// Slower C++ solution:
#include<iostream>

#include<cstdlib>

#include<cstdio>

#include<cmath>

#include<algorithm>

#include<cstring>

#include<queue>

#include<vector>

#include<stack>

#define ls k<<1

#define rs k<<1|1

#define RG register

#define MAXN 50010

#define LL long long int

using namespace std;

const int INF=0x7fffffff;

struct node{

	int next;

	int to;

	int w;

	int c;

}t[MAXN];

int head[MAXN];

int num;

int dis[MAXN],vis[MAXN],cost[MAXN];

int n,m;

void add(int from,int to,int w,int c)

{

	t[++num].next=head[from];

	t[num].to=to;

	t[num].w=w;

	t[num].c=c;

	head[from]=num;

}

void spfa()

{

	for(int i=1;i<=n;i++)

		{

			dis[i]=INF;vis[i]=0;cost[i]=INF;

		}

	cost[1]=dis[1]=0;vis[1]=1;

	queue<int>q;q.push(1);

	while(!q.empty())

		{

			int u=q.front();q.pop();vis[u]=0;

			for(int i=head[u];i;i=t[i].next)

				{

					int v=t[i].to;

					if(dis[v]>dis[u]+t[i].w||(dis[v]==dis[u]+t[i].w&&cost[v]>t[i].c))

						{

							dis[v]=dis[u]+t[i].w;

							cost[v]=t[i].c;

							if(!vis[v])

								{

									vis[v]=1;q.push(v);

								}

						}

				}

		}

}

int main()

{

//	freopen("1.in","r" ,stdin);

	//freopen("1.out","w",stdout);

	while(1)

		{

			scanf("%d%d",&n,&m);if(n==0&&m==0) break;

			int x,y,z,k;

			memset(head,0,sizeof(head));num=0;

			for(int i=1;i<=m;i++)

				{

					scanf("%d%d%d%d",&x,&y,&z,&k);

					add(x,y,z,k);add(y,x,z,k);

				}

			spfa();

			int ans=0;

			for(int i=1;i<=n;i++) ans+=cost[i];

			cout<<ans<<endl;

		}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.1041790050130735x):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <queue>



using namespace std;



const int inf = 0x3f3f3f3f;

const int N = 10414;

const int M = 40414;



struct Edge{

	int u, v, d, c;

	int next;

}edge[M];



int cnt, head[N];

int op, tp, link[N];

int vis[N], dis[N], cost[N];

queue<int>q;



void add_edge(int u, int v, int d, int c);

void spfa(int n);



int main(){

	int n, m, i, u, v, d, c;

	while(scanf("%d %d", &n, &m) && (n || m)){

		cnt = 0;

		memset(head, -1, sizeof(head));

		for(i = 0; i < m; i++){

			scanf("%d %d %d %d", &u, &v, &d, &c);

			add_edge(u, v, d, c);

			add_edge(v, u, d, c);

		}

		spfa(n);

	}

	return 0;

}

void add_edge(int u, int v, int d, int c){

	edge[cnt].u = u;

	edge[cnt].v = v;

	edge[cnt].d = d;

	edge[cnt].c = c;

	edge[cnt].next = head[u];

	head[u] = cnt++;

}

void spfa(int n)

{

    int v, d, c;

    while(!q.empty())q.pop();

    memset(vis, 0,sizeof(vis));

    memset(dis, inf, sizeof(dis));

    memset(cost, inf, sizeof(cost));

    dis[1]=0;

    cost[1]=0;

    vis[1]=true;

    q.push(1);

    while(!q.empty())

    {

        int u=q.front();

        q.pop();

        vis[u]=false;

        for(int i=head[u]; i!=-1; i=edge[i].next)

        {

            v = edge[i].v;

            d = edge[i].d;

            c = edge[i].c;

            if(dis[v] > dis[u] + d||(dis[v] == dis[u] + d && cost[v] > c))//有多条最短路时，取花费最小的

            {

                dis[v] = dis[u] +d;

                cost[v] = c;

                if(!vis[v])

                {

                    q.push(v);

                    vis[v]=true;

                }

            }

        }

    }

    int sum = 0;

    for(int i = 1; i <= n; i++){

    	sum += cost[i];

    }

    printf("%d\n", sum);

    return;

}