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stringlengths 2
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int64 97
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int64 194
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|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
|
instruction
| 0
| 13,418
| 0
| 26,836
|
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
n=int(input())
s=input()
rama=[]
for i in range(n):
rama.append(ord(s[i])-96)
visit=[1 for i in range(27)]
a=[]
maxi=0
for i in range(n):
p=visit[rama[i]]
a.append(p)
maxi=max(maxi,p)
for j in range(rama[i]):
visit[j]=max(visit[j],p+1)
print(maxi)
for i in a:
print(i,end=' ')
```
|
output
| 1
| 13,418
| 0
| 26,837
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
# -*- coding: utf-8 -*-
import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
# sys.setrecursionlimit(10 ** 9)
INF = 10 ** 18
MOD = 10 ** 9 + 7
def bisearch_min(mn, mx, func):
ok = mx
ng = mn
while ng+1 < ok:
mid = (ok+ng) // 2
if func(mid):
ok = mid
else:
ng = mid
return ok
def check(m):
if m == len(B):
return True
if B[m][-1][0] <= a:
return True
else:
return False
N = INT()
A = [ord(c)-97 for c in input()]
B = [[] for i in range(1)]
B[0].append((A[0], 0))
for i, a in enumerate(A[1:], 1):
idx = bisearch_min(-1, len(B), check)
if idx == len(B):
B.append([(a, i)])
else:
B[idx].append((a, i))
ans = [0] * N
for a, li in enumerate(B):
for _, idx in li:
ans[idx] = str(a)
if len(B) <= 2:
YES()
print(''.join(ans))
else:
NO()
```
|
instruction
| 0
| 13,419
| 0
| 26,838
|
Yes
|
output
| 1
| 13,419
| 0
| 26,839
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
n = int(input())
s = input()
g = {}
for i in range(len(s)):
g[i] = []
for i in range(len(s)):
for j in range(i):
if s[j] > s[i]:
g[i].append(j)
g[j].append(i)
colored = [False] * len(s)
color = [None] * len(s)
def brush(v, c):
colored[v] = True
color[v] = c
for n in g[v]:
if colored[n]:
if color[n] == c:
return False
else:
if not brush(n, c ^ 1):
return False
return True
failed = False
for i in range(len(s)):
if not colored[i]:
if not brush(i, 0):
failed = True
break
if failed:
print ('NO')
else:
print ('YES')
print (''.join( map(lambda i: '1' if color[i] == 1 else '0', range(len(s))) ))
```
|
instruction
| 0
| 13,420
| 0
| 26,840
|
Yes
|
output
| 1
| 13,420
| 0
| 26,841
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
import io
import os
from collections import Counter, defaultdict, deque
def solve(N, S):
# Same color must be already sorted since they can't be swapped with each other
# Greedily build increasing subsequences
indices = [[0]]
# last value -> which list
for i, x in enumerate(S[1:], 1):
for l in indices:
if S[l[-1]] <= x:
l.append(i)
break
else:
indices.append([i])
ans = [None for i in range(N)]
for color, l in enumerate(indices):
for i in l:
ans[i] = color
# Format for E1
if len(indices) <= 2:
return "YES\n" + "".join(map(str, ans))
else:
return 'NO'
# Format for E2
possible = str(len(indices))
return possible + "\n" + " ".join(str(x + 1) for x in ans)
if __name__ == "__main__":
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
(N,) = [int(x) for x in input().split()]
S = input().decode().rstrip()
ans = solve(N, S)
print(ans)
```
|
instruction
| 0
| 13,421
| 0
| 26,842
|
Yes
|
output
| 1
| 13,421
| 0
| 26,843
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
def find(x):
r = x
while r != f[r]:
r = f[r]
while x != r:
pre = f[x]
f[x] = r
x = pre
return r
a = input()
n = int(a)
a = input()
str = list(a)
id = [0] * n
f = [0] * 2 * n
name = [0] * 2 * n
for i in range(n):
id[i] = i
for i in range(2 * n):
f[i] = i
name[i] = -1
Find = 0
for i in range(n):
if Find:
break
for j in range(n - i - 1):
if str[j] > str[j + 1]:
str[j], str[j + 1] = str[j + 1], str[j]
id[j], id[j + 1] = id[j + 1], id[j]
fx = find(id[j])
fnx = find(id[j] + n)
fy = find(id[j + 1])
fny = find(id[j + 1] + n)
if fx == fy or fnx == fny:
Find = 1
break
else:
f[fx] = fny
f[fy] = fnx
if Find:
print('NO')
else:
print('YES')
for i in range(n):
fx = find(i)
if name[fx] < 0:
name[fx] = 0
if(fx >= n):
name[find(fx - n)] = 1
else:
name[find(fx + n)] = 1
print('{:d}'.format(name[fx]), end = '')
```
|
instruction
| 0
| 13,422
| 0
| 26,844
|
Yes
|
output
| 1
| 13,422
| 0
| 26,845
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
import math
import sys
from collections import defaultdict
def stdinWrapper():
data = '''8
aaabbcbb
'''
for line in data.split('\n'):
yield line
if '--debug' not in sys.argv:
def stdinWrapper():
while True:
yield input()
inputs = stdinWrapper()
def inputWrapper():
return next(inputs)
def getType(_type):
return _type(inputWrapper())
def getArray(_type):
return [_type(x) for x in inputWrapper().split()]
''' Solution '''
l = getType(int)
_str = getType(str)
dp = [1] * l
maxdp = [0] * 26
dp = [1] * len(_str)
p = [-1] * len(_str)
for i in range(1, len(_str)):
for c in range(ord(_str[i])-ord('a')+1, 26):
dp[i] = max(dp[i], maxdp[c]+1)
maxdp[ord(_str[i]) - ord('a')] = max(dp[i], maxdp[ord(_str[i]) - ord('a')])
pos = -1
_max = 0
for i in range(len(_str)):
if dp[i] > _max:
_max = dp[i]
pos = i
result = []
while True:
if pos == -1:
break
result.append(_str[pos])
pos = p[pos]
print(max(dp))
print(' '.join([str(x) for x in dp]))
```
|
instruction
| 0
| 13,423
| 0
| 26,846
|
No
|
output
| 1
| 13,423
| 0
| 26,847
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
import sys
import math
