2019 Indian Open
The 2019 Indian Open was a professional snooker tournament. It was due to take place between 18 and 22 September 2018 at the Grand Hyatt Kochi Bolgatty in Kochi, India but was postponed due to the 2018 Kerala floods. The rescheduled Indian Open was played in Kochi from 27 February to 3 March 2019. It was the fifteenth ranking event of the 2018/2019 season. Qualifying took place on 15 and 16 August 2018 in Preston, England. John Higgins was the defending champion, having beaten Anthony McGill 5–1 in the 2017 final, but he lost to Matthew Selt  in the semi-finals. Selt went on to win his first ranking title, beating Lyu Haotian 5–3 in the final. Zhou Yuelong made the first maximum break of his career in the fourth frame of his first round loss to Lyu Haotian. It was the 150th maximum in professional events. Prize fund. The breakdown of prize money for this year is shown below: The "rolling 147 prize" for a maximum break: £10,000 Qualifying. These matches were held between 15 and 16 August 2018 at the Preston Guild Hall in Preston, England. All matches were best of 7 frames. Century  breaks. Main stage centuries. There were a total of 33 century breaks made during the tournament. Zhou Yuelong made a century in a held over match. Qualifying stage centuries. There were a total of 10 century breaks made during the qualifying matches preceding the event.