Assertion: trigonometric function's value | /r/HasProperty | a \displaystyle a
Facets:
Source sentences:
text: Furthermore, since Arg ⁡ ζ = Arg ⁡ a ζ {\displaystyle \operatorname {Arg} \zeta =\operatorname {Arg} a\zeta } for any positive real value a {\displaystyle a} , then if we let ζ = ζ 1 ζ 2 {\displaystyle \zeta =\zeta