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Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,832
| 0
| 21,664
|
Tags: combinatorics, math, strings
Correct Solution:
```
MOD = 998244353
n = int(input())
s = input()
pref = s[0]
suff = s[-1]
lpref = 0
lsuff = 0
for i in range(len(s)):
if s[i] == pref:
lpref = lpref + 1
else:
break
for i in range(len(s)):
if s[len(s)-1-i] == suff:
lsuff = lsuff + 1
else:
break
if pref == suff:
res = (((lpref+1) % MOD) * ((lsuff+1) % MOD)) % MOD
else:
res = (lpref + lsuff + 1) % MOD
print(res)
```
|
output
| 1
| 10,832
| 0
| 21,665
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,833
| 0
| 21,666
|
Tags: combinatorics, math, strings
Correct Solution:
```
modu = 998244353
n = int(input())
s = input()
# first = s[0]
fans = 0
for i in range(n):
if s[i] == s[0]:
fans = fans+1
else:
break
s2 = s[::-1]
lans = 0
for i in range(n):
if s2[i] == s2[0]:
lans = lans+1
else:
break
if s[0]==s2[0] and len(set(s))>1:
print((fans*lans+lans+fans+1)%modu)
elif len(set(s))>1:
print((fans+lans+1)%modu)
else:
print((2**(fans))%modu)
```
|
output
| 1
| 10,833
| 0
| 21,667
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,834
| 0
| 21,668
|
Tags: combinatorics, math, strings
Correct Solution:
```
import sys
#import math
data = sys.stdin.readlines()
n = data[0]
s = data[1]
s = list(s[:len(s) - 1])
diferente1 = -1
diferente2 = -1
for i in range(len(s)):
if s[i] != s[0] and diferente1 == -1:
diferente1 = i
if s[-(i+1)] != s[-1] and diferente2 == -1:
diferente2 = i
if diferente1 != -1 and diferente2 != -1:
break
if s[0] == s[-1]:
print((diferente1+1)*(diferente2+1)%998244353)
else:
print(diferente1+diferente2+1)
```
|
output
| 1
| 10,834
| 0
| 21,669
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,835
| 0
| 21,670
|
Tags: combinatorics, math, strings
Correct Solution:
```
from sys import stdin,stdout
n=int(stdin.readline())
st=stdin.readline()
cntl=0
cntr=0
for i in st:
if(st[0] == i):
cntl+=1
else:
break
for j in range(n-1,-1,-1):
if(st[j] == st[n-1]):
cntr+=1
else:
break
if(st[0] == st[n-1]):
print(((cntl+1)*(cntr+1))%998244353)
else:
print(((cntl+cntr+1))%998244353 )
```
|
output
| 1
| 10,835
| 0
| 21,671
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,836
| 0
| 21,672
|
Tags: combinatorics, math, strings
Correct Solution:
```
import sys,math,bisect
from random import randint
inf = float('inf')
mod = 998244353
"========================================"
def lcm(a,b):
return int((a/math.gcd(a,b))*b)
def gcd(a,b):
return int(math.gcd(a,b))
def tobinary(n):
return bin(n)[2:]
def binarySearch(a,x):
i = bisect.bisect_left(a,x)
if i!=len(a) and a[i]==x:
return i
else:
return -1
def lowerBound(a, x):
i = bisect.bisect_left(a, x)
if i:
return (i-1)
else:
return -1
def upperBound(a,x):
i = bisect.bisect_right(a,x)
if i!= len(a)+1 and a[i-1]==x:
return (i-1)
else:
return -1
def primesInRange(n):
ans = []
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
for p in range(2, n+1):
if prime[p]:
ans.append(p)
return ans
def primeFactors(n):
factors = []
while n % 2 == 0:
factors.append(2)
n = n // 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
factors.append(i)
n = n // i
if n > 2:
factors.append(n)
return factors
def isPrime(n,k=5):
if (n <2):
return True
for i in range(0,k):
a = randint(1,n-1)
if(pow(a,n-1,n)!=1):
return False
return True
"========================================="
"""
n = int(input())
n,k = map(int,input().split())
arr = list(map(int,input().split()))
"""
from collections import deque,defaultdict,Counter
import heapq,string
n=int(input())
s=input()
cnt=0
if n==2:
print(3)
else:
pref = 1
for i in range(1,n):
if s[i]==s[i-1]:
pref+=1
else:
break
suff=1
for i in range(n-2,-1,-1):
if s[i]==s[i+1]:
suff+=1
else:
break
if s[0]==s[-1]:
print((suff+1+pref+(suff*pref))%mod)
else:
print((suff+pref+1)%mod)
```
|
output
| 1
| 10,836
| 0
| 21,673
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,837
| 0
| 21,674
|
Tags: combinatorics, math, strings
Correct Solution:
```
import sys
n = int((sys.stdin.readline()).strip())
s = (sys.stdin.readline()).strip()
counter = {}
lower = 0
for i in range(n):
counter[s[i]]=1
if len(counter)>1:
lower = i
break
counter = {}
upper = n-1
for i in reversed(range(n)):
counter[s[i]]=1
if len(counter)>1:
upper = i
break
mod = 998244353
if s[0]==s[-1]:
ans = (((lower +1)%mod)*((n-upper)%mod))%mod
else:
ans = (((lower +1)%mod)+((n-upper)%mod)-1)%mod
print(ans)
```
|
output
| 1
| 10,837
| 0
| 21,675
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
|
instruction
| 0
| 10,838
| 0
| 21,676
|
Tags: combinatorics, math, strings
Correct Solution:
```
n = int(input())
s = list(input())
c =[s[0]]
m =[s[-1]]
for i in range(len(s)-1):
if(s[i]==s[i+1]):
c.append(s[i+1])
else:
break
s.reverse()
for i in range(len(s)-1):
if(s[i]==s[i+1]):
m.append(s[i+1])
else:
break
if(s[0]!=s[-1]):
print((len(c)+len(m)+1)%998244353)
else:
print((len(c)+1)*(len(m)+1)%998244353)
```
|
output
| 1
| 10,838
| 0
| 21,677
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
