Assertion: generating function | /r/HasProperty | ∑ n ≥
Facets:
Source sentences:
text: where { n k } {\displaystyle \left\{{\begin{matrix}n\\k\end{matrix}}\right\}} denote the Stirling numbers of the second kind and where the generating function ∑ n ≥
text: 0}f(m,n)w^{m}z^{n}} is a bivariate rational generating function, then its corresponding diagonal generating function, diag ⁡ ( F ) := ∑ n ≥ 0 f ( n , n )