  Though the neutron mass is larger than the proton mass and obviously one
expects in $e^+e^-$ annihilation a creation of more $p \bar p$ pairs in
comparison with $n \bar n$ at the same energy, just the opposite inequality for
the corresponding total cross sections $\sigma_{tot}(e^+e^- \to n \bar n) >
\sigma_{tot}(e^+e^- \to p \bar p)$ has been revealed in the analysis of only
the present time existing proton electromagnetic form factors data by the
unitary and analytic approach.
