We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).  
Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.
Example 1:
Input: 
bits = [1, 0, 0]
Output: True
Explanation: 
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.
Example 2:
Input: 
bits = [1, 1, 1, 0]
Output: False
Explanation: 
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.
Note:
1 .
bits[i] is always 0 or 1.
class Solution:
     def isOneBitCharacter(self, bits):
         """
         :type bits: List[int]
         :rtype: bool
         """
         i = 0
         while i < (len(bits)-1):
             if bits[i] == 1:
                 i += 2
             else:
                 i += 1
         if i == len(bits):
             return False
         else:
             return True
class Solution:
     def isOneBitCharacter(self, bits):
         """
         :type bits: List[int]
         :rtype: bool
         """
         i = 0
         while i < (len(bits)-1):
             if bits[i] == 1:
                 i += 2
             else:
                 i += 1
         if i == len(bits):
             return False
         else:
             return True