Table:
0
A
B
C
D
E
F
1
Gauge
Railway
Class
Works no.
Year
Builder
2
3 ft 6 in
Rhodesia Railways
15th
6936–6939
1940
Beyer, Peacock
3
3 ft 6 in
Rhodesia Railways
15th
7228–7237
1947
Beyer, Peacock
4
3 ft 6 in
Rhodesia Railways
15th
7260–7279
1948–49
Beyer, Peacock
5
3 ft 6 in
Rhodesia Railways
15A
7326–7340
1949–50
Beyer, Peacock
6
3 ft 6 in
Rhodesia Railways
15A
7351–7365
1950
Beyer, Peacock
7
3 ft 6 in
Rhodesia Railways
15A
2963–2972
1952
Franco-Belge , France
8
3 ft 6 in
Sudan Railways
250
6798–6801
1936
Beyer, Peacock
9
3 ft 6 in
Sudan Railways
250
6870–6875
1937
Beyer, Peacock

Questions and formulas:
Question: Which year has a railway class of 250?
Formula: UNIQUE(CHOOSECOLS(FILTER(A1:F1,C1="250"),5))
Formula2: UNIQUE(CHOOSECOLS(FILTER(A2:F9,C2:C9="250"),5))
Level: medium
Question: Which works number has a class of 15th and year of 1940?
Formula: UNIQUE(CHOOSECOLS(FILTER(A1:F1,(C1="15th")*(E1=1940)),4))
Formula2: UNIQUE(CHOOSECOLS(FILTER(A2:F9,(C2:C9="15th")*(E2:E9=1940)),4))
Level: medium
Question: Which builder has a railway of Rhodesia Railways?
Formula: UNIQUE(CHOOSECOLS(FILTER(A1:F1,B1="rhodesia railways"),6))
Formula2: UNIQUE(CHOOSECOLS(FILTER(A2:F9,B2:B9="rhodesia railways"),6))
Level: medium
Question: Which railway has a class of 250 and year 1936?
Formula: UNIQUE(CHOOSECOLS(FILTER(A1:F1,(C1="250")*(E1=1936)),2))
Formula2: UNIQUE(CHOOSECOLS(FILTER(A2:F9,(C2:C9="250")*(E2:E9=1936)),2))
Level: medium