how do visible and infrared radiation differ?
When you say: an infrared wave with lower energy compared to visible light. I'm guessing you're referring to the photon energy: $$ E = h\nu $$. Visible light has a higher frequency than IR light, so the energy per photon of visible light is higher than IR light. However this is not related to the energy carried by the wave.
Infrared (IR) is invisible radiant energy, electromagnetic radiation with longer wavelengths than those of visible light, extending from the nominal red edge of the visible spectrum at 700 nanometers (frequency 430 THz) to 1 mm (300 GHz) (although people can see infrared up to at least 1050 nm in experiments).