In this Kata, you will implement a function `count` that takes an integer and returns the number of digits in `factorial(n)`. 
For example, `count(5) = 3`, because `5! = 120`, and `120` has `3` digits.  
More examples in the test cases. 
Brute force is not possible. A little research will go a long way, as this is a well known series.
Good luck!
Please also try:
from math import ceil, log10, pi, e

def count(n):
    return ceil(log10(2*pi*n)/2+n*(log10(n/e)))
from math import ceil, log10, pi, e

def count(n):
    return ceil(log10(2*pi*n)/2+n*(log10(n/e)))