On a broken calculator that has a number showing on its display, we can perform two operations:
Double: Multiply the number on the display by 2, or;
Decrement: Subtract 1 from the number on the display.
Initially, the calculator is displaying the number X.
Return the minimum number of operations needed to display the number Y.
Example 1:
Input: X = 2, Y = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.
Example 2:
Input: X = 5, Y = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.
Example 3:
Input: X = 3, Y = 10
Output: 3
Explanation:  Use double, decrement and double {3 -> 6 -> 5 -> 10}.
Example 4:
Input: X = 1024, Y = 1
Output: 1023
Explanation: Use decrement operations 1023 times.
Note:
1 <= X <= 10^9
1 <= Y <= 10^9
class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        res = 0
        while X < Y:
            res += Y % 2 + 1
            Y = int((Y + 1) / 2)
        return res + X - Y

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        res = 0
        while X < Y:
            res += Y % 2 + 1
            Y = int((Y + 1) / 2)
        return res + X - Y
