Given a m * n matrix grid which is sorted in non-increasing order both row-wise and column-wise. 
Return the number of negative numbers in grid.
Example 1:
Input: grid = [[4,3,2,-1],[3,2,1,-1],[1,1,-1,-2],[-1,-1,-2,-3]]
Output: 8
Explanation: There are 8 negatives number in the matrix.
Example 2:
Input: grid = [[3,2],[1,0]]
Output: 0
Example 3:
Input: grid = [[1,-1],[-1,-1]]
Output: 3
Example 4:
Input: grid = [[-1]]
Output: 1
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 100
-100 <= grid[i][j] <= 100
class Solution:
    def countNegatives(self, grid: List[List[int]]) -> int:
        count=0
        for i in grid:
            for j in i:
                if(j<0):
                    count+=1
                
            
        return count

class Solution:
    def countNegatives(self, grid: List[List[int]]) -> int:
        count=0
        for i in grid:
            for j in i:
                if(j<0):
                    count+=1
                
            
        return count
