// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;



const int inf = 0x3f3f3f3f;

const int maxv = 200010;

const int maxe = 100010;

int vertex, RailEdge, RoadEdge, cnt;

int RailHead[maxv], RoadHead[maxv], number[maxv], ans[maxv];

bool vis[maxv];

vector <int> v[maxv];

struct Edge

{

    int to, next;

}e[maxe * 4];



void addEdge(int *head, int from, int to)

{

    e[cnt].next = head[from];

    e[cnt].to = to;

    head[from] = cnt++;

}



void getNumberDFS(int cur)

{

    vis[cur] = true;

    number[cur] = cnt;

    for (int i = RoadHead[cur]; ~i; i = e[i].next)

    {

        int to = e[i].to;

        if (!vis[to])

            getNumberDFS(to);

    }

}



vector <int> valid;



void DFS(int cur)

{

    vis[cur] = true;

    int curNumber = number[cur];

    if (v[curNumber].size() == 0)

        valid.push_back(curNumber);

    v[curNumber].push_back(cur);

    for (int i = RailHead[cur]; ~i; i = e[i].next)

    {

        if (!vis[e[i].to])

            DFS(e[i].to);

    }

}



int main()

{

    memset(RailHead, -1, sizeof(RailHead));

    memset(RoadHead, -1, sizeof(RoadHead));

    for (int i = 0; i < maxv; i++)

        ans[i] = 1;





    int from, to;

    scanf("%d %d %d", &vertex, &RoadEdge, &RailEdge);

    for (int i = 0; i < RoadEdge; i++)

    {

        scanf("%d %d", &from, &to);

        addEdge(RoadHead, from, to);

        addEdge(RoadHead, to, from);

    }

    for (int i = 0; i < RailEdge; i++)

    {

        scanf("%d %d", &from, &to);

        addEdge(RailHead, from, to);

        addEdge(RailHead, to, from);

    }

    cnt = 0;

    for (int i = 1; i <= vertex; i++)

    {

        if (!vis[i])

        {

            getNumberDFS(i);

            cnt++;

        }

    }

//    printf("number:\n");

//    for (int i = 1; i <= vertex; i++)

//        printf("%d%c", number[i], i == vertex ? '\n' : ' ');

    memset(vis, false, sizeof(vis));

    for (int i = 1; i <= vertex; i++)

    {

        if (!vis[i])

        {

            DFS(i);

            for (int i = 0; i < valid.size(); i++)

            {

                int id = valid[i];

                for (int j = 0; j < v[id].size(); j++)

                    ans[v[id][j]] += v[id].size() - 1;

                v[id].clear();

            }

            valid.clear();

        }

    }

//    printf("answer:\n");

    for (int i = 1; i <= vertex; i++)

        printf("%d%c", ans[i], i == vertex ? '\n' : ' ');

    return 0;

}

/*

7 5 5

1 2

2 3

2 5

6 7

5 6

3 5

4 5

3 4

6 7

5 6

 

 1 1 4 1 4 4 4

 */






// Faster C++ solution for the same problem (measured speedup: 9.42869377446483x):
#include<bits/stdc++.h>

using namespace std;

int par1[200001],par2[200001];

vector<pair<int,int>> idx;

map<pair<int,int>,int> cnt;

int rep1(int n)

{

    if(par1[n]==n)

        return n;

    return par1[n]=rep1(par1[n]);

}

int rep2(int n)

{

    if(par2[n]==n)

        return n;

    return par2[n]=rep2(par2[n]);

}

int main()

{

    int i,j;

    int n,k,l;

    int a,b,res=0;

    scanf("%d %d %d",&n,&k,&l);

    for(i=1;i<=n;i++){

        par1[i]=i;

        par2[i]=i;

    }

    for(i=0;i<k;i++){

        scanf("%d %d",&a,&b);

        swap(a,b);

        int r1=rep1(a);

        int r2=rep1(b);

        par1[r1]=r2;

    }

    for(i=0;i<l;i++){

        scanf("%d %d",&a,&b);

        int r1=rep2(a);

        int r2=rep2(b);

        par2[r2]=r1;

    }

    for(i=1;i<=n;i++){



        idx.push_back(make_pair(rep1(i),rep2(i)));

    }



    for(i=0;i<idx.size();i++){

            //assert(idx[i].first == idx[i].second);

        cnt[idx[i]]++;

       // printf("%d %d\n",idx[i].first,idx[i].second);

    }

    for(i=0;i<idx.size();i++)

        printf("%d ",cnt[idx[i]]);

}