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SELECT COUNT(*) FROM head WHERE age > 56

How many heads of the departments are older than 56 ?

CREATE TABLE head (age INTEGER)

Quantos chefes de departamento têm mais de 56 anos?

SELECT name, born_state, age FROM head ORDER BY age

List the name, born state and age of the heads of departments ordered by age.

CREATE TABLE head (name VARCHAR, born_state VARCHAR, age VARCHAR)

Listar o nome, estado de nascimento e idade dos chefes de departamentos ordenados por idade.

SELECT creation, name, budget_in_billions FROM department

List the creation year, name and budget of each department.

CREATE TABLE department (creation VARCHAR, name VARCHAR, budget_in_billions VARCHAR)

Listar o ano de criação, nome e orçamento de cada departamento.

SELECT MAX(budget_in_billions), MIN(budget_in_billions) FROM department

What are the maximum and minimum budget of the departments?

CREATE TABLE department (budget_in_billions INTEGER)

Qual é o orçamento máximo e mínimo dos departamentos?

SELECT AVG(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15

What is the average number of employees of the departments whose rank is between 10 and 15?

CREATE TABLE department (num_employees INTEGER, ranking INTEGER)

Qual é o número médio de funcionários dos departamentos cuja classificação é entre 10 e 15?

SELECT name FROM head WHERE born_state <> 'California'

What are the names of the heads who are born outside the California state?

CREATE TABLE head (name VARCHAR, born_state VARCHAR)

Quais são os nomes das cabeças que nascem fora do estado da Califórnia?

SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama'

What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'?

CREATE TABLE department (creation VARCHAR, department_id VARCHAR); CREATE TABLE management (department_id VARCHAR, head_id VARCHAR); CREATE TABLE head (head_id VARCHAR, born_state VARCHAR)

Quais são os distintos anos de criação dos departamentos geridos por um secretário nascido no estado 'Alabama'?

SELECT born_state FROM head GROUP BY born_state HAVING COUNT(*) >= 3

What are the names of the states where at least 3 heads were born?

CREATE TABLE head (born_state VARCHAR)

Quais são os nomes dos estados onde pelo menos três cabeças nasceram?

SELECT creation FROM department GROUP BY creation ORDER BY COUNT(*) DESC LIMIT 1

In which year were most departments established?

CREATE TABLE department (creation VARCHAR)

Em que ano a maioria dos departamentos foi estabelecida?

SELECT T1.name, T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes'

Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'?

CREATE TABLE management (department_id VARCHAR, temporary_acting VARCHAR); CREATE TABLE department (name VARCHAR, num_employees VARCHAR, department_id VARCHAR)

Mostrar o nome e o número de funcionários para os departamentos gerenciados por chefes cujo valor de atuação temporária é 'Sim'?

SELECT COUNT(DISTINCT temporary_acting) FROM management

How many acting statuses are there?

CREATE TABLE management (temporary_acting VARCHAR)

Quantos status de atuação existem?

SELECT COUNT(*) FROM department WHERE NOT department_id IN (SELECT department_id FROM management)

How many departments are led by heads who are not mentioned?

CREATE TABLE management (department_id VARCHAR); CREATE TABLE department (department_id VARCHAR)

Quantos departamentos são liderados por chefes que não são mencionados?

SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes'

What are the distinct ages of the heads who are acting?

CREATE TABLE head (age VARCHAR, head_id VARCHAR); CREATE TABLE management (head_id VARCHAR, temporary_acting VARCHAR)

Quais são as idades distintas das cabeças que estão agindo?

SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security'

List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born.

CREATE TABLE management (department_id VARCHAR, head_id VARCHAR); CREATE TABLE head (born_state VARCHAR, head_id VARCHAR); CREATE TABLE department (department_id VARCHAR, name VARCHAR)

Listar os estados onde tanto o secretário do departamento de 'Tesouro' eo secretário de 'Homeland Security' nasceram.

SELECT T1.department_id, T1.name, COUNT(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING COUNT(*) > 1

Which department has more than 1 head at a time? List the id, name and the number of heads.

