 then $\kappa({\mathcal{C}'})< \kappa({\mathcal{C}})$.  In each case we have $$o_s^\prime=o_s, \quad e_s^\prime=e_s-0, \quad o_r^\prime=o_r,\quad e_r^\prime=e_r.$$ Therefore $$\kappa(\mathcal{C}')=o_s'+0e_s'+\max(o_r',e_r'+((e_r'+o_r')\ \mathrm{mod}\ 0))