Gigi is a clever monkey, living in the zoo, his teacher (animal keeper) recently taught him some knowledge of "0".
In Gigi's eyes, "0" is a character contains some circle(maybe one, maybe two).
So, a is a "0",b is a "0",6 is also a "0"，and 8 have two "0" ,etc...
Now, write some code to count how many "0"s in the text.
Let us see who is smarter? You ? or monkey?
Input always be a string(including words numbers and symbols)，You don't need to verify it, but pay attention to the difference between uppercase and lowercase letters.
Here is a table of characters：
one zeroabdegopq069DOPQR         () <-- A pair of braces as a zerotwo zero%&B8
Output will be a number of "0".
two = "%&B8"
some = f"abdegopq069DOPQR{two}"

def countzero(string):
    return sum(2 if c in two else 1 for c in string.replace("()", "0") if c in some)
two = "%&B8"
some = f"abdegopq069DOPQR{two}"

def countzero(string):
    return sum(2 if c in two else 1 for c in string.replace("()", "0") if c in some)