stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

ll dp[100009];

int arr[100009];

ll sum = 0;

long long Frog1(int n){

 

    if(n==0) return 0;

    else if(n==1) return abs(arr[n] - arr[n-1]);

    if(dp[n]!=-1) return dp[n];

    else {

            ll x = Frog1(n-1);

            ll y = Frog1(n-2);

        dp[n] = min(abs (arr[n-1] - arr[n]) + x,abs(arr[n-2] - arr[n]) + y);

        //cout << n << " = " << dp[n] << endl;

         return dp[n];

    }

}

 

 

int main()

{

    int n;

    memset(dp,-1,sizeof(dp));

    cin >> n;

    for(int i=0;i<n;i++) cin >> arr[i];

    cout << Frog1(n-1) << endl;

}

// Faster C++ solution for the same problem (measured speedup: 1.7620615200521756x):
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<unordered_map>

using namespace std;

//<DEFINE>

void Fast() {

	ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

}

void File() {

#ifndef ONLINE_JUDGE

	freopen("Input.txt", "r", stdin);

	freopen("Output.txt", "w", stdout);

#endif

}

#define ll long long

#define ull unsigned long long

#define mod 1000000007

ll gcd(ll a, ll b) {

	return!b ? a : gcd(b, a % b);

}

#define fix(n) cout << fixed << setprecision(n);

#define numOfOnes(n) __builtin_popcount(n)

#define all(a) a.begin(), a.end()

#define skip continue

#define stop(n) return cout<<n,0

#define pi  acos(-1)

#define endl "\n"

#define ceil(x,y) (x+y-1)/y

//</DEFINE>



/*█▀▀▄░░░░░░░░░░░▄▀▀█

░█░░░▀▄░▄▄▄▄▄░▄▀░░░█

░░▀▄░░░▀░░░░░▀░░░▄▀

░░░░▌░▄▄░░░▄▄░▐▀▀

░░░▐░░█▄░░░▄█░░▌▄▄▀▀▀▀█

░░░▌▄▄▀▀░▄░▀▀▄▄▐░░░░░░█

▄▀▀▐▀▀░▄▄▄▄▄░▀▀▌▄▄▄░░░█

█░░░▀▄░█░░░█░▄▀░░░░█▀▀▀

░▀▄░░▀░░▀▀▀░░▀░░░▄█▀

░░░█░░░░░░░░░░░▄▀▄░▀▄

░░░█░░░░░░░░░▄▀█░░█░░█

░░░█░░░░░░░░░░░█▄█░░▄▀

░░░█░░░░░░░░░░░████▀

░░░▀█▄▄▄▀▀▀▀▄▄▄█▀*/

int n;

vector<int>v;

int res[100001];

//<FUNCTIONS>

ll solve(int idx = 0) {

	ll res1, res2;

	if (idx == n - 1)return 0;

	if (~(res[idx]))return res[idx];

	res1 = 1e18;

	if (idx + 2 < n)res1 = solve(idx + 2) + abs(v[idx] - v[idx+2]);

	res2 = solve(idx + 1) + abs(v[idx] - v[idx+1]);

	return res[idx] = min(res1, res2);

}

//</FUNCTIONS>		

int main() {

	Fast();

	cin >> n;

	for (int i = 0; i <= n; i++)

		res[i] = -1;

	v.resize(n);

	for (int i = 0; i < n; i++)cin >> v[i];

	cout << solve()<<endl;

}
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

#define ll long long

#define ld long double

#define sf scanf

#define pf printf

#define pb push_back

#define llu unsigned long long

#define U unsigned int

#define SIZE 1000002

#define pie 3.14159265358979323

#define minuss 1e-6

#define FAST ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)

 

#define BIG 100000000

 

ll  lcm(ll a,ll b)

{

    ll GCD=__gcd(a,b);

    ll lcm=(a*b)/GCD;

    return lcm;

}

ll dp[100005];

ll weight[1000005],value[1000005];

ll total,val;

ll call(ll n)

