sys
input = sys.stdin.readline
from math import log2, log, ceil
# swap_array function
def swaparr(arr, a,b):
temp = arr[a];
arr[a] = arr[b];
arr[b] = temp
## gcd function
def gcd(a,b):
if a == 0:
return b
return gcd(b%a, a)
## nCr function efficient using Binomial Cofficient
def nCr(n, k):
if(k > n - k):
k = n - k
res = 1
for i in range(k):
res = res * (n - i)
res = res / (i + 1)
return res
## upper bound function code -- such that e in a[:i] e < x;
def upper_bound(a, x, lo=0):
hi = len(a)
while lo < hi:
mid = (lo+hi)//2
if a[mid] < x:
lo = mid+1
else:
hi = mid
return lo
## prime factorization
def primefs(n):
## if n == 1 ## calculating primes
primes = {}
while(n%2 == 0):
primes[2] = primes.get(2, 0) + 1
n = n//2
for i in range(3, int(n**0.5)+2, 2):
while(n%i == 0):
primes[i] = primes.get(i, 0) + 1
n = n//i
if n > 2:
primes[n] = primes.get(n, 0) + 1
## prime factoriazation of n is stored in dictionary
## primes and can be accesed. O(sqrt n)
return primes
## MODULAR EXPONENTIATION FUNCTION
def power(x, y, p):
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1
x = (x * x) % p
return res
## DISJOINT SET UNINON FUNCTIONS
def swap(a,b):
temp = a
a = b
b = temp
return a,b
# find function with path compression included (recursive)
# def find(x, link):
# if link[x] == x:
# return x
# link[x] = find(link[x], link);
# return link[x];
# find function with path compression (ITERATIVE)
def find(x, link):
p = x;
while( p != link[p]):
p = link[p];
while( x != p):
nex = link[x];
link[x] = p;
x = nex;
return p;
# the union function which makes union(x,y)
# of two nodes x and y
def union(x, y, link, size):
x = find(x, link)
y = find(y, link)
if size[x] < size[y]:
x,y = swap(x,y)
if x != y:
size[x] += size[y]
link[y] = x
## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES
def sieve(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
#### PRIME FACTORIZATION IN O(log n) using Sieve ####
MAXN = int(1e6 + 5)
def spf_sieve():
spf[1] = 1;
for i in range(2, MAXN):
spf[i] = i;
for i in range(4, MAXN, 2):
spf[i] = 2;
for i in range(3, ceil(MAXN ** 0.5), 2):
if spf[i] == i:
for j in range(i*i, MAXN, i):
if spf[j] == j:
spf[j] = i;
## function for storing smallest prime factors (spf) in the array
################## un-comment below 2 lines when using factorization #################
spf = [0 for i in range(MAXN)]
spf_sieve()
def factoriazation(x):
ret = {};
while x != 1:
ret[spf[x]] = ret.get(spf[x], 0) + 1;
x = x//spf[x]
return ret
## this function is useful for multiple queries only, o/w use
## primefs function above. complexity O(log n)
## taking integer array input
def int_array():
return list(map(int, input().strip().split()))
## taking string array input
def str_array():
return input().strip().split();
#defining a couple constants
MOD = int(1e9)+7;
CMOD = 998244353;
INF = float('inf'); NINF = -float('inf');
################### ---------------- TEMPLATE ENDS HERE ---------------- ###################
def ComputeLPSArray(pat):
M = len(pat); lps = [0]*M;
length = 0; i = 1;
## lps[0] is already 0, so no need of lps[0] = 0;
while( i < M ):
if (pat[i] == pat[length]):
lps[i] = length + 1;
length += 1; i += 1;
else:
if length != 0:
length = lps[length - 1];
else:
lps[i] = 0;
i += 1;
return lps;
string = input().strip();
a = ComputeLPSArray(string);
k = a[-1];
if k > 0 and a.count(k) > 1:
print(string[:k]);
else:
print("Just a legend");
``` | instruction | 0 | 29,233 | 0 | 58,466 |
No | output | 1 | 29,233 | 0 | 58,467 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.
Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.
Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened.
You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.
Input
You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output
Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.
