Assertion: calorimeter's heat | /r/HasProperty | absorbed by the water
Facets:
value: primarily
type: DEGREE
value: completely
type: DEGREE
Source sentences:
text: Show Answer The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat absorbed by water is q 1 = 675 mL × 0.997 g/mL
text: The heat produced by the reaction is absorbed by the water and the bomb:
text: The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb:
text: The heat released from the sample is largely absorbed by the water, which results in an increase in temperature.
text: When a chemical reaction occurs in the coffee cup calorimeter, the heat of the reaction is absorbed by the water.
text: From Equation \(\ref{5.5.3}\), the heat absorbed by the water is thus \[ \begin{align*} q &=mC_{s}\Delta T \\[4pt] &= \left ( 3.99 \times 10^{5} \; \cancel{g}
text: First, let us calculate the heat absorbed by the water and use the value obtained to calculate the specific heat of the metal.
text: The formula to find the heat absorbed by the water is given as
text: From Equation \ref{12.3.8}, the heat absorbed by the water is thus \[ q=mc_s\Delta T=\left ( 3.99 \times 10^{5} \; \cancel{g} \right )
text: The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb: \(\begin{array}{l}{q}_{\text{rxn}}=-\left({q}_{\text{water}}+{q}_{\text{bomb}}\right)\\ =-\left[\left(4.184\phantom{\rule{0.2em}{0ex}}\text{J/g °C}\right)\phantom{\rule{0.2em}{0ex}}×\phantom{\rule{0.2em}{0ex}}\left(775\phantom{\rule{0.2em}{0ex}}\text{g}\right)\phantom{\rule{0.2em}{0ex}}×\phantom{\rule{0.2em}{0ex}}\left(35.6\phantom{\rule{0.2em}{0ex}}\text{
text: The mathematical relationship used to calculate the amount of heat absorbed by the water is
text: This will allow us to assume that all the heat released is absorbed by the water.
text: The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb:
text: From Equation 6.3.3, the heat absorbed by the water is thus \
text: The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb: \(\begin{align*}
text: From Equation \(\ref{5.5.3}\), the heat absorbed by the water is thus \[ q=
text: The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb:
text: When the reaction is set off, any heat that is liberated is absorbed by the bomb, the water, and any piece of the equipment sticking into the water, and the temperature of the entire contents of the vat rises.
text: Show Answer The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb: [latex]{q}_{\text{rxn}}+{q}_{\text{water}}+{q}_{\text{bomb}}=0[/latex]
text: The combustion produces heat that is primarily absorbed by the water and the bomb.
text: The heat produced by the reaction is absorbed by the water and the bomb:
text: Recognize that the heat absorbed by the water was the heat lost by the metal.
text: From Equation 5.36, the heat absorbed by the water is thus q = m C s Δ T =
text: The amount of heat released during the combustion of a food item will be equal to the amount of heat absorbed by the water that surrounds the combustion chamber (often called a bomb).
text: Q = heat absorbed by water, m = mass of water in grams, Cp = 1 cal/g °C, ∆T = change in temperature
text: It consists of a hollow steel container, lined with platinum and filled with pure oxygen, into which a weighed quantity of substance is placed and ignited with an electric fuse; the heat produced is absorbed by water surrounding the bomb and, from the rise in temperature, the calories liberated are calculated.
text: It consists of a hollow steel container, lined with platinum and filled with pure oxygen, into which a weighed quantity of substance is placed and ignited with an electric fuse; the heat produced is absorbed by water surrounding the bomb and, from the rise in temperature, the calories liberated are calculated.
text: This is done by use of a instrument called Calorimeter, here fuel is taken in a container which is surrounded by water and the fuel is ignited and it releases heat which is absorbed by water.
text: the basic principle is that heat liberated is completely absorbed by water, and so calorimetric value of the fuel is known by increase in temperature of water.
text: The heat absorbed by water is q 1 = 675 mL × 0.997 g/mL