{

    if(n>=total)

        return 0;

 

    if(dp[n]!=-1)

        return dp[n];

 

    ll res1=BIG,res2=BIG;

 

   // if(weight[n]+c<=val)

    res1=abs(weight[n]-weight[n+1]) + call(n+1);

    if(n+2<=total) res2=abs(weight[n]-weight[n+2]) + call(n+2);

    //cout<<n<<" "<<res1<<" "<<res2<<endl;

    dp[n]=min(res1,res2);

    return dp[n];

 

}

int main()

{

    cin>>total;

    for ( int i = 1; i <=total; ++i )

        cin>>weight[i];

 

    memset(dp, -1, sizeof(dp));

    ll ret=call(1);

    cout<<ret<<endl;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.7614008693100522x):
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<unordered_map>

using namespace std;

//<DEFINE>

void Fast() {

	ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

}

void File() {

#ifndef ONLINE_JUDGE

	freopen("Input.txt", "r", stdin);

	freopen("Output.txt", "w", stdout);

#endif

}

#define ll long long

#define ull unsigned long long

#define mod 1000000007

ll gcd(ll a, ll b) {

	return!b ? a : gcd(b, a % b);

}

#define fix(n) cout << fixed << setprecision(n);

#define numOfOnes(n) __builtin_popcount(n)

#define all(a) a.begin(), a.end()

#define skip continue

#define stop(n) return cout<<n,0

#define pi  acos(-1)

#define endl "\n"

#define ceil(x,y) (x+y-1)/y

//</DEFINE>



/*█▀▀▄░░░░░░░░░░░▄▀▀█

░█░░░▀▄░▄▄▄▄▄░▄▀░░░█

░░▀▄░░░▀░░░░░▀░░░▄▀

░░░░▌░▄▄░░░▄▄░▐▀▀

░░░▐░░█▄░░░▄█░░▌▄▄▀▀▀▀█

░░░▌▄▄▀▀░▄░▀▀▄▄▐░░░░░░█

▄▀▀▐▀▀░▄▄▄▄▄░▀▀▌▄▄▄░░░█

█░░░▀▄░█░░░█░▄▀░░░░█▀▀▀

░▀▄░░▀░░▀▀▀░░▀░░░▄█▀

░░░█░░░░░░░░░░░▄▀▄░▀▄

░░░█░░░░░░░░░▄▀█░░█░░█

░░░█░░░░░░░░░░░█▄█░░▄▀

░░░█░░░░░░░░░░░████▀

░░░▀█▄▄▄▀▀▀▀▄▄▄█▀*/

int n;

vector<int>v;

int res[100001];

//<FUNCTIONS>

ll solve(int idx = 0) {

	ll res1, res2;

	if (idx == n - 1)return 0;

	if (~(res[idx]))return res[idx];

	res1 = 1e18;

	if (idx + 2 < n)res1 = solve(idx + 2) + abs(v[idx] - v[idx+2]);

	res2 = solve(idx + 1) + abs(v[idx] - v[idx+1]);

	return res[idx] = min(res1, res2);

}

//</FUNCTIONS>		

int main() {

	Fast();

	cin >> n;

	for (int i = 0; i <= n; i++)

		res[i] = -1;

	v.resize(n);

	for (int i = 0; i < n; i++)cin >> v[i];

	cout << solve()<<endl;

}
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;



int num[100001], memo[100001];



int dp(int n){

    if(n==0) return 0;

    if(n==1) return abs(num[0]-num[1]);

    if(memo[n]!=-1) return memo[n];

    return memo[n]=min(dp(n-1)+abs(num[n-1]-num[n]), dp(n-2)+abs(num[n-2]-num[n]));

}



int main(){

    //freopen("in.txt", "r", stdin);

    //freopen("out.txt", "w", stdout);

    ios_base::sync_with_stdio(0);

    cin.tie(0);

    memset(memo, -1, sizeof(memo));

    int n;

    cin>>n;

    for(int i=0; i<n; ++i) cin>>num[i];

    cout<<dp(n-1)<<"\n";

