}^{\bf b}$ satisfies $$\Psi([L_{{\bf b}}(\lambda)]) = L^{{\bf b}}_{f^{{\bf b}}_{\lambda}}(0), \quad \quad \quad \Psi([T_{{\bf b}}(\lambda)])      = T^{{\bf b}}_{f^{{\bf b}}_{\lambda}}(0), \quad \quad \text{ for } \lambda \in {}X