// Slower C++ solution:
/*

	Author: Luis Manuel D�az Bar�n (LUISMO)

	Problem:

	Online Judge:

	Idea:

*/

#include<bits/stdc++.h>

// Types

#define ll long long

#define ull unsigned long long

// IO

#define sf scanf

#define pf printf

#define mkp make_pair

#define fi first

#define se second

#define endl "\n"



using namespace std;



typedef pair<int, int> pii;

typedef pair<ll, ll> pll;

const ll inf = 1e16 + 3;

const int mod = 1e9 + 7;

const int lim = 2e5 + 2;



int N, M;

vector<int> adj[lim];



int dp[lim];

bool mark[lim];



int DFS(int idx)

{

    if(mark[idx])

        return dp[idx];

    // for each adjacent

    for(int i = 0; i < adj[idx].size(); i++)

    {

        int nxt = adj[idx][i];

        int aux = DFS(nxt);

        dp[idx] = max(dp[idx], 1 + aux);

    }

    mark[idx] = true;

    return dp[idx];

}



void solve()

{

    cin >> N >> M;

    // reading edges

    for (int i = 0; i < M; i++)

    {

        int xi, yi;

        cin >> xi >> yi;

        adj[xi].push_back(yi);

    }

    

    int answ = 0;



    for(int i = 1; i <= N; i++)

    {

        int aux = DFS(i);

        answ = max(answ, aux);

    }



    cout << answ;

}



void fastIO()

{

	cin.sync_with_stdio(false);

	cin.tie(0);

}



void IO()

{

	if(fopen("d:\\lmo.in","r") != NULL)

	{

		freopen("d:\\lmo.in","r",stdin);

	}

	else if(fopen("/media/Beijing/lmo.in","r") != NULL)

	{

		freopen("/media/Beijing/lmo.in", "r", stdin);

	}

}



int main()

{

	IO();



	fastIO();



	solve();

}


// Faster C++ solution for the same problem (measured speedup: 6.5230943236194925x):
#include <bits/stdc++.h>

#define eps 1e-3

#define pi acos(-1.0)

#define inf 0x3f

#define INF 0x3f3f3f3f

#define pb push_back

#define debug1 cout<<"&&";

#define debug2 cout<<"**";

#define ms(a, x) memset(a, x, sizeof(a))

#define for0(i, n) for(int i = 0; i < n; ++i)

#define for1(i, n) for(int i = 1; i <= n; ++i)

using namespace std;

typedef double db;

typedef long long ll;

typedef unsigned long long ull;

typedef pair<int, int> pii;

typedef pair<long long, int> pli;

typedef pair<long long, long long> pll;

const int mod = 1e9 + 7;

const int N = 1e5+10;

const int M = 1e6+10;

inline int gcd(int a, int b) { return b ? gcd(b, a % b) : a; }

inline ll Pow(ll a, ll b) { ll ans = 1; for( ; b; b >>= 1) { if(b&1) ans = ans * a % mod; a = a * a % mod;} return ans;}

inline ll Mul ( ll a, ll b)  { ll lf = a * ( b >> 25ll ) % mod * ( 1LL << 25 ) % mod; ll rg = a * ( b & ( ( 1ll << 25 ) - 1 ) ) % mod; return ( lf + rg ) % mod;}

inline ll C(ll y, ll x) { ll ans = 1; if(y < 0 || x < 0 || y < x) return 0; y %= mod; if(!y || !x) return 1; for0(i, x) ans = ans * (y-i) % mod; for1(i, x) ans = ans * Pow(i, mod-2) % mod; return ans; }

//==================================================================================================================================================================//



int n, m, tot, head[N], nex[N], ver[N];

int dp[N], deg[N], ans;

queue<int> q;



void add(int x, int y) {

   ver[++tot] = y, nex[tot] = head[x], head[x] = tot;

}



int main() {

   scanf("%d %d", &n, &m);

   for1(i, m) {

      int x, y;

      scanf("%d %d", &x, &y);

      add(x, y);

      deg[y]++;

   }

   for1(i, n) if(!deg[i]) q.push(i);

   while(!q.empty()) {

      int x = q.front(); q.pop();

      for(int i = head[x]; i; i = nex[i]) {

         int y = ver[i]; deg[y]--;

         dp[y] = max(dp[y], dp[x] + 1);

         if(!deg[y]) q.push(y);

      }

   }

   for1(i, n) ans = max(ans, dp[i]);

   printf("%d\n", ans);

   return 0;

}