Assertion: lens's image | /r/HasProperty | upright
Facets:
Source sentences:
text: For an object very close to the lens (0 < S 1 < |f|), a converging lens would form a magnified (bigger) virtual image, whereas a diverging lens would form a demagnified (smaller) image; For an object very far from the lens (S 1 > |f| > 0), a converging lens would form an inverted image, whereas a diverging lens would form an upright image.
text: For an object very close to the lens (0 < S 1 < |f|), a converging lens would form a magnified (bigger) virtual image, whereas a diverging lens would form a demagnified (smaller) image; For an object very far from the lens (S 1 > |f| > 0), a converging lens would form an inverted image, whereas a diverging lens would form an upright image.
text: For virtual images M is positive, so the image is upright.
text: > f 2 ) produces a positive magnification and the image is upright.
text: the image will be virtual , upright and bigger than the object .
text: For virtual images M is positive, so the image is upright.
text: > f 2 ) produces a positive magnification and the image is upright.