Table:
0
A
B
C
D
E
F
1
IWCR No.
Name
Wheel arrangement
SR No.
Year made
Year withdrawn
2
1 (1st)
Pioneer
2-2-2T
—
1861
1904
3
2 (1st)
Precursor
2-2-2T
—
1861
1904
4
1 (2nd)
—
0-4-0T
—
1906
1918
5
2 (2nd)
—
0-4-4T
—
1895
1917
6
3
—
0-4-2T
—
1870
1918
7
4
Cowes
2-4-0T
W4
1876
1925
8
5
Osborne
2-4-0T
W5
1876
1926
9
6 (1st)
Newport
2-2-2T
—
1861
1895
10
6 (2nd)
—
4-4-0T
W6
1890
1926
11
7 (1st)
—
4-4-0T
—
1861
1906
12
7 (2nd)
—
2-4-0T
W7
1882
1926
13
8
—
2-4-0T
W8
1898
1929
14
9
—
0-6-0T
W9
1872
1927
15
10
—
0-6-0T
W10
1874
1936
16
11
—
0-6-0T
W11
1878
1963
17
12
—
0-6-0T
W12
1880
1936

Questions and formulas:
Question: Which of the lowest years had a Wheel arrangement that was 0-4-2t?
Formula: MINIFS(E1,C1,"0-4-2t")
Formula2: MINIFS(E2:E17,C2:C17,"0-4-2t")
Level: easy
Question: What is the mean Year when the IWCR number was 5 and the Year withdrawn was bigger than 1926?
Formula: AVERAGE(FILTER(E1, (A1=5)*(F1>1926)))
Formula2: AVERAGE(FILTER(E2:E17, (A2:A17=5)*(F2:F17>1926)))
Level: easy
Question: Which SR number had a wheel arrangement of 0-6-0t, the year made was more recent than 1874, and the year withdrawn was 1963?
Formula: LET(query1,LET(query1,FILTER(A1:F1,(C1="0-6-0t")*(F1=1963)),SUMMARIZE(CHOOSECOLS(query1,4),SUMX(CHOOSECOLS(query1,5)))),FILTER(query1,CHOOSECOLS(query1,2)>1874))
Formula2: LET(query1,LET(query1,FILTER(A2:F17,(C2:C17="0-6-0t")*(F2:F17=1963)),SUMMARIZE(CHOOSECOLS(query1,4),SUMX(CHOOSECOLS(query1,5)))),FILTER(query1,CHOOSECOLS(query1,2)>1874))
Level: hard
Question: What is the sum number of years where the wheel arrangement of 0-4-0t?
Formula: SUMIFS(E1,C1,"0-4-0t")
Formula2: SUMIFS(E2:E17,C2:C17,"0-4-0t")
Level: easy