Assertion: parallelogram's line | /r/HasProperty | parallel
Facets:
value: to the line
type: OTHER
Source sentences:
text: Theorem: If a transversal cuts across two lines and the alternate interior angles are congruent, then the lines are parallel
text: Reason for statement 4: If lines are parallel, then alternate exterior angles are congruent.
text: then lines are parallel.
text: And because the opposite lines are parallel, hence the opposite angles are also equal.
text: Its opposing lines are parallel and of equal length.
text: In the triangle BCD, the line (IJ) passes through the midpoints of two of his edges [DC] and [BC], thus the line (IJ) will be parallel to the line that passes by the third remaining edge which is (DB), so (DB)//(IJ) and the distance IJ=1/2 DB , this is a property that they have studied, they just named property with no other name, but they can use it in triangles: '' If ABC is a triangle, M and N are the midpoints of two of his edges, then the line (MN) is parallel to the line that passes through the third edge, and the distance MN is half the measure of the third edge.''After that i tried proving that EDBJ is a parallelogram ( using only basic parallelogram properties ), but i couldn't find a way.2)