stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include<cstdio>  

#include<iostream>  

#include<algorithm>  

#include<cstdlib>  

#include<cstring>

#include<string>

#include<climits>

#include<vector>

#include<cmath>

#include<map>

#define LL long long



using namespace std;



inline char nc(){

  static char buf[100000],*p1=buf,*p2=buf;

  if (p1==p2) { p2=(p1=buf)+fread(buf,1,100000,stdin); if (p1==p2) return EOF; }

  return *p1++;

}



inline void read(int &x){

  char c=nc(),b=1;

  for (;!(c>='0' && c<='9');c=nc()) if (c=='-') b=-1;

  for (x=0;c>='0' && c<='9';x=x*10+c-'0',c=nc()); x*=b;

}



inline void read(LL &x){

  char c=nc(),b=1;

  for (;!(c>='0' && c<='9');c=nc()) if (c=='-') b=-1;

  for (x=0;c>='0' && c<='9';x=x*10+c-'0',c=nc()); x*=b;

}



int wt,ss[19];

inline void print(int x){

	if (x<0) x=-x,putchar('-'); 

	if (!x) putchar(48); else {for (wt=0;x;ss[++wt]=x%10,x/=10);for (;wt;putchar(ss[wt]+48),wt--);}

}

inline void print(LL x){

	if (x<0) x=-x,putchar('-');

	if (!x) putchar(48); else {for (wt=0;x;ss[++wt]=x%10,x/=10);for (;wt;putchar(ss[wt]+48),wt--);}

}



LL n,m;



int main()

{

    read(n);read(m);    

    LL x,y,z;

	vector<LL> a(m+10);

    for(int i=0;i<n;i++)

	{

		read(x);read(y);

        z=y-x+1;a[0]+=1;a[z]-=1;

        LL t=z+1,s;

        while(t<=m)

		{

            LL v=((x+t-1)/t);

            if((x+t-1)/t<=0) break;

            s=y/((x+t-1)/t);

            if(s>=t) a[t-1]+=1,a[s]-=1;

            if((x+t-1)/t<=1) break;

            t=max(s+1,(x+(v-1)-1)/(v-1));

        }

    }

    LL ans=0;

    for (int i=0;i<m;i++)

    	ans+=a[i],cout<<ans<<endl;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 5.138296517100874x):
#include <cstdio>

#include <algorithm>

using namespace std;

int n,m,f[100005],g[100005];



void zzk(int L,int R){

	for (int k=1,kk,kkk,a,Max,Min; k<=m && k<=R;){

		// k<=kk<=(l-1)/a

		a=(L-1)/k;

		if (a==0) Max=99999999; else Max=(L-1)/a; Min=k-1;

		kk=R/(a+1);

		kk=min(kk,Max); kk=max(kk,Min);

		f[k]++; f[kk+1]--;

		k=Max+1;

	}

}



int main(){

	scanf("%d%d",&n,&m);

	for (int i=1,l,r; i<=n; i++){

		scanf("%d%d",&l,&r);

		zzk(l,r);

	}

	for (int i=1; i<=m; i++) g[i]=g[i-1]+f[i],printf("%d\n",g[i]);

}



/*

3 3

1 2

2 3

3 3



*/
// Slower C++ solution:
//============================================================================

// Name        : test.cpp

// Author      : Qihan

// Version     :

// Copyright   : Your copyright notice

// Description : Hello World in C++, Ansi-style

//============================================================================



#include <bits/stdc++.h>

#define Lowbit(x) (x & (-x))

using namespace std;

typedef long long int LLI;

typedef pair<int,int> PII;

const int maxn = (300000 + 10);



struct Seg{

	int l,r,len;

}op[maxn];



bool cmp(Seg a,Seg b){

	return a.len < b.len;

}



int c[maxn];



void add(int x,int change,int n){

	while(x < n){

		c[x] += change;

		x += Lowbit(x);

	}

}



int sum(int x){

	int ans = 0;

	while(x > 0){

		ans += c[x];

		x -= Lowbit(x);

	}

	return ans;

