Assertion: parallelogram's diagonal | /r/HasProperty | perpendicular
Facets:
value: to each other
type: OTHER
value: to one another
type: OTHER
Source sentences:
text: If a parallelogram is a rhombus, then its diagonals are perpendicular.
text: Property 2: The diagonals of a rhombus are perpendicular bisectors of one another i.e. AO = CO and BO =
text: Vice versa, if the diagonals of a parallelogram are perpendicular, then this parallelogram is a rhombus.
text: Diagonals are perpendicular.
text: Diagonals are perpendicular.
text: The two diagonals of a rhombus are perpendicular; that is, a rhombus is an orthodiagonal quadrilateral.
text: In a rhombus, the diagonals intersect each other at right angles and hence are perpendicular to each other.
text: Moreover, a rhombus’s diagonals are perpendicular to each other; they bisect each other at right angles.
text: It also implies that the diagonals are perpendicular.
text: The two bimedians have equal length if and only if the two diagonals are perpendicular.
text: p and q, with equality if and only if the diagonals are perpendicular.
text: All the diagonals are perpendicular to one another
text: I'm thinking of a parallelogram whose diagonals are perpendicular.
text: Theorem 16.6: If the diagonals of a parallelogram are perpendicular, the parallelogram is a rhombus.
text: It also looks like the diagonals of the newly created quadrilateral are perpendicular.
text: If a parallelogram has perpendicular diagonals, you know it is a rhombus.
text: Theorem 16.8: If the diagonals of a parallelogram are congruent and perpendicular, the parallelogram is a square.
text: Its diagonals are perpendicular and each diagonal bisects two angles of the rhombus.
text: For example, the diagonals of a rhombus, kite or square are perpendicular, but those of a rectangle or general parallelogram are not.