OSA Publishing > Optics Express > Volume 19 > Issue 3 > Page 2046Daisuke Akamatsu,1,2 Masami Yasuda,1,2 Takuya Kohno,1,2,3,* Atsushi Onae,1 and Feng-Lei Hong1,2Nucl. Phys. B Proc. Suppl. (2)(1) P o u t 2 ω = η P i n ω = P i n ω tanh 2 ( η 0 P i n ω L ) ,(2) d e f f = c 0 ω ε 0 c 0 n ( ω ) n ( 2 ω ) A e f f η 0 ,(3) η = ν b 2 sn 2 ( η 0 P i n ω L ν b , ν b 4 ) ,(4) ν b = 1 Δ k / 4 η 0 P i n ω + ( 1 + ( Δ k / 4 η 0 P i n ω ) 2 ) 1 / 2
