stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include <bits/stdc++.h> 

using namespace std;

#define INF INT_MAX

#define N 100005

#define K 3

int n, k;

int arr[N][K];

int dp[N][K];

int solve(int idx, int last_k){

    int res;

    if(idx == n)

        return 0;

    if(~last_k && ~dp[idx][last_k])

        return dp[idx][last_k];

    for(int i=0; i<K; ++i){

        if(last_k != i){

            dp[idx][last_k] = max(dp[idx][last_k], arr[idx][i]+solve(idx+1, i));

        }

    }

    return dp[idx][last_k];

}

int main()

{

    cin >> n;

    memset(dp, -1, sizeof(dp[0][0]) * N * K);

    for(int i=0; i<n; ++i)

        for(int j=0; j<3; ++j)

            cin >> arr[i][j];

    cout << solve(0, -1);

    return 0;

}




// Faster C++ solution for the same problem (measured speedup: 2.170671451645033x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include <iostream>

#include <cstring>

using namespace std;

const int maxn=1e5+5;

const int inf=0x3f3f3f3f;

int dp[maxn][4];

int a[maxn],b[maxn],c[maxn];

int main()

{

   int n;

   cin>>n;

   memset(dp,0,sizeof(dp));

   for(int i=1;i<=n;++i){

       cin>>a[i]>>b[i]>>c[i];

   }

   dp[1][1]=a[1];

   dp[1][2]=b[1];

   dp[1][3]=c[1];

   for(int i=2;i<=n;++i){

       dp[i][1]=max(dp[i-1][2]+a[i],dp[i-1][3]+a[i]);

       dp[i][2]=max(dp[i-1][1]+b[i],dp[i-1][3]+b[i]);

       dp[i][3]=max(dp[i-1][2]+c[i],dp[i-1][1]+c[i]);

   }

   cout<<max(dp[n][1],max(dp[n][2],dp[n][3]))<<endl;

   return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.575239209920272x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

typedef long long int lli;

typedef long double ld;

const int oo = 1e9;

//const int mod = 1e9+9;

/*ll gcd(ll x, ll y){return (y ? gcd(y, x%y) : x); }

*ll lcm(ll x, ll y){return x*(y/gcd(x,y));}

*void exEuclid(int a, int b){

	if(b==0){x = 1; y=0; d=a; return ;}

	exEuclid(b, a%b);

	int x1=y;

	int y1=x-(a/b)*y;

	x=x1; 100000

	y=y1;

} 

* */

//===========================================================//

int n;

const int nx = 1e5+5;

int ac[nx][3];

int dp[3][nx];

int go(int a, int i){

	if(i == n) return 0;

	if(dp[a][i] != -1) return dp[a][i];

	int& ans = dp[a][i];

	

	if(a==0){

		ans=max(ans, go(1, i+1)+ac[i][0]);

		ans=max(ans, go(2, i+1)+ac[i][0]);

	}

	if(a==1){

		ans=max(ans, go(0, i+1)+ac[i][1]);

		ans=max(ans, go(2, i+1)+ac[i][1]);

	}

	if(a==2){

		ans=max(ans, go(0, i+1)+ac[i][2]);

		ans=max(ans, go(1, i+1)+ac[i][2]);

	}

	

	return ans;

}

int main(){

	cin>>n;

	for(int i=0; i<n; i++) cin>>ac[i][0]>>ac[i][1]>>ac[i][2];

	memset(dp, -1, sizeof dp);

	cout<<max(go(0,0),max(go(1,0),go(2,0)))<<"\n";

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.1818737225654488x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

const int oo = 1e9;



int n;

const int nx = 1e5+5;

int ac[nx][3];

int dp[3][nx];

int go(int a, int i)

{

	if(i==n) return 0;

	if(dp[a][i] != -1) return dp[a][i];

	int& ans = dp[a][i];

	if(a==0)