}



int main(){

//	freopen("/home/qihan/Documents/in","r",stdin);

	int n,m;

	memset(c,0,sizeof(c));

	scanf("%d%d",&n,&m);

	for(int i = 1;i <= n;i ++){

		scanf("%d%d",&op[i].l,&op[i].r);

		op[i].len = op[i].r - op[i].l + 1;

	}

	sort(op + 1,op + 1 + n,cmp);

	int k = 1;

	for(int i = 1;i <= m;i ++){

		for(;k <= n && op[k].len < i;k ++){

			add(op[k].l,1,300000);

			add(op[k].r + 1,-1,300000);

		}

		int ans = n - k + 1;

		for(int j = i;j <= m;j += i){

			ans += sum(j);

		}

		printf("%d\n",ans);

	}

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 11.303535313137068x):
#include <cstdio>

#include <algorithm>

using namespace std;

int n,m,f[100005],g[100005];



void zzk(int L,int R){

	for (int k=1,kk,kkk,a,Max,Min; k<=m && k<=R;){

		// k<=kk<=(l-1)/a

		a=(L-1)/k;

		if (a==0) Max=99999999; else Max=(L-1)/a; Min=k-1;

		kk=R/(a+1);

		kk=min(kk,Max); kk=max(kk,Min);

		f[k]++; f[kk+1]--;

		k=Max+1;

	}

}



int main(){

	scanf("%d%d",&n,&m);

	for (int i=1,l,r; i<=n; i++){

		scanf("%d%d",&l,&r);

		zzk(l,r);

	}

	for (int i=1; i<=m; i++) g[i]=g[i-1]+f[i],printf("%d\n",g[i]);

}



/*

3 3

1 2

2 3

3 3



*/
// Slower C++ solution:
#include <iostream>

#include <cstdio>

#include <cmath>

#include <cstring>

#include <algorithm>

#include <vector>

#include <map>

#include <cstdlib>

#include <set>

#include <stack>

#include <queue>

using namespace std;



#define X first

#define Y second

#define N 300010

#define M 400010

typedef long long ll;

typedef pair<int,int> pii;

const int Mod=1000000007;



int n,m;

int c[N];

vector<pii> g[N];



inline int Lowbit(int x){return x&(-x);}



void Add(int x,int v)

{

	while (x<=m)

	{

		c[x]+=v;

		x+=Lowbit(x);

	}

}



int Val(int x)

{

	int res=0;

	while (x)

	{

		res+=c[x];

		x-=Lowbit(x);

	}

	return res;

}



int main()

{

	//freopen("in.in","r",stdin);

	//freopen("out.out","w",stdout);

	

	scanf("%d%d",&n,&m);

	for (int i=1;i<=n;i++)

	{

		int l,r; scanf("%d%d",&l,&r);

		g[r-l+1].push_back(make_pair(l,r));

	}

	int sz=0;

	for (int i=1;i<=m;i++)

	{

		int x=i,res=0;

		do

		{

			res+=Val(x);

			x+=i;

		}while (x<=m);

		

		for (int j=0;j<g[i].size();j++)

		{

			Add(g[i][j].X,1);

			Add(g[i][j].Y+1,-1);

		}

		printf("%d\n",res+n-sz);

		sz+=g[i].size();

	}

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 9.447986423829457x):
#include <iostream>

#include <cstdlib>

#include <cstdio>

#include <cmath>

using namespace std;

int read(){

	int x=0,f=1;char ch=getchar();

	while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}

	while(ch>='0'&&ch<='9'){x=x*10+ch-48;ch=getchar();}

	return x*f;

}



const int maxn = 300100;

const int maxm = 100100;



struct edge{int l,r;}a[maxn];

int n,m;

int c[maxn];



void modify(int l,int r,int x){

	//printf("%d %d\n",l,r);

	c[l]+=x,c[r+1]-=x;

}



int main(){

	n=read(),m=read();

	//c[1]+=n;

	for(int i=1;i<=n;i++)

		a[i].l=read(),a[i].r=read();

	for(int i=1;i<=n;i++){

		int l=a[i].l,r=a[i].r;

		int block=sqrt(r);

