[Geometry]
Problem: Let $T=(0,0), N=(2,0), Y=(6,6), W=(2,6)$, and $R=(0,2)$. Compute the area of pentagon $T N Y W R$.

Solution: Pentagon $T N Y W R$ fits inside square $T A Y B$, where $A=(6,0)$ and $B=(0,6)$. The region of $T A Y B$ not in $T N Y W R$ consists of triangles $\triangle N A Y$ and $\triangle W B R$, as shown below.

<img_3654>

Thus

$$
\begin{aligned}
{[T N Y W R] } & =[T A Y B]-[N A Y]-[W B R] \\
& =6^{2}-\frac{1}{2} \cdot 4 \cdot 6-\frac{1}{2} \cdot 2 \cdot 4 \\
& =\mathbf{2 0} .
\end{aligned}
$$

Final answer: 20