// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

typedef long long int lli;

typedef long double ld;

const int oo = 1e9;

//const int mod = 1e9+9;

/*ll gcd(ll x, ll y){return (y ? gcd(y, x%y) : x); }

*ll lcm(ll x, ll y){return x*(y/gcd(x,y));}

*void exEuclid(int a, int b){

	if(b==0){x = 1; y=0; d=a; return ;}

	exEuclid(b, a%b);

	int x1 = y;

	int y1 = x-(a/b)*y;

	x = x1; 100000

	y = y1;

} 

* */

//===========================================================//

int n;

const int nx = 1e5+5;

int ac[nx][3];

int dp[3][nx];

int go(int a, int i){

	if(i == n) return 0;

	if(dp[a][i] != -1) return dp[a][i];

	int& ans = dp[a][i];

	

	if(a==0){

		ans=max(ans, go(1, i+1)+ac[i][0]);

		ans=max(ans, go(2, i+1)+ac[i][0]);

	}

	if(a==1){

		ans=max(ans, go(0, i+1)+ac[i][1]);

		ans=max(ans, go(2, i+1)+ac[i][1]);

	}

	if(a==2){

		ans=max(ans, go(0, i+1)+ac[i][2]);

		ans=max(ans, go(1, i+1)+ac[i][2]);

	}

	

	return ans;

}

int main(){

	cin>>n;

	for(int i=0; i<n; i++) cin>>ac[i][0]>>ac[i][1]>>ac[i][2];

	memset(dp, -1, sizeof dp);

	cout<<max(go(0,0),max(go(1,0),go(2,0)))<<"\n";

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.206882119523429x):




/******************************************************/

/******************************************************/

/**                                                  **/

/**            BISMILLAHIR RAHMANIR RAHIM            **/

/**         REAZ AHAMMED CHOWDHURY - reaziii         **/

/**  Department of Computer Science and Engineering  **/

/*         INSTITUTE OF SCIENCE AND TECHNOLOGY       **/

/**                                                  **/

/******************************************************/

/******************************************************/







#include<bits/stdc++.h>

#define sc(x)        scanf("%lld",&x)

#define pcase(x)     printf("Case %d: ",x++)

#define pn           printf("\n")

#define fri(f)       for(int i=0;i<f;i++)

#define frj(f)       for(int j=0;j<f;j++)

#define reset(x,e)   memset(x,e,sizeof(x))

#define all(x)       x.begin(),x.end()

#define input        freopen("input.txt","r",stdin);

#define output       freopen("output.txt","w",stdout)

#define infi         INT_MAX

#define m_v          3000000

#define pii          pair<int,int>

#define pch          pair<char,char>

#define pll          pair<ll,ll>

#define mgraph       map<int,vector<int> >

#define mp           make_pair

#define pb           push_back

#define clr(x)       memset(x,0,sizeof(x))

#define frx(x,y)     for(int x=0;x<y;x++)

#define ff           first

#define ss           second

using namespace std;

typedef long long int ll;

typedef unsigned long long int ull;

bool checkbitt(ll num, int pos);

ll setbitt(ll num, ll pos);

ll resetbitt(ll num, int pos);

void read(int *aa, int sz) {fri(sz) scanf("%d", (aa + i));}

void read(ll *aa, int sz) {fri(sz) scanf("%lld", (aa + i));}

void read(ll *aa, int s, int e) {for (int i = s; i < s + e; i++)scanf("%lld", (aa + i));}

void read(int *aa, int s, int e) {for (int i = s; i < s + e; i++)scanf("%d", (aa + i));}

const ll mod =       1e9 + 7;

const ll N =     1e6 + 10;



//.................___Start from here___.................//

//.................._____________________................//



int n;

int dp[N][5];

int a[N], b[N], c[N];

int A = 1, B = 2, C = 3;

int solve() {

	cin >> n;



	for (int i = 1; i <= n; i++) {

		cin >> a[i] >> b[i] >> c[i];

	}





	for (int i = n; i >= 1; i--) {

		dp[i][A] = max(dp[i + 1][B], dp[i + 1][C]) + a[i];

		dp[i][B] = max(dp[i + 1][A], dp[i + 1][C]) + b[i];

		dp[i][C] = max(dp[i + 1][A], dp[i + 1][B]) + c[i];

	}



	cout << max(dp[1][A], max(dp[1][B], dp[1][C])) << endl;







	return 0;

}

int main() {

// #ifndef ONLINE_JUDGE

// 	input;

// 	output;

// #endif

// #ifdef ONLINE_JUDGE

// 	ios_base::sync_with_stdio(false);

// 	cin.tie(0);

// #endif

	int cs = 1;

	int cn = 1;

	//cin>>cs;

	while (cs--) {

		solve();



	}

}





bool checkbitt(ll num, int pos) {return (num >> pos) & 1;}

ll setbitt(ll num, ll pos) {return (1 << pos) | num;}

ll resetbitt(ll num, int pos) {if (!checkbitt(num, pos)) return num; else return (1 << pos)^num;}