yashsingh1/xdaforums huggingface dataset:
[Off-topic] Captainkrtek:
Following order of operations it is 2

Let's break it down

PEMDAS Time

First Parentheses, (9+3) = 12

Skip Exponents...

Multiplication, 12 * 2 = 24

Division, 48/24

Skip the rest, you get 2

Some calculators do not follow order of operations, I win
[Off-topic] potentdro:
Funny, I was actually thinking of making this thread when this question first popped up a week ago. This question really did blew up all over the internet.

Most forums that I've seen, the thread was at least 25+ pages. Anything less was locked. A forum I frequent is at 140+ pages and still going (though much slower now).

Personally, my first answer was 288, but I can see why others would say 2.

Sent From My G6
[Off-topic] Nefariouss:
Unfortunately you don't really win. Multiplication and division have the same priority, therefor you work them left to right in the order they appear.	You were close though.

I mean you wouldn't say 10%5*2=1 Cause order of operations puts the answer at 4.
[Off-topic] Cover1987:
288 is right ;)

priority of multiplication and division is same -> order from left to right.
[Off-topic] elixir911911:
So I win! Ha!
[Off-topic] mrfarnhigh:
so you think:

48:2(9+3)=288 ?

well so X:2(9+3)=288 X=48 ? LOL

make it right

48 : (18+6)=?
[Off-topic] elixir911911:
Yes....in that case x does equal 48......make sure you do your math right before you challenge! Keep track of the parentheses and write the problem out....you'll see it.
[Off-topic] kareemsamman:
Here's the proof dude :D Don't challange if you're 99% sure

X = 48
[Off-topic] gaarapt:
google says: (48 ÷ 2) * (9 + 3) = 288

:D
[Off-topic] DanWilson:
You forgot to end that with

/thread
[Off-topic] Carcass.br:
OMG, let the topic die...

The answer is pi
[Off-topic] elixir911911:
Thank you! I win! And Damn dude.....you're probably like the only person that actually wrote this down but way to kill any room for argument.....I would totally hit the thanks button for you if I knew how! Lol
[Off-topic] kareemsamman:
Simply, just simplify the equation and solve for the variable X for any number, both ways(equation=2,equation=288) clearly, the values of X are wrong if the answer is 2. :)
[Off-topic] jaszek:
You can't just substitute 2(9+3) with an X. That is a whole different problem and we aren't doing integrals here to change something into a letter for easier integration. This is a standard problem which needs to follow the standard order of operations which has been stated many times nut it seems none of you want to listen. PEMDAS!!!!!!!! Multiplication and division on the same level. 6 / 2 * 3 =/= 1. It does equal 9.

Sent from this thing I call a phone.
[Off-topic] iynfynity:
if you do the (9+3), should the parenthesis be gone?
[Off-topic] :
People just don't get math haha :D Which is sad because I'm the laziest soul in my Math class. Throughout this entire school year I have only done a total of 1 homework assignments.....we get one every day :o
[Off-topic] jaszek:
That's more than me ;)
[Off-topic] monkeychef:
Always parenthesis first. Simple math my friends.
[Off-topic] jaszek:
The problem they are having is not what's in the parentheses, but the 2. They don't realize there is a multiplier between the 2 and the ( and imply that it is an x function and multiply the 2 out.
[Off-topic] elixir911911:
@ jaszek where the hell do you figure integral even play into this?
[Off-topic] Delta_1103:
I'm going with 288..

