1 3.G.1 One answer is correct. Two answers are correct. OR All answers are correct, but there is no explanation in Part (c). All answers and explanations in Part (c) are correct. Explanation in Part (c) may include information that reveals a possible misconception about the properties of quadrilaterals, e.g., a statement that each shape has at least one set of sides that do not intersect. All answers are correct. The trapezoid is circled. The rhombus and rectangle are crossed out. All three shapes are quadrilaterals. Explanation includes that they each have four sides. 2 3.G.1 Student answers one or fewer problems correctly. Student correctly answers Part (a) and Part (b). Student correctly draws all three shapes and names the shapes in Parts (a) and (b). Side lengths in Parts (b) and (c) may or may not be labeled. All answers are correct and appropriate work is shown. Student: Draws and names a shape with four right angles (e.g., a rectangle). Draws and labels side lengths of a four-sided shape with no right angles and no equal sides (e.g., a trapezoid). Draws and labels side lengths of a rhombus using triangles (may use more than two triangles). 3 3.MD.8 The answer is incorrect and work demonstrates an entirely incorrect strategy (e.g., 5 × 7). OR The answer may or may not be correct. The student work shows a strategy for solving that is unclear. Student work demonstrates a strategy for solving that makes sense for the problem, but answer may be incorrect because of a Student answers that Mr. Cooper uses 24 meters of fence. The student’s work demonstrates a strategy for solving that makes sense for
Only a correct answer is given with no other work shown. calculation error. the problem (e.g., a rectangular picture of the stall with side lengths appropriately labeled and an equation like 5 + 5 + 7 + 7 or 10 + 14). 4 3.OA.8 Student may or may not have a correct answer. Student work is missing in one or both parts. OR Student may or may not have a correct answer. Student work in both parts demonstrates a strategy or equation that is inappropriate for the problem. Student may or may not have a correct answer. Strategy may be unclear or inappropriate for the problem. Answer may or may not include a letter for the unknown, and equation may not entirely match the problem. Student answers at least one part correctly; an incorrect answer in one part is the result of a calculation error. AND Student work demonstrates a strategy appropriate to the problem. Student writes an appropriate equation(s) including a letter for the unknown. All answers are correct and appropriate work is shown. Student answers 42 feet of wood trim. Student work demonstrates a strategy appropriate to the problem (e.g., 10 + 10 + 8 + 8 + 3 + 3.) Student answers 24 more feet of wood trim are needed for the bedroom than for the closet. Student writes an appropriate equation(s) including a letter for the unknown (e.g., 8 + 10 + 10 + 5 = 33, 33 – (3 + 3 + 3) = w.) 5 3.MD.8 Answer is correct but there is no work. OR Work demonstrates an inappropriate strategy for the problem and the answer is incorrect. Work demonstrates a strategy appropriate to the problem but several calculation errors result in an incorrect answer. Answer may be incorrect due to a calculation error; however, the work demonstrates a strategy appropriate to the problem. Student correctly answers that the perimeter is 52 inches. Student work demonstrates a strategy appropriate to the problem (e.g., student may use a combination of multiplication and addition to calculate the perimeter).
6 3.MD.8 Answer is correct but there is no work. OR Work demonstrates an inappropriate strategy for the problem and the answer is incorrect. Work demonstrates a strategy appropriate to the problem but several calculation errors result in an incorrect answer. Answer may be incorrect due to a calculation error. Student work demonstrates a strategy appropriate to the problem. Student answers that Mrs. Gomez needs to build 85 feet of fence. Student work demonstrates a strategy appropriate to the problem (e.g., 10 + 15 = 25 and 25 + 32 + 15 + 10 = 85 feet, or, 25 + 50 + 10 = 85 feet).