1886 United States House of Representatives elections
The 1886 United States House of Representatives elections were held in the middle of President Grover Cleveland's first term. As in many midterm elections, the President's party lost seats to the opposition, in this case, Democrats lost seats to Republicans, although a narrow majority was retained. Many of these Republican pickups were in the industrializing Midwest states, where the debate over tariffs, which were advocated by Republicans to protect domestic industry but opposed by Democrats to allow for free agricultural trade, led to political change. The small Labor Party, supported by  industrial workers, gained one seat each in Virginia and Wisconsin, while the Greenback Party maintained its one seat in Iowa (James B. Weaver). One Independent was also elected in North Carolina. Election summaries. There were 2 Labor and 1 Independent members elected, and 1 Greenback member re-elected. The previous election saw just the Greenback elected. Special elections. ! ! Election dates. In all the states except three, elections were held November 2, 1886. Those three states, with 7 seats among them, held elections: Arizona Territory. See Non-voting delegates, below. California. ! ! ! ! ! Dakota Territory. See Non-voting delegates, below. Florida. ! Idaho Territory . See Non-voting delegates, below. Massachusetts. ! ! ! ! ! ! ! ! ! ! ! ! Michigan. ! ! ! ! ! ! ! ! ! ! ! Mississippi. ! ! ! ! ! ! ! Montana Territory. See Non-voting delegates, below. Nebraska. ! ! ! New Mexico Territory. See Non-voting delegates, below. South Carolina. ! ! ! ! ! ! Tennessee. ! ! ! ! ! ! ! ! ! ! Utah Territory. See Non-voting delegates, below. Washington Territory. See Non-voting delegates, below. West Virginia. ! ! ! ! Wisconsin. Wisconsin elected nine members of congress on Election Day, November 2, 1886. ! ! ! ! ! ! ! ! Wyoming Territory. See Non-voting delegates, below. Non-voting members. ! ! ! ! ! ! ! !