Question: two unbiased dice are thrown. find the probability?
Answer: Probability of an event = Number of outcomes favourable to that event/ Number of all possible outcomes. ... We have 11 desired outcomes. So n(E) = 12. Hence the probability of getting sum of the scores which is neither a multiple of 2 nor a multiple of 3 = n(E)/ n(S) = 12/36 = 1/3.