		//printf("->>>>>%d %d %d\n",l,r,block);

		int x=0,last=0x7f7f7f7f;

		for(int j=1;j<=block;j++){

			int sl=l/j,sr=r/j;

			if(sl&&l%j) sl++;

			sr = min(last,sr);

			if(sl&&sl<=sr) modify(sl,sr,1);

			if(j==block) x=sl-1;

			last = sl-1;

		}

		int sb=r/block;

		for(int j=1;j<=min(sb,x);j++)

			if((l%j==0)||l/j<r/j) modify(j,j,1);

	}

	for(int i=1;i<=m;i++) c[i]+=c[i-1];

	for(int i=1;i<=m;i++)

		printf("%d\n",c[i]);

}
// Slower C++ solution:
#include<set>

#include<map>

#include<stack>

#include<queue>

#include<deque>

#include<cmath>

#include<cstdio>

#include<cctype>

#include<string>

#include<vector>

#include<cstdlib>

#include<cstring>

#include<sstream>

#include<iostream>

#include<algorithm>

#define MAXN 300000

#define MAXM 100000

#define lowbit(x) (x&(-x))



using namespace std;



int n,m;

vector<int>gg[MAXM+80];

struct node{

	int a[MAXM+80];

	void add(int x,int A)

	{

		while(x<=m)

		{

			a[x]+=A;

			x+=lowbit(x);

		}

		return ;

	}

	int S(int x)

	{

		int sum=0;

		while(x)

		{

			sum+=a[x];

			x-=lowbit(x);

		}

		return sum;

	}

}tree;

int main()//You'll know it's a copy.

{

	int i,j,l,r,tmp=0,S;

	scanf("%d%d",&n,&m);

	for(i=1;i<=n;i++)

	{

		scanf("%d%d",&l,&r);

		gg[r-l+1].push_back(l);

	}

	for(i=1;i<=m;i++)

	{

		S=0;

		for(j=i;j<=m;j+=i)

			S+=tree.S(j);

		for(j=0;j<gg[i].size();j++)

			tree.add(gg[i][j],-1),tree.add(i+gg[i][j],1);

		printf("%d\n",n-tmp-S);

		tmp+=gg[i].size();

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 3.544138610531338x):
#include <iostream>

#include <cstdlib>

#include <cstdio>

#include <cmath>

using namespace std;

int read(){

	int x=0,f=1;char ch=getchar();

	while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}

	while(ch>='0'&&ch<='9'){x=x*10+ch-48;ch=getchar();}

	return x*f;

}



const int maxn = 300100;

const int maxm = 100100;



struct edge{int l,r;}a[maxn];

int n,m;

int c[maxn];



void modify(int l,int r,int x){

	//printf("%d %d\n",l,r);

	c[l]+=x,c[r+1]-=x;

}



int main(){

	n=read(),m=read();

	//c[1]+=n;

	for(int i=1;i<=n;i++)

		a[i].l=read(),a[i].r=read();

	for(int i=1;i<=n;i++){

		int l=a[i].l,r=a[i].r;

		int block=sqrt(r);

		//printf("->>>>>%d %d %d\n",l,r,block);

		int x=0,last=0x7f7f7f7f;

		for(int j=1;j<=block;j++){

			int sl=l/j,sr=r/j;

			if(sl&&l%j) sl++;

			sr = min(last,sr);

			if(sl&&sl<=sr) modify(sl,sr,1);

			if(j==block) x=sl-1;

			last = sl-1;

		}

		int sb=r/block;

		for(int j=1;j<=min(sb,x);j++)

			if((l%j==0)||l/j<r/j) modify(j,j,1);

	}

	for(int i=1;i<=m;i++) c[i]+=c[i-1];

	for(int i=1;i<=m;i++)

		printf("%d\n",c[i]);

}
// Slower C++ solution:
//============================================================================

// Name        : test.cpp

// Author      : Qihan

// Version     :

// Copyright   : Your copyright notice

// Description : Hello World in C++, Ansi-style

//============================================================================



#include <bits/stdc++.h>

#define Lowbit(x) (x & (-x))

using namespace std;

typedef long long int LLI;

typedef pair<int,int> PII;

const int maxn = (300000 + 10);



struct Seg{

	int l,r,len;

