Assertion: parallelepiped's set | /r/CapableOf | lie on same plane
Facets:
value: as the other two
type: OTHER
Source sentences:
text: Since every vector in $\{ \vec{u}, \vec{v}, \vec{w} \}$ must already lie on the same plane as another from the set, then since the volume is zero, there must exist a vector in this set that lies on the same plane as the other two.