Examples
Input
fixprefixsuffix
Output
fix
Input
abcdabc
Output
Just a legend
Submitted Solution:
```
s = list(input())
n = len(s)
exit = False
for i in range(n - 3, -1, -1):
#print(s[-1-i:])
#print(s[:i])
if (s[:i + 1] == s[-1-i:]):
for j in range(1, n - 2 - i):
if (s[:i + 1] == s[j:j + 1 + i]):
print(''.join(s[:i + 1]))
exit = True
break
if (exit):
break
if (not exit):
print('Just a legend')
``` | instruction | 0 | 29,234 | 0 | 58,468 |
No | output | 1 | 29,234 | 0 | 58,469 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A and B are preparing themselves for programming contests.
After several years of doing sports programming and solving many problems that require calculating all sorts of abstract objects, A and B also developed rather peculiar tastes.
A likes lowercase letters of the Latin alphabet. He has assigned to each letter a number that shows how much he likes that letter (he has assigned negative numbers to the letters he dislikes).
B likes substrings. He especially likes the ones that start and end with the same letter (their length must exceed one).
Also, A and B have a string s. Now they are trying to find out how many substrings t of a string s are interesting to B (that is, t starts and ends with the same letter and its length is larger than one), and also the sum of values of all letters (assigned by A), except for the first and the last one is equal to zero.
Naturally, A and B have quickly found the number of substrings t that are interesting to them. Can you do it?
Input
The first line contains 26 integers xa, xb, ..., xz ( - 105 ≤ xi ≤ 105) — the value assigned to letters a, b, c, ..., z respectively.
The second line contains string s of length between 1 and 105 characters, consisting of Lating lowercase letters— the string for which you need to calculate the answer.
Output
Print the answer to the problem.
Examples
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
xabcab
Output
2
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
aaa
Output
2
Note
In the first sample test strings satisfying the condition above are abca and bcab.
In the second sample test strings satisfying the condition above are two occurences of aa. | instruction | 0 | 29,525 | 0 | 59,050 |
Tags: data structures, dp, two pointers
Correct Solution:
```
x=list(map(int,input().split()))
s=list(input().rstrip())
n=len(s)
cx=[0]*(n+1)
for i in range(1,n+1):
cx[i]=x[ord(s[i-1])-ord("a")]
for i in range(1,n+1):
cx[i]+=cx[i-1]
pos=[{} for i in range(26)]
ans=0
for i in range(n):
ss=s[i]
ans+=pos[ord(ss)-ord("a")].get(cx[i],0)
pos[ord(ss)-ord("a")][cx[i+1]]=pos[ord(ss)-ord("a")].get(cx[i+1],0)+1
print(ans)
``` | output | 1 | 29,525 | 0 | 59,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A and B are preparing themselves for programming contests.
After several years of doing sports programming and solving many problems that require calculating all sorts of abstract objects, A and B also developed rather peculiar tastes.
A likes lowercase letters of the Latin alphabet. He has assigned to each letter a number that shows how much he likes that letter (he has assigned negative numbers to the letters he dislikes).
B likes substrings. He especially likes the ones that start and end with the same letter (their length must exceed one).
Also, A and B have a string s. Now they are trying to find out how many substrings t of a string s are interesting to B (that is, t starts and ends with the same letter and its length is larger than one), and also the sum of values of all letters (assigned by A), except for the first and the last one is equal to zero.
Naturally, A and B have quickly found the number of substrings t that are interesting to them. Can you do it?
Input
The first line contains 26 integers xa, xb, ..., xz ( - 105 ≤ xi ≤ 105) — the value assigned to letters a, b, c, ..., z respectively.
The second line contains string s of length between 1 and 105 characters, consisting of Lating lowercase letters— the string for which you need to calculate the answer.
Output
Print the answer to the problem.
Examples
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
xabcab
Output
2
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
aaa
Output
2
Note
In the first sample test strings satisfying the condition above are abca and bcab.
In the second sample test strings satisfying the condition above are two occurences of aa. | instruction | 0 | 29,526 | 0 | 59,052 |
Tags: data structures, dp, two pointers
Correct Solution:
```
xx = [int(i) for i in input().split()]
s = input()
x = [{} for _ in range(0,26)]
ss = 0
ans = 0
for i in s:
ans += x[ord(i)-97].get(ss,0)
ss += xx[ord(i)-97]
x[ord(i)-97][ss] = x[ord(i)-97].get(ss,0)+1
print(ans)
``` | output | 1 | 29,526 | 0 | 59,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A and B are preparing themselves for programming contests.
