Assertion: gaussian curvature | /r/HasProperty | intrinsic invariant
Facets:
Source sentences:
text: The crowning result, the Theorema Egregium of Gauss, established that the Gaussian curvature is an intrinsic invariant, i.e. invariant under local isometries.
text: Since Δ is manifestly an intrinsic invariant, this gives yet another proof that the Gaussian curvature is an intrinsic invariant.