CREATE TABLE management (department_id VARCHAR); CREATE TABLE department (department_id VARCHAR, name VARCHAR)

Qual departamento tem mais de 1 cabeça de cada vez? Liste o ID, o nome e o número de cabeças.

SELECT head_id, name FROM head WHERE name LIKE '%Ha%'

Which head's name has the substring 'Ha'? List the id and name.

CREATE TABLE head (head_id VARCHAR, name VARCHAR)

Qual o nome da cabeça tem a substring 'Ha'? Liste o id e o nome.

SELECT COUNT(*) FROM farm

How many farms are there?

CREATE TABLE farm (Id VARCHAR)

Quantas fazendas existem?

SELECT Total_Horses FROM farm ORDER BY Total_Horses

List the total number of horses on farms in ascending order.

CREATE TABLE farm (Total_Horses VARCHAR)

Listar o número total de cavalos em fazendas em ordem crescente.

SELECT Hosts FROM farm_competition WHERE Theme <> 'Aliens'

What are the hosts of competitions whose theme is not "Aliens"?

CREATE TABLE farm_competition (Hosts VARCHAR, Theme VARCHAR)

Quais são os anfitriões de competições cujo tema não é "Aliens"?

SELECT Theme FROM farm_competition ORDER BY YEAR

What are the themes of farm competitions sorted by year in ascending order?

CREATE TABLE farm_competition (Theme VARCHAR, YEAR VARCHAR)

Quais são os temas das competições agrícolas ordenadas por ano em ordem crescente?

SELECT AVG(Working_Horses) FROM farm WHERE Total_Horses > 5000

What is the average number of working horses of farms with more than 5000 total number of horses?

CREATE TABLE farm (Working_Horses INTEGER, Total_Horses INTEGER)

Qual é o número médio de cavalos de trabalho de fazendas com mais de 5000 número total de cavalos?

SELECT MAX(Cows), MIN(Cows) FROM farm

What are the maximum and minimum number of cows across all farms.

CREATE TABLE farm (Cows INTEGER)

Qual é o número máximo e mínimo de vacas em todas as fazendas?

SELECT COUNT(DISTINCT Status) FROM city

How many different statuses do cities have?

CREATE TABLE city (Status VARCHAR)

Quantos estados diferentes as cidades têm?

SELECT Official_Name FROM city ORDER BY Population DESC

List official names of cities in descending order of population.

CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR)

Listar nomes oficiais das cidades em ordem decrescente de população.

SELECT Official_Name, Status FROM city ORDER BY Population DESC LIMIT 1

List the official name and status of the city with the largest population.

CREATE TABLE city (Official_Name VARCHAR, Status VARCHAR, Population VARCHAR)

Listar o nome oficial e status da cidade com a maior população.

SELECT T2.Year, T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

Show the years and the official names of the host cities of competitions.

CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR); CREATE TABLE farm_competition (Year VARCHAR, Host_city_ID VARCHAR)

Mostre os anos e os nomes oficiais das cidades-sede das competições.

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

Show the official names of the cities that have hosted more than one competition.

CREATE TABLE farm_competition (Host_city_ID VARCHAR); CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR)

Mostre os nomes oficiais das cidades que sediaram mais de uma competição.

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

Show the status of the city that has hosted the greatest number of competitions.

CREATE TABLE city (Status VARCHAR, City_ID VARCHAR); CREATE TABLE farm_competition (Host_city_ID VARCHAR)

Mostre o status da cidade que hospedou o maior número de competições.

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

Please show the themes of competitions with host cities having populations larger than 1000.

CREATE TABLE city (City_ID VARCHAR, Population INTEGER); CREATE TABLE farm_competition (Theme VARCHAR, Host_city_ID VARCHAR)

Por favor, mostre os temas de competições com cidades-sede com populações maiores que 1000.

SELECT Status, AVG(Population) FROM city GROUP BY Status

Please show the different statuses of cities and the average population of cities with each status.

CREATE TABLE city (Status VARCHAR, Population INTEGER)

Por favor, mostre os diferentes status das cidades e a população média das cidades com cada status.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*)

Please show the different statuses, ordered by the number of cities that have each.