from collections import defaultdict,Counter
# input=sys.stdin.readline
# def print(x):
# sys.stdout.write(str(x)+"\n")
# sys.stdout=open("CP1/output.txt",'w')
# sys.stdin=open("CP1/input.txt",'r')
# m=pow(10,9)+7
n=int(input())
s=list(input())
s2=s[:]
s1=sorted(s)
c=[0]*n
# c1=[0]*n
for j in range(1,n):
if s[j]<s[j-1]:
c[j]=1-c[j-1]
# c1[j]=1-c1[j-1]
elif s[j]==s[j-1]:
c[j]=c[j-1]
c2=''.join(list(map(str,c)))
flag=0
# print(c)
while s!=s1:
for j in range(1,n):
if s[j]<s[j-1]:
if c[j]!=c[j-1]:
c[j],c[j-1]=c[j-1],c[j]
s[j],s[j-1]=s[j-1],s[j]
else:
flag=1
break
if flag==1:
break
# for j in range(1,n):
# if s[j]<s[j-1]:
# c[j]=1-c[j-1]
# else:
# c[j]=c[j-1]
# print(s)
# print(c)
if flag==0:
print("YES")
print(c2)
else:
print("NO")
# else:
# flag=0
# c2=''.join(list(map(str,c1)))
# # c2=c1[:]
# s=s2[:]
# while s!=s1:
# for j in range(1,n):
# if s[j]<s[j-1]:
# if c1[j]!=c1[j-1]:
# c1[j],c1[j-1]=c1[j-1],c1[j]
# s[j],s[j-1]=s[j-1],s[j]
# else:
# flag=1
# break
# if flag==1:
# break
# if flag==0:
# print("YES")
# print(c2)
# else:
# print("NO")
```
|
instruction
| 0
| 13,424
| 0
| 26,848
|
No
|
output
| 1
| 13,424
| 0
| 26,849
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
from sys import stdin, stdout
def main():
n = int(stdin.readline())
s = stdin.readline().rstrip()
h1 = 'A'
h2 = 'B'
res = []
for i,x in enumerate(s):
if i == 0:
res.append("0")
h1 = s[i]
continue
if s[i] < h1 and s[i] < h2:
stdout.write("NO")
return
if s[i] > h1:
h2 = 'B'
h1 = s[i]
res.append("0")
elif s[i] > h2:
h2 = s[i]
res.append("1")
else:
res.append("1")
stdout.write("YES\n" + "".join(res))
main()
```
|
instruction
| 0
| 13,425
| 0
| 26,850
|
No
|
output
| 1
| 13,425
| 0
| 26,851
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n lowercase Latin letters.
You have to color all its characters one of the two colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in s).
After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.
The goal is to make the string sorted, i.e. all characters should be in alphabetical order.
Your task is to say if it is possible to color the given string so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.
Input
The first line of the input contains one integer n (1 ≤ n ≤ 200) — the length of s.
The second line of the input contains the string s consisting of exactly n lowercase Latin letters.
Output
If it is impossible to color the given string so that after coloring it can become sorted by some sequence of swaps, print "NO" (without quotes) in the first line.
Otherwise, print "YES" in the first line and any correct coloring in the second line (the coloring is the string consisting of n characters, the i-th character should be '0' if the i-th character is colored the first color and '1' otherwise).
Examples
Input
9
abacbecfd
Output
YES
001010101
Input
8
aaabbcbb
Output
YES
01011011
Input
7
abcdedc
Output
NO
Input
5
abcde
Output
YES
00000
Submitted Solution:
```
def binSearch(a, n):
i, j = 0, len(a) - 1
while i != j:
if (j - i) % 2 == 1:
if a[i + ((j - i) // 2)] > n:
i = i + (j - i) // 2 + 1
else:
j = i + (j - i) // 2
else:
if a[i + (j - i) // 2] > n:
i = i + (j - i) // 2
else:
j = i + (j - i) // 2
return i
input()
k = ['a', 'a']
ans = ''
maxColor = 1
for symb in input():
i = binSearch(k, symb)
ans += str(i + 1)
if i + 1 > maxColor:
maxColor = i + 1
k.append('a')
k[i] = symb
print(maxColor)
print(*ans)
```
|
instruction
| 0
| 13,426
| 0
| 26,852
|
No
|
output
| 1
| 13,426
| 0
| 26,853
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,454
| 0
| 26,908
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
def solve(arr, n , m ) :
fix = arr[0]
for t in range(m) :
ch = fix[t]
for k in range(26) :
fix[t] = chr(ord('a') + k )
flag = True
for i in range(n) :
count = 0
for j in range(m) :
if arr[i][j] != fix[j] :
count +=1
if count >1 :
flag= False
break
if flag == True :
return ''.join(fix)
fix[t] = ch
return -1
for T in range(int(input())) :
n , m = list(map(int,input().split()))
arr = []
for i in range(n) :
arr.append(list(input()))
v = solve(arr,n , m)
print(v)
```
|
output
| 1
| 13,454
| 0
| 26,909
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,455
| 0
| 26,910
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
t=int(input())
for _ in range(t):
n,m=map(int,input().split())
s=[]
for _ in range(n):
s.append(input())
ans=list(s[0])
l=[]
for i in range(m):
for j in range(26):
ans[i]=chr(j+97)
l.append(''.join(ans))
ans[i]=s[0][i]
nf=0
for i in l:
flag=0
for j in s:
ct=0
for k in range(m):
if j[k]!=i[k]:
ct+=1
if ct>1:
flag=1
break
if flag==0:
print(''.join(i))
nf=1
break
if nf==0:
print('-1')
```
|
output
| 1
| 13,455
| 0
| 26,911
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,456
| 0
| 26,912
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
import math
import string
def change(s, i, symbol):
ans = s[0:i] + symbol + s[(i + 1):]
return ans
def check(a, n, m, s):
ans = 0
for i in range(n):
cnt = 0
for j in range(m):
if(a[i][j] != s[j]):
cnt += 1
if(cnt > 1):
return 0
return 1
t = int(input())
for ttt in range(t):
n, m = map(int, input().split())
a = []
for i in range(n):
a.append(str(input()))
s = a[0]
ans = 0
for j in range(m):
if(ans == 1):
break
for c in string.ascii_lowercase:
now = change(s, j, c)
if(check(a, n, m, now)):
ans = 1
print(now)
break
if(ans == 0):
print(-1)
```
|
output
| 1
| 13,456
| 0
| 26,913
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,457
| 0
