We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i.
Vertex i has an integer a_i written on it.
For every integer k from 1 through N, solve the following problem:
 - We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.
Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.
-----Constraints-----
 - 2 \leq N \leq 2 \times 10^5
 - 1 \leq a_i \leq 10^9
 - 1 \leq u_i , v_i \leq N
 - u_i \neq v_i
 - The given graph is a tree.
 - All values in input are integers.
-----Input-----
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}
-----Output-----
Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.
-----Sample Input-----
10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10
-----Sample Output-----
1
2
3
3
4
4
5
2
2
3
For example, the sequence A obtained from the shortest path from Vertex 1 to Vertex 5 is 1,2,5,3,4. Its longest increasing subsequence is A_1, A_2, A_4, A_5, with the length of 4.

import math
import bisect

n = int(input())
alist = [0]+list(map(int,input().split()))
uv_list = []
for i in range(n-1):
    u,v = list(map(int,input().split()))
    if u > v:
        u, v = v, u
    uv_list.append([u,v])

tree = [[] for _ in range(n+1)]
for i in range(n-1):
    uv = uv_list[i]
    tree[uv[0]].append(uv[1])
    tree[uv[1]].append(uv[0])
    

queue = [1]
used = [0]*(n+1)
ans = [0]*(n+1)
dp = []
stack = []
while queue != []:
    cur = queue[-1]

    if used[cur] == 0:
        if cur == 1:
            dp.append(alist[cur])
            stack.append([len(dp)-1,None])
        else:
            if alist[cur] > dp[-1]:
                dp.append(alist[cur])
                stack.append([len(dp)-1,None])
            else:
                offset = bisect.bisect_left(dp,alist[cur])
                stack.append([offset,dp[offset]])
                dp[offset] = alist[cur]
        ans[cur] = len(dp)

    if tree[cur] != [] and used[cur] == 0:
        for child in tree[cur]:
            if used[child] == 0:
                queue.append(child)
    else:
        queue.pop()

        #reverse
        back = stack.pop()
        if back[1] == None:
            dp.pop()
        else:
            dp[back[0]] = back[1]
    used[cur] = 1
for i in range(n):
    print((ans[i+1]))


import math
import bisect

n = int(input())
alist = [0]+list(map(int,input().split()))
uv_list = []
for i in range(n-1):
    u,v = list(map(int,input().split()))
    if u > v:
        u, v = v, u
    uv_list.append([u,v])

tree = [[] for _ in range(n+1)]
for i in range(n-1):
    uv = uv_list[i]
    tree[uv[0]].append(uv[1])
    tree[uv[1]].append(uv[0])
    

queue = [1]
used = [0]*(n+1)
ans = [0]*(n+1)
dp = []
stack = []
while queue != []:
    cur = queue[-1]

    if used[cur] == 0:
        if cur == 1:
            dp.append(alist[cur])
            stack.append([len(dp)-1,None])
        else:
            if alist[cur] > dp[-1]:
                dp.append(alist[cur])
                stack.append([len(dp)-1,None])
            else:
                offset = bisect.bisect_left(dp,alist[cur])
                stack.append([offset,dp[offset]])
                dp[offset] = alist[cur]
        ans[cur] = len(dp)

    if tree[cur] != [] and used[cur] == 0:
        for child in tree[cur]:
            if used[child] == 0:
                queue.append(child)
    else:
        queue.pop()

        #reverse
        back = stack.pop()
        if back[1] == None:
            dp.pop()
        else:
            dp[back[0]] = back[1]
    used[cur] = 1
for i in range(n):
    print((ans[i+1]))
