// Slower C++ solution:
#include <iostream>

#include <stdlib.h>

#include <queue>

#include <cstring>

#define MAX_NUM 1010

using namespace std;

int H, W, N;

bool flag[MAX_NUM][MAX_NUM] = {false};                            //??是否已遍??

int dir[4][2] = { {1, 0}, { -1, 0}, {0, 1}, {0, -1} };



class Node {

  public:

    Node();

    Node(int x, int y, int step);

    ~Node();

    int x;

    int y;

    int step;

};



Node::Node() {

}



Node::Node(int x, int y, int step) {

    this->x = x;

    this->y = y;

    this->step = step;

}



Node::~Node() {

}



int BFS(char map[][MAX_NUM], int sx, int sy, int ex, int ey) {

    queue<Node> que;                                                  //第一次出?Memory Limit Exceeded,一定不能使用new来?行?建

    Node node(sx, sy, 0);

    que.push(node);

    flag[sx][sy] = true;                                              //将遍?的?点?置?true



    while(!que.empty()) {

        Node cur = que.front();

        que.pop();



        if(cur.x == ex && cur.y == ey) {

            return cur.step;



        } else {

            for(int i = 0; i < 4; i++) {

                int k = cur.x + dir[i][0];

                int v = cur.y + dir[i][1];



                if(k >= 0 && k < H && v >= 0 && v < W && map[k][v] != 'X' && !flag[k][v]) { //将可到?并且尚未遍?的?点加入?列

                    Node temp(k, v, cur.step + 1);

                    que.push(temp);

                    flag[k][v] = true;

                }

            }

        }

    }



    return -1;

}



int main() {

    int sx, sy, arr[10][2];

    char map[MAX_NUM][MAX_NUM];



    if(cin >> H >> W >> N && H && W) {

        for(int i = 0; i < H; i++) {

            for(int j = 0; j < W; j++) {

                cin >> map[i][j];



                if(map[i][j] == 'S') {

                    map[i][j] = '.';

                    sx = i;

                    sy = j;

                }



                if(isdigit(map[i][j])) {

                    int index = map[i][j] - '0';

                    arr[index][0] = i;

                    arr[index][1] = j;

                }

            }

        }



        arr[0][0] = sx;

        arr[0][1] = sy;

        int res = 0;



        for(int i = 0; i + 1 <= N; i++) {

            memset(flag, false, sizeof(flag));

            res += BFS(map, arr[i][0], arr[i][1], arr[i + 1][0], arr[i + 1][1]);

        }



        cout << res << endl;

    }



    return 0;

}

// Faster C++ solution for the same problem (measured speedup: 2.0358306799800876x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/