| 26,914
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
import string
def spystring(words):
def neigh(word):
candidates = {word}
for i in range(len(word)):
for c in string.ascii_lowercase:
candidates.add(word[:i] + c + word[i + 1:])
return candidates
intersection = neigh(words[0])
for word in words[1:]:
intersection &= neigh(word)
return intersection and intersection.pop() or -1
def solve():
n, m = map(int, input().split())
s = [input() for _ in range(n)]
print(spystring(s))
for _ in range(int(input())):
solve()
```
|
output
| 1
| 13,457
| 0
| 26,915
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,458
| 0
| 26,916
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
import sys
import math
from collections import defaultdict,deque
import heapq
t = int(sys.stdin.readline())
for _ in range(t):
n,m = map(int,sys.stdin.readline().split())
l =[]
for i in range(n):
s = sys.stdin.readline()[:-1]
l.append(s)
#print(l,'l')
ind = -1
z = True
till = -1
for i in range(m):
#z = True
let = l[0][i]
for j in range(n):
if l[j][i] != let:
z = False
ind = j
till = i
break
if not z:
break
if z:
print(l[0])
continue
z = True
for k in range(26):
ans = l[0][:till] + chr(97+k) + l[0][till+1:]
z=True
for i in range(n):
cnt = 0
for j in range(m):
if l[i][j] != ans[j]:
cnt += 1
#print(cnt,'cnt',i,'i')
if cnt > 1:
z = False
break
if z:
print(ans)
break
if z:
continue
z = True
for k in range(26):
ans = l[ind][:till] + chr(97+k) + l[ind][till+1:]
z=True
for i in range(n):
cnt = 0
for j in range(m):
if l[i][j] != ans[j]:
cnt += 1
#print(cnt,'cnt',i,'i')
if cnt > 1:
z = False
break
if z:
print(ans)
break
if not z:
print(-1)
```
|
output
| 1
| 13,458
| 0
| 26,917
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,459
| 0
| 26,918
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
#import math
#from functools import lru_cache
#import heapq
#from collections import defaultdict
#from collections import Counter
#from sys import stdout
#from sys import setrecursionlimit
from sys import stdin
input = stdin.readline
for Ti in range(int(input().strip())):
n, m = [int(x) for x in input().strip().split()]
sa = []
for ni in range(n):
sa.append(input().strip())
s1 = sa[0]
val = True
ans = ''
for m1 in range(m):
for ci in list('abcdefghijklmnopqrstuvwwxyz'):
s1 = sa[0]
s1 = s1[:m1] + ci + s1[m1+1:]
#print(s1)
val = True
for ni in range(n):
dc = 0
for mi in range(m):
if(sa[ni][mi]!=s1[mi]): dc+=1
if(dc>1):
val=False
break
if val:
ans = s1
break
else:
continue
break
if not ans:
print('-1')
else:
print(ans)
```
|
output
| 1
| 13,459
| 0
| 26,919
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,460
| 0
| 26,920
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
# cook your dish here
import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
import math
import collections
from sys import stdin,stdout,setrecursionlimit
import bisect as bs
setrecursionlimit(2**20)
M = 10**9+7
T = int(stdin.readline())
# T = 1
def check(s1,s2):
co = 0
for i in range(m):
if(s1[i] != s2[i]):
co += 1
if(co > 1):
return False
return True
for _ in range(T):
# n = int(stdin.readline())
n,m = list(map(int,stdin.readline().split()))
# h = list(map(int,stdin.readline().split()))
# q = list(map(int,stdin.readline().split()))
# b = list(map(int,stdin.readline().split()))
# s = stdin.readline().strip('\n')
ss = []
for i in range(n):
ss.append(list(stdin.readline().strip('\n')))
res = False
for i in range(m):
for a in range(26):
c = chr(ord('a')+a)
t = ss[0].copy()
t[i] = c
cc = 0
for j in range(1,n):
if(not check(t,ss[j])):
break
cc += 1
if(cc == n-1):
res = True
break
if(res):
break
if(res):
print(''.join(t))
continue
print(-1)
```
|
output
| 1
| 13,460
| 0
| 26,921
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
|
instruction
| 0
| 13,461
| 0
| 26,922
|
Tags: bitmasks, brute force, constructive algorithms, dp, hashing, strings
Correct Solution:
```
import sys
reader = (s.rstrip() for s in sys.stdin)
input = reader.__next__
def gift():
for _ in range(t):
n,m = list(map(int,input().split()))
arrys=[]
for i in range(n):
kap=list(input())
arrys.append(kap)
ans=[]
checkdiff=True
for i in range(n):
for j in range(i,n):
if checkdiff:
counter=0
for k in range(m):
if arrys[i][k]!=arrys[j][k]:
counter+=1
if counter>2:
checkdiff=False
break
else:
break
if checkdiff:
for j in range(m):
counterdic={}
for i in range(n):
ele=arrys[i][j]
freq=counterdic.get(ele,0)
counterdic[ele]=freq+1
#print(counterdic,len(counterdic),arrys[0][j])
if len(counterdic)==1:
ans.append(arrys[0][j])
else:
ans.append(list(counterdic.keys()))
pans=ans[0]
for j in range(1,m):
#print(pans,ans)
tis=ans[j]
#print(tis,pans,ans)
tans=[]
if len(tis)==1:
for di in pans:
di+=tis
tans.append(di)
else:
for di in pans:
for ti in tis:
diu=di+ti
tans.append(diu)
#print(tans)
pans=tans
gotans=False
for ina in pans:
ans=True
for i in range(n):
counter=0
for j in range(m):
#print(arrys)
if ina[j]!=arrys[i][j]:
counter+=1
if counter>=2:
ans=False
break
if ans:
yield ina
gotans=True
break
if not gotans:
yield -1
else:
yield -1
#aaaab
#abaaa
#aaaab
if __name__ == '__main__':
t= int(input())
ans = gift()
print(*ans,sep='\n')
```
|
output
| 1
| 13,461
| 0
| 26,923
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
#include <CodeforcesSolutions.h>
#include <ONLINE_JUDGE <solution.cf(contestID = "1360",problemID = "F",method = "GET")>.h>
"""
Author : thekushalghosh
Team : CodeDiggers
