// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;

typedef pair<int, int> P;

typedef long long ll;



const int maxv = 10000 + 10;

struct edge

{

    int to, d, c;

    edge() {}

    edge(int to, int d, int c):to(to), d(d), c(c) {}

};

vector<edge> G[maxv];

int d[maxv];



int N, M;



void dijkstra(int s)

{

    priority_queue<P, vector<P>, greater<P> > que;

    memset(d, 0x3f, sizeof(d));

    d[s] = 0;

    que.push(P(0, s));

    while(!que.empty())

    {

        P p = que.top(); que.pop();

        int v = p.second;

        if(p.first > d[v]) continue;

        for(int i=0; i<G[v].size(); i++)

        {

            edge e = G[v][i];

            if(d[e.to] > d[v]+e.d)

            {

                d[e.to] = d[v] + e.d;

                que.push(P(d[e.to], e.to));

            }

        }

    }

}



int main()

{

    while(scanf("%d%d", &N, &M)==2 && N)

    {

        for(int i=0; i<N; i++)  G[i].clear();

        for(int i=0; i<M; i++)

        {

            int u, v, d, c;

            scanf("%d%d%d%d", &u, &v, &d, &c);

            u--; v--;

            G[u].push_back(edge(v, d, c));

            G[v].push_back(edge(u, d, c));

        }

        dijkstra(0);

        int ans = 0;

        for(int i=1; i<N; i++)

        {

            int mincost = 0x3f3f3f3f;

            for(int j=0; j<G[i].size(); j++)

            {

                edge e = G[i][j];

                if(d[e.to]+e.d==d[i] && e.c<mincost)

                    mincost = e.c;

            }

            ans += mincost;

        }

        printf("%d\n", ans);

    }

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.1768873920072005x):
#include<cstdio>

#include<algorithm>

#include<queue>

#include<iostream>

#include<cstring>

using namespace std;

const int maxn = 10050, maxe = 2005000, inf = 1e9;

struct node {

	int to;

	int w;

	int c;

	int next;

};

node edge[maxe];

int head[maxn];

int ip;

void init()

{

	memset(head, -1, sizeof(head));

	ip = 0;

}

void addedge(int u, int v, int w, int c)

{

	edge[ip].to = v;

	edge[ip].c = c;

	edge[ip].w = w;

	edge[ip].next = head[u];

	head[u] = ip++;

}

int cost[maxn], dis[maxn], vis[maxn];

queue<int>q;

void spfa(int s, int n)

{

	while (!q.empty())

		q.pop();

	for (int i = 1; i <= n; i++)

		dis[i] = cost[i] = inf;

	memset(vis, 0, sizeof(vis));

	dis[s] = 0, cost[s] = 0, vis[s] = 1;

	q.push(s);

	while (q.size())

	{

		int u = q.front();

		q.pop();

		vis[u] = 0;

		for (int i = head[u]; i != -1; i = edge[i].next)

		{

			int to = edge[i].to, val = edge[i].w;

			if (dis[to] > dis[u] + val || (dis[to] == dis[u] + val&&cost[to] > edge[i].c))

			{

				dis[to] = dis[u] + val;

				cost[to] = edge[i].c;

				if (!vis[to])

				{

					q.push(to);

					vis[to] = 1;

				}

			}

		}

	}

}

int main()

{

	int n, m, u, v, w, c;

	while (scanf("%d %d", &n, &m),m,n)

	{

		init();

		for (int i = 0; i < m; i++)

		{

			scanf("%d %d %d %d", &u, &v, &w, &c);

			addedge(u, v, w, c);

			addedge(v, u, w, c);

		}

		spfa(1, n);

		int ans = 0;

		for (int i = 1; i <= n; i++)

			ans += cost[i];

		printf("%d\n", ans);

	}

	return 0;

}