[Algebra]
Problem: Let $T=11$. Compute the value of $x$ that satisfies $\sqrt{20+\sqrt{T+x}}=5$.

Solution: Squaring each side gives $20+\sqrt{T+x}=25$, thus $\sqrt{T+x}=5$, and $x=25-T$. With $T=11$, $x=14$.

Final answer: 14