Assertion: algebra's v | /r/HasProperty | finite-dimensional
Facets:
Source sentences:
text: In the case where V is finite-dimensional, the equality of the dimensions implies U = V.
text: If v 1 , … , v n {\displaystyle v_{1},\ldots ,v_{n}} is a basis of V (this implies that V is finite-dimensional), then one can define, for i = 1, ..., n, a linear map v i ∗ {
text: This canonical map is an isomorphism if V is finite-dimensional, and this allows identifying V with its bidual.
text: If V is finite-dimensional, then the latter is naturally isomorphic to Λk(V∗).
text: Suppose that V is finite-dimensional.