Given an integer array arr, return true if there are three consecutive odd numbers in the array. Otherwise, return false.
Example 1:
Input: arr = [2,6,4,1]
Output: false
Explanation: There are no three consecutive odds.
Example 2:
Input: arr = [1,2,34,3,4,5,7,23,12]
Output: true
Explanation: [5,7,23] are three consecutive odds.
Constraints:
1 <= arr.length <= 1000
1 <= arr[i] <= 1000
class Solution:
    def threeConsecutiveOdds(self, arr: List[int]) -> bool:
        a=0
        while(a < len(arr)-2):
            if arr[a]&1 and arr[a+1]&1 and arr[a+2]&1:
                return True
            elif arr[a+2]&1==0:
                a+=3
            elif arr[a+1]&1==0:
                a+=2
            elif arr[a]&1==0:
                a+=1         
        return False

class Solution:
    def threeConsecutiveOdds(self, arr: List[int]) -> bool:
        a=0
        while(a < len(arr)-2):
            if arr[a]&1 and arr[a+1]&1 and arr[a+2]&1:
                return True
            elif arr[a+2]&1==0:
                a+=3
            elif arr[a+1]&1==0:
                a+=2
            elif arr[a]&1==0:
                a+=1         
        return False
