target-benchmark/spider-queries huggingface dataset:
Database: company_office (tables: companies)
Question: Which industries have both companies with headquarter in "USA" and companies with headquarter in "China"?
SQL: SELECT Industry FROM Companies WHERE Headquarters  =  "USA" INTERSECT SELECT Industry FROM Companies WHERE Headquarters  =  "China"
Database: company_office (tables: companies)
Question: Find the number of companies whose industry is "Banking" or "Conglomerate",
SQL: SELECT count(*) FROM Companies WHERE Industry  =  "Banking" OR Industry  =  "Conglomerate"
Database: company_office (tables: companies)
Question: How many companies are in either "Banking" industry or "Conglomerate" industry?
SQL: SELECT count(*) FROM Companies WHERE Industry  =  "Banking" OR Industry  =  "Conglomerate"
Database: company_office (tables: companies)
Question: Show the headquarters shared by more than two companies.
SQL: SELECT Headquarters FROM Companies GROUP BY Headquarters HAVING COUNT(*)  >  2
Database: company_office (tables: companies)
Question: Which headquarter locations are used by more than 2 companies?
SQL: SELECT Headquarters FROM Companies GROUP BY Headquarters HAVING COUNT(*)  >  2
Database: solvency_ii (tables: products)
Question: How many products are there?
SQL: SELECT count(*) FROM Products
Database: solvency_ii (tables: products)
Question: List the name of products in ascending order of price.
SQL: SELECT Product_Name FROM Products ORDER BY Product_Price ASC
Database: solvency_ii (tables: products)
Question: What are the names and type codes of products?
SQL: SELECT Product_Name ,  Product_Type_Code FROM Products
Database: solvency_ii (tables: products)
Question: Show the prices of the products named "Dining" or "Trading Policy".
SQL: SELECT Product_Price FROM Products WHERE Product_Name  =  "Dining" OR Product_Name  =  "Trading Policy"
Database: solvency_ii (tables: products)
Question: What is the average price for products?
SQL: SELECT avg(Product_Price) FROM Products
Database: solvency_ii (tables: products)
Question: What is the name of the product with the highest price?
SQL: SELECT Product_Name FROM Products ORDER BY Product_Price DESC LIMIT 1
Database: solvency_ii (tables: products)
Question: Show different type codes of products and the number of products with each type code.
SQL: SELECT Product_Type_Code ,  COUNT(*) FROM Products GROUP BY Product_Type_Code
Database: solvency_ii (tables: products)
Question: Show the most common type code across products.
SQL: SELECT Product_Type_Code FROM Products GROUP BY Product_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
Database: solvency_ii (tables: products)
Question: Show the product type codes that have at least two products.
SQL: SELECT Product_Type_Code FROM Products GROUP BY Product_Type_Code HAVING COUNT(*)  >=  2
Database: solvency_ii (tables: products)
Question: Show the product type codes that have both products with price higher than 4500 and products with price lower than 3000.
SQL: SELECT Product_Type_Code FROM Products WHERE Product_Price  >  4500 INTERSECT SELECT Product_Type_Code FROM Products WHERE Product_Price  <  3000
Database: solvency_ii (tables: products_in_events, products)
Question: Show the names of products and the number of events they are in.
SQL: SELECT T1.Product_Name ,  COUNT(*) FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name
Database: solvency_ii (tables: products_in_events, products)
Question: Show the names of products and the number of events they are in, sorted by the number of events in descending order.
SQL: SELECT T1.Product_Name ,  COUNT(*) FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name ORDER BY COUNT(*) DESC
Database: solvency_ii (tables: products_in_events, products)
Question: Show the names of products that are in at least two events.
SQL: SELECT T1.Product_Name FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name HAVING COUNT(*)  >=  2
Database: solvency_ii (tables: products_in_events, products)
Question: Show the names of products that are in at least two events in ascending alphabetical order of product name.
SQL: SELECT T1.Product_Name FROM Products AS T1 JOIN Products_in_Events AS T2 ON T1.Product_ID  =  T2.Product_ID GROUP BY T1.Product_Name HAVING COUNT(*)  >=  2 ORDER BY T1.Product_Name
Database: solvency_ii (tables: products, products_in_events)
Question: List the names of products that are not in any event.
