In this Kata, we are going to determine if the count of each of the characters in a string can be equal if we remove a single character from that string.
For example:
```
solve('abba') = false -- if we remove any character, the count of each character will not be equal.
solve('abbba') = true -- if we remove one b, the count of each character becomes 2.
solve('aaaa') = true -- if we remove one character, the remaining characters have same count.
solve('wwwf') = true -- if we remove f, the remaining letters have same count.
```
More examples in the test cases. Empty string is not tested.
Good luck!
from collections import Counter

def solve(s):
    return any(len(set(Counter(s.replace(c, '', 1)).values())) == 1 for c in s)
from collections import Counter

def solve(s):
    return any(len(set(Counter(s.replace(c, '', 1)).values())) == 1 for c in s)