Bob watches TV every day. He always sets the volume of his TV to $b$. However, today he is angry to find out someone has changed the volume to $a$. Of course, Bob has a remote control that can change the volume.
There are six buttons ($-5, -2, -1, +1, +2, +5$) on the control, which in one press can either increase or decrease the current volume by $1$, $2$, or $5$. The volume can be arbitrarily large, but can never be negative. In other words, Bob cannot press the button if it causes the volume to be lower than $0$.
As Bob is so angry, he wants to change the volume to $b$ using as few button presses as possible. However, he forgets how to do such simple calculations, so he asks you for help. Write a program that given $a$ and $b$, finds the minimum number of presses to change the TV volume from $a$ to $b$.
-----Input-----
Each test contains multiple test cases. The first line contains the number of test cases $T$ ($1 \le T \le 1\,000$). Then the descriptions of the test cases follow.
Each test case consists of one line containing two integers $a$ and $b$ ($0 \le a, b \le 10^{9}$) — the current volume and Bob's desired volume, respectively.
-----Output-----
For each test case, output a single integer — the minimum number of presses to change the TV volume from $a$ to $b$. If Bob does not need to change the volume (i.e. $a=b$), then print $0$.
-----Example-----
Input
3
4 0
5 14
3 9
Output
2
3
2
-----Note-----
In the first example, Bob can press the $-2$ button twice to reach $0$. Note that Bob can not press $-5$ when the volume is $4$ since it will make the volume negative. 
In the second example, one of the optimal ways for Bob is to press the $+5$ twice, then press $-1$ once.
In the last example, Bob can press the $+5$ once, then press $+1$.

t = int(input())

for gg in range(t):
	
	a, b = list(map(int, input().split()))
	d = abs(a-b)
	if d == 0:
		print(0)
	else:
		ans = 0
		ans += d//5
		d%=5
		ans+=d//2
		d%=2
		ans+=d
		print(ans)


t = int(input())

for gg in range(t):
	
	a, b = list(map(int, input().split()))
	d = abs(a-b)
	if d == 0:
		print(0)
	else:
		ans = 0
		ans += d//5
		d%=5
		ans+=d//2
		d%=2
		ans+=d
		print(ans)