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.3785936332555178x):
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<unordered_map>

using namespace std;

//<DEFINE>

void Fast() {

	ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

}

void File() {

#ifndef ONLINE_JUDGE

	freopen("Input.txt", "r", stdin);

	freopen("Output.txt", "w", stdout);

#endif

}

#define ll long long

#define ull unsigned long long

#define mod 1000000007

ll gcd(ll a, ll b) {

	return!b ? a : gcd(b, a % b);

}

#define fix(n) cout << fixed << setprecision(n);

#define numOfOnes(n) __builtin_popcount(n)

#define all(a) a.begin(), a.end()

#define skip continue

#define stop(n) return cout<<n,0

#define pi  acos(-1)

#define endl "\n"

#define ceil(x,y) (x+y-1)/y

//</DEFINE>



/*█▀▀▄░░░░░░░░░░░▄▀▀█

░█░░░▀▄░▄▄▄▄▄░▄▀░░░█

░░▀▄░░░▀░░░░░▀░░░▄▀

░░░░▌░▄▄░░░▄▄░▐▀▀

░░░▐░░█▄░░░▄█░░▌▄▄▀▀▀▀█

░░░▌▄▄▀▀░▄░▀▀▄▄▐░░░░░░█

▄▀▀▐▀▀░▄▄▄▄▄░▀▀▌▄▄▄░░░█

█░░░▀▄░█░░░█░▄▀░░░░█▀▀▀

░▀▄░░▀░░▀▀▀░░▀░░░▄█▀

░░░█░░░░░░░░░░░▄▀▄░▀▄

░░░█░░░░░░░░░▄▀█░░█░░█

░░░█░░░░░░░░░░░█▄█░░▄▀

░░░█░░░░░░░░░░░████▀

░░░▀█▄▄▄▀▀▀▀▄▄▄█▀*/

int n;

vector<int>v;

int res[100001];

//<FUNCTIONS>

ll solve(int idx = 0) {

	ll res1, res2;

	if (idx == n - 1)return 0;

	if (~(res[idx]))return res[idx];

	res1 = 1e18;

	if (idx + 2 < n)res1 = solve(idx + 2) + abs(v[idx] - v[idx+2]);

	res2 = solve(idx + 1) + abs(v[idx] - v[idx+1]);

	return res[idx] = min(res1, res2);

}

//</FUNCTIONS>		

int main() {

	Fast();

	cin >> n;

	for (int i = 0; i <= n; i++)

		res[i] = -1;

	v.resize(n);

	for (int i = 0; i < n; i++)cin >> v[i];

	cout << solve()<<endl;

}
// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;

int v[100010];

int memo[100010];

int c;



int f(int i)

{



    if(memo[i]!=-1)

        return memo[i];



    if(i == 0)

        return memo[0] = 0;



    if(i == 1)

        return memo[1] = abs(v[0] - v[1]);



    return memo[i] = min(abs(v[i] - v[i-1]) + f(i-1), abs(v[i] - v[i-2]) + f(i-2));

}



int main()

{



    memset(memo, -1, sizeof(memo));

    cin>>c;



    for(int i = 0; i<c; i++)

    {

        cin>>v[i];

    }



    cout<<f(c-1)<<endl;



    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.3644456737420791x):
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<unordered_map>

using namespace std;

//<DEFINE>

void Fast() {

	ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

}

void File() {

#ifndef ONLINE_JUDGE

	freopen("Input.txt", "r", stdin);

	freopen("Output.txt", "w", stdout);

#endif

}

#define ll long long

#define ull unsigned long long

#define mod 1000000007

ll gcd(ll a, ll b) {

	return!b ? a : gcd(b, a % b);

}

#define fix(n) cout << fixed << setprecision(n);

#define numOfOnes(n) __builtin_popcount(n)

#define all(a) a.begin(), a.end()

#define skip continue

#define stop(n) return cout<<n,0

#define pi  acos(-1)

#define endl "\n"

