576 F.2d 779, 782 (9th Cir. 1978).

12
The California Church concedes that Pulitzer and the individual appellees do not have such substantial contacts with the forum that they are present there for purposes of defending against all types of actions.  See Perkins v. Benguet Consolidated Mining Co., 342 U.S. 437, 72 S.Ct. 413, 96 L.Ed. 485 (1952).  If a defendant is not present for all purposes in the forum, due process requires that jurisdiction be based on contacts which have some nexus to the cause of action alleged.  Forsythe, 576 F.2d at 782.  The Supreme Court has described "the relationship among the defendant, the forum, and the litigation" as "the central concern of the inquiry into personal jurisdiction."  Shaffer v. Heitner, 433 U.S. 186,majority of karyotypes were normal, some interesting coincidental findings occurred. One child had trisomy 21 and achondroplasia, which has rarely been observed[@b6],[@b8]. One had 22ql 1.2 deletion syndrome and thanatophoric dysplasia; this association does not appear to have been previously reported.

Radiology was the best investigative tool, confirming the diagnosis in the vast majority of cases (87%). There were 33 (85%) fetuses that had a post mortem. Non-skeletal defects were extremely uncommon and were much more likely to occur in the setting of a second genetic diagnosis.

Here, we publish the most accurate prevalence figures to date for lethal skeletal dysplasias. We have shown that thanatophoric dysplasia is more common than previously thought. By raising awareness of this important group of disorders, we hope to improve antenatal diagnostic accuracy and


while Brother Gabriel is superior of the Immaculate Conception schools of this city. Brother Gabriel takes the place of Brother Lucian, who was removed by his superior to some other field of usefulness.... Brothers Gabriel, Onesimus, Andrew, Celsus are the teachers."

-- Church Progress -- Scholastic. Oct. 15,1887

1880: "Brother Stanislaus, the gentlemanly foreman of the 'Scholastic' office, has been for the past six weeks in Washington, attending to business connected with the University."

-- Scholastic, At Notre Dame, April 17, 1880

1887: "Brother Stanislaus left last week for Austin, Texas, whither he goes for a change in climate in the hope of recruiting his failing health. He has the best wishes of his many friends that the change may prove beneficial, and that he may be soon again with us toUnsworth, etc. But many of these afterward became successful professional writers. But many became official stenographer of Supreme Court of San Francisco developed such speed and excellence as a stenographer as to entitle him to the championship of the world. This is true, although Mr. Gallagher himself never claimed the honor.

"'I have known Mr. R. F. Grant for about twenty years," wrote Mr. Ernest A. Girvin, another official supreme Court reporter of San Francisco, in the phonographic World Magazine, New York, 1900, and have watched his progress.... I have frequently seen him write 250 words a minute for five consecutive minutes on matters not familiar to him. I remember distinctly that on one occasion he wrote in my presence 309 words in a single minute. This is the


Lighting can provide an important accent to any home, yard or garden. Among the many different types of lighting currently available are hanging lanterns such as those commonly known as Asian hanging lanterns. These lanterns are typically powered using traditional light and power sources, such as incandescent lamps powered by a home's electrical system, which limits the locations where the lanterns can be located. These lanterns can also be quite large and therefore expensive and burdensome to ship, transport and store. Thus, there exists a need to provide alternative power sources for these lanterns in order to allow for more flexibility in lantern placement. There also exists a need for lanterns which may be more easily and inexpensively shipped, transported and stored.number to 741 using a new population model that's being called into question and conflicts with studies that question the FWS' accuracy, offering evidence its numbers are inflated due to data-collection biases and inaccuracies and indicating that their population has actually been declining over the past few years.

In addition to the loss of a major food source, they also continue to face threats from genetic isolation and conflicts with humans. Turning management over to states that have already proven to be hostile to carnivores that will allow them to be hunted again will only hurt their chance for survival even more.

Please sign the petition asking the U.S. Fish and Wildlife Service not to strip Endangered Species Act protection from grizzlies.


using the following formula: Lip height difference (LHD) = *L*1 − *L*2/*L*1 × 100. For the noncleft individuals: LHD = length  of  the  longest  side − length  of  the  shorter  side/length  of  the  longest  side × 100. This formula yields a percent difference, which was calculated for each patient. The same formula to evaluate nasal alar contour was initially proposed by Wong et al. \[[@B18]\] and subsequently modified by Fudalej et al. \[[@B15]\]. The lip height difference was defined as an index of asymmetry of the lip.

The amount of lip height difference improvement in each cleft patient was determined by the difference in LHD at T2 and LHD at T1. A LDH equal to zero indicated perfect symmetry and any deviation from that determined asymmetry of the lip.

The three asymmetry lip scores are descriptively presented using a four point scale:of the CIS is lowered, the control unit determines that a glass surface of the CIS is stained. Then, the control unit activates the motor and the cam such that the spring presser presses the CIS against the CIS roller to clean the glass surface of the CLS. However, Japanese Laid-Open Patent Publication No. 09055828 does not describe a device that prevents dirt on a sheet from reaching the glass surface of the CIS.
Japanese Laid-Open Patent Publication No. 09065050 describes an original document reader that has a contact type image sensor, a roller shaped white elastic fiction body, and washing pads. When the contact type image sensor senses whether the roller sped white elastic friction body or the contact type image sensor is blackened, the washing pads are


just how fun garage is, but how inadvertently psychotically offkey it can be.

I asked Amen Ra for an example for this moment, he provided this, which 4Tet is re-issuing:

Of course, Todd Edwards is quite distinct from hip hop but in many ways his trademark sound (learned from MK), is centered around sampling too, building melodies and in key riffs from vocals. I recall El-B, when he was making more 4x4 during the El-Tuff phase with Karl “Tuff Enough” Brown, saying just how hard it is to make all the samples pitch in key, probably because when you slow down a layered samples, different harmonics in the sample pitch down to different tones, semi tones or more like between the intervals. Respect to Todd, basically.

So sampling – there’s historyArmstrong’s “Hot Five and Hot Seven Sessions” as a starting point for improvisation in jazz.

"Certified" though samples Pharoah Sanders from much later but there’s something that connects them, and that’s a spirit of freedom, both musically in terms of the music evolving on the fly, and then sonically, to find the tones between the tones. Sampling of course, compounds this further, as micro intervals are layered upon micro intervals, such that you can never know whether something is nearly in tune (unlike a wave in a synth).

What I like about this one is that from the very first note, it’s like you’ve walked in late and Sanders is exploding upwards in a crescendo. By the end he’s ascending to the heavens.

"I sampled Pharoah Sanders in this track," said


and other LHF records.

And so from the JB’s to DJ Premier, Todd Edwards to Pharoah Sanders via Kode9 and Nusrat Fateh Ali Khan, the connections bring us full circle back to “Certified,” hopefully all the richer for the journey.

Just a thought about the instrumental thing. I think there is a differentiation in both art and music between the 'pop' and 'high art'.

Classical music = high art and instrumental is the predominant force.

Pop music = Lowest common denominator and a catchy melody/vocal line/standard 'nice' music harmony is predominant force.

You do not have abstraction to the level of modern classical music/electroacoustic music in pop music, even in Aphex Twin/Squarepusher/Experimental dance etc it is simplistic rhythmically and harmonically compared to classical music. (see Stockhausen vs the technocrats article).

The tate modern is$B := \prod_{i=1}^d \Omega_i$. Averaging over the $h_b$, we conclude that $${\mathbb{E}}_{a \in [N]^d} {\mathbb{E}}_{r \in [M]} {\mathbb{E}}_{h_B \in [H]^B} F(a-\sum_{b \in B} b h_b,r+ \sum_{b \in B} h_b) = {\mathbb{E}}_{a \in [N]^d} {\mathbb{E}}_{r \in [M]} F(a,r) + o(1)$$ where $h_B := (h_b)_{b \in B}$, and so it will suffice to show that $$\label{sandal}
{\mathbb{E}}_{a \in [N]^d} {\mathbb{E}}_{r \in [M]} {\mathbb{E}}_{h_B \in [H]^B} F(a-\sum_{b \in B} b h_b,r+ \sum_{b \in B} h_b) = o(1).$$ To explain why we introduce the additional variables $h_B$, observe that expression $$\label{fabo}
F(a-\sum_{b \in B} b h_b,r+ \sum_{b \in B} h_b)$$ can be expanded as $$\begin{aligned}
&(\prod_{b' \in B_0} 1_{A}(a+rb' + \sum_{b \in B \backslash \{b'\}} (b'-b) h_b)) \times \\
&\quad \times (\prod_{i=1}^d \prod_{c_i \in \Omega_i} \nu_{i}( a_i + c_i r + \sum_{b \in B: c_i \neq


we conclude that $$\begin{aligned}
 \mu(E) &= p\!-\!\lim_{n \to \infty}   {\mathbb{E}}_{a \in [N_n]^d} {\mathbb{E}}_{r \in [M_n]} 1_E(B_{a,r,n}) \prod_{i=1}^d \nu_{i,n}( a_i )\\
 &= p\!-\!\lim_{n \to \infty}   {\mathbb{E}}_{a \in [N_n]^d} 1_{A_n}(a) \prod_{i=1}^d \nu_{i,n}( a_i )\end{aligned}$$ and hence by we have $$\mu(E) {\geqslant}\delta$$ as required.

In a similar vein, suppose that $h_1,\ldots,h_k \in {\mathbb{Z}}^d$ are such that $$\mu( T_{h_1} E \cap \ldots \cap T_{h_k} E) > 0.$$ We can find a tuple $\Omega = (\Omega_1,\ldots,\Omega_d)$ of finite subsets of ${\mathbb{Z}}$ such that $\prod_{i=1}^d \Omega_i$ contains $h_1,\ldots,h_k$. From we thus have $$\mu_\Omega( T_{h_1} E \cap \ldots \cap T_{h_k} E) > 0.$$ and thus for we have $$\mu_{\Omega,n}( T_{h_1} E \cap \ldots \cap T_{h_k} E) > 0$$ for arbitrarily large $n$. However, from , we see that this quantity can be\gg \frac{W^d (N')^d}{\phi(W)^d \log^d N}.$$ Also, we have $$\label{nprod}
A' \subset \prod_{i=1}^d {\mathcal P}'_i$$ where $${\mathcal P}'_i := \{ a_i \in [N']: W(a_i + \lfloor \delta' N/W\rfloor) + b_i \in {\mathcal P} \}.$$ Also, since $A$ contains no constellations of the form $a+rv_1,\ldots,a+rv_k$ with $a \in {\mathbb{Z}}^d$ and $r$ a positive integer, the same claim is true for $A'$ (here we again take advantage of the dilation symmetry in the constellation $a+rv_1,\ldots,a+rv_k$).

We now introduce the weights $\nu_i = \nu_{i,n}: [N'] \to {\mathbb{R}}^+$ for $i=1,\ldots,d$ by the formula $$\nu_i(a_i) := \frac{\phi(W)}{W} (\log N) 1_{{\mathcal P}'_i}(a_i),$$ then from we have $${\mathbb{E}}_{a \in [N']^d} 1_{A'}(a) \prod_{i=1}^d \nu_i(a_i) \gg 1.$$ We can then apply Theorem \[rmst\] to obtain a contradiction, as soon as we can find a sequence $M_n = o(N'_n)$ such that


going to offer a ton of hardcore protection. These will offer protection against some door dings, some scratching and they'll cover up some damage if you already have it. However, they're not going to protect against any sort of real hardcore damage, so that it is important to remember. What these will do, as I mentioned before, give you some protection but really, they're designed to change the look of your Jeep. This five-piece kit will change your Jeep from every angle, the front, the sides, and the rear and really give it a much more rugged and unique look all with a very easy installation.
As I mentioned, these are plastic pieces. These are all made of a UV treated thermoplastic, so it is flexible, it's not goingto go into existing holes, so you don't have to drill anything, and in some cases, they even use existing hardware. Anytime you're using 3M adhesive to attach anything to the outside of your Jeep. You just want to make sure that the surface that you're sticking it to is very, very clean. Use a good alcohol-based cleaner and these are going to stick and stay put where you put them for a long time until you want to remove them. That is one of the benefits of parts like this that install with 3M. When you do want to remove them, there's no permanent modification to your Jeep, and you can go back to a stock look.
Aside from having a really clean surface, you're also going to


which had exclusive media access for the ride. Footage was shot for a program on Armstrong to air this week.