}op[maxn];



bool cmp(Seg a,Seg b){

	return a.len < b.len;

}



int c[maxn];



void add(int x,int change,int n){

	while(x < n){

		c[x] += change;

		x += Lowbit(x);

	}

}



int sum(int x){

	int ans = 0;

	while(x > 0){

		ans += c[x];

		x -= Lowbit(x);

	}

	return ans;

}



int main(){

//	freopen("/home/qihan/Documents/in","r",stdin);

	int n,m;

	memset(c,0,sizeof(c));

	scanf("%d%d",&n,&m);

	for(int i = 1;i <= n;i ++){

		scanf("%d%d",&op[i].l,&op[i].r);

		op[i].len = op[i].r - op[i].l + 1;

	}

	sort(op + 1,op + 1 + n,cmp);

	int k = 1;

	for(int i = 1;i <= m;i ++){

		for(;k <= n && op[k].len < i;k ++){

			add(op[k].l,1,300000);

			add(op[k].r + 1,-1,300000);

		}

		int ans = n - k + 1;

		for(int j = i;j <= m;j += i){

			ans += sum(j);

		}

		printf("%d\n",ans);

	}

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.209659143236819x):
#include <iostream>

#include <cstdlib>

#include <cstdio>

#include <cmath>

using namespace std;

int read(){

	int x=0,f=1;char ch=getchar();

	while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}

	while(ch>='0'&&ch<='9'){x=x*10+ch-48;ch=getchar();}

	return x*f;

}



const int maxn = 300100;

const int maxm = 100100;



struct edge{int l,r;}a[maxn];

int n,m;

int c[maxn];



void modify(int l,int r,int x){

	//printf("%d %d\n",l,r);

	c[l]+=x,c[r+1]-=x;

}



int main(){

	n=read(),m=read();

	//c[1]+=n;

	for(int i=1;i<=n;i++)

		a[i].l=read(),a[i].r=read();

	for(int i=1;i<=n;i++){

		int l=a[i].l,r=a[i].r;

		int block=sqrt(r);

		//printf("->>>>>%d %d %d\n",l,r,block);

		int x=0,last=0x7f7f7f7f;

		for(int j=1;j<=block;j++){

			int sl=l/j,sr=r/j;

			if(sl&&l%j) sl++;

			sr = min(last,sr);

			if(sl&&sl<=sr) modify(sl,sr,1);

			if(j==block) x=sl-1;

			last = sl-1;

		}

		int sb=r/block;

		for(int j=1;j<=min(sb,x);j++)

			if((l%j==0)||l/j<r/j) modify(j,j,1);

	}

	for(int i=1;i<=m;i++) c[i]+=c[i-1];

	for(int i=1;i<=m;i++)

		printf("%d\n",c[i]);

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;



typedef long long ll;

typedef pair<int, int> PII;

typedef pair<int, PII> PIP;



const int MM = 1e9 + 7;

const double eps = 1e-8;

const int MAXN = 2e6 + 10;



int n, m;



void prework(){



}



void read(){



}



vector<PIP> E;



class BITree{

public:

    static const int SIZE = 100010, BIAS = 5;

    long long u[SIZE];

    void clear(){

        memset(u,0,sizeof(u));

    }

    void modify(int x, long long v){

        for(x+=BIAS;x<SIZE;x+=x&-x) u[x]+=v;

    }

    long long getsum(int x){

        long long s=0;

        for(x+=BIAS;x;x-=x&-x) s+=u[x];

        return s;

    }

} honoka;



int ans[MAXN];



void solve(int casi){

	scanf("%d%d", &n, &m);

	for(int i = 1; i <= n; i++){

		int x, y;

		scanf("%d%d", &x, &y);

		E.push_back(PIP(y, PII(-1, x)));

	}

	ans[1] = 0;

	for(int i = 2; i <= m; i++){

		ans[i] = 0;

		for(int j = 0; j < m; j += i){

			E.push_back(PIP(min(j + i - 1, m), PII(i, j + 1)));

