// Slower C++ solution:
/*

*

*/

#include<iostream>

#include<cstring>

#include<cstdio>

#include<cmath>

#include<string>

#include<queue>

#define CLR(ARR,NUM) memset(ARR,NUM,sizeof(ARR))

#define GETNUM(NUM) scanf("%d",&NUM)

#define faster_io() ios_base::sync_with_stdio(false)

using namespace std;

const int MAXN = 1010;

char map[MAXN][MAXN];

bool vis[10][MAXN][MAXN];

struct node{

	int x;

	int y;

	int deep;

	int n;

};

int dx[]={0,0,1,-1};

int dy[]={1,-1,0,0};



int main()

{

	CLR(vis,false);

	CLR(map,'X');

	int h,w,n;

	cin >> h >> w >> n;

	getchar();

	int sx,sy;

	for(int i=1;i<=h;i++){

		for(int j=1;j<=w;j++){

			map[i][j]=getchar();

			if(map[i][j]=='S'){

				sx=i;

				sy=j;

			}

		}

		getchar();

	}

	node t;

	t.x=sx;

	t.y=sy;

	t.deep=0;

	t.n=0;

	queue<node>q;

	vis[0][sx][sy]=true;

	q.push(t);

	int ans = -1;

	while(!q.empty()){

		node cur=q.front();

		if(cur.n==n){

			ans=cur.deep;

			break;

		}

		q.pop();

		for(int i=0;i<4;i++){

			int tx=cur.x+dx[i];

			int ty=cur.y+dy[i];

			if(map[tx][ty]!='X'&&!vis[cur.n][tx][ty]){

				node t = cur;

				t.x=tx;

				t.y=ty;

				t.deep++;

				if(map[tx][ty]=='1'+t.n){

					t.n++;

				}

				vis[t.n][tx][ty]=true;

				q.push(t);

			}

		}

	}

	cout << ans << endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.517102448835457x):
#include<iostream>

#include<queue>

#include<cctype>





using namespace std;



int cnt;

char field[1002][1002];

int cost[1002][1002];

int factory[9][2];

int x[4] = {1, 0, -1, 0};

int y[4] = {0, 1, 0, -1};



int bfs(int sx, int sy, int gx, int gy) {

    queue< pair<int,int> > que;



    for(int i = 0; i < 1002; i++) {

        for (int j = 0; j < 1002; j++) {

            cost[i][j] = -1;

        }

    }



    que.push(make_pair(sx, sy));

    cost[sx][sy] = 0;



    while(!que.empty()) {

        pair<int, int> p;

        p = que.front();

        que.pop();

        

        if(p.first == gx && p.second == gy) {

            break;

        }



        for(int i = 0; i < 4; i++) {

            int tx = p.first + x[i]; int ty = p.second + y[i];

            if(field[tx][ty] != 'X' && cost[tx][ty] == -1) {

                que.push(pair<int, int>(tx, ty));

                cost[tx][ty] = cost[p.first][p.second] + 1;

            }

        }

    }

    return cost[gx][gy];

}



int main() {

    int w, h, n, sx, sy;



    cin >> h >> w >> n;



    for (int y = 1; y <= h; y++) {

        for (int x = 1; x <= w; x++) {

            cin >> field[x][y];

            if (field[x][y] == 'S') {

                sx = x;

                sy = y;

            } else if(isdigit(field[x][y])) {

                int tmp = field[x][y] - '0';

                factory[tmp][0] = x;

                factory[tmp][1] = y;

            }

        }

        field[0][y] = 'X';

        field[w + 1][y] = 'X';

    }



    for (int x = 0; x <= w + 1; x++) {

        field[x][0] = 'X';

        field[x][h + 1] = 'X';

    }



    int cnt = 0;

    for (int i = 1; i <= n; i++) {

        // 次の目的地へ行くで

        cnt += bfs(sx, sy, factory[i][0], factory[i][1]);

        sx = factory[i][0];

        sy = factory[i][1];

    }



    cout << cnt << endl;

}