#define NULL ((void *)0)
typedef unsigned long size_t; // Customize by platform.
typedef long intptr_t;
typedef unsigned long uintptr_t;
typedef long scalar_t__; // Either arithmetic or pointer type.
/* By default, we understand bool (as a convenience). */
typedef int bool;
#define false 0
#define true 1

/* Forward declarations */

/* Type definitions */

/* Variables and functions */
int gcd(unsigned int, unsigned int);
int /*<<< orphan*/ printf(char *, ...);
int /*<<< orphan*/ scanf(char *, unsigned int *, unsigned int *);
int main(void) {
  unsigned int primoNumero;
  unsigned int secondoNumero;
  printf("Inserisci i due numeri per calcolare il Massimo comun divisore: ");
  scanf("%u %u", &primoNumero, &secondoNumero);
  printf("Il massimo comun divisore tra %u e %u e' pari a: %u", primoNumero,
         secondoNumero, gcd(primoNumero, secondoNumero));
  return 0;
}


x86 assembly (clang, -O0):
<main>:
push   %rbp
mov    %rsp,%rbp
sub    $0x20,%rsp
movl   $0x0,-0x4(%rbp)
lea    0xeba(%rip),%rdi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xeed(%rip),%rdi
lea    -0x8(%rbp),%rsi
lea    -0xc(%rbp),%rdx
call   1040 <scanf@plt>
mov    -0x8(%rbp),%eax
mov    %eax,-0x14(%rbp)
mov    -0xc(%rbp),%eax
mov    %eax,-0x10(%rbp)
mov    -0x8(%rbp),%edi
mov    -0xc(%rbp),%esi
call   1050 <gcd@plt>
mov    -0x14(%rbp),%esi
mov    -0x10(%rbp),%edx
mov    %eax,%ecx
lea    0xec0(%rip),%rdi
mov    $0x0,%al
call   1030 <printf@plt>
xor    %eax,%eax
add    $0x20,%rsp
pop    %rbp
ret

x86 assembly (clang, -O2):
<main>:
push   %rbp
push   %rbx
push   %rax
lea    0xec6(%rip),%rdi
xor    %eax,%eax
call   1030 <printf@plt>
lea    0xef9(%rip),%rdi
lea    0x4(%rsp),%rsi
mov    %rsp,%rdx
call   1040 <scanf@plt>
mov    0x4(%rsp),%ebx
mov    (%rsp),%ebp
mov    %ebx,%edi
mov    %ebp,%esi
call   1050 <gcd@plt>
lea    0xedb(%rip),%rdi
mov    %ebx,%esi
mov    %ebp,%edx
mov    %eax,%ecx
xor    %eax,%eax
call   1030 <printf@plt>
xor    %eax,%eax
add    $0x8,%rsp
pop    %rbx
pop    %rbp
ret

LLVM IR (-O0):
@.str = [65 x i8] c"Inserisci i due numeri per calcolare il Massimo comun divisore: \00"
@.str.1 = [6 x i8] c"%u %u\00"
@.str.2 = [52 x i8] c"Il massimo comun divisore tra %u e %u e' pari a: %u\00"
define i32 @main() {
%1 = alloca i32
%2 = alloca i32
%3 = alloca i32
store i32 0, i32* %1
%4 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([65 x i8], [65 x i8]* @.str, i64 0, i64 0))
%5 = call i32 @scanf(i8* getelementptr inbounds ([6 x i8], [6 x i8]* @.str.1, i64 0, i64 0), i32* %2, i32* %3)
%6 = load i32, i32* %2
%7 = load i32, i32* %3
%8 = load i32, i32* %2
%9 = load i32, i32* %3
%10 = call i32 @gcd(i32 %8, i32 %9)
%11 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([52 x i8], [52 x i8]* @.str.2, i64 0, i64 0), i32 %6, i32 %7, i32 %10)
ret i32 0
}

LLVM IR (-O2):
@.str = [65 x i8] c"Inserisci i due numeri per calcolare il Massimo comun divisore: \00"
@.str.1 = [6 x i8] c"%u %u\00"
@.str.2 = [52 x i8] c"Il massimo comun divisore tra %u e %u e' pari a: %u\00"
define i32 @main() {
%1 = alloca i32
%2 = alloca i32
%3 = bitcast i32* %1 to i8*
%4 = bitcast i32* %2 to i8*
%5 = tail call i32 (i8*, ...) @printf(i8* dereferenceable(1) getelementptr inbounds ([65 x i8], [65 x i8]* @.str, i64 0, i64 0))
%6 = call i32 @scanf(i8* getelementptr inbounds ([6 x i8], [6 x i8]* @.str.1, i64 0, i64 0), i32* %1, i32* %2)
%7 = load i32, i32* %1
%8 = load i32, i32* %2
%9 = call i32 @gcd(i32 %7, i32 %8)
%10 = call i32 (i8*, ...) @printf(i8* dereferenceable(1) getelementptr inbounds ([52 x i8], [52 x i8]* @.str.2, i64 0, i64 0), i32 %7, i32 %8, i32 %9)
ret i32 0
}