// Slower C++ solution:
#include <iostream>

#include <queue>

#include <functional>

#include <cstring>

using namespace std;



struct edge{

    int v, d, c;

    edge(){}

    edge(int v, int d, int c) : v(v),d(d),c(c){}

};



int N, M;

const int INF = 0x3f3f3f3f;

typedef pair<int, int> P;//距?， ?点

int d[10665];



vector<edge> G[10665];



void dijkstra(int s){

    priority_queue<P, vector<P>,greater<P> > que;

    memset(d, INF, sizeof(d));

    d[s] = 0;

    que.push(P(0,s));

    while(!que.empty())

    {

        P p = que.top();

        que.pop();

        int q = p.second;

        if(d[q] < p.first) continue;

        for(int i = 0; i < G[q].size(); i++)

        {

            edge e = G[q][i];

            if(d[e.v] > d[q] + e.d)

            {

                d[e.v] = d[q] + e.d;

                que.push(P(d[e.v], e.v));

            }

        }

    }

}





int main()

{

    while(cin >> N >> M)

    {

        if(!N) break;

        for(int i = 0; i < N; i++)

		{

			G[i].clear();

		}

        for(int i = 0; i < M; i++)

        {

            int u,t,c,d;

            cin >> u >> t >> d >> c;

            u--;t--;

            G[u].push_back(edge(t,d,c));

            G[t].push_back(edge(u,d,c));

        }

        dijkstra(0);

        int ans=0;

        for(int k = 1; k < N; k++)

        {

            int mincost = INF;

            for(int j = 0; j < G[k].size(); j++)

            {

                if(d[G[k][j].v]+G[k][j].d == d[k]

                 && G[k][j].c < mincost)

                    mincost = G[k][j].c;

            }

            ans += mincost;

        }

        cout << ans << endl;

    }

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.1245301089268798x):
#include<stdio.h>

#include<string.h>  

#include<math.h>  

  

//#include<map>   

//#include<set>

#include<deque>  

#include<queue>  

#include<stack>  

#include<bitset> 

#include<string>  

#include<iostream>  

#include<algorithm>  

using namespace std;  

  

#define ll long long  

#define INF 0x3f3f3f3f  

#define mod 1000000

#define clean(a,b) memset(a,b,sizeof(a))// 水印 

//spfa

//https://cn.vjudge.net/contest/239171#problem/C 



using namespace std;

//const int maxn=10005;

const int inf=0x3f3f3f3f;

int N,M,k;

int head[10100],cost[10100],dis[10100];

bool vst[10100];

struct node{

    int to,next,dis,cost;

}edge[50100];

void addEdge(int a,int b,int dis,int cost)

{

    edge[k].to=b;

    edge[k].dis=dis;

    edge[k].cost=cost;

    edge[k].next=head[a];

    head[a]=k;

    k++;

}

void spfa(int x)

{

	clean(dis,INF);

	clean(vst,0);

	clean(cost,INF);

//    memset(dis,inf,sizeof(dis));

//    memset(vst,0,sizeof(vst));

//    memset(cost,inf,sizeof(cost));

    queue<int> q;

    dis[x]=0;

    cost[x]=0;

    q.push(x);

    while(!q.empty())

	{

        x=q.front();q.pop();

        vst[x]=0;

        for(int i=head[x];i!=-1;i=edge[i].next)

		{

            node b=edge[i];

            if(dis[b.to]>dis[x]+b.dis)

			{

                if(!vst[b.to])

				{

                    vst[b.to]=1;

                    q.push(b.to);

                }

                dis[b.to]=dis[x]+b.dis;

                cost[b.to]=b.cost;

            }

			else if(dis[b.to]==dis[x]+b.dis)

			{

                if(cost[b.to]>b.cost)

                    cost[b.to]=b.cost;

            }

        }

    }

}



int main()

{

    while(cin>>N>>M,N)

	{

        clean(head,-1);

        k=0;

        for(int i=0;i<M;i++){

            int a,b,d,c;

            cin>>a>>b>>d>>c;

            addEdge(a,b,d,c);

            addEdge(b,a,d,c);

        }

        spfa(1);

        long long re=0;

        for(int i=1;i<=N;i++){

            re+=cost[i];

        }

        cout<<re<<endl;

    }



    return 0;

}