Assertion: triangle's area | /r/HasProperty | equal
Facets:
value: in the diagram to the left
type: LOCATION
value: to `sqrt(12
type: OTHER
value: to a + b )²
type: OTHER
value: to that of two smaller squares
type: OTHER
value: to its defect
type: OTHER
value: interestingly
type: DEGREE
Source sentences:
text: Furthermore, the four triangles that the original triangle is subdivided into by the medial triangle are all mutually congruent by SSS, so their areas are equal and thus the area of each is 1/4 the area of the original triangle.:p.177
text: The area of a triangle is equal to half of the product of its base and height.
text: Interestingly, the area of all these triangles is equal.
text: In particular, the area of a triangular face of a tetrahedron is less than or equal to the sum of the areas of the other three sides.
text: It is known that right angles were laid out accurately in Ancient Egypt; that their surveyors did use ropes for measurement; that Plutarch recorded in Isis and Osiris (around 100 AD) that the Egyptians admired the 3 : 4 : 5 triangle; and that the Berlin Papyrus 6619 from the Middle Kingdom of Egypt (before 1700 BC) stated that "the area of a square of 100 is equal to that of two smaller squares.
text: The area of a hyperbolic triangle is equal to its defect multiplied by the square of R:
text: The area of the triangle is equal to `sqrt(12*6*4*2) = sqrt(576)
text: Now it is clear, that an area of the square CDEF is equal to ( a + b )².
text: On the other hand, this area is equal to a sum of areas of four right-angled triangles and a square AKMB, that is
text: He treated each side of a right triangle as though it were a square and discovered that the total area of the two smaller squares is equal to the area of the largest square.
text: For example, in the diagram to the left, the area of each triangle is equal to one-half the area of the parallelogram.