Question: how many moles of atoms are there in 28 g of nitrogen n2?
Answer: Thankyou! 12.04 ×10²³ atoms are present in 28 g of nitrogen. As in 28 g of nitrogen 2 moles are present and in one mole 6.02 × 10²³ atoms. Now,14 g=6.02 × 10^23 mol.