Assertion: parity function | /r/CapableOf | exist 2 c
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Source sentences:
text: Assuming axiom of choice it can be easily proved that parity functions exist and there are 2 c {\displaystyle 2^{\mathfrak {c}}} many of them - as many as the number of all functions from { 0 , 1 } ω {\displaystyle \{0,1\}^{\omega }} to { 0 , 1 } {\displaystyle \{0,1\}} .