// Slower C++ solution:
#include <bits/stdc++.h>

#define ll long long

#define INF 0x3f3f3f3f

#define MOD 1000000007

#define EPS 1e-10

#define rep(i,n) for(int i=0;i<(int)(n);++i)

#define rrep(i,n) for(int i=(int)(n)-1;i>=0;--i)

#define srep(i,s,t) for(int i=(int)(s);i<(int)(t);++i)

#define each(a,b) for(auto& (a): (b))

#define all(v) (v).begin(),(v).end()

#define len(v) (int)(v).size()

#define zip(v) sort(all(v)),v.erase(unique(all(v)),v.end())

#define cmx(x,y) x=max(x,y)

#define cmn(x,y) x=min(x,y)

#define fi first

#define se second

#define pb push_back

#define show(x) cout<<#x<<" = "<<(x)<<endl

#define spair(p) cout<<#p<<": "<<p.fi<<" "<<p.se<<endl

#define sar(a,n) cout<<#a<<":";rep(pachico,n)cout<<" "<<a[pachico];cout<<endl

#define svec(v) cout<<#v<<":";rep(pachico,v.size())cout<<" "<<v[pachico];cout<<endl

#define svecp(v) cout<<#v<<":";each(pachico,v)cout<<" {"<<pachico.first<<":"<<pachico.second<<"}";cout<<endl

#define sset(s) cout<<#s<<":";each(pachico,s)cout<<" "<<pachico;cout<<endl

#define smap(m) cout<<#m<<":";each(pachico,m)cout<<" {"<<pachico.first<<":"<<pachico.second<<"}";cout<<endl



using namespace std;



typedef pair<int,int> P;

typedef pair<ll,ll> pll;

typedef vector<int> vi;

typedef vector<vi> vvi;

typedef vector<ll> vl;

typedef vector<vl> vvl;

typedef vector<double> vd;

typedef vector<P> vp;

typedef vector<string> vs;



const int MAX_N = 100005;



int in() {

    int n, c;

    while ((c = getchar()) < '0') if (c == EOF) return -1;

    n = c - '0';

    while ((c = getchar()) >= '0') n = n * 10 + c - '0';

    return n;

}



void out(int n) {

    int res[11], i = 0;

    do { res[i++] = n % 10, n /= 10; } while (n);

    while (i) putchar(res[--i] + '0');

    putchar('\n');

}



#define impl(x, last) x == last ? 0 : 31 - __builtin_clz(x ^ last)



class RadixHeap{

private:

    int last, size_;

    vector<P> bucket_[32];

public:

    RadixHeap() : last(0), size_(0){}

    void push(int x, int val){

        size_++, bucket_[impl(x, last)].emplace_back(x, val);

    }

    P pop(bool flag = true){

        if(bucket_[0].empty()){

            int id = 1;

            while(bucket_[id].empty()) id++;

            last = min_element(bucket_[id].begin(), bucket_[id].end())->first;

            for(auto val : bucket_[id]){

                bucket_[impl(val.first, last)].push_back(val);

            }

            bucket_[id].clear();

        }

        P res = bucket_[0].back();

        if(flag) size_--, bucket_[0].pop_back();

        return res;

    }

    P top(){

        return pop(false);

    }

    bool empty(){

        return !size_;

    }

};



struct edge{

    int to, cost;

};



vector<edge> G[MAX_N];

int d[MAX_N];

void solve(int s){

    memset(d, INF, sizeof(d));

    RadixHeap que;

    d[s] = 0;

    que.push(0, s);

    while(!que.empty()){

        P p = que.top();

        que.pop();

        int v = p.second;

        if(d[v] < p.first) continue;

        for(auto& e : G[v]){

            if(d[e.to] > d[v] + e.cost){

                d[e.to] = d[v] + e.cost;

                que.push(d[e.to], e.to);

            }

        }

    }

}



int main()

{

    int n, m, s;

    n = in(), m = in(), s = in();

    rep(i,m){

        int a,b,c;

        a = in(), b = in(), c = in();

        G[a].pb((edge){b, c});

    }

    solve(s);

    rep(i,n){

        if(d[i] == INF){

            putchar('I'), putchar('N'), putchar('F'), putchar('\n');

        }else{

            out(d[i]);

        }

    }

    return 0;

}




// Faster C++ solution for the same problem (measured speedup: 3.820322951776352x):
#include <bits/stdc++.h>

#define ll long long

#define INF 1000000005

#define MOD 1000000007

#define EPS 1e-10

#define rep(i,n) for(int i=0;i<(int)(n);++i)

#define rrep(i,n) for(int i=(int)(n)-1;i>=0;--i)

#define srep(i,s,t) for(int i=(int)(s);i<(int)(t);++i)

#define each(a,b) for(auto& (a): (b))

#define all(v) (v).begin(),(v).end()

#define len(v) (int)(v).size()

#define zip(v) sort(all(v)),v.erase(unique(all(v)),v.end())

#define cmx(x,y) x=max(x,y)

#define cmn(x,y) x=min(x,y)

#define fi first

#define se second

#define pb push_back

#define show(x) cout<<#x<<" = "<<(x)<<endl

#define spair(p) cout<<#p<<": "<<p.fi<<" "<<p.se<<endl

#define sar(a,n) cout<<#a<<":";rep(pachico,n)cout<<" "<<a[pachico];cout<<endl

#define svec(v) cout<<#v<<":";rep(pachico,v.size())cout<<" "<<v[pachico];cout<<endl

#define svecp(v) cout<<#v<<":";each(pachico,v)cout<<" {"<<pachico.first<<":"<<pachico.second<<"}";cout<<endl

#define sset(s) cout<<#s<<":";each(pachico,s)cout<<" "<<pachico;cout<<endl

#define smap(m) cout<<#m<<":";each(pachico,m)cout<<" {"<<pachico.first<<":"<<pachico.second<<"}";cout<<endl



using namespace std;



typedef pair<int,int> P;

typedef pair<ll,ll> pll;

typedef vector<int> vi;

typedef vector<vi> vvi;

typedef vector<ll> vl;

typedef vector<vl> vvl;

typedef vector<double> vd;

typedef vector<P> vp;

typedef vector<string> vs;



const int MAX_N = 100005;



#define T int



class Dijkstra {

public:

	struct edge{

		int to; T cost;

	};

	vector<vector<edge> > G;

	vector<T> d;

	int V;

	using pti = pair<T,int>;

	Dijkstra(int node_size){

		V = node_size;

		G.resize(V),d.resize(V,numeric_limits<T>::max());

	}

	//無向グラフの場合

	void add_edge(int u,int v,T cost){

		G[u].pb((edge){v,cost});

	}

	void solve(int s){

		set<pti> st;

		d[s] = 0;

		st.insert(pti(0,s));

		while(!st.empty()){

			pti p = *(st.begin());

			st.erase(st.begin());

			int v = p.second;

			if(d[v] < p.first) continue;

			for(auto& w : G[v]){

				if(d[w.to] > d[v] + w.cost){

					d[w.to] = d[v] + w.cost;

					st.insert(pti(d[w.to],w.to));

				}

			}

		}

	}

};



int main()

{

    cin.tie(0);

    ios::sync_with_stdio(false);

    int n, m, r;

    cin >> n >> m >> r;

	Dijkstra dj(n);

	rep(i,m){

		int a,b,c;

		cin >> a >> b >> c;

		dj.add_edge(a, b, c);

	}

	dj.solve(r);

	each(val,dj.d){

		if(val == numeric_limits<T>::max()){

			cout << "INF\n";

		}else{

			cout << val << "\n";

		}

	}

    return 0;

}