Assertion: protactinium's life | /r/HasProperty | 30.2 y
Facets:
value: in appendix b
type: LOCATION
Source sentences:
text: Since the activity R is given, and the half-life of 137Cs is found in Appendix B to be 30.2 y, we can use the equation [latex]R=\frac{0.693N}{t_{1/2}}\\[/latex] to find N. Solution Solving the equation [latex]R=\frac{0.693N}{t_{1/2}}\\[/latex] for N gives [latex]\displaystyle{N}=\frac{Rt_{1/2}}{0.693}\\[/latex] Entering the given values yields