Given a triangle of consecutive odd numbers:
```
             1
          3     5
       7     9    11
   13    15    17    19
21    23    25    27    29
...
```
find the triangle's row knowing its index (the rows are 1-indexed), e.g.:
```
odd_row(1)  ==  [1]
odd_row(2)  ==  [3, 5]
odd_row(3)  ==  [7, 9, 11]
```
**Note**: your code should be optimized to handle big inputs.
___
The idea for this kata was taken from this kata: [Sum of odd numbers](https://www.codewars.com/kata/sum-of-odd-numbers)
def odd_row(n):
    stop = n * (n+1)
    return list(range(stop - n*2 + 1, stop, 2))
def odd_row(n):
    stop = n * (n+1)
    return list(range(stop - n*2 + 1, stop, 2))