stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define L long long

#define W V<L>

#define R(n) for(L i=0;i<n;i++)

W S(V<W>&p,L E){if(!E){return{1,0};}V<V<W>>T(2);for(W x:p){T[x[1]&1].push_back({x[0]/2,x[1]/2});if(x[0]&1){T[(x[1]+1)&1].push_back({x[0]/2,(x[1]+1)/2});}}V<W>c(4,W(3));c[3]=W(3,1);R(2){for(W x:T[i]){L Q=(2*x[0]+x[1])%3;c[i][Q]^=1;}}R(2){if(c[!i]==c[2]||c[!i]==c[3]){W ans=S(T[i],E-1);ans[0]*=2;ans[1]*=2;ans[1]+=i;return ans;}}for(W&v:p){v[0]++;}W A=S(p,E);A[0]--;return A;}

int main(){L M=2e17;L n;cin>>n;V<W>p(n);R(n){L a,b;cin>>a>>b;p[i]={a+M,b+M};}W Q=S(p,70);cout<<Q[0]-M<<" "<<Q[1]-M;}

// Faster C++ solution for the same problem (measured speedup: 1.1446012693593108x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  vel c(2);

	rep(i, 2) {

		for (pin x : qab[i]) {

			int qc = (2 * x.first + x.second) % 3;

          c[i]^=(qc+1);

		}

	}

	rep(i, 2) {

		if (!c[1 - i]) {

			pin ans = solve(qab[i], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += i;

			return ans;

		}

	}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define L long long

#define W V<L>

#define R(n) for(L i=0;i<n;i++)

#define X return

W S(V<W>&p,L E){if(!E){X{1,0};}V<V<W>>T(2);for(W x:p){T[x[1]&1].push_back({x[0]/2,x[1]/2});if(x[0]&1){T[(x[1]+1)&1].push_back({x[0]/2,(x[1]+1)/2});}}V<W>c(4,W(3));c[3]=W(3,1);R(2){for(W x:T[i]){L Q=(2*x[0]+x[1])%3;c[i][Q]^=1;}}R(2){if(c[!i]==c[2]||c[!i]==c[3]){W ans=S(T[i],E-1);ans[0]*=2;ans[1]*=2;ans[1]+=i;X ans;}}for(W&v:p){v[0]++;}W A=S(p,E);A[0]--;X A;}

int main(){L M=2e17;L n;cin>>n;V<W>p(n);R(n){L a,b;cin>>a>>b;p[i]={a+M,b+M};}W Q=S(p,70);cout<<Q[0]-M<<" "<<Q[1]-M;}

// Faster C++ solution for the same problem (measured speedup: 1.1446012693593108x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  vel c(2);

	rep(i, 2) {

		for (pin x : qab[i]) {

			int qc = (2 * x.first + x.second) % 3;

          c[i]^=(qc+1);

		}

	}

	rep(i, 2) {

		if (!c[1 - i]) {

			pin ans = solve(qab[i], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += i;

			return ans;

		}

	}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<iostream>

#include<algorithm>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

vel solve(V<vel>& ab, int ex) {

	if (ex == 0) { return { 1, 0 }; }

	V<V<vel>> qab(2);

	for (vel x : ab) {

		int a1 = x[0];

		int b1 = x[1];

		qab[x[1] & 1].push_back({ x[0] / 2,x[1] / 2 });

		if (x[0] & 1) { qab[(x[1] + 1) & 1].push_back({ x[0] / 2,(x[1] + 1) / 2 }); }

	}

	V<vel> c(3,vel(2));

	rep(i, 2) {

		for (auto x : qab[i]) {

			int qc = (3 - x[0] + x[1]) % 3; qc = (qc + 3) % 3;

			if (qc == 0) { c[i][0] ^= 1; }

			if (qc == 1) { c[i][1] ^= 1; }

			if (qc == 2) { c[i][0] ^= 1; c[i][1] ^= 1; }

		}

	}

	if (c[0] == c[2]) {

		vel ans = solve(qab[1], ex - 1);

		ans[0] *= 2; ans[1] *= 2;ans[1]++;

		return ans;

