stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include<bits/stdc++.h>



using namespace std;



int main(){

	long long int n; cin >> n;

	long long int res = 0;

	for(int i=1; i<=n; i++){

		if(i % 3 == 0){

			

		}else if(i % 5 == 0){

			

		}else{

			res += i;

		}

	}

	

	cout << res << "\n";

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.9008267988493954x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
#include<iostream>



using namespace std;



int main(){

    int n;

    cin>>n;

    long long int s=0;

    for(int i=1;i<=n;i++){

        if(i%3 && i%5){

            s+=i;

        }

    }

    cout<<s;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.89838161324526x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

int main()

{

    ll n;  cin>>n;

    ll sum=0;

    for(ll i=1;i<=n;i++)

    {

        if(i%3==0||i%5==0)

            continue;

        sum+=i;

    }

    cout<<sum;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.898148861473751x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

int  main(){

	ll n,ans=0;

	cin>>n;

	for(int i=1;i<=n;i++){

		if(i%3==0||i%5==0)continue;

		else ans+=i; 

	}

	cout<<ans<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 1.9003179993202644x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

int main(){

    long long n,ans=0;

    cin>>n;

    for(int i=1;i<=n;i++){

        if(i%3&&i%5){

            ans+=i;

        }

    }

    cout<<ans;

}


// Faster C++ solution for the same problem (measured speedup: 1.8982242016082636x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

int main()

{

         long long c=0,i,n,f=0,b=0;

         cin>>n;

         for(i=1;i<=n;i++)

        {

           b+=i;

           if((i%3)==0 || (i%5)==0) {f+=i;

           }

         }

 

         cout<<b-f<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 2.5806196793130662x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
// In the name of God



#include <bits/stdc++.h>



using namespace std;



int main() {

	ios_base::sync_with_stdio(false);

	cin.tie(0);



	int n;

	cin >> n;



	long long ans = 0;

	

	for(int i = 1; i <= n; i++) {

		if(i % 3 == 0 || i % 5 == 0) continue;

		ans += i;

	}

	cout << ans;



	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.038609467738431x):
#include <stdio.h>



int main(){

	int input;

	scanf("%d",&input);

 

	long long ans=0;

 

	for(int i = 1; i <= input; i++){

 		if(i % 3 != 0 && i % 5 != 0){

 			ans += i;

			}

		}

 	printf("%lld\n",ans);

 	return 0;

 }
// Slower C++ solution:
#include<iostream>   //AA06( 21/ 04/ 20) If u see my code, Have a Good Day! (^_^)



using namespace std;



int main()

{

    long long int N, i, sum = 0;



    cin >> N;



    for(i = 1; i <= N; ++i) {



        if(i % 3 == 0 || i % 5 == 0 || i % 15 == 0) {

            continue;

        }



        sum = sum + i;





    }



    cout << sum << endl;



    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.7137775394558705x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

int main()

{

   int n; cin >> n;

   long long sum =0;

   int p = n+1;

   while(p--)

   {

       if (p%5==0 || p%3 == 0){/*do nth */}

       else {sum += p;}

   }

   cout << sum <<endl;

    return 0;

}




// Faster C++ solution for the same problem (measured speedup: 2.9795982401098393x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#define GODSPEED ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);

#define pb push_back

#define f(i,x,n) for(i=x;i<n;i++)

#define rf(i,x,n) for(i=n;i>x;i--)

#define ll long long

#define GCD(a,b) __gcd(a,b)

#define adios return 0;



/*

SHERAJUL ARIFIN

Dept. of CSE,

IUT.

*/





#include <bits/stdc++.h>

using namespace std;



int main()

{

    GODSPEED;

    ll t,n,a,b,c,d,s=0,i,j,flag;

    cin>>n;

    for(i=1;i<=n;i++)

    {

        if(i%15!=0 and i%3!=0 and i%5!=0) s+=i;

    }

    cout<<s<<endl;







    adios;

}


// Faster C++ solution for the same problem (measured speedup: 2.9503392280945384x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);

using namespace std;

	const int maxn=55;

	int a[maxn][maxn];

	int n;

	int main(){

		IOS

		cin>>n;

		long long ans=0;

		for(int i=1;i<=n;i++){

			if(i%3&&i%5)

				ans+=i;

		}

		cout<<ans<<endl;

		return 0;

	} 

// Faster C++ solution for the same problem (measured speedup: 1.9158564193845744x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;



 int main()

 {

 	int n;

 	cin>>n;

 	long long sum = 0;

 	for(int i = 1;i<=n;++i){

 		if(i%3 != 0 && i%5 != 0) sum += i;

	}

	cout<<sum<<endl;

 	return 0;

 }

// Faster C++ solution for the same problem (measured speedup: 1.9010465224920214x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<iostream>

#include<algorithm>

#include<cmath>

#include<cstdlib>

#include<cstdio>

#include<cstring>

#include<iomanip>

#include<string>

#include<set>

#include<map>

#include<vector>

#include<queue>

#include<stack>

#include<utility>

#define PI acos(-1.0)

typedef long long ll;

using namespace std;

int main(){

	ll ans = 0,n;

	cin >> n;

	for(int i = 1;i <= n;i++){

		if(!(i % 3 == 0 || i % 5 == 0)){

			ans += i;

