TESTE DO 3º BIMESTRE DE 2014 PARA OS 1ºS ANOS - MANHÃ, TARDE E NOITE
Autor: BONIFACIO MATEMÁTICA | Publicado: 2014-09-10T16:55:00-07:00


ESC.
EST.&nbsp; GILNEY DE SOUZA – EM. INOVADOR,
DIFERENCIADO E EJA&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;SÃO MIGUEL/RN, 3º bimestre/ 2014 –
AVALIAÇÃO DE MATEMÁTICA. 

TESTE DO 3º BIMESTRE DE 2014 – PROF: JOSÉ BONIFÁCIO
BEZERRA

01)&nbsp;Determine 25% de 160.

RESPOSTA: ­­­25/100*160 =&gt;
0,25*160 = 40

02)&nbsp;Determine 8% de 500.

RESPOSTA: 8/100*500 =&gt; 0,08*500 = 40

03)&nbsp;Determine 15% de 150.

RESPOSTA: 15/100*150 =&gt;
0,15*150 = 22,5

04)&nbsp;O número 8 representa
qual porcentagem de 200? 

RESPOSTA: x/100*200 = 8 =&gt;
0,2x = 8 =&gt; x = 8:0, 2 =&gt; x = 4%

05)&nbsp;O número 12
representa qual porcentagem de 800? 

RESPOSTA: : x/100*800 = 12 =&gt; 0,8x
= 12 =&gt; x = 12:0, 8 =&gt; x = 1,5%

06)&nbsp;Se 65% dos 40 alunos
do 8° ano de um colégio são homens, quantas são as mulheres?

RESPOSTA: 100% - 65% = 35%, Então
35 % corresponde a quantidade de mulheres. 35/100*40 = 0,35*40 = 14 = 14 mulheres.

07)&nbsp;Uma bicicleta,
cujo preço é R$ 1200,00, pode ser comprada da seguinte maneira:

<!--[if !supportLists]-->a)&nbsp; <!--[endif]-->a vista, com 20% de
desconto.&nbsp;RESPOSTA: 20/100*1200 =
0,20*1200 = 240,00, então: 1200 – 240 = 960,00
pagamento para 90 dias, com acréscimo de 15% sobre o preço
inicial.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; RESPOSTA: 15/100*1200 = 0,15*1200 = 180,00, preço
atual 1200 +180 = 1380,00

<!--[if !supportLists]-->b)&nbsp;
<!--[endif]-->Responda: Qual é a diferença, em reais, entre as duas opções de compra?
RESPOSTA: 1380,00 - 960,00 = 420,00

08)&nbsp;Na compra de um aparelho obtive
desconto de 15% por ter feito o pagamento à vista. Se paguei R$ 102,00 reais
pelo aparelho, qual era o seu preço original? RESPOSTA: 100% - 15% = 85%, então: 85/100*x=102&nbsp; 0,85x=102 =&gt; x = 120

09)&nbsp;(CASA0902/10-AgApoioOper(Motorista)
– 2012) – Uma fundação que cuida de crianças abandonadas conseguiu, em janeiro,
encaminhar 72 crianças para adoção, o que representa 60% das crianças da
fundação. Pode-se concluir que o número de crianças dessa fundação que não
foram encaminhadas é

   

    <!--[endif]-->
    


60%&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 72&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 60x = 40*72

40%&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; x&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 60x = 2880 então&nbsp; x = 2880: 60, x = 48 crianças

<!--[if !mso]-->
   



 
 
<v:shape id="Caixa_x0020_de_x0020_Texto_x0020_2" o:gfxdata="UEsDBBQABgAIAAAAIQC75UiUBQEAAB4CAAATAAAAW0NvbnRlbnRfVHlwZXNdLnhtbKSRvU7DMBSF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=
" o:spid="_x0000_s1027" style="height: 60.3pt; margin-left: 61.85pt; margin-top: 6.7pt; mso-height-percent: 0; mso-height-percent: 0; mso-height-relative: margin; mso-position-horizontal-relative: text; mso-position-horizontal: absolute; mso-position-vertical-relative: text; mso-position-vertical: absolute; mso-width-percent: 0; mso-width-percent: 0; mso-width-relative: margin; mso-wrap-distance-bottom: 0; mso-wrap-distance-left: 9pt; mso-wrap-distance-right: 9pt; mso-wrap-distance-top: 0; mso-wrap-style: square; position: absolute; v-text-anchor: top; visibility: visible; width: 301.05pt; z-index: 251659264;" type="#_x0000_t202">
 
  <!--[if !mso]-->
  
  <!--[endif]-->
&nbsp;

&nbsp;(A) 44.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
(B) 36.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (C) 47.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (D) 48.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;(E) 52.

