# Introduction
There is a war and nobody knows - the alphabet war!  
There are two groups of hostile letters. The tension between left side letters and right side letters was too high and the war began.
# Task
Write a function that accepts `fight` string consists of only small letters and return who wins the fight. When the left side wins return `Left side wins!`, when the right side wins return `Right side wins!`, in other case return `Let's fight again!`.
The left side letters and their power:
```
 w - 4
 p - 3
 b - 2
 s - 1
```
The right side letters and their power:
```
 m - 4
 q - 3
 d - 2
 z - 1
```
The other letters don't have power and are only victims.
# Example
# Alphabet war Collection
Alphavet war 
Alphabet war - airstrike - letters massacre
Alphabet wars - reinforces massacre
Alphabet wars - nuclear strike
Alphabet war - Wo lo loooooo priests join the war
def alphabet_war(fight):
    left_alp = {'w': 4, 'p': 3, 'b': 2, 's': 1}
    right_alp = {'m': 4, 'q': 3, 'd': 2, 'z': 1}
    
    left_score = 0
    right_score = 0
    for i in left_alp:
        left_score += fight.count(i) * left_alp[i]
        
    for i in right_alp:
        right_score += fight.count(i) * right_alp[i]
    
    return "Right side wins!" if right_score > left_score else "Let's fight again!" if right_score == left_score else "Left side wins!"

def alphabet_war(fight):
    left_alp = {'w': 4, 'p': 3, 'b': 2, 's': 1}
    right_alp = {'m': 4, 'q': 3, 'd': 2, 'z': 1}
    
    left_score = 0
    right_score = 0
    for i in left_alp:
        left_score += fight.count(i) * left_alp[i]
        
    for i in right_alp:
        right_score += fight.count(i) * right_alp[i]
    
    return "Right side wins!" if right_score > left_score else "Let's fight again!" if right_score == left_score else "Left side wins!"