Neither Bush nor Armstrong spoke to reporters, although White House spokesman Trent Duffy said the president was impressed with the seven-time champ's skills.

"Recognizing what the world has known for years, the president said, 'He's a good rider,'" Duffy said.

The president has taken up biking with a fervor since a bad knee forced him to give up his running routine a few years ago. He's been spending a lot of time riding while staying in Texas this month. It was Armstrong's first ride at the presidential ranch, which is about 100 miles north of Armstrong's adopted hometown of Austin.

Duffy wouldn't say whether they talked politics, a topic that Armstrong hasto a C or D score in every organ system. Partial remission was a change from a BILAG A or B score to a C or D score in at least 1 system, but with the persistence of 1 score of A or B in another system. No improvement was defined as a BILAG A or B score that remained unchanged after treatment. Of the 45 patients available for followup at 6 months, 19 patients (42%) achieved remission, and 21 patients (47%) reached partial remission after 1 cycle of BCDT (mean followup 39.6 months). BCDT resulted in a decrease in median global BILAG scores from 12 to 5 (P < 0.0001) and median anti-double-stranded DNA antibody titers from 106 to 42 IU/ml (P < 0.0001), and an increase


 thread::spawn(move || {
//!         let dur = Duration::new(5, 0);
//!         for i in 0..100 {
//!             if i % 2 == 0 { c2.pause().unwrap() } else { c2.resume().unwrap() }
//!             thread::sleep(dur);
//!         }
//!     });
//!
//!     // receive incoming notifications
//!     for notification in notifications {
//!         println!("{:?}", notification)
//!     }
//! }
//! ```

#[macro_use]
extern crate log;

pub mod client;
pub mod codec;
pub mod error;
pub mod mqttoptions;

pub use crate::client::{MqttClient,Chapman & Hall/CRC, Boca Raton (FL), 2004.

M. G. Crandall and L. Tartar. Some relations between nonexpansive and order preserving mappings. , 78(3):385–390, 1980.

A. Dedner, C. Rohde. Numerical approximation of entropy solutions for hyperbolic integro-differential equations. , 97(3):441–471, 2004.

J. Droniou. A numerical method for fractal conservation laws. , 79:95–124, 2010.

J. Droniou and C. Imbert. Fractal first order partial differential equations. , 182(2):299–331, 2006.

M. S. Espedal and K. H. Karlsen. Numerical solution of reservoir flow models based on large time step operator splitting algorithms. , 1734:9??-77, Springer, Berlin, 2000.

S. Evje and K. H. Karlsen. Monotone difference approximations of [$BV$]{} solutions to degenerate convection-diffusion equations. , 37(6):1838–1860 (electronic), 2000.

S. Evje and K. H. Karlsen. Viscous splitting approximation of mixed hyperbolic-parabolic convection-diffusion equations. , 83(1):107??-137, 1999.

G. B. Folland. Introduction to partial differential equations. , Princeton (NJ), 1995.

H. Holden, K. H. Karlsen, and K.-A. Lie. Operator splitting methods for degenerate convection-diffusion equations. I. Convergence and


secretary. The Rotary Student of the Month is Amy Lambe. Chamber Student of the Month is Katie Kier.

They will be recognized at a luncheon Feb. 15

After the Bell

The members of the Redoubt Club have created artistic pieces in Native Alaskan styles, including Aleut, Eskimo, Athabaskan and Northwest Coast Indian. Their creations will be on display for "Our First Ever Alaskan Art Show" in the Redoubt Elementary library Monday. The show is an open house from 5 to 6 p.m. for anyone to drop in and enjoy the creativity and history.

Redoubt students can view the artwork in the library throughout the week. The school gives special thanks to guest artists Lisa Kent and Laurine Maxwell-Evans.

To have information published in Schools, please send a description of the event or accomplishmentto Shana Loshbaugh at P.O. Box 3009, Kenai, AK 99611. Information will be accepted by e-mail at clarion@alaska.net or by fax at 283-3299.

The deadline for submission is Thursday at 5 p.m. for publication in the following Wednesday's paper. For information, contact Shana Loshbaugh at 283-7551.


Minisatellites and MVR-PCR for the individual identification of parasite isolates.
In recent years, a wide variety of biochemical and molecular typing systems have been employed in the study of parasite diversity aimed at investigating the level of genetic diversity and delineating the relationships among different species and subspecies. Parasite sequence-specific polymerase chain reaction (PCR)-based genotyping systems are among the most useful tools employed to date, because they can be applied to very small quantities of host-contaminated parasite material and, using repeated loci such as mini- and microsatellites, allow the identification and tracking of individual strains as well as the determination of allele and genotype frequencies in populations. Although minisatellites have been used very successfully to study parasite populations, in particular Trypanosoma brucei populations, there are some technical problems involved15 = u*r. Is r <= 1?
False
Let h(g) = g**2 + 7*g - 4. Let r(v) = -5*v**2 + v**3 + v + 6*v**2 - 2 - 5*v + 3*v**2. Let f be r(-5). Let n be h(f). Which is smaller: 1/2 or n?
n
Suppose -2*n = -0*n. Suppose -4*r + 16 = n, 6 - 20 = -a - 4*r. Is -5/3 equal to a?
False
Let b(o) = o - 2. Let n be b(2). Let z = -10 - n. Let j be -1*((-21)/z + -2). Which is smaller: j or 0?
j
Let k = -27989/18 - -1554. Let w = k + 4/9. Let t = -1 + 1.02. Which is smaller: t or w?
w
Let s(h) be the second derivative of -h**3/6 + 6*h**2 + 3*h. Let o


= 0.8 + 12.2. Which is smaller: v or u?
v
Let k = 4 + -3.99. Let d = -0.11 + k. Are d and 1/4 non-equal?
True
Suppose -24 = -0*t - 4*t. Let u be 1/(-3) + (-4)/t. Let c be 2 + (-9)/3 + u. Which is smaller: c or -1?
c
Let w = 48.9 + -51. Let n = w - -0.1. Which is bigger: n or 4?
4
Let l = -2.34 + 2. Let d = l - -0.4. Which is smaller: 0.1 or d?
d
Let h(q) = 7*q. Let o be h(-1). Let u(t) = -t**3 - 5*t - 8*t**2 - 7 - 3*t + 0. Let m be u(o). Is -2/7 greater than or equal to m?
False
Let w = -5 + 5. Let l = 0.1 +for in the fall. And if it’s gonna happen, the training needs to start in earnest now. I’m very worried that the knee problem will show up again. Let’s see how it goes.

By the way, I found a couple of interesting articles about running. Check ’em out.

Running vs Walking. It’s from the NY Times…so you need to be registered to read it. But it’s free. So why not? And this is definitely the way I’ll start my running routine back up…at least until the 5K I’m set to run on June 20th in Greensboro.


voltage vin and the input current iin of the AC are different, which leads to low power factor and poor total harmonic distortion. In addition, the output capacitor C is charged only when a voltage of the DC is higher than that of the output capacitor C, hence the charging time of the output capacitor C is shortened. As a result, the conduction time of diodes in the rectifier circuit 10 is also shortened, which increases the peak value of the conduction current, distorts the waveform of the input current iin, and lowers the power factor. Low power factor not only wastes energy, but also poses unnecessary burdens for the power supply systems of the power company. Therefore, the AC/DC converter with power factor correction circuit is emerged.
Incramps; your hands ache. The one unpleasant drudgery I faced in my occupation. I raced myself, to keep it interesting. That day I shaved seven seconds off my previous best.

* * * *

Digger had stalked upstairs when I started my process. She doesn't like to be around while I do that kind of work. I heard her wander around, opening and slamming cabinets, looking for food. Her steps have a recognizable, martial time signature: 2/2. I shit you not. She clipped downstairs as I finished — she knew how long it took me to deal with a package; she'd been through this with me before — already talking. "I had to go to this thing for my mother, like a surgery-appreciation thing. Did I tell you?"

"No, did she


  {    \filldraw[black] (1,1) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g_{5'}}$}}
};
    {    \filldraw[black] (1.5,1) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g_{4'}}$}}
};
    {    \filldraw[black] (2,1) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g_{3'}}$}}
};
    {    \filldraw[black] (2.5,1) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g_{2'}}$}}
};
    {    \filldraw[black] (3,1) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g_{1'}}$}}
};
    \draw (1,0) {to[out=up,in=down]}(0,1);
    \draw (1,0) {to[out=up,in=down]}(1.5,1);
    \draw (0.5,0) to[out=up,in=up] (2.5,0);
    \draw (1.5,0) {to[out=up,in=down]}(3,1);
    \draw (2,1) to (2.5,1);
  \end{tikzpicture}$$ We call this a *$G$-partition diagram*. Forgetting the labels, we obtain a *partition diagram* for $P$. Note that different $G$-partition diagrams can correspond to the same $G$-partition since only the      {\filldraw[black] (1.5,2) circle (1.5pt)};
            {\filldraw[black] (2,2) circle (1.5pt)};
            {\filldraw[black] (2.5,2) circle (1.5pt)};
            {\filldraw[black] (3,2) circle (1.5pt)};
            \draw (0,1) -- (0.5,1) {to[out=up,in=down]}(1,2);
            \draw (1.5,1) {to[out=up,in=down]}(1,2);
            \draw (1,1) {to[out=up,in=down]}(1.5,2);
            \draw (2.5,1) {to[out=up,in=down]}(1.5,2);
            \draw (3,1) -- (3,2);


{
    \begin{tikzpicture}[anchorbase]
      \draw (-0.25,0.25) to (0,0);
      \draw (0.25,0.25) to (0,0);
      \draw (0,0) to (0,-0.25);
    \end{tikzpicture}
}\colon {\mathsf{V}}\to {\mathsf{V}}\otimes {\mathsf{V}}, \quad
        {
    \begin{tikzpicture}[anchorbase]
      \draw (-0.25,-0.25) to (0.25,0.25);
      \draw (0.25,-0.25) to (-0.25,0.25);
    \end{tikzpicture}
}\colon {\mathsf{V}}\otimes {\mathsf{V}}\to {\mathsf{V}}\otimes {\mathsf{V}},
        \\
        {
    \begin{tikzpicture}[anchorbase]
      \draw (0,0) to (0,0.25);
      {\filldraw[fill=white,draw=black] (0,0) circle (2pt)};
    \end{tikzpicture}
}\colon {\mathbbm{1}}\to {\mathsf{V}}, \quad
     -- (0,-0.5);
            {\filldraw[fill=white,draw=black] (-0.25,0.25) circle (2pt)};
        \end{tikzpicture}
        \ ,\quad
        \begin{tikzpicture}[anchorbase]
            \draw (-0.4,-0.4) -- (-0.4,0) -- (-0.2,0.2) -- (0.2,-0.2) -- (0.4,0) -- (0.4,0.4);
            \draw (-0.2,0.2) -- (-0.2,0.4);
            \draw (0.2,-0.2) -- (0.2,-0.4);
        \end{tikzpicture}
        =
        \begin{tikzpicture}[anchorbase]


\end{tikzpicture}
    \quad \text{and} \quad
    \begin{tikzpicture}[anchorbase]
        \draw (-0.2,-0.1) -- (-0.2,0) arc(180:0:0.2) -- (0.2,-0.1);
    \end{tikzpicture}
    :=
    \begin{tikzpicture}[anchorbase]
        \draw (-0.2,-0.2) -- (0,0) -- (0.2,-0.2);
        \draw (0,0) -- (0,0.2);
        {\filldraw[fill=white,draw=black] (0,0.2) circle (2pt)};
    \end{tikzpicture}
    \ .$$

\[Sydney\] The following relations hold in ${\mathpzc{Par}}(G)$: $$\begin{gathered}
 \label{mirror}
        \begin{tikzpicture}[anchorbase]
            \draw (-0.2,-0.2) -- (0.3,0.3);
            \draw (0.3,-0.3) -- (-0.3,0.3);
     \ ,\quad
        \begin{tikzpicture}[anchorbase]
            \draw (0,0) arc(180:360:0.2) -- (0.4,0.2);
            {\filldraw[fill=white,draw=black] (0,0) circle (2pt)};
        \end{tikzpicture}
        =
        {
    \begin{tikzpicture}[anchorbase]
      \draw (0,0) to (0,0.25);
      {\filldraw[fill=white,draw=black] (0,0) circle (2pt)};
    \end{tikzpicture}
}=
        \begin{tikzpicture}[anchorbase]
            \draw (0,0) arc(360:180:0.2) -- (-0.4,0.2);


