## Task
Given a positive integer as input, return the output as a string in the following format: 
Each element, corresponding to a digit of the number, multiplied by a power of 10 in such a way that with the sum of these elements you can obtain the original number.
## Examples
Input | Output
---   | ---
0     | ""
56    | "5\*10+6"
60    | "6\*10"
999   | "9\*100+9\*10+9"
10004 | "1\*10000+4"
Note: `input >= 0`
def simplify(n):
    s = str(n)
    l = len(s)
    result = []
    for i, d in enumerate(s, 1):
        if int(d):
            p = "" if l == i else f"*{10**(l-i)}"
            result.append(f"{d}{p}")
    return "+".join(result)


#    s = str(n)
#    return  "+".join(f"{d}{f'*{10**(-i)}' if i else ''}" for i, d in enumerate(s, -len(s)+1) if int(d))

def simplify(n):
    s = str(n)
    l = len(s)
    result = []
    for i, d in enumerate(s, 1):
        if int(d):
            p = "" if l == i else f"*{10**(l-i)}"
            result.append(f"{d}{p}")
    return "+".join(result)


#    s = str(n)
#    return  "+".join(f"{d}{f'*{10**(-i)}' if i else ''}" for i, d in enumerate(s, -len(s)+1) if int(d))
