3つの立方数の和
nが0
a 3 + ( − a ) 3 + 0 3 = 0 {\displaystyle a^{3}+(-a)^{3}+0^{3}=0}
nが1
( 9 b 4 ) 3 + ( 3 b − 9 b 4 ) 3 + ( 1 − 9 b 3 ) 3 = 1 {\displaystyle (9b^{4})^{3}+(3b-9b^{4})^{3}+(1-9b^{3})^{3}=1}
nが2
( 1 + 6 c 3 ) 3 + ( 1 − 6 c 3 ) 3 + ( − 6 c 2 ) 3 = 2 {\displaystyle (1+6c^{3})^{3}+(1-6c^{3})^{3}+(-6c^{2})^{3}=2}