// Slower C++ solution:
#include <bits/stdc++.h>



using namespace std;

typedef pair<int, int> P;

typedef long long ll;



const int maxv = 10000 + 10;

struct edge

{

    int to, d, c;

    edge() {}

    edge(int to, int d, int c):to(to), d(d), c(c) {}

};

vector<edge> G[maxv];

int d[maxv];



int N, M;



void dijkstra(int s)

{

    priority_queue<P, vector<P>, greater<P> > que;

    memset(d, 0x3f, sizeof(d));

    d[s] = 0;

    que.push(P(0, s));

    while(!que.empty())

    {

        P p = que.top(); que.pop();

        int v = p.second;

        if(p.first > d[v]) continue;

        for(int i=0; i<G[v].size(); i++)

        {

            edge e = G[v][i];

            if(d[e.to] > d[v]+e.d)

            {

                d[e.to] = d[v] + e.d;

                que.push(P(d[e.to], e.to));

            }

        }

    }

}



int main()

{

    while(scanf("%d%d", &N, &M)==2 && N)

    {

        for(int i=0; i<N; i++)  G[i].clear();

        for(int i=0; i<M; i++)

        {

            int u, v, d, c;

            scanf("%d%d%d%d", &u, &v, &d, &c);

            u--; v--;

            G[u].push_back(edge(v, d, c));

            G[v].push_back(edge(u, d, c));

        }

        dijkstra(0);

        int ans = 0;

        for(int i=1; i<N; i++)

        {

            int mincost = 0x3f3f3f3f;

            for(int j=0; j<G[i].size(); j++)

            {

                edge e = G[i][j];

                if(d[e.to]+e.d==d[i] && e.c<mincost)

                    mincost = e.c;

            }

            ans += mincost;

        }

        printf("%d\n", ans);

    }

    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.1602158811482082x):
#include <iostream>

#include <stdio.h>

#include <string.h>

#include <queue>

using namespace std;

const int maxn=10050,maxm=20050,inf=0x3f3f3f3f;

struct Edge

{

    int to,next,dis,cos ;

}edge[maxm*2];

struct Pair

{

    int D,V,C;

    Pair(){;}

    Pair(int d,int c,int v)

    {

        D=d,V=v,C=c;

    }

    friend bool operator <(const Pair a,const Pair b)

    {

        if(a.D!=b.D)

        return a.D>b.D;

        else return a.C>b.C;

    }

};

int tot,head[maxn],dist[maxn],cost[maxn];

bool vis[maxn];

void init()

{

    tot=0;

    memset(head,-1,sizeof(head));

}

void add_edge(int u,int v,int d,int c)

{

    edge[tot].to=v;

    edge[tot].dis=d;

    edge[tot].cos=c;

    edge[tot].next=head[u];

    head[u]=tot++;

}

int dijstra(int start)

{

    memset(vis,false,sizeof(vis));

    memset(dist,inf,sizeof(dist));

    int ans=0;

    dist[start]=0;

   // vis[start]=true;

    priority_queue<Pair>que;

    que.push(Pair(0,0,start));

    while(!que.empty())

    {

        Pair now=que.top();

        que.pop();

        if(vis[now.V])

            continue;

        vis[now.V]=true;

        ans+=now.C;

        for(int i=head[now.V];i!=-1;i=edge[i].next)

        {

            int to=edge[i].to;

            que.push(Pair(now.D+edge[i].dis,edge[i].cos,to));

        }

    }

    return ans;

}

int main()

{

    int u,v,d,c;

    int n,m;

    while(scanf("%d%d",&n,&m)!=-1)

    {

        init();

        if(n==0&&m==0)break;

        for(int i=0;i<m;i++)

        {

            scanf("%d%d%d%d",&u,&v,&d,&c);

            add_edge(u,v,d,c);

            add_edge(v,u,d,c);

        }

        printf("%d\n",dijstra(1));

    }

    return 0;

}