Assertion: component's value | /r/HasProperty | equal
Facets:
Source sentences:
text: Comparison with the eigenvector factorization of XTX establishes that the right singular vectors W of X are equivalent to the eigenvectors of XTX, while the singular values σ (k) of X {\displaystyle \mathbf {X} } are equal to the square-root of the eigenvalues λ (k) of XTX.