Greg has an array a = a_1, a_2, ..., a_{n} and m operations. Each operation looks as: l_{i}, r_{i}, d_{i}, (1 ≤ l_{i} ≤ r_{i} ≤ n). To apply operation i to the array means to increase all array elements with numbers l_{i}, l_{i} + 1, ..., r_{i} by value d_{i}.
Greg wrote down k queries on a piece of paper. Each query has the following form: x_{i}, y_{i}, (1 ≤ x_{i} ≤ y_{i} ≤ m). That means that one should apply operations with numbers x_{i}, x_{i} + 1, ..., y_{i} to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
-----Input-----
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 10^5). The second line contains n integers: a_1, a_2, ..., a_{n} (0 ≤ a_{i} ≤ 10^5) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: l_{i}, r_{i}, d_{i}, (1 ≤ l_{i} ≤ r_{i} ≤ n), (0 ≤ d_{i} ≤ 10^5).
Next k lines contain the queries, the query number i is written as two integers: x_{i}, y_{i}, (1 ≤ x_{i} ≤ y_{i} ≤ m).
The numbers in the lines are separated by single spaces.
-----Output-----
On a single line print n integers a_1, a_2, ..., a_{n} — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
-----Examples-----
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
from sys import stdin, stdout

rd = lambda: list(map(int, stdin.readline().split()))

n, m, k = rd()
a = rd()
b = [rd() for _ in range(m)]
x = [0]*(m+1)
y = [0]*(n+1)

for _ in range(k):
  l, r = rd()
  x[l-1] += 1
  x[r  ] -= 1

s = 0
for i in range(m):
  l, r, d = b[i]
  s += x[i]
  y[l-1] += s*d
  y[r  ] -= s*d

s = 0
for i in range(n):
  s += y[i]
  a[i] += s
print(' '.join(map(str, a)))
from sys import stdin, stdout

rd = lambda: list(map(int, stdin.readline().split()))

n, m, k = rd()
a = rd()
b = [rd() for _ in range(m)]
x = [0]*(m+1)
y = [0]*(n+1)

for _ in range(k):
  l, r = rd()
  x[l-1] += 1
  x[r  ] -= 1

s = 0
for i in range(m):
  l, r, d = b[i]
  s += x[i]
  y[l-1] += s*d
  y[r  ] -= s*d

s = 0
for i in range(n):
  s += y[i]
  a[i] += s
print(' '.join(map(str, a)))