TRABALHO DO 3º BIMESTRE DE 2014 PARA OS 1ºS ANOS DA MANHÃ, TARDE E NOITE
Autor: BONIFACIO MATEMÁTICA | Publicado: 2014-09-10T17:04:00-07:00


ESC.
EST.&nbsp; GILNEY DE SOUZA – EM. INOVADOR,
DIFERENCIADO E EJA&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;SÃO
MIGUEL/RN, __/__/ 2014 – AVALIAÇÃO DE MATEMÁTICA. 

ALUNO
(A):&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; CHAVE DE CORREÇÃO&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Nº
______

ALUNO
(A):_____________________________________&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Nº ______

SÉRIE:
_____TURMA: ________&nbsp;&nbsp; TURNO:
____________&nbsp;&nbsp; NOTA: ________



TRABALHO DO 3º BIMESTRE
DE 2014 – PROF: JOSÉ BONIFÁCIO BEZERRA

01)&nbsp;Determine 25% de 360.

RESPOSTA: 25:100*
360 = 90
02)&nbsp;Determine 8% de 550.

RESPOSTA: 8:100* 550 = 44&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 
03)&nbsp;Determine 15% de 150.

RESPOSTA: 15:100*150
= 22,5
04)&nbsp;O número 8 representa
qual porcentagem de 20? 

X:100*20
= 8&nbsp; É 40%
&nbsp; 05)&nbsp;O número 12 representa qual porcentagem
de 80? &nbsp;&nbsp;

X:100*80
= 80&nbsp; É 15%
06)&nbsp;Se 35% dos 40 alunos
do 8° ano de um colégio são homens, quantas são as mulheres?

35:100*40
= 14 HOMNES, ENTÃO: 40 – 14 = 26 MULHERES
07)&nbsp;Uma bicicleta, cujo preço é R$
1200,00, pode ser comprada da seguinte maneira:

a) a vista, com 15% de desconto.&nbsp;15:100*1200 = 180,00, então 1200 -180 = 1020,00

b) pagamento para 90 dias, com acréscimo de 25% sobre o preço
inicial.&nbsp;25:100*
1200 = 300,00 então 1200 + 300 = 1500,00

Responda: Qual é a diferença, em reais, entre as duas opções de compra?

A diferença é 1500
– 1020 = 480,00
08)&nbsp;Na compra de um aparelho obtive
desconto de 15% por ter feito o pagamento à vista. Se paguei R$ 102,00 reais
pelo aparelho, qual era o seu preço original? 100% - 15% = 85%, então 85:100 * x = 102,
então: 0,85x = 102

X
= 102 : 0,85 é igual a R$ 120,00
09)&nbsp;(CASA0902/10-AgApoioOper(Motorista)
– 2012) – Uma fundação que cuida de crianças abandonadas conseguiu, em janeiro,
encaminhar 72 crianças para adoção, o que representa 60% das crianças da
fundação. Pode-se concluir que o número de crianças dessa fundação que não
foram encaminhadas é



   

    <!--[endif]-->
    


60%&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 72&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 60x = 40*72

40%&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; x&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 60x = 2880 então&nbsp; x = 2880: 60, x = 48 crianças

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(A)
44.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;

(B)
46.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;

(C)
47.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;

(D) 48.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;

(E) 52.

10)&nbsp;(VNSP1201/003-AssistAdmin-I 2012) – Um
arquiteto projetou uma Escola Infantil, utilizando 45% da área total do terreno
para o prédio que continha as salas de aula e 15% para as salas de projeção,
biblioteca e laboratórios. Mesmo assim, sobrou uma área de 900 m² para
ambientes de lazer. Podemos concluir que o terreno tinha um total, em m², de

   

    <!--[endif]-->
    


45% + 15% = 60% (salas de
    aulas, sala de projeção, biblioteca e laboratórios e 40 % que corresponde a
    900 m2 ( lazer)

60%&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; x

40%&nbsp;&nbsp;&nbsp;&nbsp; 900 m2 então 40x = 60*900 =
    40x= 54000 = x = 1350

60% = 1350 + 40% = 900,
    totalizando uma área de 1350 + 900 =2250
    m2



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&nbsp;(A) 3 250.