		}

	}

	sort(E.begin(), E.end());

	for(int i = 0; i < E.size(); i++){

		if (E[i].second.first < 0){

			honoka.modify(-1, 1);

			honoka.modify(E[i].second.second+1, -1);

		}

		else{

			ans[E[i].second.first] += honoka.getsum(E[i].second.second);

		}

	}

	for(int i = 1; i <= m; i++)

		printf("%d\n", n - ans[i]);

}



void printans(){



}





int main(){

	prework();

	int T = 1;

//	cin>>T;

	for(int i = 1; i <= T; i++){

		read();

		solve(i);

		printans();

	}

	return 0;

}






// Faster C++ solution for the same problem (measured speedup: 4.752383659748203x):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <cmath>

using namespace std;

const int SIZEN = 3 * 100010;

const int SIZEM = 100010;

int l[SIZEN] = {0},r[SIZEN] = {0};

int ans[SIZEM] = {0};

int N,M;





void Input(){

	scanf("%d%d",&N,&M);

	for(int i = 1;i <= N;i++)scanf("%d%d",&l[i],&r[i]);

}





void Judge(int x){

//	printf("x = %d\n",x);

	int ll,rr;

	int n = sqrt(l[x]);

	int last = M+1;

	for(int i = 1;i <= n;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		rr = min(last-1,rr);

		last = min(ll,last);

		if(ll > rr)continue;

		ans[ll]++;ans[rr+1]--;

	}

	for(int i = 1;i < last;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		if(ll > rr)continue;

		

		ans[i]++;ans[i+1]--;

	} 

} 

void Work(){

	for(int i = 1;i <= N;i++)Judge(i);

	for(int i = 1;i <= M;i++)ans[i] += ans[i-1];

	for(int i = 1;i <= M;i++)printf("%d\n",ans[i]);

}

int main(){

	Input();

	Work();

	return 0;

}
// Slower C++ solution:
#include <bits/stdc++.h>



typedef long long LL;



using namespace std;



int N,M;

struct Event

{

	int len,L,R;	

};

vector<Event>E;



Event Make(int len,int L,int R)

{

	return (Event){len,L,R};

}



int Tr[300010];

int lowbit(int x){return x&-x;}

int getsum(int x){int S=0;while(x){S+=Tr[x];x-=lowbit(x);}return S;}

void add(int x,int y){while(x<=M){Tr[x]+=y;x+=lowbit(x);}}



bool cmp(Event A,Event B)

{

	return A.len<B.len;

}



int main()

{

	scanf("%d%d",&N,&M);

	for (int i=1;i<=N;i++)

	{

		int LL,RR;

		scanf("%d%d",&LL,&RR);

		E.push_back(Make(RR-LL+1,LL,RR));

	}

	sort(E.begin(),E.end(),cmp);

	int now = 0;

	int cnt = N;

	for (int i=1;i<=M;i++)

	{

		while(now<E.size() && E[now].len<i)

		{

			Event tmp = E[now];

			add(tmp.L,1);

			add(tmp.R+1,-1);

			now++;

			cnt--;

		}

		int ans = cnt;

		for (int j=i;j<=M;j+=i) ans+=getsum(j);

		printf("%d\n",ans);

	}

}

// Faster C++ solution for the same problem (measured speedup: 4.737448067522345x):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <cmath>

using namespace std;

const int SIZEN = 3 * 100010;

const int SIZEM = 100010;

int l[SIZEN] = {0},r[SIZEN] = {0};

int ans[SIZEM] = {0};

int N,M;





void Input(){

	scanf("%d%d",&N,&M);

	for(int i = 1;i <= N;i++)scanf("%d%d",&l[i],&r[i]);

}





void Judge(int x){

//	printf("x = %d\n",x);

	int ll,rr;

	int n = sqrt(l[x]);

	int last = M+1;

	for(int i = 1;i <= n;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		rr = min(last-1,rr);

		last = min(ll,last);

		if(ll > rr)continue;

		ans[ll]++;ans[rr+1]--;

	}

	for(int i = 1;i < last;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		if(ll > rr)continue;

