【鸡尾酒排序】
鸡尾酒排序，也就是定向冒泡排序，鸡尾酒搅拌排序，搅拌排序（也可以视作选择排序的一种变形），涟漪排序，来回排序或快乐小时排序，是冒泡排序的一种变形。此演算法与冒泡排序的不同处在于排序时是以双向在序列中进行排序。
== 伪代码 ==
将一个序列由小到大进行排序：
function cocktail_sort(list, list_length){ // the first element of list has index 0
bottom = 0;
top = list_length - 1;
swapped = true;
while(swapped == true) // if no elements have been swapped, then the list is sorted
{
swapped = false;
for(i = bottom; i  listi + 1)  // test whether the two elements are in the correct order
{
swap(listi, listi + 1); // let the two elements change places
swapped = true;
}
}
// decreases top the because the element with the largest value in the unsorted
// part of the list is now on the position top
top = top - 1;
for(i = top; i > bottom; i = i - 1)
{
if(listi // increases bottom because the element with the smallest value in the unsorted
// part of the list is now on the position bottom
bottom = bottom + 1;
}
}
== 与冒泡排序不同的地方 ==
鸡尾酒排序等于是冒泡排序的轻微变形。不同的地方在于从低到高然后从高到低，而冒泡排序则仅从低到高去比较序列里的每个元素。他可以得到比冒泡排序稍微好一点的效能，原因是冒泡排序只从一个方向进行比对（由低到高），每次循环只移动一个项目。
以序列（2,3,4,5,1）为例，鸡尾酒排序只需要访问一次序列就可以完成排序，但如果使用冒泡排序则需要四次。但是在乱数序列的状态下，鸡尾酒排序与冒泡排序的效率与其他众多排序算法相比均比较低。
==实作范例==
===C语言===
void cocktail_sort(int arr, int len) {
int i, left = 0, right = len - 1;
int temp;
while (left  arri + 1) {
temp = arri;
arri = arri + 1;
arri + 1 = temp;
}
right--;
for (i = right; i > left; i--)
if (arri - 1 > arri) {
temp = arri;
arri = arri - 1;
arri - 1 = temp;
}
left++;
}
}
===C++===
template //整数或浮点数皆可使用,若要使用物件(class)时必须设定大于(>)的运算子功能
void cocktail_sort(T arr, int len) {
int j, left = 0, right = len - 1;
while (left  arrj + 1)
swap(arrj, arrj + 1);
right--;
for (j = right; j > left; j--)
if (arrj - 1 > arrj)
swap(arrj - 1, arrj);
left++;
}
}
===Rust===
fn cocktail_sort(arr: &mut T) {
let mut bottom: usize = 0;
let mut top = arr.len() - 1;
let mut swapped = true;
while swapped {
swapped = false;
for i in bottom..top {
if arri > arri+1 {
arr.swap(i, i+1);
swapped = true;
}
}
top -= 1;
for j in ((bottom + 1)..=top).rev() {
if arrj
===JAVA===
public static void cocktail_sort(int arr) {
int i, left = 0, right = arr.length - 1;
int temp;
while (left  arri + 1) {
temp = arri;
arri = arri + 1;
arri + 1 = temp;
}
right--;
for (i = right; i > left; i--)
if (arri - 1 > arri) {
temp = arri;
arri = arri - 1;
arri - 1 = temp;
}
left++;
}
}
===JavaScript===
Array.prototype.cocktail_sort = function() {
var i, left = 0, right = this.length - 1;
var temp;
while (left  thisi + 1) {
temp = thisi;
thisi = thisi + 1;
thisi + 1 = temp;
}
right--;
for (i = right; i > left; i--)
if (thisi - 1 > thisi) {
temp = thisi;
thisi = thisi - 1;
thisi - 1 = temp;
}
left++;
}
};
===PHP===
function swap(&$x, &$y) {
$t = $x;
$x = $y;
$y = $t;
}
function cocktail_sort(&$arr) {//php的阵列视为基本型别，所以必须用传参才能修改原阵列
$left = 0;
$right = count($arr) - 1;
while ($left  $arr$j + 1)
swap($arr$j, $arr$j + 1);
$right--;
for ($j = $right; $j > $left; $j--)
if ($arr$j - 1 > $arr$j)
swap($arr$j - 1, $arr$j);
$left++;
}
}
===Python 2.7===
def cocktail_sort(l):
l_len = len(l)
for i in range(l_len, 0, -1):
rem_i_l_len = abs(i - l_len)
isNeedContinue = False
obverse_count = len(lrem_i_l_len : i-1)
reverse_count = len(lrem_i_l_len + 1 : i-1)
for j in range(obverse_count):
if lj > lj + 1:
lj, lj + 1 = lj + 1, lj
isNeedContinue = True
# you can print this to observe the whole process
# print l
for j in range(reverse_count, 0, -1):
if lj
===Python 3.10===
def cocktail_sort(arr: list, bottom: int = None, top: int = None):
if not bottom and not top:
bottom, top = 0, len(arr) - 1
if bottom == top or bottom > top:
return
swapped: bool = False
for i in range(bottom, top):
if arri > arri + 1:
arri + 1, arri = arri, arri + 1
swapped = True
for i in range(top - 1, bottom, -1):
if arri
=== Golang ===
func cocktailSort(arr int) {
left := 0
right := len(arr) - 1
for left  arri+1 {
arri, arri+1 = arri+1, arri
}
}
right--
for i := right; i > left; i-- {
if arri-1 > arri {
arri-1, arri = arri, arri-1
}
}
left++
}
}
===Julia (程式语言)===
# Julia Sample : CocktailSort
function CocktailSort(A)
isordered, lo, hi  = false, 1, length(A)
while !isordered && hi > lo
isordered = true
for i=lo+1:hi
if Ai  Ai
Ai-1, Ai = Ai, Ai-1
isordered = false
end
end
lo += 1
end
return A
end
# Main Code
A = 16,586,1,31,354,43,3
println(A)                      # Original Array
println(CocktailSort(A)) 		# Cocktail Sort Array
== 复杂度 ==
鸡尾酒排序最糟或是平均所花费的次数都是，但如果序列在一开始已经大部分排序过的话，会接近。
== 外部连结 ==
* Java source code and an animated demo of cocktail sort (called bi-directional bubble sort) and several other algorithms
*Implementations of cocktail sort in several different programming languages