Your task is to ___Reverse and Combine Words___. It's not too difficult, but there are some things you have to consider...
### So what to do?
Input: String containing different "words" separated by spaces
```
1. More than one word? Reverse each word and combine first with second, third with fourth and so on...
   (odd number of words => last one stays alone, but has to be reversed too)
2. Start it again until there's only one word without spaces
3. Return your result...
```
### Some easy examples:
```
Input:  "abc def"
Output: "cbafed"
Input:  "abc def ghi 123"
Output: "defabc123ghi"
Input:  "abc def gh34 434ff 55_eri 123 343"
Output: "43hgff434cbafed343ire_55321"
```
I think it's clear?! First there are some static tests, later on random tests too...
### Hope you have fun! :-)
def reverse_and_combine_text(text):
    lst=text.split(' ')
    #return lst
    if len(lst)==1:
        return text    
    while len(lst)!=1:
        lst1=[]      
        for i in lst:
            a=''.join(list(reversed(i)))
            lst1.append(a)
        #return lst1
        lst2=[]
        if len(lst)%2==0:
            for x in range(0,len(lst),2):
                lst2.append(lst1[x]+lst1[x+1])
            lst=lst2
        else:
            for x in range(0,len(lst)-1,2):
                lst2.append(lst1[x]+lst1[x+1])
            lst2.append(lst1[-1])
            lst=lst2
            #return lst
    return lst[0]
def reverse_and_combine_text(text):
    lst=text.split(' ')
    #return lst
    if len(lst)==1:
        return text    
    while len(lst)!=1:
        lst1=[]      
        for i in lst:
            a=''.join(list(reversed(i)))
            lst1.append(a)
        #return lst1
        lst2=[]
        if len(lst)%2==0:
            for x in range(0,len(lst),2):
                lst2.append(lst1[x]+lst1[x+1])
            lst=lst2
        else:
            for x in range(0,len(lst)-1,2):
                lst2.append(lst1[x]+lst1[x+1])
            lst2.append(lst1[-1])
            lst=lst2
            #return lst
    return lst[0]