I prefer Python language over the C++ language :p :D
Visit my website : thekushalghosh.github.io
"""
import sys,math,cmath,time
start_time = time.time()
global tt
#---------------------- USER DEFINED INPUT FUNCTIONS ----------------------#
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
return(input().strip())
def invr():
return(map(int,input().split()))
##########################################################################
################# ---- THE ACTUAL CODE STARTS BELOW ---- #################
def solve():
n,m = invr()
a = []
for i in range(n):
s = insr()
a.append(s)
b = [["0"] * len(a) for i in range(m)]
for i in range(m):
for j in range(n):
b[i][j] = a[j][i]
q = a[0]
qw = 0
for i in range(m):
qq = string_counter(b[i])
for j in range(26):
w = q[:i] + chr(97 + j) + q[i + 1:]
for k in range(n):
ww = 0
for l in range(m):
if w[l] != a[k][l]:
ww = ww + 1
if ww < 2:
True
else:
break
else:
print(w)
qw = 1
break
if qw == 1:
break
if qw == 0:
print(-1)
################## ---- THE ACTUAL CODE ENDS ABOVE ---- ##################
##########################################################################
def main():
global tt
if not ONLINE_JUDGE:
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
t = 1
t = inp()
for tt in range(t):
solve()
if not ONLINE_JUDGE:
print("Time Elapsed :",time.time() - start_time,"seconds")
sys.stdout.close()
#------------------ USER DEFINED PROGRAMMING FUNCTIONS ------------------#
def counter(a):
q = [0] * max(a)
for i in range(len(a)):
q[a[i] - 1] = q[a[i] - 1] + 1
return(q)
def string_counter(a):
q = [0] * 26
for i in range(len(a)):
q[ord(a[i]) - 97] = q[ord(a[i]) - 97] + 1
return(q)
ONLINE_JUDGE = __debug__
if ONLINE_JUDGE:
input = sys.stdin.readline
main()
```
|
instruction
| 0
| 13,463
| 0
| 26,926
|
Yes
|
output
| 1
| 13,463
| 0
| 26,927
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
## necessary imports
import sys
input = sys.stdin.readline
from math import *
# swap_array function
def swaparr(arr, a,b):
temp = arr[a];
arr[a] = arr[b];
arr[b] = temp
## gcd function
def gcd(a,b):
if a == 0:
return b
return gcd(b%a, a)
## nCr function efficient using Binomial Cofficient
def nCr(n, k):
if(k > n - k):
k = n - k
res = 1
for i in range(k):
res = res * (n - i)
res = res / (i + 1)
return res
## upper bound function code -- such that e in a[:i] e < x;
def upper_bound(a, x, lo=0):
hi = len(a)
while lo < hi:
mid = (lo+hi)//2
if a[mid] < x:
lo = mid+1
else:
hi = mid
return lo
## prime factorization
def primefs(n):
## if n == 1 ## calculating primes
primes = {}
while(n%2 == 0):
primes[2] = primes.get(2, 0) + 1
n = n//2
for i in range(3, int(n**0.5)+2, 2):
while(n%i == 0):
primes[i] = primes.get(i, 0) + 1
n = n//i
if n > 2:
primes[n] = primes.get(n, 0) + 1
## prime factoriazation of n is stored in dictionary
## primes and can be accesed. O(sqrt n)
return primes
## MODULAR EXPONENTIATION FUNCTION
def power(x, y, p):
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1
x = (x * x) % p
return res
## DISJOINT SET UNINON FUNCTIONS
def swap(a,b):
temp = a
a = b
b = temp
return a,b
# find function with path compression included (recursive)
# def find(x, link):
# if link[x] == x:
# return x
# link[x] = find(link[x], link);
# return link[x];
# find function with path compression (ITERATIVE)
def find(x, link):
p = x;
while( p != link[p]):
p = link[p];
while( x != p):
nex = link[x];
link[x] = p;
x = nex;
return p;
# the union function which makes union(x,y)
# of two nodes x and y
def union(x, y, link, size):
x = find(x, link)
y = find(y, link)
if size[x] < size[y]:
x,y = swap(x,y)
if x != y:
size[x] += size[y]
link[y] = x
## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES
def sieve(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
#### PRIME FACTORIZATION IN O(log n) using Sieve ####
MAXN = int(1e6 + 5)
def spf_sieve():
spf[1] = 1;
for i in range(2, MAXN):
spf[i] = i;
for i in range(4, MAXN, 2):
spf[i] = 2;
for i in range(3, ceil(MAXN ** 0.5), 2):
if spf[i] == i:
for j in range(i*i, MAXN, i):
if spf[j] == j:
spf[j] = i;
## function for storing smallest prime factors (spf) in the array
################## un-comment below 2 lines when using factorization #################
# spf = [0 for i in range(MAXN)]
# spf_sieve()
def factoriazation(x):
ret = {};
while x != 1:
ret[spf[x]] = ret.get(spf[x], 0) + 1;
x = x//spf[x]
return ret
## this function is useful for multiple queries only, o/w use
## primefs function above. complexity O(log n)
## taking integer array input
def int_array():
return list(map(int, input().strip().split()))
## taking string array input
def str_array():
return input().strip().split();
#defining a couple constants
MOD = int(1e9)+7;
CMOD = 998244353;
INF = float('inf'); NINF = -float('inf');
################### ---------------- TEMPLATE ENDS HERE ---------------- ###################
def isValid(this):
for i in range(n):
count = 0;
for j in range(m):
if this[j] != a[i][j]:
count += 1;
if count > 1:
return False
return True;
for _ in range(int(input())):
n, m = int_array(); a = [];
for __ in range(n):
a.append(list(input().strip()));
x = a[0]; f = 1;
for i in range(m):
if not f:
break;
for j in range(26):
this = x.copy(); this[i] = chr(97 + j);
if isValid(this):
print(''.join(this));
f = 0; break;
if f:
print(-1);
```
|
instruction
| 0
| 13,464
| 0
| 26,928
|
Yes
|
output
| 1
| 13,464
| 0
| 26,929
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
from copy import deepcopy
