// Slower C++ solution:
#include"stdio.h"

#include"stdlib.h"

#include"string.h"

#include"algorithm"

#include"queue"

using namespace std;

struct mmm

{

	int x,y;

}vv;

int dir[4][2] = {0,-1,-1,0,0,1,1,0};

char xx[1005][1005];

int bb[11][2];

queue <mmm> qq;

int vis[1005][1005];

int bfs(char t)

{

	int sum = 0;

	int pl = 0;

	while(!qq.empty())

	{

		vv = qq.front();

		int x0 = vv.x;

		int y0 = vv.y;

		//printf("%d %d %d\n",x0,y0,vis[x0][y0]);

		qq.pop();

		if(xx[x0][y0] == t && !pl)

		{

			sum = vis[x0][y0];

			pl = 1;

		}

		for(int i = 0;i < 4;i++)

		{

			int xt = x0 + dir[i][0];

			int yt = y0 + dir[i][1];

			if(xx[xt][yt] != '#' && xx[xt][yt] != 'X' && vis[xt][yt] == -1)

			{

				vis[xt][yt] = vis[x0][y0] + 1;

				vv.x = xt;

				vv.y = yt;

				qq.push(vv);

			}

		}

	}

	return sum;

}

int main()

{

	int a,b,c,d,x1,y1,sum;

	while(~scanf("%d %d %d",&a,&b,&c))

	{

	//	if(a == 0 && b == 0)

	//	break;

		memset(xx,'#',sizeof(xx));

		getchar();

		for(int i = 1;i <= a;i++)

		{

			for(int j = 1;j <= b;j++)

			{

				xx[i][j] = getchar();

				if(xx[i][j] == 'S')

				{

					x1 = i;

					y1 = j;

				}

				else if(xx[i][j] != 'X')

				{

					bb[xx[i][j] - '0'][0] = i;

					bb[xx[i][j] - '0'][1] = j;

				}

			}

			getchar();

		}

		bb[0][0] = x1;

		bb[0][1] = y1;

		sum = 0;

		for(int i = 1;i <= c;i++)

		{

			vv.x = bb[i-1][0];

			vv.y = bb[i-1][1];

			memset(vis,-1,sizeof(vis));

			vis[vv.x][vv.y] = 0;

			qq.push(vv);

			sum += bfs(i + '0');

		}

		printf("%d\n",sum);

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 6.0547633782363315x):
#include <iostream>

#include <queue>

using namespace std;

int w, h, n;

char map[1024][1024];

int d[1024][1024];

const int direction[4][2] = {

    { -1, 0 },

    { 1, 0 },

    { 0, -1 },

    { 0, 1 },

};

int factory[16][2];

typedef pair<int, int> P;

int bfs(int sx, int sy, int gx, int gy)

{

    for (int i = 0; i < h; ++i)

    {

        for (int j = 0; j < w; ++j)

        {

            d[i][j] = -1;

        }

    }

    queue<P> que;

    que.push(P(sx, sy));

    d[sx][sy] = 0;

    while (que.size())

    {

        const P p = que.front(); que.pop();

        if (p.first == gx && p.second == gy)

        {

            break;

        }

        for (int i = 0; i < 4; ++i)

        {

            int nx = p.first + direction[i][0];

            int ny = p.second + direction[i][1];

            if (0 <= nx && nx < h && 0 <= ny && ny < w && map[nx][ny] != 'X' && d[nx][ny] == -1)

            {

                que.push(P(nx, ny));

                d[nx][ny] = d[p.first][p.second] + 1;

            }

        }

    }



    return d[gx][gy];

}



int main(int argc, char *argv[])

{



    cin >> h >> w >> n;

    for (int i = 0; i < h; ++i)

    {

        for (int j = 0; j < w; ++j)

        {

            cin >> map[i][j];

        }

    }



    for (int i = 0; i < h; ++i)

    {

        for (int j = 0; j < w; ++j)

        {

            if (map[i][j] == 'S')

            {

                factory[0][0] = i;

                factory[0][1] = j;

                map[i][j] = '.';

            }

            else if (isdigit(map[i][j]))

            {

                int index = map[i][j] - '0';

                factory[index][0] = i;

                factory[index][1] = j;

            }

        }

    }



    int step = 0;

    for (int i = 0; i < n; ++i)

    {

        step += bfs(factory[i][0], factory[i][1], factory[i + 1][0], factory[i + 1][1]);

    }



    cout << step << endl;



    return 0;

}

///////////////////////////End Sub//////////////////////////////////