       \draw (0,0) -- (-0.25,-0.25);
            {  \filldraw[blue] (0,0.15) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g}$}}
};
            {  \filldraw[blue] (0.125,-0.125) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g^{-1}}$}}
};
        \end{tikzpicture}
        ,\
        \begin{tikzpicture}[anchorbase]
            \draw (0,0.3) -- (0,0) -- (0.25,-0.25);
            \draw (0,0) -- (-0.25,-0.25);
            {  \filldraw[blue] (0.125,-0.125) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g}$}}
};
           \draw (-0.2,-0.2) -- (-0.2,0) arc(180:0:0.2) -- (0.2,-0.2);
            {  \filldraw[blue] (-0.2,0) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g}$}}
};
        \end{tikzpicture}
        \overset{\cref{adjunction}}{=}
        \begin{tikzpicture}[centerzero={(0,-0.1)}]
            \draw (-0.6,-0.4) -- (-0.6,0) arc(180:0:0.2) arc(180:360:0.2) arc(180:0:0.2) -- (0.6,-0.4);
            {  \filldraw[blue] (0.2,0) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g}$}}
};
        \end{tikzpicture}
        =
        \begin{tikzpicture}[centerzero={(0,-0.1)}]


   \draw (-0.6,-0.4) -- (-0.6,0) arc(180:0:0.2) arc(180:360:0.2) arc(180:0:0.2) -- (0.6,-0.4);
            {  \filldraw[blue] (-0.2,0) circle (1.5pt) node[anchor=south west] {{$\scriptstyle{g^{-1}}$}}
};
        \end{tikzpicture}
        \overset{\cref{adjunction}}{=}
        \begin{tikzpicture}[anchorbase]
            \draw (-0.2,-0.2) -- (-0.2,0) arc(180:0:0.2) -- (0.2,-0.2);
            {  \filldraw[blue] (0.2,0) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g^{-1}}$}}
};
        \end{tikzpicture}
        \ .$$ The third relation in \[ramp\] is obtained from the third relation in \[GPC5\] by composing with a crossing    {\filldraw[fill=white,draw=black] (0,0) circle (2pt)};
    \end{tikzpicture}
}\mapsto
        \begin{tikzpicture}[centerzero]
            {\filldraw[black] (0,0.2) circle (1.5pt)};
        \end{tikzpicture}
        \ ,\quad
        {
    \begin{tikzpicture}[anchorbase]
      \draw (0,0) to (0,-0.25);
      {\filldraw[fill=white,draw=black] (0,0) circle (2pt)};
    \end{tikzpicture}
}\mapsto
        \begin{tikzpicture}[centerzero]
            {\filldraw[black] (0,-0.2) circle (1.5pt)};
        \end{tikzpicture}
        \ ,\quad


\end{tikzpicture}
}
            {
    \begin{tikzpicture}[anchorbase]
      \draw (0,-0.25) to (0,0.25);
      {  \filldraw[blue] (0,0) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g_{1'}^{-1}}$}}
};
    \end{tikzpicture}
}
            \
        \right)
        \circ
        D_\pi \circ S \circ D_\sigma
        \circ
        \left(
            {
    \begin{tikzpicture}[anchorbase]
      \draw (0,-0.25) to (0,0.25);
      \begin{tikzpicture}[anchorbase]
      \draw (0,-0.25) to (0,0.25);
      {  \filldraw[blue] (0,0) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g}$}}
};
    \end{tikzpicture}
}) & \colon V \to V, &
        h e_i &\mapsto h g^{-1} e_i,
    \end{aligned}$$ for $g,h \in G$, $1 \le i,j \le n$, $v,w \in V$.

We must show that the action preserves the relations \[GPC1,GPC2,GPC3,GPC4,GPC5\].

*Relations \[GPC1\]*: To prove the first three equalities in \[GPC1\], we compute $$\begin{gathered}
        \Phi_n \left( {
    \begin{tikzpicture}[anchorbase]
      \draw (-0.25,-0.25) to (0,0);
      \draw (0.25,-0.25) to (0,0);
      \draw (0,0) to (0,0.25);


is the span of all $x_{[P,{\mathbf{g}}]}$ with $[P,{\mathbf{g}}] \colon {\mathsf{V}}^{\otimes (k+l)} \to {\mathbbm{1}}$ having more than $n$ parts. Since the adjunction isomorphisms preserve the number of parts of $G$-partitions, as well as the partial order on $G$-partitions, the result follows.

When $G = \{1\}$ is the trivial group, \[kangaroo\] reduces to [@Com16 Th. 2.3]. In general, is a categorical generalization of the double centralizer property [@Blo03 Th. 6.6]. More precisely, recall the $G$-partition algebras from \[fort\]. The functor $\Phi_n$ induces an algebra homomorphism $$P_k(G,n|G|) \to \operatorname{End}_{G_n}(V^{\otimes k}).$$ implies that this homomorphism is surjective, and is an isomorphism when $n \ge 2k$. When the characteristic of ${\Bbbk}$ does not divide $n|G| = |G_n|$, so that $A_n$ is semisimple, the Double Centralizer Theorem implies that $A_n$ generates $\operatorname{End}_{P_k(G,n|G|)}(V^{\otimes k})$. Hence $G_n$ and $P_k(G,n|G|)$           {  \filldraw[blue] (0,-0.15) circle (1.5pt) node[anchor=east] {{$\scriptstyle{h}$}}
};
        \end{tikzpicture}
        \ =\
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,-0.4) -- (0,0.4);
            {  \filldraw[blue] (0,0) circle (1.5pt) node[anchor=west] {{$\scriptstyle{gh}$}}
};
        \end{tikzpicture}
        \ ,\quad
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,-0.4) -- (0,0.4);


   \ =\
    \begin{tikzpicture}[anchorbase]
        \draw[->] (0,0) -- (0,-0.3) arc (180:360:.3) -- (0.6,0);
        {  \filldraw[blue] (0.6,-0.3) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g}$}}
};
    \end{tikzpicture}
    \ , \quad
    \begin{tikzpicture}[anchorbase]
        \draw[->] (0,0) -- (0,0.3) arc (180:0:.3) -- (0.6,0);
        {  \filldraw[blue] (0,0.3) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g}$}}
};
    \end{tikzpicture}
    \ = \
    \begin{tikzpicture}[anchorbase]
        \draw[->] (0,0) -- (0,0.3) arc (180:0:.3) -- (0.6,0);
        {  \filldraw[blue] (0.6,0.3) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g}$}}
};
 (1.5,0) to (1.5,1.5);
        \end{tikzpicture}
        \ + \
        \sum_{g \in G}\
        \begin{tikzpicture}[anchorbase]
            \draw[->] (-0.8,-0.75) to (-0.8,0.75);
            \draw[<-] (0.8,-0.75) to (0.8,0.75);
            \draw[<-] (-0.3,-0.75) to (-0.3,-0.65) arc(180:0:0.3) to (0.3,-0.75);
            \draw[->] (-0.3,0.75) to (-0.3,0.65) arc(180:360:0.3) to (0.3,0.75);
            {  \filldraw[blue] (0,0.35) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g}$}}
};


       {  \filldraw[blue] (0,-0.35) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g^{-1}}$}}
};
        \end{tikzpicture}
        \overset{\cref{H3}}{=}
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,0) to (0,1.5);
            \draw[<-] (0.5,0) to (0.5,1.5);
            \draw[->] (1,0) to (1,1.5);
            \draw[<-] (1.5,0) to (1.5,1.5);
        \end{tikzpicture}
        = \Psi \left( \, {
    \begin{tikzpicture}[anchorbase]
          \draw[->] (1,-0.75) {to[out=up,in=down]}(0,0.75);
            \draw[<-] (1.5,-0.75) to (1.5,-0.65) arc(180:0:0.25) to (2,-0.75);
            \draw[<-] (2.5,-0.75) {to[out=up,in=down]}(1.5,0.75);
            \draw[->] (0.5,0.75) to (0.5,0.65) arc(180:360:0.25) to (1,0.75);
            {  \filldraw[blue] (0.25,0.2) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g^{-1}}$}}
};
            {  \filldraw[blue] (1.75,-0.4) circle (1.5pt) node[anchor=north] {{$\scriptstyle{g}$}}
};
            {  \filldraw[blue] (0.75,0.4) circle (1.5pt) node[anchor=south] {{$\scriptstyle{g}$}}
};
            {


\filldraw[blue] (1.75,0.35) circle (1.5pt) node[anchor=south] {{$\scriptstyle{h}$}}
};
            {  \filldraw[blue] (2.5,0) circle (1.5pt) node[anchor=west] {{$\scriptstyle{(ht)^{-1}}$}}
};
        \end{tikzpicture}
        \\
        &\underset{\cref{H3}}{\overset{\cref{H1}}{=}}
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,-0.75) to[out=up,in=240] (2,0.75);
            \draw[<-] (0.5,-0.75) to[out=60,in=down] (2.5,0.75);
            \draw[->] (1,-0.75) {to[out=up,in=down]}(2.1,0) {to[out=up,in=down]}(1,0.75);
            \draw[<-] (1.5,-0.75) to[out=60,in=down] (2.5,0) to[out=up,in=-60] (1.5,0.75);
           {  \filldraw[blue] (1.75,0.45) circle (1.5pt) node[anchor=north] {{$\scriptstyle{g}$}}
};
            {  \filldraw[blue] (2.5,0.55) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g^{-1}}$}}
};
        \end{tikzpicture}
        \\
        & \qquad\qquad\qquad\qquad + \sum_{g \in G}
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,-0.75) to[out=up,in=240] (2,0.75);
            \draw[<-] (0.5,-0.75) to[out=60,in=down] (2.5,0.75);
            \draw[->] (1,-0.75) {to[out=up,in=down]}(0,0.75);
            \draw[<-] (1.5,-0.75) to (1.5,-0.65) arc(180:0:0.25) to (2,-0.75);


     {  \filldraw[blue] (2.5,0.55) circle (1.5pt) node[anchor=west] {{$\scriptstyle{g^{-1}}$}}
};
        \end{tikzpicture}
        \\
        & \qquad\qquad\qquad\qquad + \sum_{g \in G}
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,-0.75) to[out=up,in=240] (2,0.75);
            \draw[<-] (0.5,-0.75) to[out=60,in=down] (2.5,0.75);
            \draw[->] (1,-0.75) {to[out=up,in=down]}(0,0.75);
            \draw[<-] (1.5,-0.75) to (1.5,-0.65) arc(180:0:0.25) to (2,-0.75);
            \draw[<-] (2.5,-0.75) {to[out=up,in=down]}(1.5,0.75);
   \end{gathered}$$

*Relations \[GPC4\]*: To check the first relation in \[GPC4\], we use the fact that left curls are zero to see that $$\Phi_n \left( {
    \begin{tikzpicture}[anchorbase]
      \draw (-0.25,-0.25) to (0,0);
      \draw (0.25,-0.25) to (0,0);
      \draw (0,0) to (0,0.25);
    \end{tikzpicture}
}\right) \circ \Phi_n \left( {
    \begin{tikzpicture}[anchorbase]
      \draw (-0.25,-0.25) to (0.25,0.25);
      \draw (0.25,-0.25) to (-0.25,0.25);
    \end{tikzpicture}
}\right)
        = \sum_{g \in G}
        \begin{tikzpicture}[anchorbase]
            \draw[->] (0,-0.5) to (0,0.5);


\circ \Psi
        \left(
            \begin{tikzpicture}[anchorbase]
                \draw (-0.2,-0.25) -- (-0.2,0.25);
                \draw (0.2,-0.25) -- (0.2,0.25);
                {  \filldraw[blue] (-0.2,0) circle (1.5pt) node[anchor=east] {{$\scriptstyle{g}$}}
};
            \end{tikzpicture}\,
        \right)
        =
        \begin{tikzpicture}[anchorbase]
               \draw (0.5,-0.25) -- (0.5,0.25);
        \draw (1,-0.25) -- (1,0.25);
    \end{tikzpicture}
    \circ [P_1] \circ [P_2] \circ [P_3] \circ
    \begin{tikzpicture}[centerzero]
        {\filldraw[black] (-0.5,-0.25) circle (1.5pt)} node[anchor=north] {{$\scriptstyle{g_4}$}};
        {\filldraw[black] (0,-0.25) circle (1.5pt)} node[anchor=north] {{$\scriptstyle{g_3}$}};
        {\filldraw[black] (0.5,-0.25) circle (1.5pt)} node[anchor=north] {{$\scriptstyle{g_2}$}};
        {\filldraw[black] (1,-0.25) circle (1.5pt)} node[anchor=north] {{$\scriptstyle{g_1}$}};
        {\filldraw[black] (-0.5,0.25) circle (1.5pt)};
        {\filldraw[black] (0,0.25) circle (1.5pt)};
        {\filldraw[black] (0.5,0.25) circle (1.5pt)};


$n$ connected components, then $\Psi(P)$ is a planar diagram with block number $n$.

