Write a function 
```javascript 
tripledouble(num1,num2)
```
```python
triple_double(num1, num2)
```
which takes numbers `num1` and `num2` and returns `1` if there is a straight triple of a number at any place in `num1` and also a straight double of the **same** number in `num2`.
If this isn't the case, return `0`
## Examples
```python
triple_double(451999277, 41177722899) == 1
# num1 has straight triple 999s and num2 has straight double 99s
triple_double(1222345, 12345) == 0
# num1 has straight triple 2s but num2 has only a single 2
triple_double(12345, 12345) == 0
triple_double(666789, 12345667) == 1
```
import re
def triple_double(num1, num2):
    str = "{0}|{1}".format(num1,num2)
    regex = re.compile(r'(\d)(\1){2}.*\|.*(\1){2}')
    match = regex.search(str)
    return True if match else False
import re
def triple_double(num1, num2):
    str = "{0}|{1}".format(num1,num2)
    regex = re.compile(r'(\d)(\1){2}.*\|.*(\1){2}')
    match = regex.search(str)
    return True if match else False