		}

	}

	cout << ans << endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.9006340951710068x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>



using namespace std;



int main(){

	long long int n; cin >> n;

	long long int res = 0;

	for(int i=1; i<=n; i++){

		if(i % 3 == 0){

			

		}else if(i % 5 == 0){

			

		}else{

			res += i;

		}

	}

	

	cout << res << "\n";

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.9011429793330363x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<iostream>



using namespace std;



int main(){

    int n;

    cin>>n;

    long long int s=0;

    for(int i=1;i<=n;i++){

        if(i%3 && i%5){

            s+=i;

        }

    }

    cout<<s;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.8986973870006458x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

int main()

{

    ll n;  cin>>n;

    ll sum=0;

    for(ll i=1;i<=n;i++)

    {

        if(i%3==0||i%5==0)

            continue;

        sum+=i;

    }

    cout<<sum;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.8984645965135798x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

int  main(){

	ll n,ans=0;

	cin>>n;

	for(int i=1;i<=n;i++){

		if(i%3==0||i%5==0)continue;

		else ans+=i; 

	}

	cout<<ans<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 1.9006340951710068x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

int main(){

    long long n,ans=0;

    cin>>n;

    for(int i=1;i<=n;i++){

        if(i%3&&i%5){

            ans+=i;

        }

    }

    cout<<ans;

}


// Faster C++ solution for the same problem (measured speedup: 1.8985399491800499x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

int main()

{

         long long c=0,i,n,f=0,b=0;

         cin>>n;

         for(i=1;i<=n;i++)

        {

           b+=i;

           if((i%3)==0 || (i%5)==0) {f+=i;

           }

         }

 

         cout<<b-f<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 2.5810489354550734x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
// In the name of God



#include <bits/stdc++.h>



using namespace std;



int main() {

	ios_base::sync_with_stdio(false);

	cin.tie(0);



	int n;

	cin >> n;



	long long ans = 0;

	

	for(int i = 1; i <= n; i++) {

		if(i % 3 == 0 || i % 5 == 0) continue;

		ans += i;

	}

	cout << ans;



	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.0389485667704177x):
//e

#include <stdio.h>

int main ()

{

	long long int a, sum = 0;

	scanf ("%lld",&a);

	

	for (int i = 1; i <= a; i++)

	{

		if (i%3 == 0 || i%5 == 0)

		{

			continue;

		}

		else

		{

		sum+= i;

		}

	}	

	

	printf ("%lld\n", sum);

	

	return 0;

}
// Slower C++ solution:
#include<iostream>   //AA06( 21/ 04/ 20) If u see my code, Have a Good Day! (^_^)



using namespace std;



int main()

{

    long long int N, i, sum = 0;



    cin >> N;



    for(i = 1; i <= N; ++i) {



        if(i % 3 == 0 || i % 5 == 0 || i % 15 == 0) {

            continue;

        }



        sum = sum + i;





    }



    cout << sum << endl;



    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.7143157672920233x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

int main()

{

   int n; cin >> n;

   long long sum =0;

   int p = n+1;

   while(p--)

   {

       if (p%5==0 || p%3 == 0){/*do nth */}

       else {sum += p;}

   }

   cout << sum <<endl;

    return 0;

}




// Faster C++ solution for the same problem (measured speedup: 2.9801891885903475x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#define GODSPEED ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);

#define pb push_back

#define f(i,x,n) for(i=x;i<n;i++)

#define rf(i,x,n) for(i=n;i>x;i--)

#define ll long long

#define GCD(a,b) __gcd(a,b)

#define adios return 0;



/*

SHERAJUL ARIFIN

Dept. of CSE,

IUT.

*/





#include <bits/stdc++.h>

using namespace std;



int main()

{

    GODSPEED;

    ll t,n,a,b,c,d,s=0,i,j,flag;

    cin>>n;

    for(i=1;i<=n;i++)

    {

        if(i%15!=0 and i%3!=0 and i%5!=0) s+=i;

    }

    cout<<s<<endl;







    adios;

}


// Faster C++ solution for the same problem (measured speedup: 2.9509243735884363x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);

using namespace std;

	const int maxn=55;

	int a[maxn][maxn];

	int n;

	int main(){

		IOS

		cin>>n;

		long long ans=0;

		for(int i=1;i<=n;i++){

			if(i%3&&i%5)

				ans+=i;

		}

		cout<<ans<<endl;

		return 0;

	} 

// Faster C++ solution for the same problem (measured speedup: 1.9162363942498655x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;



 int main()

 {

 	int n;

 	cin>>n;

 	long long sum = 0;

 	for(int i = 1;i<=n;++i){

 		if(i%3 != 0 && i%5 != 0) sum += i;

	}

	cout<<sum<<endl;

 	return 0;

 }

// Faster C++ solution for the same problem (measured speedup: 1.901423560086795x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<iostream>