CREATE TABLE city (Status VARCHAR)

Por favor, mostre os diferentes status, ordenados pelo número de cidades que têm cada um.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

List the most common type of Status across cities.

CREATE TABLE city (Status VARCHAR)

Listar o tipo mais comum de status em todas as cidades.

SELECT Official_Name FROM city WHERE NOT City_ID IN (SELECT Host_city_ID FROM farm_competition)

List the official names of cities that have not held any competition.

CREATE TABLE farm_competition (Official_Name VARCHAR, City_ID VARCHAR, Host_city_ID VARCHAR); CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR, Host_city_ID VARCHAR)

Listar os nomes oficiais das cidades que não realizaram qualquer competição.

SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500

Show the status shared by cities with population bigger than 1500 and smaller than 500.

CREATE TABLE city (Status VARCHAR, Population INTEGER)

Mostrar o status compartilhado por cidades com população maior que 1500 e menor que 500.

SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500

Find the official names of cities with population bigger than 1500 or smaller than 500.

CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR)

Encontre os nomes oficiais de cidades com população maior que 1500 ou menor que 500.

SELECT Census_Ranking FROM city WHERE Status <> "Village"

Show the census ranking of cities whose status are not "Village".

CREATE TABLE city (Census_Ranking VARCHAR, Status VARCHAR)

Mostre o ranking do censo de cidades cujo status não é "Vila".

SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY COUNT(*) DESC LIMIT 1

which course has most number of registered students?

CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (course_Id VARCHAR)

Qual curso tem o maior número de alunos registrados?

SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY COUNT(*) LIMIT 1

what is id of students who registered some courses but the least number of courses in these students?

CREATE TABLE student_course_registrations (student_id VARCHAR)

o que é id de alunos que registraram alguns cursos, mas o menor número de cursos nesses alunos?

SELECT T2.first_name, T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id

what are the first name and last name of all candidates?

CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (first_name VARCHAR, last_name VARCHAR, person_id VARCHAR)

Qual o nome e sobrenome de todos os candidatos?

SELECT student_id FROM students WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance)

List the id of students who never attends courses?

CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE students (student_id VARCHAR)

Listar o id de alunos que nunca frequentam cursos?

SELECT student_id FROM student_course_attendance

List the id of students who attended some courses?

CREATE TABLE student_course_attendance (student_id VARCHAR)

Listar o ID dos alunos que participaram de alguns cursos?

SELECT T1.student_id, T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id

What are the ids of all students for courses and what are the names of those courses?

CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR)

Quais são os IDs de todos os alunos para os cursos e quais são os nomes desses cursos?

SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1

What is detail of the student who most recently registered course?

CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR); CREATE TABLE students (student_details VARCHAR, student_id VARCHAR)

Qual é o detalhe do aluno que mais recentemente se registrou no curso?

SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"

How many students attend course English?

CREATE TABLE student_course_attendance (course_id VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR)

Quantos alunos frequentam o curso de inglês?

SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171

How many courses do the student whose id is 171 attend?

CREATE TABLE courses (course_id VARCHAR); CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR)

Quantos cursos o aluno cujo id é 171 participar?

SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "stanley.monahan@example.org"

Find id of the candidate whose email is stanley.monahan@example.org?

CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (person_id VARCHAR, email_address VARCHAR)

Encontrar ID do candidato cujo e-mail é stanley.monahanexample.org?

SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1

Find id of the candidate who most recently accessed the course?

CREATE TABLE candidate_assessments (candidate_id VARCHAR, assessment_date VARCHAR)

Encontrar o ID do candidato que mais recentemente acessou o curso?

SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1

What is detail of the student who registered the most number of courses?

CREATE TABLE students (student_details VARCHAR, student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR)

Qual é o detalhe do aluno que registrou o maior número de cursos?

SELECT T1.student_id, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id

List the id of students who registered some courses and the number of their registered courses?

CREATE TABLE students (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR)

Liste o ID dos alunos que registraram alguns cursos e o número de seus cursos registrados?