(B) 3 000.

(C) 2 750.

(D) 2 450.

(E) 2 250.



11)&nbsp;Comprei
um novo computador, mas como não tinha o dinheiro todo, fiz um empréstimo para
pagá-lo. Ao final do empréstimo terei pago R$&nbsp;4.300,00. Só de juros
pagarei R$&nbsp;1.800,00. A taxa foi de 3%&nbsp;a.m. Por quantos &nbsp;anos
pagarei pelo empréstimo? Qual o preço do computador sem os juros?



M = 4300,00&nbsp; J= 1800,00&nbsp;
M = C +J, ENTÃO: 4300 = C + 1800, 4300 - 1800 = C então: C = 2500,00.

J=(C*I*T)/100.&nbsp; Resposta: 24 meses = 2 anos

12)
Comprei o material para a reforma da minha casa, pelo qual pagarei um total de R$&nbsp;38.664,00.
O seu valor à vista era de R$&nbsp;27.000,00 e a taxa de juros é de
2,4%&nbsp;a.m. Por quantos &nbsp;anos eu pagarei por este material?
M
= 38.664,00&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; C = 27.000,00&nbsp; J = 11.664,00

J=(C*I*T)/100, então: C =
27.000,00 J = 11.664,00, I = 2,4% a.m, t=?

11.664,00 =
(27.000,00*2,4*t)/100

11.664,00 = 270*2,4t

11.664,00 = 648t, então:
11.664,00/648t = 18 = t = 1,5 ano



13)
Aninha retirou de uma aplicação o total R$&nbsp;74.932,00, após decorridos
3,5&nbsp;semestres. O valor dos juros obtidos foi de R$&nbsp;22.932,00. Qual a
taxa de juros&nbsp;a.b.?

M = 74.932,00,&nbsp; J = 22.932,00, C = M – J → C = 74.932,00 -
22.932,00

C = 52000

T = 3,5 S = 3,5*6M = 21M,
como 1 bimestre é igual a 2 meses, temos 10,5 bimestres.



J=(C*I*T)/100 → 22.932,00 = (52000*i*10,5)/100

22.932,00 =520*10,5i → 22.932,00 =5460i →22.932,00: 5460i → i = 4,2% a.b

14)
O valor principal de uma aplicação é de R$&nbsp;2.000,00. Resgatou-se um total
de R$&nbsp;2.450,00 após 1&nbsp;mês. Qual o valor da taxa de juros&nbsp;a.d.?

M = 2450,00,&nbsp; J = 450,00, 2000 = 2450 – J → j = 2450 – 2000
→j = 450,00

J=(C*I*T)/100 → 450 =
(2000*i*30)/100

450 = 600i → i =0,75% a.d.



15) &nbsp;Em uma aplicação recebi de juros
R$&nbsp;141,75. O dinheiro ficou aplicado por 45&nbsp;dias. Eu tinha aplicado
R$&nbsp;3.500,00. Qual foi a taxa de juros a.a. da aplicação?

J= 141,75,&nbsp; C =
3.500,00&nbsp; T = 45 dias&nbsp;&nbsp; I = ?

J=(C*I*T)/100 → 141,75 =
(3500*I*45)/100 → 141,75 = 35*45*I

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 141,75 = 1575I →I =
141,75: 1575 → I = 0,09% a.d

0.09 x 360d = 32,4% a.a



&nbsp;16) Aplicando-se R$&nbsp;15.000,00 a
uma taxa de juro composto de 1,7% a.m., quanto receberei de volta após um ano
de aplicação? Qual o juro obtido neste período? Dado:
(1,017)12 = 1,224197



M =
P(1 +I)N → M = 15.000(1 +0,017)12

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; M = 15.000*(1,017)12
→ M = 15.000*1,224197 → M = 18362,96

J = M – C → J = 18362,96 -
15.000 → J = 3.362,96






&nbsp;Bom
desempenho! J.B. B