A variation of determining leap years, assuming only integers are used and years can be negative and positive.
Write a function which will return the days in the year and the year entered in a string.  For example 2000, entered as an integer, will return as a string 2000 has 366 days
There are a few assumptions we will accept the year 0, even though there is no year 0 in the Gregorian Calendar.
Also the basic rule for validating a leap year are as follows
Most years that can be divided evenly by 4 are leap years. 
Exception: Century years are NOT leap years UNLESS they can be evenly divided by 400.
So the years 0, -64 and 2016 will return 366 days.
Whilst 1974, -10 and 666 will return 365 days.
def year_days(year):
    if year % 4 != 0 :
        return f'{year} has {365} days'
    elif year % 4 == 0 and year % 100 == 0 and year % 400 != 0:
        return f'{year} has {365} days'
    else:
        return f'{year} has {366} days'
        
    


def year_days(year):
    if year % 4 != 0 :
        return f'{year} has {365} days'
    elif year % 4 == 0 and year % 100 == 0 and year % 400 != 0:
        return f'{year} has {365} days'
    else:
        return f'{year} has {366} days'
        
    

