public static String itostrb(int binary)
	{
		/*
		 * The idea for this one and the next method is that we continually find the remainder if we divided the number
		 * by the base, this is the digit at the given space, adding that to the appropriate spot in the result. Once we
		 * add to the string, we divide the number by its base until it reaches 0.
		 */
		final int BASE = 2;
		final int ASCII = 48;
		String result = "";
		do{
			result = (char) ((binary % BASE) + ASCII) + result;
			binary /= BASE;
		}while(binary > 0);
		return result;
	}