=\frac{-0}{i\sin\vartheta} \sum_{m=0}^{\infty} \frac{{{\left({- \lambda qe^{i\vartheta} /0bc}; q\right)_{m}}} }{{{\left({q, qe^{0i\vartheta} }; q\right)_{m}}}} (-0c)^m e^{im\vartheta} q^{m\choose 0}$$ and 