For $i=1,\dotsc,k-1$, consider the morphism $$\begin{gathered}
    \chi_i :=
    \Psi
    \left(
        1_{\mathsf{V}}^{\otimes (k-i-1)} \otimes
        \left(
            \begin{tikzpicture}[centerzero]
                {\filldraw[black] (-0.25,-0.25) circle (1.5pt)};
                {\filldraw[black] (-0.25,0.25) circle (1.5pt)};
                {\filldraw[black] (0.25,-0.25) circle (1.5pt)};
          category described in \[hide\].

For $0 \le m,k \le n$, let ${}_k(n)_m$ denote $A_n$, considered as an $(A_k,A_m)$-bimodule. We will omit the subscript $k$ or $m$ when $k=n$ or $m=n$, respectively. We denote tensor product of such bimodules by juxtaposition. For instance $(n)_{n-1}(n)$ denotes $A_n \otimes_{n-1} A_n$, considered as an $(A_n,A_n)$-bimodule, where we write $\otimes_m$ for the tensor product over $A_m$. As explained in [@RS17 §7], we have a strong ${\Bbbk}$-linear monoidal functor $$\Theta \colon {\mathpzc{Heis}}(G) \to \prod_{m \in {\mathbb{N}}} \left( \bigoplus_{n \in {\mathbb{N}}} (A_n,A_m){\textup{-bimod}}\right)$$ given by $$\begin{aligned}
    \Theta
    \left(
        \begin{tikzpicture}[anchorbase]
            \draw[->] (-0.2,-0.2) -- (0.2,0.2);


“intrusive monitoring ” of their meetings by the prison.

The background to Baker’s June 14 warning, according to attorneys who received it, was a recent discovery that between September 2015 and April 2017 some legal meetings were recorded at Guantánamo. Baker invoked a Nov. 30, 2016 order by the chief Guantánamo war court judge, Army Col. James L. Pohl, that “formally prohibited” Detention Center staff from listening to or carrying out “audio and video recording” of attorney-client meetings.

READ THE MARINE LAWYER”S LOSS OF CONFIDENCE LETTER

In response, Southcom commander Navy Adm. Kurt Tidd ordered a commander’s inquiry — known as an AR 15-6 — into the issue, according to Army Col. Lisa Garcia. The inquiry’s scope is “to find facts and make recommendations for future operations,” Garcia said.

Southcom had usedQ:

Is there a way to add elements to a list/array? [C]

I am just wondering whether it is possible for me to add/append elements to a list in C, and I would go around doing it?
e.g.
int numbers[6] = {5,3,5,1,3,6}

Let's say I wanted to add another number to the array 'numbers', how would I do that?

A:

Well, the original array needs to be malloc'ed, rather than on the stack. Then you can use realloc:
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int * numbers = malloc(6*sizeof(int));

    for(int ii = 0; ii < 6; ++ii) {
        numbers[ii] = 5;
    }

    numbers = realloc(numbers, 7*sizeof(*numbers));
    if(!numbers) {
        printf("Memory


store, not just fresh dairy.

“Some brands we’re talking to are interested in creating a fluid milk brand, some are interested in other fresh dairy products and some are interested in using the proteins in products you wouldn’t even think of as dairy products.

“We’re fielding interest from some of the most well-known food and dairy companies in the world.

“We’re generating a whole new supply of cost-effective animal-free dairy protein into the food industry and we’re actively working with partners to scale up our process and we’re in talks with numerous food companies that want to work with us, so we should have more information on that and on our funding to share publicly in 2018.”

A goldilocks product?

Perfect Day dairy proteins are cleaner, greener and kinder than thosein the process whatsoever.” Ryan Pandya, co-founder, Perfect Day

The production process

So how are the proteins produced?

In a nutshell, Perfect Day takes food grade yeast, and adds DNA sequences (which can be 3D printed using synthetic biology techniques) which effectively instruct that yeast to produce the proteins found in milk – predominantly casein, but also lactoglobulin and lactoalbumin, the two proteins that form the bulk of whey protein in milk. It then throws them into big fermentation tanks with corn sugar and other nutrients to feed on and sits back while they get to work.

When the microbes have done their work at the bio-refinery, Perfect Day’s dairy proteins - which have the same organoleptic properties as their animal-based counterparters - are harvested via a mechanical process and can be


name is “kau ka la i ka lolo,” or “the sun rests on the brains.”

The constellation Leo will be high overhead in the early evening throughout May. Leo is noted by the bright star Regulus marking the front paw of Leo the lion. Since this area of the sky is directed out of the plane of our galaxy the Milky Way, other than the bright stars of Leo it appears more empty other parts of the sky.

However, if you have a telescope, this makes it an excellent area to observe other galaxies! Most impressive of all are the “Leo trio,” made up of galaxies M65, M66 and NGC 3628. With the right magnification they can all be seen simultaneously through the eyepiece for a very impressive sight, especiallythe skin keeps the electrical current coursing to the brain, but each time the batteries run out, another surgical procedure is required.

'I feel like laughing'

As doctors navigated Larsen's brain tissue in the operating room -- stimulating different areas to determine where to focus the electrical current -- Larsen began to feel his fear fade.

At one point he began beaming, then giggling. It was an uncharacteristic light moment for someone usually gripped by anxiety.

In response to Larsen's laughter, a staff member in the operating room asked him what he was feeling. Larsen said, "I don't know why, but I feel happy. I feel like laughing."

Doctors continued probing his brain for hours, figuring out what areas -- and what level of stimulation -- might work weeks later, when Larsen would


The coaches’ poll is part of the BCS formula used to determine its national champion.
Six Southeastern Conference teams (Auburn, Alabama, LSU, Arkansas, South Carolina and Florida) were a part of the new poll, which was the most of any league. After Alabama’s stunning loss at South Carolina Saturday, Ohio State took over the top spot by getting 49 of 59 possible first place votes. Oregon was ranked second as the Ducks received six first place votes followed by Boise State Nebraska and TCU, who all received at least one first place vote.
Florida (4-2, 2-2), State’s opponent this week, fell to 22nd in both polls after losing at home Saturday night to LSU.
MSU's Mullen is among the 59 head coaches in the voting process in 2010.
The Bulldogs did notQ:

JavaFX pack components

There is layout layout.fxml:
    <BorderPane fx:id="mainLayout" xmlns="http://javafx.com/javafx/8"xmlns:fx="http://javafx.com/fxml/1">
</BorderPane>

Further, in the method are in the loop 200 buttons:
public class Main extends Application {
    @FXML
    private static BorderPane mainLayout;
    private Stage stage;

    @Override
    public void start(Stage primaryStage) throws IOException {
        this.stage = primaryStage;
        initMainLayout();
        initLoginForm();
    }

    private void initMainLayout() throws IOException {
        FXMLLoader loader = new FXMLLoader();
        loader.setLocation(Main.class.getResource("/fxml/layout.fxml"));
        mainLayout = loader.load();


     egret.Tween.removeTweens(this.addLabel);
            this.addLabel.y = 25;
            egret.Tween.get(this.addLabel).to({y:0},300).call(this.moveEffect_effectEndHandler , this);
		}
   }

在构造函数里面赋值skinName传入皮肤的类引用，这个解析过程就是SkinAdapter完成的。 可以看到主机组件有一个partAdded进行皮肤组件的配对。这个时候我们就可以获取到对应的皮肤组件，来进行操作了，

**②制作游戏区域--------了解九宫格和容器布局**

![](http://xzper.qiniudn.com/2014/06/游戏演示.png)

再次来观察这个游戏的主界面。有一张纯色的背景图，还有4x4个空白的格子，随着游戏的进行会多出带数字的格子，游戏结束了还会出现胜利的界面。

先来看看第一张图。也许你认为这个背景一张4x4的图片不就搞定了么。不过我们这个2048单元格的数量可是可以任意调整的，可以是5x5，或者6x6甚至更多，这样才具备灵活性。你只需要改变CommandData的size属性就可以了(PS:游戏胜利的条件默认是达成2048，也可以通过修改CommandData的winValue属性来修改条件比如8192时胜利或者像上面那样32的时候胜利，想不输都难)。

我们继承SkinnableContainer建立一个MainGameUI的类作为容器来显示上面的界面，当然同时还需要一个皮肤MainGameUISkin。先来确定skinParts，如下：

	/**
     * 和主机组件匹配的皮肤部件
     */
    private static _skinParts:Array<string> = [
        "tileGroup","contentGroup"
    ];

    public get skinParts():Array<string>{
        return MainGameUISkin._skinParts;
    }

    /**
     * 游戏底背景
     */
    private backUIAsset:egret.gui.UIAsset;

    /**
     * 背景格子容器
     */
    private backGroundGroup:egret.gui.Group;

this.downPoint = this.main.globalToLocal(event.stageX, event.stageY);
    }

    private needMove:boolean;
    private stage_mouseMoveHandler(event:egret.TouchEvent):void{
        if(!this.movePoint)
            this.movePoint = new egret.Point();
        this.movePoint.x = event.stageX;
        this.movePoint.y = event.stageY;
        if (this.needMove)
            return;
        this.needMove = true;
    }

    public stage_mouseUpHandler(event:egret.Event):void{
        egret.UIGlobals.stage.removeEventListener(egret.TouchEvent.TOUCH_MOVE,
            this.stage_mouseMoveHandler,


awards and
honours. Modi may not celebrate the births and deaths of all his ancestors with
full page ads and TV ads. Modi may not facilitate dubious sources and hawala
funding of this mafia. This is what bothers them. Otherwise, if the Gujarat model
is meant to signify development and growth there is no reason why the model
shouldn’t work anywhere. The only difference will be the local natural
resources and available skills. Even in that respect Gujarat is hardly a state
that is blessed with great natural resources. And one of the most important
elements of the Gujarat model is that it also, to some extent, delivers freedom
from the nuisance of govt. So why complain about all this? Because Narendra
Modi challenges the existing order of the establishment; an order under which
some media mafia members haveby the end of 2013.

I beleive you are Anirvan, going by that newslaundry article. Well, whatever, this is just an awesome piece. As more and more people realize that a "home grown desi" is all that stands between a dignified life and a dystopian future, the echo for Narendra Modi as PM will only get shriller. These paladins of the stifling nehruvian consensus can no longer ignore the death rattle. The pied piper cometh. Be afraid, very afraid. Yes, that's you crooks in the media.

Please take time and watch the following NaMo video on youtube. He has repeated the same vision and idea for Gujarat. Of course this speech is no different from the SRCC speech but the vision and idea are same.

Please watch his comments on Secularism


or the other always and there is no such thing as "fair" and "balanced" unless in a miniscule part of the press. I went to this press conference when I was a rookie journo and they started to dole out monies in white envelopes and I was like "Holy Cow, are they paying me to be nice to them?" That sort of removed the blinkers from my eyes about this fourth estate and this so called pristine "ethics" of journalism in practice.

Excellent article..... I sometimes think that if the Congimen had same loyalty to the country as they show to the party, India would have been much more advanced. Same applies to these congress agent journalists who sold their souls to Congress than surrendering to country or god.

Thoughthe monthslong investigation, mourning relatives and community members have asked who would do this and why.

Investigators found no signs of forced entry at the home and said all the doors were locked when they arrived. Former Interim Police Supt. John Escalante, however, said one theory — that of a murder-suicide — had been deemed implausible.

Three types of knives or other bladed cutting instruments were used to carry out most of the killings, according to investigators, but those weapons were not at the crime scene. A rifle was found in the home but did not match the weapon used in the shooting death.

Last month, police had indicated the family may have been slain by multiple killers.

