## Task:
You have to create a function `isPronic` to check whether the argument passed is a Pronic Number and return true if it is & false otherwise.
### Description:
`Pronic Number` -A pronic number, oblong number, rectangular number or heteromecic number, is a number which is the product of two consecutive integers, that is, n(n + 1).
> The first few Pronic Numbers are - 0, 2, 6, 12, 20, 30, 42...
### Explanation:
      0 = 0 × 1   // ∴  0 is a Pronic Number
      2 = 1 × 2   // ∴  2 is a Pronic Number
      6 = 2 × 3   // ∴  6 is a Pronic Number
     12 = 3 × 4   // ∴ 12 is a Pronic Number
     20 = 4 × 5   // ∴ 20 is a Pronic Number
     30 = 5 × 6   // ∴ 30 is a Pronic Number
     42 = 6 × 7   // ∴ 42 is a Pronic Number
import math
def is_pronic(n):
    return n >= 0 and math.sqrt(1 + 4 * n) % 1 == 0
import math
def is_pronic(n):
    return n >= 0 and math.sqrt(1 + 4 * n) % 1 == 0