stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include <stdio.h>

#include <string.h>

#include <iostream>

#include <algorithm>

#include <math.h>

#include <vector>

#include <queue>

using namespace std;

int n,m,p;

int sx,sy;

char s[1505][1505];

struct node{

	int x,y,step;

	node(int sx,int sy,int step)

	{

		this->x=sx;this->y=sy;this->step=step;

	}

};

int dx[4]={0,0,-1,1};

int dy[4]={1,-1,0,0};

int vis[1505][1500];

node bfs(node u,int pos)

{

	queue<node> q;

	while(!q.empty())q.pop();

	q.push(u);

	

	while(!q.empty())

	{

		node v=q.front();q.pop();

		if(s[v.x][v.y]==pos+'0') return v;

		for(int i=0;i<4;i++)

		{

			int x=v.x+dx[i];

			int y=v.y+dy[i];

			if(x>=1&&x<=n&&y>=1&&y<=m&&s[x][y]!='X'&&vis[x][y]==0)

			{

				vis[x][y]=1;

				node now=node(x,y,v.step+1);

				q.push(now);

			}

		}

	}

}

int main()

{

	while(cin>>n>>m>>p)

	{

		int ans=0;

		for(int i=1;i<=n;i++)

		{

			cin>>s[i]+1;

			for(int j=1;j<=m;j++)

			{

				if(s[i][j]=='S') sx=i,sy=j;

			}

		}

		node u=node(sx,sy,0);	

		for(int i=1;i<=p;i++)

		{		

			memset(vis,0,sizeof(vis));

			vis[u.x][u.y]=1;

			u=bfs(u,i);

			ans+=u.step;

			u.step=0;

		}

		cout<<ans<<endl;

	}

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.1213644898033952x):
#include <cstdio>

#include <cmath>

#include <algorithm>

#include <queue>

#include <iostream>

#include <vector>

#include <cstdlib>

#include <cstring>

#define eps 1e-6

#define ll long long

#define INF 0x3f3f3f3f

using namespace std;



char map[1005][1005];

int dis[1005][1005];

int dx[] = {0,0,1,-1};

int dy[] = {1,-1,0,0};

int row,col,n;

int current = 1;

int firstX,firstY;

int ans = 0;

typedef pair<int,int> pos;

queue <pos> q;



void bfs(){

    while(q.size()){

        pos t = q.front();

        q.pop();

        if(map[t.first][t.second] - '0'== current){

            ans += dis[t.first][t.second];

            current++;

            //清空队列保证下次起点正常

            while(q.size()){

                q.pop();

            }

            //重置距离数组

            memset(dis,INF,sizeof dis);

            dis[t.first][t.second] = 0;

            //设置下一次广搜的起点

            q.push(pos(t.first,t.second));

        }

        //四个方向进行bfs

        for(int i = 0;i<4;i++){

            int x = t.first + dx[i];

            int y = t.second + dy[i];

            if(x<0 || x>= row || y < 0|| y>=col || map[x][y] == 'X' || dis[x][y] != INF)//INF判断是否走过

                continue;

            else{

                q.push(pos(x,y));

                dis[x][y] = dis[t.first][t.second] + 1;

            }

        }

    }

}



int main(){

    cin>>row>>col>>n;

    //初始化

    ans = 0;

    memset(dis,INF,sizeof dis);

    for(int i = 0;i<row;i++){

        for(int j = 0;j<col;j++){

            cin>>map[i][j];

            if(map[i][j] == 'S'){

                //设置起点

                q.push(pos(i,j));

                dis[i][j] = 0;

            }

        }

    }

    //开始广搜

    bfs();

    cout<<ans<<endl;

    return 0;

}
// Slower C++ solution:
#include<cstdio>

#include<cstring>

#include<queue>

using namespace std;

int map[1005][1005];

struct node{

	int x,y,time;

}s[10],p;

queue<node> q;

int vis[1005][1005];

int n,m,T;

int dir[4][2]={{0,1},{1,0},{0,-1},{-1,0}};

int bfs(int a,int b){

	while(!q.empty())

		q.pop();

	q.push(s[a]);

	memset(vis,0,sizeof vis);

	vis[s[a].x][s[a].y]=1;

	while(!q.empty()){

		p=q.front();

		q.pop();

		int x=p.x,y=p.y,time=p.time;

		for(int i=0;i<4;i++){

			int x1=x+dir[i][0],y1=y+dir[i][1];

			if(x1<=0||y1<=0||x1>n||y1>m||vis[x1][y1]||map[x1][y1])

				continue ;

			if(x1==s[b].x&&y1==s[b].y)

				return time+1;

			vis[x1][y1]=1;

			p.x=x1,p.y=y1,p.time=time+1;

			q.push(p);

