解離定数
H 3 B ⇌ H + + H 2 B − K 1 = [ H + ] ⋅ [ H 2 B − ] [ H 3 B ] p K 1 = − log  K 1 {\displaystyle H_{3}B\rightleftharpoons \ H^{+}+H_{2}B^{-}\qquad K_{1}={[H^{+}]\cdot [H_{2}B^{-}] \over [H_{3}B]}\qquad pK_{1}=-\log K_{1}}
H 2 B − ⇌ H + + H B − 2 K 2 = [ H + ] ⋅ [ H B − 2 ] [ H 2 B − ] p K 2 = − log  K 2 {\displaystyle H_{2}B^{-}\rightleftharpoons \ H^{+}+HB^{-2}\qquad K_{2}={[H^{+}]\cdot [HB^{-2}] \over [H_{2}B^{-}]}\qquad pK_{2}=-\log K_{2}}
H B − 2 ⇌ H + + B − 3 K 3 = [ H + ] ⋅ [ B − 3 ] [ H B − 2 ] p K 3 = − log  K 3 {\displaystyle HB^{-2}\rightleftharpoons \ H^{+}+B^{-3}\qquad K_{3}={[H^{+}]\cdot [B^{-3}] \over [HB^{-2}]}\qquad pK_{3}=-\log K_{3}}