#define ceil(x,y) (x+y-1)/y

//</DEFINE>



/*█▀▀▄░░░░░░░░░░░▄▀▀█

░█░░░▀▄░▄▄▄▄▄░▄▀░░░█

░░▀▄░░░▀░░░░░▀░░░▄▀

░░░░▌░▄▄░░░▄▄░▐▀▀

░░░▐░░█▄░░░▄█░░▌▄▄▀▀▀▀█

░░░▌▄▄▀▀░▄░▀▀▄▄▐░░░░░░█

▄▀▀▐▀▀░▄▄▄▄▄░▀▀▌▄▄▄░░░█

█░░░▀▄░█░░░█░▄▀░░░░█▀▀▀

░▀▄░░▀░░▀▀▀░░▀░░░▄█▀

░░░█░░░░░░░░░░░▄▀▄░▀▄

░░░█░░░░░░░░░▄▀█░░█░░█

░░░█░░░░░░░░░░░█▄█░░▄▀

░░░█░░░░░░░░░░░████▀

░░░▀█▄▄▄▀▀▀▀▄▄▄█▀*/

int n;

vector<int>v;

int res[100001];

//<FUNCTIONS>

ll solve(int idx = 0) {

	ll res1, res2;

	if (idx == n - 1)return 0;

	if (~(res[idx]))return res[idx];

	res1 = 1e18;

	if (idx + 2 < n)res1 = solve(idx + 2) + abs(v[idx] - v[idx+2]);

	res2 = solve(idx + 1) + abs(v[idx] - v[idx+1]);

	return res[idx] = min(res1, res2);

}

//</FUNCTIONS>		

int main() {

	Fast();

	cin >> n;

	for (int i = 0; i <= n; i++)

		res[i] = -1;

	v.resize(n);

	for (int i = 0; i < n; i++)cin >> v[i];

	cout << solve()<<endl;

}
// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;



const int N = 1e5 + 9;



int n, h[N], dp[N];



int solve(int i){

    if(i == n - 1)  return 0;

    if(i == n)   return 1e9;



    int &ret = dp[i];

    if(~ret)    return ret;



    return ret = min(abs(h[i] - h[i + 1]) + solve(i + 1), abs(h[i] - h[i + 2]) + solve(i + 2));

}



int main(){



    cin >> n;

    for(int i = 0;i < n;i++)

        cin >> h[i];



    memset(dp, -1, sizeof dp);



    cout << solve(0);

}


// Faster C++ solution for the same problem (measured speedup: 1.367419638168909x):
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<unordered_map>

using namespace std;

//<DEFINE>

void Fast() {

	ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

}

void File() {

#ifndef ONLINE_JUDGE

	freopen("Input.txt", "r", stdin);

	freopen("Output.txt", "w", stdout);

#endif

}

#define ll long long

#define ull unsigned long long

#define mod 1000000007

ll gcd(ll a, ll b) {

	return!b ? a : gcd(b, a % b);

}

#define fix(n) cout << fixed << setprecision(n);

#define numOfOnes(n) __builtin_popcount(n)

#define all(a) a.begin(), a.end()

#define skip continue

#define stop(n) return cout<<n,0

#define pi  acos(-1)

#define endl "\n"

#define ceil(x,y) (x+y-1)/y

//</DEFINE>



/*█▀▀▄░░░░░░░░░░░▄▀▀█

░█░░░▀▄░▄▄▄▄▄░▄▀░░░█

░░▀▄░░░▀░░░░░▀░░░▄▀

░░░░▌░▄▄░░░▄▄░▐▀▀

░░░▐░░█▄░░░▄█░░▌▄▄▀▀▀▀█

░░░▌▄▄▀▀░▄░▀▀▄▄▐░░░░░░█

▄▀▀▐▀▀░▄▄▄▄▄░▀▀▌▄▄▄░░░█

█░░░▀▄░█░░░█░▄▀░░░░█▀▀▀

░▀▄░░▀░░▀▀▀░░▀░░░▄█▀

░░░█░░░░░░░░░░░▄▀▄░▀▄

░░░█░░░░░░░░░▄▀█░░█░░█

░░░█░░░░░░░░░░░█▄█░░▄▀

░░░█░░░░░░░░░░░████▀

░░░▀█▄▄▄▀▀▀▀▄▄▄█▀*/

int n;

vector<int>v;

int res[100001];

