This kata is from check py.checkio.org
You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.
Let's look at a few examples:
* array = [1, 2, 3, 4] and N = 2, then the result is 3^2 == 9;
* array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.
def index(array, n):
    for idx, i in enumerate(array):
        if idx == n:
            x = array[idx] ** n
            return x
    else:
        return -1
def index(array, n):
    for idx, i in enumerate(array):
        if idx == n:
            x = array[idx] ** n
            return x
    else:
        return -1