Q:

Is this copy constructor elision? 

The following code doesn't call the copy constructor. 
struct X
{
   int x;
   X(int num)
   {
      x = num;
      std::cout << "ctor" << std::endl;
   }
   X(const X& other)
   {
      std::cout << "copy ctor" << std::endl;
   }
};

int main(int argc, _TCHAR* argv[])
{
   X* x = new X(3);
   X* y(x);
}

Output:
ctor

Is it copy-ctor elision? 

A:

The code
X* x = new X(3);
X* y(x);

is not the same as
X x(3);
X* y = new X(x);

You're not copying objects, but pointers.  After X* y(x);, both pointers will point to the same object.