You have a large electronic screen which can display up to $998244353$ decimal digits. The digits are displayed in the same way as on different electronic alarm clocks: each place for a digit consists of $7$ segments which can be turned on and off to compose different digits. The following picture describes how you can display all $10$ decimal digits:
[Image]
As you can see, different digits may require different number of segments to be turned on. For example, if you want to display $1$, you have to turn on $2$ segments of the screen, and if you want to display $8$, all $7$ segments of some place to display a digit should be turned on.
You want to display a really large integer on the screen. Unfortunately, the screen is bugged: no more than $n$ segments can be turned on simultaneously. So now you wonder what is the greatest integer that can be displayed by turning on no more than $n$ segments.
Your program should be able to process $t$ different test cases.
-----Input-----
The first line contains one integer $t$ ($1 \le t \le 100$) — the number of test cases in the input.
Then the test cases follow, each of them is represented by a separate line containing one integer $n$ ($2 \le n \le 10^5$) — the maximum number of segments that can be turned on in the corresponding testcase.
It is guaranteed that the sum of $n$ over all test cases in the input does not exceed $10^5$.
-----Output-----
For each test case, print the greatest integer that can be displayed by turning on no more than $n$ segments of the screen. Note that the answer may not fit in the standard $32$-bit or $64$-bit integral data type.
-----Example-----
Input
2
3
4
Output
7
11
t=int(input())
for _ in range(t):
    n=int(input())
    if n%2==0:
        x=n//2
        for i in range(x):
            print(1,end='')
    else:
        x=n//2
        x-=1
        print(7,end='')
        for i in range(x):
            print(1,end='')
    print()
t=int(input())
for _ in range(t):
    n=int(input())
    if n%2==0:
        x=n//2
        for i in range(x):
            print(1,end='')
    else:
        x=n//2
        x-=1
        print(7,end='')
        for i in range(x):
            print(1,end='')
    print()