n = int(input())
s = input()
for i in range(n-1):
if s[i+1]==s[i]:
pass
else:
l = i+1
break
for i in range(n-1):
if s[n-1-(i+1)]==s[n-1-i]:
pass
else:
r = n-1-i-1
break
ans =0
temp = 0
inf = 998244353
if s[0]==s[-1]: #ans = (n-r)*l+n-r
ans = ans+ n%inf -r%inf
ans = ans%inf
temp = temp+n%inf - r%inf
temp = temp%inf
temp = temp *(l%inf)
temp = temp%inf
ans = ans+temp
ans = ans%inf
else:
ans = ans+l%inf+n%inf -r%inf #ans = n-r+l
ans = ans%inf
print(ans)
```
|
instruction
| 0
| 10,839
| 0
| 21,678
|
Yes
|
output
| 1
| 10,839
| 0
| 21,679
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
n = int(input())
s = input()
fs = s[0]
indf = 0
for i in range(n):
if s[i] != fs:
break
indf += 1
ls = s[-1]
indl = 0
for i in range(-1, -n, -1):
if s[i] != ls:
break
indl += 1
mas = []
for i in range(n):
if s[i] not in mas:
mas.append(s[i])
if s == s[0] * n:
ans = (n * (n + 1) // 2)
elif s[0] == s[-1]:
ans = ((indf + 1) * (indl + 1))
else:
ans = (indf + indl + 1)
print(ans % 998244353)
```
|
instruction
| 0
| 10,840
| 0
| 21,680
|
Yes
|
output
| 1
| 10,840
| 0
| 21,681
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
Mod = 998244353
n = int(input())
string = input()
front = 1
i= 1
while(i<n):
if(string[i]==string[0]):
front+=1
else:
break
i+=1
rear = 1
i = n-2
while(i>=0):
if(string[i]==string[n-1]):
rear+=1
else:
break
i-=1
if(front+rear>n):
n = n%Mod
ans = n*(n+1)%Mod
elif(string[0]!=string[n-1]):
ans = front%Mod +rear%Mod
ans = (ans + 1)%Mod
else:
Mid = n -(front+rear)
front = front%Mod
rear = rear%Mod
ans = (front+rear+1)%Mod
temp = (front*rear)%Mod
ans = (ans+temp)%Mod
print(ans)
```
|
instruction
| 0
| 10,841
| 0
| 21,682
|
Yes
|
output
| 1
| 10,841
| 0
| 21,683
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
n=int(input())
s=input()
ans=0
k1,k2=0,-1
for i in range(1,n):
if s[i]!=s[0]:
k1=i
break
for i in range(n-2,-1,-1):
if s[i]!=s[-1]:
k2=i
break
if s[0]==s[-1]:
ans=(k1+1)*(n-k2)
else:
ans+=k1+n-k2-1
ans+=1
print(ans%998244353)
```
|
instruction
| 0
| 10,842
| 0
| 21,684
|
Yes
|
output
| 1
| 10,842
| 0
| 21,685
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
n = int(input())
s = input()
list_s = list(s)
count_char =0
x=-1
current_char = list_s[x]
while(current_char == list_s[-1]):
count_char+=1
x = x-1
current_char = list_s[x]
if list_s[0] == list_s[-1]:
print(count_char*3)
else:
print(count_char*2)
```
|
instruction
| 0
| 10,843
| 0
| 21,686
|
No
|
output
| 1
| 10,843
| 0
| 21,687
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
n = int(input())
s = input().strip()
head = s[0]
cnt1 = 1
tmp = 0
for i in range(1,n//2):
if s[i] == head:
cnt1 += 1
else:
tmp = i-1
break
tail = s[n-1]
cnt2 = 1
for i in range(n-2,tmp,-1):
if s[i] == tail:
cnt2 += 1
else:
break
if head != tail:
print(cnt1+cnt2+1)
else:
print((cnt1+1)*(cnt2+1))
```
|
instruction
| 0
| 10,844
| 0
| 21,688
|
No
|
output
| 1
| 10,844
| 0
| 21,689
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
import sys
import math
data = sys.stdin.readlines()
n = data[0]
s = data[1]
data = list(s[:len(s) - 1])
diferente1 = -1
diferente2 = -1
for i in range(len(s)):
if s[i] != s[0] and diferente1 == -1:
diferente1 = i
if s[-(i+1)] != s[-1] and diferente2 == -1:
diferente2 = i
if diferente1 != -1 and diferente2 != -1:
break
if s[0] == s[-1]:
#print((diferente1+1)*(diferente2+1))
print("Hola")
else:
#print(diferente1+diferente2+1)
print(s[-3])
```
|
instruction
| 0
| 10,845
| 0
| 21,690
|
No
|
output
| 1
| 10,845
| 0
| 21,691
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s of length n consisting only of lowercase Latin letters.
A substring of a string is a contiguous subsequence of that string. So, string "forces" is substring of string "codeforces", but string "coder" is not.
Your task is to calculate the number of ways to remove exactly one substring from this string in such a way that all remaining characters are equal (the number of distinct characters either zero or one).
It is guaranteed that there is at least two different characters in s.
Note that you can remove the whole string and it is correct. Also note that you should remove at least one character.
Since the answer can be rather large (not very large though) print it modulo 998244353.
If you are Python programmer, consider using PyPy instead of Python when you submit your code.
Input
The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the string s.
The second line of the input contains the string s of length n consisting only of lowercase Latin letters.
It is guaranteed that there is at least two different characters in s.
Output
Print one integer — the number of ways modulo 998244353 to remove exactly one substring from s in such way that all remaining characters are equal.
Examples
Input
4
abaa
Output
6
Input
7
aacdeee
Output
6
Input
2
az
Output
3
Note
Let s[l; r] be the substring of s from the position l to the position r inclusive.
Then in the first example you can remove the following substrings:
* s[1; 2];
* s[1; 3];
* s[1; 4];
* s[2; 2];
* s[2; 3];
* s[2; 4].
