##Task:
You have to write a function **pattern** which creates the following pattern upto n number of rows. 
* If the Argument is 0 or a Negative Integer then it should return "" i.e. empty string.
* If any odd number is passed as argument then the pattern should last upto the largest even number which is smaller than the passed odd number.
* If the argument is 1 then also it should return "".
##Examples:
pattern(8):
    22
    4444
    666666
    88888888
pattern(5):
    22
    4444
```Note: There are no spaces in the pattern```
```Hint: Use \n in string to jump to next line```
pattern=lambda n:'\n'.join(i*str(i)for i in range(2,n+1,2))
pattern=lambda n:'\n'.join(i*str(i)for i in range(2,n+1,2))