Assertion: metric space's diameter | /r/HasProperty | finite
Facets:
Source sentences:
text: Note that, more generally, and with the same one-line proof, every compact metric space has finite diameter.
text: However the following statement is false: "If a metric space is complete and has finite diameter, then it is compact.
text: If the diameter of A is finite, i.e. d(A) < , then A is said to be bounded.