Assertion: distribution's variance | /r/CapableOf | derive new total precision
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text: That is, to combine n data points with total precision of nτ (or equivalently, total variance of n/σ2) and mean of values x ¯ {\displaystyle {\bar {x}}} , derive a new total precision simply by adding the total precision of the data to the prior total precision, and form a new mean through a precision-weighted average, i.e. a weighted average of the data mean and the prior mean, each weighted by the associated total precision.