In the second example you can remove the following substrings:
* s[1; 4];
* s[1; 5];
* s[1; 6];
* s[1; 7];
* s[2; 7];
* s[3; 7].
In the third example you can remove the following substrings:
* s[1; 1];
* s[1; 2];
* s[2; 2].
Submitted Solution:
```
n = int(input())
arr = input()
mod = 998244353
left =0
right = 0
l = arr[0]
r = arr[-1]
for c in arr:
if l == c:
left+=1
else:break
if left!=n:
for c in arr[::-1]:
if r == c:
right+=1
else:break
ans = left+right+1
if left == n:
ans = n*(n+1)//2
else:
if left+right == n:
ans = left+right+1
else:
if l == r:
ans = left+(2*right)+1
else:
ans = left+right+1
print(ans%mod)
# print('Left:',left,'Right:',right,right+left)
```
|
instruction
| 0
| 10,846
| 0
| 21,692
|
No
|
output
| 1
| 10,846
| 0
| 21,693
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
|
instruction
| 0
| 10,897
| 0
| 21,794
|
Tags: brute force, constructive algorithms, greedy, implementation, strings
Correct Solution:
```
from sys import stdin, stdout
from math import *
from heapq import *
from collections import *
def is_palind(s):
ln=len(s)
for i in range(ln):
if (s[i] != s[ln-1-i]):
return False
return True
def main():
n,m=[int(x)for x in stdin.readline().split()]
npalinds=[]
palinds=[]
alls=[]
for i in range(n):
s=stdin.readline().strip()
if (is_palind(s)==True):
palinds.append(s)
else:
npalinds.append(s)
alls.append(s)
res=''
used=[False]*(n+1)
for ind,s in enumerate(palinds):
if (palinds.count(s)%2==1):
if (len(s)>len(res)):
res=s
if (res in palinds):
used[alls.index(res)]=True
reslist=deque()
reslist.append(res)
for i in range(len(alls)):
if (used[i]==False):
p=alls[i]
for j in range(len(alls)):
if (used[j]==False) and (i!=j):
q=alls[j]
if is_palind(p+q):
reslist.appendleft(p)
reslist.append(q)
used[i]=True
used[j]=True
res="".join(reslist)
stdout.write("%d\n%s"%(len(res),res))
return 0
if __name__ == "__main__":
main()
```
|
output
| 1
| 10,897
| 0
| 21,795
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
def ispal(s):
if (s==s[::-1]):
return 1
return 0
n,m=map(int,input().split())
A=[]
vis=[0]*n
for i in range(n):
A.append(list(input()))
if ispal(A[i]):
vis[i]=1
B=[]
C=[]
ans=0
for i in range(n):
if (vis[i]!=-1):
for j in range(i+1,n):
if (vis[j]!=-1 and A[i]==A[j][::-1]):
vis[i]=-1
vis[j]=-1
B.extend(A[i])
C.append(A[j])
ans=ans+2
break
for i in range(n):
if (vis[i]==1):
ans=ans+1
B.extend(A[i])
break
C.reverse()
for j in C:
B.extend(j)
print(len(B))
print(*B,sep="")
```
|
instruction
| 0
| 10,901
| 0
| 21,802
|
Yes
|
output
| 1
| 10,901
| 0
| 21,803
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
from collections import defaultdict,Counter
n,m = map(int,input().strip().split())
ls = []
for _ in range(n):
st = input()
ls.append(st)
start = ""
end = ""
temp = ""
ans = 0
dic = defaultdict(int)
f = 1
for i,val in enumerate(ls):
if i not in dic:
for j,value in enumerate(ls):
if j not in dic:
if i!=j and val==value[::-1]:
dic[i] = 1
dic[j] = 1
ans += 2*m
start += val
end = value+end
elif val==value[::-1] and f==1:
ans += m
temp = val
f = 0
print(ans)
if ans>0:
print(start+temp+end)
```
|
instruction
| 0
| 10,902
| 0
| 21,804
|
Yes
|
output
| 1
| 10,902
| 0
| 21,805
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
import math
t=1
while(t):
x,y=map(int,input().split())
l=[]
j=[]
k=[]
m=[]
t1=[]
t2=[]
for i in range(x):
l1=input()
l.append(l1)
for i in range(x):
r=l[:i]+l[i+1:]
if l[i][::-1] in r:
j.append(l[i])
k.append(l[i][::-1])
if(l[i]==l[i][::-1]):
m.append(l[i])
for i in range(len(j)):
if j[i] not in t1 and j[i][::-1] not in t1:
t1.append(j[i])
t2.append(j[i][::-1])
str1=str()
str2=str()
for i in range(len(t1)):
str1=str1+t1[i]
for i in range(len(t2)-1,-1,-1):
str2=str2+t2[i]
if(len(m)>0):
print(len(str1+m[0]+str2))
print(str1+m[0]+str2)
elif(len(str1+str2)>0):
print(len(str1+str2))
print(str1+str2)
else:
print(0)
t=t-1
```
|
instruction
| 0
| 10,903
| 0
| 21,806
|
Yes
|
output
| 1
| 10,903
| 0
| 21,807
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
n,m=map(int,input().split())
dp=[0]*n
for i in range(n):
s=input()
dp[i]=s
dpp=[]
dpop=[]
for i in range(n):
if dp[i]==dp[i][::-1]:
dpp.append(dp[i])
elif dp[i][::-1] in dp:
if dp[i][::-1] not in dpop:
dpop.append(dp[i])
dpop.append(dp[i][::-1])
s=""
if dpp:
s=dpp[0]
while dpop:
a=dpop.pop(0)
b=dpop.pop(0)
s=a+s+b
print(len(s))
print(s)
```
|
instruction
| 0
| 10,904
| 0
| 21,808
|
Yes
|
output
| 1
| 10,904
| 0
| 21,809
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
q, z = [int(x) for x in input().split()]
str1 = []
for x in range(q):
str1.append(input())
str2 = []
for each in str1:
str2.append(each[::-1])
str3 = set(str1) & set(str2)
'''
temp = set(str1) & set(str2)
temp1 = []
for each in str3:
temp.remove(each)
if each[::-1] not in temp:
temp1.append(each)
else:
temp.remove
for each in temp1:
str3.remove(each)
str4 = []
c = 0
for each in str3:
str4.insert(c, each)
str4.insert(-1*c-1, each[::-1])
str3.remove(each)
str3.remove(each[::-1])
num1 = len(str4) // 2