SQL: SELECT Product_Name FROM Products WHERE Product_ID NOT IN (SELECT Product_ID FROM Products_in_Events)
Database: entertainment_awards (tables: artwork)
Question: How many artworks are there?
SQL: SELECT count(*) FROM artwork
Database: entertainment_awards (tables: artwork)
Question: List the name of artworks in ascending alphabetical order.
SQL: SELECT Name FROM artwork ORDER BY Name ASC
Database: entertainment_awards (tables: artwork)
Question: List the name of artworks whose type is not "Program Talent Show".
SQL: SELECT Name FROM artwork WHERE TYPE != "Program Talent Show"
Database: entertainment_awards (tables: festival_detail)
Question: What are the names and locations of festivals?
SQL: SELECT Festival_Name ,  LOCATION FROM festival_detail
Database: entertainment_awards (tables: festival_detail)
Question: What are the names of the chairs of festivals, sorted in ascending order of the year held?
SQL: SELECT Chair_Name FROM festival_detail ORDER BY YEAR ASC
Database: entertainment_awards (tables: festival_detail)
Question: What is the location of the festival with the largest number of audience?
SQL: SELECT LOCATION FROM festival_detail ORDER BY Num_of_Audience DESC LIMIT 1
Database: entertainment_awards (tables: festival_detail)
Question: What are the names of festivals held in year 2007?
SQL: SELECT Festival_Name FROM festival_detail WHERE YEAR  =  2007
Database: entertainment_awards (tables: festival_detail)
Question: What is the average number of audience for festivals?
SQL: SELECT avg(Num_of_Audience) FROM festival_detail
Database: entertainment_awards (tables: festival_detail)
Question: Show the names of the three most recent festivals.
SQL: SELECT Festival_Name FROM festival_detail ORDER BY YEAR DESC LIMIT 3
Database: entertainment_awards (tables: festival_detail, artwork, nomination)
Question: For each nomination, show the name of the artwork and name of the festival where it is nominated.
SQL: SELECT T2.Name ,  T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID
Database: entertainment_awards (tables: festival_detail, artwork, nomination)
Question: Show distinct types of artworks that are nominated in festivals in 2007.
SQL: SELECT DISTINCT T2.Type FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID WHERE T3.Year  =  2007
Database: entertainment_awards (tables: festival_detail, artwork, nomination)
Question: Show the names of artworks in ascending order of the year they are nominated in.
SQL: SELECT T2.Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID ORDER BY T3.Year
Database: entertainment_awards (tables: festival_detail, artwork, nomination)
Question: Show the names of festivals that have nominated artworks of type "Program Talent Show".
SQL: SELECT T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID WHERE T2.Type  =  "Program Talent Show"
Database: entertainment_awards (tables: festival_detail, artwork, nomination)
Question: Show the ids and names of festivals that have at least two nominations for artworks.
SQL: SELECT T1.Festival_ID ,  T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID GROUP BY T1.Festival_ID HAVING COUNT(*)  >=  2
Database: entertainment_awards (tables: festival_detail, artwork, nomination)
Question: Show the id, name of each festival and the number of artworks it has nominated.
SQL: SELECT T1.Festival_ID ,  T3.Festival_Name ,  COUNT(*) FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID  =  T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID  =  T3.Festival_ID GROUP BY T1.Festival_ID
Database: entertainment_awards (tables: artwork)
Question: Please show different types of artworks with the corresponding number of artworks of each type.
SQL: SELECT TYPE ,  COUNT(*) FROM artwork GROUP BY TYPE
Database: entertainment_awards (tables: artwork)
Question: List the most common type of artworks.
SQL: SELECT TYPE FROM artwork GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
Database: entertainment_awards (tables: festival_detail)
Question: List the year in which there are more than one festivals.
SQL: SELECT YEAR FROM festival_detail GROUP BY YEAR HAVING COUNT(*)  >  1
Database: entertainment_awards (tables: artwork, nomination)
Question: List the name of artworks that are not nominated.