48/2(9+3)

48/2(12)

24(12)

288
[Off-topic] boborone:
Alright, after internal struggle, you win. It's 288. And I've had two years of calculus. It sucks to be wrong in math.
[Off-topic] banjongchutinantakul:
The answer seems to be 288.
[Off-topic] :
That's right! But it feels oh so amazing when you're right ;)

-I wrangled together some consonants and vowels and created this post-
[Off-topic] jaszek:
I saw people changing the whole "(9+3)" into X...which is similar when you do integral substitution, or whatever that's called. The stuff with u and du.
[Off-topic] elixir911911:
Dude that is nothing like u and du. That is for an integral.....that is learned toward the end of Calc 1 beginning of Calc 2. This is basic pre algebra hocus pocus. Nothing at all like u substitution. Integral have nothing to do with this equation. Entirely different topic. And the plugging in a random variable for random numbers and solving is a great way to prove it.....ouch.
[Off-topic] kareemsamman:
Yaaay!
[Off-topic] cashyftw:
The answer is 288!
[Off-topic] jaszek:
Maybe if you weren't raging and read my posts, you would realize I said that this is nothing like this, but people are making it out to be like that.
[Off-topic] Carcass.br:
I think that he said that you can replace the "parentheses expression" for a variable, as you do in an integral.(chain rule)
[Off-topic] Ayrlupine:
If I read this from someone I would tell them to GTFO for terrible notation.
[Off-topic] SciFiSurfer:
The way I would read 48÷2(9+3) is as follows:

Forty-eight divided by two multiplied by the result of nine plus three.

In other words:

= 48 ÷ 2 (9 + 3)

= 48 ÷ 2 * 12

= 24 * 12

= 288

I mean, I may not be able to do logarithms and higher forms of math, but c'mon, if I can get order-of-operations correct, there's no excuse for anyone else.

In order to get 2, you would have to write this as 48 ÷ (2(9+3)).
[Off-topic] irockstar661:
My wife says its 288 cause she goes to college like its 1986
[Off-topic] winxx:
2 because I take pre calculus and my calculator is never wrong
[Off-topic] melvinchng:
A really good question... but what is the answer???
[Off-topic] orkfia:
2

that notation implies the 2 is multiplied first.
[Off-topic] melvinchng:
conclusion 1: the answer is 288.

Conclusion 2: the answer is 2.

Just see what condition are you in. Normally it is 2, but 288 is the correct answer.

Scientific calculator will give you 2. But if you type 48÷2(9+3)= in

Www.Google.com you will get 288

Android calculator will get 288 too.
[Off-topic] MacaronyMax:
2 is winning!!! :D
[Off-topic] jaszek:
So I can say it's 288 because I take Calculus II and I don't need a calculator.
[Off-topic] SciFiSurfer:
Good God almighty, this thread, the poll, and some of the people posting in it are retarded.

Imagine going to a football game, and the winning team was picked based on polls or audience opinion.
[Off-topic] MacaronyMax:
48/2(9+3)=

And the equation in the second half equals this,

2(9+3)=24

Soo the sum is 48/24, which is 2 :D
[Off-topic] kdj67f:
You mean product?
[Off-topic] stubborn_d0nkey:
Badly written question.

2 and 288 aren't the only answers, 3/256 can also be the answer (hint, how would you read x2? x being a variable)

I'd bet on the home team
[Off-topic] DanWilson:
That .gif made me so happy. I owe you a cookie.

Or a ho.

I'm an avid pimp.

Make this a ****ing Live Wallpaper for Android NAO!
[Off-topic] boborone:
Haha ha haha hash aha haha ha ha
[Off-topic] dbilliter:
I have a degree in mathematics and statistics and I say 288. Because it is 48/2(9+3)= 48/2*12=24*12=288. However, 48/[2(9+3)] = 2.
[Off-topic] kdj67f:
Good idea...
[Off-topic] dawncobra:
the result is : 288
[Off-topic] MacaronyMax:
:mad::mad::mad::mad::mad::mad::mad::mad::mad:

DIE TROLL DIE XD hehe ;)
[Off-topic] SciFiSurfer:
Product? You mean like:
[Off-topic] madnish30:
288! What's the debate about !? BODMAS !?
[Off-topic] melvinchng:
Anyone can think some good enough reasons so I can explain it to my friend why it is not 2...
[Off-topic] MarkokaZjEE:
288 for sure :)
[Off-topic] GazaIan:
It's 288.

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction.

Multiplication and Division (pair 1) are evil twins, you do them from left to right, no matter which comes first.

