Your task it to return ```true``` if the fractional part (rounded to 1 digit) of the result (```a``` / ```b```) exists, more than ```0``` and is multiple of ```n```.
Otherwise return ```false```. (For Python return True or False)
All arguments are positive digital numbers.
Rounding works like toFixed() method. (if more than...5 rounds up)
Find exapmles below: 
```
isMultiple(5, 2, 3) -> false // 2.5 -> 5 is not multiple of 3
isMultiple(5, 3, 4) -> false // 1.7 -> 7 is not multiple of 4
isMultiple(5, 4, 3) -> true // 1.3 -> 3 is multiple of 3
isMultiple(666, 665, 2) -> false // 1.0 -> return false
```
def isMultiple(a, b, n):
    x=int((a/b-a//b)*10+0.5)
    return 0<x<10 and x%n==0
def isMultiple(a, b, n):
    x=int((a/b-a//b)*10+0.5)
    return 0<x<10 and x%n==0