Assertion: abelian group's element | /r/HasProperty | a 2n – 1
Facets:
Source sentences:
text: Since in a group every element has its unique inverse and since there are odd number of elements a 1 , a 2 , …, a 2n – 1 none of which is the identity element of G, it follows that there is one element a (say) among a 1 , a 2 , …, a 2n – 1 whose inverse is a itself.