for each in temp1:
str4.insert(num1, each)
'''
str3 = list(str3)
#print(str3)
if len(str3) % 2 == 0:
for x in range(len(str3)):
if x == str3.index(str3[x][::-1]):
str3.pop(x)
break
for x in range(len(str3)):
temp = str3[x]
num1 = str3.index(temp[::-1])
if x != num1:
str3[num1], str3[-1*x-1] = str3[-1*x-1], str3[num1]
print(z*len(str3))
print("".join(str3))
```
|
instruction
| 0
| 10,905
| 0
| 21,810
|
No
|
output
| 1
| 10,905
| 0
| 21,811
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
n,m=map(int,input().split())
a=[]
ans=[]
res=''
for i in range(n):
a.append(input())
b=a.copy()
for i in a:
#print(a)
x=i
y=i[::-1]
a.remove(i)
#print(x,y)
if y in a:
ans.append(x)
a.remove(y)
else:
if x==y:
res=x
for i in a:
if i==i[::-1]:
res=i
break
s=''
if len(ans)==0:
if res!='':
print(len(res))
print(res)
else:
print(0)
print()
else:
for i in ans:
s+=i
if res!='':
s+=res+s[::-1]
else:
s+=s[::-1]
print(len(s))
print(s)
"""4 2
oo
ox
xo
xx4
"""
```
|
instruction
| 0
| 10,906
| 0
| 21,812
|
No
|
output
| 1
| 10,906
| 0
| 21,813
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
n, m = map(int, input().split())
s = []
c = ""
for i in range(n):
s.append(input())
while s:
try:
ind = s.index(a[::-1])
c = a + c + s[ind]
s.pop(ind)
except:
pass
s.pop(0)
print(len(c))
print(c)
```
|
instruction
| 0
| 10,907
| 0
| 21,814
|
No
|
output
| 1
| 10,907
| 0
| 21,815
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Returning back to problem solving, Gildong is now studying about palindromes. He learned that a palindrome is a string that is the same as its reverse. For example, strings "pop", "noon", "x", and "kkkkkk" are palindromes, while strings "moon", "tv", and "abab" are not. An empty string is also a palindrome.
Gildong loves this concept so much, so he wants to play with it. He has n distinct strings of equal length m. He wants to discard some of the strings (possibly none or all) and reorder the remaining strings so that the concatenation becomes a palindrome. He also wants the palindrome to be as long as possible. Please help him find one.
Input
The first line contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 50) — the number of strings and the length of each string.
Next n lines contain a string of length m each, consisting of lowercase Latin letters only. All strings are distinct.
Output
In the first line, print the length of the longest palindrome string you made.
In the second line, print that palindrome. If there are multiple answers, print any one of them. If the palindrome is empty, print an empty line or don't print this line at all.
Examples
Input
3 3
tab
one
bat
Output
6
tabbat
Input
4 2
oo
ox
xo
xx
Output
6
oxxxxo
Input
3 5
hello
codef
orces
Output
0
Input
9 4
abab
baba
abcd
bcde
cdef
defg
wxyz
zyxw
ijji
Output
20
ababwxyzijjizyxwbaba
Note
In the first example, "battab" is also a valid answer.
In the second example, there can be 4 different valid answers including the sample output. We are not going to provide any hints for what the others are.
In the third example, the empty string is the only valid palindrome string.
Submitted Solution:
```
n, m = map(int, input().split())
arr = []
pal = ''
rev = ''
for i in range(n):
temp = input()
arr.append(temp)
if temp == temp[::-1]:
rev = temp
for j in range(i):
if arr[i] == arr[j][::-1]:
pal = arr[i] + pal + arr[j]
if pal != '':
l = int((len(pal) + 1) / 2)
pal = pal[0:l] + rev + pal[l:]
if pal == '':
print(0)
else:
print(len(pal))
print(pal)
```
|
instruction
| 0
| 10,908
| 0
| 21,816
|
No
|
output
| 1
| 10,908
| 0
| 21,817
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,925
| 0
| 21,850
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
import math
cases = int(input())
for t in range(cases):
n,k = list(map(int,input().split()))
s = ''.join(sorted(input()))
if k==1:
print(''.join(s))
elif s[0]!=s[k-1]:
print(s[k-1])
else:
if s[0]==s[-1]:
print(s[0]*(math.ceil(n/k)))
elif s[k]==s[-1]:
print(s[0]+s[k]*math.ceil((n-k)/k))
else:
print(s[0]+s[k:])
```
|
output
| 1
| 10,925
| 0
| 21,851
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,926
| 0
| 21,852
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
for _ in range(int(input())):
n,k = map(int,input().split())
given = sorted(input())
if len(set(given[:k]))!=1:
ans = given[k-1]
else:
ans = ''
if len(set(given[k:]))==1:
for i in range(0,n,k):
ans+=given[i]
else:
ans = ''.join(given[k-1:])
print(ans)
```
|
output
| 1
| 10,926
| 0
| 21,853
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,927
| 0
| 21,854
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
# cook your dish here
t=int(input())
for _ in range(t):
n,k=map(int,input().split())
s=list(input())
s.sort()
c=s[0]
if s[k-1]!=c:
print(s[k-1])
else:
x=set(s[k:])
if len(x)==0 or len(x)==1:
ans=['']*k
j=0
for i in range(n):
ans[j]=ans[j]+s[i]
j=(j+1)%k
ans.sort()
m=ans[-1]
else:
m=''
for i in range(k-1,n):
m=m+s[i]
print(m)
```
|
output
| 1
| 10,927
| 0
| 21,855
