積分回路
{ V i = ( R + 1 S C ) i + V o − ( V i − R ⋅ i ) μ = V o ( 1 ) ( 2 ) より μ V i = μ R ⋅ i − V o ( 2 ) ∴ Δ = | R + 1 S C , 1 μ R , − 1 | = − { ( μ + 1 ) R + 1 S C } ( 3 ) Δ V o = | R + 1 S C , 1 μ R , μ | V i = μ ( 1 S C ) ⋅ V i ( 4 ) V o V i = ( 4 ) / ( 3 ) / V i = − 1 / { ( μ + 1 ) / μ ⋅ S C R + 1 / μ } ≒ − ( 1 C R ) ⋅ ( 1 S ) ( 5 ) 積分 {\displaystyle {\begin{aligned}&\left\{{\begin{aligned}&Vi=\left({\frac {R+1}{SC}}\right)i+Vo\\&-(Vi-R\cdot i)\mu =Vo\\\end{aligned}}\right.&&{\begin{aligned}&(1)\\\\&(2)\ {\text{より}}\end{aligned}}\\&\quad \ \mu Vi=\mu R\cdot i-Vo&&{\begin{aligned}(2)\end{aligned}}\\&{\begin{aligned}{\begin{aligned}\quad \ \therefore \Delta =\\\\\ \end{aligned}}&{\begin{aligned}\left\vert {\begin{aligned}&{\frac {R+1}{SC}},&1\\&\mu R,&-1\end{aligned}}\right\vert \\\end{aligned}}\\=&-\left\{\left(\mu +1\right)R+{\frac {1}{SC}}\right\}\end{aligned}}&&{\begin{aligned}\\\\\\(3)\end{aligned}}\\&{\begin{aligned}{\begin{aligned}\quad \ \Delta Vo=\\\\\ \end{aligned}}&{\begin{aligned}\left\vert {\begin{aligned}&{\frac {R+1}{SC}},&1\\&\mu R,&\mu \end{aligned}}\right\vert {\begin{aligned}Vi\\\\\ \end{aligned}}\\\end{aligned}}\\=&\mu \left({\frac {1}{SC}}\right)\cdot Vi\end{aligned}}&&{\begin{aligned}\\\\\\(4)\end{aligned}}\\&{\begin{aligned}{\frac {Vo}{Vi}}&=(4)/(3)/Vi\\&=-1/\left\{\left(\mu +1\right)/\mu \cdot SCR+1/\mu \right\}\\&\fallingdotseq -\left({\frac {1}{CR}}\right)\cdot \left({\frac {1}{S}}\right)\end{aligned}}&&{\begin{aligned}\\\\\\(5)\ {\text{積分}}\end{aligned}}\\\end{aligned}}}