	}

	if (c[1] == c[2]) {

		vel ans = solve(qab[0], ex - 1);

		ans[0] *= 2; ans[1] *= 2;

		return ans;

	}

	rep(i, ab.size()) { ab[i][0]++; }

	vel ans = solve(ab, ex); ans[0]--;

	return ans;

}

signed main() {

	int inf = 2e17;

	int n; cin >> n;

	V<vel> ab(n);

	rep(i, n) {

		int a, b; cin >> a >> b;

		ab[i] = { a + inf,b + inf };

	}

	vel ret = solve(ab, 70);

	cout << ret[0] - inf << " " << ret[1] - inf << "\n";

}

// Faster C++ solution for the same problem (measured speedup: 1.1466056431216451x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

vel solve(V<vel>& ab, int ex) {

	if (ex == 0) { return { 1, 0 }; }

	V<V<vel>> qab(2);

	for (vel x : ab) {

		qab[x[1] & 1].push_back({ x[0] / 2,x[1] / 2 });

		if (x[0] & 1) { qab[(x[1] + 1) & 1].push_back({ x[0] / 2,(x[1] + 1) / 2 }); }

	}

	V<vel> c(3,vel(2));

	rep(i, 2) {

		for (vel x : qab[i]) {

			int qc = (3 - x[0] + x[1]) % 3; qc = (qc + 3) % 3;

			if (qc==0) { c[i][0] ^= 1; }

			if (qc==1) { c[i][1] ^= 1; }

			if (qc == 2) { c[i][0] ^= 1; c[i][1] ^= 1; }

		}

	}

	rep(i, 2) {

		if (c[1-i] == c[2]) {

			vel ans = solve(qab[i], ex - 1);

			ans[0] *= 2; ans[1] *= 2; ans[1] += i;

			return ans;

		}

	}

	rep(i, ab.size()) { ab[i][0]++; }

	vel ans = solve(ab, ex); ans[0]--;

	return ans;

}

signed main() {

	int inf = 2e17;

	int n; cin >> n;

	V<vel> ab(n);

	rep(i, n) {

		int a, b; cin >> a >> b;

		ab[i] = { a + inf,b + inf };

	}

	vel ret = solve(ab, 70);

	cout << ret[0] - inf << " " << ret[1] - inf << "\n";

}

// Faster C++ solution for the same problem (measured speedup: 1.1463033711462325x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define vel V<long long>

#define rep(i,n) for(int i=0;i<n;i++)

vel solve(V<vel>& ab, int ex) {

	if (!ex) { return { 1, 0 }; }

	V<V<vel>> qab(2);

	for (vel x : ab) {

		qab[x[1] & 1].push_back({ x[0] / 2,x[1] / 2 });

		if (x[0] & 1) { qab[(x[1] + 1) & 1].push_back({ x[0] / 2,(x[1] + 1) / 2 }); }

	}

	V<vel> c(3, vel(2));

	rep(i, 2) {

		for (vel x : qab[i]) {

			int qc = (2 * x[0] + x[1]) % 3;

			if ((qc+1)%2) { c[i][0] ^= 1; }

			if (qc) { c[i][1] ^= 1; }

		}

	}

	rep(i, 2) {

		if (c[1 - i] == c[2]) {

			vel ans = solve(qab[i], ex - 1);

			ans[0] *= 2; ans[1] *= 2; ans[1] += i;

			return ans;

		}

	}

	for(vel &v:ab) { v[0]++; }

	vel ans = solve(ab, ex); ans[0]--;

	return ans;

}

int main() {

	long long inf = 2e17;

	int n; cin >> n;

	V<vel> ab(n);

	rep(i, n) {

		long long a, b; cin >> a >> b;

		ab[i] = { a + inf,b + inf };

	}

	vel ret = solve(ab, 70);

	cout << ret[0] - inf << " " << ret[1] - inf << "\n";

