Assertion: abelian group's subgroup | /r/CreatedBy | normal subgroups
Facets:
Source sentences:
text: = xN, for all x G, is a homomorphism, and ker( ) = N. (b) There is a one-to-one correspondence between subgroups of G/N and subgroups of G that contain N. Under this correspondence, normal subgroups correspond to normal subgroups.