SQL: SELECT Name FROM Artwork WHERE Artwork_ID NOT IN (SELECT Artwork_ID FROM nomination)
Database: entertainment_awards (tables: festival_detail)
Question: Show the number of audience in year 2008 or 2010.
SQL: SELECT Num_of_Audience FROM festival_detail WHERE YEAR  =  2008 OR YEAR  =  2010
Database: entertainment_awards (tables: festival_detail)
Question: What are the total number of the audiences who visited any of the festivals?
SQL: SELECT sum(Num_of_Audience) FROM festival_detail
Database: entertainment_awards (tables: festival_detail)
Question: In which year are there festivals both inside the 'United States' and outside the 'United States'?
SQL: SELECT YEAR FROM festival_detail WHERE LOCATION  =  'United States' INTERSECT SELECT YEAR FROM festival_detail WHERE LOCATION != 'United States'
Database: customers_campaigns_ecommerce (tables: premises)
Question: How many premises are there?
SQL: SELECT count(*) FROM premises
Database: customers_campaigns_ecommerce (tables: premises)
Question: What are all the distinct premise types?
SQL: SELECT DISTINCT premises_type FROM premises
Database: customers_campaigns_ecommerce (tables: premises)
Question: Find the types and details for all premises and order by the premise type.
SQL: SELECT premises_type ,  premise_details FROM premises ORDER BY premises_type
Database: customers_campaigns_ecommerce (tables: premises)
Question: Show each premise type and the number of premises in that type.
SQL: SELECT premises_type ,  count(*) FROM premises GROUP BY premises_type
Database: customers_campaigns_ecommerce (tables: mailshot_campaigns)
Question: Show all distinct product categories along with the number of mailshots in each category.
SQL: SELECT product_category ,  count(*) FROM mailshot_campaigns GROUP BY product_category
Database: customers_campaigns_ecommerce (tables: customers, mailshot_customers)
Question: Show the name and phone of the customer without any mailshot.
SQL: SELECT customer_name ,  customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM mailshot_customers)
Database: customers_campaigns_ecommerce (tables: mailshot_customers, customers)
Question: Show the name and phone for customers with a mailshot with outcome code 'No Response'.
SQL: SELECT T1.customer_name ,  T1.customer_phone FROM customers AS T1 JOIN mailshot_customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE T2.outcome_code  =  'No Response'
Database: customers_campaigns_ecommerce (tables: mailshot_customers)
Question: Show the outcome code of mailshots along with the number of mailshots in each outcome code.
SQL: SELECT outcome_code ,  count(*) FROM mailshot_customers GROUP BY outcome_code
Database: customers_campaigns_ecommerce (tables: customers, mailshot_customers)
Question: Show the names of customers who have at least 2 mailshots with outcome code 'Order'.
SQL: SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE outcome_code  =  'Order' GROUP BY T1.customer_id HAVING count(*)  >=  2
Database: customers_campaigns_ecommerce (tables: customers, mailshot_customers)
Question: Show the names of customers who have the most mailshots.
SQL: SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
Database: customers_campaigns_ecommerce (tables: customers, mailshot_customers)
Question: What are the name and payment method of customers who have both mailshots in 'Order' outcome and mailshots in 'No Response' outcome.
SQL: SELECT T2.customer_name ,  T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE T1.outcome_code  =  'Order' INTERSECT SELECT T2.customer_name ,  T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id  =  T2.customer_id WHERE T1.outcome_code  =  'No Response'
Database: customers_campaigns_ecommerce (tables: customer_addresses, premises)
Question: Show the premise type and address type code for all customer addresses.
SQL: SELECT T2.premises_type ,  T1.address_type_code FROM customer_addresses AS T1 JOIN premises AS T2 ON T1.premise_id  =  T2.premise_id
Database: customers_campaigns_ecommerce (tables: customer_addresses)
Question: What are the distinct address type codes for all customer addresses?
SQL: SELECT DISTINCT address_type_code FROM customer_addresses
Database: customers_campaigns_ecommerce (tables: customer_orders)
Question: Show the shipping charge and customer id for customer orders with order status Cancelled or Paid.
