// Slower C++ solution:
/**

 *  Author : Coda

 *  Title : OSU!

 *  Date : 2019-08-20

 */

#include <bits/stdc++.h>

using namespace std ;



typedef long long ll ;

typedef unsigned long long ull ;

typedef double DB ;

const long long mod = 1e9+7 ;

const double pi = acos(-1) ;

#define PB push_back

#define MP make_pair

#define lb lower_bound

#define ub upper_bound

#define fs first

#define sd second

#define pii pair<int,int>

#define INF 0x3f3f3f3f

#define LLINF 0x3f3f3f3f3f3f3f3f

#define debug(x) cout << #x << " = " << x << endl

#define debug2(x,y) cout << #x << " = " << x << ' ' << #y << " = " << y << endl

#define debug3(x,y,z) cout << #x << " = " << x << ' ' << #y << " = " << y << ' ' << #z << " = " << z << endl

//#pragma comment(linker,"/STACK:10240000,10240000")

//#include <random>

//mt19937 rand_(time(0));

ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}

ll qpow(ll a,ll b,ll c){ll t=1;while(b){if(b&1)t=t*a%c;a=a*a%c;b>>=1;}return t;}

ll inv(ll x){return qpow(x,mod-2,mod);}

int test = 1 ;



const int maxn = 5 + 3e5 ;

const int maxm = 5 + 1e6 ;

// Write the variables here



int N,W ;

ll v[maxn],w[maxn] ;

ll dp[maxn] ;



//#define TEST

int main(){

#ifdef TEST

    freopen("in.txt","r",stdin) ;

#endif

    while(test--){

        // code begins

        scanf("%d%d",&N,&W) ;



        ll sum = 0 ;

        for(int i=1 ; i<=N ; i++){

            scanf("%lld%lld",&w[i],&v[i]) ;

        }

        for(int i=1 ; i<=100000 ; i++){

            dp[i] = LLINF ;

        }

        dp[0] = 0;

        ll ans = 0 ;

        for(int i=1 ; i<=N ; i++){

            for(int j=100000 ; j>=v[i] ; j--){

                dp[j] = min(dp[j],dp[j-v[i]]+w[i]);

            }

        }

        for(int i=1 ; i<=100000 ; i++){

            if(dp[i]<=W) ans = max(ans,i*1ll) ;

        }

        printf("%lld\n",ans) ;



    }

#ifdef TEST

    cout << "time: " << (long long)clock() * 1000 / CLOCKS_PER_SEC << " ms" << endl;

#endif

    return 0 ;

}


// Faster C++ solution for the same problem (measured speedup: 2.5036977187322886x):
#include <bits/stdc++.h>

#define FIN         ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)

#define ii          pair<int,int>

#define F           first

#define S           second

#define pb          push_back

#define all(x)      (x).begin(),(x).end()

#define rall(x)     (x).rbegin(),(x).rend()

#define fore(i,a,b) for(int i = a;i < b; i+= 1)

#define forr(i,a)   for(int i = a; i >= 0; i--)

#define fori(i,m)   for(auto i = m.begin(); i != m.end(); i++) 

#define w(t)        while(t--)

#define sz(s)       int(s.size())

#define cls(a,car)  memset(a,car,sizeof (a))

#define db(x)       cerr << #x << " is " << x << '\n'

#define FL          freopen("input.txt", "r", stdin),freopen("output.txt", "w", stdout);

#define EjecuteTime cerr << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n"

#define angle(x)    double(x * acos(-1) / 180.0)

using namespace std;

typedef long long   ll;

typedef vector<int> vi;

typedef vector<ii>  vii;

const int N = 1 * 1e5 + 5;

const ll mod = 1e9 + 7;

const double E = 1e-9;

//int dx[] = {1, 0}, dy[] = {0, 1};

//int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};

//int dx[] = {2, 1, -1, -2, -2, -1, 1, 2}, dy[] = {1, 2, 2, 1, -1, -2, -2, -1};

//int dx[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy[] = {0 ,1, 1, 1, 0, -1, -1, -1};

// fflush(stdout)

// cout << flush

// a + b = a ^ b + 2 * (a & b)

int n, W;

ll w[101];

int v[101];

ll dp[2][N];

ll f(int i, int want){

    if(want < 0)return 1e18;

    if(i == n)return want == 0 ? 0 : 1e18;

    ll &ans = dp[i][want];

    if(ans == -1){

        ans = 1e18;

        ans = min(f(i + 1, want), ans);

        ans = min(ans, f(i + 1, want - v[i]) + w[i]);



    }return ans;

}

int main(){

    //FL;

    FIN;

    cin >> n >> W;

    // optimizando memoria

    int sum = 0;

    for(int i = 0; i < n; i++){

        cin >> w[i] >> v[i];

        sum += v[i];

    }

    for(int i = n; i >= 0; i--){

        for(int want = 0; want <= sum; want++){// hast limite sumaMAx

            ll &ans = dp[i & 1][want];

            if(i == n){

                ans = want == 0 ? 0 : 1e18;

                continue;

            }

            ans = 1e18;

            ans = min(ans, dp[(i + 1) & 1][want]);

            if(want - v[i] >= 0)

                ans = min(ans, dp[(i + 1) & 1][want - v[i]] + w[i]);

        }

    }

    int ans = 0;

    for(int i = 0; i < sum + 1; i++){

        ll cur = dp[0 & 1][i];

        if(cur <= W)

            ans = i;

    }

    cout << ans << '\n';

    EjecuteTime;

    return 0;

}