		}

	}

}

int main()

{

	scanf("%d%d%d",&n,&m,&T);

	for(int i=1;i<=n;i++){

		scanf("\n");

		for(int j=1;j<=m;j++){

			char c;

			c=getchar();

			if(c=='S')

				s[0].x=i,s[0].y=j;

			if(c=='X')

				map[i][j]=1;

			if(c>='1'&&c<='9')

				s[c-'0'].x=i,s[c-'0'].y=j;

		}

	}

	int time=0;

	for(int i=0;i<T;i++)

		time+=bfs(i,i+1);

	printf("%d\n",time);

}

// Faster C++ solution for the same problem (measured speedup: 4.9993073082845765x):
#include <iostream>

#include <queue>

using namespace std;

const int INF = 100000000;

typedef pair<int,int> Point;

Point AllPoint[1000];

int W,H;

int x[4] = {0,1,0,-1};

int y[4] = {1,0,-1,0};

char map[1000][1000];

int deep[1000][1000];

int N;

void BFS(Point Start,Point Over){

    queue<Point> que;

    int FirstDeep = deep[Start.first][Start.second];

    for (int i = 0;i<H;i++){

        for (int j = 0;j<W;j++){

            deep[i][j] = INF;

        }

    }

    que.push(Start);

    deep[Start.first][Start.second] = FirstDeep;

    while (que.size()){

        Point p = que.front();

        que.pop();

        if (p.first== Over.first&&p.second == Over.second)

            break;

        for (int i = 0;i<4;i++){

            int ix = p.first+x[i];

            int iy = p.second+y[i];

            if (ix>=0&&ix<=H

                &&iy>=0&&iy<=W

                &&deep[ix][iy] == INF

                &&map[ix][iy]!='X'){

                que.push(Point(ix,iy));

                deep[ix][iy] = deep[p.first][p.second]+1;

            }

        }

    }

}







int main(){

    cin >> H >> W;

    cin >> N;

    for (int i = 0;i<H;i++){

        for (int j = 0;j<W;j++){

            cin >> map[i][j];

            if ((int)map[i][j]-48>=1&&(int)map[i][j]-48<=N){

                AllPoint[(int)map[i][j]-48].first = i;

                AllPoint[(int)map[i][j]-48].second = j;



            }

            if (map[i][j] == 'S'){

                AllPoint[0].first = i;

                AllPoint[0].second = j;

            }

        }

    }

    deep[AllPoint[0].first][AllPoint[0].second] = 0;

    for (int i = 0;i<N;i++){

        BFS(AllPoint[i],AllPoint[i+1]);

    }

    cout << deep[AllPoint[N].first][AllPoint[N].second]<<endl;



    return 0;

}

//#....

//S.##.

//###G.

//#####

//#####



//#S######.#

//......#..#

//.#.##.##.#

//.#........

//##.##.####

//....#....#

//.#######.#

//....#.....

//.####.###.

//....#...G#
// Slower C++ solution:
/*

*

*/

#include<iostream>

#include<cstring>

#include<cstdio>

#include<cmath>

#include<string>

#include<queue>

#define CLR(ARR,NUM) memset(ARR,NUM,sizeof(ARR))

#define GETNUM(NUM) scanf("%d",&NUM)

#define faster_io() ios_base::sync_with_stdio(false)

using namespace std;

const int MAXN = 1010;

char map[MAXN][MAXN];

bool vis[10][MAXN][MAXN];

struct node{

	int x;

	int y;

	int deep;

	int n;

};

int dx[]={0,0,1,-1};

int dy[]={1,-1,0,0};



int main()

{

	CLR(vis,false);

	CLR(map,'X');

	int h,w,n;

	cin >> h >> w >> n;

	getchar();

	int sx,sy;

	for(int i=1;i<=h;i++){

		for(int j=1;j<=w;j++){

			map[i][j]=getchar();

			if(map[i][j]=='S'){

				sx=i;

				sy=j;

			}

		}

		getchar();

	}

	node t;

	t.x=sx;

	t.y=sy;

	t.deep=0;

	t.n=0;

	queue<node>q;

	vis[0][sx][sy]=true;

	q.push(t);

	int ans = -1;

	while(!q.empty()){

		node cur=q.front();

		if(cur.n==n){

			ans=cur.deep;

			break;

