Assertion: isometry's point | /r/HasProperty | $a$
Facets:
Source sentences:
text: On the plane, for example, assume that a point $a$ does not lie in the image of an isometry $
text: Assume $f$ has at least two fixed points $A,
text: The point $T(a')$ must be $a$ as that is the only point that satisfies all the point to point distances, so $a$ does lie in the image of $T$.