Assertion: deuterium's effect | /r/HasProperty | observable
Facets:
value: always
type: DEGREE
value: with this substitution
type: OTHER
Source sentences:
text: The kinetic isotope effect will always be observable with this substitution since k 1 appears in the simplified rate expression regardless of which step is rate-determining, but it will be less pronounced if the second step is rate-determining due to some cancellation between the isotope effects on k 1 and k 2 .