//<FUNCTIONS>

ll solve(int idx = 0) {

	ll res1, res2;

	if (idx == n - 1)return 0;

	if (~(res[idx]))return res[idx];

	res1 = 1e18;

	if (idx + 2 < n)res1 = solve(idx + 2) + abs(v[idx] - v[idx+2]);

	res2 = solve(idx + 1) + abs(v[idx] - v[idx+1]);

	return res[idx] = min(res1, res2);

}

//</FUNCTIONS>		

int main() {

	Fast();

	cin >> n;

	for (int i = 0; i <= n; i++)

		res[i] = -1;

	v.resize(n);

	for (int i = 0; i < n; i++)cin >> v[i];

	cout << solve()<<endl;

}
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

#define N (int)2e5

int n,memo[N],c[N];



int dp(int curr) {

    if (curr == n) return 0;

    if (curr > n) return 1e9;

    int &sol = memo[curr];

    if (sol != -1) return sol;

    sol = min(

        dp(curr + 1) + abs(c[curr] - c[curr + 1]) ,

        dp(curr + 2) + abs(c[curr] - c[curr + 2])

    );

    return sol;

}



int main() {

    scanf("%d" , &n);

    for (int i = 1 ; i <= n ; i++)

        scanf("%d" , &c[i]);

    memset (memo , -1 , sizeof memo);

    printf("%d\n" , dp(1));

}


// Faster C++ solution for the same problem (measured speedup: 1.7514320187885477x):
#include <bits/stdc++.h>

#include <algorithm>

#include <climits>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <iostream>

#include <math.h>

using namespace __gnu_pbds;

using namespace std;

#define ll long long

typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> pbds;

#define vll vector<ll> 

#define nl cout << endl

#define fr(a,b) for(auto i=a;i<b;i++)

#define pll pair<ll,ll>

#define f first

#define s second

#define vpll vector<pll>

#define ump unordered_map

#define YES cout << "YES" << endl

#define NO cout << "NO" << endl

#define IN(a,b) ((a).find(b)!=(a).end())

#define pb push_back

#define mkp make_pair

#define PI M_PI

#define INF 1e18

#define deb(x) if(ON) cout << #x <<" : " << x << endl

#define fast ios_base::sync_with_stdio(false)

#define io cin.tie(NULL),cout.tie(NULL)

#define ON !false

ll dx[]={0,-1,0,1};

ll dy[]={1,0,-1,0};

const ll mod=1e9+7;

ll i,j;

ll add(ll a,ll b){

    return  ((a%mod)+(b%mod)+mod)%mod;

}

ll mul(ll a,ll b){

    return ((a%mod)*(b%mod)+mod)%mod;

}

void pause(ll id){

    cout << "Waiting " << id << endl;

    cin >> id;

}



const int mxn=1e5+10;

ll n,t;





signed main(){

    fast;

    io;

    if(!true){

        freopen("in.txt","r",stdin);

        freopen("out.txt","w",stdout);

    }



    cin >> n;

    ll h[n];

    vll ans(n,0);

    ll i,j;

    for(i=0;i<n;i++){

        cin >> h[i];

    }

    for(i=1;i<n;i++){

        ll mn=abs(h[i]-h[i-1])+ans[i-1];

        if(i>=2){

            mn=min(mn,abs(h[i]-h[i-2])+ans[i-2]);

        }

        ans[i]+=mn;

    }

    cout << ans[n-1] << endl;

   

    return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define ll long long int

#define dbl double

#define pi acos(-1)

#define sc1(a) scanf("%lld",&a)

#define sc2(a,b) scanf("%lld%lld",&a,&b)

