Question: what is the standard enthalpy of formation of liquid methanol?
Answer: Calculate the standard enthalpy of formation of liquid methanol, CH3OH(l), using the following information: C(graph) + O2 → CO2(g) H° = –393.5 kJ/mol H2(g) + (1/2)O2 → H2O(l) H° = –285.8 kJ/mol CH3OH(l) + (3/2)O2(g) → CO2(g) + 2H2O(l) H° = –726.4 kJ/mol.