// Slower C++ solution:
//

//  AOJ 0558 Chees

//

//  Created by TaoSama on 2015-02-20

//  Copyright (c) 2014 TaoSama. All rights reserved.

//

#include <algorithm>

#include <cctype>

#include <cmath>

#include <cstdio>

#include <cstdlib>

#include <cstring>

#include <iomanip>

#include <iostream>

#include <map>

#include <queue>

#include <string>

#include <set>

#include <vector>

#define CLR(x,y) memset(x, y, sizeof(x))



using namespace std;

const int INF = 0x3f3f3f3f;

const int MOD = 1e9 + 7;

const int N = 1e5 + 10;



struct Point {

	int x, y;

	Point(int x = 0, int y = 0): x(x), y(y) {}

} c[15];

int n, m, k, dp[1005][1005];

int d[4][2] = { -1, 0, 1, 0, 0, 1, 0, -1};

char a[1005][1005];



int bfs(int x) {

	memset(dp, 0x3f, sizeof dp);

	queue <Point> q; q.push(c[x - 1]);

	dp[c[x - 1].x][c[x - 1].y] = 0;

	while(!q.empty()) {

		Point cur = q.front(); q.pop();

		for(int i = 0; i < 4; ++i) {

			Point nxt(cur.x + d[i][0], cur.y + d[i][1]);

			if(nxt.x < 1 || nxt.x > n || nxt.y < 1 || nxt.y > m

			        || a[nxt.x][nxt.y] == 'X') continue;

			if(dp[nxt.x][nxt.y] == INF) {

				dp[nxt.x][nxt.y] = dp[cur.x][cur.y] + 1;

				q.push(nxt);

			}

		}

	}

	return dp[c[x].x][c[x].y];

}

int main() {

#ifdef LOCAL

	freopen("in.txt", "r", stdin);

//	freopen("out.txt","w",stdout);

#endif

	ios_base::sync_with_stdio(0);



	while(cin >> n >> m >> k) {

		for(int i = 1; i <= n; ++i) {

			for(int j = 1; j <= m; ++j) {

				cin >> a[i][j];

				if(a[i][j] == 'S')

					c[0].x = i, c[0].y = j;

				if(isdigit(a[i][j]))

					c[a[i][j] - '0'].x = i, c[a[i][j] - '0'].y = j;

			}

		}

		int ans = 0;

		for(int i = 1; i <= k; ++i)

			ans += bfs(i);

		cout << ans << endl;

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.5566231294381248x):
#include<cstdio>

#include<cstring>

#include<iostream>

#include<queue>

#include<vector>

#include<algorithm>

#include<string>

#include<cmath>

#include<set>

#include<map>

#include<vector>

#include<stack>

#include<utility>

#include<sstream>

using namespace std;

typedef long long ll;

const int inf = 0x3f3f3f3f;

const int maxn = 1005;

int a[1005][1005];

int x[20], y[20];

int ans, w, h, n;

bool leap[1005][1005];

int dir[4][2] = { 1, 0, -1, 0, 0, 1, 0, -1 };

struct Node

{

	int x, y, t;

	Node(int x, int y, int t) :x(x), y(y), t(t){}

};

int work(int xx, int yy, int pos)

{

	memset(leap, false, sizeof(leap));

	leap[xx][yy] = 1;

	queue<Node>p;

	p.push(Node(xx, yy, 0));

	while (p.size())

	{

		Node temp = p.front();

		p.pop();

		for (int i = 0; i < 4; i++)

		{

			int tempx = temp.x + dir[i][0];

			int tempy = temp.y + dir[i][1];

			if (tempx >= 1 && tempx <= h&&tempy >= 1 && tempy <= w)

			{

				if (a[tempx][tempy] == 1)continue;

				if (leap[tempx][tempy] == 1)continue;

				if (tempx == x[pos + 1] && tempy == y[pos + 1])

				{

					return temp.t + 1;

				}

				leap[tempx][tempy] = 1;

				p.push(Node(tempx, tempy, temp.t + 1));

			}

		}

	}



}

int main()

{

#ifdef LOCAL

	freopen("C:\\Users\\ΡΡ\\Desktop\\in.txt", "r", stdin);

	//freopen("C:\\Users\\ΡΡ\\Desktop\\out.txt","w",stdout);

#endif // LOCAL

	while (scanf("%d%d%d", &h, &w, &n) != EOF)

	{

		char s[1005];

		for (int i = 1; i <= h; i++)

		{

			scanf("%s", s);

			for (int j = 1; j <= w; j++)

			{

				if (s[j - 1] == '.')

					a[i][j] = 0;

				else if (s[j - 1] == 'X')

					a[i][j] = 1;

				else if (s[j - 1] == 'S')

				{

					x[0] = i; y[0] = j;

					a[i][j] = 0;

				}

				else

				{

					a[i][j] = 0;

					int id = s[j - 1] - '0';

					x[id] = i; y[id] = j;

				}

			}

		}

		ans = 0;

		for (int i = 0; i < n; i++)

		{

			ans = ans + work(x[i], y[i], i);

		}

		printf("%d\n", ans);

	}

	return 0;

}