Assertion: electric potential | /r/HasProperty | 25.0 kv.
Facets:
Source sentences:
text: The expression for the magnitude of the electric field between two uniform metal plates is [latex]E=\frac{V_{\text{AB}}}{d}\\[/latex]. Since the electron is a single charge and is given 25.0 keV of energy, the potential difference must be 25.0 kV. Entering this value for V AB and the plate separation of 0.0400 m, we obtain [latex]E=\frac{25.0\text{ kV}}{0.0400\text{ m}}=6.25\times10^
text: Since the electron is a single charge and is given 25.0 keV of energy, the potential difference must be 25.0 kV. Entering this value for and the plate separation of 0.0400 m, we obtain .
text: Since the electron is a single charge and is given 25.0 keV of energy, the potential difference must be 25.0 kV. Entering this value for and the plate separation of 0.0400 m, we obtain