SQL: SELECT order_shipping_charges ,  customer_id FROM customer_orders WHERE order_status_code  =  'Cancelled' OR order_status_code  =  'Paid'
Database: customers_campaigns_ecommerce (tables: customer_orders, customers)
Question: Show the names of customers having an order with shipping method FedEx and order status Paid.
SQL: SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id  =  T2.customer_id WHERE shipping_method_code  =  'FedEx' AND order_status_code  =  'Paid'
Database: college_3 (tables: course)
Question: How many courses are there in total?
SQL: SELECT count(*) FROM COURSE
Database: college_3 (tables: course)
Question: Count the number of courses.
SQL: SELECT count(*) FROM COURSE
Database: college_3 (tables: course)
Question: How many courses have more than 2 credits?
SQL: SELECT count(*) FROM COURSE WHERE Credits  >  2
Database: college_3 (tables: course)
Question: Count the number of courses with more than 2 credits.
SQL: SELECT count(*) FROM COURSE WHERE Credits  >  2
Database: college_3 (tables: course)
Question: List all names of courses with 1 credit?
SQL: SELECT CName FROM COURSE WHERE Credits  =  1
Database: college_3 (tables: course)
Question: What are the names of courses with 1 credit?
SQL: SELECT CName FROM COURSE WHERE Credits  =  1
Database: college_3 (tables: course)
Question: Which courses are taught on days MTW?
SQL: SELECT CName FROM COURSE WHERE Days  =  "MTW"
Database: college_3 (tables: course)
Question: What are the course names for courses taught on MTW?
SQL: SELECT CName FROM COURSE WHERE Days  =  "MTW"
Database: college_3 (tables: department)
Question: What is the number of departments in Division "AS"?
SQL: SELECT count(*) FROM DEPARTMENT WHERE Division  =  "AS"
Database: college_3 (tables: department)
Question: How many departments are in the division AS?
SQL: SELECT count(*) FROM DEPARTMENT WHERE Division  =  "AS"
Database: college_3 (tables: department)
Question: What are the phones of departments in Room 268?
SQL: SELECT DPhone FROM DEPARTMENT WHERE Room  =  268
Database: college_3 (tables: department)
Question: Give the phones for departments in room 268.
SQL: SELECT DPhone FROM DEPARTMENT WHERE Room  =  268
Database: college_3 (tables: enrolled_in)
Question: Find the number of students that have at least one grade "B".
SQL: SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade  =  "B"
Database: college_3 (tables: enrolled_in)
Question: How many students have had at least one "B" grade?
SQL: SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade  =  "B"
Database: college_3 (tables: gradeconversion)
Question: Find the max and min grade point for all letter grade.
SQL: SELECT max(gradepoint) ,  min(gradepoint) FROM GRADECONVERSION
Database: college_3 (tables: gradeconversion)
Question: What are the maximum and minumum grade points?
SQL: SELECT max(gradepoint) ,  min(gradepoint) FROM GRADECONVERSION
Database: college_3 (tables: student)
Question: Find the first names of students whose first names contain letter "a".
SQL: SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%'
Database: college_3 (tables: student)
Question: What are the first names for students who have an "a" in their first name?
SQL: SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%'
Database: college_3 (tables: faculty)
Question: Find the first names and last names of male (sex is M) faculties who live in building NEB.
SQL: SELECT Fname ,  Lname FROM FACULTY WHERE sex  =  "M" AND Building  =  "NEB"
Database: college_3 (tables: faculty)
Question: What are the full names of faculties with sex M and who live in building NEB?
SQL: SELECT Fname ,  Lname FROM FACULTY WHERE sex  =  "M" AND Building  =  "NEB"
Database: college_3 (tables: faculty)
Question: Find the rooms of faculties with rank professor who live in building NEB.
SQL: SELECT Room FROM FACULTY WHERE Rank  =  "Professor" AND Building  =  "NEB"
Database: college_3 (tables: faculty)
Question: What are the rooms for members of the faculty who are professors and who live in building NEB?
SQL: SELECT Room FROM FACULTY WHERE Rank  =  "Professor" AND Building  =  "NEB"
Database: college_3 (tables: department)
Question: Find the department name that is in Building "Mergenthaler".