After several years of doing sports programming and solving many problems that require calculating all sorts of abstract objects, A and B also developed rather peculiar tastes.
A likes lowercase letters of the Latin alphabet. He has assigned to each letter a number that shows how much he likes that letter (he has assigned negative numbers to the letters he dislikes).
B likes substrings. He especially likes the ones that start and end with the same letter (their length must exceed one).
Also, A and B have a string s. Now they are trying to find out how many substrings t of a string s are interesting to B (that is, t starts and ends with the same letter and its length is larger than one), and also the sum of values of all letters (assigned by A), except for the first and the last one is equal to zero.
Naturally, A and B have quickly found the number of substrings t that are interesting to them. Can you do it?
Input
The first line contains 26 integers xa, xb, ..., xz ( - 105 ≤ xi ≤ 105) — the value assigned to letters a, b, c, ..., z respectively.
The second line contains string s of length between 1 and 105 characters, consisting of Lating lowercase letters— the string for which you need to calculate the answer.
Output
Print the answer to the problem.
Examples
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
xabcab
Output
2
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
aaa
Output
2
Note
In the first sample test strings satisfying the condition above are abca and bcab.
In the second sample test strings satisfying the condition above are two occurences of aa. | instruction | 0 | 29,527 | 0 | 59,054 |
Tags: data structures, dp, two pointers
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
#from bisect import bisect_left as bl #c++ lowerbound bl(array,element)
#from bisect import bisect_right as br #c++ upperbound br(array,element)
from collections import *
def main():
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
values=list(map(int,input().split(" ")))
s=input()
dic=defaultdict(lambda:[])
pre=[0 for x in range(len(s)+1)]
for x in range(len(s)):
pre[x+1]=pre[x]+values[ord(s[x])-ord('a')]
dic[s[x]].append(x)
ans=0
for x,y in dic.items():
here=defaultdict(lambda:0)
for z in y:
if pre[z] in here:
ans+=here[pre[z]]
here[pre[z+1]]+=1
print(ans)
#-----------------------------hey angel-------------------------------------!
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | output | 1 | 29,527 | 0 | 59,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A and B are preparing themselves for programming contests.
After several years of doing sports programming and solving many problems that require calculating all sorts of abstract objects, A and B also developed rather peculiar tastes.
A likes lowercase letters of the Latin alphabet. He has assigned to each letter a number that shows how much he likes that letter (he has assigned negative numbers to the letters he dislikes).
B likes substrings. He especially likes the ones that start and end with the same letter (their length must exceed one).
Also, A and B have a string s. Now they are trying to find out how many substrings t of a string s are interesting to B (that is, t starts and ends with the same letter and its length is larger than one), and also the sum of values of all letters (assigned by A), except for the first and the last one is equal to zero.
Naturally, A and B have quickly found the number of substrings t that are interesting to them. Can you do it?
Input
The first line contains 26 integers xa, xb, ..., xz ( - 105 ≤ xi ≤ 105) — the value assigned to letters a, b, c, ..., z respectively.
The second line contains string s of length between 1 and 105 characters, consisting of Lating lowercase letters— the string for which you need to calculate the answer.
Output
Print the answer to the problem.
Examples
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
xabcab
Output
2
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
aaa
Output
2
Note
In the first sample test strings satisfying the condition above are abca and bcab.
In the second sample test strings satisfying the condition above are two occurences of aa. | instruction | 0 | 29,528 | 0 | 59,056 |
Tags: data structures, dp, two pointers
Correct Solution:
```
w = [int(x) for x in input().split()]
c = [{} for i in range(26)]
val, s = 0, 0
for i in [ord(ch) - ord('a') for ch in input()]:
if s - w[i] in c[i]:
val += c[i][s - w[i]]
c[i][s] = c[i][s] + 1 if s in c[i] else 1
s += w[i]
print(val)
``` | output | 1 | 29,528 | 0 | 59,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A and B are preparing themselves for programming contests.