	{

		ans=max(ans, go(1, i+1)+ac[i][0]);

		ans=max(ans, go(2, i+1)+ac[i][0]);

	}

	if(a==1)

	{

		ans=max(ans, go(0, i+1)+ac[i][1]);

		ans=max(ans, go(2, i+1)+ac[i][1]);

	}

	if(a==2)

	{

		ans=max(ans, go(0, i+1)+ac[i][2]);

		ans=max(ans, go(1, i+1)+ac[i][2]);

	}

	

	return ans;

	

}

int main()

{

    cin>>n;

    for(int i=0; i<n; i++) cin>>ac[i][0]>>ac[i][1]>>ac[i][2];

    memset(dp, -1, sizeof dp);

    cout<<max(go(0,0), max(go(1,0),go(2,0)))<<"\n";

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.18185169082768x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;



int const N=1e5+5, M=1e9+7, OO = 0x3f3f3f3f;



int n;

int arr[3][N];



int mem[N][4];

int solve(int i, int last)

{

    if(i==n)

        return 0;

    if(mem[i][last]!=-1)

        return mem[i][last];

    int op1= (last!=1) ? solve(i+1, 1)+arr[0][i] : 0;

    int op2= (last!=2) ? solve(i+1, 2)+arr[1][i] : 0;

    int op3= (last!=3) ? solve(i+1, 3)+arr[2][i] : 0;

    return mem[i][last]=max(op1,max(op2,op3));

}





int main()

{

//    freopen("input.txt","rt",stdin);

//    freopen("output.txt","wt",stdout);

    scanf("%d",&n);

    for(int i=0; i<n; i++)

        scanf("%d %d %d",arr[0]+i,arr[1]+i,arr[2]+i);

    memset(mem, -1, sizeof mem);

    printf("%d\n",solve(0,0));







    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.5569480486411544x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define ALL(x) begin(x),end(x)

typedef long long ll;

int OO = 0x3f3f3f3f;



int n;

int a[100005];

int b[100005];

int c[100005];

int mem[100005][3];



int solve(int x, int k)

{

    int op1, op2, op3;

    if(x == n)

        return 0;



    if(mem[x][k] != -1)

        return mem[x][k];



    op1 = op2 = op3 = 0;

    if(k != 1)

        op1 = solve(x+1, 1)+a[x];

    if(k != 2)

        op2 = solve(x+1, 2)+b[x];

    if(k != 3)

        op3 = solve(x+1, 3)+c[x];



    return mem[x][k] = max(op1, max(op2, op3));

}



int main()

{

    memset(mem, -1, sizeof mem);

    cin >> n;

    for(int i = 0; i< n; i++)

    {

        cin >> a[i] >> b[i] >> c[i];

    }

    cout << solve(0, 0) << endl;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.183676641281715x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;



const int N = 1e5 + 9, OO = 0x3f3f3f3f;



int n, points[N][3], dp[N][4];



int solve(int i, int prev){

    if(i == n)  return 0;



    int &ret = dp[i][prev];

    if(~ret)    return ret;



    ret = 0;

    for(int j = 0;j < 3;j++)

        if(prev != j)   ret = max(ret, points[i][j] + solve(i + 1, j));





    return ret;

}



int main(){



    cin >> n;

    for(int i = 0;i < n;i++)

        cin >> points[i][0] >> points[i][1] >> points[i][2];



    memset(dp, -1, sizeof dp);



    cout << solve(0, 3);

}


// Faster C++ solution for the same problem (measured speedup: 2.5719529391057203x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;



#define ll long long

#define size 100001



int a[size];

int b[size];

int c[size];

int dp[size][4];



int max_sum(int n, int p)

{

    if(n <= 0)

        return 0;

    if(n > 0 && dp[n][p] != -1)

        return dp[n][p];

    int ans = INT_MIN;

    if(p != 0)

    {

        ans = max(ans,a[n]+max_sum(n-1,0));

    }

    if(p != 1)

