#define NULL ((void *)0)
typedef unsigned long size_t; // Customize by platform.
typedef long intptr_t;
typedef unsigned long uintptr_t;
typedef long scalar_t__; // Either arithmetic or pointer type.
/* By default, we understand bool (as a convenience). */
typedef int bool;
#define false 0
#define true 1

/* Forward declarations */

/* Type definitions */

/* Variables and functions */
int /*<<< orphan*/ getchar();
int inmultire(int, int);
int /*<<< orphan*/ printf(char *, int);
int /*<<< orphan*/ putchar(char);
int /*<<< orphan*/ scanf(char *, int *);
int main() {
  int x, y;
  printf("Bo$$ , baga aici 2 numere ca sa le inmultesti %c\n", 31);
  putchar('\t');
  scanf("%d", &x);
  putchar('\t');
  scanf("%d", &y);
  putchar('\n');
  printf("Rezultatul inmultirii este %d\n", inmultire(x, y));
  getchar();
  return 0;
}


x86 assembly (clang, -O0):
<main>:
push   %rbp
mov    %rsp,%rbp
sub    $0x10,%rsp
movl   $0x0,-0x4(%rbp)
lea    0xe9a(%rip),%rdi
mov    $0x1f,%esi
call   1050 <printf@plt>
mov    $0x9,%edi
call   1030 <putchar@plt>
lea    0xeb1(%rip),%rdi
lea    -0x8(%rbp),%rsi
call   1070 <scanf@plt>
mov    $0x9,%edi
call   1030 <putchar@plt>
lea    0xe97(%rip),%rdi
lea    -0xc(%rbp),%rsi
call   1070 <scanf@plt>
mov    $0xa,%edi
call   1030 <putchar@plt>
mov    -0x8(%rbp),%edi
mov    -0xc(%rbp),%esi
call   1040 <inmultire@plt>
mov    %eax,%esi
lea    0xe73(%rip),%rdi
call   1050 <printf@plt>
mov    $0x0,%al
call   1060 <getchar@plt>
xor    %eax,%eax
add    $0x10,%rsp
pop    %rbp
ret

x86 assembly (clang, -O2):
<main>:
push   %rbx
sub    $0x10,%rsp
lea    0xea4(%rip),%rdi
mov    $0x1f,%esi
call   1050 <printf@plt>
mov    $0x9,%edi
call   1030 <putchar@plt>
lea    0xebb(%rip),%rbx
lea    0xc(%rsp),%rsi
mov    %rbx,%rdi
call   1070 <scanf@plt>
mov    $0x9,%edi
call   1030 <putchar@plt>
lea    0x8(%rsp),%rsi
mov    %rbx,%rdi
call   1070 <scanf@plt>
mov    $0xa,%edi
call   1030 <putchar@plt>
mov    0xc(%rsp),%edi
mov    0x8(%rsp),%esi
call   1040 <inmultire@plt>
lea    0xe7c(%rip),%rdi
mov    %eax,%esi
call   1050 <printf@plt>
xor    %eax,%eax
call   1060 <getchar@plt>
xor    %eax,%eax
add    $0x10,%rsp
pop    %rbx
ret

LLVM IR (-O0):
@.str = [50 x i8] c"Bo$$ , baga aici 2 numere ca sa le inmultesti %c\0A\00"
@.str.1 = [3 x i8] c"%d\00"
@.str.2 = [31 x i8] c"Rezultatul inmultirii este %d\0A\00"
define i32 @main() {
%1 = alloca i32
%2 = alloca i32
%3 = alloca i32
store i32 0, i32* %1
%4 = call i32 @printf(i8* getelementptr inbounds ([50 x i8], [50 x i8]* @.str, i64 0, i64 0), i32 31)
%5 = call i32 @putchar(i8 signext 9)
%6 = call i32 @scanf(i8* getelementptr inbounds ([3 x i8], [3 x i8]* @.str.1, i64 0, i64 0), i32* %2)
%7 = call i32 @putchar(i8 signext 9)
%8 = call i32 @scanf(i8* getelementptr inbounds ([3 x i8], [3 x i8]* @.str.1, i64 0, i64 0), i32* %3)
%9 = call i32 @putchar(i8 signext 10)
%10 = load i32, i32* %2
%11 = load i32, i32* %3
%12 = call i32 @inmultire(i32 %10, i32 %11)
%13 = call i32 @printf(i8* getelementptr inbounds ([31 x i8], [31 x i8]* @.str.2, i64 0, i64 0), i32 %12)
%14 = call i32 (...) @getchar()
ret i32 0
}

LLVM IR (-O2):
@.str = [50 x i8] c"Bo$$ , baga aici 2 numere ca sa le inmultesti %c\0A\00"
@.str.1 = [3 x i8] c"%d\00"
@.str.2 = [31 x i8] c"Rezultatul inmultirii este %d\0A\00"
define i32 @main() {
%1 = alloca i32
%2 = alloca i32
%3 = bitcast i32* %1 to i8*
%4 = bitcast i32* %2 to i8*
%5 = tail call i32 @printf(i8* getelementptr inbounds ([50 x i8], [50 x i8]* @.str, i64 0, i64 0), i32 31)
%6 = tail call i32 @putchar(i8 signext 9)
%7 = call i32 @scanf(i8* getelementptr inbounds ([3 x i8], [3 x i8]* @.str.1, i64 0, i64 0), i32* %1)
%8 = call i32 @putchar(i8 signext 9)
%9 = call i32 @scanf(i8* getelementptr inbounds ([3 x i8], [3 x i8]* @.str.1, i64 0, i64 0), i32* %2)
%10 = call i32 @putchar(i8 signext 10)
%11 = load i32, i32* %1
%12 = load i32, i32* %2
%13 = call i32 @inmultire(i32 %11, i32 %12)
%14 = call i32 @printf(i8* getelementptr inbounds ([31 x i8], [31 x i8]* @.str.2, i64 0, i64 0), i32 %13)
%15 = call i32 (...) @getchar()
ret i32 0
}