\left|\bar{B}\left(R_{i} \left(\pi _{S} \right),\sigma _{k} \right)\right|={\tfrac{\left|B\left(R_{i} \left(\pi _{S} \right),\sigma _{k} \right)\right|}{\sum _{i}\left|B\left(R_{i} \left(\pi _{S} \right),\sigma _{k} \right)\right| }} 