Question: what is the equation of the line perpendicular to 2x-3y=13?
Answer: Answer Expert Verified 2x - 3y = 13, when solved for -3y, results in -3y = -2x + 13. Then y = (2/3)x + C. Any line perpendicular to this y = (2/3)x + C has the slope which is the negative reciprocal of (2/3); that slope is -3/2.