Assertion: parabola's equation | /r/HasAspect | the form
Facets:
value: by the af+bg theorem
type: OTHER
Source sentences:
text: The focus has the form [latex]\left(p,0\right)[/latex], so the equation will have the form [latex]{y}^{2}=4px[/latex]. Multiplying [latex]4p[/latex]
text: The focus has the form ( p , 0 ) , so the equation will have the form y 2 = 4 p x .
text: So, by the AF+BG theorem, the tangential equation of C has the form HP+KQ=0.
text: The equation used is the standard equation that has the form
text: The focus has the form [latex]\left(p,0\right)[/latex], so the equation will have the form [latex]{y}^{2}=4px[/latex]. Multiplying [latex]4p[/latex]
text: The focus has the form [latex]\left(p,0\right)[/latex], so the equation will have the form [latex]{y}^{2}=4px[/latex]. Multiplying [latex]4p[/latex], we have [latex]4p=4\left(-\frac{1}{2}\right)=-2[/latex].
text: The focus has the form [latex]\left(p,0\right)[/latex], so the equation will have the form [latex]{y}^{2}=4px[/latex]. Multiplying [latex]4p[/latex], we have [latex]4p=4\left(-\frac{1}{2}\right)=-2[/latex].
text: If the asymptotes are taken to be the horizontal and vertical coordinate axes (respectively, \(y = 0\) and \(x = 0\)), then the equation of the equilateral hyperbola has the form
text: The canonical equation of a parabola has the form
text: The equation of the parabola, with vertical axis of symmetry, has the form y = a x 2 + b
text: The equation of a catenary in Cartesian coordinates has the form
text: Since the is the axis of of the parabola and its is at the origin, the equation of the parabola has the form