// Slower C++ solution:
#include<set>

#include<map>

#include<cmath>

#include<ctime>

#include<queue>

#include<stack>

#include<cstdio>

#include<string>

#include<vector>

#include<random>

#include<cstdlib>

#include<cstring>

#include<iomanip>

#include<iostream>

#include<algorithm>

#include<unordered_map>

#define endl "\n"

#define fi first

#define se second

#define db double

#define gcd __gcd

#define pb push_back

#define mp make_pair

#define lowbit(x) (x & (-x))

#define PII  pair<int, int> 

#define all(x) x.begin(), x.end()

#define debug(x) cout << #x << " = " << x << endl

#define rep(i, a, b) for(__typeof(b) i = a; i <= (b); i++)

#define Rep(i, a, b) for(__typeof(a) i = a; i >= (b); i--)

#define FAST ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)

template<class T> inline T qmin(T a, T b) { return a < b ? a : b; }

template<class T> inline T qmax(T a, T b) { return a > b ? a : b; }

typedef long long ll;

typedef unsigned long long ull;

const db eps = 1e-9;

const db PI = acos(-1);

const int inf = 0x3f3f3f3f;

const int mod = (int)1e9 + 7;

const int maxn = (int)1e5 + 5;//remember to modify it, No RE or MLE

const ll INF = 0x3f3f3f3f3f3f3f3f;

using namespace std;

ll qpow(ll x, ll y) { ll ret = 1; for( ; y; y >>= 1, x = (x * x) % mod) if(y & 1) ret = (ret * x) % mod; return ret; }



inline int read(){

	char ch = getchar();

	int x = 0, f = 1;

	while(ch < '0' || ch > '9'){

		if(ch == '-') f = -1;

		ch = getchar();

	}

	while('0' <= ch && ch <= '9'){

		x = x * 10 + ch - '0';

		ch = getchar();

	}

	return x * f;

}



int n, m;

vector<int> G[maxn];

int dp[maxn], ind[maxn];



void dfs(int u){

	for(int v : G[u]){

		if(!dp[v]){

			dfs(v);

			dp[u] = qmax(dp[u], dp[v] + 1);

		} else {

			dp[u] = qmax(dp[u], dp[v] + 1);

		}

	}

}



int main()

{

	n = read(), m = read();

	rep(i, 1, m) {

		int u = read(), v = read();

		G[u].pb(v);

		ind[v]++;

	}

	rep(i, 1, n){

		if(!ind[i]){

			dfs(i);

		}

	}

	printf("%d\n", *max_element(dp, dp + n + 1));

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.4771034978099657x):
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<iostream>

#include<algorithm>

#include<iomanip>

#include<string>

#include<cmath>

#include<vector>

#include<set>

#include<queue>

#include<stack>

#include<fstream>

#include<map>

#include<bitset>

#include<unordered_map>

#include<cstring>

#include<cctype>

using namespace std;

#define  ll long long

#define  ull unsigned long long

#define  ul unsigned long

#define all(v) v.begin(),v.end()

#define sz(n) (int)n.size()

#define pb(s) push_back(s);

#define format(n) fixed<<setprecision(n)

#define finl "\n"

#define Mohammed_Atef_Hassan fast();

#define mod 1000000007

#define INF LLONG_MAX

#define PI acos(-1)

#define clr(dp,n) memset(dp,n,sizeof dp)

#define ex(n) return cout<<n<<finl,0;

int dx[] = { 0, 1, 0, -1, 1, 1, -1, -1 };

int dy[] = { 1, 0, -1, 0, 1, -1, 1, -1 };

ll fix_mod(ll x, ll y)

{

	return (y + x % y) % y;

}

void fast() {

	std::ios_base::sync_with_stdio(false);

	cin.tie(nullptr); cout.tie(nullptr);

}

vector<vector<int>>edg;

int mem[(int)1e5 + 10];

int solve(int u)

{

	int& ret = mem[u];

	if (~ret)return ret;

	ret = 0;

	for (auto v : edg[u])

	{

		ret = max(ret,solve(v)+1);

	}

	return ret;

}

int main()

{

	Mohammed_Atef_Hassan

		clr(mem, -1);

		int n, m;

	cin >> n >> m;

	edg = vector<vector<int>>(n + 1);

	while (m--)

	{

		int x, y;

		cin >> x >> y;

		edg[x].push_back(y);

	}

	int mx = 0;

	for (int i = 1; i <= n; i++)

	{

		mx = max(mx, solve(i));

	}

	ex(mx);

}