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,928
| 0
| 21,856
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
for lo in range(int(input())):
#n = int(input())
n,k = map(int,input().split())
st = input()
ls = [0 for i in range(26)]
c = 0
mn = 30
for i in st:
x = ord(i)-97
if ls[x]==0:
c+=1
ls[x]+=1
mn = min(x,mn)
if c==1:
z = 0
if ls[mn]%k!=0:
z+=1
z+=(ls[mn]//k)
ans = ""
for i in range(z):
ans+=chr(97+mn)
print(ans)
continue
if ls[mn]<k:
z = 0
for i in range(26):
z+=ls[i]
if mn!=i and z>=k:
ans = chr(97+i)
break
print(ans)
continue
if ls[mn]==k and c==2:
x = 0
mn2 = 0
for i in range(26):
if mn!=i and ls[i]>0:
mn2 = i
x = ls[i]
break
z = 0
if ls[mn2]%k!=0:
z+=1
z+=(ls[mn2]//k)
ans = chr(97+mn)
for i in range(z):
ans+=chr(97+mn2)
print(ans)
continue
z = 0
ans = ""
for i in range(26):
if mn==i:
for j in range(ls[mn]-k+1):
ans+=chr(mn+97)
else:
for j in range(ls[i]):
ans+=chr(i+97)
print(ans)
```
|
output
| 1
| 10,928
| 0
| 21,857
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,929
| 0
| 21,858
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
for _ in range(int(input())):
n,k = map(int, input().split())
s = ''.join(sorted(input()))
if(s[0] != s[k-1] or k == n):
print(s[k-1])
continue
if(s[k] != s[n-1]):
print(s[0]+s[k:])
else:
print(s[0]+s[n-1]*((n-1)//k))
```
|
output
| 1
| 10,929
| 0
| 21,859
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,930
| 0
| 21,860
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
import math
t = int(input())
for _ in range(t):
n,m = map(int,input().split())
s = input()
s1 = [i for i in s]
s1.sort()
s = ''.join(s1)
#print(s)
if m==n:
print(s[n-1])
continue
if m==1:
print(s)
continue
lis = [[s[i]] for i in range(m)]
pos = -1
for i in range(m-1):
if lis[i]==lis[m-1]:
pos = i
break
if pos==-1:
print(*lis[m-1])
continue
pp = pow(2,10)
for i in range(20):
pp+=i
if pos==0:
if s[m]==s[n-1]:
print(s[0]+s[m]*(math.ceil((n-m)/m)))
else:
print(s[0]+s[m:])
else:
print(*lis[m-1])
```
|
output
| 1
| 10,930
| 0
| 21,861
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,931
| 0
| 21,862
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
I=input
exec(int(I())*"n,k=map(int,I().split());s=''.join(sorted(I()));c=s[k-1];print(c+(c==s[0])*s[k::k**(s[k%n]==s[-1])]);")
```
|
output
| 1
| 10,931
| 0
| 21,863
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
|
instruction
| 0
| 10,932
| 0
| 21,864
|
Tags: constructive algorithms, greedy, sortings, strings
Correct Solution:
```
#ライブラリインポート
from collections import defaultdict
con = 10 ** 9 + 7
#入力受け取り
def getlist():
return list(map(int, input().split()))
#処理内容
def main():
T = int(input())
for i in range(T):
N, K = getlist()
s = sorted(list(input()))
#面倒
if N == K:
print(s[-1])
elif s[0] != s[K - 1]:
print(s[K - 1])
elif s[0] == s[-1]:
var = 0
if N % K == 0:
var = int(N // K)
else:
var = int(N // K) + 1
ans = s[0] * var
print(ans)
elif s[K] == s[-1]:
ans = s[0]
var = 0
if (N - K) % K == 0:
var = int(N // K) - 1
else:
var = int(N // K)
ans += var * s[-1]
print(ans)
else:
ans = s[0]
for j in range(K, N):
ans += s[j]
print(ans)
if __name__ == '__main__':
main()
```
|
output
| 1
| 10,932
| 0
| 21,865
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
import math
t=int(input())
def als(A):
if len(list(set(list(A))))==1:
return True
return False
for _ in range(t):
n,k=list(map(int,input().split()))
s=input()
ss=s
ss=list(ss)
ss.sort()
ss=''.join(ss)
bb=list(set(list(ss)))
bb=''.join(bb)
a=[0]*26
for x in s:
a[ord(x)-97]+=1
tt=[]
idx=[]
for i in range(26):
if a[i]!=0:
tt.append(a[i])
idx.append(i)
if tt[0]<k:
print(ss[k-1])
elif als(ss[k:]):
res=ss[0]
val=math.ceil(len(ss[k:])/k)*ss[k]
print(res+val)
else:
print(ss[0]+ss[k:])
```
|
instruction
| 0
| 10,933
| 0
| 21,866
|
Yes
|
output
| 1
| 10,933
| 0
| 21,867
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
for u in range(int(input())):
n,k=map(int,input().split())
s=''.join(sorted(input()))
if(k==n or s[0]!=s[k-1]):
print(s[k-1])
elif(s[k]==s[-1]):
print(s[0]+s[k]*((n-1)//k))
else:
print(s[k-1:])
```
|
instruction
| 0
| 10,934
| 0
| 21,868
|
Yes
|
output
| 1
| 10,934
| 0
| 21,869
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
import sys
#from math import *
def eprint(*args):
print(*args, file=sys.stderr)
zz=1
if zz:
input=sys.stdin.readline
else:
sys.stdin=open('input.txt', 'r')
sys.stdout=open('output2.txt','w')
t=int(input())
while t>0:
t-=1
n,k=map(int,input().split())
s=list(input().rstrip())
s.sort()
d={}
a=["" for i in range(k)]
for i in range(k):
a[i%k]+=s[i]
j=0
i=k
if len(set(s[k:]))==1:
for i in range(k,len(s)):
a[j%k]+=s[i]
j+=1
if j==k or a[j][0]>a[0][0]:
j=0
else:
for i in range(k,len(s)):
a[j%k]+=s[i]
#print(a)
print(max(a))
```
|
instruction
| 0
| 10,935
| 0
| 21,870
|
Yes
|
output
| 1
| 10,935
| 0
| 21,871
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, k = map(int, input().split())
s = sorted([c for c in input()])
if s[k-1] != s[0]:
print(s[k-1])
else:
fi = s[0]
se = None
three = False
