Question: how many electrons are present in 1.8 ml of water?
Answer: 1 molecule of H2O contains 10electrons. So one mole that is equal to 22.4 L of H2O will contain 6.022 ×10^23 × 10 electrons. So 1.8 ml will have - 6.022×10^23×1.8×10/22.4 ×1000=6.022×10^21×1.8/22.4.