=====Function Descriptions=====
itertools.product()
This tool computes the cartesian product of input iterables.
It is equivalent to nested for-loops.
For example, product(A, B) returns the same as ((x,y) for x in A for y in B).
Sample Code
>>> from itertools import product
>>>
>>> print list(product([1,2,3],repeat = 2))
[(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)]
>>>
>>> print list(product([1,2,3],[3,4]))
[(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)]
>>>
>>> A = [[1,2,3],[3,4,5]]
>>> print list(product(*A))
[(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 3), (3, 4), (3, 5)]
>>>
>>> B = [[1,2,3],[3,4,5],[7,8]]
>>> print list(product(*B))
[(1, 3, 7), (1, 3, 8), (1, 4, 7), (1, 4, 8), (1, 5, 7), (1, 5, 8), (2, 3, 7), (2, 3, 8), (2, 4, 7), (2, 4, 8), (2, 5, 7), (2, 5, 8), (3, 3, 7), (3, 3, 8), (3, 4, 7), (3, 4, 8), (3, 5, 7), (3, 5, 8)]
=====Problem Statement=====
You are given a two lists A and B. Your task is to compute their cartesian product AXB.
Example
A = [1, 2]
B = [3, 4]
AxB = [(1, 3), (1, 4), (2, 3), (2, 4)]
Note: A and B are sorted lists, and the cartesian product's tuples should be output in sorted order.
=====Input Format=====
The first line contains the space separated elements of list A.
The second line contains the space separated elements of list B.
Both lists have no duplicate integer elements.
=====Constraints=====
0<A<30
0<B<30
=====Output Format=====
Output the space separated tuples of the cartesian product.
import itertools
ar1 = list(map(int,input().split()))
ar2 = list(map(int,input().split()))
cross = list(itertools.product(ar1,ar2))
for i in cross:
    print(i,end=' ')

import itertools
ar1 = list(map(int,input().split()))
ar2 = list(map(int,input().split()))
cross = list(itertools.product(ar1,ar2))
for i in cross:
    print(i,end=' ')