for i in range(n):
if s[i] != fi:
if se == None:
se = s[i]
elif s[i] != se:
three = True
break
if three:
print("".join(s[k-1:]))
else:
i = 0
while i < n and s[0] == s[i]:
i += 1
if i == n:
string = [s[0]] * (n//k)
if n % k != 0:
string += [s[0]]
print("".join(string))
elif i == k:
if (n - i) % k == 0:
print(s[0] + s[i]*((n-i)//k))
else:
print(s[0] + s[i]*((n-i)//k + 1))
else:
print("".join(s[k-1:]))
```
|
instruction
| 0
| 10,936
| 0
| 21,872
|
Yes
|
output
| 1
| 10,936
| 0
| 21,873
|
Evaluate the correctness of the submitted Python 2 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
raw_input = stdin.readline
pr = stdout.write
def in_num():
return int(raw_input())
def in_arr():
return map(int,raw_input().split())
def pr_num(n):
stdout.write(str(n)+'\n')
def pr_arr(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return stdin.read().split()
range = xrange # not for python 3.0+
inp=inp()
pos=1
for t in range(int(inp[0])):
n,k=int(inp[pos]),int(inp[pos+1])
pos+=2
s=list(inp[pos])
pos+=1
s.sort()
ans=[s[i] for i in range(k)]
if n==k or ans[0]!=ans[-1]:
pr(ans[-1]+'\n')
continue
if s[k]==s[-1]:
ln=n-k
pr(ans[0]+''.join(s[k]*((ln/k)+int(ln%k!=0)))+'\n')
else:
pr(ans[0]+''.join(s[k:])+'\n')
```
|
instruction
| 0
| 10,937
| 0
| 21,874
|
Yes
|
output
| 1
| 10,937
| 0
| 21,875
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
import sys,os.path
import math
if __name__ == '__main__':
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
for _ in range(int(input())):
n,k = map(int,input().split())
s = input()
l = [0 for i in range(26)]
flag = True
for i in range(n):
l[ord(s[i])-ord('a')]+=1
for i in range(n-1):
if s[i]!=s[i+1]:
flag = False
break
if flag:
ans = s[0]*(math.ceil(n/k))
print(ans)
else:
f = False
first = 26
for i in range(26):
if l[i]!=0:
first = min(first,i)
if l[i]!=0 and l[i]!=k:
f = True
break
if l[first]<k:
su = 0
for i in range(26):
su+=l[i]
if su>=k:
print(chr(97+i))
break
else:
if not f:
ans = ""
val = math.ceil(l[first]/k)
a = chr(97+first)*val
ans+=a
for i in range(first+1,26):
if l[i]!=0:
val = math.ceil(l[i]/k)
ans+=chr(97+i)*val
else:
ans = ""
ans += chr(97+first)*(l[first]-k+1)
for i in range(first+1,26):
if l[i]!=0:
a = chr(97+i)*l[i]
ans+=a
print(ans)
```
|
instruction
| 0
| 10,938
| 0
| 21,876
|
No
|
output
| 1
| 10,938
| 0
| 21,877
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, k = map(int, input().split())
a = sorted(input())
ans = a[k-1]
if(len(set(a[0:k]))>1):
print(ans)
else:
for i in range(k, n):
if(len(set(a[i:]))>1):
ans = ans + a[i]
else :
ans = ans + a[i]
break
print(ans)
```
|
instruction
| 0
| 10,939
| 0
| 21,878
|
No
|
output
| 1
| 10,939
| 0
| 21,879
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
import sys
try:
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
except:
pass
for _ in range(int(input())):
n,k = [int(x) for x in input().split()]
s = str(input())
s = "".join(sorted(s))
if k==n: print(s[n-1]); continue
if s[0]!=s[k-1]: print(s[k-1]); continue
print(s[0],end="")
if s[k]==s[n-1]:
print(k,n-1)
for _ in range(int((n-k)/k)): print(s[k],end="")
if (n-k)%k: print(s[k],end="")
print()
else:
print(s[k:])
```
|
instruction
| 0
| 10,940
| 0
| 21,880
|
No
|
output
| 1
| 10,940
| 0
| 21,881
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Phoenix has a string s consisting of lowercase Latin letters. He wants to distribute all the letters of his string into k non-empty strings a_1, a_2, ..., a_k such that every letter of s goes to exactly one of the strings a_i. The strings a_i do not need to be substrings of s. Phoenix can distribute letters of s and rearrange the letters within each string a_i however he wants.
For example, if s = baba and k=2, Phoenix may distribute the letters of his string in many ways, such as:
* ba and ba
* a and abb
* ab and ab
* aa and bb
But these ways are invalid:
* baa and ba
* b and ba
* baba and empty string (a_i should be non-empty)
Phoenix wants to distribute the letters of his string s into k strings a_1, a_2, ..., a_k to minimize the lexicographically maximum string among them, i. e. minimize max(a_1, a_2, ..., a_k). Help him find the optimal distribution and print the minimal possible value of max(a_1, a_2, ..., a_k).
String x is lexicographically less than string y if either x is a prefix of y and x ≠ y, or there exists an index i (1 ≤ i ≤ min(|x|, |y|)) such that x_i < y_i and for every j (1 ≤ j < i) x_j = y_j. Here |x| denotes the length of the string x.
Input
The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases. Each test case consists of two lines.
The first line of each test case consists of two integers n and k (1 ≤ k ≤ n ≤ 10^5) — the length of string s and the number of non-empty strings, into which Phoenix wants to distribute letters of s, respectively.
The second line of each test case contains a string s of length n consisting only of lowercase Latin letters.
It is guaranteed that the sum of n over all test cases is ≤ 10^5.
