Exercícios de potenciação – 9os Anos
Autor: Marcos Pontes | Publicado: 2017-02-16T14:14:00-03:00


Exercícios de potenciação – 9os Anos



<!--[if !supportLists]-->1)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->Calcule
as seguintes potências:

<!--[if !supportLists]-->a)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->3
4 =

<!--[if !supportLists]-->b)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->2
5 =

<!--[if !supportLists]-->c)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->1
4 =

<!--[if !supportLists]-->d)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->0
6 =

<!--[if !supportLists]-->e)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(-2)
4 = 

f)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 5
0 =

g)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
<!--[endif]-->(2,43) 0 =

h)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
<!--[endif]-->(-0,5) 0 =

i)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->17¹
=

j)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
<!--[endif]-->(1,45) ¹ =

k)&nbsp;&nbsp;&nbsp; <!--[endif]-->(-5)
¹ =

l)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 3
-1 =

m)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(-3)
-2 =

n)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->2
– 4 =

o)&nbsp;&nbsp;&nbsp; (-0,75)
-2 =



<!--[if !supportLists]-->2)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->Neste
exercício é importante ir observando os resultados após os cálculos!!! Portanto,
resolva:

<!--[if !supportLists]-->a)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->2
6 =

<!--[if !supportLists]-->b)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(-2)
6 =

<!--[if !supportLists]-->c)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->2
5 =

<!--[if !supportLists]-->d)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(-2)
5 =

<!--[if !supportLists]-->e)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->3²
=

<!--[if !supportLists]-->f)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(-3)
² =

<!--[if !supportLists]-->g)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->3³
=

<!--[if !supportLists]-->h)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(-3)³
=

<!--[if !supportLists]-->i)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
<!--[endif]-->(-4) -1 =



<!--[if !supportLists]-->3)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->Para
resolver as potências a seguir é preciso fazer cada cálculo passo a passo,
evitando assim erros com sinais:

<!--[if !supportLists]-->a)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->-2
³ =

<!--[if !supportLists]-->b)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->-3²
=

<!--[if !supportLists]-->c)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->-4³
=

<!--[if !supportLists]-->d)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->-5³
=

<!--[if !supportLists]-->e)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->-5²
=

<!--[if !supportLists]-->f)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->–
(-2)³ =

<!--[if !supportLists]-->g)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->–
(-3)² =

<!--[if !supportLists]-->h)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->–
(-5)² =





4) Coloque V (verdadeiro) ou F
(falso):

Para resolver este exercício é importante conhecer muito bem as propriedades
da potência.

(&nbsp;&nbsp;&nbsp;&nbsp; ) 5 – 6
. 5 6 = 1

(&nbsp;&nbsp;&nbsp;&nbsp; ) 6 -2 .
6 -5 = 6 10

(&nbsp;&nbsp;&nbsp;&nbsp; ) 7³ : 7 5
= 7 -5 . 7³

(&nbsp;&nbsp;&nbsp;&nbsp; ) 2 5
: 2³ = 1²

(&nbsp;&nbsp;&nbsp;&nbsp; ) 3³ . 3 5
= 9 8 

(&nbsp; &nbsp;&nbsp;&nbsp;) (p
+ 3) -2 = p
-2 + 3 -2

(&nbsp;&nbsp;&nbsp;&nbsp; ) 7² + 7³ = 7 5

(&nbsp;&nbsp;&nbsp;&nbsp; ) (3 5)²
= 3 7



5) Simplifique as expressões, usando sempre que possível as
propriedades da potência:

<!--[if !supportLists]-->a)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(2xy²)³
=

<!--[if !supportLists]-->b)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(3xy²)
. (2x²y³) =

<!--[if !supportLists]-->c)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <!--[endif]-->(5ab²)²
. (a²b)³ =