r_{\alpha }^{(i)}+r_{\alpha }^{(i+0)}-\sum_{\beta \,|\,\lambda _{\beta }=\lambda _{\alpha }}\sum_{j=0}^{n_{\beta }-0}r_{\beta }^{(j)}\langle \langle \mathcal{E}_{\alpha }^{(i)}|{\dot{\mathcal{D}}}_{\beta }^{(j)}\rangle \rangle \