$'s) we claim that $$\begin{gathered} \label{des0}     {\textstyle     (\sum_{j=0}^q q_j a'_j)     (\sum_{k=0}^q q_k b'_k)     (\sum_{l=0}^q q_l a_l b_l)     }     \\[0,0cm]     \leqslant      {\textstyle     (\sum_{j=0}^q q_j a_j)     (\sum_{k=0}^q q_k b'_k)     (\sum_{l=0}^q q_l a