  In this work, we explore the implications of the narrower state
$Z_{cs}(3985)$ in BESIII and the wider state $Z_{cs}(4000)$ in LHCb as two
different states. We treat them as two $|\bar{D}_sD^*/\bar{D}_s^*D\rangle$
di-meson resonances with different hadronic components in a solvable
nonrelativistic effective field theory. We include the possible violations of
heavy quark spin symmetry and SU(3) flavor symmetry. Treating them as two
states, our results show that $Z_{cs}(4000)$ is the pure
$(|\bar{D}_s^*D\rangle+ |\bar{D}_sD^*\rangle)/\sqrt{2}$ state, which is the
partner of $Z_{c}(3900)$ in the SU(3) flavor symmetry limit. The $Z_{cs}(3985)$
is the $(|\bar{D}_s^*D\rangle -|\bar{D}_sD^*\rangle)/\sqrt{2}$ state. Our
calculations also imply the existence of a tensor $\bar{D}_s^*D^*$ resonance as
the heavy quark spin symmetry partner of the $Z_{cs}(3985)$ state. Its mass and
decay width are $4126$ MeV and $13$ MeV, respectively. Meanwhile, the decay
$Z_{cs}(3985)\to J/\psi K $ is suppressed by the heavy quark spin symmetry.
Searching for the tensor $\bar{D}_s^*D^*$ state and the $Z_{cs}(3985) \to
J/\psi K$ decay mode in experiments would be helpful to test the prerequisite
that $Z_{cs}(3985)$ and $Z_{cs}(4000)$ are two different states.
