Assertion: dual basis | /r/HasProperty | computed given the basis
Facets:
value: readily
type: MANNER
Source sentences:
text: In general the dual basis of a basis in a finite dimensional vector space can be readily computed as follows: given the basis f 1 , … , f n {\displaystyle f_{1},\ldots ,f_{n}} and corresponding dual basis f 1 , … , f n {\displaystyle f^{1},\ldots ,f^{n}} we can build matrices