Divya's watch of worth Rs10 cr is abducted by N thieves(1,2....i...N). The fight over the watch leads to a final decision that it should belong to the thief who wins a simple game. The rules of the game state that every thief  registers a time in the format HH:MM:SS . Accordingly the average A of three clockwise angles  between the hours , minutes and seconds hands is calculated . Thus the ith thief  with the maximum A wins the game and gets to keep the watch.

The thieves are poor in mathematics and will need your help . Given the number of thieves and their registered time resolves the conflict and help them in choosing the winner 

-----Input-----
First line of input contains T which denotes the number of test cases.

The first line of each test case consists of an integer which denotes the number of thieves thereby N line follow which give the time choosen by each thieve in the format HH:MM:SS.

-----Output:-----
Output single integer i which denotes the ith thief.

-----Constraints:-----

1<=T<=100

1<=N<=50

01<=HH<=12

00<=MM<=60

00<=SS<=60

-----Example:-----
Input:
2
3
12:28:26
07:26:04
11:23:17
2
07:43:25
06:23:34

Output:
3
1

Starter code:

Solutions:
for t in range(int(input())):
 n = int(input())
 mx = -1
 for i in range(n):
  h, m, s = list(map(int,input().split(":")))
  h %= 12
  m %= 60
  s %= 60
  ha = h*30 + m*0.5 + s*0.5/60
  ma = m*6 + s*0.1
  sa = s*6
  
  hm1 = abs(ha - ma)
  hm2 = 360 - hm1
  hm3 = abs(hm1 - hm2)
  hm = min(hm1, hm2, hm3)
  
  ms1 = abs(ma - sa)
  ms2 = 360 - ms1
  ms3 = abs(ms1 - ms2)
  ms = min(ms1, ms2, ms3)
  
  sh1 = abs(sa - ha)
  sh2 = 360 - sh1
  sh3 = abs(sh1 - sh2)
  sh = min(sh1, sh2, sh3)
  
  avg = (hm + ms + sh) / 3
  if (mx < avg):
   ans = i+1
   mx = avg
 print(ans)

# your code goes here
from sys import stdin, stdout
t = int(stdin.readline())
while t:
 t -= 1
 n = int(stdin.readline())
 maxi = -1
 index = 0
 for i in range(n):
  hh,mm,ss = list(map(int, stdin.readline().strip().split(':')))
  ssa = ss * 360.0 / 60.0
  mma = (mm + (ss / 60.0)) * 360.0 / 60.0
  hha = (hh + (mm + (ss / 60.0)) / 60.0) * 360.0 / 12.0
  avg = (abs(ssa-hha) + abs(mma-ssa) + abs(mma-hha)) / 3
  # print hha, mma, ssa
  if avg > maxi:
   maxi = avg
   index = i
 stdout.write(str(index+1)+'\n')