Q:

Find the intersection between a linear equation and a quadratic equation, where the linear equation is x, not y

What the title says essentially.  Where one is x=0.6(y-4)^2+4 and another is x=15
The confusing part for me is that it is x=15, there is no y. There are a lot of help for y=?,  but x=? 
NEVERMIND, I figured out how to do it.  Sorry guys ;)
I am guessing I need to sub in 15 into the equation, then solve for y

A:

You would need to sub in 15 to the equation x=0.6(y-4)^2+4
That will give you the two y values in which the line intersects with the quadratic.