[LG Optimus G (International)] cickvoa:
First of all, why are you mentioning intensity?

Second, “direct current with 5 V specs“. Man, you got totally wrong there.

„provide enough direct CURRENT … to set to 5 V“. you are doing it again sir, VOLTAGE is measured in VOLTS, CURRENT is measured in AMPERS !!!!!

Second, you must have larger potential form charger to battery, because current wouldn’t flow. Since max battery has 4,2V, it is set to 5V (don’t know why 5, but it is bigger than 4,2)

third, 3,7V is not standard, it is potential difference on Lithiom batteries, as it is 1,5V on CoZn batteries (usual called "Alkaline" or 1,2V on Ni-Mh or Ni-Cd batteries

Standard with mAh is wrong, Wh (watthour) is more correct, but OK, lets go with mAh.

Second, since we are talking about mAh's, mAh is measuring unit for capacity. If you find me charger that can store 1200mAh of capacity good for you (it is called battery, to be precise)

Again, Li-ion cell at full charge is around 4,2 V and „empty“ is around 3,4 V.

Again, totally noob. Sir, V O L T S are for V O L T A G E, A M P E R S are for C U R R E N T, M I L I A M P E R H O U R S are for C A P A C I T Y !!!!!!! If you tell sentence like that to some specialist, he/she would start to LOL to you. If you tell that on some exam, believe me, you wouldn’t pass this year.

Bad sentence… only thing you can measure from battery is voltage and currently current. Other, such as mAh, you can calculate. For ex. If you say that during 1 h of measuring average current was 800mA, than you can say, OK my battery gave me 800mAh. Period. If you want to be more precise, or say it in correct measuring units, that you go like this: “my battery gave me 800mA in 1 h. OK, I have 800mAh. BUT, my battery is rated to 3,7 V (average voltage), than you say OK, capacity of this battery is 800mAh*3,7V=2,96mAhV. Since electric power in DC systems is calculated as P=U*I (in watts), so W=V*A, you say that battery has 2,96Wh of capacity.”

Then you look at battery (my O4X) and look, it is written “2150 mAh/8,2Wh”. LG made this good :P

Again, volts and stuff, you do not have idea what are you talking about

Yes, I could tell that by reading first few words of your post mister :)

Correct Liions are charged in impulses. BUT adapter does not provide impulses on its output, it provides 5V (as it is voltage source) and current [0, RATED] A. (those [] means that 0 and rated are included, in case you do not know math too, and that is called interval)

For impules, there is charging unit inside phone.

Wiki...well, you could read it a little, on en.wiki infos are correct, ive checked.

you have some bad attitude. but i understand, attack is the best defence. Enjoy your studying a little and do not embarrass yourself anymore. It is not problem if you do not know, okay, but if you are forcing me, and have no idea abaut basics (such as measuring units), cmon mister. do your homework.

Okay, this is review of your post. I am little hangovered, so if I sound a little uninterested or rough, forgive me :)

now, lets talk little about basics. Im not in the mood to write equasions and upload some schemes, so ill just put it on paper by hand and upload.

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