// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;



const int N = 2e5 + 5;



struct point {

    int x, y, id;

} a[N];



bool cmp1(const point& a, const point& b) {

    if (a.x != b.x) {

        return a.x < b.x;

    }

    return a.y < b.y;

}



bool cmp2(const point& a, const point& b) {

    if (a.y != b.y) {

        return a.y < b.y;

    }

    return a.x < b.x;

}



int n;

bool visited[N];

vector<pair<long long, int> > g[N];



long long prim(int x) {

    priority_queue<pair<long long, int>, vector<pair<long long, int> >, greater<pair<long long, int> > > pq;

    long long ans = 0;

    pq.push({0, x});

    while(!pq.empty()) {

        pair<long long, int> p = pq.top();

        pq.pop();

        x = p.second;

        if (visited[x]) {

        	continue;

		}

        ans += p.first;

        visited[x] = true;

        for(int i = 0; i < g[x].size(); i++) {

            int y = g[x][i].second;

            if (!visited[y]) {

            	pq.push(g[x][i]);

            }

        }

    }

    return ans;

}



int main() {

	ios::sync_with_stdio(false);

	cin.tie(nullptr);

	cin >> n;

	for (int i = 0; i < n; i++) {

		cin >> a[i].x >> a[i].y;

		a[i].id = i + 1;

	}

	sort(a, a + n, cmp1);

	for (int i = 1; i < n; i++) {

		g[a[i].id].push_back({abs(a[i].x - a[i - 1].x), a[i - 1].id});

		g[a[i - 1].id].push_back({abs(a[i].x - a[i - 1].x), a[i].id});

	}

	sort(a, a + n, cmp2);

	for (int i = 1; i < n; i++) {

		g[a[i].id].push_back({abs(a[i].y - a[i - 1].y), a[i - 1].id});

		g[a[i - 1].id].push_back({abs(a[i].y - a[i - 1].y), a[i].id});

	}

	cout << prim(1) << '\n';

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.6374747807194636x):
#include <bits/stdc++.h>

using namespace std;

#define ll long long

struct p {

	int x, y;

	int indx;

};

const int N = 1e5 + 5;

p points[N];

int n;

int par[N];

int get(int n) {

	if (par[n] == n) return n;

	return par[n] = get(par[n]);

}

vector<int> g[N];

void solve() {

	for (int i = 0; i < N; i++)

		par[i] = i;

	vector<pair<int, pair<int, int> >> edg;

	for (int i = 0; i < n; i++) {

//		g[i].clear();

//		g[i].resize(n);

		for (int j = 0; j < g[i].size(); j++) {

//			g[i][j] = j;

			int v = g[i][j];

			ll c = min(abs(points[i].x - points[v].x),

					abs(points[i].y - points[v].y));

			edg.push_back(make_pair(c, make_pair(i, v)));

		}

	}

	sort(edg.begin(), edg.end());

	ll ans = 0;

	for (int i = 0; i < edg.size(); i++) {

		int u = edg[i].second.first;

		int v = edg[i].second.second;

		int r1 = get(u);

		int r2 = get(v);

		if (r1 == r2) continue;

		//cout << u << "  " << v << endl;

		ans += edg[i].first;

		par[r1] = r2;

	}

	cout << ans << endl;

}

void gen(vector<pair<int, int> > &a, vector<pair<int, int> > &b) {



	sort(b.begin(), b.end());



	for (int i = 0; i < a.size(); i++) {



		auto it = lower_bound(b.begin(), b.end(), make_pair(a[i].first, -1));

		if (it != b.end()) {

			g[a[i].second].push_back(it->second);

			g[it->second].push_back(a[i].second);

		}

		if (it != b.begin()) {

			it--;



			g[a[i].second].push_back(it->second);

			g[it->second].push_back(a[i].second);

		}

	}

}

int main() {

	ios_base::sync_with_stdio(0);

	cin.tie(0);

	cin >> n;

	vector<pair<int, pair<int, int> > > v;

	for (int i = 0; i < n; i++) {

		cin >> points[i].x >> points[i].y;

		points[i].indx = i;

		v.push_back(make_pair(points[i].x, make_pair(points[i].y, i)));

	}

	sort(v.begin(), v.end());

	vector<pair<int, int> > last, cur;

	for (int i = 0; i < n;) {

		int X = v[i].first;

		while (i < n && v[i].first == X) {

			cur.push_back(v[i].second);

			i++;

		}

		if (last.size()) gen(last, cur);

		last = cur;

		cur.clear();

	}

	for (int i = 0; i + 1 < n; i++) {

		int u = v[i].second.second;

		int V = v[i + 1].second.second;

		g[u].push_back(V);

		g[V].push_back(u);

	}

	for (int i = 0; i < n; i++)

		swap(v[i].first, v[i].second.first);

	last.clear();

	sort(v.begin(), v.end());

	for (int i = 0; i < n;) {

		int X = v[i].first;



		while (i < n && v[i].first == X) {

			cur.push_back(v[i].second);

			i++;

		}

		if (last.size()) gen(last, cur);

		last = cur;

		cur.clear();

	}

	for (int i = 0; i + 1 < n; i++) {

		int u = v[i].second.second;

		int V = v[i + 1].second.second;

		g[u].push_back(V);

		g[V].push_back(u);

	}



	solve();

	return 0;

}