Abhiram needs to search for an antidote. He comes to know that clue for finding the antidote is carefully hidden by KrishnaMurthy in the form of a puzzle.
The puzzle consists of a string S and a keywordK. Abhiram needs to find the string of position of anagrams R of the keyword in the string which is the clue. 
The antidote is found in the box numbered R. Help him find his clue R.
Anagram: A word or phrase that is made by arranging the letters of another word or phrase in a different order. Eg: 'elvis' and 'lives' are both anagrams of each other.
Note: Consider, Tac and act are not anagrams(case sensitive).
-----Input:-----
The first line contains a string S of length land the second line contains a keyword K.
-----Output:-----
Output contains a line"The antidote is found in R." Where R= string of positions of anagrams.(the position of the first word in the string is 1).
-----Constraints:-----
1<=l<=500
1<=k<=50
-----Example:-----
Input:
cat is the act of tac
cat
Output:
The antidote is found in 46.
s = input().split(" ")
k = input()
l = "abcdefghijklmnopqrstuvwxyz"
a = 26*[0]
n = len(k)
c = ""
for i in range(n):
 a[l.find(k[i])]+=1
for i in range(len(s)):
 x = s[i]
 m = len(x)
 if (m==n):
  b = 26*[0] 
  for j in range(m):
   b[l.find(x[j])]+=1
  if a==b and x!=k:
   c += str(i+1)
print("The antidote is found in "+c+".")
s = input().split(" ")
k = input()
l = "abcdefghijklmnopqrstuvwxyz"
a = 26*[0]
n = len(k)
c = ""
for i in range(n):
 a[l.find(k[i])]+=1
for i in range(len(s)):
 x = s[i]
 m = len(x)
 if (m==n):
  b = 26*[0] 
  for j in range(m):
   b[l.find(x[j])]+=1
  if a==b and x!=k:
   c += str(i+1)
print("The antidote is found in "+c+".")