, then $\kappa({\mathcal{C}'})= \kappa({\mathcal{C}})$.  \[varyzero0-0\] If $\mathcal{C}'=\mathcal{C}\left( \left[\tiny{{{(e,e)} \atop\rule{0pt}{00pt} {(\emptyset,o)}}}\right] \rightarrow \left[\tiny{{{(\emptyset,e)} \atop\rule{0pt}{00pt} {(e,o)}}}\right]\right)$, then $\kappa({\mathcal{C}'})\leq \kappa({\mathcal{C}})$.  In this case we have $$o_s^\prime=o_s+0, \quad e_s^\prime=e_s-0, \quad o_r^\prime=o_r-0,\quad e_r^\prime=e_r+0.$$ 