Output
Print t answers — one per test case. The i-th answer should be the minimal possible value of max(a_1, a_2, ..., a_k) in the i-th test case.
Example
Input
6
4 2
baba
5 2
baacb
5 3
baacb
5 3
aaaaa
6 4
aaxxzz
7 1
phoenix
Output
ab
abbc
b
aa
x
ehinopx
Note
In the first test case, one optimal solution is to distribute baba into ab and ab.
In the second test case, one optimal solution is to distribute baacb into abbc and a.
In the third test case, one optimal solution is to distribute baacb into ac, ab, and b.
In the fourth test case, one optimal solution is to distribute aaaaa into aa, aa, and a.
In the fifth test case, one optimal solution is to distribute aaxxzz into az, az, x, and x.
In the sixth test case, one optimal solution is to distribute phoenix into ehinopx.
Submitted Solution:
```
def solve():
N, K = [int(el) for el in input().split()]
s = input()
arr = ['' for _ in range(K)]
ind = -1
for ch in sorted(s):
ind = (ind + 1) % K
arr[ind] += ch
arr.sort()
return arr[-1]
for t in range(1, int(input()) + 1):
print(solve())
```
|
instruction
| 0
| 10,941
| 0
| 21,882
|
No
|
output
| 1
| 10,941
| 0
| 21,883
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,990
| 0
| 21,980
|
Tags: brute force, implementation, strings
Correct Solution:
```
t=int(input())
for _ in range(t):
a=str(input())
b=str(input())
x=len(a)
y=len(b)
if x>y:
mini=0
for i in range(y):
for j in range(i+1,y+1):
s=b[i:j]
l=j-i
p=0
for k in range(l,x+1):
if a[p:k]==s:
mini=max(mini,k-p)
p+=1
print(x+y-(2*mini))
else:
mini=0
for i in range(x):
for j in range(i+1,x+1):
s=a[i:j]
l=j-i
p=0
for k in range(l,y+1):
if b[p:k]==s:
mini=max(mini,k-p)
p+=1
print(x+y-(2*mini))
```
|
output
| 1
| 10,990
| 0
| 21,981
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,991
| 0
| 21,982
|
Tags: brute force, implementation, strings
Correct Solution:
```
for i in range(int(input())):
a=list(input())
b=list(input())
a1=len(a)
b1=len(b)
if a1>b1:
a1,b1=b1,a1
a,b=b,a
s=[]
for i in range(a1):
for j in range(i+1,a1+1):
s.append(a[i:j])
s1=0
for i in range(b1):
for j in range(i+1,i+1+a1):
t=b[i:j]
if t in s:
s1=max(s1,len(t))
s1=a1+b1-s1-s1
print(s1)
```
|
output
| 1
| 10,991
| 0
| 21,983
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,992
| 0
| 21,984
|
Tags: brute force, implementation, strings
Correct Solution:
```
def getCharNGram(n,s):
charGram = [''.join(s[i:i+n]) for i in range(len(s)-n+1)]
return charGram
t = int(input())
for _ in range(t):
A = input()
B = input()
if len(A) < len(B):
ans = len(B)+len(A)
for i in range(1,len(A)+1):
check = getCharNGram(i, A)
for c in check:
if c in B:
ans = min(ans, len(B)-i+len(A)-i)
else:
ans = len(A)+len(B)
for i in range(1,len(B)+1):
check = getCharNGram(i, B)
#print(check)
for c in check:
if c in A:
ans = min(ans, len(A)-len(c)+len(B)-i)
print(ans)
```
|
output
| 1
| 10,992
| 0
| 21,985
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,993
| 0
| 21,986
|
Tags: brute force, implementation, strings
Correct Solution:
```
T = int(input())
for _ in range(T):
a = input()
b = input()
out = len(a) + len(b)
for i in range(len(a)):
for j in range(len(a), i, -1):
if a[i:j] in b:
out = min(out, len(a)+len(b)-2*(j-i))
print(out)
```
|
output
| 1
| 10,993
| 0
| 21,987
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,994
| 0
| 21,988
|
Tags: brute force, implementation, strings
Correct Solution:
```
from sys import stdin
input = stdin.readline
t = int(input())
for _ in range(t):
a = input().rstrip()
b = input().rstrip()
aa = set()
bb = set()
for i in range(len(a)):
c = []
for j in range(i, len(a)):
c.append(a[j])
aa.add(tuple(c))
for i in range(len(b)):
c = []
for j in range(i, len(b)):
c.append(b[j])
bb.add(tuple(c))
z = aa.intersection(bb)
max_len = 0
for i in z:
max_len = max(max_len, len(i))
ans = (len(a) + len(b)) - (max_len + max_len)
print(ans)
```
|
output
| 1
| 10,994
| 0
| 21,989
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,995
| 0
| 21,990
|
Tags: brute force, implementation, strings
Correct Solution:
```
import sys,functools,collections,bisect,math,heapq
input = sys.stdin.readline
#print = sys.stdout.write
def fun(A ,B):
n = len(A)
m = len(B)
#Edge cases.
if m == 0 or n == 0:
return 0
if n == 1 and m == 1:
if A[0] == B[0]:
return 1
else:
return 0
#Initializing first row and column with 0 (for ease i intialized everthing 0 :p)
dp = [[0 for x in range(m + 1)] for y in range(n + 1)]
final = 0
#this code is a lot like longest common subsequence(only else condition is different).