After several years of doing sports programming and solving many problems that require calculating all sorts of abstract objects, A and B also developed rather peculiar tastes.
A likes lowercase letters of the Latin alphabet. He has assigned to each letter a number that shows how much he likes that letter (he has assigned negative numbers to the letters he dislikes).
B likes substrings. He especially likes the ones that start and end with the same letter (their length must exceed one).
Also, A and B have a string s. Now they are trying to find out how many substrings t of a string s are interesting to B (that is, t starts and ends with the same letter and its length is larger than one), and also the sum of values of all letters (assigned by A), except for the first and the last one is equal to zero.
Naturally, A and B have quickly found the number of substrings t that are interesting to them. Can you do it?
Input
The first line contains 26 integers xa, xb, ..., xz ( - 105 ≤ xi ≤ 105) — the value assigned to letters a, b, c, ..., z respectively.
The second line contains string s of length between 1 and 105 characters, consisting of Lating lowercase letters— the string for which you need to calculate the answer.
Output
Print the answer to the problem.
Examples
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
xabcab
Output
2
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
aaa
Output
2
Note
In the first sample test strings satisfying the condition above are abca and bcab.
In the second sample test strings satisfying the condition above are two occurences of aa. | instruction | 0 | 29,529 | 0 | 59,058 |
Tags: data structures, dp, two pointers
Correct Solution:
```
score=[]
from collections import *
z=list(map(int,input().split()))
s=input()
for i in range(26):
score.append(defaultdict(int))
pre=[]
total=0
for i in range(len(s)):
s1=z[ord(s[i])-97]
t=ord(s[i])-97
if(i==0):
pre.append(s1)
else:
pre.append(pre[-1]+s1)
s1=pre[-1]
score[t][s1]+=1
if(z[t]==0):
total+=max(0,score[t][s1]-1)
else:
total+=max(0,score[t][s1-z[t]])
print(total)
``` | output | 1 | 29,529 | 0 | 59,059 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A and B are preparing themselves for programming contests.
After several years of doing sports programming and solving many problems that require calculating all sorts of abstract objects, A and B also developed rather peculiar tastes.
A likes lowercase letters of the Latin alphabet. He has assigned to each letter a number that shows how much he likes that letter (he has assigned negative numbers to the letters he dislikes).
B likes substrings. He especially likes the ones that start and end with the same letter (their length must exceed one).
Also, A and B have a string s. Now they are trying to find out how many substrings t of a string s are interesting to B (that is, t starts and ends with the same letter and its length is larger than one), and also the sum of values of all letters (assigned by A), except for the first and the last one is equal to zero.
Naturally, A and B have quickly found the number of substrings t that are interesting to them. Can you do it?
Input
The first line contains 26 integers xa, xb, ..., xz ( - 105 ≤ xi ≤ 105) — the value assigned to letters a, b, c, ..., z respectively.
The second line contains string s of length between 1 and 105 characters, consisting of Lating lowercase letters— the string for which you need to calculate the answer.
Output
Print the answer to the problem.
Examples
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
xabcab
Output
2
Input
1 1 -1 1 1 1 1 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1 1
aaa
Output
2
Note
In the first sample test strings satisfying the condition above are abca and bcab.
In the second sample test strings satisfying the condition above are two occurences of aa. | instruction | 0 | 29,530 | 0 | 59,060 |
Tags: data structures, dp, two pointers
Correct Solution:
```
score=[]
from collections import *
z=list(map(int,input().split()))
s=input()
for i in range(26):
score.append(defaultdict(int))
pre=[]
total=0
for i in range(len(s)):
s1=z[ord(s[i])-97]
t=ord(s[i])-97
if(i==0):
pre.append(s1)
else:
pre.append(pre[-1]+s1)
s1=pre[-1]
score[t][s1]+=1
if(z[t]==0):
total+=max(0,score[t][s1]-1)
else:
total+=max(0,score[t][s1-z[t]])
fin=[]
count=1
for i in range(1,len(s)):
if(s[i]==s[i-1]):
count+=1
else:
fin.append([count,s[i-1]])
count=1
fin.append([count,s[-1]])
print(total)
``` | output | 1 | 29,530 | 0 | 59,061 |
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