You have $n$ gifts and you want to give all of them to children. Of course, you don't want to offend anyone, so all gifts should be equal between each other. The $i$-th gift consists of $a_i$ candies and $b_i$ oranges.
During one move, you can choose some gift $1 \le i \le n$ and do one of the following operations:
  eat exactly one candy from this gift (decrease $a_i$ by one);  eat exactly one orange from this gift (decrease $b_i$ by one);  eat exactly one candy and exactly one orange from this gift (decrease both $a_i$ and $b_i$ by one). 
Of course, you can not eat a candy or orange if it's not present in the gift (so neither $a_i$ nor $b_i$ can become less than zero).
As said above, all gifts should be equal. This means that after some sequence of moves the following two conditions should be satisfied: $a_1 = a_2 = \dots = a_n$ and $b_1 = b_2 = \dots = b_n$ (and $a_i$ equals $b_i$ is not necessary).
Your task is to find the minimum number of moves required to equalize all the given gifts.
You have to answer $t$ independent test cases.
-----Input-----
The first line of the input contains one integer $t$ ($1 \le t \le 1000$) — the number of test cases. Then $t$ test cases follow.
The first line of the test case contains one integer $n$ ($1 \le n \le 50$) — the number of gifts. The second line of the test case contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 10^9$), where $a_i$ is the number of candies in the $i$-th gift. The third line of the test case contains $n$ integers $b_1, b_2, \dots, b_n$ ($1 \le b_i \le 10^9$), where $b_i$ is the number of oranges in the $i$-th gift.
-----Output-----
For each test case, print one integer: the minimum number of moves required to equalize all the given gifts.
-----Example-----
Input
5
3
3 5 6
3 2 3
5
1 2 3 4 5
5 4 3 2 1
3
1 1 1
2 2 2
6
1 1000000000 1000000000 1000000000 1000000000 1000000000
1 1 1 1 1 1
3
10 12 8
7 5 4
Output
6
16
0
4999999995
7
-----Note-----
In the first test case of the example, we can perform the following sequence of moves:
  choose the first gift and eat one orange from it, so $a = [3, 5, 6]$ and $b = [2, 2, 3]$;  choose the second gift and eat one candy from it, so $a = [3, 4, 6]$ and $b = [2, 2, 3]$;  choose the second gift and eat one candy from it, so $a = [3, 3, 6]$ and $b = [2, 2, 3]$;  choose the third gift and eat one candy and one orange from it, so $a = [3, 3, 5]$ and $b = [2, 2, 2]$;  choose the third gift and eat one candy from it, so $a = [3, 3, 4]$ and $b = [2, 2, 2]$;  choose the third gift and eat one candy from it, so $a = [3, 3, 3]$ and $b = [2, 2, 2]$.
t=int(input())
for _ in range(t):
    n=int(input())
    a=list(map(int,input().split()))
    b=list(map(int,input().split()))
    ma=min(a)
    mb=min(b)
    ans=0
    for i in range(n):
        ga=a[i]-ma 
        gb=b[i]-mb 
        ans=ans+max(ga,gb)
    print(ans)
t=int(input())
for _ in range(t):
    n=int(input())
    a=list(map(int,input().split()))
    b=list(map(int,input().split()))
    ma=min(a)
    mb=min(b)
    ans=0
    for i in range(n):
        ga=a[i]-ma 
        gb=b[i]-mb 
        ans=ans+max(ga,gb)
    print(ans)