// Slower C++ solution:
#include<cstdio>

#include<cstring>

#include<iostream>

#include<queue>

#include<vector>

#include<algorithm>

#include<string>

#include<cmath>

#include<set>

#include<map>

#include<vector>

#include<stack>

#include<utility>

#include<sstream>

using namespace std;

typedef long long ll;

const int inf = 0x3f3f3f3f;

const int maxn = 1005;

int a[1005][1005];

int x[20], y[20];

int ans, w, h, n;

bool leap[1005][1005];

int dir[4][2] = { 1, 0, -1, 0, 0, 1, 0, -1 };

struct Node

{

	int x, y, t;

	Node(int x, int y, int t) :x(x), y(y), t(t){}

};

int work(int xx, int yy, int pos)

{

	memset(leap, false, sizeof(leap));

	leap[xx][yy] = 1;

	queue<Node>p;

	p.push(Node(xx, yy, 0));

	while (p.size())

	{

		Node temp = p.front();

		p.pop();

		for (int i = 0; i < 4; i++)

		{

			int tempx = temp.x + dir[i][0];

			int tempy = temp.y + dir[i][1];

			if (tempx >= 1 && tempx <= h&&tempy >= 1 && tempy <= w)

			{

				if (a[tempx][tempy] == 1)continue;

				if (leap[tempx][tempy] == 1)continue;

				if (tempx == x[pos + 1] && tempy == y[pos + 1])

				{

					return temp.t + 1;

				}

				leap[tempx][tempy] = 1;

				p.push(Node(tempx, tempy, temp.t + 1));

			}

		}

	}



}

int main()

{

#ifdef LOCAL

	freopen("C:\\Users\\ΡΡ\\Desktop\\in.txt", "r", stdin);

	//freopen("C:\\Users\\ΡΡ\\Desktop\\out.txt","w",stdout);

#endif // LOCAL

	while (scanf("%d%d%d", &h, &w, &n) != EOF)

	{

		char s[1005];

		for (int i = 1; i <= h; i++)

		{

			scanf("%s", s);

			for (int j = 1; j <= w; j++)

			{

				if (s[j - 1] == '.')

					a[i][j] = 0;

				else if (s[j - 1] == 'X')

					a[i][j] = 1;

				else if (s[j - 1] == 'S')

				{

					x[0] = i; y[0] = j;

					a[i][j] = 0;

				}

				else

				{

					a[i][j] = 0;

					int id = s[j - 1] - '0';

					x[id] = i; y[id] = j;

				}

			}

		}

		ans = 0;

		for (int i = 0; i < n; i++)

		{

			ans = ans + work(x[i], y[i], i);

		}

		printf("%d\n", ans);

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.9931408966092579x):
    #include <iostream>

    #include <queue>

    using namespace std;

    int w, h, n;

    char map[1024][1024];

    // 各点到当前工厂的距?

    int d[1024][1024];

    const int direction[4][2] = {

    	{ -1, 0 },

    	{ 1, 0 },

    	{ 0, -1 },

    	{ 0, 1 },

    };

     

    int factory[16][2];

    typedef pair<int, int> P;

     

     

     

    //************************************

    // Method:    bfs

    // FullName:  bfs

    // Access:    public 

    // Returns:   int

    // Qualifier:

    // Parameter: const int & sx 起点x

    // Parameter: const int & sy 起点y

    // Parameter: const int & gx ?点x

    // Parameter: const int & gy ?点y

    //************************************

    int bfs(const int& sx, const int& sy, const int& gx, const int& gy)

    {

    	//memset(d, -1, sizeof(d));

    	for (int i = 0; i < h; ++i)

    	{

    		for (int j = 0; j < w; ++j)

    		{

    			d[j][i] = -1;

    		}

    	}

    	queue<P> que;

    	que.push(P(sx, sy));

    	d[sx][sy] = 0;

    	while (que.size())

    	{

    		const P p = que.front(); que.pop();

    		// 如果是?点就?束

    		if (p.first == gx && p.second == gy)

    		{

    			break;

    		}

     

    		// 四方向漫游

    		for (int i = 0; i < 4; ++i)

    		{

    			int nx = p.first + direction[i][0];

    			int ny = p.second + direction[i][1];

    			// 是否可以移?，并且?点没有???

    			if (0 <= nx && nx < w && 0 <= ny && ny < h && map[nx][ny] != 'X' && d[nx][ny] == -1)

    			{

    				que.push(P(nx, ny));

    				d[nx][ny] = d[p.first][p.second] + 1;

    			}

    		}

    	}

     

    	return d[gx][gy];

    }

     

    ///////////////////////////SubMain//////////////////////////////////

    int main(int argc, char *argv[])

    {

     

    	cin >> h >> w >> n;

    	for (int i = 0; i < h; ++i)

    	{

    		for (int j = 0; j < w; ++j)

    		{

    			cin >> map[j][i];

    		}

    	}

     

    	for (int i = 0; i < h; ++i)

    	{

    		for (int j = 0; j < w; ++j)

    		{

    			if (map[j][i] == 'S')

    			{

    				factory[0][0] = j;

    				factory[0][1] = i;

    				map[j][i] = '.';

    			}

    			else if (isdigit(map[j][i]))

    			{

    				int index = map[j][i] - '0';

    				factory[index][0] = j;

    				factory[index][1] = i;

    			}

    		}

    	}

     

    	int step = 0;

    	for (int i = 0; i < n; ++i)

    	{

    		// 按?序吃遍中?

    		step += bfs(factory[i][0], factory[i][1], factory[i + 1][0], factory[i + 1][1]);

    	}

    	

    	cout << step << endl;

     

    	return 0;

    }

    ///////////////////////////End Sub//////////////////////////////////