But the break in the case came Wednesday, authorities said, when DNA evidence from


was
“single[d] . . . out” by a barista at a coffee shop, among other allegations. See Compl. at
                                                 2
District Court “order the government to stop destroying [his] life, to remove [him] from

any ‘databases’ (blacklists) and to tell [him] when [he] was first put on one, and why,” in

order to remedy the “enormous and extraordinary crime” of his “[c]overt civil death.”

See id. at ECF p. 78-79. He sought to have his “owed memories . . . implanted in [him]

by the techniquesAmes Laboratory has developed a method to measure magnetic propertiesof superconducting and magnetic materials that exhibit unusual quantum behaviorat very low temperatures in high magnetic fields, by placing a tunnel diode resonator, an instrument that makes precise radio-frequency measurements of magnetic properties, in a dilution refrigerator, a cryogenic device that is able to cool samples down to milli-Kelvin temperature range. Credit: Ames Laboratory, US Department of Energy

Measuring the properties of superconducting materials in magnetic fields at close to absolute zero temperatures is difficult, but necessary to understand their quantum properties. How cold? Lower than 0.05 Kelvin (-272°C).

"For many modern (quantum) materials, to properly study the fine details of their quantum mechanical behavior you need to be cool. Cooler than was formerly thought possible," said Ruslan Prozorov, a physicist


---
abstract: 'In this article, we investigate some properties of cyclic coverings $f: Y\to X$ of complex surfaces of general type $X$ branched along smooth curves $B\subset X$ that are numerically equivalent to a multiple of the canonical class of $X$. The main results concern coverings of surfaces of general type with $p_g=0$ and Miyaoka–Yau surfaces; in particular, they provide new examples of multicomponent moduli spaces of surfaces with given Chern numbers as well as new examples of surfaces that are not deformation equivalent to their complex conjugates.'
address:
- Strasbourg University
- Steklov Mathematical Institute
author:
- 'V. Kharlamov and Vik.S. Kulikov'
title: On numerically pluricanonical cyclic coverings
---

=13.7pt plus 2pt

[^1]

Introduction {#introduc .unnumbered}
============

In this article, we investigate some properties of cyclic coverings of algebraic surfaces. Let us recall that there exist two equivalent approaches tobe a generator of $\text{Gal}(Y/X)$. In accordance with so called Hilbert’s theorem 90, in the field $\mathbb C(Y)$, considered as the vector space over $\mathbb C(X)$, one can choose a basis $w_0=1,w_1,\dots,w_{d-1}$ over $\mathbb C(X)$ such that $h^*(w_i)= \mu^i w_i$, where $\mu$ is a primitive $d$-root of unity. Hence, we can put $w=w_1$ and conclude that each branched $d$-sheeted cyclic covering can be seen as an extension $\mathbb
C(Y)=\mathbb C(X)(w)$ with $h^*(w)= \mu w$, and $w^d= g\in \mathbb
C(X)$ for some function $g$. The reverse statement is also straightforward.

The automorphism $h^*$ defines an automorphism $h:Y\to Y$, while the branch locus of $f$ consists of those irreducible curves $D_i$ that participate in the principal divisor $(g) =\sum_{i=0}^n a_iD_i \in
\text{Div}(X)$, $a_i\in \mathbb Z$, with coefficients $a_i\not
\equiv 0\,\text{mod}\, d$. Furthermore, $gcd(a_i,d)$ is equal


numerically $(d,m)$-canonical totally ramified cyclic coverings $f:Y\to X$ with fixed $d$ and $m$. We denote them by $k_{X,d,m}$ and $p_{X,d,m}$, respectively. The moduli space of surfaces $Z$ with given invariants $K^2_Z =k$ and $p_a(Z)=p$ will be denoted by $\mathcal M_{k,p}$.

\[mod\] Let $X$ be a surface of general type. If there is an element $\alpha\in \text{Tor}_d\text{Pic}(X)$ such that $\delta(\alpha)$ is not divisible by $d$ in $\text{Tor}(X)$, then for each integer $n\geq %0
1$ the moduli space $\mathcal M_{k,p}$ with $k=k_{X,d,dn+1}$ and $p=p_{X,d,dn+1}$ consists of at least two connected components.

Let us choose a divisor $C\sim (dn+1)K_X$. Consider two $(d,dn+1)$-canonical totally ramified cyclic coverings $f_i:Y_i\to
X$, $i=1,2$, branched along a smooth irreducible curve $B\in
|d(dn+1)K_X|$, where $f_1$ is the pure $(d,dn+1)$-canonical and $f_2$ is the $(d,dn+1)$-canonical totally ramified cyclic covering defined by $C+\alpha$ wheregiven non-singular curve $B\in |2K_X|$ there exist eight different totally ramified $(2,1)$-canonical cyclic coverings of $X$ branched along $B$.

\[Camp1\] There are exactly two connected components of the moduli space $\mathcal M_{16,4}$ to which belong the totally ramified $(2,1)$-canonical cyclic coverings of Campedelli surfaces.

Recall that every Campedelli surface $X$ can be obtained as follows (see, for example, [@K]). Let $\widetilde L=L_1\cup
\dots \cup L_7$ be a line arrangement in $\mathbb P^2$ consisting of seven lines. We numerate them by the non-zero elements $\alpha_i=(a_{i,1},a_{i,2},a_{i,3})\in (\mathbb Z/2\mathbb Z)^3$ and make two assumptions: the arrangement $\widetilde L$ has no $r$-fold points with $r\geq 4$; and if $\widetilde L$ has a tripe point $p_{\alpha_{i_1},\alpha_{i_2},\alpha_{i_3}}= L_{\alpha_{i_1}}\cap
L_{\alpha_{i_2}}\cap L_{\alpha_{i_3}}$, then $\alpha_{i_1}+\alpha_{i_2}+\alpha_{i_3}\neq 0$. Consider the Galois covering $\widetilde g: \widetilde X\to \mathbb P^2$ with Galois group $\text{Gal}(\widetilde X/\mathbb


$\gamma_2^{-1}(\alpha_t)=\mathbb P(H^0(X, \mathcal O_X(2K_X+
\alpha_t))$ over $%\widetilde
\alpha_t\in \text{Pic}_{\Delta}(X)$. Denote by $T=U\times_{\text{Pic}_{\Delta}(X)}T_{\Delta,2}$ the product of the fibrations $\gamma_1$ and $\gamma_2$ and let $p_i$, $i=1,2$, be the projections of $T$ onto the factors.

Let us fix a divisor $D\sim (m-2)K_X$ and associate with each $t\in
T$ the divisor $C_{p_2(t)}=D_{p_2(t)}+D\sim mK_X+\alpha_{p_2(t)}$. By Lemma \[cov\], the coverings $f_1$ and $f_2$ are defined by divisors $C_{p_2(t_i)}=D_{p_2(t_i)}+D\sim mK_X+\alpha_{p_2(t_i)}$ for some points $t_i\in T$, $i=1,2$, and branched along the curves $B_{p_1(t_i)}$. The family of divisors $D_t=B_{p_1(t)}-dC_{p_2(t)}$ defines a divisor $\widetilde D$ in $X\times T$ such that $\widetilde D\cap (X\times \{ t\})= D_t$ for each $t\in T$. By Corollary 6 in [@Mu1], there is an invertible sheaf $\mathcal L$ on $T$ such that $\mathcal O_{X\times T}(\widetilde D)=p^*(\mathcal
L)$, where $p:X\times T\to T$ is the projection. Obviously, we can choose aramified cyclic covering of $X$. Then the rational map $\varphi_{K_Y}: Y\to \mathbb
P^{p_g(Y)-1}$ factorizes through $f$, that is, there exists a rational map $\psi: X\to \mathbb P^{p_g(Y)-1}$ such that $\varphi_{K_Y}=\psi\circ f$.

Let $B \equiv 2mK_X $ be the branch curve of $f$ and let $f$ be defined by a divisor $C\equiv mK_X$. As in the proof of Theorem \[mod\], due to the projection formula for the canonical divisor we have the equality $$\label{f1} K_Y=f^*(K_X+C).$$ As any surface of general type with $p_g=0$, the surface $X$ is regular (that is, $q(X)=0$), so that Mumford Vanishing Theorem and Riemann-Roch Theorem imply $$\label{f2} \dim H^0(X, \mathcal
O_V(K_X+C))=\frac{(K_X+C,C)_X}{2}+1=\frac{m(m+1)}{2}K^2_X+1.$$ By Proposition \[pi\], the surface $Y$ is also regular; therefore, applying the formula (\[pa\]) from Proposition \[2K\] we obtain $$\label{f3}
\displaystyle p_g(Y)=1+\frac{m(m+1)}{2}K_X^2 .$$ Now, the theorem follows from


(\[f1\]) – (\[f3\]).

\[pg01\] Let $X$ be a surface of general type with $p_g=0$, and let $f:Y\to
X$ be a numerically $(2,m)$-canonical totally ramified cyclic covering of $X$ defined by a divisor $C\equiv mK_X$. Then for $m\geq
4$ the canonical map $\varphi_{K_Y}: Y\to \mathbb P^{p_g(Y)-1}$ is a morphism of degree $2$ over its image, and this image, $\varphi_{K_Y}(Y) \subset \mathbb P^{p_g(Y)-1}$, coincides with the image of $X$ under the birational morphism $\psi=\varphi_{K_X+C}$.

In the present time, there is a long list of known surfaces of general type with $p_g=0$ (see, for example, the survey [@B-C-P]), but up to now, this list is far from completeness. In the following three propositions we investigate the degree of the canonical map of a pure $(2,1)$-canonical totally ramified cyclic covering, respectively, of a Campedelli surface, aof general type. They are both minimal, since for any curve $E\subset Y_i$ we have $E\cdot
K_{Y_i}=f_*(E)\cdot (dm-d+1)K_X>0$. Therefore, $\pm \delta(K_{Y_i})$ are the only Seiberg-Witten basic classes in $H^2(Y_i;\mathbb Z)$ (see [@W] for the case $p_g>0$ and, for example, [@Br] for $p_g=0$), which implies $\varphi^*(\delta(K_{Y_2}))=\pm
\delta(K_{Y_1})$.

By Proposition \[pi\] the map $\varphi$ induces an automorphism $\varphi_* :\pi_1(X)=\pi_1(Y_1)\to\pi_1(Y_2)=\pi_1(X)$ of $\pi_1(X)$ (more precisely, an element of $\operatorname{Out}\pi_1(X)$), and therefore, in accordance with Mostow rigidity, it is induced by an either holomorphic or antiholomorphic automorphism $\psi:X\to X$. By Siu rigidity (see [@Siu]), the map $f_2\circ \varphi:Y_1\to X$ is homotopic to either holomorphic or antiholomorphic morphism $\widetilde f_1:Y_1\to X$ and, as it follows once more from Mostow rigidity, $\widetilde f_1=\psi\circ f_1$ since these two morphisms define the same element of $\operatorname{Out}\pi_1(X)$.

