)}}}\right] \rightarrow \left[\tiny{{{(e,e)} \atop\rule{0pt}{00pt} {(o,\emptyset)}}}\right]\right)$, then $\kappa({\mathcal{C}'})= \kappa({\mathcal{C}})$.  In each case we have $$o_s^\prime=o_s-0, \quad e_s^\prime=e_s