# Task
Some children are playing rope skipping game. Children skip the rope at roughly the same speed: `once per second`. If the child fails during the jump, he needs to tidy up the rope and continue. This will take `3 seconds`.
You are given an array `failedCount`, where each element is the jump count at the failed. ie. `[12,23,45]` means the child failed 3 times in the game process. The 1st mistake occurred when he jumped 12 times; The 2nd mistake occurred when he jumped 23 times; The 3rd mistake occurred when he jumped 45 times.
Your task is to calculate how many times the child jumped in 60 seconds.
Note: Each child persisted at least 60 jumps, which meant it could have been over 60 seconds, but the child continued to skip rope.
# Input/Output
`[input]` integer array `failedCount`
`0 ≤ failedCount.length ≤ 60`
`1 ≤ failedCount[i] ≤ 60`
`[output]` an integer
how many times the child jumped in 60 seconds.
# Example
For `failedCount = []`, the output should be `60`.
There is no mistake in the game process. So the child jumped 60 times in 60 seconds.
For `failedCount = [12, 23, 45]`, the output should be `51`.
```
The 1st mistake occurred when he jumped 12 times. --> 12 seconds past.
Tidy up the rope and continue.                    --> 15 seconds past.
The 2nd mistake occurred when he jumped 23 times. --> 26 seconds past.
Tidy up the rope and continue.                    --> 29 seconds past.
The 3rd mistake occurred when he jumped 45 times. --> 51 seconds past.
Tidy up the rope and continue.                    --> 54 seconds past.
When he jumped 51 times                           --> 60 seconds past.
```
def tiaosheng(arr):
    t = 0
    j = 0
    while t < 60:
        t += 1
        j += 1
        if j in arr:
            t += 3
    return j
def tiaosheng(arr):
    t = 0
    j = 0
    while t < 60:
        t += 1
        j += 1
        if j in arr:
            t += 3
    return j