Assertion: cube's root | /r/HasProperty | digital
Facets:
Source sentences:
text: If the number x is divisible by 3, its cube has digital root 9; that is,
text: If it has a remainder of 1 when divided by 3, its cube has digital root 1; that is,
text: If it has a remainder of 2 when divided by 3, its cube has digital root 8; that is,
text: It is, however, easy to show that most numbers are not perfect cubes because all perfect cubes must have digital root 1, 8 or 9.