Assertion: sound wave's wavelength | /r/HasProperty | lambda
Facets:
Source sentences:
text: The frequency and speed can be used to determine the wavelength (lambda): lambda = v / f = (346 m/s) / (20 Hz) = 17.3 m
text: So the new wavelength will be lambda = (2.24 m) / 1.2599 = 1.78 m Since the wavelength is twice the effective length of the string, the string must have an effective length of 0.89 m or 89 cm.
text: The wavelength (lambda) of the resonating air column can be determined using a good diagram accompanied by the length of the air column.
text: The strategy in this problem involves determining the wavelength (lambda) from the speed and the frequency and then determining the length from the wavelength-length relationship.
text: The frequency and speed can be used to determine the wavelength (lambda): lambda = v / f = (346 m/s) / (20 Hz) = 17.3 m
text: The wavelength (lambda) of a 262 Hz sound at this temperature is lambda = v / f = (338 m/s) / (262 Hz)
text: The wavelength (lambda) of a 262 Hz sound at this temperature is lambda = v / f = (338 m/s) / (262 Hz)
text: The wavelength (lambda) of a 440 Hz sound can be determine from the wave equation (v = f*lambda)
text: So the new wavelength will be lambda = (2.24 m) / 1.2599 = 1.78 m Since the wavelength is twice the effective length of the string, the string must have an effective length of 0.89 m or 89 cm.
text: The wavelength (lambda) of the resonating air column can be determined using a good diagram accompanied by the length of the air column.
text: The strategy in this problem involves determining the wavelength (lambda) from the speed and the frequency and then determining the length from the wavelength-length relationship.