Addition and Substraction (pair 2) are evil twins, you do them from left to right, no matter which comes first.

Pair 1 ALWAYS happens before Pair 2.

Now, lets begin, shall we?

There are Parenthesis. (9+3) becomes (12).

Our new problem is now 48÷2(12).

There are no exponents.

Multiplication and Division are in this problem. As stated, the evil twins are always done from left to right.

48÷2= 24. Our new problem is 24(12).

24 x 12 = 288.

There is no addition or subtraction. You are done.

:D
[Off-topic] MacaronyMax:
BEDMAS

Brackets, Exponents, Division, Multiplication, Addition, Subtraction

Brackets first then :D
[Off-topic] :
It's 288, people stop being so stubborn and really think about the answer...Maxey :p
[Off-topic] MacaronyMax:
It's 2!!!!!!! :D
[Off-topic] GazaIan:
Sarcasm, right?
[Off-topic] MacaronyMax:
No! It's 2 :D Even look at the pooll :p
[Off-topic] zwade01:
Damn you for breaking it down into a child-like form and changing my mind from 2 to 288 :mad:
[Off-topic] MacaronyMax:
Stay strong! Its 2 :p
[Off-topic] melvinchng:
I asked my math teaches, he say it is 288 too...
[Off-topic] MacaronyMax:
Yeah well.... He's wrong! :p

Banana Mafia - Desire Z
[Off-topic] SciFiSurfer:
Well, what do you expect from a community of kids who have problems spelling and using proper grammar?
[Off-topic] GazaIan:
Nope, it's 288.

The problem is you're doing it the wrong way, you're multiplying the 12 and 2 first. While it is PEMDAS, Division and Multiplication are always done from left to right, regardless of what comes first.

Out of curiosity, and not trying to be rude or anything, but what grade are you in? Or have you already graduated?
[Off-topic] MacaronyMax:
:( No you are! :p You even posted in your quote :D
[Off-topic] melvinchng:
I'm very confirm. Answer is 288
[Off-topic] loxias:
"pemdas" is just for children to memorize, logic is what provides the answer in the system

how about: 48/2(9+3) = 48/2 * 48/(9+3) = 96 = 48/18 + 48/6 = 32/3 ???
[Off-topic] GazaIan:
What. The. F*ck. Is. That.
[XPERIA X10 Q&A, Help & Troubleshooting] alex4659:
Hi,

While charging my X10, the red light is flashing every second or so, then eventually stops blinking.

The led that is blinking red is directly under the USB / charging port.

Also, when i try to power it on it give a little vibration and nothing happens?

Sometimes i get the triple flashing red light?

What does this all mean????

thanks,

Alex
[XPERIA X10 Q&A, Help & Troubleshooting] bcsiy:
I'm having the same problem, can someone please help...thanks!
[XPERIA X10 Q&A, Help & Troubleshooting] kaisan1:
it means that your battery is totally/completely empty.. plug in your charger and leave your phone for about 2 hours, it will be back to normal.. DO NOT TURN IT ON..DO NOT TOUCH IT... be patient and leave it as it is( charger plugged in) for 2 hrs..

HIT THANKS BUTTON IF HELPED..!!
[XPERIA X10 Q&A, Help & Troubleshooting] Prodigy:
Or to simplify, if thqt dpesnt work, u'll have to buy a new battery on ebay or something.
[XPERIA X10 Q&A, Help & Troubleshooting] alex4659:
problem solved

Long story short, it was both the phone and the battery. So I got a replacment of both.

Thank you everybody for all the support.

Alex
[XPERIA X10 Q&A, Help & Troubleshooting] 0505killee:
Do you mind going in to detail as to what exactly was wrong with your phone? I'm having the same problem, and I want to know what to get fixed.

Thanks
[XPERIA X10 Q&A, Help & Troubleshooting] CescVicious:
OMG my phone did this five minutes ago!! O_O i was so scared xDD

now it is charging the battery, i will never let the battery drain like that again :eek:
[XPERIA X10 Q&A, Help & Troubleshooting] auninda:
same thnig happened to my arc a few mins ago and now its charging ok :D
[XPERIA X10 Q&A, Help & Troubleshooting] SysGhost:
Old thread, I know. But I'd like to shed some more light on this particular problem.

