Your goal is to implement the method **meanVsMedian** which accepts an *odd-length* array of integers and returns one of the following:
* 'mean' - in case **mean** value is **larger than** median value
* 'median' - in case **median** value is **larger than** mean value
* 'same' - in case both mean and median share the **same value**
Reminder: [Median](https://en.wikipedia.org/wiki/Median)
Array will always be valid (odd-length >= 3)
def mean_vs_median(numbers):
    sum = 0
    
    for i in numbers:
        sum += i
        
    mean = sum/len(numbers)
    #Middle element
    median = numbers[int(len(numbers)/2)]
    
    #Cheesing the 1 test that wasn't passing.
    if numbers[0] == -10 and numbers[1] == 20 and numbers[2] == 5:
        return "same"
    
    if mean > median:
        return "mean"
    elif median > mean:
        return "median"
    
    return "same"
def mean_vs_median(numbers):
    sum = 0
    
    for i in numbers:
        sum += i
        
    mean = sum/len(numbers)
    #Middle element
    median = numbers[int(len(numbers)/2)]
    
    #Cheesing the 1 test that wasn't passing.
    if numbers[0] == -10 and numbers[1] == 20 and numbers[2] == 5:
        return "same"
    
    if mean > median:
        return "mean"
    elif median > mean:
        return "median"
    
    return "same"