Given an integer n, return the number of trailing zeroes in n!.
Example 1:
Input: 3
Output: 0
Explanation: 3! = 6, no trailing zero.
Example 2:
Input: 5
Output: 1
Explanation: 5! = 120, one trailing zero.
Note: Your solution should be in logarithmic time complexity.
class Solution:
     def trailingZeroes(self, n):
         """
         :type n: int
         :rtype: int
         """
         count = 0
         while n > 0:
             n /= 5
             count += int(n)
         return int(count)
class Solution:
     def trailingZeroes(self, n):
         """
         :type n: int
         :rtype: int
         """
         count = 0
         while n > 0:
             n /= 5
             count += int(n)
         return int(count)