		}

		q.pop();

		for(int i=0;i<4;i++){

			int tx=cur.x+dx[i];

			int ty=cur.y+dy[i];

			if(map[tx][ty]!='X'&&!vis[cur.n][tx][ty]){

				node t = cur;

				t.x=tx;

				t.y=ty;

				t.deep++;

				if(map[tx][ty]=='1'+t.n){

					t.n++;

				}

				vis[t.n][tx][ty]=true;

				q.push(t);

			}

		}

	}

	cout << ans << endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 12.707197493598168x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<iostream>

#include<cstdio>

#include<queue>

#include<utility>

#include<cstring>

using namespace std;

char map[1005][1005];

bool vis[1005][1005];

int dx[]={0,0,-1,1};

int dy[]={1,-1,0,0};

int sx,sy;

int h,w;

int bfs(int n){

	memset(vis,false,sizeof(vis));

	queue<pair<pair<int,int>,int> >que;

	que.push(make_pair(make_pair(sx,sy),0));

	while(!que.empty()){

		pair<int,int>now=que.front().first;

		int cnt=que.front().second;

		que.pop();

		if(map[now.first][now.second]==n+48){

			sx=now.first;

			sy=now.second;

			return cnt;

		}

		for(int i=0;i<4;i++){

			int _x=now.first+dx[i];

			int _y=now.second+dy[i];

			if(_x<0||_y<0||_x>=h||_y>=w||map[_x][_y]=='X'||vis[_x][_y]){

				continue;

			}

			vis[_x][_y]=true;

			que.push(make_pair(make_pair(_x,_y),cnt+1));

		}

	}

}

int main(){

	int n;

	while(cin>>h>>w>>n){

		memset(map,0,sizeof(map));

		for(int i=0;i<h;i++){

			scanf("%s",map[i]);

		}

		for(int i=0;i<h;i++){

			for(int j=0;j<w;j++){

				if(map[i][j]=='S'){

					sx=i;

					sy=j;

					map[i][j]=='.';

					break;

				}

			}

		}

		int count=0;

		for(int k=1;k<=n;k++){

			count+=bfs(k);

		}

		cout<<count<<endl;

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 3.002843144420098x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<stdio.h>

#include<string.h>

#include<queue>

#include<algorithm>

#define MAX_N 1002

using namespace std;

struct node{int x,y;};

char _map[MAX_N][MAX_N];

int dp[MAX_N][MAX_N];

int ox[]={0,0,1,-1};

int oy[]={1,-1,0,0};

int S_x,S_y;

int h,w,cnt;



node make_node(int x,int y){

	node t;

	t.x=x,t.y=y;

	return t;

}

void solve(){

	queue<node> que;

	int step=0;

	

	for(int i=1;i<=cnt;i++){

		que.push(make_node(S_x,S_y));

		_map[S_x][S_y]='.';

		memset(dp,-1,sizeof(dp));

		dp[S_x][S_y]=step;

		while(!que.empty()){

			node t=que.front();que.pop();

			if(_map[t.x][t.y]=='0'+i){

				step=dp[t.x][t.y];

				S_x=t.x,S_y=t.y;

				break;

			}

			for(int j=0;j<4;j++){

				int x=t.x+ox[j];

				int y=t.y+oy[j];

				if(0<=x&&x<h&&0<=y&&y<w&&_map[x][y]!='X'&&dp[x][y]==-1){

					que.push(make_node(x,y));

					dp[x][y]=dp[t.x][t.y]+1;

				}

			}

		}

		while(!que.empty()) que.pop();

	}

	

	printf("%d\n",step);

}



int main()

{

	while(scanf("%d%d%d",&h,&w,&cnt)!=EOF){

		for(int i=0;i<h;i++)

			scanf("%s",_map[i]);

		for(int j=0;j<h;j++)

			for(int k=0;k<w;k++)

				if(_map[j][k]=='S')

					S_x=j,S_y=k,j=h,k=w;

		solve();

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 4.958808190484333x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<cstdio>

#include<cstring>

#include<queue>

using namespace std;

int map[1005][1005];

struct node{

	int x,y,time;

}s[10],p;

queue<node> q;

int vis[1005][1005];

int n,m,T;

int dir[4][2]={{0,1},{1,0},{0,-1},{-1,0}};

int bfs(int a,int b){

	while(!q.empty())

		q.pop();

	q.push(s[a]);

	memset(vis,0,sizeof vis);

	vis[s[a].x][s[a].y]=1;

	while(!q.empty()){

		p=q.front();

		q.pop();

		int x=p.x,y=p.y,time=p.time;

		for(int i=0;i<4;i++){

			int x1=x+dir[i][0],y1=y+dir[i][1];

			if(x1<=0||y1<=0||x1>n||y1>m||vis[x1][y1]||map[x1][y1])

				continue ;

			if(x1==s[b].x&&y1==s[b].y)

				return time+1;

			vis[x1][y1]=1;

			p.x=x1,p.y=y1,p.time=time+1;

			q.push(p);

