// Slower C++ solution:
/************************************************

* Author        :somniloquy

* Created Time  :2015/10/30 16:15:09

 ************************************************/



#include <cstdio>

#include <algorithm>

#include <iostream>

#include <cstring>

#include <queue>



using namespace std;



const int hw_max = 1000 + 5;

char graph[hw_max][hw_max];

int sign[hw_max][hw_max];

int h, w, n, ans;

int dx[4] = {-1, 1, 0, 0};

int dy[4] = {0, 0, -1, 1};

struct node

{

	int x;

	int y;

	int time;

} start;



void BFS(node op, char ed)

{

	queue <node> process;

	process.push(op);

	sign[op.x][op.y] = 1;

	while(!process.empty())

	{

		node now = process.front();

		process.pop();

		for(int i = 0; i < 4; i ++)

		{

			node next = now;

			next.x += dx[i];

			next.y += dy[i];

			next.time ++;

			if(next.x >= 0 && next.x < h && next.y >= 0 && next.y < w && graph[next.x][next.y] != 'X' && !sign[next.x][next.y])

			{

				if(graph[next.x][next.y] == ed)

				{

					ans += next.time;

					next.time = 0;

					start = next;

				       	return;

				}

				else

				{

					process.push(next);

					sign[next.x][next.y] = 1;

				}

			}

		}

	}

}



int main()

{

	while(~scanf("%d %d %d", & h, & w, & n))

	{

		getchar();

		for(int i = 0; i < h; i ++)

		{

			for(int j = 0; j < w; j ++)

			{

			       scanf("%c", & graph[i][j]);

			       if(graph[i][j] == 'S')

			       {

					start.x = i;

					start.y = j;

					start.time = 0;

			       }

			}

			getchar();

		}

		ans = 0;

		for(int i = 1; i <= n; i ++)

		{

			memset(sign, 0, sizeof(sign));

			BFS(start, '0' + i);

		}

		printf("%d\n", ans);

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.539287849318879x):
#include<iostream>

#include<cstdio>

#include<queue>

#include<cstring>

#include<vector>

#include<set>

using namespace std;

typedef long long ll;

int H,W,N;

char mm[1005][1005];

bool v[1005][1005];

int xx,yy;

struct node{

    int x,y,step;

};

queue<node> que;

int dx[4]={0,0,1,-1};

int dy[4]={1,-1,0,0};

bool check(int x,int  y){

    if(1<=x&&x<=H&&1<=y&&y<=W&&!v[x][y]&&mm[x][y]!='X')return true;

    else return false;

}

int bfs(int g){

    while(!que.empty())que.pop();

    node t;

    t.x=xx;

    t.y=yy;

    t.step=0;

    v[xx][yy]=1;

    que.push(t);

    while(!que.empty()){

        t=que.front();

        que.pop();

        for(int i=0;i<4;i++){

            int nx=t.x+dx[i];

            int ny=t.y+dy[i];

            if(check(nx,ny)){

                if(mm[nx][ny]==g+'0'){

                    xx=nx;

                    yy=ny;

                    return t.step+1;

                }

                node tt;

                tt.x=nx;

                tt.y=ny;

                tt.step=t.step+1;

                v[nx][ny]=1;

                que.push(tt);

            }

        }

    }

}

int main(){

    while(~scanf("%d%d%d",&H,&W,&N)){

        for(int i=1;i<=H;i++){

            scanf("%s",mm[i]+1);

        }

        for(int i=1;i<=H;i++){

            for(int j=1;j<=W;j++){

                if(mm[i][j]=='S'){

                    xx=i;

                    yy=j;

                }

            }

        }

        int ans=0;

        for(int i=1;i<=N;i++){

            memset(v,0,sizeof(v));

            ans+=bfs(i);

        }

        printf("%d\n",ans);

    }

    return 0; 

}