    {

        ans = max(ans,b[n]+max_sum(n-1,1));

    }

    if(p != 2)

    {

        ans = max(ans,c[n]+max_sum(n-1,2));

    }



    return dp[n][p] = ans;

}







int main()

{

  //OJ;

  int t = 1;

  //cin>>t;

  while(t--){

   memset(dp,-1,sizeof(dp));

  int n;

  cin>>n;



  for(int i = 1; i <= n; i++)

  {

      cin>>a[i]>>b[i]>>c[i];

  }

  cout<<max_sum(n,3)<<endl;

  }

   return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.581179699358683x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""
// Slower C++ solution:
#include <bits/stdc++.h>





using namespace std;



vector<vector<int>> vec(100007);

int n;



long long meme[100007][5];





long long solve(int index, int flag){

    if(index==n){

        return 0;

    }

    

    long long &res = meme[index][flag]; 

    

    if(res != -1){

        return res;

    }

    res = 0;

    

    if(flag!=0){

        res = max(res,vec[index][0]+solve(index+1,0));

    }

    if(flag!=1){

        res =  max(res,vec[index][1]+solve(index+1,1));

    }

    if(flag!=2){

        res =  max(res,vec[index][2]+solve(index+1,2));

    }

    return res;

}



int main(){

    cin>>n;

    int num1,num2,num3;

    memset(meme,-1,sizeof(meme));

    for(int i = 0 ; i<n ; i++){

        cin>>num1>>num2>>num3;

        vec[i].push_back(num1);

        vec[i].push_back(num2);

        vec[i].push_back(num3);

    }

    long long sol = solve(0,3);

    cout<<sol<<endl;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 7.962755909419476x):
#include <bits/stdc++.h>



#define cn count

#define pb push_back

#define in insert

#define fs first

#define sc second

#define sz size

#define len length

#define forn(i, n) for (ll i = 0; i < (ll) (n); ++i)

#define forni(i, n) for (ll i = 1; i < (ll) (n); ++i)

#define IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)



using namespace std;

using ll = long long;

const ll inf = 1e9+7; 

const double PI =  3.141592653589793;



int main(){

	IO;

	ll n,abc[3],ans = 0;

	cin>>n;

	ll dp[n+1][3];

	memset(dp,0,sizeof(dp));

	forni(i,n+1){

		forn(j,3) cin>>abc[j];

		forn(j,3){

			forn(k,3) if(k!=j)dp[i][j] = max(dp[i][j],dp[i-1][k] + abc[j]);

		}

	}

	forn(i,3) ans = max(dp[n][i],ans);

	cout<<ans<<'\n';

	return 0;

}





// _   .-')                .-. .-')                 .-')                                               

//( '.( OO )_              \  ( OO )               ( OO ).                                             

// ,--.   ,--.).-'),-----. ,--. ,--.  .-'),-----. (_)---\_) ,--. ,--.     .-----.  ,-.-')  .-'),-----. 

// |   `.'   |( OO'  .-.  '|  .'   / ( OO'  .-.  '/    _ |  |  | |  |    '  .--./  |  |OO)( OO'  .-.  '

// |         |/   |  | |  ||      /, /   |  | |  |\  :` `.  |  | | .-')  |  |('-.  |  |  \/   |  | |  |

// |  |'.'|  |\_) |  |\|  ||     ' _)\_) |  |\|  | '..`''.) |  |_|( OO )/_) |OO  ) |  |(_/\_) |  |\|  |

// |  |   |  |  \ |  | |  ||  .   \    \ |  | |  |.-._)   \ |  | | `-' /||  |`-'| ,|  |_.'  \ |  | |  |

// |  |   |  |   `'  '-'  '|  |\   \    `'  '-'  '\       /('  '-'(_.-'(_'  '--'\(_|  |      `'  '-'  '

// """    """     """""""" """  """"      """""""  """""""  """"""""      """"""   """         """""""