// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;



#define ENGZ ios::sync_with_stdio(0);cin.tie(0);ios_base::sync_with_stdio(0);

#define sfi(x) scanf("%d" , &x)

#define sfi2(x, y) scanf("%d%d" , &x,&y)

#define sfl2(x, y) scanf("%I64d%I64d" , &x,&y)

#define sfl(x) scanf("%I64d" , &x)

#define sfl3(x, y, z) scanf("%I64d%I64d%I64d", &x, &y, &z)

#define sfd(x) scanf("%lf", &x)

#define sfd2(x, y) scanf("%lf", &x, &y)

#define sfs(x) scanf("%s", &x)

#define testv(x) cerr << x << ' '

#define wtf(s) freopen((s), "w", stdout)

#define rff(s) freopen((s), "r", stdin)

#define test cerr << "here"

#define fst(x) cout << fixed << setprecision(x)

#define mod 1000000007

#define pi (2 * acos(0))

typedef long double ld;

typedef long long ll;



int par[200005], rnk[200005];



int findp(int x)

{

    if (par[x] == x)

        return x;

    return par[x] = findp(par[x]);

}



bool iscon(int x, int y)

{

    if (findp(x) == findp(y))

        return true;

    return false;

}



void con(int x, int y)

{

    int px = findp(x), py = findp(y);

    if (rnk[px] > rnk[py])

        par[py] = px;

    else if (rnk[px] < rnk[py])

        par[px] = py;

    else

        par[px] = py, rnk[px]++;

}





    pair<pair<ll, ll>, int> a[100005], b[100005];

int main()

{

    ENGZ

    int n;

    ll ans = 0;

    for (int i = 0; i < 100005; i++)

        par[i] = i;

    cin >> n;

    for (int i = 0; i < n; i++)

    {

        cin >> a[i].first.first >> a[i].first.second;

        b[i].first.first = a[i].first.second;

        b[i].first.second = a[i].first.first;

        a[i].second = b[i].second = i;

    }

    sort(a, a + n);

    sort(b, b + n);

    map<ll, vector<pair<int, int>>> mp;

    for (int i = 0; i < n - 1; i++)

    {

        mp[abs(a[i].first.first - a[i + 1].first.first)].push_back({a[i].second, a[i + 1].second});

        mp[abs(b[i].first.first - b[i + 1].first.first)].push_back({b[i].second, b[i + 1].second});

    }

    for (auto it: mp)

    {

        for (auto i: it.second)

        {

            if (!iscon(i.first, i.second))

                con(i.first, i.second), ans += it.first;

        }

    }

    cout << ans;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.4045734908987992x):
#include <bits/stdc++.h>



using namespace std;

#define ll long long

#define f first

#define s second

ll n,x,y,tmp,ans;



int par[100005] , sz[100005];



int findPar(int node)

{

    if (par[node]==node) return node;

    return par[node] = findPar(par[node]);

}



void mergeCom(int node , int node2)

{

    int led = findPar(node) , led2 = findPar(node2);



    if (sz[led] > sz[led2])

    {

        par[led2]=led , sz[led] += sz[led2];

    }

    else

    {

        par[led]=led2 , sz[led2] += sz[led];

    }

}



int main()

{

    cin >> n;

    pair < pair<ll,ll> , ll> arr[n+1] , arr2[n+1];

    vector <pair<ll , pair<ll,ll> > > vec;



    for (int i=1; i<=n; i++)

    {

        cin >> x >> y;

        arr[i].f.f=x , arr[i].f.s=y , arr[i].s=i;

        arr2[i].f.f=y , arr2[i].f.s=x , arr2[i].s=i;

        par[i]=i , sz[i]=1;

    }

    sort(arr+1,arr+n+1) , sort(arr2+1,arr2+n+1);

    for (int i=1; i<n; i++)

    {

        tmp = min(abs(arr[i+1].f.f-arr[i].f.f) , abs(arr[i+1].f.s-arr[i].f.s));

        vec.push_back({tmp , {arr[i+1].s , arr[i].s}});



        tmp = min(abs(arr2[i+1].f.f-arr2[i].f.f) , abs(arr2[i+1].f.s-arr2[i].f.s));

        vec.push_back({tmp , {arr2[i+1].s , arr2[i].s}});

    }



    sort(vec.begin() , vec.end());

    tmp = n-1;

    for (int i=0; i<vec.size(); i++)

    {

        if (!tmp) break;

        x = vec[i].s.f , y = vec[i].s.s;

        if (findPar(x)==findPar(y)) continue;

        ans += vec[i].f , tmp--;

        mergeCom(vec[i].s.f , vec[i].s.s);

    }

    cout << ans << "\n";



    return 0;

}