// Slower C++ solution:
/*

*

*/

#include<iostream>

#include<cstring>

#include<cstdio>

#include<cmath>

#include<string>

#include<queue>

#define CLR(ARR,NUM) memset(ARR,NUM,sizeof(ARR))

#define GETNUM(NUM) scanf("%d",&NUM)

#define faster_io() ios_base::sync_with_stdio(false)

using namespace std;

const int MAXN = 1010;

char map[MAXN][MAXN];

bool vis[10][MAXN][MAXN];

struct node{

	int x;

	int y;

	int deep;

	int n;

};

int dx[]={0,0,1,-1};

int dy[]={1,-1,0,0};



int main()

{

	CLR(vis,false);

	CLR(map,'X');

	int h,w,n;

	cin >> h >> w >> n;

	getchar();

	int sx,sy;

	for(int i=1;i<=h;i++){

		for(int j=1;j<=w;j++){

			map[i][j]=getchar();

			if(map[i][j]=='S'){

				sx=i;

				sy=j;

			}

		}

		getchar();

	}

	node t;

	t.x=sx;

	t.y=sy;

	t.deep=0;

	t.n=0;

	queue<node>q;

	vis[0][sx][sy]=true;

	q.push(t);

	int ans = -1;

	while(!q.empty()){

		node cur=q.front();

		if(cur.n==n){

			ans=cur.deep;

			break;

		}

		q.pop();

		for(int i=0;i<4;i++){

			int tx=cur.x+dx[i];

			int ty=cur.y+dy[i];

			if(map[tx][ty]!='X'&&!vis[cur.n][tx][ty]){

				node t = cur;

				t.x=tx;

				t.y=ty;

				t.deep++;

				if(map[tx][ty]=='1'+t.n){

					t.n++;

				}

				vis[t.n][tx][ty]=true;

				q.push(t);

			}

		}

	}

	cout << ans << endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.7996782272579557x):
#include<cstdio>

#include<cstring>

#include<queue>

#define maxn 1002

#define maxc 10

using namespace std;

struct point{

    int r,c;

};

char graph[maxn][maxn];

int len[maxn][maxn];

bool mark[maxn][maxn];

point node[maxc];

int dir[4][2]={1,0,-1,0,0,1,0,-1};

int main(void){

    int h,w,cheese,tr,tc,answer=0;

    scanf("%d%d%d",&h,&w,&cheese);

    memset(graph,0,sizeof(graph));

    memset(node,0,sizeof(node));

    for(int i=1;i<=h;i++) for(int j=1;j<=w;j++){

        do scanf("%c",&graph[i][j]);

        while(graph[i][j]==' ' || graph[i][j]=='\n');

        if(graph[i][j]>='0' && graph[i][j]<='9'){

            node[graph[i][j]-'0'].r=i;

            node[graph[i][j]-'0'].c=j;

        }

        else if(graph[i][j]=='S'){

            node[0].r=i;

            node[0].c=j;

        }

    }

    for(int cnt=0;cnt<cheese;cnt++){

        memset(len,0,sizeof(len));

        memset(mark,false,sizeof(mark));

        for(int i=0;i<=h+1;i++){mark[i][0]=true;mark[i][w+1]=true;}

        for(int j=0;j<=w+1;j++){mark[0][j]=true;mark[h+1][j]=true;}

        queue<point> q;

        q.push(node[cnt]);

        len[node[cnt].r][node[cnt].c]=0;

        point ongo,togo;

        while(!q.empty()){

            ongo=q.front();

            q.pop();

            if(mark[ongo.r][ongo.c]) continue;

            mark[ongo.r][ongo.c]=true;

            if(ongo.r==node[cnt+1].r && ongo.c==node[cnt+1].c){

                answer+=len[ongo.r][ongo.c];

                break;

            }

            for(int i=0;i<4;i++){

                togo.r=ongo.r+dir[i][0];togo.c=ongo.c+dir[i][1];

                if(mark[togo.r][togo.c]==false && graph[togo.r][togo.c]!='X'){

                    len[togo.r][togo.c]=len[ongo.r][ongo.c]+1;

                    q.push(togo);

                }

            }

        }

    }

    printf("%d\n",answer);

    return 0;

}