"""Python 2/3 compat layer leftovers.""" import decimal as _decimal import math as _math import warnings from contextlib import redirect_stderr, redirect_stdout from io import BytesIO from io import StringIO as UnicodeIO from types import SimpleNamespace from .textTools import Tag, bytechr, byteord, bytesjoin, strjoin, tobytes, tostr warnings.warn( "The py23 module has been deprecated and will be removed in a future release. " "Please update your code.", DeprecationWarning, ) __all__ = [ "basestring", "bytechr", "byteord", "BytesIO", "bytesjoin", "open", "Py23Error", "range", "RecursionError", "round", "SimpleNamespace", "StringIO", "strjoin", "Tag", "tobytes", "tostr", "tounicode", "unichr", "unicode", "UnicodeIO", "xrange", "zip", ] class Py23Error(NotImplementedError): pass RecursionError = RecursionError StringIO = UnicodeIO basestring = str isclose = _math.isclose isfinite = _math.isfinite open = open range = range round = round3 = round unichr = chr unicode = str zip = zip tounicode = tostr def xrange(*args, **kwargs): raise Py23Error("'xrange' is not defined. Use 'range' instead.") def round2(number, ndigits=None): """ Implementation of Python 2 built-in round() function. Rounds a number to a given precision in decimal digits (default 0 digits). The result is a floating point number. Values are rounded to the closest multiple of 10 to the power minus ndigits; if two multiples are equally close, rounding is done away from 0. ndigits may be negative. See Python 2 documentation: https://docs.python.org/2/library/functions.html?highlight=round#round """ if ndigits is None: ndigits = 0 if ndigits < 0: exponent = 10 ** (-ndigits) quotient, remainder = divmod(number, exponent) if remainder >= exponent // 2 and number >= 0: quotient += 1 return float(quotient * exponent) else: exponent = _decimal.Decimal("10") ** (-ndigits) d = _decimal.Decimal.from_float(number).quantize( exponent, rounding=_decimal.ROUND_HALF_UP ) return float(d)