大統一理論
( 4 , 2 , 1 ) → ( 3 , 2 ) + 1 / 6 , 1 / 3 ⊕ ( 1 , 2 ) − 1 / 2 , − 1 {\displaystyle (\mathbf {4} ,\mathbf {2} ,\mathbf {1} )\to (\mathbf {3} ,\mathbf {2} )_{+1/6,1/3}\oplus (\mathbf {1} ,\mathbf {2} )_{-1/2,-1}}
( 4 ̄ , 1 , 2 ) → ( 3 ̄ , 1 ) − 2 / 3 , − 1 / 3 ⊕ ( 3 ̄ , 1 ) 1 / 3 , − 1 / 3 ⊕ ( 1 , 1 ) + 1 , 1 ⊕ ( 1 , 1 ) 0 , 1 {\displaystyle ({\overline {\mathbf {4} }},\mathbf {1} ,\mathbf {2} )\to ({\overline {\mathbf {3} }},\mathbf {1} )_{-2/3,-1/3}\oplus ({\overline {\mathbf {3} }},\mathbf {1} )_{1/3,-1/3}\oplus (\mathbf {1} ,\mathbf {1} )_{+1,1}\oplus (\mathbf {1} ,\mathbf {1} )_{0,1}}
10 → ( 3 , 2 ) + 1 / 6 ⊕ ( 3 ̄ , 1 ) − 2 / 3 ⊕ ( 1 , 1 ) + 1 {\displaystyle \mathbf {10} \to (\mathbf {3} ,\mathbf {2} )_{+1/6}\oplus ({\overline {\mathbf {3} }},\mathbf {1} )_{-2/3}\oplus (\mathbf {1} ,\mathbf {1} )_{+1}}
5 ̄ → ( 3 ̄ , 1 ) + 1 / 3 ⊕ ( 1 , 2 ) − 1 / 2 {\displaystyle {\overline {\mathbf {5} }}\to ({\overline {\mathbf {3} }},\mathbf {1} )_{+1/3}\oplus (\mathbf {1} ,\mathbf {2} )_{-1/2}}
1 → ( 1 , 1 ) 0 {\displaystyle \mathbf {1} \to (\mathbf {1} ,\mathbf {1} )_{0}}