SELECT T3.course_name, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id

How many registed students do each course have? List course name and the number of their registered students?

CREATE TABLE students (student_id VARCHAR); CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR)

Quantos alunos registrados cada curso tem? Listar o nome do curso e o número de seus alunos registrados?

SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"

Find id of candidates whose assessment code is "Pass"?

CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR)

Encontrar identificação de candidatos cujo código de avaliação é "Pass"?

SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"

Find the cell mobile number of the candidates whose assessment code is "Fail"?

CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (cell_mobile_number VARCHAR, person_id VARCHAR); CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR)

Encontre o número de celular dos candidatos cujo código de avaliação é "Falha"?

SELECT student_id FROM student_course_attendance WHERE course_id = 301

What are the id of students who registered course 301?

CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR)

Quais são os alunos que inscreveram o curso 301?

SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1

What is the id of the student who most recently registered course 301?

CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR)

Qual é o ID do aluno que mais recentemente registrou o curso 301?

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id

Find distinct cities of addresses of people?

CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE people_addresses (address_id VARCHAR)

Encontrar cidades distintas de endereços de pessoas?

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id

Find distinct cities of address of students?

CREATE TABLE students (student_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE people_addresses (address_id VARCHAR, person_id VARCHAR)

Encontrar cidades distintas de endereço de estudantes?

SELECT course_name FROM courses ORDER BY course_name

List the names of courses in alphabetical order?

CREATE TABLE courses (course_name VARCHAR)

Listar os nomes dos cursos em ordem alfabética?

SELECT first_name FROM people ORDER BY first_name

List the first names of people in alphabetical order?

CREATE TABLE people (first_name VARCHAR)

Listar os primeiros nomes de pessoas em ordem alfabética?

SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance

What are the id of students who registered courses or attended courses?

CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR)

Quais são as identidades dos alunos que se inscreveram ou participaram de cursos?

SELECT course_id FROM student_course_registrations WHERE student_id = 121 UNION SELECT course_id FROM student_course_attendance WHERE student_id = 121

Find the id of courses which are registered or attended by student whose id is 121?

CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR); CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR)

Encontrar o id de cursos que são registrados ou frequentados por estudante cujo id é 121?

SELECT * FROM student_course_registrations WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance)

What are all info of students who registered courses but not attended courses?

CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR)

Quais são todas as informações dos alunos que se inscreveram nos cursos, mas não participaram?

SELECT T2.student_id FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.registration_date

List the id of students who registered course statistics in the order of registration date.

CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR, registration_date VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR)

Liste o ID dos alunos que registraram as estatísticas do curso na ordem da data de registro.

SELECT T2.student_id FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.date_of_attendance

List the id of students who attended statistics courses in the order of attendance date.

CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR)

Liste o ID dos alunos que participaram de cursos de estatística na ordem de data de comparecimento.

SELECT date FROM weather WHERE max_temperature_f > 85

Give me the dates when the max temperature was higher than 85.

CREATE TABLE weather (date VARCHAR, max_temperature_f INTEGER)

Dê-me as datas em que a temperatura máxima foi superior a 85.

SELECT name FROM station WHERE lat < 37.5

What are the names of stations that have latitude lower than 37.5?

CREATE TABLE station (name VARCHAR, lat INTEGER)

Quais são os nomes das estações que têm latitude inferior a 37,5?

SELECT city, MAX(lat) FROM station GROUP BY city

For each city, return the highest latitude among its stations.

CREATE TABLE station (city VARCHAR, lat INTEGER)

Para cada cidade, retorne a latitude mais alta entre suas estações.

SELECT start_station_name, end_station_name FROM trip ORDER BY id LIMIT 3

Give me the start station and end station for the trips with the three oldest id.

CREATE TABLE trip (start_station_name VARCHAR, end_station_name VARCHAR, id VARCHAR)

Dê-me a estação inicial e a estação final para as viagens com a identificação mais antiga.

SELECT AVG(lat), AVG(long) FROM station WHERE city = "San Jose"

What is the average latitude and longitude of stations located in San Jose city?