		}

	}

}

int main()

{

	scanf("%d%d%d",&n,&m,&T);

	for(int i=1;i<=n;i++){

		scanf("\n");

		for(int j=1;j<=m;j++){

			char c;

			c=getchar();

			if(c=='S')

				s[0].x=i,s[0].y=j;

			if(c=='X')

				map[i][j]=1;

			if(c>='1'&&c<='9')

				s[c-'0'].x=i,s[c-'0'].y=j;

		}

	}

	int time=0;

	for(int i=0;i<T;i++)

		time+=bfs(i,i+1);

	printf("%d\n",time);

}

// Faster C++ solution for the same problem (measured speedup: 4.988078595333867x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include <iostream>

#include <cstdio>

#include <cstring>

#include <cmath>

#include <vector>

#include <queue>

#include <set>

#include <map>

#include <stack>

#include <utility>

#include <algorithm>

#include <sstream>

using namespace std;

typedef pair<int,int> P;



const int max_n=1000+10;

int h,w,n,sx,sy,dx[]={0,0,-1,1},dy[]={-1,1,0,0},d[max_n][max_n],ans;

char c[max_n][max_n];



void bfs(int x,int y,int m){

	if(m>n)return;

	queue<P> q;

	memset(d,0,sizeof(d));

	q.push(P(x,y));

	d[x][y]=1;

	while(!q.empty()){

		P p=q.front();

		q.pop();

		if(c[p.first][p.second]=='0'+m){

		    ans+=d[p.first][p.second]-1;

		    bfs(p.first,p.second,m+1);

		    return;

		}

		for(int i=0;i<4;i++){

			int tx=p.first+dx[i],ty=p.second+dy[i];

			if(tx>=0 && tx<h && ty>=0 && ty<w && c[tx][ty]!='X' && !d[tx][ty]){

				q.push(P(tx,ty));

				d[tx][ty]=d[p.first][p.second]+1;

			}

		}

	}

}



int main(){

    scanf("%d%d%d",&h,&w,&n);

    for(int i=0;i<h;i++)

        for(int j=0;j<w;j++){

            cin>>c[i][j];

            if(c[i][j]=='S'){sx=i;sy=j;}

        }

    bfs(sx,sy,1);

    cout<<ans<<endl;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 5.118166035331772x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include <iostream>

#include <cstdio>

#include <cstring>

#include <cmath>

#include <vector>

#include <queue>

#include <set>

#include <map>

#include <stack>

#include <utility>

#include <algorithm>

#include <sstream>

using namespace std;



struct Node{

	int x,y;

};



const int max_n=1000+10;

int h,w,n,dx[]={0,0,-1,1},dy[]={-1,1,0,0},d[max_n][max_n],ans;

Node sN;

char c[max_n][max_n];



void bfs(int m){

	if(m>n)return;

	queue<Node> q;

	memset(d,0,sizeof(d));

	q.push(sN);

	d[sN.x][sN.y]=1;

	while(!q.empty()){

		Node p=q.front();

		q.pop();

		

		if(c[p.x][p.y]=='0'+m){

		    ans+=d[p.x][p.y]-1;

		    sN.x=p.x;

		    sN.y=p.y;

		    return;

		}

		for(int i=0;i<4;i++){

			Node nN;

			nN.x=p.x+dx[i];

			nN.y=p.y+dy[i];

			if(nN.x>=0 && nN.x<h 

            && nN.y>=0 && nN.y<w 

		   	&& c[nN.x][nN.y]!='X' && !d[nN.x][nN.y]){

				q.push(nN);

				d[nN.x][nN.y]=d[p.x][p.y]+1;

			}

		}

	}

}



int main(){

    scanf("%d%d%d",&h,&w,&n);

    for(int i=0;i<h;i++)

        scanf("%s",c[i]);

    for(int i=0;i<h;i++)

        for(int j=0;j<w;j++)

            if(c[i][j]=='S'){

            	sN.x=i;

            	sN.y=j;

            	break;

            }

    for(int i=1;i<=n;i++)bfs(i);

    cout<<ans<<endl;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 5.115547385970162x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/