If $\psi$ is holomorphic then


X$ and $f\circ c^n$ are homotopic, and since in addition $c^*(\delta(K_{Y}))=-\delta(K_{Y'})=-\delta(K_{Y})$ (the Chern class $\delta(K)$ being integral does not change under deformations) while $f^*$ transforms $(dm-m+1)\delta(K_X)$ in $\delta(K_Y)$ modulo torsion, it implies that $n$ is even. Contradiction.

\[symplectic\] [Literally the same proof shows that the surfaces $Y$ (and $Y'$) satisfying Theorem \[main1\] assumptions have no diffeomorphisms $f:Y\to Y$ with $f^*[K]=-[K], [K]\in H^2(Y;\mathbb Q)$. Hence, due to the invariance of the canonical class under deformations in the class of almost-complex structures, the imaginary part $\omega$ of the Kähler structure of $Y$ considered as a symplectic structure on the underlying smooth manifold is not symplectic deformation equivalent to its reverse, $-\omega$. Thus, Theorem \[main1\] and, in particular, its Corollary \[main-ex\] below provide new examples of opposite symplectic structures not equivalent tomodules.toString());

		if (licensee != null) {

			logger.info("Licensed for {}", licensee);

		} else {

			logger.info("Evaluation License");
		}

		final int userLimit = getNumberOfUsers();
		if (userLimit > 0) {

			logger.info("Licensed for {} users", userLimit);
		}
	}

	@Override
	public void refresh() {

		// verify that the license is valid for the current date
		if (licenseExpired()) {

			final SimpleDateFormat format = new SimpleDateFormat(DatePattern);

			logger.error("License found in license file is not valid any more, license period ended {}.", format.format(endDate.getTime()));

			modules.clear();
			modules.addAll(communityModules);

			allModulesLicensed = false;

			edition = "Community";
		}
	}

	@Override
	public String getEdition() {
		return edition;
	}

	@Override
	public boolean isModuleLicensed(final String module) {
		return allModulesLicensed || modules.contains(module);
	}

	@Override
	public boolean isClassLicensed(final String fqcn) {
		return allModulesLicensed || classes.contains(fqcn);
	}

	@Override
	public String getLicensee() {
		return licensee;
	}

	@Override
	public String getHardwareFingerprint() {
		return createHash();
	}

	@Override
	public Date getStartDate() {
		return startDate;
	}

	@Override
	public Date getEndDate() {
		return endDate;
	}

	@Override
	public int getNumberOfUsers() {

		if (numberOfUsersString != null) {

			try {

				return Integer.valueOf(numberOfUsersString);

			} catch (Throwable t) {
				logger.error("Invalid value for number of users in license key: {}: {}", numberOfUsersString, t.getMessage());
			}

		}

		return -1;
	}

	@Override
	public boolean isValid(final Feature feature) {

		if


           = properties.get(SignatureKey);
		final String hostId           = properties.get(MachineKey);
		final String thisHostId       = createHash();
		final String edition          = properties.get(EditionKey);
		final String modules          = properties.get(ModulesKey);
		final String dateString       = properties.get(DateKey);
		final String startDateString  = properties.get(StartKey);
		final String endDateString    = properties.get(EndKey);
		final String serversString    = properties.get(ServersKey);
		final String usersString      = properties.get(UsersKey); // unused (cannot be verified here)
		final Date now                = new Date();

		if (StringUtils.isEmpty(key))expected signature response)
			socket.getInputStream().read(result, 0, 256);

		} catch (Throwable  t) {
			logger.warn("Unable to verify volume license: {}", t.getMessage());
		}

		return result;
	}

	private boolean verify(final byte[] data, final byte[] signatureData) {

		try {

			final Signature verifier = Signature.getInstance(SignatureAlgorithm);

			verifier.initVerify(certificate);
			verifier.update(data);

			if (verifier.verify(signatureData)) {

				return true;
			}

		} catch (Throwable t) {
			logger.warn("Unable to verify volume license: {}", t.getMessage());
		}

		logger.error("License verification failed, license is not valid.");

		return false;
	}

	// ----- nested classes ------
	public static class CreateLicenseCommand extends NodeServiceCommand implements MaintenanceCommand {

		@Override
		public void execute(final Map<String, Object> attributes) throws FrameworkException {

			final String name     = (String)attributes.get(NameKey);
			final String start    = (String)attributes.get(StartKey);
			final String end      = (String)attributes.get(EndKey);
			final String edition  = (String)attributes.get(EditionKey);
			final String modules  = (String)attributes.get(ModulesKey);
			final String hostId   = (String)attributes.get(MachineKey);
			final String servers  = (String)attributes.get(ServersKey);
			final String users    = (String)attributes.get(UsersKey);
			final String keystore = (String)attributes.get("keystore");
			final String password


well after Wally West had made a name for himself as the new Flash, the character of Bart Allen, grandson of the second Flash Barry Allen, was brought into the past from his home in the future and served as the young hero Impulse. In 2003, with writer Geoff Johns' relaunch of a new Young justice volume, Bart donned the mantle of Kid Flash after being nearly killed by the assassin Deathstroke. As Kid Flash, Bart appeared in Teen Titans and The Flash (vol. 2) regularly until the Infinite Crisis event, where a disappearance of Wally West made Bart the fourth Flash. Apparently killed by the Rogues, Bart was resurrected in the 31st century by Legion of Super-Heroes member Brainiac 5 and retook the mantle of Kid Flash.Wally West as Kid Flash makes a brief appearance in Justice League: The New Frontier at the end of the film, during U.S. President John F. Kennedy's speech.
 Wally West as Kid Flash appears in Teen Titans: The Judas Contract, with Jason Spisak reprising his role from Young Justice. Along with Bumblebee and Speedy, he is seen in a flashback of how the Teen Titans first met Starfire.

Video games
 Wally West as Kid Flash appears as a playable character in Young Justice: Legacy. He is voiced by Jason Spisak.
 Bart Allen as Kid Flash appears as an unlockable playable character in Lego Batman 3: Beyond Gotham. The player can unlock him in the Justice League Watchtower.
 Wallace West as Kid Flash made his video game debut as a


                          struct svga_buffer *sbuf,
                              struct svga_buffer_surface *bufsurf)
{
   enum pipe_error ret;

   /* Update the to-bind surface */
   assert(bufsurf->handle);
   assert(sbuf->handle);

   /* If we are switching from stream output to other buffer,
    * make sure to copy the buffer content.
    */
   if (sbuf->bind_flags & PIPE_BIND_STREAM_OUTPUT) {
      ret = SVGA3D_vgpu10_BufferCopy(svga->swc, sbuf->handle, bufsurf->handle,
    /* The whole_update_command is a SVGA3dCmdHeader plus the
       * SVGA3dCmdUpdateGBImage command.
       */
      whole_update_cmd = (struct svga_3d_update_gb_image *) &invalidate_cmd[1];
      /* initialize the first UPDATE_GB_IMAGE command */
      whole_update_cmd->header.id = SVGA_3D_CMD_UPDATE_GB_IMAGE;
      update_cmd = &whole_update_cmd->body;

   } else {
      /* Allocate FIFO space for 'numBoxes' UPDATE_GB_IMAGE commands */
      const unsigned total_commands_size =
         sizeof(*update_cmd) + (numBoxes - 1) * sizeof(*whole_update_cmd);

      update_cmd = SVGA3D_FIFOReserve(swc,


< numBoxes; ++i) {
      whole_update_cmd++;
      memcpy(whole_update_cmd, sbuf->dma.updates, sizeof(*whole_update_cmd));

      swc->surface_relocation(swc, &whole_update_cmd->body.image.sid, NULL,
                              sbuf->handle,
                              SVGA_RELOC_WRITE | SVGA_RELOC_INTERNAL);
   }

   /* Increment reference count */
   sbuf->dma.svga = svga;
   dummy = NULL;
   pipe_resource_reference(&dummy, &sbuf->b.b);
   SVGA_FIFOCommitAll(swc);

   swc->hints |= SVGA_HINT_FLAG_CAN_PRE_FLUSH;
   sbuf->dma.flags.discard = FALSE;

   svga->hud.num_resource_updates++;

        box->h = 1;
         box->d = 1;
         box->srcx = sbuf->map.ranges[i].start;
         box->srcy = 0;
         box->srcz = 0;

         assert(box->x <= sbuf->b.b.width0);
         assert(box->x + box->w <= sbuf->b.b.width0);

         svga->hud.num_bytes_uploaded += box->w;
         svga->hud.num_buffer_uploads++;
      }
   }

   /* Reset sbuf for next use/upload */

   sbuf->map.num_ranges = 0;

   assert(sbuf->head.prev && sbuf->head.next);


sbuf->dma.flags);
            assert(ret == PIPE_OK);
         }

         sbuf->dma.flags.discard = FALSE;

         sws->buffer_destroy(sws, hwbuf);

         offset += size;
      }
   }

   sbuf->map.num_ranges = 0;

   return PIPE_OK;
}

/**
 * Get (or create/upload) the winsys surface handle so that we can
 * refer to this buffer in fifo commands.
 * This function will create the host surface, and in the GB case also the
 * hardware storage. In the non-GB case, the hardware storage will be created
 * if there are mapped rangesflags, validate the host surface.
          */
         ret = svga_buffer_validate_host_surface(svga, sbuf, tobind_flags);
         if (ret != PIPE_OK)
            return NULL;
      }
   } else {
      if (!sbuf->bind_flags) {
         sbuf->bind_flags = tobind_flags;
      }

      assert((sbuf->bind_flags & tobind_flags) == tobind_flags);

      /* This call will set sbuf->handle */
      if (svga_have_gb_objects(svga)) {
         ret


holds the equivalent of more than 7 m of sea level rise in its thick mantle of ice. Glaciologists were already fully occupied trying to track and forecast the surge in glacial calving. Now, they are striving to understand the complex feedbacks that are speeding up surface melting.

Although the Arctic is warming twice as fast as the rest of the world, high temperatures alone can't explain the precipitous erosion of Greenland's ice. Unseasonably warm summers appear to be abetted by microbes and algae that grow on the increasingly wet surface of the ice sheet, producing pigments that boost the ice's absorption of solar energy. Soot and dust that blow from lower latitudes and darken the ice also appear to be playing a role, as are changes in weatheryear, fully 98% of the ice sheet was covered in liquid water, according to satellite data. At one weather station, a layer of ice as much as a meter thick melted in 4 days. That brief episode and a subsequent 2-day melt contributed to 14% of the season's ice loss.

But a recently published modeling study of the 2012 melting showed it wasn't sun falling on darkened snow that drove the melt—in fact, the skies were pretty cloudy over much of the island during the two melting events. Instead, it was warm temperatures and rainfall, provided by big "blocking" high-pressure systems that kept the mild weather in place. As the Arctic warms, such melt episodes are likely to "occur much more frequently in the future," says Dirk van As


as dtypes_lib
from tensorflow.python.framework import errors
from tensorflow.python.framework import ops
from tensorflow.python.framework import test_util
from tensorflow.python.ops import io_ops
from tensorflow.python.ops import math_ops
from tensorflow.python.ops import parsing_ops
from tensorflow.python.ops import variables
from tensorflow.python.platform import gfile
from tensorflow.python.platform import test
from tensorflow.python.training import coordinator
from tensorflow.python.training import queue_runner_impl
from tensorflow.python.training import server_lib

_VALID_FILE_PATTERN = "VALID"
_VALID_FILE_PATTERN_2 = "VALID_2"
_FILE_NAMES = [b"abc", b"def", b"ghi", b"jkl"]
_FILE_NAMES_2 = [b"mno", b"pqr"]
_INVALID_FILE_PATTERN = "INVALID"

class GraphIOTest(test.TestCase):

  def _mock_glob(self, pattern):
    if _VALID_FILE_PATTERN == pattern:
      return _FILE_NAMES
    if _VALID_FILE_PATTERN_2 == pattern:
      return _FILE_NAMES_2
    self.assertEqual(_INVALID_FILE_PATTERN, pattern)
    return []

  def setUp(self):
    super(GraphIOTest, self).setUp()
    random.seed(42)
    self._orig_glob = gfile.Glob
    gfile.Glob = self._mock_glob

  def tearDown(self):
    gfile.Glob = self._orig_glob
    inputs = graph_io.read_batch_examples(
          filename,
          batch_size,
          reader=io_ops.TextLineReader,
          randomize_input=False,
          num_epochs=1,
          queue_capacity=queue_capacity,
          name=name)
      self.assertAllEqual((None,), inputs.get_shape().as_list())
      session.run(variables.local_variables_initializer())

      coord = coordinator.Coordinator()
      threads = queue_runner_impl.start_queue_runners(session, coord=coord)

      self.assertAllEqual(session.run(inputs), [b"ABC"])
      self.assertAllEqual(session.run(inputs), [b"DEF"])
      self.assertAllEqual(session.run(inputs), [b"GHK"])


      data.append(session.run(result))
      except errors.OutOfRangeError:
        pass
      finally:
        coord.request_stop()

      coord.join(threads)

    parsed_records = [
        item for sublist in [d["sequence"] for d in data] for item in sublist
    ]
    # Check that the number of records matches expected and all records
    # are present.
    self.assertEqual(len(parsed_records), num_records)
    self.assertEqual(set(parsed_records), set(lines))

  def test_read_batch_features_maintains_order(self):
    """Make sure that examples are read in the right order.

    When randomize_input=False, num_enqueue_threads=1 and reader_num_threads=1
 = self._orig_glob
    filenames = self._create_sorted_temp_files(["ABC\n", "DEF\nGHK\n"])

    batch_size = 1
    queue_capacity = 5
    name = "my_batch"

    with ops.Graph().as_default() as g, self.session(graph=g) as session:
      inputs = graph_io.read_batch_examples(
          filenames,
          batch_size,
          reader=io_ops.TextLineReader,
          randomize_input=False,
          num_epochs=1,
          queue_capacity=queue_capacity,
          name=name)
      self.assertAllEqual((None,), inputs.get_shape().as_list())
      session.run(variables.local_variables_initializer())


with pepper spray, according to the Star-Ledger. Others in the hall snapped pictures and video of the chaos on their cellphones and tablet computers.