}

// Faster C++ solution for the same problem (measured speedup: 1.152160724385585x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<iostream>

#include<vector>

#include<bits/stdc++.h>

using namespace std;

#define V vector

#define W V<long long>

#define R(i,n) for(int i=0;i<n;i++)

W S(V<W>&p,int E) {

	if (!E) { return { 1, 0 }; }

	V<V<W>> T(2);

	for (W x : p) {

		T[x[1] & 1].push_back({ x[0] / 2,x[1] / 2 });

		if (x[0] & 1) { T[(x[1] + 1) & 1].push_back({ x[0] / 2,(x[1] + 1) / 2 }); }

	}

	V<W> c(3,W(2));

	R(i, 2) {

		for (W x : T[i]) {

			int Q = (2 * x[0] + x[1]) % 3;

			if ((Q+ 1) % 2) { c[i][0] ^= 1; }

			if (Q) { c[i][1] ^= 1; }

		}

	}

	R(i, 2) {

		if (c[1 - i] == c[2]) {

			W ans = S(T[i], E-1);

			ans[0] *= 2; ans[1] *= 2; ans[1] += i;

			return ans;

		}

	}

	for (W&v : p) { v[0]++; }

	W A=S(p, E);A[0]--;return A;

}

int main() {

	long long M = 2e17;

	int n; cin >> n;

	V<W> p(n);

	R(i, n) {

		long long a, b; cin >> a >> b;

		p[i] = { a + M,b + M };

	}

	W Q = S(p, 70);

	cout << Q[0] - M << " " << Q[1] - M;

}

// Faster C++ solution for the same problem (measured speedup: 1.1446234005997418x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define W V<long long>

#define R(i,n) for(int i=0;i<n;i++)

W S(V<W>&p,int E){if(!E){return{1,0};}V<V<W>>T(2);for(W x:p){T[x[1]&1].push_back({x[0]/2,x[1]/2});if(x[0]&1){T[(x[1]+1)&1].push_back({x[0]/2,(x[1]+1)/2});}}V<W>c(3,W(2));R(i,2){for(W x:T[i]){int Q=(2*x[0]+x[1])%3;if((Q+1)%2){c[i][0]^=1;}if(Q){c[i][1]^=1;}}}R(i,2){if(c[1-i]==c[2]){W ans=S(T[i],E-1);ans[0]*=2;ans[1]*=2;ans[1]+=i;return ans;}}for(W&v:p){v[0]++;}W A=S(p,E);A[0]--;return A;}

int main(){long long M=2e17;int n;cin>>n;V<W>p(n);R(i,n){long long a,b;cin>>a>>b;p[i]={a+M,b+M};}W Q=S(p,70);cout<<Q[0]-M<<" "<<Q[1]-M;}

// Faster C++ solution for the same problem (measured speedup: 1.1446234005997418x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define W V<long long>

#define L long long

#define R(n) for(L i=0;i<n;i++)

W S(V<W>&p,L E){if(!E){return{1,0};}V<V<W>>T(2);for(W x:p){T[x[1]&1].push_back({x[0]/2,x[1]/2});if(x[0]&1){T[(x[1]+1)&1].push_back({x[0]/2,(x[1]+1)/2});}}V<W>c(3,W(2));R(2){for(W x:T[i]){L Q=(2*x[0]+x[1])%3;if((Q+1)%2){c[i][0]^=1;}if(Q){c[i][1]^=1;}}}R(2){if(c[1-i]==c[2]){W ans=S(T[i],E-1);ans[0]*=2;ans[1]*=2;ans[1]+=i;return ans;}}for(W&v:p){v[0]++;}W A=S(p,E);A[0]--;return A;}

int main(){L M=2e17;L n;cin>>n;V<W>p(n);R(n){L a,b;cin>>a>>b;p[i]={a+M,b+M};}W Q=S(p,70);cout<<Q[0]-M<<" "<<Q[1]-M;}

// Faster C++ solution for the same problem (measured speedup: 1.1402043070421632x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define W V<long long>