SQL: SELECT DName FROM DEPARTMENT WHERE Building  =  "Mergenthaler"
Database: college_3 (tables: department)
Question: What is the name of the department in the Building Mergenthaler?
SQL: SELECT DName FROM DEPARTMENT WHERE Building  =  "Mergenthaler"
Database: college_3 (tables: course)
Question: List all information about courses sorted by credits in the ascending order.
SQL: SELECT * FROM COURSE ORDER BY Credits
Database: college_3 (tables: course)
Question: What is all the information about courses, ordered by credits ascending?
SQL: SELECT * FROM COURSE ORDER BY Credits
Database: college_3 (tables: course)
Question: List the course name of courses sorted by credits.
SQL: SELECT CName FROM COURSE ORDER BY Credits
Database: college_3 (tables: course)
Question: What are the course names, ordered by credits?
SQL: SELECT CName FROM COURSE ORDER BY Credits
Database: college_3 (tables: student)
Question: Find the first name of students in the descending order of age.
SQL: SELECT Fname FROM STUDENT ORDER BY Age DESC
Database: college_3 (tables: student)
Question: What are the first names of students, ordered by age from greatest to least?
SQL: SELECT Fname FROM STUDENT ORDER BY Age DESC
Database: college_3 (tables: student)
Question: Find the last name of female (sex is F) students in the descending order of age.
SQL: SELECT LName FROM STUDENT WHERE Sex  =  "F" ORDER BY Age DESC
Database: college_3 (tables: student)
Question: What are the last names of female students, ordered by age descending?
SQL: SELECT LName FROM STUDENT WHERE Sex  =  "F" ORDER BY Age DESC
Database: college_3 (tables: faculty)
Question: Find the last names of faculties in building Barton in alphabetic order.
SQL: SELECT Lname FROM FACULTY WHERE Building  =  "Barton" ORDER BY Lname
Database: college_3 (tables: faculty)
Question: What are the last names of faculty in building Barton, sorted by last name?
SQL: SELECT Lname FROM FACULTY WHERE Building  =  "Barton" ORDER BY Lname
Database: college_3 (tables: faculty)
Question: Find the first names of faculties of rank Professor in alphabetic order.
SQL: SELECT Fname FROM FACULTY WHERE Rank  =  "Professor" ORDER BY Fname
Database: college_3 (tables: faculty)
Question: What are the first names for all faculty professors, ordered by first name?
SQL: SELECT Fname FROM FACULTY WHERE Rank  =  "Professor" ORDER BY Fname
Database: college_3 (tables: department, minor_in)
Question: Find the name of the department that has the biggest number of students minored in?
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
Database: college_3 (tables: department, minor_in)
Question: What is the name of the department with the most students minoring in it?
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
Database: college_3 (tables: department, minor_in)
Question: Find the name of the department that has no students minored in?
SQL: SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO
Database: college_3 (tables: department, minor_in)
Question: What is the name of the department htat has no students minoring in it?
SQL: SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO  =  T2.DNO
Database: college_3 (tables: department, member_of)
Question: Find the name of the department that has the fewest members.
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
Database: college_3 (tables: department, member_of)
Question: What is the name of the department with the fewest members?
SQL: SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO  =  T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
Database: college_3 (tables: faculty)
Question: Find the rank of the faculty that the fewest faculties belong to.
SQL: SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
Database: college_3 (tables: faculty)
Question: What is the least common faculty rank?
SQL: SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
Database: college_3 (tables: course, faculty)
Question: What are the first and last names of the instructors who teach the top 3 number of courses?
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Database: college_3 (tables: course, faculty)
Question: What are the full names of the 3 instructors who teach the most courses?
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Database: college_3 (tables: course, faculty)
Question: Which building does the instructor who teaches the most number of courses live in?
SQL: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Database: college_3 (tables: course, faculty)
Question: Give the building that the instructor who teaches the greatest number of courses lives in.
SQL: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Database: college_3 (tables: course, enrolled_in)
Question: What are the name of courses that have at least five enrollments?
SQL: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Database: college_3 (tables: course, enrolled_in)
Question: Give the names of the courses with at least five enrollments.
SQL: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Database: college_3 (tables: course, faculty)
Question: Find the first name and last name of the instructor of course that has course name
SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"