#define NULL ((void *)0)
typedef unsigned long size_t; // Customize by platform.
typedef long intptr_t;
typedef unsigned long uintptr_t;
typedef long scalar_t__; // Either arithmetic or pointer type.
/* By default, we understand bool (as a convenience). */
typedef int bool;
#define false 0
#define true 1

/* Forward declarations */

/* Type definitions */

/* Variables and functions */
int /*<<< orphan*/ printf(char *, ...);
int main(int argc, char **argv) {
  printf("= Aufgabe 7.1 =\n");
  if (2 + 2 * 5 == 20) {
    printf("Der + Operator bindet stärker als der * Op\n");
  } else {
    printf("Der * Operator bindet stärker als der + Op\n");
  }
  printf("= Aufgabe 7.2 =\n");
  printf("10 >> 1 = %d (entspricht dem Ausdruck: 10 / 2)\n", 10 >> 1);
  printf("10 >> 2 = %d (entspricht dem Ausdruck: 10 / 4)\n", 10 >> 2);
  printf("10 << 1 = %d (entspricht dem Ausdruck: 10 * 2)\n", 10 << 1);
  printf("10 << 2 = %d (entspricht dem Ausdruck: 10 * 4)\n", 10 << 2);
  return 0;
}


x86 assembly (clang, -O0):
<main>:
push   %rbp
mov    %rsp,%rbp
sub    $0x10,%rsp
movl   $0x0,-0x4(%rbp)
mov    %edi,-0x8(%rbp)
mov    %rsi,-0x10(%rbp)
lea    0xed3(%rip),%rdi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xed6(%rip),%rdi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xef5(%rip),%rdi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xef8(%rip),%rdi
mov    $0x5,%esi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xf15(%rip),%rdi
mov    $0x2,%esi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xf32(%rip),%rdi
mov    $0x14,%esi
mov    $0x0,%al
call   1030 <printf@plt>
lea    0xf4f(%rip),%rdi
mov    $0x28,%esi
mov    $0x0,%al
call   1030 <printf@plt>
xor    %eax,%eax
add    $0x10,%rsp
pop    %rbp
ret

x86 assembly (clang, -O2):
<main>:
push   %rax
lea    0xf98(%rip),%rdi
call   1030 <puts@plt>
lea    0xf9c(%rip),%rdi
call   1030 <puts@plt>
lea    0xfbc(%rip),%rdi
call   1030 <puts@plt>
lea    0xeb4(%rip),%rdi
mov    $0x5,%esi
xor    %eax,%eax
call   1040 <printf@plt>
lea    0xed1(%rip),%rdi
mov    $0x2,%esi
xor    %eax,%eax
call   1040 <printf@plt>
lea    0xeee(%rip),%rdi
mov    $0x14,%esi
xor    %eax,%eax
call   1040 <printf@plt>
lea    0xf0b(%rip),%rdi
mov    $0x28,%esi
xor    %eax,%eax
call   1040 <printf@plt>
xor    %eax,%eax
pop    %rcx
ret

LLVM IR (-O0):
@.str = [17 x i8] c"= Aufgabe 7.1 =\0A\00"
@.str.1 = [45 x i8] c"Der * Operator bindet st\C3\A4rker als der + Op\0A\00"
@.str.2 = [17 x i8] c"= Aufgabe 7.2 =\0A\00"
@.str.3 = [48 x i8] c"10 >> 1 = %d (entspricht dem Ausdruck: 10 / 2)\0A\00"
@.str.4 = [48 x i8] c"10 >> 2 = %d (entspricht dem Ausdruck: 10 / 4)\0A\00"
@.str.5 = [48 x i8] c"10 << 1 = %d (entspricht dem Ausdruck: 10 * 2)\0A\00"
@.str.6 = [48 x i8] c"10 << 2 = %d (entspricht dem Ausdruck: 10 * 4)\0A\00"
define i32 @main(i32 %0, i8** %1) {
%3 = alloca i32
%4 = alloca i32
%5 = alloca i8**
store i32 0, i32* %3
store i32 %0, i32* %4
store i8** %1, i8*** %5
%6 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([17 x i8], [17 x i8]* @.str, i64 0, i64 0))
%7 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([45 x i8], [45 x i8]* @.str.1, i64 0, i64 0))
%8 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([17 x i8], [17 x i8]* @.str.2, i64 0, i64 0))
%9 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([48 x i8], [48 x i8]* @.str.3, i64 0, i64 0), i32 5)
%10 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([48 x i8], [48 x i8]* @.str.4, i64 0, i64 0), i32 2)
%11 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([48 x i8], [48 x i8]* @.str.5, i64 0, i64 0), i32 20)
%12 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([48 x i8], [48 x i8]* @.str.6, i64 0, i64 0), i32 40)
ret i32 0
}

LLVM IR (-O2):
@.str.3 = [48 x i8] c"10 >> 1 = %d (entspricht dem Ausdruck: 10 / 2)\0A\00"
@.str.4 = [48 x i8] c"10 >> 2 = %d (entspricht dem Ausdruck: 10 / 4)\0A\00"
@.str.5 = [48 x i8] c"10 << 1 = %d (entspricht dem Ausdruck: 10 * 2)\0A\00"
@.str.6 = [48 x i8] c"10 << 2 = %d (entspricht dem Ausdruck: 10 * 4)\0A\00"
@str = [16 x i8] c"= Aufgabe 7.1 =\00"
@str.7 = [44 x i8] c"Der * Operator bindet st\C3\A4rker als der + Op\00"
@str.8 = [16 x i8] c"= Aufgabe 7.2 =\00"
define i32 @main(i32 %0, i8** nocapture readnone %1) {
%3 = tail call i32 @puts(i8* dereferenceable(1) getelementptr inbounds ([16 x i8], [16 x i8]* @str, i64 0, i64 0))
%4 = tail call i32 @puts(i8* dereferenceable(1) getelementptr inbounds ([44 x i8], [44 x i8]* @str.7, i64 0, i64 0))
%5 = tail call i32 @puts(i8* dereferenceable(1) getelementptr inbounds ([16 x i8], [16 x i8]* @str.8, i64 0, i64 0))
%6 = tail call i32 (i8*, ...) @printf(i8* dereferenceable(1) getelementptr inbounds ([48 x i8], [48 x i8]* @.str.3, i64 0, i64 0), i32 5)
%7 = tail call i32 (i8*, ...) @printf(i8* dereferenceable(1) getelementptr inbounds ([48 x i8], [48 x i8]* @.str.4, i64 0, i64 0), i32 2)
%8 = tail call i32 (i8*, ...) @printf(i8* dereferenceable(1) getelementptr inbounds ([48 x i8], [48 x i8]* @.str.5, i64 0, i64 0), i32 20)
%9 = tail call i32 (i8*, ...) @printf(i8* dereferenceable(1) getelementptr inbounds ([48 x i8], [48 x i8]* @.str.6, i64 0, i64 0), i32 40)
ret i32 0
}