		

		ans[i]++;ans[i+1]--;

	} 

} 

void Work(){

	for(int i = 1;i <= N;i++)Judge(i);

	for(int i = 1;i <= M;i++)ans[i] += ans[i-1];

	for(int i = 1;i <= M;i++)printf("%d\n",ans[i]);

}

int main(){

	Input();

	Work();

	return 0;

}
// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;



typedef long long LL;



const int N = 3e5 + 10, M = 1e5 + 10;

int n, m;

int l[N], r[N], idx[N], len[N];

int a[M];



bool cmp(int x, int y) {

    return len[x] < len[y];

}



void add(int x, int v) {

    for (; x <= m + 1; x += x & -x) a[x] += v;

}



int query(int x) {

    int ret = 0;

    for (; x; x -= x &-x) ret += a[x];

    return ret;

}



int main() {

    scanf("%d%d", &n, &m);

    for (int i = 0; i < n; i++) {

        scanf("%d%d", l + i, r + i); 

        len[i] = r[i] - l[i] + 1;

        idx[i] = i;

    }

    sort(idx, idx + n, cmp);

    int j = 0;

    for (int i = 1; i <= m; i++) {

        while (j < n && len[idx[j]] < i) {

            add(l[idx[j]], 1);

            add(r[idx[j]]+1, -1);

            j++;

        }

        int ans = 0;

        for (int k = i; k <= m; k += i) ans += query(k);

        printf("%d\n", ans + n - j);

    }

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 4.723144723922626x):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <cmath>

using namespace std;

const int SIZEN = 3 * 100010;

const int SIZEM = 100010;

int l[SIZEN] = {0},r[SIZEN] = {0};

int ans[SIZEM] = {0};

int N,M;





void Input(){

	scanf("%d%d",&N,&M);

	for(int i = 1;i <= N;i++)scanf("%d%d",&l[i],&r[i]);

}





void Judge(int x){

//	printf("x = %d\n",x);

	int ll,rr;

	int n = sqrt(l[x]);

	int last = M+1;

	for(int i = 1;i <= n;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		rr = min(last-1,rr);

		last = min(ll,last);

		if(ll > rr)continue;

		ans[ll]++;ans[rr+1]--;

	}

	for(int i = 1;i < last;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		if(ll > rr)continue;

		

		ans[i]++;ans[i+1]--;

	} 

} 

void Work(){

	for(int i = 1;i <= N;i++)Judge(i);

	for(int i = 1;i <= M;i++)ans[i] += ans[i-1];

	for(int i = 1;i <= M;i++)printf("%d\n",ans[i]);

}

int main(){

	Input();

	Work();

	return 0;

}
// Slower C++ solution:
#include <iostream>

#include <cstdio>

#include <cmath>

#include <cstring>

#include <algorithm>

#include <vector>

#include <map>

#include <cstdlib>

#include <set>

#include <stack>

#include <queue>

using namespace std;



#define X first

#define Y second

#define N 300010

#define M 400010

typedef long long ll;

typedef pair<int,int> pii;

const int Mod=1000000007;



int n,m;

int c[N];

vector<pii> g[N];



inline int Lowbit(int x){return x&(-x);}



void Add(int x,int v)

{

	while (x<=m)

	{

		c[x]+=v;

		x+=Lowbit(x);

	}

}



int Val(int x)

{

	int res=0;

	while (x)

	{

		res+=c[x];

		x-=Lowbit(x);

	}

	return res;

}



int main()

{

	//freopen("in.in","r",stdin);

	//freopen("out.out","w",stdout);

	

	scanf("%d%d",&n,&m);

	for (int i=1;i<=n;i++)

	{

		int l,r; scanf("%d%d",&l,&r);

		g[r-l+1].push_back(make_pair(l,r));

	}

	int sz=0;

	for (int i=1;i<=m;i++)

	{

		int x=i,res=0;

		do

		{

			res+=Val(x);

			x+=i;

		}while (x<=m);

		

		for (int j=0;j<g[i].size();j++)

		{

			Add(g[i][j].X,1);