#define L long long

#define R(n) for(L i=0;i<n;i++)

W S(V<W>&p,L E){if(!E){return{1,0};}V<V<W>>T(2);for(W x:p){T[x[1]&1].push_back({x[0]/2,x[1]/2});if(x[0]&1){T[(x[1]+1)&1].push_back({x[0]/2,(x[1]+1)/2});}}V<W>c(4,W(3));c[3]=W(3,1);R(2){for(W x:T[i]){L Q=(2*x[0]+x[1])%3;c[i][Q]^=1;}}R(2){if(c[!i]==c[2]||c[!i]==c[3]){W ans=S(T[i],E-1);ans[0]*=2;ans[1]*=2;ans[1]+=i;return ans;}}for(W&v:p){v[0]++;}W A=S(p,E);A[0]--;return A;}

int main(){L M=2e17;L n;cin>>n;V<W>p(n);R(n){L a,b;cin>>a>>b;p[i]={a+M,b+M};}W Q=S(p,70);cout<<Q[0]-M<<" "<<Q[1]-M;}

// Faster C++ solution for the same problem (measured speedup: 1.158574866338694x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

#define V vector

#define L long long

#define W V<L>

#define R(n) for(L i=0;i<n;i++)

W S(V<W>&p,L E){if(!E){return{1,0};}V<V<W>>T(2);for(W x:p){T[x[1]&1].push_back({x[0]/2,x[1]/2});if(x[0]&1){T[(x[1]+1)&1].push_back({x[0]/2,(x[1]+1)/2});}}V<W>c(4,W(3));c[3]=W(3,1);R(2){for(W x:T[i]){L Q=(2*x[0]+x[1])%3;c[i][Q]^=1;}}R(2){if(c[!i]==c[2]||c[!i]==c[3]){W ans=S(T[i],E-1);ans[0]*=2;ans[1]*=2;ans[1]+=i;return ans;}}for(W&v:p){v[0]++;}W A=S(p,E);A[0]--;return A;}

int main(){L M=2e17;L n;cin>>n;V<W>p(n);R(n){L a,b;cin>>a>>b;p[i]={a+M,b+M};}W Q=S(p,70);cout<<Q[0]-M<<" "<<Q[1]-M;}

// Faster C++ solution for the same problem (measured speedup: 1.158574866338694x):
#include<iostream>

#include<vector>

using namespace std;

#define int long long

#define V vector

#define vel V<int>

#define rep(i,n) for(int i=0;i<n;i++)

#define mkp make_pair

#define pin pair<int,int>

pin solve(V<pin>& ab, int ex) {

	if (!ex) { return mkp(1,0); }

	V<V<pin>> qab(2);

  int sz=ab.size();

  qab[0].reserve(sz);

  qab[1].reserve(sz);

	for (pin &x : ab) {

		qab[x.second & 1].push_back(mkp(x.first / 2,x.second / 2));

		if (x.first & 1) { qab[(x.second + 1) & 1].push_back(mkp(x.first / 2,(x.second + 1) / 2)); }

	}

  int c=0;

  		for (pin &x : qab[0]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[1], ex - 1);

			ans.first *= 2; ans.second *= 2; ans.second += 1;

			return ans;

		}

    c=0;

		for (pin &x : qab[1]) {

			int qc = (2 * x.first + x.second)%3;

          c^=(qc+1);

		}

		if (!c) {

			pin ans = solve(qab[0], ex - 1);

			ans.first *= 2; ans.second *= 2;

			return ans;

		}

	for(pin &v:ab) { v.first++; }

	pin ans = solve(ab, ex); ans.first--;

	return ans;

}

signed main() {

	long long inf = 2e17;

	int n; scanf("%lld", &n);

	V<pin> ab(n);

	rep(i, n) {

		long long a, b; scanf("%lld", &a); scanf("%lld", &b);

		ab[i] = { a + inf,b + inf };

	}

	pin ret = solve(ab, 70);

	cout << ret.first - inf << " " << ret.second - inf << "\n";

}