Subrectangle Queries
Tags: leetcode, dsa, theabbie
Published: 2022-06-09 23:00:43

Implement the class `SubrectangleQueries` which receives a `rows x cols` rectangle as a matrix of integers in the constructor and supports two methods:

1. `updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)`

*   Updates all values with `newValue` in the subrectangle whose upper left coordinate is `(row1,col1)` and bottom right coordinate is `(row2,col2)`.

2. `getValue(int row, int col)`

*   Returns the current value of the coordinate `(row,col)` from the rectangle.

**Example 1:**

**Input**
\["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"\]
\[\[\[\[1,2,1\],\[4,3,4\],\[3,2,1\],\[1,1,1\]\]\],\[0,2\],\[0,0,3,2,5\],\[0,2\],\[3,1\],\[3,0,3,2,10\],\[3,1\],\[0,2\]\]
**Output**
\[null,1,null,5,5,null,10,5\]
**Explanation**
SubrectangleQueries subrectangleQueries = new SubrectangleQueries(\[\[1,2,1\],\[4,3,4\],\[3,2,1\],\[1,1,1\]\]);  
// The initial rectangle (4x3) looks like:
// 1 2 1
// 4 3 4
// 3 2 1
// 1 1 1
subrectangleQueries.getValue(0, 2); // return 1
subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);
// After this update the rectangle looks like:
// 5 5 5
// 5 5 5
// 5 5 5
// 5 5 5 
subrectangleQueries.getValue(0, 2); // return 5
subrectangleQueries.getValue(3, 1); // return 5
subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);
// After this update the rectangle looks like:
// 5   5   5
// 5   5   5
// 5   5   5
// 10  10  10 
subrectangleQueries.getValue(3, 1); // return 10
subrectangleQueries.getValue(0, 2); // return 5

**Example 2:**

**Input**
\["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"\]
\[\[\[\[1,1,1\],\[2,2,2\],\[3,3,3\]\]\],\[0,0\],\[0,0,2,2,100\],\[0,0\],\[2,2\],\[1,1,2,2,20\],\[2,2\]\]
**Output**
\[null,1,null,100,100,null,20\]
**Explanation**
SubrectangleQueries subrectangleQueries = new SubrectangleQueries(\[\[1,1,1\],\[2,2,2\],\[3,3,3\]\]);
subrectangleQueries.getValue(0, 0); // return 1
subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);
subrectangleQueries.getValue(0, 0); // return 100
subrectangleQueries.getValue(2, 2); // return 100
subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);
subrectangleQueries.getValue(2, 2); // return 20

**Constraints:**

*   There will be at most `500` operations considering both methods: `updateSubrectangle` and `getValue`.
*   `1 <= rows, cols <= 100`
*   `rows == rectangle.length`
*   `cols == rectangle[i].length`
*   `0 <= row1 <= row2 < rows`
*   `0 <= col1 <= col2 < cols`
*   `1 <= newValue, rectangle[i][j] <= 10^9`
*   `0 <= row < rows`
*   `0 <= col < cols`

**SOLUTION:**

    class SubrectangleQueries:
    
        def __init__(self, rectangle: List[List[int]]):
            self.rec = rectangle
    
        def updateSubrectangle(self, row1: int, col1: int, row2: int, col2: int, newValue: int) -> None:
            for i in range(row1, row2 + 1):
                for j in range(col1, col2 + 1):
                    self.rec[i][j] = newValue
    
        def getValue(self, row: int, col: int) -> int:
            return self.rec[row][col]
    
    
    # Your SubrectangleQueries object will be instantiated and called as such:
    # obj = SubrectangleQueries(rectangle)
    # obj.updateSubrectangle(row1,col1,row2,col2,newValue)
    # param_2 = obj.getValue(row,col)