// Slower C++ solution:
#include<iostream>

#include<cstring>

#include<algorithm>





using namespace std;



const long long inf= 1e10+ 123;

const int mx=1e5+123;

int dp[mx], h[mx], n;



int solve( int i)

{

    if(i==n)

        return 0;



    if(dp[i]!= -1)

        return dp[i];



    int ret1, ret2;

    ret1= abs(h[i]- h[i+1])+ solve(i+1);

    if(i+2<=n)

        ret2= abs(h[i]- h[i+2])+ solve(i+2);

    else

        ret2= inf;

    return dp[i]=min(ret1, ret2);

}



int main()

{

    memset(dp, -1, sizeof(dp));



    cin>> n;

    for(int i=1; i<=n; i++)

        cin>> h[i];



    cout<< solve(1)<< endl;



    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.3493765248225817x):
//                                 Alisher_2211

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        # include <bits/stdc++.h>

# define  long          long long

# define  all(vc)       vc.begin(),vc.end()

# define  allr(vc)      vc.rbegin(),vc.rend()

# define  pb            push_back

# define  fi            first 

# define  se            second

# define  pi            pair <long, long>    

# define  lcm(a, b)     (a * b) / __gcd(a, b)

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        using namespace std;

const long N = 100100;

void read(){freopen("input.txt" , "r" , stdin );freopen("output.txt", "w" , stdout );}

long dp[N];

long n;

void solve(){

    cin >> n;

    vector <long> v(n + 1), d(n);

    for (int i = 1; i <= n; ++i) cin >> v[i];

    for (int i = 2; i <= n; ++i){

        long o1 = dp[i - 1] + abs( v[i] - v[i - 1] );

        long o2 = dp[i - 2] + abs( v[i] - v[i - 2] );

        if( i == 2 ) o2 = 1e9 + 100;

        dp[i] = min(o1, o2);

    }

    cout << dp[n];

}

int32_t main(){

ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); 

        long T = 1;

        //cin >> T;

        while( T-- ){

            solve();

            cout<<'\n';

        }

cerr << "\nTime elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n";

}