Given two integer arrays of equal length target and arr.
In one step, you can select any non-empty sub-array of arr and reverse it. You are allowed to make any number of steps.
Return True if you can make arr equal to target, or False otherwise.
Example 1:
Input: target = [1,2,3,4], arr = [2,4,1,3]
Output: true
Explanation: You can follow the next steps to convert arr to target:
1- Reverse sub-array [2,4,1], arr becomes [1,4,2,3]
2- Reverse sub-array [4,2], arr becomes [1,2,4,3]
3- Reverse sub-array [4,3], arr becomes [1,2,3,4]
There are multiple ways to convert arr to target, this is not the only way to do so.
Example 2:
Input: target = [7], arr = [7]
Output: true
Explanation: arr is equal to target without any reverses.
Example 3:
Input: target = [1,12], arr = [12,1]
Output: true
Example 4:
Input: target = [3,7,9], arr = [3,7,11]
Output: false
Explanation: arr doesn't have value 9 and it can never be converted to target.
Example 5:
Input: target = [1,1,1,1,1], arr = [1,1,1,1,1]
Output: true
Constraints:
target.length == arr.length
1 <= target.length <= 1000
1 <= target[i] <= 1000
1 <= arr[i] <= 1000
class Solution:
    def canBeEqual(self, target: List[int], arr: List[int]) -> bool:
        for i in range(len(target)):
            for j in range(i, len(target)):
                if arr[j] == target[i]:
                    break
            else:
                return False
            
            arr[i:j+1] = reversed(arr[i:j+1:])
        
        return arr == target
class Solution:
    def canBeEqual(self, target: List[int], arr: List[int]) -> bool:
        for i in range(len(target)):
            for j in range(i, len(target)):
                if arr[j] == target[i]:
                    break
            else:
                return False
            
            arr[i:j+1] = reversed(arr[i:j+1:])
        
        return arr == target