Assertion: curve's point | /r/HasProperty | cusp
Facets:
value: most often
type: DEGREE
Source sentences:
text: {\displaystyle y-x^{3}=0} is considered as singular, as having a singular point (a cusp) at infinity.
text: By eliminating variables (by any tool of elimination theory), an algebraic curve may be projected onto a plane algebraic curve, which however may introduce new singularities such as cusps or double points.
text: {\displaystyle F_{x}(x,y)=0} at that point then the curve is not differentiable there, but instead is a singular point – either a cusp or a point where the curve intersects itself.
text: A point of the curve where F x = F y = 0 is a singular point, which means that the curve in not differentiable at this point, and thus that the curvature is not defined (most often, the point is either a crossing point or a cusp).