四十一角形
x 1 = − 1 + λ 1 + λ 2 + λ 3 + λ 4 5 x 2 = − 1 + λ 1 σ 4 + λ 2 σ 3 + λ 3 σ 2 + λ 4 σ 5 x 3 = − 1 + λ 1 σ 3 + λ 2 σ + λ 3 σ 4 + λ 4 σ 2 5 x 4 = − 1 + λ 1 σ 2 + λ 2 σ 4 + λ 3 σ + λ 4 σ 3 5 x 5 = − 1 + λ 1 σ + λ 2 σ 2 + λ 3 σ 3 + λ 4 σ 4 5 {\displaystyle {\begin{aligned}&x_{1}={\frac {-1+\lambda _{1}+\lambda _{2}+\lambda _{3}+\lambda _{4}}{5}}\,\\&x_{2}={\frac {-1+\lambda _{1}\sigma ^{4}+\lambda _{2}\sigma ^{3}+\lambda _{3}\sigma ^{2}+\lambda _{4}\sigma }{5}}\,\\&x_{3}={\frac {-1+\lambda _{1}\sigma ^{3}+\lambda _{2}\sigma +\lambda _{3}\sigma ^{4}+\lambda _{4}\sigma ^{2}}{5}}\,\\&x_{4}={\frac {-1+\lambda _{1}\sigma ^{2}+\lambda _{2}\sigma ^{4}+\lambda _{3}\sigma +\lambda _{4}\sigma ^{3}}{5}}\,\\&x_{5}={\frac {-1+\lambda _{1}\sigma +\lambda _{2}\sigma ^{2}+\lambda _{3}\sigma ^{3}+\lambda _{4}\sigma ^{4}}{5}}\,\\\end{aligned}}}