No need to panic just yet. The battery might be just fine.

I had this problem myself recently, and on top of that that with brand new batteries.

After some investigation and troubleshooting, I figured out that many batteries does drain to a level very close to what is the lowest "safe" voltage for a lithium-polymer battery. Batteries are fine and within tolerances.

However, the X10i in my case, and other Xperia devices in other cases, are extremely fastidious about what is considered a safe "drained" level.

Just as mentioned earlier, one just need to leave it charging for an hour or two. It'll kick back into normal charging cycle.

But if one can't wait for this slow process, one can use an external battery charger for lithium-polymer batteries.

There are several universal lithium-polymer-chargers designed for cell/camera/pad/mp3 -batteries out there.

Even a good quality lithium-ion charger works fine with lithium-polymer batteries, as they're using the same charging voltages and timings.

The practical "difference" with polymer batteries is that they're slightly more sensitive to voltages and , thus I want to emphasise "Good quality lithium ion charger".

There is another, slightly more dangerous, trick:

...slightly more dangerous... dangerous... yes... that's right... dangerous.

Are you sure? Did you read the "dangerous" part above?

(I will not take any whatsoever responsibility if anyone choose to follow through with this trick)

Okay then... It's your pants...

Find a stable 5 volt DC supply, and make sure you know the + and - terminals on both the battery and the power supply. Any 5 volt USB power will do just fine.

First:

Very well then, onwards:

Remove back cover on the phone and remove the battery.

Connect the ( + ) wire from the power supply to the ( + ) terminal on the battery. Hold it there.

Now, for about 10 seconds, connect the ( - )wire to the ( - ) terminal.

Once you counted 10 seconds, disconnect all wires from the battery and disconnect the power supply.

If the battery has become warm by this procedure, place it somewhere away from any flammable materials and let it cool down. The warmer the battery is, the greater is the risk for the battery to catch fire and/or explode.

Bath tube or the kitchen sink is a good place to let it cool down. No water thou.

Reinsert the cooled down battery into the device and connect the charger. Device should enter a normal charging cycle.

If the 5 steps above didn't kick it into life, repeat the steps in order. But do not try this for more than 2 -3 times. If it doesn't work after the third time, the battery is very likely dead and should be replaced. (...or you did something very wrong ;) )
[XPERIA X10 Q&A, Help & Troubleshooting] nargany:
I have problem with charging Sony Ericsson xperia x10

Today I bought Sony Ericsson xperia x10 (white). I began to charge battery. After it is started charging, the lamp has begun lighting without blinking. On the screen the indicator [in black] goes to grow up (from left to right) but it is not still finishing during 8 hours. What does it mean? is it normal?
[XPERIA X10 Q&A, Help & Troubleshooting] aatifaneeq:
aww,.. same thing happened with me, right now.even i have plugged in charger too... do not know what to do :/

edited:

Its because battery drained completely . Thanks to Allah, now its up and start charging..
[XPERIA X10 Q&A, Help & Troubleshooting] shafali1:
hope this helps

Having the same problem.

let your phone charge for a couple of hours as the slow flashing red light while charging means that your battery is completly dead.

then take off charge.

to reboot, first hold down the power button and whille holding it, press and hold down the volume up button until you feel 1 short sharp vibration. release both buttons and as soon as you do, it should reboot.

reboot wont work if you get to 3 vibrationsits which comes after the one short sharp vibation.

the reboot should turn your phone on using safe mode..... im still working on how to get it out of safe mode....

very important to remember to hold the power button first, and while holding it, press and hold down the volume up button.

dont press and hold down the power button and the volume up button simultaneously, the reboot wont work.
[Flipout and Charm General] kain_org:
I have successfully used reverse USB tethering on a flipout. This method should be portable to other devices running the motorola android multi-device driver with usb0.

