Assertion: parabola's equation | /r/AtLocation | the form
Facets:
Source sentences:
text: If the equation is in the form [latex]{y}^{2}=4px[/latex], then the axis of symmetry is the x-axis, [latex]y=0[/latex] set [latex]4p[/latex] equal to the coefficient of x in the given equation to solve for [latex]p[/latex].
text: Thus, the curve must be entirely to the right of the Y axis when the equation is in this form.
text: If the equation is in the form [latex]{x}^{2}=4py[/latex], then the axis of symmetry is the y-axis, [latex]x=0[/latex] set [latex]4p[/latex] equal to the coefficient of y in the given equation to solve for [latex]p[/latex].
text: If the equation is in the form [latex]{\left(y-k\right)}^{2}=4p\left(x-h\right)[/latex], then: use the given equation to identify [latex]h[/latex] and [latex]k[/latex] for the vertex, [latex]\left(h,k\right)[/latex]
text: If the equation is in the form [latex]{\left(x-h\right)}^{2}=4p\left(y-k\right)[/latex], then: use the given equation to identify [latex]h[/latex] and [latex]k[/latex] for the vertex, [latex]\left(h,k\right)[/latex]
text: If the equation is in the form y 2 = 4 p x , then the axis of symmetry is the x-axis, y = 0
text: If the equation is in the form x 2 = 4 p y
text: If the equation is in the form ( y − k ) 2 = 4 p (
text: If the equation is in the form (
text: If the equation is in the form [latex]{y}^{2}=4px[/latex], then the axis of symmetry is the x-axis, [latex]y=0[/latex] set [latex]4p[/latex] equal to the coefficient of x in the given equation to solve for [latex]p[/latex].
text: If the equation is in the form [latex]{x}^{2}=4py[/latex], then the axis of symmetry is the y-axis, [latex]x=0[/latex] set [latex]4p[/latex] equal to the coefficient of y in the given equation to solve for [latex]p[/latex].
text: If the equation is in the form [latex]{\left(y-k\right)}^{2}=4p\left(x-h\right)[/latex], then: use the given equation to identify [latex]h[/latex] and [latex]k[/latex] for the vertex, [latex]\left(h,k\right)[/latex]
text: If the equation is in the form [latex]{\left(x-h\right)}^{2}=4p\left(y-k\right)[/latex], then: use the given equation to identify [latex]h[/latex] and [latex]k[/latex] for the vertex, [latex]\left(h,k\right)[/latex]
text: When the equation is in the form x2 = - 4ay the curve opens downward, is entirely below the X axis, and has as its focus a point on the negative Y axis.