t=int(input())
for _ in range(t):
n,m=list(map(int,input().split()))
s=[]
for i in range(n):
s.append(list(input()))
def diff(a,b):
count=0
for i in range(0,len(a)):
if a[i]!=b[i]:
count+=1
return count
flag1=0
str=-1
temp = deepcopy(s[0])
for i in range(0,m):
temp=deepcopy(s[0])
for c in 'qwertyuiopasdfghjklzxcvbnm':
temp[i]=c
# print(temp)
flag=1
for l in s[1:]:
if diff(l,temp)>1:
flag=0
break
if flag==1:
flag1=1
break
if flag1==1:
break
if flag1==1:
print(''.join(temp))
else:
print(-1)
```
|
instruction
| 0
| 13,465
| 0
| 26,930
|
Yes
|
output
| 1
| 13,465
| 0
| 26,931
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
for T in range(int(input())):
n, m = [int(x) for x in input().split()]
arr = []
for i in range(n):
arr.append(list(input()))
if n == 1:
print(*arr[0], sep = '')
continue
first = arr[0]
done = 0
for i in range(m):
prev = first[i]
for j in range(97, 97 + 26):
ch = chr(j)
first[i] = ch
for k in range(1, n):
bad = 0
for pos in range(m):
if first[pos] != arr[k][pos]:
bad += 1
if bad > 1:
break
if bad > 1:
break
else:
print(*first, sep = '')
done = 1
break
if done:
break
if done:
break
else:
first[i] = prev
if not done:
print(-1)
```
|
instruction
| 0
| 13,466
| 0
| 26,932
|
No
|
output
| 1
| 13,466
| 0
| 26,933
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
import sys
try:
sys.stdin = open('Input.txt', 'r')
sys.stdout = open('Output.txt', 'w')
except:
pass
for testCases in range(int(input())):
s = []
n,m = map(int,input().split())
for i in range(n):
s.append(list(input()))
# print(s)
# break
ans = s[0]
index = -1
char = ''
limit = 0
flag = True
checkAns = True
for i in range(n):
limit = 0
diff1 = 0
diff2 = 0
for j in range(m):
# print(j,ans)
if flag:
if s[i][j] != ans[j]:
if limit == 2:
checkAns = False
break
if limit == 0:
index = j
char = s[i][j]
limit +=1
else:
temp1 = ans[:]
temp1[index] = char
temp2 = ans[:]
temp2[j] = s[i][j]
ans = [temp1,temp2]
flag = False
# print(ans)
else:
# print("YAY")
if ans[0]!=[] and s[i][j]!=ans[0][j]:
diff1 += 1
if ans[1]!=[] and s[i][j]!=ans[1][j]:
diff2 += 1
if diff1>=2:
ans[0] = []
if diff2>=2:
ans[1] = []
if checkAns == False:
break
if checkAns:
try:
print("".join(ans))
except:
if ans[0]!=[]:
print("".join(ans[0]))
elif ans[1]!=[]:
print("".join(ans[1]))
else:
print(-1)
else:
print(-1)
```
|
instruction
| 0
| 13,467
| 0
| 26,934
|
No
|
output
| 1
| 13,467
| 0
| 26,935
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
def stringgen(arr,n,m):
first=arr[0]
for i in range(m):
save=first[i]
for ch in "abcdefghijklmnopqrstuvxyz":
first[i]=ch
flag=True
for rest in arr[1:]:
cnt=0
for x in range(m):
if rest[x]!=first[x]:
cnt+=1
if cnt>1:
flag=False
break
if flag==True:
return "".join(first)
first[i]=save
return -1
for i in range(int(input())):
n,m=map(int,input().strip().split())
blanck=[]
for j in range(n):
blanck.append([i for i in input()])
print(stringgen(blanck,n,m))
```
|
instruction
| 0
| 13,468
| 0
| 26,936
|
No
|
output
| 1
| 13,468
| 0
| 26,937
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
def solve(n, m, arr):
if n == 1:
print(arr[0])
return
# s1 = arr[0]
# s2 = ""
s1, s2 = "", ""
for i in range(1, n):
diff = check(arr[0], arr[i])
if len(diff) <= 1:
continue
elif len(diff) == 2:
idx1, idx2 = diff
s1, s2 = arr[0], arr[i]
s1 = s1[:idx1] + arr[i][idx1] + s1[idx1 + 1:]
s2 = s2[:idx2] + arr[0][idx2] + s2[idx2 + 1:]
break
else:
print(-1)
return
if s1 == "":
print(arr[0])
return
f1, f2 = True, True
for s in arr:
diff = check(s1, s)
if len(diff) > 1:
f1 = False
break
if f1:
print(s1)
return
for s in arr:
diff = check(s2, s)
if len(diff) > 1:
f2 = False
break
if f2:
print(s2)
return
print(-1)
return
def check(s1, s2):
diff = []
for i in range(len(s1)):
if s1[i] != s2[i]:
diff.append(i)
return diff
t = int(input())
for i in range(0, t):
n, m = map(int, input().split())
arr = []
for j in range(n):
arr.append(input())
solve(n, m, arr)
```
|
instruction
| 0
| 13,469
| 0
| 26,938
|
No
|
output
| 1
| 13,469
| 0
| 26,939
|
Evaluate the correctness of the submitted Python 2 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings a_1, a_2, …, a_n: all of them have the same length m. The strings consist of lowercase English letters.
Find any string s of length m such that each of the given n strings differs from s in at most one position. Formally, for each given string a_i, there is no more than one position j such that a_i[j] ≠ s[j].
Note that the desired string s may be equal to one of the given strings a_i, or it may differ from all the given strings.
For example, if you have the strings abac and zbab, then the answer to the problem might be the string abab, which differs from the first only by the last character, and from the second only by the first.
Input
The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
Each test case starts with a line containing two positive integers n (1 ≤ n ≤ 10) and m (1 ≤ m ≤ 10) — the number of strings and their length.
Then follow n strings a_i, one per line. Each of them has length m and consists of lowercase English letters.
Output
Print t answers to the test cases. Each answer (if it exists) is a string of length m consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes).
Example
Input
5
2 4
abac
zbab
2 4
aaaa
bbbb
3 3
baa
aaa
aab
2 2
ab
bb
3 1
a
b
c
Output
abab
-1
aaa
ab
z
Note
The first test case was explained in the statement.
In the second test case, the answer does not exist.
