// Slower C++ solution:
#include <bits/stdc++.h>



#include <utility>

using namespace std;



#define REP(i, n) for ( int i = 0; i < (n); i++ )

const int INF = 1e9;

using Pii = pair<int, int>;



const int con_type = 26;

int D = 365;

int C[con_type];

int S[365][con_type];

vector<int> ans;

int last[con_type];



struct State {

  int cost;

  vector<int> ans;

  vector<int> last;



  State() {

    cost = 0;

    last = vector<int>(26, -1);

  }



  State(int cost, vector<int> ans, vector<int> last):

    cost(cost), ans(ans), last(last) {};



  bool operator<( const State& s ) const {

    return cost < s.cost;

  }



  bool operator>( const State& s ) const {

    return cost > s.cost;

  }

};



void solve() {

  priority_queue<State> Q;

  Q.push(State());

  REP(d, D) {

    priority_queue<State> nQ;

    while ( !Q.empty() ) {

      State now = Q.top(); Q.pop();

      vector<Pii> add_cost;

      int sum = 0;

      int type_cost[26];

      REP(i, con_type) {

        sum += (d-now.last[i])*C[i];

        type_cost[i] = (d-now.last[i])*C[i];

      }

      REP(i, con_type) {

        add_cost.emplace_back(Pii(S[d][i]+(d-now.last[i])*C[i]-sum, i));

      }

      sort(add_cost.begin(), add_cost.end(), greater<Pii>());

      REP(i, 6) {

        int id = add_cost[i].second;

        State next = now;

        next.cost += S[d][id];

        next.cost -= sum;

        next.cost += type_cost[id];

        next.ans.emplace_back(id);

        next.last[id] = d;

        nQ.push(next);

      }

    }

    Q = priority_queue<State>();

    REP(i, min(1400, (int)nQ.size())) {

      Q.push(nQ.top()); nQ.pop();

    }

  }



  ans = Q.top().ans;

}



void input() {

  cin >> D;

  REP(i, con_type) {

    cin >> C[i];

    last[i] = -1;

  }

  REP(i, D) REP(j, con_type) cin >> S[i][j];

}



void output() {

  REP(i, D) cout << ans[i]+1 << endl;

}



signed main() {

  cin.tie(0);

  ios_base::sync_with_stdio(0);

  cout << fixed << setprecision(12);



  input();

  solve();

  output();



  return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.3491060316193884x):
#include <bits/stdc++.h>



#include <utility>

using namespace std;



#define REP(i, n) for ( int i = 0; i < (n); i++ )

const int INF = 1e9;

using Pii = pair<int, int>;



const int con_type = 26;

int D = 365;

int C[con_type];

int S[365][con_type];

vector<int> ans;

int last[con_type];



struct State {

  int cost;

  vector<int> ans;

  vector<int> last;



  State() {

    cost = 0;

    last = vector<int>(26, -1);

  }



  State(int cost, vector<int> ans, vector<int> last):

    cost(cost), ans(ans), last(last) {};



  bool operator<( const State& s ) const {

    return cost < s.cost;

  }



  bool operator>( const State& s ) const {

    return cost > s.cost;

  }

};



void solve() {

  priority_queue<State> Q;

  Q.push(State());

  REP(d, D) {

    priority_queue<State> nQ;

    while ( !Q.empty() ) {

      State now = Q.top(); Q.pop();

      vector<Pii> add_cost;

      int sum = 0;

      int type_cost[26];

      REP(i, con_type) {

        sum += (d-now.last[i])*C[i];

        type_cost[i] = (d-now.last[i])*C[i];

      }

      REP(i, con_type) {

        add_cost.emplace_back(Pii(S[d][i]+(d-now.last[i])*C[i]-sum, i));

      }

      sort(add_cost.begin(), add_cost.end(), greater<Pii>());

      REP(i, 4) {

        int id = add_cost[i].second;

        State next = now;

        next.cost += S[d][id];

        next.cost -= sum;

        next.cost += type_cost[id];

        next.ans.emplace_back(id);

        next.last[id] = d;

        nQ.push(next);

      }

    }

    Q = priority_queue<State>();

    REP(i, min(1600, (int)nQ.size())) {

      Q.push(nQ.top()); nQ.pop();

    }

  }



  ans = Q.top().ans;

  REP(i, 1000) {

    vector<int> next = ans;



  }

}



void input() {

  cin >> D;

  REP(i, con_type) {

    cin >> C[i];

    last[i] = -1;

  }

  REP(i, D) REP(j, con_type) cin >> S[i][j];

}



void output() {

  REP(i, D) cout << ans[i]+1 << endl;

}



signed main() {

  cin.tie(0);

  ios_base::sync_with_stdio(0);

  cout << fixed << setprecision(12);



  input();

  solve();

  output();



  return 0;

}