// Slower C++ solution:
#include <iostream>

#include <cstdio>

#include <cstdlib>

#include <cstring>

#include <cmath>

#include <algorithm>

#include <vector>

#include <queue>

#include <stack>

using namespace std;

 

//思路：并?集 + ? + ?列 （??取出方式） 



int parent[100016];

int height[100016];



//并?集 

void init(int n)

{

	for(int i = 1; i <= n; i++){

		parent[i] = i;

		height[i] = 0;

	}

}

 

int find(int x)

{

	if(parent[x] == x)  return x;

	else  return parent[x] = find(parent[x]);

}

 

//用来描述原始? 

vector<int> children[100016];

int parent_tree[100016];

bool marked[100016];

int ancestor[100016];

// ?条指令被拆分? 操作 + 目?

stack<char> operation;

stack<int>  target;

 

void bfs(int index, int the_ancestor)

{

	queue<int> q_index;

	queue<int> q_ancestor;

	q_index.push(index);

	q_ancestor.push(the_ancestor);

	while (!q_index.empty())

	{

		the_ancestor = q_ancestor.front(); 

		q_ancestor.pop();

		index = q_index.front(); 

		q_index.pop();

		if(marked[index] == true)  the_ancestor = index;  //如果?点自身被??，?它的染色祖先是自己，它的自己不??的儿子的最近染色祖先是它

		ancestor[index] = the_ancestor;  //??index的最近染色祖先 

		for(vector<int>::iterator it = children[index].begin(); it != children[index].end(); it++){  //将index的儿子加入?列 

			q_index.push(*it);

			q_ancestor.push(the_ancestor);

		}

	}

}

 

int main()

{

 

	int N, Q;

	while(scanf("%d %d", &N, &Q) && (N || Q)){

		for(int i = 1; i <= N; i++){

			children[i].clear();

			marked[i] = false;

		}

		marked[1] = true;

		parent_tree[1] = 1;

		int p;

		for(int i = 2; i <= N; i++){

			scanf("%d", &p);

			parent_tree[i] = p;

			children[p].push_back(i);

		}

		getchar(); 

		for(int i = 0; i < Q; i++){

			char ch;

			int t;

			scanf("%c %d", &ch, &t);

			getchar();

			if(ch == 'M'){

				if(marked[t])  continue;  //不?存重?的 "M v"，防止之后重?反染色 

				else  marked[t] = true;

			}

			operation.push(ch);

			target.push(t);

		}

		bfs(1, 1);

		init(N);

		for(int i = 1; i <= N; i++){

			parent[i] = ancestor[i];

		}

		unsigned long long result = 0;

		while(!operation.empty()){  //从后往前取出操作

			char ch = operation.top(); 

			operation.pop();

			int t = target.top(); 

			target.pop();

			if(ch == 'Q')  result += find(t);  //?目index从1?始

			else{  //??点t反染色（取消染色），t的祖先??其父?点的祖先

				parent[t] = find(parent_tree[t]);

			}

		}

		printf("%lld\n", result);

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.516484568664068x):
#include <stdio.h>

#include <stdlib.h>

#include <cmath>

#include <string.h>

#include <iostream>

#include<algorithm>

#include <queue>

#include <vector>

#include<string>

//******************************************************

#define lrt (rt*2)

#define rrt  (rt*2+1)

#define LL long long

#define inf 0x3f3f3f3f

#define pi acos(-1.0)

#define exp 1e-8

const double temp=(1+sqrt(5))/2;

//***************************************************

#define eps             1e-8

#define inf             0x3f3f3f3f

#define INF             2e18

#define LL              long long

#define ULL             unsigned long long

#define PI              acos(-1.0)

#define pb              push_back

#define mk              make_pair



#define all(a)          a.begin(),a.end()

#define rall(a)         a.rbegin(),a.rend()

#define SQR(a)          ((a)*(a))

#define Unique(a)       sort(all(a)),a.erase(unique(all(a)),a.end())

#define min3(a,b,c)     min(a,min(b,c))

#define max3(a,b,c)     max(a,max(b,c))

#define min4(a,b,c,d)   min(min(a,b),min(c,d))

#define max4(a,b,c,d)   max(max(a,b),max(c,d))

#define max5(a,b,c,d,e) max(max3(a,b,c),max(d,e))

#define min5(a,b,c,d,e) min(min3(a,b,c),min(d,e))

#define Iterator(a)     __typeof__(a.begin())

#define rIterator(a)    __typeof__(a.rbegin())

#define FastRead        ios_base::sync_with_stdio(0);cin.tie(0)

#define CasePrint       pc('C'); pc('a'); pc('s'); pc('e'); pc(' '); write(qq++,false); pc(':'); pc(' ')

#define vi              vector <int>

#define vL              vector <LL>

#define For(I,A,B)      for(int I = (A); I < (B); ++I)

#define rFor(I,A,B)     for(int I = (A); I >= (B); --I)

#define Rep(I,N)        For(I,0,N)

using namespace std;

const int maxn=1e5+10;

int pre[maxn];

void iint()

{

    for(int i=0;i<maxn;i++) pre[i]=i;

}

int find(int x)

{

    return x==pre[x]?x:find(pre[x]);

}

void join(int x,int y)

{

    int fx=find(x),fy=find(y);

    if(fx!=fy)  pre[fx]=fy;

}

int main()

{

    int n,k,num;

    char str[5];

    while(cin>>n>>k)

    {

        LL sum=0;

        if(n+k==0)  break;

        iint();

        for(int i=2;i<=n;i++)

        {

            scanf("%d",&pre[i]);

        }

        while(k--)

        {

            scanf("%s%d",str,&num);

            if(str[0]=='M') pre[num]=num;

            else if(str[0]=='Q')    sum+=find(num);

        }

        cout<<sum<<endl;

    }

    return 0;

}