// Slower C++ solution:
#include <iostream>

#include <cstdio>

#include <cassert>

#include <cstring>

#include <vector>

#include <valarray>

#include <array>

#include <queue>

#include <set>

#include <unordered_set>

#include <map>

#include <unordered_map>

#include <algorithm>

#include <cmath>

#include <complex>

#include <random>



using namespace std;

using ll = long long;

using ull = unsigned long long;

template<class T = ll> constexpr T TEN(int n) {return (n==0)?1:10*TEN<T>(n-1);}



const int MP = 100100;

vector<int> pr;

vector<ull> bpr;



void first() {

    bool used[MP] = {};

    for (int i = 2; i < MP; i++) {

        if (used[i]) continue;

        pr.push_back(i);

        ull x = ((__int128(1)<<64) + i-1 ) / i;

        bpr.push_back(x);

        for (int j = 2*i; j < MP; j += i) {

            used[j] = true;

        }

    }

}



map<ll, int> fact(ll n) {

    int pc = (int)pr.size();

    map<ll, int> mp;

    while (n % 2 == 0) {

        n /= 2;

        mp[2]++;

    }

    while (n % 3 == 0) {

        n /= 3;

        mp[3]++;

    }

    for (int i = 2; i < pc; i++) {

        ll d = pr[i]; ull rd = bpr[i];

        while (true) {

            ll nd = __int128(n)*rd >> 64;

            if (nd * d != n) break;

            n = nd;

            mp[d]++;

        }

    }

    if (n > 1) mp[n]++;

    return mp;

}





int main() {

    first();

    using F = vector<ll>;

    map<F, F> g;

    map<F, int> a;

    int n;

    scanf("%d", &n);

    bool one = false;

    for (int i = 0; i < n; i++) {

        if (i % 1000 == 0) {

//            cout << i << " " << gc << endl;

        }

        ll s;

        scanf("%lld", &s);

        map<ll, int> fac = fact(s);

        F d0, d1;

        for (auto p: fac) {

            p.second %= 3;

            if (p.second == 1) {

                d0.push_back(p.first);

                d1.push_back(p.first);

                d1.push_back(p.first);

            } else if (p.second == 2) {

                d0.push_back(p.first);

                d0.push_back(p.first);

                d1.push_back(p.first);

            }

        }

        sort(d0.begin(), d0.end());

        sort(d1.begin(), d1.end());

        if (d0.size() == 0) {

            one = true;

            continue;

        }

        g[d0] = d1; g[d1] = d0;

        a[d0]++;

    }



    int ans = 0;

    for (auto p: g) {

        ans += max(a[p.first], a[p.second]);

    }

    cout << ans/2 + (one ? 1 : 0) << endl;

    return 0;

}


// Faster C++ solution for the same problem (measured speedup: 1.11015411545575x):
#include <iostream>

#include <cstdio>

#include <cassert>

#include <cstring>

#include <vector>

#include <valarray>

#include <array>

#include <queue>

#include <set>

#include <unordered_set>

#include <map>

#include <unordered_map>

#include <algorithm>

#include <cmath>

#include <complex>

#include <random>

 

using namespace std;

using ll = long long;

using ull = unsigned long long;

template<class T = ll> constexpr T TEN(int n) {return (n==0)?1:10*TEN<T>(n-1);}

 

struct Prime {

    int n;

    vector<bool> used;

    vector<int> pr;

    vector<ull> bpr;

    Prime(int n) : n(n) {

        used = vector<bool>(n+1, false);

        for (int i = 2; i <= n; i++) {

            if (used[i]) continue;

            pr.push_back(i);

            bpr.push_back(((__int128(1)<<64)+i-1) / i);

            for (int j = 2*i; j <= n; j += i) {

                used[j] = true;

            }

        }

    }    

    map<ll, int> fact(ll x) {

        assert(x <= (ll)n*n);

        int pc = (int)pr.size();

        map<ll, int> mp;

        for (int i = 0; i < pc; i++) {

            ll d = pr[i]; ull rd = bpr[i];

//            if (x < d*d) break; 枝刈り

            while (true) {

                ll xd = __int128(x)*rd >> 64;

                if (xd * d != x) break;

                x = xd;

                mp[d]++;

            }

        }

        if (x > 1) mp[x]++;

        return mp;

    }

};

 

const int MP = 100100;

 

ll mul(ll a, ll b) {

    if (TEN(12)/a < b) return TEN(12);

    return a*b;

}

 

int main() {

    Prime pr(MP);

    using P = pair<ll, ll>;

    map<ll, P> g;

    int n;

    scanf("%d", &n);

    bool one = false;

    for (int i = 0; i < n; i++) {

        ll s;

        scanf("%lld", &s);

        map<ll, int> fac = pr.fact(s);

        ll d0 = 1, d1 = 1;

        for (auto p: fac) {

            p.second %= 3;

            if (p.second == 1) {

                d0 = mul(d0, p.first);

                d1 = mul(d1, p.first);

                d1 = mul(d1, p.first);

            } else if (p.second == 2) {

                d0 = mul(d0, p.first);

                d0 = mul(d0, p.first);

                d1 = mul(d1, p.first);

            }

        }

        if (d0 == 1) {

            one = true;

            continue;

        }

        if (d0 < d1) {

            g[d0].first++;

        } else {

            g[d1].second++;

        }

    }

 

    int ans = 0;

    for (auto p: g) {

        ans += max(p.second.first, p.second.second);

    }

    cout << ans + (one ? 1 : 0) << endl;

    return 0;

}