// Slower C++ solution:
// Created by ahmed_drawy on 10/09/19.

///dp educational contest atcoder - vjudge

#include <bits/stdc++.h>

#include <string.h>

#pragma clang diagnostic push

#pragma ide diagnostic ignored "OCUnusedMacroInspection"

using namespace std;

#define lp(i,start , end)       for(int i = start ; i<end ; ++i)

#define lllp(i,start , end)       for(ll i = start ; i<end ; ++i)

#define inN(arr ,  n) for(int i = 0 ; i< n ; ++i)  cin>>arr[i];

#define Rlp(i,start , end)      for(int i = start ; i>end ; --i)

#define all(v)                   ((v).begin(),(v).end())

#define sz(v)                  (int)((v).size())

#define clr(v,d)                memset(v , d , sizeof(v))

#define inf 0x3f3f3f3f

//#define dbg (v)    for(auto it : v)cout<<it<<' ';

typedef long long               ll;

typedef vector<int>             vi;

typedef vector  <ll>            vll;

typedef vector<vector<int> >    adj;

typedef pair<int ,int>          pii;

const double EPS =1e-7;

const int OO = 1e6;

#define endl '\n'

#define cint(c) (int)c -'0';

#define itc(c) (char)c +'A';

bool sortpair( const pair<int , int> & x, const pair<int , int> & y){

    return  x.first != y.first ? x.first < y.first : x.second > y.second ;

}

int dcomp(double x , double y){

    return fabs(x-y) <= EPS? 0: x>y?1:-1;

}



void smile() {

    ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL);

#ifndef ONLINE_JUDGE

//    freopen("/home/tw3/Desktop/Desktop/training/in.txt", "r", stdin);

//    freopen("/home/tw3/Desktop/Desktop/training/out.txt" , "w" , stdout);

#endif

}

#define fastin smile()



int n ;

const int N = 1e5 +3;

ll dp[N];

int h[N];

//ll solve(int indx , int state){

//    if(indx == n-1 )return 0 ;

//    ll &ret = dp[indx  ] [ state];

//    if(~ret )

//        return ret;

//    ret=  INT_MAX;

//    for (int i = 1; i <=2 && i+indx < n ; ++i) {

//        ret = min(ret , abs(h[indx]  - h[indx+ i])+solve(indx + i , i ));

//    }

//    return ret ;

//}

int main() {

    fastin;

    cin >> n;

    inN(h,  n );

    clr(dp , 0);

    for (int j = 1; j <n ; ++j) {

        if(j>=2){

            dp[j] = min(dp[j-1] + abs(h[j-1] - h[j]) , abs(h[j-2] - h[j])+dp[j-2]);

        }

        else if(j ==1){

            dp[j] = abs(h[j] - h[j-1])+dp[j-1];

        }

    }

    cout << dp[n-1];

//

//    clr(dp , -1);

//    cout << solve(0, 1)<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 1.2879436191609752x):
#include <bits/stdc++.h>

using namespace std;



#define ll long long

#define mp make_pair

#define pb push_back

#define loop(i, n)      for(int i = 0 ; i < n ; ++i)

#define rloop(i, n)     for(int i = int(n)-1 ; i >= 0 ; --i)

#define loopOne(i, n)   for(int i = 1 ; i <= n; ++i)

#define range(i, a, b)  for(int i = int(a) ; i <= int(b) ; ++i)

#define sz(x)   int(x.size())



void GO(){

    ios_base::sync_with_stdio(false);

    cin.tie(0);

    cout.tie(0);

}

const ll N = 1e5+100, OO = 1e9;

int mx = -OO, mn = OO;

int dx[4] = {0, 0, 1, -1};

int dy[4] = {1, -1, 0, 0};



int arr[N], n, memo[N], res;



int Solve(int idx){



    if(memo[idx] != -1)    return memo[idx];

    int op1 = OO, op2 = OO;

    if(idx + 1 >= n)    return 0;

    op1 = abs(arr[idx]-arr[idx+1]) + Solve(idx+1);

    if(idx + 2 < n)

        op2 = abs(arr[idx]-arr[idx+2]) + Solve(idx+2);



    return memo[idx] = min(op1, op2);

}



int main() {

//    freopen("input.txt", "r", stdin);

//    freopen("output.txt", "w", stdout);

    GO();

    scanf("%d", &n);

    for(int i = 0; i < n; ++i){

        scanf("%d", arr+i);

    }

    memset(memo, -1, sizeof(memo));

    printf("%d", Solve(0));

    return 0;

}