Assertion: tetrahedron's edge | /r/HasProperty | equal
Facets:
value: in other words
type: OTHER
value: in an isosceles tetrahedron
type: LOCATION
value: in length
type: OTHER
Source sentences:
text: The hidden assumption, I think, is that the edges of the two polyhedra intersect; in other words, that the midspheres are equal.
text: The 8 vertices are truncated such that all edges are equal length.
text: For example, since each edge of the tetrahedron is also one of the cube's face diagonals, the edges of the tetrahedron must be equal in length.
text: The regular dodecahedron represents a special intermediate case where all edges and angles are equal.
text: Continuing from there in that direction, we pass through a degenerate case where twelve vertices coincide in the centre, and on to the regular great stellated dodecahedron where all edges and angles are equal again, and the faces have been distorted into regular pentagrams.
text: In other words, in an isosceles tetrahedron the opposite edges are equal.