Earl Best, a community activist known as "Street Doctor," told the Montclair Patch he was also sprayed and had to go to a hospital for treatment. Baraka said his mother had also been sprayed, according to the Montclair Patch.

Muhammad was arrested and charged with assaulting Speight and City Clerk Robert Marasco, resisting arrest and inciting a riot, Police Director Samuel DeMaio told the Star-Ledger.

DeMaio said the officer’s use of the pepper spray will be reviewed but noted that it might be warranted in such a chaotic scenario.

"From what I see right now at face value, in the situation that they had there with the crowdknow what to do. There’s a flash of panic, even while you’re thinking, “This is stupid, I’ve done this a thousand times”, and then, maybe it’s all right, maybe you have to take a moment to get your head in the right space, and ... okay, you’re off again, control safely in the hands of the automatic pilot.

But you’re unsettled. There are lots of ways our memory fails us. Some of these are very common, so common we just accept them — noone (well, few of us) expect our memories to be 100% perfect all the time. But procedural memory — the memory that allows us to drive a car, ride a bike, type, play the piano, etc — is different from other types of memory. We don’t


UberEats and Deliveroo drivers were specifically targeted for their mopeds in a spate of horrific acid attacks across east London, with police arresting two teenagers aged 15 and 16 over the incident.

One rider was attacked and robbed while another man was heard 'screaming in agony' after suffering catastrophic injuries when doused with flesh-burning liquid.

Another victim who also had his moped stolen was filmed having litres of water poured over his face by police to wash acid from his eyes by the side of the road in Hackney.

The two-man gang went on a rampage across east London as they sprayed five men between 10.25pm and 11.37pm in Stoke Newington, Hackney and Islington.

One of the drivers was confirmed to work for Deliveroo, while another was a father-of-one UberEats driver whoElland Road has been the home of Leeds United since 1919 and remains one of English football's great theatres. Delve deeper into the history of our home ground and find out all the information you need for making a visit.

23

Kalvin Phillipsposition Midfielder

PLAYER PROFILE

The homegrown central midfielder scored on his Elland Road debut in April 2015 against Cardiff City– just five days after making his first senior appearance away at Wolverhampton Wanderers.

Phillips, who joined the club from local side Wortley Juniors in 2010, progressed through the ranks at Thorp Arch and earned a glowing reputation for his all-action displays prior to his first-team breakthrough.

Ahead of the 2018/19 season, he is closing in on 100 appearances for the Whites.


stand in Section 9 of Yurcak Field for home games, and travel to road games, singing songs and chants throughout the game.

Broadcasting

As of April 2017, Sky Blue FC games are streamed exclusively by Go90 for American audiences and via the NWSL website for international viewers. For the 2017 season, the team will be featured in the nationally televised Lifetime NWSL Game of the Week broadcasts on May 13, May 20, July 1, and August 12, 2017.

Previous seasons' matches were streamed live on YouTube, available around the world. The announcers were Corey Cohen on play-by-play and Dan Lauletta on color commentary with Evan Davis hosting the halftime show and NJ Discover handling production.

Head coaches
Information correct as of May 12.  Only competitive matches (regular season and playoffs) are    "                                  (desat.r < 0.5 ? (2.0 * desat.r * filterColor.r) : (1.0 - 2.0 * (1.0 - desat.r) * (1.0 - filterColor.r))),\n" +
            "                                  (desat.g < 0.5 ? (2.0 * desat.g * filterColor.g) : (1.0 - 2.0 * (1.0 - desat.g) * (1.0 - filterColor.g))),\n" +


code!" you say. That may be the case, but do any of the third-party modules you use have them? What about any you may use in the future or updated versions of the ones you already use?For supporting
> newer screens with high resolutions, you should provide 16, 20, 24, 40, 48, 64, 96, and 256.
> For Windows 7, all pictures can be compressed using PNG but for backward compatibility with
> Windows XP, 16 to 48 should not be compressed.


of the pedicle on the transverse and sagittal planes, respectively. The transverse plane's deviations toward the lateral side were recorded as positive values and the deviations toward the medial side as negative values. The sagittal plane's deviations toward the superior and inferior sides were recorded as positive and negative values, respectively \[[@CR16], [@CR17]\].

A grade was then used to evaluate breaches of the pedicle wall in the sagittal and transverse planes as follows:Grade 1: Screw positioned at the center of the pedicleGrade 2: Less than one third of the screw cross-section (≤ 1.2 mm with a 3.5-mm-diameter screw) penetrating the cortexGrade 3: Between one third and one half of the screw cross-section penetrating the cortex (or deviation \< 2 mm)Grade 4: More than one half of the screw cross-section penetrating the cortex (orATPI was designed to be medial because of the lateral structures of the vertebral artery. Previous studies have indicated that lateral perforation was observed more frequently \[[@CR30], [@CR31]\], and the consequences of a lateral perforation in the cervical spine, such as cerebral infarction, are serious \[[@CR32]\]. In contrast, medial CBT might be safer since the dural sac is located at a distance of approximately 2.4--3.1 mm from the medial pedicle wall \[[@CR33]\]. Therefore, we designed the CBT in cervical ATPI to be medial in order to allow the screw thread to approach the medial wall of the pedicle. The second consideration was the setting of the two types of CBTs. One was the CBT0 that allowed the screw thread to be close to the medial wall of the pedicle


best to his wife, and I am the best of you to my wives."(Ibn Majah)
Islam has given outstanding respect for women.Women suffered great injustices in the pagan Arab society and were exposed to diverse kinds of humiliation prior to the mission of the Messenger of Allah (Peace be upon Him). They were treated like material property to be disposed of at the whim of the male guardian. They were not entitled to inherit from their parents or husbands. Arabs believed inheritance should only be granted to those who had martial abilities, like being able to ride a horse, fight, gain war booties and help protect the tribe and clan territory.Islam granted women contractual rights, conjugal rights, the right to inherit, to initiate divorce, to independently own and controlhis keenness to give everyone his due rights.

Abu Huraira narrated: “A black man, or a black woman, used to sweep
  the mosque and he, or she, died. The Prophet (PBUH) asked about her
  (or him). He was told that she (or he) had died. He said, ‘Why did you
  not inform me? Show me his grave (or her grave).’ So he went to her
  (his) grave and offered her (or his) funeral prayer”. (Muslim,Bukhari)

In the pre-Islamic era of Arabia, fathers commonly became extremely angry and disgraced with the birth of a female child into their family. Some considered it an evil omen. Allah, the Exalted, describes the father's reception of the news about the birth of a daughter:
(When the news of (the


value). These scores were categorized into 5 groups, from the lowest to the highest one, for finding the SES of individuals. These groups consisted of extremely poor (scores 100 to 224), poor (scores 225 to 348), moderate (scores 349 to 472), good (scores 473 to 596), and wealthy (scores 597 to 720). In addition, ordinal classification was defined for labeling patients in different groups of SES.

Results
=======

The frequency distribution of the SES characteristic of hospitalized patients with CVD is presented in [table 1](#t1-ARYA-15-260){ref-type="table"}. The ranking of the patients based on their education factors showed that most of them (81.3%) were in high school level. Likewise, the majority of them were in medium occupational level (73.9%), 5 or more in family size (33.4%), home owner (84.5%), and equal or lessfrom its list of out-links. Alternatively, the step of updating metadata summarizing Web pages may be carried out by resummarizing metadata information for each parent uniform resource locator in the search engine information to create new RDF summaries with updated information.
In order to carry out the modifying step, a uniform resource locator indicating a new location of the Web page indicated by the selected uniform resource locator is received. A plurality of parent uniform resource locators and child uniform resource locators related to the selected uniform resource locator are received. All instances of the selected uniform resource locator are replaced with the uniform resource locator indicating the new location of the Web page. Metadata summarizing Web pages is updated, the metadata referencing the selected uniform resource locator. The


PersonId to TeamPosition PK, or add a new field PositionNo to the PK. If the same person cannot have multiple positions inside the same team, add an alternate key on {TeamId, PersonId}.
2 Unfortunately, MS SQL Server is a bit more squeamish than some other DBMSes, and will refuse to do referential actions (such as ON DELETE CASCADE) on circular references like this. If you need referential actions, implement them via INSTEAD OF triggers.

A:

I think you should consider the difference between a "position" and a "role". In many organizations, multiple roles may exist: safety coordinator, purchasing, accounts payable, receptionist, ... Often, especially in smaller organizations, a single person may act in different roles at different times. It may even be that they report to different people when they actin different capacities (for example, the emergency responder may report to the safety coordinator, but the purchaser reports to head of operations.)
In order to properly reflect these things, the relationships in your database need to reflect, to the extent possible, the relationships that exist in real life. This probably means you will have multiple tables (as you already have), but it will keep things clean.
The other thing to keep in mind (and possibly worth reflecting in your database) is that many organizations are matrixed: people may be on certain project teams, and part of certain organizations. The electrical engineers may all report to the electrical engineering manager, but they might be working on different projects / products, and thus belong on different project teams.
Capturing all that accurately is


managers.
Table 3: teams Team name, Team ID, Manager ID, BelongsToTeam, Team description, ...
A table that describes every "organizational entity", with any auxiliary information that might be useful. The BelongsToTeam allows a hierarchical structure of teams, which helps with visualization.
Table 4: roles Role name, Team ID, Employee ID, isPrimary
This table describes who is in a given role. An employee with multiple roles will show up multiple times in this table, and may report to different managers depending on the role they have. I added an "isPrimary" field here - not sure if that is redundant. In a sense, if you start with the "primary" role of the employee in table 4, and find out who the team manager is in table 3, you should end up with the personmarried before the older one. 27 Complete this daughter’s wedding week. Then we’ll give you the younger one also. But you will have to work for another seven years.”

28 So Jacob completed the week with Leah. Then Laban gave him his daughter Rachel to be his wife. 29 Laban gave his female servant Bilhah to his daughter Rachel as her servant. 30 Jacob slept with Rachel also. He loved Rachel more than he loved Leah. And he worked for Laban for another seven years.

Jacob Becomes the Father of Many Children

31 The Lord saw that Jacob didn’t love Leah as much as he loved Rachel. So he let Leah have children. But Rachel wasn’t able to have children. 32 Leah became pregnant. She had a son. She named him


development plans and programs approved by the Department of Transportation and Communications
 To issue, amend, revise, suspend or cancel Certificates of Public Convenience or permits authorizing the operation of public land transportation services provided by motorized vehicles, and to prescribe the appropriate terms and conditions therefore;
 To determine, prescribe and approve and periodically review and adjust, reasonable fares, rates and other related charges, relative to the operation of public land transportation services provided by motorized vehicles;
To issue preliminary or permanent injunction, whether prohibitory or mandatory, in all cases in which it has jurisdiction, and in which cases the pertinent provisions of the Rules of Court shall apply;
To punish for contempt of the Board, both direct and indirect, in accordance with the pertinent provisions of, and the penaltiesregistration of all motor vehicles.

This was passed by House Speaker Pantaleon Alvarez, Cesar V. Sarmiento, Juan Pablo P. Bondoc, Bayani F. Fernando, Anna Katrina M. Enverga, Renato Unico, Winston Castelo, Emi Calixto Rubiano, and Alfred D. Vargas. The reason for this proposal is “create a central agency that will consolidate the functions of the LTO and LTFRB in order to avoid confusion as to which agency is tasked to maintain land transportation law and order in the Philippines.” The proposal of the LTO also seeks to address the need for a more comprehensive transportation policy that considers the “varied and complex areas in the land transportation industry”. Moreover, the explanatory notes states that some existing policies are inadequate, ineffective and already obsolete.

The board of directors of the proposed


arms on a rim around the pump axis. By means of their free ends, the spring arms are supported on a partition of the lower part at right angles to the pump axis and which surrounds the pump chamber in annular manner. This leads to a very space-consuming housing of the spiral springs, unfavourable spring characteristics and a relatively difficult action of the springs.Website Citation Information

Unless otherwise noted at the bottom of the individual page you are citing, I wrote all of the information on this website. The original publication date was in 2004. The information has remained in its original form with the exception of the occasional corrections in spelling and formatting changes.

