Assertion: dodecahedron's face | /r/CapableOf | assume the shape of regular decagons
Facets:
Source sentences:
text: d icosahedron / d dodecahedron = √(τ 2 +1)/3 (7τ-6)/5 = 1.1698 the faces of the dodecahedron assume the shape of regular decagons, thus obtaining the Archimedean truncated dodecahedron, in which each vertex is shared by three regular polygons: two decagons and a triangle.