Given a number `n`, make a down arrow shaped pattern.
For example, when `n = 5`, the output would be:
    123454321
     1234321
      12321
       121
        1
and for `n = 11`, it would be:
    123456789010987654321
     1234567890987654321
      12345678987654321
       123456787654321
        1234567654321
         12345654321
          123454321
           1234321
            12321
             121
              1
An important thing to note in the above example is that the numbers greater than 9 still stay single digit, like after 9 it would be 0 - 9 again instead of 10 - 19.
Note: There are spaces for the indentation on the left of each line and no spaces on the right.
Have fun!
get_a_down_arrow_of=lambda n,s=0: "" if n<1 else " "*s+"1" if n==1 else "\n".join([" "*s+"".join([str(q%10) for q in range(1,n+1)]+[str(q%10) for q in range(n-1,0,-1)])]+[get_a_down_arrow_of(n-1,s+1)])
get_a_down_arrow_of=lambda n,s=0: "" if n<1 else " "*s+"1" if n==1 else "\n".join([" "*s+"".join([str(q%10) for q in range(1,n+1)]+[str(q%10) for q in range(n-1,0,-1)])]+[get_a_down_arrow_of(n-1,s+1)])