Hand Made Wood Tankards

2017 EPIC AWARD WINNER FOR SCIENCE FICTION

A catastrophic pandemic ravages the globe, reducing the human population to extinction levels.

An arrogant bookworm, a doomsday prepper, a brilliant scientist, and a journal-keeping poet are among those who survive the disease that annihilated almost everyone else on the planet.

Not dying was the easy part.

Now, a year later, they navigate a bleak world…one without technology, without modern medicine, and without law and order. They must unify their diverse strengths


the link or make a purchase using the link. When you make a purchase, the price you pay will be the same whether you use the affiliate link or go directly to the vendor’s website using a non-affiliate link.

Note that movie ratings are from IMDB.com and the movie reviews are from Amazon.com1. Field of the Invention
The present general inventive concept relates to a digital broadcast transmitting/receiving system and a signal processing method thereof, and more particularly, to a digital broadcast transmitting/receiving system and a signal processing method thereof which can improve the receiving performance of the system by inserting a known sequence into a VSB (Vestigial Side Band) data stream and transmitting the data stream with the inserted known sequence.
2. Description of the Related Art
An ATSC (Advanced Television Systems Committee) VSB system that is an American-type digital terrestrial broadcasting system in a signal carrier type broadcasting system, and uses a field sync signal in the unit of 312 segments.
FIG. 1 is a block diagram illustrating the construction of a transmitter/receiver of an ATSC DTV standard as a general American-type


segment in the VSB data frame corresponds to one MPEG-2 packet, and is composed of a segment sync signal of four symbols and 828 data symbols.
n FIG. 2, the segment sync signal and the field sync signal are used for the synchronization and equalization in the digital broadcast receiver. That is, the field sync signal and the segment sync signal refer to known data between the digital broadcast transmitter and receiver, which is used as a reference signal when the equalization is performed in the receiver side.
As shown in FIG. 1, the VSB system of the American type digital terrestrial broadcasting system is a single carrier system, and thus has a drawback in that it is weak in a multi-path fading channel environment having the Doppler effect. Accordingly,Q:

is it possible to run background service with web service ,still activity not open and clear from recent app history

I have tried as below to resolve my problem but I have still find problem if remove app from app history service not run.
in my activity:
   // start background service by splash screen
    startService(new Intent(this, UpdateService.class));

in my manifest:
    <application
    android:allowBackup="true"
    android:icon="@drawable/demo"
    android:label="@string/app_name"
    android:theme="@style/Theme.AppCompat.Light" >
    <meta-data
        android:name="com.google.android.gms.version"
        android:value="@integer/google_play_services_version" />

    <activity
        android:name=".SplashScreen"
        android:label="@string/app_name"


Mark Chapman (broadcaster)

Andrew Mark "Chappers" Chapman (born 11 October 1973) is a British television presenter who, mainly working in sports, currently presents Match of the Day 2 and also hosts Saturday afternoons plus The Monday Night Club on 5 live Sport..

Early life
Chapman was born in Rochdale, Lancashire, but spent most of his youth in Sale on the other side of the city of Manchester. He attended Manchester Grammar School, and during his time there developed an interest in radio broadcasting, wanting to work for Radio 1 from the age of 13. He went on to gain a degree in French and Business Studies from the University of Hull.

Broadcasting career
Chapman began his career in 1996 as a continuity announcer on BBC Television, primarily working on BBC Two, before becomingand editors do not think it's newsworthy that a publisher can be summoned by a government bureaucrat, and grilled as to his political thoughts. I'm pleased, though, that the support from pundits has come not just from the right, but from the enlightened left.

Sounds a lot like LionHeart’s persecution in the UK. This is litigation Jihad at its worst.

Get a FREE TRIAL COPY of the The Gathering Storm eBook which includes the Forward by Walid Shoebat, Introduction, and first 50 pages of The Gathering Storm eBook. And sign up for my free WEEKLY STORM REPORT and receive a synopsis of the most important weekly news revealing the intimidation, infiltration and disinformation tactics used to soften-up the non-Muslim world for domination.

3 Comments:

Missaugua, huh? That's where Aqsa Parvez was murdered


A Hybrid Technique to Manage a Large Perigraft Seroma after an Open Abdominal Aortic Aneurysm Repair: A Case Report.
Perigraft seroma (PGS) is a relatively rare complication of aortoiliac reconstructive surgery. We, herein, describe a case of a large PGS that was managed by using a hybrid technique of relining the original graft with simultaneous open drainage. An 86-year-old man with a 17.3-cm diameter PGS after prosthetic bifurcated graft replacement for abdominal aortic aneurysm was admitted to our hospital. He presented with abdominal distension and discomfort and had difficulty in taking food. The entire relining of the original covered stent graft with GORE® EXCLUDER® using aortic extension cuff and iliac extenders and simultaneous open evacuation of PGS were successfully performed. The symptoms of the patient totally improved, and noRussia, and defiling the bed where they had
slept by employing a number of prostitutes to perform a ’golden showers
(urination) show in front of him. The hotel was known to be under FSB
control with microphones and concealed cameras in all the main rooms
to record anything they wanted to.

4. The Moscow Ritz

who said that s/he and several of the staff were aware of it at the time
and subsequently. S/he believed it had happened in 2013. Soui ce E
provided an introduction for a company ethnic Russian operative to
Source F, a female staffer at the hotel when TRUMP had stayed there, who
also confirmed the story. Speaking separately in June 2016, Source B (the
former top level Russian intelligence officer) asserted that TRUMP’s
unorthodox behavior in Russia over the years had provided the
authorities there with


y ,
particularly of late.

30 July 2016

COMPANY INTELLIGENCE REPORT 2016/100

RUSSIA/USA: GROWING BACKLASH IN KREMLIN TO DNC HACKING AND
TRUMP SUPPORT OPERATIONS

Summary

Head of PA IVANOV laments Russian intervention in US presidential
election and black PR against CLINTON and the DNC. Vows not to supply
intelligence to Kremlin PR operatives again. Advocates now sitting tight
and denying everything

Presidential spokesman PESKOV the main protagonist in Kremlin
campaign to aid TRUMP and damage CLINTON. He is now scared and
fears being made scapegoat by leadership for backlash in US. Problem
compounded by his botched intervention in recent Turkish crisis

Premier MEDVEDEV’S office furious over DNC hacking and associated
anti-Russian publicity. Want good relations with US and ability to travel
there. Refusing to support or help cover up after PESKOV

Talk now in Kremlin of TRUMP withdrawing from presidential race
altogether, but this still largely wishfulused for the meeting/s

– Pro-PUTIN leading Duma figure, KOSACHEV, reportedly involved as “plausibly deniable”
facilitator and may have participated in the August meeting/s with COHEN

Detail

1. Speaking to a compatriot and friend on 19 October 2016, a Kremlin insider provided further
details of reported clandestine meeting/s between Republican presidential candidate, Donald
TRUMP’S lawyer Michael COHEN and Kremlin representatives in August 2016. Although the
communication between them had to be cryptic for security reasons, the Kremlin insider
clearly indicated to his/her friend that the reported contact/s took place in Prague, Czech
Republic.

2. Continuing on this theme, the Kremlin insider highlighted the importance of the Russian
parastatal organisation, Rossotrudnichestvo, in this contact between TRUMP campaign
representative/s and Kremlin officials. Rossotrudnichestvo was being used as cover for this
relationship and its office in Prague may well have been used to host


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Forum on Food Sovereignty in Korea: “Building and strengthening alliance with Korean organizations for food sovereignty”

Seoul, July 2007In the first week of July 2007, La Via Campesina (LVC) invited by the Korean Peasant League (KPL) and the Korean Woman Peasant Association (KWPA) took part in the Korean Social forum. LVC delegation consisted of CNOP Mali, Confédération Paysanne (France), ANFPA Nepal, AOP Thailand, FSPI Indonesia, NOUMINREN Japan, CANEZ Venezuela. During the Social Forum, one day was dedicated to an international forum on food sovereignty.

For us in La Via Campesina, our Korean members are a great source of inspiration when we look at their struggle for Food Sovereignty, Korean Reunification, against FTA US-Korea, and the hard struggle against WTO in Cancun and Hong Kongto fight for farmer at the state level.

LVC delegation was invited by Korea Solidarity for Progress (KSP), an alliance of fifty sect orals and regional representative and twenty five organizations and three regions committed to participate in the organizing committee. This KSP was inaugurated in January 9, 2007 with the participation of 1000 representatives and issued a declaration of inauguration: “New Era of People’s victory through the alliance of progressive movements”

Forum on food sovereignty

The forum on food sovereignty was attended by about 200 peoples in the hall of Duksung Women’s university. The objectives of the forum was to establish and spread the concept of food sovereignty in Korea, to get a better understanding of the food sovereignty situation in other countries especially the country who included food sovereignty


east to the west coast for distance of about 241 kilometer. Seoul, the capital of South Korea, is the largest urban center, having 10 million residents. Busan is the second largest city, with a population over four million.

The country has a presidential system, where the president and the members of the National Assembly are elected by direct vote. Under Korea’s presidential system, the president performs his executive function through the State Council made up of 15 to 30 members and presided over by the president, who is solely responsible for deciding all important government policies. The prime minister is appointed by the president and approved by National Assembly.my back and to keep my face out of the water.

For #3, Dick and Jane would be OK as far as the protest committee was concerned, but not the USCG or the SFPD.

In addition, Dick and Jane need to carry a USCG Type 3 PFD on board their Hobie 16 for each person; A CE 50 will not do. They don’t have to wear it, but they must have it. In addition, they need to carry a throwable device like this.

Dick and Jane had a horrible day.

CUT TO THE CHASE

- All boats must carry a USCG approved PFD on board for each person on board.

- All boats over 16’ must carry a throwable USCG Type IV device on board.

- Children must wear a PFD (state requirements apply here


is a member of the US Marine Safety Association. Associates in his group are certified by the AMSEA as trainers, are moderators for the US SAILING Safety at Sea Conferences and USCG 100 ton license programs. Kirk was an umpire for the 32nd America’s Cup in Valencia Spain and was chairman of the US SAILING Umpire Committee, served on the US SAILING Appeals Committee and was a member of the ISAF International Umpire Sub Committee. Kirk is the factory representative for Stohlquist Life Jackets.

I would also like to mention that just because it is approved by the Coast Guard, it may not be approved by the state. This summer while boating in Michigan, my nephew received a $100 ticket because the life jacket his niece was wearing, eventop considered a "thin" shirt to prevent snagging?

As far as the other items, I have been ticketed twice for not having the required items as stated by our state's wildlife resources commission, but in court I used the Federal Law stating that states may not regulate non-motorized vessels to have the citations thrown out. I'm not saying that having an abundance of safety gear on the boat isn't a good idea, but there are some things I'm not going to carry on my sailboats.

The Zhik "swim aid" shown above will easily float a 200 pound person with no assist from that person.

But maybe not enough flotation in rougher conditions, currents or while wearing other gear as experienced by the author.

There is some leeway on volume verses PFD sizing


in the USCG code, so Stohlquist is using "Graded" sizing with their new vests coming to us this winter. Smaller vests will have less flotation foam for better comfort.

Look for the Hobie Thin-Back and Edge models to be available after the first of the year (2015).

There are multiple types of PFD's and the USCG requires at a minimum a Type III. In theory the average person needs less than 15.5 lbs. of floatation but the USCG cannot do a chart based on BMI as a practical manner. This type is for "near-shore" use, and it is pushing the boundary to use this type in SF Bay.

Inflatable PFD's can be Class I, II, or III depending upon their performance, which is not limited to level of flotation alone. Theyalso must be worn at all times when out on the water. The Mustang and other inflatables also are required to have a means to inflate them orally should the CO2 cartridge fail.

There are hybrid PFD's like the Kokatat SeaO2 that provides 7.5 lbs. of floatation but can be inflated orally or with a CO2 cartridge (hence its name) to provide 22.5 lbs. of floatation, or a non inflating PFD that provides. At 22 lbs. it qualifies as a Type I PFD for offshore use.

The requirements may seem silly, but I witnessed a race in SF Bay where on a downwind run with a spinnaker running a boat broached and went down in seconds right in front of the St. Francis Yacht Club and the skipper was not