Assertion: abelian group's subgroup | /r/HasProperty | z / 2 k z
Facets:
Source sentences:
text: 2}\times \mathrm {C} _{2},} is the 2-torsion subgroup (so ( Z / 2 k Z ) × {\displaystyle (\mathbb {Z} /2^{k}\mathbb {Z} )^{\times }} is not cyclic) and the powers of 3 are a cyclic subgroup of order 2k − 2, so ( Z / 2 k Z ) × ≅ C 2 × C 2