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//**************************************Accepted*****************************************//



#include<bits/stdc++.h>



#define all(x) x.begin(),x.end()

#define pb push_back

#define mp make_pair

#define Unique(x) x.erase(unique(all(x)),x.end());



#define CIN_FILE "input.txt"

#define COUT_FILE "output.txt"



using namespace std;



const int dx[]={-1,0,1,0};

const int dy[]={0,-1,0,1};



int Read()

{

	char c;

	c=getchar();



	int tsqua=0;



	while(c!=' '&&c!='\n')

	{

		tsqua=(((tsqua<<1)<<1)<<1)+(tsqua<<1)+(int)(c-'0');



		c=getchar();

	}



	return tsqua;

}



typedef long long ll;



int n,m;

int Deg[111111],Q[111111];

vector<int> E[111111];

int Head,Tail;

int res;

int D[111111];



int main(int argc, char const *argv[])

{

	ios::sync_with_stdio(false);

	

	cin>>n>>m;

	for(int i=0;i<m;i++)

	{

		int a,b;

		cin>>a>>b;

		

		E[a].pb(b);

		Deg[b]++;

	}

	

	for(int i=1;i<=n;i++)if(!Deg[i])Q[++Tail]=i;

	

	while(Head<Tail)

	{

		int x=Q[++Head];

		

		res=max(res,D[x]);

		

		for(int i=0;i<E[x].size();i++)Deg[E[x][i]]--;

		

		for(int i=0;i<E[x].size();i++)D[E[x][i]]=max(D[E[x][i]],D[x]+1);

		

		for(int i=0;i<E[x].size();i++)if(!Deg[E[x][i]])Q[++Tail]=E[x][i];

	}

	

	cout<<res;

	

	//printf("Time used = %.12f",(double)(clock())/CLOCKS_PER_SEC);

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 3.84636056191504x):
#include <bits/stdc++.h>

#define eps 1e-3

#define pi acos(-1.0)

#define inf 0x3f

#define INF 0x3f3f3f3f

#define pb push_back

#define debug1 cout<<"&&";

#define debug2 cout<<"**";

#define ms(a, x) memset(a, x, sizeof(a))

#define for0(i, n) for(int i = 0; i < n; ++i)

#define for1(i, n) for(int i = 1; i <= n; ++i)

using namespace std;

typedef double db;

typedef long long ll;

typedef unsigned long long ull;

typedef pair<int, int> pii;

typedef pair<long long, int> pli;

typedef pair<long long, long long> pll;

const int mod = 1e9 + 7;

const int N = 1e5+10;

const int M = 1e6+10;

inline int gcd(int a, int b) { return b ? gcd(b, a % b) : a; }

inline ll Pow(ll a, ll b) { ll ans = 1; for( ; b; b >>= 1) { if(b&1) ans = ans * a % mod; a = a * a % mod;} return ans;}

inline ll Mul ( ll a, ll b)  { ll lf = a * ( b >> 25ll ) % mod * ( 1LL << 25 ) % mod; ll rg = a * ( b & ( ( 1ll << 25 ) - 1 ) ) % mod; return ( lf + rg ) % mod;}

inline ll C(ll y, ll x) { ll ans = 1; if(y < 0 || x < 0 || y < x) return 0; y %= mod; if(!y || !x) return 1; for0(i, x) ans = ans * (y-i) % mod; for1(i, x) ans = ans * Pow(i, mod-2) % mod; return ans; }

//==================================================================================================================================================================//



int n, m, tot, head[N], nex[N], ver[N];

int dp[N], deg[N], ans;

queue<int> q;



void add(int x, int y) {

   ver[++tot] = y, nex[tot] = head[x], head[x] = tot;

}



int main() {

   scanf("%d %d", &n, &m);

   for1(i, m) {

      int x, y;

      scanf("%d %d", &x, &y);

      add(x, y);

      deg[y]++;

   }

   for1(i, n) if(!deg[i]) q.push(i);

   while(!q.empty()) {

      int x = q.front(); q.pop();

      for(int i = head[x]; i; i = nex[i]) {

         int y = ver[i]; deg[y]--;

         dp[y] = max(dp[y], dp[x] + 1);

         if(!deg[y]) q.push(y);

      }

   }

   for1(i, n) ans = max(ans, dp[i]);

   printf("%d\n", ans);

   return 0;

}