Complete the function that takes two numbers as input, ```num``` and ```nth``` and return the `nth` digit of `num` (counting from right to left).
## Note
- If ```num``` is negative, ignore its sign and treat it as a positive value
- If ```nth``` is not positive, return `-1`
- Keep in mind that `42 = 00042`. This means that ```findDigit(42, 5)``` would return `0`
## Examples
```
findDigit(5673, 4)     returns 5
findDigit(129, 2)      returns 2
findDigit(-2825, 3)    returns 8
findDigit(-456, 4)     returns 0
findDigit(0, 20)       returns 0
findDigit(65, 0)       returns -1
findDigit(24, -8)      returns -1
```
def find_digit(num, nth):
    if nth <= 0: return -1
    num = str(abs(num))
    return 0 if nth > len(num) else int(num[::-1][nth-1])

def find_digit(num, nth):
    if nth <= 0: return -1
    num = str(abs(num))
    return 0 if nth > len(num) else int(num[::-1][nth-1])
