##Task:
You have to write a function **pattern** which creates the following pattern upto n number of rows. *If the Argument is 0 or a Negative Integer then it should return "" i.e. empty string.*
##Pattern:
    (n)
    (n)(n-1)
    (n)(n-1)(n-2)
    ................
    .................
    (n)(n-1)(n-2)....4
    (n)(n-1)(n-2)....43
    (n)(n-1)(n-2)....432
    (n)(n-1)(n-2)....4321
##Examples:
pattern(4):
    4
    43
    432
    4321
pattern(6):
    6
    65
    654
    6543
    65432
    654321
```Note: There are no blank spaces```
```Hint: Use \n in string to jump to next line```
def pattern(n):
    return '\n'.join(''.join(str(j) for j in range(n, i, -1)) for i in range(n-1, -1, -1))
def pattern(n):
    return '\n'.join(''.join(str(j) for j in range(n, i, -1)) for i in range(n-1, -1, -1))