1 Even or Odd

8kyu Tantangan #1/366 - 15 Feb 2024

1.1 Instruction

Create a function that takes an integer as an argument and returns "Even" for even numbers or "Odd" for odd numbers.

Solusi bar-bar

even_or_odd <- function(n) {
  ifelse(abs(n/2 - as.integer(n/2)) == 0.5, "Odd", "Even")
}

Solusi simple

even_or_odd <- function(n) {
  #  %% operator modulo
  ifelse(n %% 2 == 1, "Odd", "Even")
}

even_or_odd <- function(n) c("Even", "Odd")[n %% 2 + 1]

library(testthat)
test_that('even_or_odd(1) returns "Odd"', {
  expect_equal(even_or_odd(1), "Odd")
})

Test passed 🎉

test_that('even_or_odd(2) returns "Even"', {
  expect_equal(even_or_odd(2), "Even")
})

Test passed 🌈

test_that('even_or_odd(0) returns "Even"', {
  expect_equal(even_or_odd(0), "Even")
})

Test passed 🥇

test_that('even_or_odd(-1) returns "Odd"', {
  expect_equal(even_or_odd(-1), "Odd")
})

Test passed 😸

test_that('even_or_odd(-2) returns "Even"', {
  expect_equal(even_or_odd(-2), "Even")
})

Test passed 😸