Submitted Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
raw_input = stdin.readline
pr = stdout.write
mod=10**9+7
def ni():
return int(raw_input())
def li():
return map(int,raw_input().split())
def pn(n):
stdout.write(str(n)+'\n')
def pa(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return map(int,stdin.read().split())
range = xrange # not for python 3.0+
# main code
for t in range(ni()):
n,m=li()
l=[]
for i in range(n):
l.append(list(raw_input().strip()))
f1=0
for i in range(n):
ans=list(l[i])
f2=0
f3=0
for j in range(n):
if i==j:
continue
f=0
for k in range(m):
if ans[k]!=l[j][k]:
#print i,j,k,'asdf'
if not f2:
ans[k]=l[j][k]
f2=1
else:
f+=1
if f>1:
break
if f>1:
f3=1
break
#print f,f3,f2,j,k,ans
if not f3:
f1=1
break
if f1:
pr(''.join(ans)+'\n')
else:
pn(-1)
```
|
instruction
| 0
| 13,470
| 0
| 26,940
|
No
|
output
| 1
| 13,470
| 0
| 26,941
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,888
| 0
| 27,776
|
Tags: implementation
Correct Solution:
```
n = input()
s = input()
n = int(n)
print('1'*min(s.count('1'), 1)+'0'*s.count('0'))
```
|
output
| 1
| 13,888
| 0
| 27,777
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,889
| 0
| 27,778
|
Tags: implementation
Correct Solution:
```
n = int(input())
s = input()
flag=0
ans=""
for ele in s:
if ele=='1' and flag==0:
ans+=ele
flag=1
if ele=='0':
ans+=ele
print(ans)
```
|
output
| 1
| 13,889
| 0
| 27,779
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,890
| 0
| 27,780
|
Tags: implementation
Correct Solution:
```
n=int(input())
s=input()
m=''
counter=0
for i in range(n):
if s[i]== '1':
counter=counter+1
for j in range(n-counter):
m=m+'0'
if s=='0':
print(0)
else:
print('1'+m)
```
|
output
| 1
| 13,890
| 0
| 27,781
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,891
| 0
| 27,782
|
Tags: implementation
Correct Solution:
```
n=int(input())
s=input()
while('01' in s or '11' in s):
if('01' in s):
s=s.replace('01','10')
elif('11' in s):
s=s.replace('11','1')
print(s)
```
|
output
| 1
| 13,891
| 0
| 27,783
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,892
| 0
| 27,784
|
Tags: implementation
Correct Solution:
```
num = int(input())
s = input()
if "1" not in s:
print(s)
else:
ans = "1" + s.count("0")*"0"
print(ans)
```
|
output
| 1
| 13,892
| 0
| 27,785
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,893
| 0
| 27,786
|
Tags: implementation
Correct Solution:
```
n=int(input())
s=input()
if n==1:
print(s)
exit()
s=list(s)
zero=s.count('0')
print('1'+'0'*zero)
```
|
output
| 1
| 13,893
| 0
| 27,787
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,894
| 0
| 27,788
|
Tags: implementation
Correct Solution:
```
# int(input())
# [int(s) for s in input().split()]
# input()
def solve():
n = int(input())
s = input()
if s.count("1") == 0:
print(s)
else:
print("1"+"0"*(s.count("0")))
if __name__ == "__main__":
solve()
```
|
output
| 1
| 13,894
| 0
| 27,789
|
Provide tags and a correct Python 3 solution for this coding contest problem.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
|
instruction
| 0
| 13,895
| 0
| 27,790
|
Tags: implementation
Correct Solution:
```
n=int(input())
s=input()
z=0
o=0
for c in s:
if c=="1":
o+=1
else:
z+=1
t=""
for i in range(z):
t+="0"
if o==0:
print(t)
else:
t="1"+t
print(t)
```
|
output
| 1
| 13,895
| 0
| 27,791
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n, s = input(), input()
if s == '0':
print(s)
else:
print('1','0'*s.count('0'),sep='')
```
|
instruction
| 0
| 13,896
| 0
| 27,792
|
Yes
|
output
| 1
| 13,896
| 0
| 27,793
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n=int(input())
s=input()
print(s[0]+'0'*s[1:].count('0'))
```
|
instruction
| 0
| 13,897
| 0
| 27,794
|
Yes
|
output
| 1
| 13,897
| 0
| 27,795
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n = int(input())
s1 = input()
if s1.count('1') == 0:
print(0)
else:
print('1' + '0' * s1.count('0'))
```
|
instruction
| 0
| 13,898
| 0
| 27,796
|
Yes
|
output
| 1
| 13,898
| 0
| 27,797
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n = int(input())
a = input()
while '01' in a or '11' in a:
a = a.replace('01', '10')
a = a.replace('11', '1')
print(a)
```
|
instruction
| 0
| 13,899
| 0
| 27,798
|
Yes
|
output
| 1
| 13,899
| 0
| 27,799
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n=int(input())
s=input()
count=0
for i in s:
if(i=='0'):
count+=1
print('1'+'0'*count)
```
|
instruction
| 0
| 13,900
| 0
| 27,800
|
No
|
output
| 1
| 13,900
| 0
| 27,801
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n = int(input())
s = input()
z = 0
o = 0
for c in s:
if c == '0':
z += 1
else:
o += 1
ans = None
if o >= 1:
ans = 1 << z
else:
ans = 0
s = ""
while ans > 0:
s = str(ans % 2) + s
ans //= 2
print(s)
```
|
instruction
| 0
| 13,901
| 0
| 27,802
|
No
|
output
| 1
| 13,901
| 0
| 27,803
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n = int(input())
s = input()
c = 2
j = 0
for i in s:
if i == 1:
c += 1
if n == 1:
print(1)
elif n % 2 == 0:
print(1, end='')
while j < (n - c):
print(0, end = '')
j += 1
else:
print(1, end='')
while j < (n - c):
print(0, end = '')
j += 1
print(1, end='')
```
|
instruction
| 0
| 13,902
| 0
| 27,804
|
No
|
output
| 1
| 13,902
| 0
| 27,805
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string s.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" <image> "110");
2. replace "11" with "1" (for example, "110" <image> "10").
Let val(s) be such a number that s is its binary representation.
Correct string a is less than some other correct string b iff val(a) < val(b).
Your task is to find the minimum correct string that you can obtain from the given one using the operations described above. You can use these operations any number of times in any order (or even use no operations at all).
Input
The first line contains integer number n (1 ≤ n ≤ 100) — the length of string s.
The second line contains the string s consisting of characters "0" and "1". It is guaranteed that the string s is correct.
Output
Print one string — the minimum correct string that you can obtain from the given one.
Examples
Input
4
1001
Output
100
Input
1
1
Output
1
Note
In the first example you can obtain the answer by the following sequence of operations: "1001" <image> "1010" <image> "1100" <image> "100".
In the second example you can't obtain smaller answer no matter what operations you use.
Submitted Solution:
```
n = int(input())
B = input()
z = 0
for c in B:
z += c == '0'
print('1'+'0'*z)
```
|
instruction
| 0
| 13,903
| 0
| 27,806
|
No
|
output
| 1
| 13,903
| 0
| 27,807
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got a string s = s1s2... s|s| of length |s|, consisting of lowercase English letters. There also are q queries, each query is described by two integers li, ri (1 ≤ li ≤ ri ≤ |s|). The answer to the query is the number of substrings of string s[li... ri], which are palindromes.
String s[l... r] = slsl + 1... sr (1 ≤ l ≤ r ≤ |s|) is a substring of string s = s1s2... s|s|.
String t is called a palindrome, if it reads the same from left to right and from right to left. Formally, if t = t1t2... t|t| = t|t|t|t| - 1... t1.
Input
The first line contains string s (1 ≤ |s| ≤ 5000). The second line contains a single integer q (1 ≤ q ≤ 106) — the number of queries. Next q lines contain the queries. The i-th of these lines contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ |s|) — the description of the i-th query.
It is guaranteed that the given string consists only of lowercase English letters.
Output
Print q integers — the answers to the queries. Print the answers in the order, in which the queries are given in the input. Separate the printed numbers by whitespaces.