10)&nbsp;(VNSP1201/003-AssistAdmin-I 2012) – Um
arquiteto projetou uma Escola Infantil, utilizando 45% da área total do terreno
para o prédio que continha as salas de aula e 15% para as salas de projeção,
biblioteca e laboratórios. Mesmo assim, sobrou uma área de 900 m² para
ambientes de lazer. Podemos concluir que o terreno tinha um total, em m², de:

   

    <!--[endif]-->
    


45% + 15% = 60% (salas de
    aulas, sala de projeção, biblioteca e laboratórios e 40 % que corresponde a
    900 m2 ( lazer)

60%&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; x

40%&nbsp;&nbsp;&nbsp;&nbsp; 900 m2 então 40x = 60*900 =
    40x= 54000 = x = 1350

60% = 1350 + 40% = 900,
    totalizando uma área de 1350 + 900 =2250
    m2



<!--[if !mso]-->
   




&nbsp;(A) 3 250. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(B) 3 000. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(C) 2 750. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(D) 2 450. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(E)
2 250.

11)&nbsp;Calcule
os JUROS, quando: Usando a fórmula J = (C.i.t )/100

<!--[if !supportLists]-->a)&nbsp;&nbsp;&nbsp; <!--[endif]-->C =
5.000,00,&nbsp; i = 3% ao mês e t = 1 ano&nbsp; Resp: J = 1800,00



<!--[if !supportLists]-->b)&nbsp;&nbsp;&nbsp; <!--[endif]-->C = 22.660,00,
i = 1,5% ao mês e t = 2 anos e 6 meses &nbsp;

Resp: J= 10197,00

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 

<!--[if !supportLists]-->c)&nbsp;&nbsp;&nbsp;
<!--[endif]-->C = 10.558,00, i = 60% ao ano e t = 6 meses &nbsp;Resp: J= 3167,40



<!--[if !supportLists]-->d)&nbsp;&nbsp;
<!--[endif]-->C = 1.200,00, i = 15% ao mês e t = &nbsp;1 ano e meio&nbsp;
Resp:&nbsp; J = 3 240,00



<!--[if !supportLists]-->e)&nbsp;&nbsp;&nbsp;
<!--[endif]-->C = 60.000,00, i = 0,05% ao mês e t = 3 anos&nbsp; Resp:&nbsp;&nbsp;&nbsp;
J = 1080,00



12)
Complete a tabela com o que falta:




 

  
LINHA

  
JUROS ( J )

  
CAPITAL (C )

  
TAXA ( I)

  
TEMPO (T)

 

  
01

  
45.000,00

  
R$
  50.000,00

  
3%
  a. m.

  
30
  meses

 

  
02

  
R$
  1.200,00

  
1000,00

  
0,5
  % a.m.

  
20
  anos

 

  
03

  
R$
  960,00

  
R$
  12.000,00

  
2 % a.a

  
04
  anos

 

  
04

  
R$
  1080,00

  
R$
  25.000,00

  
0,12
  % a.m.

  
36 meses

 





13) Tomando
por base a questão de Nº 12, determine o montante referente as linhas 01 e 04:

Linha 01 –
MONTANTE: R$ 50.000,00 + R$ 45.000,00 = R$ 95.000,00



Linha 04 –
MONTANTE: R$ 25.000,00 + R$ 1080,00 = R$ 26.080,00



16) Aplicando-se R$&nbsp;15.000,00 a
uma taxa de juro composto de 1,7% a.m., quanto receberei de volta após um ano
de aplicação? Qual o juro obtido neste período? Dado:
(1,017)12 = 1,224197 

Sugestão:
Use as fórmulas: M = P(1 +I)N
e&nbsp; J = M – C 

M =
15.000,00 x 1,224197 =&gt; M = 18.362,96



17) Complete as tabelas:


 

  
Multiplicação (x)

  
10

  
100

  
1000

  
10000

 

  
12,45

  
124,5

  
1245

  
12450

  
124500

 

  
0,12

  
1,2

  
12

  
120

  
1200

 

  
3,75

  
37,5

  
375

  
3750

  
37500

 

  
14,65

  
145,6

  
1465

  
14650

  
146500

 






 

  
Divisão (:)

  
10

  
100

  
1000

  
10000

 

  
12,45

  
1,245

  
0,1245

  
0,01245

  
0,001245

 

  
0,12

  
0,012

  
0,0012

  
0,00012

  
0,000012

 

  
3,75

  
0,375

  
0,0375

  
0,00375

  
0,000375

 

  
14,65

  
1,465

  
0,1465

  
0,01465

  
0,001465

 





&nbsp;Observação: Os rascunhos deverão estar
grampeados na folha da avaliação,&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
caso contrário ficará sem validade a avaliação.

Pois, se perdoarem as ofensas uns dos outros, o Pai celestial também
perdoará vocês. Mas, se não perdoarem uns aos outros, o Pai celestial não
perdoará as ofensas de vocês.&nbsp;
Mateus 6:14-15


&nbsp;Bom desempenho! J.B. B