Given a mathematical equation that has `*,+,-,/`, reverse it as follows:
```Haskell
solve("100*b/y") = "y/b*100"
solve("a+b-c/d*30") = "30*d/c-b+a"
```
More examples in test cases. 
Good luck!
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def solve(eq):
    #
    # implemantation takes advantage of abscence of spaces
    #
    leq = (eq.replace('*', ' * ')
             .replace('/', ' / ')
             .replace('+', ' + ')
             .replace('-', ' - ')
             .split(' ')) 

    out = ''.join(leq[::-1])

    return out


def solve(eq):
    #
    # implemantation takes advantage of abscence of spaces
    #
    leq = (eq.replace('*', ' * ')
             .replace('/', ' / ')
             .replace('+', ' + ')
             .replace('-', ' - ')
             .split(' ')) 

    out = ''.join(leq[::-1])

    return out