CREATE TABLE station (lat INTEGER, long INTEGER, city VARCHAR)

Qual é a latitude e longitude média das estações localizadas em San Jose?

SELECT id FROM trip ORDER BY duration LIMIT 1

What is the id of the trip that has the shortest duration?

CREATE TABLE trip (id VARCHAR, duration VARCHAR)

Qual é o ID da viagem que tem a duração mais curta?

SELECT SUM(duration), MAX(duration) FROM trip WHERE bike_id = 636

What is the total and maximum duration of trips with bike id 636?

CREATE TABLE trip (duration INTEGER, bike_id VARCHAR)

Qual é a duração total e máxima das viagens com bike id 636?

SELECT zip_code, AVG(mean_temperature_f) FROM weather WHERE date LIKE "8/%" GROUP BY zip_code

For each zip code, return the average mean temperature of August there.

CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER, date VARCHAR)

Para cada código postal, retorne a temperatura média de agosto lá.

SELECT COUNT(DISTINCT bike_id) FROM trip

From the trip record, find the number of unique bikes.

CREATE TABLE trip (bike_id VARCHAR)

A partir do registro da viagem, encontre o número de bicicletas únicas.

SELECT COUNT(DISTINCT city) FROM station

What is the number of distinct cities the stations are located at?

CREATE TABLE station (city VARCHAR)

Qual é o número de cidades distintas em que as estações estão localizadas?

SELECT COUNT(*) FROM station WHERE city = "Mountain View"

How many stations does Mountain View city has?

CREATE TABLE station (city VARCHAR)

Quantas estações tem Mountain View?

SELECT DISTINCT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available = 7

Return the unique name for stations that have ever had 7 bikes available.

CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available VARCHAR)

Devolva o nome exclusivo para estações que já tiveram 7 bicicletas disponíveis.

SELECT start_station_name, start_station_id FROM trip WHERE start_date LIKE "8/%" GROUP BY start_station_name ORDER BY COUNT(*) DESC LIMIT 1

Which start station had the most trips starting from August? Give me the name and id of the station.

CREATE TABLE trip (start_station_name VARCHAR, start_station_id VARCHAR, start_date VARCHAR)

Qual estação de partida teve mais viagens a partir de agosto? Dê-me o nome e o ID da estação.

SELECT bike_id FROM trip WHERE zip_code = 94002 GROUP BY bike_id ORDER BY COUNT(*) DESC LIMIT 1

Which bike traveled the most often in zip code 94002?

CREATE TABLE trip (bike_id VARCHAR, zip_code VARCHAR)

Qual bicicleta viajou com mais frequência no código postal 94002?

SELECT COUNT(*) FROM weather WHERE mean_humidity > 50 AND mean_visibility_miles > 8

How many days had both mean humidity above 50 and mean visibility above 8?

CREATE TABLE weather (mean_humidity VARCHAR, mean_visibility_miles VARCHAR)

Quantos dias tiveram umidade média acima de 50 e visibilidade média acima de 8?

SELECT T1.lat, T1.long, T1.city FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id ORDER BY T2.duration LIMIT 1

What is the latitude, longitude, city of the station from which the shortest trip started?

CREATE TABLE trip (start_station_id VARCHAR, duration VARCHAR); CREATE TABLE station (lat VARCHAR, long VARCHAR, city VARCHAR, id VARCHAR)

Qual é a latitude, longitude, cidade da estação a partir da qual a viagem mais curta começou?

SELECT id FROM station WHERE city = "San Francisco" INTERSECT SELECT station_id FROM status GROUP BY station_id HAVING AVG(bikes_available) > 10

What are the ids of stations that are located in San Francisco and have average bike availability above 10.

CREATE TABLE status (id VARCHAR, station_id VARCHAR, city VARCHAR, bikes_available INTEGER); CREATE TABLE station (id VARCHAR, station_id VARCHAR, city VARCHAR, bikes_available INTEGER)

Quais são os IDs das estações que estão localizadas em São Francisco e têm disponibilidade média de bicicletas acima de 10.