If you are comparing to any windows drivers, say that installed from the driver installer MSI when connecting a flipout and maybe other devices in 'portal' mode, the (windows) driver will be motousbnet. On linux, the driver is cdc_subset. However, this driver does not know how to bind to the motorola

1. Figure out the usb vendor id, product id, and interface class, interface subclass, and interface protocol of the networking interface. On the flipout, this is named the 'motorola networking interface'. On my device, it has these ids: 0x22b8, 0x41da, 0x02, 0x0a, 0x01. You can find these ids via exploring /sys/bus/usb on a linux system, or with the lsusb utility.

2. patch your cdc_subset driver to support the USB id and interface of the above device. You will need to inspect via lsusb or sysfs to setup a 'product' and 'driver info' structure in cdc_subset.c to select the correct interface and endpoints. The pertinent parts of my cdc_subset.c are as follows:

add to products
{
// Moto flipout usb
USB_DEVICE_AND_INTERFACE_INFO (0x22b8, 0x41da, 0x02, 0x0a, 0x01),
.driver_info = (unsigned long) &motousb_info,
},

add near other driver_infos:
static const struct driver_info	motousb_info = {
.description =	"Motorola USB endpoint",
.check_connect = always_connected,
.in=0x84, .out=0x03,
};

3. Doing such a mod and compiling yourself a new cdc_subset.ko, and installing that, will yield a usb driver that can talk to usb0 on your flipout. At this point, you just have to configure networking. I setup proxyarp on my LAN and usb0 interfaces, and set up some manual addresses and routes. Other options could be to add usb0 to a bridge, or do routing and DHCP, or routing + nat + DHCP. You'll probably need to netcfg rmnet0 down and setprop net.dns1 and net.rmnet0.dns1 your ips manually. Make sure you save your old dns. I'm not sure if that gets restored from carrier when you turn rmnet back on.

4. after all that, you should be online.

5. EDIT: all compiling and module installation steps noted above happen on the host PC, if that wasn't clear.
[Flipout and Charm General] kain_org:
Work to follow:

use SL4A to automate usb0 bringup

interface with APNDroid to soft-down the 3g instead of nuking it the hard way. killing the radio process will get you back online, but thats effectively the same as resetting the baseband, so you'll need to re-unlock your SIM etc.
[Flipout and Charm General] pmarcelll:
Thanks man! This is awesome. It worked on my Motorola Defy (same parameters) under Ubunutu.
[Flipout and Charm General] balek:
Hi,

I thing this is what i am looking for, enable a motorola device (defy) to be a usb0 device with ubuntu so you can have an IP, and ssh easly with your droid (using vlc remote with usb cable). I realy appreciate this native feature with my old htc.

where is the cdc_subset.c ?

tkx
[Flipout and Charm General] kain_org:
It's in the kernel source. -- You'll have to download the linux or kernel source package that matches the kernel you run on your ubuntu machine, modify your cdc_subset driver, rebuild it, and install it.

Learning things like the kernel build system and how to install a kernel module are exercises for the reader.
[Flipout and Charm General] breakingspell:
Good job! I'll try it once i get my Ubuntu installation up and running again ^_^
[Flipout and Charm General] sdxmob:
Defy and Debian USB network works partially...

Hello. The idea was good...

My config is:

- on one side: a Defy (CM7 1.0-RC1 Nightly build 2037, Gingerbread 2.3.4)

- on the other side: a Linux Debian (Squeeze , kernel 3.0.0-1-686-pae)

I patched the cdc_subset driver as proposed. I saw a little difference on the endpoints: lsusb -v reports 0x83 for 'in' endpoint and 0x2 (bulk) or 0x3 (interrupt) for 'out' endpoint. I tried all combinations and only 0x83/0x2 give a working ping between hosts. => Are the initial endpoints working (0x84/0x3) ?

See attached file for the complete listing, search 'SDX' to see where I patched.

When I plug the USB cable, the usb0 interface is brought up on linux automatically and that's perfect.

