// Slower C++ solution:
#include <bits/stdc++.h>

#define eps 1e-3

#define pi acos(-1.0)

#define inf 0x3f

#define INF 0x3f3f3f3f

#define pb push_back

#define debug1 cout<<"&&";

#define debug2 cout<<"**";

#define ms(a, x) memset(a, x, sizeof(a))

#define for0(i, n) for(int i = 0; i < n; ++i)

#define for1(i, n) for(int i = 1; i <= n; ++i)

using namespace std;

typedef double db;

typedef long long ll;

typedef unsigned long long ull;

typedef pair<int, int> pii;

typedef pair<long long, int> pli;

typedef pair<long long, long long> pll;

const int mod = 1e9 + 7;

const int N = 1e5+10;

const int M = 1e6+10;

inline int gcd(int a, int b) { return b ? gcd(b, a % b) : a; }

inline ll Pow(ll a, ll b) { ll ans = 1; for( ; b; b >>= 1) { if(b&1) ans = ans * a % mod; a = a * a % mod;} return ans;}

inline ll Mul ( ll a, ll b)  { ll lf = a * ( b >> 25ll ) % mod * ( 1LL << 25 ) % mod; ll rg = a * ( b & ( ( 1ll << 25 ) - 1 ) ) % mod; return ( lf + rg ) % mod;}

//==================================================================================================================================================================//



int n, h[N], dp[N];



int main() {

   scanf("%d", &n);

   ms(dp, inf); dp[n] = 0;

   for1(i, n) scanf("%d", h+i);

   for(int i = n; i; --i) {

      if(i == 2) dp[i-1] = min(dp[i-1], dp[i] + abs(h[i] - h[i-1]));

      else {

         dp[i-1] = min(dp[i-1], dp[i] + abs(h[i] - h[i-1]));

         dp[i-2] = min(dp[i-2], dp[i] + abs(h[i] - h[i-2]));

      }

   }

   printf("%d\n", dp[1]);

   return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.3739042194654818x):
////=====BIsmillahir Rahmanir Rahim =====////



/*                        ______

 _______   /\     |``\   |        |  /

    |     /  \    |__/   |____    |/

    |    / _ _\   |  \   |        |\

    |   /      \  |   \  |______  |  \



            Dept. of CSE

         Comilla University



*/

#include<bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp>

#include <ext/pb_ds/tree_policy.hpp>

#include <ext/pb_ds/detail/standard_policies.hpp>

#define fi 2*acos(0.0)

#define ee 2.71828

#define ll  long long

#define FIO ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);

#define Node struct node

#define spc " "

#define  E  2.71828182845904523536

#define pb push_back

#define pp pop_back

#define ff first

#define ss second

#define valid(nx,ny) nx>=0 && nx<n && ny>=0 && ny<m

#define edl printf("\n")

#define infinity 1e16

#define mod 1000000007

#define cn continue

#define csprint1 printf("Case %lld: ", cs++)

#define csprint2 printf("Case %lld:\n", cs++)

#define sf(a) scanf("%lld", &a)

#define sff(a,b) scanf("%lld %lld",&a,&b)

#define sfff(a,b,c) scanf("%lld %lld %lld",&a,&b,&c)

#define sffff(a,b,c,d) scanf("%lld %lld %lld %lld",&a,&b,&c,&d)

#define all(v) v.begin(),v.end()

#define pfn(a) printf("%lld\n",a)

#define pfs(a) printf("%lld ",a)



using namespace __gnu_pbds;

using namespace std;

typedef pair<ll, ll> pl;

typedef vector<int> vi;

typedef vector<pl> vpi;

typedef vector<pl> vpl;

typedef tree<pair<ll, int> , null_type, less<pair<ll, int> >, rb_tree_tag, tree_order_statistics_node_update> ost;

#define error(args...) { string _s = #args; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, args); }

void err(istream_iterator<string> it) {}

template<typename T, typename... Args>

void err(istream_iterator<string> it, T a, Args... args)

{

    cerr << *it << " = " << a <<","<< spc;

    err(++it, args...);

    cout<<edl;

}

///Bit manipulation



bool checkbit(int mask,int bit){return mask & (1<<bit);}

int setbit(int mask,int bit){ return mask | (1<<bit) ; }

int clearbit(int mask,int bit){return mask & ~(1<<bit);}

int togglebit(int mask,int bit){return mask ^ (1<<bit);}

int bitno(int mask) {return (int)__builtin_popcount(mask);}



/*----------------------Graph Moves----------------*/

const int fx[]={+1,-1,+0,+0};

const int fy[]={+0,+0,+1,-1};

//const int fx[]={+0,+0,+1,-1,-1,+1,-1,+1};   // Kings Move

//const int fy[]={-1,+1,+0,+0,+1,+1,-1,-1};  // Kings Move

//const int fx[]={-2, -2, -1, -1,  1,  1,  2,  2};  // Knights Move

//const int fy[]={-1,  1, -2,  2, -2,  2, -1,  1}; // Knights Move

/*------------------------------------------------*/



///=====================================///



const int  maX=1e5+10;

ll M = 10000007;

int main() {

    ll n;sf(n);

    ll ara[n];

    for(ll i=0;i<n;i++)sf(ara[i]);

    ll sum=0;

    ll dp[maX];

    dp[n-1]=0;

    for(ll i=n-2;i>=0;i--){

        ll x,y;

        x=dp[i+1]+abs(ara[i]-ara[i+1]);

        y=infinity;

        if(i+2<n){

            y=dp[i+2]+abs(ara[i]-ara[i+2]);

        }

        //cout<<x<<spc<<y<<endl;

        dp[i]=min(x,y);

    }

    pfn(dp[0]);

return 0;

}