// Slower C++ solution:
/*

*

*/

#include<iostream>

#include<cstring>

#include<cstdio>

#include<cmath>

#include<string>

#include<queue>

#define CLR(ARR,NUM) memset(ARR,NUM,sizeof(ARR))

#define GETNUM(NUM) scanf("%d",&NUM)

#define faster_io() ios_base::sync_with_stdio(false)

using namespace std;

const int MAXN = 1010;

char map[MAXN][MAXN];

bool vis[10][MAXN][MAXN];

struct node{

	int x;

	int y;

	int deep;

	int n;

};

int dx[]={0,0,1,-1};

int dy[]={1,-1,0,0};



int main()

{

	CLR(vis,false);

	CLR(map,'X');

	int h,w,n;

	cin >> h >> w >> n;

	getchar();

	int sx,sy;

	for(int i=1;i<=h;i++){

		for(int j=1;j<=w;j++){

			map[i][j]=getchar();

			if(map[i][j]=='S'){

				sx=i;

				sy=j;

			}

		}

		getchar();

	}

	node t;

	t.x=sx;

	t.y=sy;

	t.deep=0;

	t.n=0;

	queue<node>q;

	vis[0][sx][sy]=true;

	q.push(t);

	int ans = -1;

	while(!q.empty()){

		node cur=q.front();

		if(cur.n==n){

			ans=cur.deep;

			break;

		}

		q.pop();

		for(int i=0;i<4;i++){

			int tx=cur.x+dx[i];

			int ty=cur.y+dy[i];

			if(map[tx][ty]!='X'&&!vis[cur.n][tx][ty]){

				node t = cur;

				t.x=tx;

				t.y=ty;

				t.deep++;

				if(map[tx][ty]=='1'+t.n){

					t.n++;

				}

				vis[t.n][tx][ty]=true;

				q.push(t);

			}

		}

	}

	cout << ans << endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 6.389986927459187x):
#include<cstdio>

#include<cstring>

#include<iostream>

#include<queue>

#include<vector>

#include<algorithm>

#include<string>

#include<cmath>

#include<set>

#include<map>

#include<vector>

#include<stack>

#include<utility>

#include<sstream>

using namespace std;

typedef long long ll;

const int inf = 0x3f3f3f3f;

const int maxn = 1005;

int a[1005][1005];

int x[20], y[20];

int ans, w, h, n;

bool leap[1005][1005];

int dir[4][2] = { 1, 0, -1, 0, 0, 1, 0, -1 };

struct Node

{

	int x, y, t;

	Node(int x, int y, int t) :x(x), y(y), t(t){}

};

int work(int xx, int yy, int pos)

{

	memset(leap, false, sizeof(leap));

	leap[xx][yy] = 1;

	queue<Node>p;

	p.push(Node(xx, yy, 0));

	while (p.size())

	{

		Node temp = p.front();

		p.pop();

		for (int i = 0; i < 4; i++)

		{

			int tempx = temp.x + dir[i][0];

			int tempy = temp.y + dir[i][1];

			if (tempx >= 1 && tempx <= h&&tempy >= 1 && tempy <= w)

			{

				if (a[tempx][tempy] == 1)continue;

				if (leap[tempx][tempy] == 1)continue;

				if (tempx == x[pos + 1] && tempy == y[pos + 1])

				{

					return temp.t + 1;

				}

				leap[tempx][tempy] = 1;

				p.push(Node(tempx, tempy, temp.t + 1));

			}

		}

	}



}

int main()

{

#ifdef LOCAL

	freopen("C:\\Users\\ΡΡ\\Desktop\\in.txt", "r", stdin);

	//freopen("C:\\Users\\ΡΡ\\Desktop\\out.txt","w",stdout);

#endif // LOCAL

	while (scanf("%d%d%d", &h, &w, &n) != EOF)

	{

		char s[1005];

		for (int i = 1; i <= h; i++)

		{

			scanf("%s", s);

			for (int j = 1; j <= w; j++)

			{

				if (s[j - 1] == '.')

					a[i][j] = 0;

				else if (s[j - 1] == 'X')

					a[i][j] = 1;

				else if (s[j - 1] == 'S')

				{

					x[0] = i; y[0] = j;

					a[i][j] = 0;

				}

				else

				{

					a[i][j] = 0;

					int id = s[j - 1] - '0';

					x[id] = i; y[id] = j;

				}

			}

		}

		ans = 0;

		for (int i = 0; i < n; i++)

		{

			ans = ans + work(x[i], y[i], i);

		}

		printf("%d\n", ans);

	}

	return 0;

}