18. (E) The correct rearrangement after rearrangement is CFDBAE. And Second sentence after rearrangement is F. So,Option E is the correct answer. 19. (D) The correct rearrangement after rearrangement is CFDBAE. And Third sentence after rearrangment is D. So,Option D is the correct answer. 20. (E) The correct rearrangement after rearrangement is CFDBAE. And Last sentence after rearrangement is E. So,Option E is the correct answer. 21.(A) Option A is correct answer. 22.(B) Option B is correct answer. 23.(D) Option D is correct answer. 24.(C) Option C is correct answer. 25.(A) Option A is correct answer. 26. (B) Option B is correct answer. 27. (A) Option A is correct answer. 28. (A) Option A is correct answer. 29.(C) Option C is correct answer. 30. (A) Option A is correct answer. 31. (C) No. of distributed by Company B = 0.9 × 6300 = 5670 No. of books received by each distributer = 5670/10 = 576 Books distributed by company F = 0.75 × 7200 = 5400 Books received by each distributer = = 900  Required Difference = 900 – 567 = 333 32. (B) No. of books distributed by Company B = 0.9 × 6300 = 5670 No. of books distributed by company C = 0.85 × 5600 = 4760  Required Ratio = 5670 : 4760  567 : 476 33. (A) Books distributed by company E among distributers = 0.8 × 5500 = 4400
Books received buy each distributer = = 550 Books distributed by Company F among distributor = 0.75 × 7200 = 5400 Books received by each distributer = = 900  Required % = = 63.63  64% 34. (C) total no. of books distributed by Company D among distributor = 0.7 × 3600 = 2520 total no. of distributed books = 4x + 5x = 9x = 9x = 2520 x = x = 280  No. of non-academic books = 4 × 280 = 1120 35. (D) No. books distributed company B = 0.9 × 6300 = 5670 No. of books distributed by company E = 0.8 × 5500 = 4400  Required % = = 128.86  129% 36. (A) Let mark price = 100x After discount of 40% selling price = = 60x loss  10% CP = = ...(i) When discount of 20% is given SP = = 80x CP = 80x – 7.5 ...(ii) Comparing (i) & (ii) = 80x – 7.5
x = CP = = 37.5 Rs. 37. (D) Let amound = 99x Initially amount was distributed in ratio = x : y : z = 1 : 3 : 5 Amount received by Y = 33x After erroneous distribution, amount was distributed in ratio = x : y : z = 2 : 3 : 6 Amount got by y after erroneous distribution = 27x Amount lost by y = Rs. 60 = 33x – 27x = 60 x = 10 Amount = 99 × 10 = 990 38. (A) Let age of Rahul's father = 7x Age of Rahul = = 4x Age of 3 year ago = = x % of Rahul' son = x +3 = = 33 = 12x = 99 – 3 = 96 x = 8 Required difference = (7 × 8) – (8 + 3) = 45 39. (C) Let speed of first and second trains in m/sec be 2x and 3x sum of the length of train and second train = 180 + 270 = 450 m sum of their speeds = 2x = 3x = 5x = m/s x = m/s Time taken by second train = = = 54 seconds 40. (E) Let Rakesh's investment = x Ram investment = 31500
Shyam investment = 27000 profit Ratio Rakesh : Ram : Shyam x × 12 : 31500×8 : 27000×8 3x : 63000 : 54000 total profit = 19200 Rakesh's profit = = = = 192x = 75x + 117000 × 25 x = = 25000 41-45 41. (A) = 112 + 1010 1122 42. (B) 43. (C) 44. (E) 45. (B) 11 × 3 – 4 = 29 29 × 3 – 4 = 83 83 × 3 – 4 = 245 245 × 3 – 4 = 731 731 × 3 – 4 = 2189 46-50 46. (C) = = = = ?  8 47. (D) 685 – 181 = (42% – 28%) of ? 504 = 14% of ? = ?  3600 48. (A) 103 × 721 [35% × 80% × 40% – 35% × 20% × 30%] = ? = 721000 = ? = 721 × 91 = ? 65611 49. (C)  = x 6 + 806 = x
x = 812 50. (E) = 20% of ? = ? = = 5 51. (B) Part filled without leak in 1 hour = Part filled with leak in 1 hour = Part emptied by leak in 1 hour : =  x = 7 52. (B) Average of 7 No. = 304 Sum of that seven no. = 304 × 7 = 2128 Average of first three no. = 456 sum of that first three No. = 456 × 3  1368 Sum of last three No. = 234 × 3 = 702  Third Number = 2128 – (1368 + 702) = 58 53. (B) We know the difference b/w C.I & S.I for 3 is, C.I. - S.I. = 1280 = by solving it we get P = 10,000 54. (C) Area of rectangle = length × Breadth Area of given rectangle = 9 × 8 = 72 cm2 As per the given data, area of square is twice the area of rectangle Area of square = 2 × 72 cm2 = 144 cm2 Area of square = a2, where a = side of the square 144 = a2 = a = side of square = a = 12 cm for square, diameter of circumcircle = Diagonal of square = = cm Radius of circumcircle = cm 55. (C) mixture of 90 liter of the spirit and water contains 20% water first mixture = (20/100) × 90 = 18 litres
spirit = 90 – 18 = 72 litres After adding some water to the mixture water became 50% of the new mixture 7 = litres of in new mixture = 50% of new mixture total litres of new mixture = = 144 litres So water to be added = 144 – 90 = 54 litres 56-60 56. (B) x = y = x > y 57. (A) Multiple (i) by 7 and multiply (ii) by 3 and subtract (ii) from (i) y = x = x > y 58. (E) x = – 7, y = – 6, 59. (A) x = y = x > y 60 (D) x = 15, 24 y = 25, 24 y > x 61. (C) No. of A level employees in II = 0.14 × 25500 = 3570 No. of D level employees in I = 0.33 × 2050 = 6765 Required % = = 52.77 53% 62. (E) Total No. of F level employees in I = 0.13 × = 2665 total no. of E level employees in II = 0.18 × 2550 = 4590 Required No. = 4590 + 2665 = 7255 63. (B) No. of B level employees in I = 0.05 × 20500 = 1025 No. of B level employees II
= 0.16 × 255 = 4080 Required % = 74.87 75% 64. (C) No. of C level employees in organization I = 0.14 × 20500 = 2870 Let x be the % of employees in organization II which is approximately equal to level C in I = = x = x = 11.25 12% F in II is approximately equal to level C in I. 65. (C) Maximum no. of employees are there for level C. 66-70 66. (E) 67. (A) 68. (C) 69. (B) 70. (B) 71-73 71. (E) 72. (C) 73. (A) 74-75 74. (D) A > M (False) D < R 75. (B) Q = S (False) R > U (True) 76-78 76. (A) 77. (D) 78. (E) 79-80 79. (B) total = 26 + 40 + 30 = 96 A (26L) 30B (40 R)
New position B (71R) A (56L) the total strength of the children is 96 80. (A) A left H and New position = 26 + (71 – 40) – 1 = 56 A (26L) 30B (40R) New position B (71 R) A (56L) The position of A from the left end in the new position is 56th 81-85 81. (C) 82. (C) 83. (B) 84. (D) 85. (D) 86-90 86. (C) 87. (E) 88. (D) 89. (A) 90. (D) 91. (B) 92. (A) 93. (E) online can be as either "do" or "ti" 94. (C) Alphabetical Arrange:- ENTHUSIASM AEHIMNSSTU Each leitre changed with Next letter word: BFIJNOTTUV Forth letter of the word T 95. (D) 96-100 96. (D) 97. (D) 98. (A) 99. (A) 100. (A)