SELECT T1.name, T1.id FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(T2.bikes_available) > 14 UNION SELECT name, id FROM station WHERE installation_date LIKE "12/%"

What are the names and ids of stations that had more than 14 bikes available on average or were installed in December?

CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE station (name VARCHAR, id VARCHAR, installation_date VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available INTEGER)

Quais são os nomes e IDs de estações que tinham mais de 14 bicicletas disponíveis em média ou foram instaladas em dezembro?

SELECT cloud_cover FROM weather WHERE zip_code = 94107 GROUP BY cloud_cover ORDER BY COUNT(*) DESC LIMIT 3

What is the 3 most common cloud cover rates in the region of zip code 94107?

CREATE TABLE weather (cloud_cover VARCHAR, zip_code VARCHAR)

Quais são as 3 taxas de cobertura de nuvem mais comuns na região do código postal 94107?

SELECT zip_code FROM weather GROUP BY zip_code ORDER BY AVG(mean_sea_level_pressure_inches) LIMIT 1

What is the zip code in which the average mean sea level pressure is the lowest?

CREATE TABLE weather (zip_code VARCHAR, mean_sea_level_pressure_inches INTEGER)

Qual é o código postal em que a pressão média do nível do mar é a mais baixa?

SELECT AVG(bikes_available) FROM status WHERE NOT station_id IN (SELECT id FROM station WHERE city = "Palo Alto")

What is the average bike availability in stations that are not located in Palo Alto?

CREATE TABLE status (bikes_available INTEGER, station_id VARCHAR, id VARCHAR, city VARCHAR); CREATE TABLE station (bikes_available INTEGER, station_id VARCHAR, id VARCHAR, city VARCHAR)

Qual é a disponibilidade média de bicicletas em estações que não estão localizadas em Palo Alto?

SELECT AVG(long) FROM station WHERE NOT id IN (SELECT station_id FROM status GROUP BY station_id HAVING MAX(bikes_available) > 10)

What is the average longitude of stations that never had bike availability more than 10?

CREATE TABLE station (long INTEGER, id VARCHAR, station_id VARCHAR, bikes_available INTEGER); CREATE TABLE status (long INTEGER, id VARCHAR, station_id VARCHAR, bikes_available INTEGER)

Qual é a longitude média das estações que nunca tiveram disponibilidade de bicicletas superior a 10?

SELECT date, zip_code FROM weather WHERE max_temperature_f >= 80

When and in what zip code did max temperature reach 80?

CREATE TABLE weather (date VARCHAR, zip_code VARCHAR, max_temperature_f VARCHAR)

Quando e em que código postal a temperatura máxima atingiu 80?

SELECT T1.id FROM trip AS T1 JOIN weather AS T2 ON T1.zip_code = T2.zip_code GROUP BY T2.zip_code HAVING AVG(T2.mean_temperature_f) > 60

Give me ids for all the trip that took place in a zip code area with average mean temperature above 60.

CREATE TABLE trip (id VARCHAR, zip_code VARCHAR); CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER)

Dê-me IDs para toda a viagem que ocorreu em uma área de código postal com temperatura média acima de 60.

SELECT zip_code, COUNT(*) FROM weather WHERE max_wind_Speed_mph >= 25 GROUP BY zip_code

For each zip code, return how many times max wind speed reached 25?

CREATE TABLE weather (zip_code VARCHAR, max_wind_Speed_mph VARCHAR)

Para cada código postal, retornar quantas vezes a velocidade máxima do vento atingiu 25?

SELECT date, zip_code FROM weather WHERE min_dew_point_f < (SELECT MIN(min_dew_point_f) FROM weather WHERE zip_code = 94107)

On which day and in which zip code was the min dew point lower than any day in zip code 94107?

CREATE TABLE weather (date VARCHAR, zip_code VARCHAR, min_dew_point_f INTEGER)

Em que dia e em que código postal foi o ponto de orvalho mínimo menor do que qualquer dia no código postal 94107?

SELECT T1.id, T2.installation_date FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id

For each trip, return its ending station's installation date.