#include<algorithm>

#include<cmath>

#include<cstdlib>

#include<cstdio>

#include<cstring>

#include<iomanip>

#include<string>

#include<set>

#include<map>

#include<vector>

#include<queue>

#include<stack>

#include<utility>

#define PI acos(-1.0)

typedef long long ll;

using namespace std;

int main(){

	ll ans = 0,n;

	cin >> n;

	for(int i = 1;i <= n;i++){

		if(!(i % 3 == 0 || i % 5 == 0)){

			ans += i;

		}

	}

	cout << ans << endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.9010110509684106x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>



using namespace std;



int main(){

	long long int n; cin >> n;

	long long int res = 0;

	for(int i=1; i<=n; i++){

		if(i % 3 == 0){

			

		}else if(i % 5 == 0){

			

		}else{

			res += i;

		}

	}

	

	cout << res << "\n";

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.9015200360582492x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<iostream>



using namespace std;



int main(){

    int n;

    cin>>n;

    long long int s=0;

    for(int i=1;i<=n;i++){

        if(i%3 && i%5){

            s+=i;

        }

    }

    cout<<s;

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.899073958687623x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

int main()

{

    ll n;  cin>>n;

    ll sum=0;

    for(ll i=1;i<=n;i++)

    {

        if(i%3==0||i%5==0)

            continue;

        sum+=i;

    }

    cout<<sum;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.8988411220308479x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;

int  main(){

	ll n,ans=0;

	cin>>n;

	for(int i=1;i<=n;i++){

		if(i%3==0||i%5==0)continue;

		else ans+=i; 

	}

	cout<<ans<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 1.9010110509684106x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include <bits/stdc++.h>

using namespace std;

int main(){

    long long n,ans=0;

    cin>>n;

    for(int i=1;i<=n;i++){

        if(i%3&&i%5){

            ans+=i;

        }

    }

    cout<<ans;

}


// Faster C++ solution for the same problem (measured speedup: 1.8989164896421327x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

int main()

{

         long long c=0,i,n,f=0,b=0;

         cin>>n;

         for(i=1;i<=n;i++)

        {

           b+=i;

           if((i%3)==0 || (i%5)==0) {f+=i;

           }

         }

 

         cout<<b-f<<endl;

}

// Faster C++ solution for the same problem (measured speedup: 2.5815608390150877x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
// In the name of God



#include <bits/stdc++.h>



using namespace std;



int main() {

	ios_base::sync_with_stdio(false);

	cin.tie(0);



	int n;

	cin >> n;



	long long ans = 0;

	

	for(int i = 1; i <= n; i++) {

		if(i % 3 == 0 || i % 5 == 0) continue;

		ans += i;

	}

	cout << ans;



	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.0393529546980074x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);

	return 0;

}
// Slower C++ solution:
#include<iostream>   //AA06( 21/ 04/ 20) If u see my code, Have a Good Day! (^_^)



using namespace std;



int main()

{

    long long int N, i, sum = 0;



    cin >> N;



    for(i = 1; i <= N; ++i) {



        if(i % 3 == 0 || i % 5 == 0 || i % 15 == 0) {

            continue;

        }



        sum = sum + i;





    }



    cout << sum << endl;



    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 2.7143157672920233x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);



}
// Slower C++ solution:
#include<bits/stdc++.h>

using namespace std;

int main()

{

   int n; cin >> n;

   long long sum =0;

   int p = n+1;

   while(p--)

   {

       if (p%5==0 || p%3 == 0){/*do nth */}

       else {sum += p;}

   }

   cout << sum <<endl;

    return 0;

}




// Faster C++ solution for the same problem (measured speedup: 2.9801891885903475x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);



}
// Slower C++ solution:
#define GODSPEED ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);

#define pb push_back

#define f(i,x,n) for(i=x;i<n;i++)

#define rf(i,x,n) for(i=n;i>x;i--)

#define ll long long

#define GCD(a,b) __gcd(a,b)

#define adios return 0;



/*

SHERAJUL ARIFIN

Dept. of CSE,

IUT.

*/





#include <bits/stdc++.h>

using namespace std;



int main()

{

    GODSPEED;

    ll t,n,a,b,c,d,s=0,i,j,flag;

    cin>>n;

    for(i=1;i<=n;i++)

    {

        if(i%15!=0 and i%3!=0 and i%5!=0) s+=i;

    }

    cout<<s<<endl;







    adios;

}


// Faster C++ solution for the same problem (measured speedup: 2.9509243735884363x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);



}
// Slower C++ solution:
#include<bits/stdc++.h>

#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);

using namespace std;

	const int maxn=55;

	int a[maxn][maxn];

	int n;

	int main(){

		IOS

		cin>>n;

		long long ans=0;

		for(int i=1;i<=n;i++){

			if(i%3&&i%5)

				ans+=i;

		}

		cout<<ans<<endl;

		return 0;

	} 

// Faster C++ solution for the same problem (measured speedup: 1.9162363942498655x):
#include <stdio.h>



int main(){

	int n;

	scanf("%d", &n);

	long long int total = 0;

	

	for (int i = 1; i <= n; i++){

		if (i % 3 != 0 && i % 5 != 0){

			total += i;

		}

	}

	printf("%lld", total);



}