for i in range(1, n + 1):
for j in range(1, m + 1):
if A[i - 1] == B[j - 1]:
dp[i][j] = 1 + dp[i - 1][j - 1]
else:
dp[i][j] = 0
final = max(final, dp[i][j])
return final
t = int(input())
for _ in range(t):
s = input().strip()
s1 = input().strip()
x = fun(s,s1)
print(len(s)+len(s1)-(2*x))
```
|
output
| 1
| 10,995
| 0
| 21,991
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,996
| 0
| 21,992
|
Tags: brute force, implementation, strings
Correct Solution:
```
import sys
def I(): return int(sys.stdin.readline().rstrip())
def MI(): return map(int,sys.stdin.readline().rstrip().split())
def LI(): return list(map(int,sys.stdin.readline().rstrip().split()))
def LI2(): return list(map(int,sys.stdin.readline().rstrip()))
def S(): return sys.stdin.readline().rstrip()
def LS(): return list(sys.stdin.readline().rstrip().split())
def LS2(): return list(sys.stdin.readline().rstrip())
t = I()
for _ in range(t):
a = S()
b = S()
len_a = len(a)
len_b = len(b)
ans = len_a+len_b
for i in range(1,min(len_a,len_b)+1):
for j in range(len_a-i+1):
for k in range(len_b-i+1):
if a[j:j+i] == b[k:k+i]:
ans = min(ans,len_a+len_b-2*i)
print(ans)
```
|
output
| 1
| 10,996
| 0
| 21,993
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the strings a and b, consisting of lowercase Latin letters. You can do any number of the following operations in any order:
* if |a| > 0 (the length of the string a is greater than zero), delete the first character of the string a, that is, replace a with a_2 a_3 … a_n;
* if |a| > 0, delete the last character of the string a, that is, replace a with a_1 a_2 … a_{n-1};
* if |b| > 0 (the length of the string b is greater than zero), delete the first character of the string b, that is, replace b with b_2 b_3 … b_n;
* if |b| > 0, delete the last character of the string b, that is, replace b with b_1 b_2 … b_{n-1}.
Note that after each of the operations, the string a or b may become empty.
For example, if a="hello" and b="icpc", then you can apply the following sequence of operations:
* delete the first character of the string a ⇒ a="ello" and b="icpc";
* delete the first character of the string b ⇒ a="ello" and b="cpc";
* delete the first character of the string b ⇒ a="ello" and b="pc";
* delete the last character of the string a ⇒ a="ell" and b="pc";
* delete the last character of the string b ⇒ a="ell" and b="p".
For the given strings a and b, find the minimum number of operations for which you can make the strings a and b equal. Note that empty strings are also equal.
Input
The first line contains a single integer t (1 ≤ t ≤ 100). Then t test cases follow.
The first line of each test case contains the string a (1 ≤ |a| ≤ 20), consisting of lowercase Latin letters.
The second line of each test case contains the string b (1 ≤ |b| ≤ 20), consisting of lowercase Latin letters.
Output
For each test case, output the minimum number of operations that can make the strings a and b equal.
Example
Input
5
a
a
abcd
bc
hello
codeforces
hello
helo
dhjakjsnasjhfksafasd
adjsnasjhfksvdafdser
Output
0
2
13
3
20
|
instruction
| 0
| 10,997
| 0
| 21,994
|
Tags: brute force, implementation, strings
Correct Solution:
```
n = int(input())
for i in range(n):
s1 = input()
s2 = input()
if (len(s1) > len(s2)): s1, s2 = s2, s1
max = 0
for j in range(len(s1)):
for k in range(j, len(s1)):
found = s2.find(s1[j:k+1])
if (found != -1):
if (k - j + 1 > max):
max = k - j + 1
else:
break
print(len(s1) + len(s2) - 2*max)
```
|
output
| 1
| 10,997
| 0
| 21,995
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Paul hates palindromes. He assumes that string s is tolerable if each its character is one of the first p letters of the English alphabet and s doesn't contain any palindrome contiguous substring of length 2 or more.
Paul has found a tolerable string s of length n. Help him find the lexicographically next tolerable string of the same length or else state that such string does not exist.
Input
The first line contains two space-separated integers: n and p (1 ≤ n ≤ 1000; 1 ≤ p ≤ 26). The second line contains string s, consisting of n small English letters. It is guaranteed that the string is tolerable (according to the above definition).
Output
If the lexicographically next tolerable string of the same length exists, print it. Otherwise, print "NO" (without the quotes).
Examples
Input
3 3
cba
Output
NO
Input
3 4
cba
Output
cbd
Input
4 4
abcd
Output
abda
Note
String s is lexicographically larger (or simply larger) than string t with the same length, if there is number i, such that s1 = t1, ..., si = ti, si + 1 > ti + 1.
The lexicographically next tolerable string is the lexicographically minimum tolerable string which is larger than the given one.
A palindrome is a string that reads the same forward or reversed.
|
instruction
| 0
| 11,141
| 0
| 22,282
|
Tags: greedy, strings
Correct Solution:
```
import sys
from math import log2,floor,ceil,sqrt,gcd
import bisect
# from collections import deque
# sys.setrecursionlimit(10**5)
Ri = lambda : [int(x) for x in sys.stdin.readline().split()]
ri = lambda : sys.stdin.readline().strip()
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
INF = 10 ** 18
MOD = 1000000007
n,k = Ri()
st = ri()
st = [i for i in st]
arr = [chr(ord('a')+i) for i in range(k)]
flag = -1
ch = -1
if n == 1:
# YES()
if st[0] == arr[-1]:
NO()
else:
print(chr(ord(st[0])+1))
else:
for i in range(n-1,-1,-1):
for j in range(ord(st[i])-ord('a')+1, k):
tch = arr[j]
if i-2 >=0 :
if tch == st[i-1] or tch == st[i-2]:
continue
else:
flag = i
ch = tch
break
elif i-1>= 0:
if tch == st[i-1]:
continue
else:
flag = i
ch = tch
break
else:
flag = i
ch = tch
break
if flag != -1:
break
# print(flag)
if flag == -1:
NO()
else:
st[flag] = ch
# print(st)
# print(flag,n)
for i in range(flag+1,n):
# print("fs")
for j in range(0, k):
tch = arr[j]
if i-2 >=0 :
if tch == st[i-1] or tch == st[i-2]:
continue
else:
flag = i
ch = tch
st[i] = ch
break
elif i-1>= 0:
if tch == st[i-1]:
continue
else:
flag = i
ch = tch
st[i] = ch
break
else:
flag = i
ch = tch
st[i] = ch
break
# YES()
print("".join(st))
```
|
output
| 1
| 11,141
| 0
| 22,283
|
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