// Slower C++ solution:
//

//  AOJ 0558 Chees

//

//  Created by TaoSama on 2015-02-20

//  Copyright (c) 2014 TaoSama. All rights reserved.

//

#include <algorithm>

#include <cctype>

#include <cmath>

#include <cstdio>

#include <cstdlib>

#include <cstring>

#include <iomanip>

#include <iostream>

#include <map>

#include <queue>

#include <string>

#include <set>

#include <vector>

#define CLR(x,y) memset(x, y, sizeof(x))



using namespace std;

const int INF = 0x3f3f3f3f;

const int MOD = 1e9 + 7;

const int N = 1e5 + 10;



struct Point {

	int x, y;

	Point(int x = 0, int y = 0): x(x), y(y) {}

} c[15];

int n, m, k, dp[1005][1005];

int d[4][2] = { -1, 0, 1, 0, 0, 1, 0, -1};

char a[1005][1005];



int bfs(int x) {

	memset(dp, 0x3f, sizeof dp);

	queue <Point> q; q.push(c[x - 1]);

	dp[c[x - 1].x][c[x - 1].y] = 0;

	while(!q.empty()) {

		Point cur = q.front(); q.pop();

		for(int i = 0; i < 4; ++i) {

			Point nxt(cur.x + d[i][0], cur.y + d[i][1]);

			if(nxt.x < 1 || nxt.x > n || nxt.y < 1 || nxt.y > m

			        || a[nxt.x][nxt.y] == 'X') continue;

			if(dp[nxt.x][nxt.y] == INF) {

				dp[nxt.x][nxt.y] = dp[cur.x][cur.y] + 1;

				q.push(nxt);

			}

		}

	}

	return dp[c[x].x][c[x].y];

}

int main() {

#ifdef LOCAL

	freopen("in.txt", "r", stdin);

//	freopen("out.txt","w",stdout);

#endif

	ios_base::sync_with_stdio(0);



	while(cin >> n >> m >> k) {

		for(int i = 1; i <= n; ++i) {

			for(int j = 1; j <= m; ++j) {

				cin >> a[i][j];

				if(a[i][j] == 'S')

					c[0].x = i, c[0].y = j;

				if(isdigit(a[i][j]))

					c[a[i][j] - '0'].x = i, c[a[i][j] - '0'].y = j;

			}

		}

		int ans = 0;

		for(int i = 1; i <= k; ++i)

			ans += bfs(i);

		cout << ans << endl;

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.6444042472006175x):
#include<queue>

#include<cstdio>

#include<cstring>

#include<algorithm>

using namespace std;



#define MAXN 1000

struct node{

    int x,y,st;

    bool operator == (node B) const{

        return x==B.x&&y==B.y;

    }

};

int H,W,N;

char Map[MAXN+5][MAXN+5];

bool vis[MAXN+5][MAXN+5];



const int dir[4][2]={{0,1},{0,-1},{1,0},{-1,0}};

int bfs(node S,node T){

    queue<node> Q;

    Q.push(S);

    memset(vis,0,sizeof vis);

    while(!Q.empty()){

        node u=Q.front();Q.pop();

        for(int i=0;i<4;i++){

            node tmp=u;

            tmp.x+=dir[i][0],tmp.y+=dir[i][1],tmp.st++;

            if(tmp.x<1||tmp.x>H||tmp.y<1||tmp.y>W||vis[tmp.x][tmp.y]||Map[tmp.x][tmp.y]=='X')

                continue;

            if(tmp==T)

                return tmp.st;

            vis[tmp.x][tmp.y]=1;

            Q.push(tmp);

        }

    }

    return -1;

}



pair<int,int> pos[10];



int main(){

    scanf("%d%d%d",&H,&W,&N);

    for(int i=1;i<=H;i++)

        scanf("%s",Map[i]+1);

    node S;

    for(int i=1;i<=H;i++)

        for(int j=1;j<=W;j++){

            if(Map[i][j]!='.'&&Map[i][j]!='X'&&Map[i][j]!='S')

                pos[Map[i][j]-'1'+1]=make_pair(i,j);

            if(Map[i][j]=='S')

                S.x=i,S.y=j,S.st=0;

        }

    int Ans=0;

    for(int i=1;i<=N;i++){

        Ans+=bfs(S,(node){pos[i].first,pos[i].second,0});

        S=(node){pos[i].first,pos[i].second,0};

    }

    printf("%d\n",Ans);

}