Examples
Input
caaaba
5
1 1
1 4
2 3
4 6
4 5
Output
1
7
3
4
2
Note
Consider the fourth query in the first test case. String s[4... 6] = «aba». Its palindrome substrings are: «a», «b», «a», «aba».
|
instruction
| 0
| 14,465
| 0
| 28,930
|
Tags: dp, hashing, strings
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
def main():
# n, k = map(int, input().split())
# s = input()
s=input()
n=len(s)
palin = [[0 for _ in range(n)] for _ in range(n)]
dp = [[0 for _ in range(n)] for _ in range(n)]
for sz in range(n):
for i in range(n - sz):
j = i + sz
if sz == 0:
palin[i][j] = 1
elif s[i] == s[j]:
if sz == 1:
palin[i][j] = 1
else:
palin[i][j] = palin[i + 1][j - 1]
else:
palin[i][j] = int(s[i] == s[j] and palin[i + 1][j - 1])
for sz in range(n):
for i in range(n - sz):
j = i + sz
if sz == 0:
dp[i][j] = 1
else:
dp[i][j] = dp[i][j - 1] + dp[i + 1][j] - dp[i + 1][j - 1] + palin[i][j]
# print(*dp,sep='\n')
for _ in range(int(input())):
l, r = list(map(int, input().split()))
print(dp[l - 1][r - 1])
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
if __name__ == "__main__":
for t in range(1):main()#int(input())): main()
```
|
output
| 1
| 14,465
| 0
| 28,931
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string s = s1s2... s|s| of length |s|, consisting of lowercase English letters. There also are q queries, each query is described by two integers li, ri (1 ≤ li ≤ ri ≤ |s|). The answer to the query is the number of substrings of string s[li... ri], which are palindromes.
String s[l... r] = slsl + 1... sr (1 ≤ l ≤ r ≤ |s|) is a substring of string s = s1s2... s|s|.
String t is called a palindrome, if it reads the same from left to right and from right to left. Formally, if t = t1t2... t|t| = t|t|t|t| - 1... t1.
Input
The first line contains string s (1 ≤ |s| ≤ 5000). The second line contains a single integer q (1 ≤ q ≤ 106) — the number of queries. Next q lines contain the queries. The i-th of these lines contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ |s|) — the description of the i-th query.
It is guaranteed that the given string consists only of lowercase English letters.
Output
Print q integers — the answers to the queries. Print the answers in the order, in which the queries are given in the input. Separate the printed numbers by whitespaces.
Examples
Input
caaaba
5
1 1
1 4
2 3
4 6
4 5
Output
1
7
3
4
2
Note
Consider the fourth query in the first test case. String s[4... 6] = «aba». Its palindrome substrings are: «a», «b», «a», «aba».
Submitted Solution:
```
s=input()
n=len(s)
mark=[]
dp=[]
for i in range(n):
mark.append([0]*n)
dp.append([0]*n)
for i in range(0,n):
for j in range(0,n):
if i+j>=n or i-j<0 :break
if s[i-j]==s[i+j]:
print(i-j,' ',i+j)
mark[i-j][i+j]=1
else : break
for j in range(1,n):
if i+j>=n or i-j+1<0:break
if s[i-j+1]==s[i+j]:
print(i-j+1,' ',i+j)
mark[i-j+1][i+j]=1
else : break
for i in range(n-1,-1,-1):
dp[i][i]=1
for j in range(i+1,n,1):
dp[i][j]=dp[i+1][j]+dp[i][j-1]+mark[i][j]
if i+1<=j-1:dp[i][j]-=dp[i+1][j-1]
q=int(input())
while q>0:
q-=1
A=list(map(int,input().split()))
A[0]-=1
A[1]-=1
print(dp[A[0]][A[1]])
```
|
instruction
| 0
| 14,466
| 0
| 28,932
|
No
|
output
| 1
| 14,466
| 0
| 28,933
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string s = s1s2... s|s| of length |s|, consisting of lowercase English letters. There also are q queries, each query is described by two integers li, ri (1 ≤ li ≤ ri ≤ |s|). The answer to the query is the number of substrings of string s[li... ri], which are palindromes.
String s[l... r] = slsl + 1... sr (1 ≤ l ≤ r ≤ |s|) is a substring of string s = s1s2... s|s|.
String t is called a palindrome, if it reads the same from left to right and from right to left. Formally, if t = t1t2... t|t| = t|t|t|t| - 1... t1.
Input
The first line contains string s (1 ≤ |s| ≤ 5000). The second line contains a single integer q (1 ≤ q ≤ 106) — the number of queries. Next q lines contain the queries. The i-th of these lines contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ |s|) — the description of the i-th query.
It is guaranteed that the given string consists only of lowercase English letters.
Output
Print q integers — the answers to the queries. Print the answers in the order, in which the queries are given in the input. Separate the printed numbers by whitespaces.
Examples
Input
caaaba
5
1 1
1 4
2 3
4 6
4 5
Output
1
7
3
4
2
Note
Consider the fourth query in the first test case. String s[4... 6] = «aba». Its palindrome substrings are: «a», «b», «a», «aba».
Submitted Solution:
```
s=str(input())
dp=[[0 for i in range(len(s))]for j in range(len(s))]
for i in range(len(s)):
dp[i][i]=1
n=len(s)
for i in range(n-1):
if s[i]==s[i+1]:
dp[i][i+1]=1
# print(dp)
for i in range(2,n):
for j in range(n-i):
# print(i,
# j)
if s[j]==s[i+j] and dp[j+1][i+j-1]:
dp[j][i+j]=1
a=[]
for j in range(n):
c=0
for i in range(n):
c+=dp[i][j]
a.append(c)
prefix=[a[0]]
for i in range(1,n):
prefix.append(prefix[i-1]+a[i])
for _ in range(int(input())):
u,v=map(int,input().split())
# print(u,v)
print(prefix[v-1]-prefix[u-1]+1)
```
|
instruction
| 0
| 14,467
| 0
| 28,934
|
No
|
output
| 1
| 14,467
| 0
| 28,935
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string s = s1s2... s|s| of length |s|, consisting of lowercase English letters. There also are q queries, each query is described by two integers li, ri (1 ≤ li ≤ ri ≤ |s|). The answer to the query is the number of substrings of string s[li... ri], which are palindromes.
String s[l... r] = slsl + 1... sr (1 ≤ l ≤ r ≤ |s|) is a substring of string s = s1s2... s|s|.
String t is called a palindrome, if it reads the same from left to right and from right to left. Formally, if t = t1t2... t|t| = t|t|t|t| - 1... t1.
Input
The first line contains string s (1 ≤ |s| ≤ 5000). The second line contains a single integer q (1 ≤ q ≤ 106) — the number of queries. Next q lines contain the queries. The i-th of these lines contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ |s|) — the description of the i-th query.
It is guaranteed that the given string consists only of lowercase English letters.
Output
Print q integers — the answers to the queries. Print the answers in the order, in which the queries are given in the input. Separate the printed numbers by whitespaces.
