Base on the fairy tale [Diamonds and Toads](https://en.wikipedia.org/wiki/Diamonds_and_Toads) from Charles Perrault. In this kata you will have to complete a function that take 2 arguments: 
- A string, that correspond to what the daugther says.
- A string, that tell you wich fairy the girl have met, this one can be `good` or `evil`. 
The function should return the following count as a hash:
- If the girl have met the `good` fairy:
  - count 1 `ruby` everytime you see a `r` and 2 everytime you see a `R`
  - count 1 `crystal` everytime you see a `c` and 2 everytime you see a `C`
- If the girl have met the `evil` fairy: 
  - count 1 `python` everytime you see a `p` and 2 everytime uou see a `P`
  - count 1 `squirrel` everytime you see a `s` and 2 everytime you see a `S`
**Note**: For this kata I decided to remplace the normal `Diamonds` and `Toads` by some programming languages. And just discover that [Squirrel](https://en.wikipedia.org/wiki/Squirrel_(programming_language) is a programming language.
def diamonds_and_toads(sentence,fairy):
    res={}
    if fairy == 'good':
        res['ruby']=sentence.count('r')+sentence.count('R')*2
        res['crystal']=sentence.count('c')+sentence.count('C')*2
    elif fairy == 'evil':
        res['python']=sentence.count('p')+sentence.count('P')*2
        res['squirrel']=sentence.count('s')+sentence.count('S')*2
    
    return res
def diamonds_and_toads(sentence,fairy):
    res={}
    if fairy == 'good':
        res['ruby']=sentence.count('r')+sentence.count('R')*2
        res['crystal']=sentence.count('c')+sentence.count('C')*2
    elif fairy == 'evil':
        res['python']=sentence.count('p')+sentence.count('P')*2
        res['squirrel']=sentence.count('s')+sentence.count('S')*2
    
    return res