You are given a integer $n$ ($n > 0$). Find any integer $s$ which satisfies these conditions, or report that there are no such numbers:
In the decimal representation of $s$:   $s > 0$,  $s$ consists of $n$ digits,  no digit in $s$ equals $0$,  $s$ is not divisible by any of it's digits. 
-----Input-----
The input consists of multiple test cases. The first line of the input contains a single integer $t$ ($1 \leq t \leq 400$), the number of test cases. The next $t$ lines each describe a test case.
Each test case contains one positive integer $n$ ($1 \leq n \leq 10^5$).
It is guaranteed that the sum of $n$ for all test cases does not exceed $10^5$.
-----Output-----
For each test case, print an integer $s$ which satisfies the conditions described above, or "-1" (without quotes), if no such number exists. If there are multiple possible solutions for $s$, print any solution.
-----Example-----
Input
4
1
2
3
4
Output
-1
57
239
6789
-----Note-----
In the first test case, there are no possible solutions for $s$ consisting of one digit, because any such solution is divisible by itself.
For the second test case, the possible solutions are: $23$, $27$, $29$, $34$, $37$, $38$, $43$, $46$, $47$, $49$, $53$, $54$, $56$, $57$, $58$, $59$, $67$, $68$, $69$, $73$, $74$, $76$, $78$, $79$, $83$, $86$, $87$, $89$, $94$, $97$, and $98$.
For the third test case, one possible solution is $239$ because $239$ is not divisible by $2$, $3$ or $9$ and has three digits (none of which equals zero).
tc = int(input())
for _ in range(tc):
	n = int(input())
	if n > 1:
		print("2" + "3" * (n-1))
	else:
		print(-1)

tc = int(input())
for _ in range(tc):
	n = int(input())
	if n > 1:
		print("2" + "3" * (n-1))
	else:
		print(-1)