Examples
Input
caaaba
5
1 1
1 4
2 3
4 6
4 5
Output
1
7
3
4
2
Note
Consider the fourth query in the first test case. String s[4... 6] = «aba». Its palindrome substrings are: «a», «b», «a», «aba».
Submitted Solution:
```
s = input()
n = len(s) + 1
dp = [[0] * n for i in range(n)]
for i in range(n):
p, q = i, i
while q < n - 1 and p >= 0:
if s[p] == s[q]:
dp[p][q] += 1
p, q = p - 1, q + 1
for i in range(n):
p, q = i, i + 1
while q < n - 1 and p >= 0:
if s[p] == s[q]:
dp[p][q] += 1
p, q = p - 1, q + 1
for i in range(n):
for j in range(i + 1, n):
dp[i][j] += dp[i][j - 1]
for j in range(n):
for i in range(j - 1, -1, -1):
dp[i][j] += dp[i + 1][j]
Q = int(input())
for i in range(Q):
l, r = map(int, input().split())
print(dp[l - 1][r - 1])
```
|
instruction
| 0
| 14,468
| 0
| 28,936
|
No
|
output
| 1
| 14,468
| 0
| 28,937
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string s = s1s2... s|s| of length |s|, consisting of lowercase English letters. There also are q queries, each query is described by two integers li, ri (1 ≤ li ≤ ri ≤ |s|). The answer to the query is the number of substrings of string s[li... ri], which are palindromes.
String s[l... r] = slsl + 1... sr (1 ≤ l ≤ r ≤ |s|) is a substring of string s = s1s2... s|s|.
String t is called a palindrome, if it reads the same from left to right and from right to left. Formally, if t = t1t2... t|t| = t|t|t|t| - 1... t1.
Input
The first line contains string s (1 ≤ |s| ≤ 5000). The second line contains a single integer q (1 ≤ q ≤ 106) — the number of queries. Next q lines contain the queries. The i-th of these lines contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ |s|) — the description of the i-th query.
It is guaranteed that the given string consists only of lowercase English letters.
Output
Print q integers — the answers to the queries. Print the answers in the order, in which the queries are given in the input. Separate the printed numbers by whitespaces.
Examples
Input
caaaba
5
1 1
1 4
2 3
4 6
4 5
Output
1
7
3
4
2
Note
Consider the fourth query in the first test case. String s[4... 6] = «aba». Its palindrome substrings are: «a», «b», «a», «aba».
Submitted Solution:
```
s = input()
n = len(s) + 1
dp = [[0] * n for i in range(n)]
for i in range(n):
p, q = i, i
while q < n - 1 and p >= 0:
if s[p] == s[q]:
dp[p][q] += 1
p, q = p - 1, q + 1
for i in range(n):
p, q = i, i + 1
while q < n - 1 and p >= 0:
if s[p] == s[q]:
dp[p][q] += 1
p, q = p - 1, q + 1
for i in range(n):
for j in range(1, n):
dp[i][j] += dp[i][j - 1]
for j in range(n):
for i in range(n - 2, -1, -1):
dp[i][j] += dp[i + 1][j]
Q = int(input())
for i in range(Q):
l, r = map(int, input().split())
print(dp[l - 1][r - 1])
```
|
instruction
| 0
| 14,469
| 0
| 28,938
|
No
|
output
| 1
| 14,469
| 0
| 28,939
|
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').
Constraints
* 1 \leq |s| \leq 10^5
* 1 \leq |t| \leq 10^5
* s and t consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
t
Output
If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print `-1`.
Examples
Input
contest
son
Output
10
Input
contest
programming
Output
-1
Input
contest
sentence
Output
33
|
instruction
| 0
| 14,796
| 0
| 29,592
|
"Correct Solution:
```
from string import ascii_lowercase
from bisect import bisect_right
s = input()
t = input()
p = {c: [] for c in s}
for x, c in enumerate(s):
p[c].append(x)
z = 0
l = -1
for c in t:
if c not in p:
print(-1)
break
x = bisect_right(p[c], l)
if x == len(p[c]):
x = 0
z += 1
l = p[c][x]
else:
print(z * len(s) + l + 1)
```
|
output
| 1
| 14,796
| 0
| 29,593
|
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').
Constraints
* 1 \leq |s| \leq 10^5
* 1 \leq |t| \leq 10^5
* s and t consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
t
Output
If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print `-1`.
Examples
Input
contest
son
Output
10
Input
contest
programming
Output
-1
Input
contest
sentence
Output
33
|
instruction
| 0
| 14,797
| 0
| 29,594
|
"Correct Solution:
```
s=input()
t=input()
ans1=0
ans2=0
m=len(s)
n=len(t)
s=s+s
for i in range(n):
a=s.find(t[i],ans2)
if a==-1:
print(-1)
exit()
if a>=m:
ans1+=1
ans2=a%m+1
print((ans1*m)+ans2)
```
|
output
| 1
| 14,797
| 0
| 29,595
|
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').
Constraints
* 1 \leq |s| \leq 10^5
* 1 \leq |t| \leq 10^5
* s and t consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
t
Output
If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print `-1`.
Examples
Input
contest
son
Output
10
Input
contest
programming
Output
-1
Input
contest
sentence
Output
33
|
instruction
| 0
| 14,798
| 0
| 29,596
|
"Correct Solution:
```
import bisect
s = list(input())
t = list(input())
if len(set(t)-set(s)) > 0:
print(-1)
exit()
c = set(s)
dic = {}
for char in c:
dic[char] = []
for i in range(len(s)):
dic[s[i]] += [i]
last = -1
r = 0
for char in t:
tmp = last
idx = bisect.bisect_right(dic[char], last)
if idx < len(dic[char]):
last = dic[char][idx]
if tmp == last:
r += 1
last = dic[char][0]
print(len(s)*r + last + 1)
```
|
output
| 1
| 14,798
| 0
| 29,597
|
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').
Constraints
* 1 \leq |s| \leq 10^5
* 1 \leq |t| \leq 10^5
* s and t consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
t
Output
If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print `-1`.
Examples
Input
contest
son
Output
10
Input
contest
programming
Output
-1
Input
contest
sentence
Output
33
|
instruction
| 0
| 14,799
| 0
| 29,598
|
"Correct Solution:
```
s = input()
t = input()
temp = s[:]
cnt = 0
strmax = len(t)
ans = 0
for i in t:
if s.find(i)==-1:
print("-1")
exit(0)
while cnt<strmax:
num = temp.find(t[cnt])
if num != -1:
ans+=num+1
temp = temp[num+1:]
cnt+=1
else:
ans+=len(temp)
temp = s[:]
print(ans)
```
|
output
| 1
| 14,799
| 0
| 29,599
|
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