// Slower C++ solution:
/************************************************

* Author        :somniloquy

* Created Time  :2015/10/30 16:15:09

 ************************************************/



#include <cstdio>

#include <algorithm>

#include <iostream>

#include <cstring>

#include <queue>



using namespace std;



const int hw_max = 1000 + 5;

char graph[hw_max][hw_max];

int sign[hw_max][hw_max];

int h, w, n, ans;

int dx[4] = {-1, 1, 0, 0};

int dy[4] = {0, 0, -1, 1};

struct node

{

	int x;

	int y;

	int time;

} start;



void BFS(node op, char ed)

{

	queue <node> process;

	process.push(op);

	sign[op.x][op.y] = 1;

	while(!process.empty())

	{

		node now = process.front();

		process.pop();

		for(int i = 0; i < 4; i ++)

		{

			node next = now;

			next.x += dx[i];

			next.y += dy[i];

			next.time ++;

			if(next.x >= 0 && next.x < h && next.y >= 0 && next.y < w && graph[next.x][next.y] != 'X' && !sign[next.x][next.y])

			{

				if(graph[next.x][next.y] == ed)

				{

					ans += next.time;

					next.time = 0;

					start = next;

				       	return;

				}

				else

				{

					process.push(next);

					sign[next.x][next.y] = 1;

				}

			}

		}

	}

}



int main()

{

	while(~scanf("%d %d %d", & h, & w, & n))

	{

		getchar();

		for(int i = 0; i < h; i ++)

		{

			for(int j = 0; j < w; j ++)

			{

			       scanf("%c", & graph[i][j]);

			       if(graph[i][j] == 'S')

			       {

					start.x = i;

					start.y = j;

					start.time = 0;

			       }

			}

			getchar();

		}

		ans = 0;

		for(int i = 1; i <= n; i ++)

		{

			memset(sign, 0, sizeof(sign));

			BFS(start, '0' + i);

		}

		printf("%d\n", ans);

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 5.0765978606098985x):
#include <iostream>

#include <queue>

using namespace std;

int w, h, n;

char map[1024][1024];

int d[1024][1024];

const int direction[4][2] = {

    { -1, 0 },

    { 1, 0 },

    { 0, -1 },

    { 0, 1 },

};

int factory[16][2];

typedef pair<int, int> P;

int bfs(int sx, int sy, int gx, int gy)

{

    for (int i = 0; i < h; ++i)

    {

        for (int j = 0; j < w; ++j)

        {

            d[i][j] = -1;

        }

    }

    queue<P> que;

    que.push(P(sx, sy));

    d[sx][sy] = 0;

    while (que.size())

    {

        const P p = que.front(); que.pop();

        if (p.first == gx && p.second == gy)

        {

            break;

        }

        for (int i = 0; i < 4; ++i)

        {

            int nx = p.first + direction[i][0];

            int ny = p.second + direction[i][1];

            if (0 <= nx && nx < h && 0 <= ny && ny < w && map[nx][ny] != 'X' && d[nx][ny] == -1)

            {

                que.push(P(nx, ny));

                d[nx][ny] = d[p.first][p.second] + 1;

            }

        }

    }



    return d[gx][gy];

}



int main(int argc, char *argv[])

{



    cin >> h >> w >> n;

    for (int i = 0; i < h; ++i)

    {

        for (int j = 0; j < w; ++j)

        {

            cin >> map[i][j];

        }

    }



    for (int i = 0; i < h; ++i)

    {

        for (int j = 0; j < w; ++j)

        {

            if (map[i][j] == 'S')

            {

                factory[0][0] = i;

                factory[0][1] = j;

                map[i][j] = '.';

            }

            else if (isdigit(map[i][j]))

            {

                int index = map[i][j] - '0';

                factory[index][0] = i;

                factory[index][1] = j;

            }

        }

    }



    int step = 0;

    for (int i = 0; i < n; ++i)

    {

        step += bfs(factory[i][0], factory[i][1], factory[i + 1][0], factory[i + 1][1]);

    }



    cout << step << endl;



    return 0;

}

///////////////////////////End Sub//////////////////////////////////