// Slower C++ solution:


/**

    And in the end, the love you take is equal to the love you make.



        I LOVE YOU LAURA.

**/



#include <bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <ext/rope>



#define _CRT_SECURE_NO_DEPRECATE

#define _CRT_DISABLE_PERFCRIT_LOCKS



#define findOrder find_by_order

#define orderKey order_of_key



#define isOn(mask, i) (mask & (1 << i))

#define turn(mask, i) (mask |= (1 << i))

#define switch(mask, i) (mask &= ~(1 << i))

#define change(mask, i) (mask ^= (1 << i))

#define lowbit(mask) (mask & (-mask))

#define turnAll(mask, n) (mask = (1 << n) - 1)

#define switchLastBit(mask) (mask & (mask - 1))

#define turnLastZero(mask) (mask | (mask + 1))

#define modulo(x, mod) ((x) & (mod - 1))

#define log2(x) (31 - __builtin_clz(x))



#define mkp make_pair

#define pb push_back

#define pf push_front

#define eb emplace_back

#define ef emplace_front

#define ins insert

#define rsz resize

#define f first

#define s second

#define lb lower_bound

#define ub upper_bound



#define sz(x) ((int)x.size())

#define all(x) begin(x), end(x)

#define rall(x) rbegin(x), rend(x)



#define debug(x) (cerr << x << " ")



using namespace std;

using namespace __gnu_pbds;

using namespace __gnu_cxx;



typedef double db;

typedef long long ll;

typedef long double ld;

typedef unsigned long long ull;



typedef pair<int, int> ii;

typedef pair<ll,ll> pll;

typedef pair<ld,ld> pdb;

typedef pair<int, ii> tri;

typedef complex<ld> cd;



typedef vector<int> vi;

typedef vector<ii> vii;

typedef vector<ld> vdb;

typedef vector<cd> vcd;

typedef vector<ll> vll;

typedef vector<string> vs;

typedef vector<vll> matrix;



typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_tree;



const ll mod = 1e9+7;

const int maxn = 1e5+2;

const int pi = 2 * acos(0.0);

const db eps = 1e-9;



ll n, m;

vll graph[maxn];

ll dp[maxn];



ll dfs (int node){

    ll &ans = dp[node];



    if (ans != -1) return ans;



    for (auto v: graph[node]){

        ans = max(ans, dfs(v) + 1);

    }

    return ans;

}



int main()

{

    ios_base::sync_with_stdio(0);

    cin.tie(0); cout.tie(0);



    memset(dp, -1, sizeof dp);



    cin >> n >> m;



    for (int i = 1; i <= m; i++){

        int a, b; cin >> a >> b;



        graph[a].pb(b);

    }



    ll ans = 0;

    for (int i = 1; i <= n; i++){

        ans = max(ans, dfs(i) + 1);

    }



    cout << ans << "\n";



    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.2504304153067238x):
#include <bits/stdc++.h>

using namespace std;

/*

#define mod 7

typedef long long ll;



ll fact[1000006], inv[1000006];



ll fp(ll base, ll exp)

{

    if (exp == 0)

        return 1;

    ll ans = fp(base, exp / 2);

    ans = (ans * ans) % mod;

    if (exp % 2 != 0)

        ans = (ans * (base % mod)) % mod;

    return ans;

}



void calcFacAndInv(ll n)

{

    fact[0] = inv[0] = 1;

    for (ll i = 1; i <= n; i++)

    {

        fact[i] = (i * fact[i - 1]) % mod;

        inv[i] = fp(fact[i], mod - 2);

    }

}



ll ncr(ll n, ll r)

{

    return ((fact[n] * inv[r]) % mod * inv[n - r]) % mod;

}



ll npr(ll n, ll r)

{

    return (fact[n] * inv[n - r]) % mod;

}



int main()

{

    calcFacAndInv(100000);

     cout<<inv[3];

    return 0;

}

*/





// GCD



int gcd(long long a,long long b)

{

    if (b==0)

        return a;

    return gcd (b,a%b);

}

//prime factoriation

/*

set<int >s;

bool prime factorization (int x)

{

    for (int j=2; j*j<=x; ++j)

    {

        while (x%j==0)

        {

            s.insert(j);

            x/=j;

        }

    }

    if (x>1)

    {

        s.insert(x);

    }

    if (s.size()==2)

        return true ;

    else

        return false ;

}



#define ll long long

int a,b,q,p,n;

int countDivisorss(int x,int y)

{

    ll cnt = 0;

    for (int i = min(x,y); i <= sqrt(n); i++)

    {

        if (x % i == 0&&y%i==0)

        {

            if (x / i == i||y / i == i)

                cnt++;



            else

                cnt = cnt + 2;

        }

    }

    return cnt;

}

int countDivisors(int x)

{

    ll cnt = 0;

    int tmp=n;

    if (n-x>10000000)  tmp=sqrt(n);

    for (int i = x; i <= tmp; i++)

    {

        if (x % i == 0)

        {

         if (x/i==i)

            cnt++;

         else

            cnt = cnt + 2;

        }

    }

    return cnt;

}

*/



/*

        int s =n/2,e=n-1;

        while (s<=e&&e<=n-1)

        {

            int mid =s+e/2;



            if (arr[mid]==arr[n/2])

            {

                s=mid;

                num +=mid -s;

            }

            else

                e=mid-1;

        }

        */





/*



const int N = 1e5 + 5;



vector<int> adj[N];

bool visited[N];

int nodesNum;

void dfs(int node)

{

    if (visited[node])

        return;

    visited[node] = true;

    for (int child: adj[node])

        dfs(child);

}



//fast power



#define mod 1000000007

long long fp(long long  base, long long exp)

{

    if (exp == 0)

        return 1;

    long long  ans = fp(base, exp / 2);

    ans = (ans * ans);

    if (exp % 2 != 0)

        ans = (ans * (base )) ;

    return ans;

}



*/

#define IO   ios::sync_with_stdio(false)

/*

vector<int> v,t;

int n,V,a[21],MAX;

void dfs(int x,int sum)

{

    if(x==n)

    {

        if(sum>MAX&&sum<=V)

        {

            MAX=sum;

            t=v;

        }

        return;

    }

    v.push_back(a[x]);

    dfs(x+1,sum+a[x]);

    v.pop_back();

    dfs(x+1,sum);

}

*/

const int N=1e5+7;

int n,m,x,y;

int dp[N];

bool vis[N];

vector<int> adj[N];

void dfs(int node)

{

    vis[node] = 1;

    for (int child = 0; child< adj[node].size(); child++)

    {

        if (!vis[adj[node][child]])

            dfs(adj[node][child]);

        dp[node] = max(dp[node], 1 + dp[adj[node][child]]);

    }

}

int LongestPath()

{

    for (int i = 1; i <= n; i++)

    {

        if (!vis[i])

            dfs(i);

    }

    int ans = 0;

    for (int i = 1; i <= n; i++)

    {

        ans = max(ans, dp[i]);

    }

    return ans;

}

int main()

{

    cin>>n>>m;

    while(m--)

    {

        cin>>x>>y;

        adj[x].push_back(y);

    }

    cout << LongestPath();

    return 0;

}