CREATE TABLE station (installation_date VARCHAR, id VARCHAR); CREATE TABLE trip (id VARCHAR, end_station_id VARCHAR)

Para cada viagem, devolva a data de instalação da estação final.

SELECT T1.id FROM trip AS T1 JOIN station AS T2 ON T1.start_station_id = T2.id ORDER BY T2.dock_count DESC LIMIT 1

Which trip started from the station with the largest dock count? Give me the trip id.

CREATE TABLE trip (id VARCHAR, start_station_id VARCHAR); CREATE TABLE station (id VARCHAR, dock_count VARCHAR)

Que viagem começou na estação com a maior contagem de docas?

SELECT COUNT(*) FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id WHERE T2.city <> "San Francisco"

Count the number of trips that did not end in San Francisco city.

CREATE TABLE trip (end_station_id VARCHAR); CREATE TABLE station (id VARCHAR, city VARCHAR)

Conte o número de viagens que não terminaram na cidade de São Francisco.

SELECT date FROM weather WHERE zip_code = 94107 AND EVENTS <> "Fog" AND EVENTS <> "Rain"

In zip code 94107, on which day neither Fog nor Rain was not observed?

CREATE TABLE weather (date VARCHAR, EVENTS VARCHAR, zip_code VARCHAR)

No código postal 94107, em que dia nem Nevoeiro nem Chuva foi observado?

SELECT id FROM station WHERE lat > 37.4 EXCEPT SELECT station_id FROM status GROUP BY station_id HAVING MIN(bikes_available) < 7

What are the ids of stations that have latitude above 37.4 and never had bike availability below 7?

CREATE TABLE status (id VARCHAR, station_id VARCHAR, lat INTEGER, bikes_available INTEGER); CREATE TABLE station (id VARCHAR, station_id VARCHAR, lat INTEGER, bikes_available INTEGER)

Quais são os identificadores de estações que têm latitude acima de 37,4 e nunca tiveram disponibilidade de bicicleta abaixo de 7?

SELECT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(bikes_available) > 10 EXCEPT SELECT name FROM station WHERE city = "San Jose"

What are names of stations that have average bike availability above 10 and are not located in San Jose city?

CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE status (station_id VARCHAR); CREATE TABLE station (name VARCHAR, city VARCHAR, bikes_available INTEGER)

Quais são os nomes das estações que têm disponibilidade média de bicicletas acima de 10 e não estão localizadas na cidade de San Jose?

SELECT name, lat, city FROM station ORDER BY lat LIMIT 1

What are the name, latitude, and city of the station with the lowest latitude?

CREATE TABLE station (name VARCHAR, lat VARCHAR, city VARCHAR)

Qual é o nome, a latitude e a cidade da estação com a latitude mais baixa?

SELECT date, mean_temperature_f, mean_humidity FROM weather ORDER BY max_gust_speed_mph DESC LIMIT 3

What are the date, mean temperature and mean humidity for the top 3 days with the largest max gust speeds?

CREATE TABLE weather (date VARCHAR, mean_temperature_f VARCHAR, mean_humidity VARCHAR, max_gust_speed_mph VARCHAR)

Quais são a data, a temperatura média e a umidade média para os 3 dias superiores com as maiores velocidades máximas de rajada?

SELECT city, COUNT(*) FROM station GROUP BY city HAVING COUNT(*) >= 15

List the name and the number of stations for all the cities that have at least 15 stations.

CREATE TABLE station (city VARCHAR)

Listar o nome e o número de estações para todas as cidades que têm pelo menos 15 estações.

SELECT start_station_id, start_station_name FROM trip GROUP BY start_station_name HAVING COUNT(*) >= 200

Find the ids and names of stations from which at least 200 trips started.

CREATE TABLE trip (start_station_id VARCHAR, start_station_name VARCHAR)

Encontre os IDs e nomes das estações a partir das quais pelo menos 200 viagens começaram.

SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_visibility_miles) < 10

Find the zip code in which the average mean visibility is lower than 10.

CREATE TABLE weather (zip_code VARCHAR, mean_visibility_miles INTEGER)

Encontre o código postal em que a visibilidade média é inferior a 10.