#define sc3(a,b,c) scanf("%lld%lld%lld",&a,&b,&c)

#define pb push_back



ll ara[1000005];



map<ll,ll>vis;

map<ll,ll>vis1;

map<ll,ll>pos;

map<ll,ll>high;

map<ll,ll>low;

map<string,ll>mp;

vector<ll>vec;

vector<ll>v;

stack<ll>q;

string str1[100];

string str2[100];

priority_queue<ll>pq;

ll dp[1000005],t;

ll mn=1000000;

ll call(ll id)

{

    if(id==t )return 0;

    if(dp[id]!=-1)

        return dp[id];

    ll p=call(id+1)+abs(ara[id+1]-ara[id]);

    ll q=100000000;

    if(id+2!=t+1)

        q=call(id+2)+abs(ara[id+2]-ara[id]);

    dp[id]=min(p,q);

    return dp[id];



}

int main()

{



    // ll t;

    memset(dp,-1,sizeof(dp));

    sc1(t);

    for(ll i=1; i<=t; i++)

    {

        sc1(ara[i]);

    }

    cout<<call(1)<<endl;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 9.207946713960602x):
#include <bits/stdc++.h>

#include <algorithm>

#include <climits>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <iostream>

#include <math.h>

using namespace __gnu_pbds;

using namespace std;

#define ll long long

typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> pbds;

#define vll vector<ll> 

#define nl cout << endl

#define fr(a,b) for(auto i=a;i<b;i++)

#define pll pair<ll,ll>

#define f first

#define s second

#define vpll vector<pll>

#define ump unordered_map

#define YES cout << "YES" << endl

#define NO cout << "NO" << endl

#define IN(a,b) ((a).find(b)!=(a).end())

#define pb push_back

#define mkp make_pair

#define PI M_PI

#define INF 1e18

#define deb(x) if(ON) cout << #x <<" : " << x << endl

#define fast ios_base::sync_with_stdio(false)

#define io cin.tie(NULL),cout.tie(NULL)

#define ON !false

ll dx[]={0,-1,0,1};

ll dy[]={1,0,-1,0};

const ll mod=1e9+7;

ll i,j;

ll add(ll a,ll b){

    return  ((a%mod)+(b%mod)+mod)%mod;

}

ll mul(ll a,ll b){

    return ((a%mod)*(b%mod)+mod)%mod;

}

void pause(ll id){

    cout << "Waiting " << id << endl;

    cin >> id;

}



const int mxn=1e5+10;

ll n,t;





signed main(){

    fast;

    io;

    if(!true){

        freopen("in.txt","r",stdin);

        freopen("out.txt","w",stdout);

    }



    cin >> n;

    ll h[n];

    vll ans(n,0);

    ll i,j;

    for(i=0;i<n;i++){

        cin >> h[i];

    }

    for(i=1;i<n;i++){

        ll mn=abs(h[i]-h[i-1])+ans[i-1];

        if(i>=2){

            mn=min(mn,abs(h[i]-h[i-2])+ans[i-2]);

        }

        ans[i]+=mn;

    }

    cout << ans[n-1] << endl;

   

    return 0;

}
// Slower C++ solution:
#include <bits/stdc++.h>



#define forn(i, n) for (int i = 0; i < int(n); ++i)

#define for1(i, n) for (int i = 1; i <= int(n); ++i)

#define fore(i, l, r) for (int i = int(l); i <= int(r); ++i)

#define ford(i, n) for (int i = int(n)-1; i >= 0; --i)

#define pb push_back

#define eb emplace_back

#define ms(a, x) memset(a, x, sizeof(a))

#define F first

#define S second

#define endl '\n'

