In a country called Chef Land, there was a lot of monetary fraud, so Chefu, the head of the country, decided to choose new denominations of the local currency ― all even-valued coins up to an integer $N$ should exist. After a few days, a citizen complained that there was no way to create an odd value, so Chefu decided that he should also introduce coins with value $1$. Formally, you are given an integer $N$; for $v = 1$ and each even positive integer $v \le N$, coins with value $v$ exist.
You are also given an integer $S$. To handle transactions quickly, find the minimum number of coins needed to pay a price $S$.
-----Input-----
- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
- The first and only line of each test case contains two space-separated integers $S$ and $N$.
-----Output-----
For each test case, print a single line containing one integer ― the minimum number of coins.
-----Constraints-----
- $1 \le T \le 10,000$
- $1 \le S \le 10^9$
- $2 \le N \le 10^9$
- $N$ is even
-----Subtasks-----
Subtask #1 (100 points): original constraints
-----Example Input-----
4
2 2
1 14
30 10
31 4
-----Example Output-----
1
1
3
9
-----Explanation-----
Example case 1: One coin with value $2$ is sufficient.
Example case 2: We need to use one coin with value $1$.
Example case 3: We need $3$ coins, each with value $10$.
Example case 4: We can use seven coins with value $4$, one coin with value $2$ and one coin with value $1$.
t = int(input())
for _ in range(t):
 s,n = map(int, input().split())
 if s<n:
  if s==1:
   coins = 1
  elif s%2==0:
   coins = 1
  else:
   coins = 2
 else:
  coins = s//n
  r = s%n
  if r==1:
   coins = coins + 1
  elif r!=0 and r%2==0:
   coins = coins + 1
  elif r%2!=0:
   coins = coins + 2
 print(coins)
t = int(input())
for _ in range(t):
 s,n = map(int, input().split())
 if s<n:
  if s==1:
   coins = 1
  elif s%2==0:
   coins = 1
  else:
   coins = 2
 else:
  coins = s//n
  r = s%n
  if r==1:
   coins = coins + 1
  elif r!=0 and r%2==0:
   coins = coins + 1
  elif r%2!=0:
   coins = coins + 2
 print(coins)