Chef likes all arrays equally. But he likes some arrays more equally than others. In particular, he loves Rainbow Arrays. 
An array is Rainbow if it has the following structure:
- First a1 elements equal 1. 
- Next a2 elements equal 2. 
- Next a3 elements equal 3. 
- Next a4 elements equal 4. 
- Next a5 elements equal 5. 
- Next a6 elements equal 6. 
- Next a7 elements equal 7. 
- Next a6 elements equal 6. 
- Next a5 elements equal 5. 
- Next a4 elements equal 4. 
- Next a3 elements equal 3. 
- Next a2 elements equal 2. 
- Next a1 elements equal 1. 
- ai can be any non-zero positive integer.
- There are no other elements in array. 
Help Chef in finding out if the given array is a Rainbow Array or not. 
-----Input-----
- The first line of the input contains an integer T denoting the number of test cases.
- The first line of each test case contains an integer N, denoting the number of elements in the given array. 
- The second line contains N space-separated integers A1, A2, ..., AN denoting the elements of array. 
-----Output-----
- For each test case, output a line containing "yes" or "no" (without quotes) corresponding to the case if the array is rainbow array or not. 
-----Constraints-----
- 1 ≤ T ≤ 100
- 7 ≤ N ≤ 100
- 1 ≤ Ai ≤ 10
-----Subtasks-----
- Subtask 1 (100 points) : Original constraints
-----Example-----
Input
3
19
1 2 3 4 4 5 6 6 6 7 6 6 6 5 4 4 3 2 1
14
1 2 3 4 5 6 7 6 5 4 3 2 1 1
13
1 2 3 4 5 6 8 6 5 4 3 2 1
Output
yes
no
no
-----Explanation-----
The first example satisfies all the conditions. 
The second example has 1 element of value 1 at the beginning and 2 elements of value 1 at the end. 
The third one has no elements with value 7 after elements with value 6.
t = int(input())
for i in range(t):
 l = int(input())
 li = list(map(int, input().split()))[:l]
 a = []
 b = [1, 2, 3, 4, 5, 6, 7]
 c = li[::-1]
 for i in li:
  if i not in a:
   a.append(i)
 a.sort()
 if a == b and li == c:
  print('yes')
 else:
  print('no')
t = int(input())
for i in range(t):
 l = int(input())
 li = list(map(int, input().split()))[:l]
 a = []
 b = [1, 2, 3, 4, 5, 6, 7]
 c = li[::-1]
 for i in li:
  if i not in a:
   a.append(i)
 a.sort()
 if a == b and li == c:
  print('yes')
 else:
  print('no')