// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;



typedef long long ll;

typedef vector<int> vi;



#define Forn(i, n) for(int i=1; i<=(n); i++)

#define forn(i, n) for(int i=0; i<(n); i++)

#define lid id<<1|1

#define rid (id<<1)+2

#define foreach(it, a) for(__typeof((a).begin()) it=(a).begin(); it!=(a).end(); it++)

#define pb push_back

#define mp make_pair

#define all(x) (x).begin(), (x).end()

#define mid l+r>>1

#define lson lid, l, mid

#define rson rid, mid, r 

#define f first

#define s second

#define int long long



const int MAX=1e5+5;



int N, M, ptr, ret, a[MAX];



struct Seg

{

    int tag1[MAX*4], tag2[MAX*4];

    Seg()

    {

        memset(tag1, 0, sizeof(tag1));

        memset(tag2, 0, sizeof(tag2));

    }

    inline void update(int id, int l, int r, int a, int b, int k1, int b1)

    {

       if(r<=a||b<=l) return;

       if(a<=l&&r<=b)

       {

           tag1[id]+=k1;

           tag2[id]+=b1;

           return;

       }

       update(lson, a, b, k1, b1);

       update(rson, a, b, k1, b1);

    }

    inline void update(int l, int r, int k1, int b1)

    {

        if(l>=r) return;

        update(0, 0, ptr, l, r, k1, b1);

    }

    inline void print(int id, int l, int r, int &ret)

    {

        if(l+1==r)

        {

            if(l) ret=min(ret, tag1[id]*l+tag2[id]);

            return;

        }

        

        tag1[lid]+=tag1[id];

        tag2[lid]+=tag2[id];

        

        tag1[rid]+=tag1[id];

        tag2[rid]+=tag2[id];

        

        print(lson, ret);

        print(rson, ret);

    }

}S;



signed main()

{

    scanf("%lld %lld", &N, &M);

    forn(i, N)

        scanf("%lld", &a[i]);

    ptr=M+1;

    

    forn(i, N-1)

    {

        if(a[i]==a[i+1]) continue;

        if(a[i]<a[i+1])

        {

            S.update(1, a[i]+1, 0, a[i+1]-a[i]);

            S.update(a[i]+1, a[i+1]+1, -1, a[i+1]+1);

            S.update(a[i+1]+1, ptr, 0, a[i+1]-a[i]);

        }

        else

        {

            S.update(1, a[i+1]+1, -1, a[i+1]+1);

            S.update(a[i+1]+1, a[i]+1, 0, M-a[i]+a[i+1]);

            S.update(a[i]+1, ptr, -1, M+a[i+1]+1);

        }

    }

    ret=2e18;

    S.print(0, 0, ptr, ret);

    printf("%lld\n", ret);

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 39.64928007784259x):
#include<cstdio>

#include<algorithm>

using namespace std;

#define ll long long

const int maxn=1e5+5;

const ll INF=0x3f3f3f3f3f3f3f3f;

int a[maxn];

struct node

{

    int l,r;

    ll diff,lz;

}tree[4*maxn];

void build(int l,int r,int cur)

{

    tree[cur].l=l;

    tree[cur].r=r;

    if(l==r)

        return;

    int mid=(l+r)>>1;

    build(l,mid,cur<<1);

    build(mid+1,r,cur<<1|1);

    return;

}

void push_up(int cur)

{

    tree[cur].diff=tree[cur<<1].diff+tree[cur<<1|1].diff;

    return;

}

void push_down(int cur)

{

    if(tree[cur].lz!=0)

    {

        tree[cur<<1].diff+=(tree[cur<<1].r-tree[cur<<1].l+1)*tree[cur].lz;

        tree[cur<<1].lz+=tree[cur].lz;

        tree[cur<<1|1].diff+=(tree[cur<<1|1].r-tree[cur<<1|1].l+1)*tree[cur].lz;

        tree[cur<<1|1].lz+=tree[cur].lz;

        tree[cur].lz=0;

    }

    return;

}

void add(int l,int r,ll val,int cur)

{

    if(l>r) return;

    if(tree[cur].l>=l&&tree[cur].r<=r)

    {

        tree[cur].diff+=(tree[cur].r-tree[cur].l+1)*val;

        tree[cur].lz+=val;

        return;

    }

    if(tree[cur].l>r||tree[cur].r<l)

        return;

    push_down(cur);

    add(l,r,val,cur<<1);

    add(l,r,val,cur<<1|1);

    push_up(cur);

    return;

}

ll diff0[maxn];

void together(int cur)

{

    if(tree[cur].l==tree[cur].r)

    {

        diff0[tree[cur].l]=tree[cur].diff;

        return;

    }

    push_down(cur);

    together(cur<<1);

    together(cur<<1|1);

    push_up(cur);

    return;

}

ll minn[maxn];

int main()

{

    int n,m;

    scanf("%d%d",&n,&m);

    for(int i=1;i<=n;i++)

        scanf("%d",&a[i]);

    build(0,m-1,1);

    ll base=0;

    for(int i=1;i<n;i++)

    {

        if(a[i]<a[i+1])

        {

            base+=(ll)(a[i+1]-a[i]);

            add(a[i]+1,a[i+1]-1,-1,1);

            add(a[i+1],a[i+1],a[i+1]-a[i]-1,1);

        }

        else

        {

            base+=(ll)(m-a[i]+a[i+1]);

            add(0,0,-(m-a[i]),1);

            add(1,a[i+1]-1,-1,1);

            add(a[i+1],a[i+1],m-a[i]+a[i+1]-1,1);

            add(a[i]+1,m-1,-1,1);

        }

    }

    together(1);

    minn[0]=base;

    for(int i=1;i<=m;i++)

        minn[i]=minn[i-1]+diff0[i-1];

    ll ans=INF;

    for(int i=1;i<=m;i++)

        ans=min(ans,minn[i]);

    printf("%lld\n",ans);

    return 0;

}

/*

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 1 5 1 4

 8 9 7 5 6 9

 

 9 9 8 7 6 5 4 3 2

 */