Q:

Is it true that for any integral domain $D$ , $Frac(D)[x] \cong Frac(D[x])$ ? 

Is it true that for any integral domain $D$ , $Frac(D)[x] \cong Frac(D[x])$ ? ,  where $Frac$ denotes the fraction field of the integral domain .  I am at a complete loss , please help .  Thanks in advance .  

A:

HINT
Is $Frac(D)[x]$ always a field?  Is $Frac(D[x])$ always a field?  Note the first one has the form $R[x]$ and the second one $Frac[S]$, with $R$ and $S$ rings.