#define de(x) cout<<#x<<" = "<<(x)<<endl

#define de2(x,y) cout<<#x<<" = "<<(x) <<' '<< #y<<" = "<<y<<endl;



using namespace std;



typedef long long ll;

typedef pair<int, int> pii;

const int INF = 0x3f3f3f3f;

mt19937 gen(chrono::high_resolution_clock::now().time_since_epoch().count());



const int N=1e5+5;

int dp[N];

int main() {

    ios::sync_with_stdio(false);

    cin.tie(nullptr);

	int n;

	cin>>n;

	vector<int> a(n);

	for(auto& it:a) cin>>it;

	ms(dp,INF);

	dp[0]=0;

	for(int i=1;i<n;i++){

		dp[i]=min(dp[i],dp[i-1]+abs(a[i]-a[i-1]));

		if(i>1) dp[i]=min(dp[i],dp[i-2]+abs(a[i]-a[i-2]));

	}

	cout<<dp[n-1];

    return 0;

}




// Faster C++ solution for the same problem (measured speedup: 1.3994627865289277x):
#include <bits/stdc++.h>

#include <algorithm>

#include <climits>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <iostream>

#include <math.h>

using namespace __gnu_pbds;

using namespace std;

#define ll long long

typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> pbds;

#define vll vector<ll> 

#define nl cout << endl

#define fr(a,b) for(auto i=a;i<b;i++)

#define pll pair<ll,ll>

#define f first

#define s second

#define vpll vector<pll>

#define ump unordered_map

#define YES cout << "YES" << endl

#define NO cout << "NO" << endl

#define IN(a,b) ((a).find(b)!=(a).end())

#define pb push_back

#define mkp make_pair

#define PI M_PI

#define INF 1e18

#define deb(x) if(ON) cout << #x <<" : " << x << endl

#define fast ios_base::sync_with_stdio(false)

#define io cin.tie(NULL),cout.tie(NULL)

#define ON !false

ll dx[]={0,-1,0,1};

ll dy[]={1,0,-1,0};

const ll mod=1e9+7;

ll i,j;

ll add(ll a,ll b){

    return  ((a%mod)+(b%mod)+mod)%mod;

}

ll mul(ll a,ll b){

    return ((a%mod)*(b%mod)+mod)%mod;

}

void pause(ll id){

    cout << "Waiting " << id << endl;

    cin >> id;

}



const int mxn=1e5+10;

ll n,t;





signed main(){

    fast;

    io;

    if(!true){

        freopen("in.txt","r",stdin);

        freopen("out.txt","w",stdout);

    }



    cin >> n;

    ll h[n];

    vll ans(n,0);

    ll i,j;

    for(i=0;i<n;i++){

        cin >> h[i];

    }

    for(i=1;i<n;i++){

        ll mn=abs(h[i]-h[i-1])+ans[i-1];

        if(i>=2){

            mn=min(mn,abs(h[i]-h[i-2])+ans[i-2]);

        }

        ans[i]+=mn;

    }

    cout << ans[n-1] << endl;

   

    return 0;

}
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;



int a[1000001];

int dp[1000001];

int it;



int fr(int p){

	if (p==it-1){

      return 0;

    }

	if(dp[p]!=-1){

      return dp[p];

    }

	int re=abs(a[p]-a[p+1])+fr(p+1);

	if(p!=it-2){

      re=min(re,abs(a[p]-a[p+2])+fr(p+2));

    }

	return dp[p]=re;

}

int main(){

	cin>>it;

	for(int i=0;i<it;i++){

    cin>>a[i];

    }



	memset(dp,-1,sizeof dp);

	cout<<fr(0)<<endl;

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 4.975496057249196x):
#include <bits/stdc++.h>

#include <algorithm>

#include <climits>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <iostream>

#include <math.h>

using namespace __gnu_pbds;

using namespace std;

#define ll long long

typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> pbds;

#define vll vector<ll> 

#define nl cout << endl

#define fr(a,b) for(auto i=a;i<b;i++)

#define pll pair<ll,ll>

#define f first

#define s second

#define vpll vector<pll>

#define ump unordered_map

#define YES cout << "YES" << endl

#define NO cout << "NO" << endl

#define IN(a,b) ((a).find(b)!=(a).end())

