// Slower C++ solution:
#include <bits/stdc++.h>

/*

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <ext/rb_tree>

*/

#define mem(x,y) memset(x,y,sizeof(x))

//#define P(x) cout<<#x<<" = "<<x<<endl;

#define PN(x,n) cout<<'{'<<x[0];for(int i=1;i<n;i++)cout<<','<<x[i];cout<<'}'<<endl;

#define RP(i,n) for(int i=0;i<n;i++)

#define RP2(i,a,b) for(int i=a;i<=b;i++)

#define mp make_pair

#define P pair<int,int>

#define pb push_back

#define fi first

#define se second

#define inf 0x3f3f3f3f

#define dinf 1e99

#define OJ

#define ite iterator

const int dx[]={1,0,-1,0};

const int dy[]={0,1,0,-1};

using namespace std;/*

using namespace __gnu_cxx;

using namespace __gnu_pbds;

typedef long long ll;

typedef unsigned long long ull;

typedef tree<int, int, less<int>, rb_tree_tag, tree_order_statistics_node_update> Tree;

const double PI = acos(-1.0);  

const double eps = 1e-5;

const double T = 5; //t of fire

const double delta = 0.99; //decreasing speed of t

const int INF = 1000000000;*/

const int maxn=1005;

bool vis[maxn][maxn];

int d[maxn][maxn];

int ans,n,m,k,sx,sy;

int lx[maxn],ly[maxn],G[maxn][maxn];

char bf;

queue<P> q;

int bfs(int sx,int sy,int ex,int ey){

    mem(vis,0);

    q.push(mp(sx,sy));

    vis[sx][sy] = 1;

    d[sx][sy] = 0;

    while(!q.empty()){

	P u = q.front(); q.pop();

	for(int dr=0;dr<4;dr++){

	    P v=mp(u.fi+dx[dr],u.se+dy[dr]);

	    if(v.fi<1 || v.se<1 || v.fi>n || v.se>m || vis[v.fi][v.se] || G[v.fi][v.se]) continue;

	    d[v.fi][v.se]=d[u.fi][u.se] + 1;

	    vis[v.fi][v.se] = 1;

	    q.push(v);

	}

    }

    return d[ex][ey];

}

int main(){

    cin>>n>>m>>k;

    for(int i=1;i<=n;i++){

	for(int j=1;j<=m;j++){

	    cin>>bf;

	    if(bf=='.') G[i][j] = 0;

	    else if(bf == 'S') sx = i, sy = j, G[i][j] = 0;

	    else if(bf=='X') G[i][j] = 1;

	    else lx[bf-48] = i, ly[bf-48]=j;

	}

    }

    for(int i=1;i<=k;i++){

	ans += bfs(sx,sy,lx[i],ly[i]);

	sx=lx[i], sy=ly[i];

    }

    cout<<ans<<endl;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.0038096185133316x):
#include <iostream>

#include <cstdio>

#include <cstring>

#include <cmath>

#include <vector>

#include <queue>

#include <set>

#include <map>

#include <stack>

#include <utility>

#include <algorithm>

#include <sstream>

using namespace std;



struct Node{

	int x,y;

};



const int max_n=1000+10;

int h,w,n,dx[]={0,0,-1,1},dy[]={-1,1,0,0},d[max_n][max_n],ans=0;

Node sN;

char c[max_n][max_n];



int bfs(int m){

	for(int i=0;i<h;i++)

	    for(int j=0;j<w;j++)

	        d[i][j]=0;

	queue<Node> q;

	q.push(sN);

	d[sN.x][sN.y]=1;

	while(!q.empty()){

		Node p=q.front();

		q.pop();

		

		if(c[p.x][p.y]=='0'+m){

		    sN.x=p.x;

		    sN.y=p.y;

		}

		else{

			for(int i=0;i<4;i++){

				Node nN;

				nN.x=p.x+dx[i];

				nN.y=p.y+dy[i];

				if(nN.x>=0 && nN.x<h 

	            && nN.y>=0 && nN.y<w 

			   	&& c[nN.x][nN.y]!='X' && !d[nN.x][nN.y]){

					q.push(nN);

					d[nN.x][nN.y]=d[p.x][p.y]+1;

				}

			}

		}

	}

	return d[sN.x][sN.y]-1;

}



int main(){

    scanf("%d%d%d",&h,&w,&n);

    for(int i=0;i<h;i++)

        scanf("%s",c[i]);

    for(int i=0;i<h;i++)

        for(int j=0;j<w;j++)

            if(c[i][j]=='S'){

            	sN.x=i;

            	sN.y=j;

            	break;

            }

    for(int i=1;i<=n;i++)ans+=bfs(i);

    cout<<ans<<endl;

    return 0;

}