###Task:
You have to write a function **pattern** which returns the following Pattern(See Examples) upto n rows, where n is parameter.
####Rules/Note:
* If the Argument is 0 or a Negative Integer then it should return "" i.e. empty string.
* The length of each line = (2n-1).
* Range of n is (-∞,100]
###Examples:
pattern(5):
        12345
       12345 
      12345  
     12345   
    12345    
pattern(10):
             1234567890
            1234567890 
           1234567890  
          1234567890   
         1234567890    
        1234567890     
       1234567890      
      1234567890       
     1234567890        
    1234567890         
pattern(15):
                  123456789012345
                 123456789012345 
                123456789012345  
               123456789012345   
              123456789012345    
             123456789012345     
            123456789012345      
           123456789012345       
          123456789012345        
         123456789012345         
        123456789012345          
       123456789012345           
      123456789012345            
     123456789012345             
    123456789012345              
pattern(20):
                       12345678901234567890
                      12345678901234567890 
                     12345678901234567890  
                    12345678901234567890   
                   12345678901234567890    
                  12345678901234567890     
                 12345678901234567890      
                12345678901234567890       
               12345678901234567890        
              12345678901234567890         
             12345678901234567890          
            12345678901234567890           
           12345678901234567890            
          12345678901234567890             
         12345678901234567890              
        12345678901234567890               
       12345678901234567890                
      12345678901234567890                 
     12345678901234567890                  
    12345678901234567890
def pattern(n):
    return "\n".join(" "*(n-1-i)+"".join([str(i%10) for i in range(1,n+1)])+" "*i for i in range(n))

def pattern(n):
    return "\n".join(" "*(n-1-i)+"".join([str(i%10) for i in range(1,n+1)])+" "*i for i in range(n))