			Add(g[i][j].Y+1,-1);

		}

		printf("%d\n",res+n-sz);

		sz+=g[i].size();

	}

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 44.775284004007915x):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <cmath>

using namespace std;

const int SIZEN = 3 * 100010;

const int SIZEM = 100010;

int l[SIZEN] = {0},r[SIZEN] = {0};

int ans[SIZEM] = {0};

int N,M;





void Input(){

	scanf("%d%d",&N,&M);

	for(int i = 1;i <= N;i++)scanf("%d%d",&l[i],&r[i]);

}





void Judge(int x){

//	printf("x = %d\n",x);

	int ll,rr;

	int n = sqrt(l[x]);

	int last = M+1;

	for(int i = 1;i <= n;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		rr = min(last-1,rr);

		last = min(ll,last);

		if(ll > rr)continue;

		ans[ll]++;ans[rr+1]--;

	}

	for(int i = 1;i < last;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		if(ll > rr)continue;

		

		ans[i]++;ans[i+1]--;

	} 

} 

void Work(){

	for(int i = 1;i <= N;i++)Judge(i);

	for(int i = 1;i <= M;i++)ans[i] += ans[i-1];

	for(int i = 1;i <= M;i++)printf("%d\n",ans[i]);

}

int main(){

	Input();

	Work();

	return 0;

}
// Slower C++ solution:
#include<set>

#include<map>

#include<stack>

#include<queue>

#include<deque>

#include<cmath>

#include<cstdio>

#include<cctype>

#include<string>

#include<vector>

#include<cstdlib>

#include<cstring>

#include<sstream>

#include<iostream>

#include<algorithm>

#define MAXN 300000

#define MAXM 100000

#define lowbit(x) (x&(-x))



using namespace std;



int n,m;

vector<int>gg[MAXM+80];

struct node{

	int a[MAXM+80];

	void add(int x,int A)

	{

		while(x<=m)

		{

			a[x]+=A;

			x+=lowbit(x);

		}

		return ;

	}

	int S(int x)

	{

		int sum=0;

		while(x)

		{

			sum+=a[x];

			x-=lowbit(x);

		}

		return sum;

	}

}tree;

int main()//You'll know it's a copy.

{

	int i,j,l,r,tmp=0,S;

	scanf("%d%d",&n,&m);

	for(i=1;i<=n;i++)

	{

		scanf("%d%d",&l,&r);

		gg[r-l+1].push_back(l);

	}

	for(i=1;i<=m;i++)

	{

		S=0;

		for(j=i;j<=m;j+=i)

			S+=tree.S(j);

		for(j=0;j<gg[i].size();j++)

			tree.add(gg[i][j],-1),tree.add(i+gg[i][j],1);

		printf("%d\n",n-tmp-S);

		tmp+=gg[i].size();

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 16.796151657867277x):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <cmath>

using namespace std;

const int SIZEN = 3 * 100010;

const int SIZEM = 100010;

int l[SIZEN] = {0},r[SIZEN] = {0};

int ans[SIZEM] = {0};

int N,M;





void Input(){

	scanf("%d%d",&N,&M);

	for(int i = 1;i <= N;i++)scanf("%d%d",&l[i],&r[i]);

}





void Judge(int x){

//	printf("x = %d\n",x);

	int ll,rr;

	int n = sqrt(l[x]);

	int last = M+1;

	for(int i = 1;i <= n;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		rr = min(last-1,rr);

		last = min(ll,last);

		if(ll > rr)continue;

		ans[ll]++;ans[rr+1]--;

	}

	for(int i = 1;i < last;i++){

		if(l[x]%i == 0) ll = l[x]/i;

		else ll = l[x]/i+1;

		rr = r[x]/i;

		if(ll > rr)continue;

		

		ans[i]++;ans[i+1]--;

	} 

} 

void Work(){

	for(int i = 1;i <= N;i++)Judge(i);

	for(int i = 1;i <= M;i++)ans[i] += ans[i-1];

	for(int i = 1;i <= M;i++)printf("%d\n",ans[i]);

}

int main(){

	Input();

	Work();

	return 0;

}