ASB Classic 2023 - Đôi nam

Nikola Mektić Mate Pavić
| runner = Nathaniel Lammons Jackson Withrow
| score = 6–4, 6–7(5–7), [10–6]
| edition =
| main_name = ATP Auckland Open
| before_name = ASB Classic
| before_year = 2020
}}

Nikola Mektić và Mate Pavić là nhà vô địch, đánh bại Nathaniel Lammons và Jackson Withrow trong trận chung kết, 6–4, 6–7(5–7), [10–6].

Luke Bambridge và Ben McLachlan là đương kim vô địch, nhưng Bambridge đã giải nghệ quần vợt và McLachlan chọn tham dự ở Adelaide.

Hạt giống
Nikola Mektić / Mate Pavić (Vô địch)
Marcel Granollers / Horacio Zeballos (Bán kết)
Simone Bolelli / Fabio Fognini (Vòng 1)
Jamie Murray / Michael Venus (Vòng 1)
}}

Kết quả

Kết quả
N Mektić M Pavić
| RD1-score01-1=7
| RD1-score01-2=65
| RD1-score01-3=[10]
| RD1-seed02=WC
| RD1-team02= A Rai F Reynolds
| RD1-score02-1=5
| RD1-score02-2=77
| RD1-score02-3=[5]

| RD1-seed03=
| RD1-team03= M González A Molteni
| RD1-score03-1=w/o
| RD1-score03-2=
| RD1-score03-3=
| RD1-seed04=
| RD1-team04= P Cachín F Cerúndolo
| RD1-score04-1=
| RD1-score04-2=
| RD1-score04-3=

| RD1-seed05=3
| RD1-team05= S Bolelli F Fognini
| RD1-score05-1=4
| RD1-score05-2=3
| RD1-score05-3=
| RD1-seed06=
| RD1-team06= A Erler L Miedler
| RD1-score06-1=6
| RD1-score06-2=6
| RD1-score06-3=

| RD1-seed07=Alt
| RD1-team07= S Báez LD Martínez
| RD1-score07-1=6
| RD1-score07-2=6
| RD1-score07-3=
| RD1-seed08=
| RD1-team08= S Doumbia F Reboul
| RD1-score08-1=4
| RD1-score08-2=4
| RD1-score08-3=

| RD1-seed09=
| RD1-team09= Q Halys A Mannarino
| RD1-score09-1=4
| RD1-score09-2=1
| RD1-score09-3=
| RD1-seed10=PR
| RD1-team10= J Chardy F Martin
| RD1-score10-1=6
| RD1-score10-2=6
| RD1-score10-3=

| RD1-seed11=
| RD1-team11= N Lammons J Withrow
| RD1-score11-1=62
| RD1-score11-2=6
| RD1-score11-3=[12]
| RD1-seed12=4
| RD1-team12= J Murray M Venus
| RD1-score12-1=77
| RD1-score12-2=4
| RD1-score12-3=[10]

| RD1-seed13=Alt
| RD1-team13= A Bublik J-P Smith
| RD1-score13-1=
| RD1-score13-2=
| RD1-score13-3=
| RD1-seed14=
| RD1-team14= S Gillé J Vliegen
| RD1-score14-1=w/o
| RD1-score14-2=
| RD1-score14-3=

| RD1-seed15=WC
| RD1-team15= A Lawson A Sitak
| RD1-score15-1=64
| RD1-score15-2=2
| RD1-score15-3=
| RD1-seed16=2
| RD1-team16= M Granollers H Zeballos
| RD1-score16-1=77
| RD1-score16-2=6
| RD1-score16-3=

| RD2-seed01=1
| RD2-team01= N Mektić M Pavić
| RD2-score01-1=77
| RD2-score01-2=3
| RD2-score01-3=[10]
| RD2-seed02=
| RD2-team02= M González A Molteni
| RD2-score02-1=63
| RD2-score02-2=6
| RD2-score02-3=[5]

| RD2-seed03=
| RD2-team03= A Erler L Miedler
| RD2-score03-1=6
| RD2-score03-2=6
| RD2-score03-3=
| RD2-seed04=Alt
| RD2-team04= S Báez LD Martínez
| RD2-score04-1=4
| RD2-score04-2=0
| RD2-score04-3=

| RD2-seed05=PR
| RD2-team05= J Chardy F Martin
| RD2-score05-1=2
| RD2-score05-2=64
| RD2-score05-3=
| RD2-seed06=
| RD2-team06= N Lammons J Withrow
| RD2-score06-1=6
| RD2-score06-2=77
| RD2-score06-3=

| RD2-seed07=
| RD2-team07= S Gillé J Vliegen
| RD2-score07-1=4
| RD2-score07-2=78
| RD2-score07-3=[7]
| RD2-seed08=2
| RD2-team08= M Granollers H Zeballos
| RD2-score08-1=6
| RD2-score08-2=66
| RD2-score08-3=[10]

| RD3-seed01=1
| RD3-team01= N Mektić M Pavić
| RD3-score01-1=77
| RD3-score01-2=6
| RD3-score01-3=
| RD3-seed02=
| RD3-team02= A Erler L Miedler
| RD3-score02-1=65
| RD3-score02-2=3
| RD3-score02-3=

| RD3-seed03=
| RD3-team03= N Lammons J Withrow
| RD3-score03-1=77
| RD3-score03-2=77
| RD3-score03-3=
| RD3-seed04=2
| RD3-team04= M Granollers H Zeballos
| RD3-score04-1=65
| RD3-score04-2=65
| RD3-score04-3=

| RD4-seed01=1
| RD4-team01= N Mektić M Pavić
| RD4-score01-1=6
| RD4-score01-2=65
| RD4-score01-3=[10]
| RD4-seed02=
| RD4-team02= N Lammons J Withrow
| RD4-score02-1=4
| RD4-score02-2=77
| RD4-score02-3=[6]
}}

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