// Slower C++ solution:
#include <queue>

#include <cstring>

#include <iostream>

using namespace std;



const int N = 1111;

const int cx[] = {0, 0, 1, -1}, cy[] = {1, -1, 0, 0};

char maze[N][N];

int step[N][N];

int h, w, n, sx, sy, ans;



int bfs(int cheese){

    memset(step, -1, sizeof(step));

    queue<pair<int, int> > que;

    que.push(make_pair(sx, sy));

    step[sx][sy] = 0;

    while(!que.empty()){

        int x = que.front().first, y = que.front().second;

        que.pop();

        for(int i = 0; i < 4; ++i){

            int nx = x + cx[i], ny = y + cy[i];

            if(nx < 0 || h <= nx || ny < 0 || w <= ny || maze[nx][ny] == 'X' || step[nx][ny] != -1) continue;

            step[nx][ny] = step[x][y] + 1;

            if(maze[nx][ny] - '0' == cheese){

                sx = nx;

                sy = ny;

                return step[nx][ny];

            }

            que.push(make_pair(nx, ny));

        }

    }

    return 0;

}



int main(){

    ios::sync_with_stdio(false);

    cin.tie(NULL);

    while(cin >> h >> w >> n){

        for(int i = 0; i < h; ++i)

            for(int j = 0; j < w; ++j){

                cin >> maze[i][j];

                if(maze[i][j] == 'S'){

                    sx = i;

                    sy = j;

                }

            }

        ans = 0;

        for(int i = 1; i <= n; ++i)

            ans += bfs(i);

        cout << ans << endl;

    }

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.2078193870144451x):
#include <stdio.h>  

#include <string.h>  

#include <queue>  

#define MAX_W 1000  

#define MAX_H 1000  

#define MAX_N 9  

  

using namespace std;  

  

char m[MAX_H][MAX_W + 1];  

int w, h, n;  

int gx[MAX_N + 1], gy[MAX_N + 1];  

int dx[] = {0, 0, 1, -1}, dy[] = {1, -1, 0, 0};  

  

int bfs(int sx, int sy, int gx, int gy)  

{  

    int d[MAX_H][MAX_W];  

    memset(d, -1, sizeof(d));  

    queue<int> que;  

    que.push(sx * w + sy);  

    d[sx][sy] = 0;  

          

    while(que.size())  

    {  

        int x = que.front()/w, y = que.front()%w;  

        que.pop();  

        if(x == gx && y == gy)  

            break;  

  

        for(int di = 0; di < 4; ++di){  

            int nx = x + dx[di], ny = y + dy[di];  

            if(nx >= 0 && nx < h && ny >= 0 && ny < w && 'X' != m[nx][ny] && -1 == d[nx][ny]){  

                d[nx][ny] = d[x][y] + 1;  

                que.push(nx * w + ny);  

            }  

        }  

    }  

    return d[gx][gy];  

}  

  

void solve()  

{  

    int ans = 0;  

    for(int i = 0; i < n; i ++)  

        ans += bfs(gx[i], gy[i], gx[i + 1], gy[i + 1]);  

    printf("%d\n", ans);  

}  

  

int main()  

{  

    scanf("%d%d%d", &h, &w, &n);  

    for(int i = 0; i < h; i ++)  

        scanf("%s", m[i]);  

          

    for(int i = 0; i < h; i ++)  

        for(int j = 0; j < w; j ++){  

            if('1' <= m[i][j] && '9' >= m[i][j])  

                gx[m[i][j] - '0'] = i, gy[m[i][j] - '0'] = j;  

            else if('S' == m[i][j])  

                gx[0] = i, gy[0] = j;  

        }  

  

    if(w || h)  

        solve();  

    return 0;  

}