Question: can e ever be 0?
Answer: Since the base, which is the irrational number e = 2.718 (rounded to 3 decimal places), is a positive real number, i.e., e is greater than zero, then the range of f, y = f(x) = e^x, is the set of all POSITIVE (emphasis, mine) real numbers; therefore, e^x can never equal zero (0) even though as x approaches negative ...