To find the above numbers: Given: 3.5 grams of salt per 100 total volume Total Volume for each solution: 900 mL Grams salt for 100% salt: 3.5 g * 9 = 31.5 g NaCl Moles salt for 100% salt: 31.5 g NaCl / 58.5 g NaCl per mole NaCl = 0.5385 moles NaCl Since each mole of NaCl dissociates into 2 moles of ions, total moles of ions is: 0.5385 moles * 2 = 1.0769 moles Grams sugar for 100% sugar: 1.0769 moles * 342 g C12H22O11 per mole sucrose = 368.31 g C12H22O11 Volume of water = 900 mL - grams of solutes Take half of 31.5 grams NaCl and half of 368.31 grams C12H22O11 for 50%/50% solution.
(each mole of NaCl; dissociates; into 2 moles of ions) (total moles of ions; is; 0.5385 moles * 2 = 1.0769 moles Grams sugar for 100% sugar) Context(total moles of ions is,List([306, 328))):(342 g; C12H22O11; per mole sucrose = 368.31 g C12H22O11 Volume of water) Context(total moles of ions is,List([306, 328))):(900 mL - grams of solutes; Take; half of 31.5 grams NaCl)
total moles of ions is,List([306, 328)) total moles of ions is,List([306, 328))
each mole of NaCl total moles of ions 342 g 900 mL - grams of solutes
dissociates is C12H22O11 Take
into 2 moles of ions
0.5385 moles * 2 = 1.0769 moles Grams sugar for 100% sugar
per mole sucrose = 368.31 g C12H22O11 Volume of water
half of 31.5 grams NaCl