#define pb push_back

#define mkp make_pair

#define PI M_PI

#define INF 1e18

#define deb(x) if(ON) cout << #x <<" : " << x << endl

#define fast ios_base::sync_with_stdio(false)

#define io cin.tie(NULL),cout.tie(NULL)

#define ON !false

ll dx[]={0,-1,0,1};

ll dy[]={1,0,-1,0};

const ll mod=1e9+7;

ll i,j;

ll add(ll a,ll b){

    return  ((a%mod)+(b%mod)+mod)%mod;

}

ll mul(ll a,ll b){

    return ((a%mod)*(b%mod)+mod)%mod;

}

void pause(ll id){

    cout << "Waiting " << id << endl;

    cin >> id;

}



const int mxn=1e5+10;

ll n,t;





signed main(){

    fast;

    io;

    if(!true){

        freopen("in.txt","r",stdin);

        freopen("out.txt","w",stdout);

    }



    cin >> n;

    ll h[n];

    vll ans(n,0);

    ll i,j;

    for(i=0;i<n;i++){

        cin >> h[i];

    }

    for(i=1;i<n;i++){

        ll mn=abs(h[i]-h[i-1])+ans[i-1];

        if(i>=2){

            mn=min(mn,abs(h[i]-h[i-2])+ans[i-2]);

        }

        ans[i]+=mn;

    }

    cout << ans[n-1] << endl;

   

    return 0;

}
// Slower C++ solution:


#include <iostream>

#include <bits/stdc++.h>





using namespace std;





int a[100005], p[100005],n, i;

int respuesta(int x)

{

    if(x==n) return 0;

    if(x>n) return 1e9;

    if(p[x]!=-1)return p[x];

    return p[x]=min(abs(a[x+1]-a[x])+respuesta(x+1), abs(a[x+2]-a[x])+respuesta(x+2));

}





int main()

{

    memset(p,-1,sizeof p);

    cin>>n;

    for(i=1;i<=n;i++)

    {

        cin>>a[i];

    }

    cout<<respuesta(1)<<endl;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.3738518121464998x):
#include <bits/stdc++.h>

#include <algorithm>

#include <climits>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <iostream>

#include <math.h>

using namespace __gnu_pbds;

using namespace std;

#define ll long long

typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> pbds;

#define vll vector<ll> 

#define nl cout << endl

#define fr(a,b) for(auto i=a;i<b;i++)

#define pll pair<ll,ll>

#define f first

#define s second

#define vpll vector<pll>

#define ump unordered_map

#define YES cout << "YES" << endl

#define NO cout << "NO" << endl

#define IN(a,b) ((a).find(b)!=(a).end())

#define pb push_back

#define mkp make_pair

#define PI M_PI

#define INF 1e18

#define deb(x) if(ON) cout << #x <<" : " << x << endl

#define fast ios_base::sync_with_stdio(false)

#define io cin.tie(NULL),cout.tie(NULL)

#define ON !false

ll dx[]={0,-1,0,1};

ll dy[]={1,0,-1,0};

const ll mod=1e9+7;

ll i,j;

ll add(ll a,ll b){

    return  ((a%mod)+(b%mod)+mod)%mod;

}

ll mul(ll a,ll b){

    return ((a%mod)*(b%mod)+mod)%mod;

}

void pause(ll id){

    cout << "Waiting " << id << endl;

    cin >> id;

}



const int mxn=1e5+10;

ll n,t;





signed main(){

    fast;

    io;

    if(!true){

        freopen("in.txt","r",stdin);

        freopen("out.txt","w",stdout);

    }



    cin >> n;

    ll h[n];

    vll ans(n,0);

    ll i,j;

    for(i=0;i<n;i++){

        cin >> h[i];

    }

    for(i=1;i<n;i++){

        ll mn=abs(h[i]-h[i-1])+ans[i-1];

        if(i>=2){

            mn=min(mn,abs(h[i]-h[i-2])+ans[i-2]);

        }

        ans[i]+=mn;

    }

    cout << ans[n-1] << endl;

   

    return 0;

}