Assertion: octahedron's vertex | /r/HasProperty | the vertices of a cube
Facets:
Source sentences:
text: It's fairly trivial, though -- a cube fits within a dodecahedron's vertices (as seen from the compound of five cubes within a dodecahedron), and the vertices of a stella octangula are the vertices of a cube...
text: Understandably so, for we already know that the two vertices F and G are two of the vertices of a cube (see Figure 1A).
text: The eight vertices are the vertices of a cube.