With a simple network configuration, ping works on both hosts.

.

So everything seems right. :)

I then tried to transfer a huge 100MB file to see the performance:

- scp from linux to defy => OK, ~5MB/s

- scp from defy to linux => FAILURE after a few MB transfered

In the second test, the connection is completely frozen and I see errors on both interfaces (ifconfig usb0, error packets). I repeated the test multiple times with alternate network configs, without wifi etc., and I could never transfer the file completely.

Can someone confirm me:

- that the transfer is working for him in both ways with huge files

- what is reported by "lsusb -v -d 22b8:41da" to see if my endpoints for a Defy are correct

I'm not sure, but maybe cdc_subset is not the right driver to patch ?

Or simply it's a bug in scp or sshd on Defy ! I should try with something else like ftp or http...

I keep working on this topic...Thx for any clue !
[Flipout and Charm General] balek:
Any news with defy ?
[Galaxy S I9000 Q&A, Help & Troubleshooting] treleung:
Hey Guys,

Just flashed a new Gingerbread ROM, and it came with the all blacked out Market. It's hard to read and in my opinion not very good looking.

Does anyone have the stock market to flash from CWM? Or is there an installable apk for this?

Thanks!:o
[Xoom Themes and Apps] phouse1025:
Not too long ago there was an article posted on XDA talkin about a new app for honeycomb. It was suposed to pick up the radio signals from near by phones and decrypt them and allow you to listen in on the calls made from it and also look through the contents of the phone. Now I can't find it anywhere? Can anyone help me with a link to the article or a link to DL the app?
[Xoom Themes and Apps] SirLegolas:
Probably the dev got sent to Guantanamo...
[Xoom Themes and Apps] bskim23:
Lol!
[Xoom Themes and Apps] jondwillis:
sssssssssssssssssssssssssssnap
[Xoom Themes and Apps] phouse1025:
lol yea, i wish i could find it though, seems like it would be fun to play around with, i knew i shoulda downloaded it when i first saw it. well if anyone else happened to see it then let me know
[Xoom Themes and Apps] JanetPanic:
If it was not an April Fools prank then it was almost definitely very illegal.

Listening into other cell phones would fall under wiretap ordinance. It might be a bluetooth hack, which would still be illegal but not as bad, since you are talking about looking through the contents of a phone. Bluetooth (short of a exploit) would not let you look through the phone arbitrarily either though.
[Xoom Themes and Apps] erzhik:
Even if this kind of an app was real, why in the world would you install it? Seems like just asking for serious trouble, serious as in jail time serious.
[Xoom Themes and Apps] twinkyz1979:
http://getandroidstuff.com/download-ispy-android-app-access-devices-storage-listen-phone-call/
[Xoom Themes and Apps] lokko21:
Good stuff, why would somebody want to install something like this, probably unsecured cheated ppl.

Evo Better Than The Best...
[Xoom Themes and Apps] burden010:
This.... cannot be a real app.
[Xoom Themes and Apps] drziddo:
It was an aprill fools day prank.

And I downloaded it and inside the apk there were a sorry guys, this is a...

Lol
[Vibrant Q&A, Help & Troubleshooting] AuroEdge:
Will all of the ROMs posted on the forums work with the Cincinnati Bell Vibrant or are they meant for other carriers?
[Vibrant Q&A, Help & Troubleshooting] geoffcorey:
The bell vibrant is an i9k phone actually (technically I9000m, one of the many "smart" moves by Samsung was to make 8-10 different flavors of the same phone, and label them with the same name, e.g. tmo-us vibrant and the bell vibrant)

So pretty much all the roms in the tmo-us dev section won't work on your phone, and even if they do, your battery will be nothing and your keys won't work.
[Vibrant Q&A, Help & Troubleshooting] stavros05:
I also have cinci bell. Been running trigger 2.9.2 for a few days, the only issue so far has been no voicemail icon? Battery life has been about 48 hours from charge to dead with moderate use. is there a bell specific rom even available? please advise.