// Slower C++ solution:
#include<iostream>

#include<queue>

#include<cstdlib>

#include<cstdio>

#include<cstring>



using namespace std;

const int maxn=4e4+100;

const int inf=0x3f3f3f3f;



struct Edge{

    int next;

    int to;

    int w;

    int  c;



}G[maxn];



int inq[maxn];

int dis[maxn];

int head[maxn];

int k=0;





void adde(int v,int to,int w,int c)//加?

{

    G[k].to=to;//第k条?指向的点

    G[k].w=w;//第k条?的??

    G[k].c=c;

    G[k].next=head[v];//与第k条??同起点的上一条?的?存位置

    head[v]=k++;

}



queue<int>Q;



void spfa(int s)

{

        while(!Q.empty())Q.pop();

        memset(inq,0,sizeof(inq));

        memset(dis,inf,sizeof(dis));

        dis[s] = 0;

        inq[s] = 1;

        Q.push(s);

        while(!Q.empty())

        {

                int u = Q.front();

                Q.pop();

                inq[u]=0;

                for(int i=head[u];i!=-1;i=G[i].next)//遍?以u?起点的所有?

                {

                        int v=G[i].to;

                        if(dis[v]>dis[u]+G[i].w)

                        {

                                dis[v]=dis[u]+G[i].w;

                                if(inq[v]==0)

                                {

                                    Q.push(v);

                                    inq[v]=1;

                                }

                        }

                }

                inq[u]=0;



        }

}



int main()

{

        int n,m;

        while(scanf("%d%d",&n,&m)!=EOF)

        {

                if(n==0&m==0)

                        return 0;

                memset(head,-1,sizeof(head));



                k=0;

                for(int i=0;i<m;i++)

                {

                            int a,b,c,d;

                            scanf("%d%d%d%d",&a,&b,&c,&d);

                            adde(a,b,c,d);

                            adde(b,a,c,d);

                }

                spfa(1);

                int ans=0;

                for(int i=2;i<=n;++i)

                {

                        int mi=inf;

                        for(int j=head[i];j!=-1;j=G[j].next)

                        {

                                if(dis[G[j].to]+G[j].w==dis[i]&&G[j].c<mi)

                                        mi=G[j].c;

                        }

                        ans+=mi;

                }

                printf("%d\n",ans);

        }

        return 0;



}

// Faster C++ solution for the same problem (measured speedup: 1.3611729390825735x):
#include<stdio.h>

#include<string.h>  

#include<math.h>  

  

//#include<map>   

//#include<set>

#include<deque>  

#include<queue>  

#include<stack>  

#include<bitset> 

#include<string>  

#include<iostream>  

#include<algorithm>  

using namespace std;  

  

#define ll long long  

#define INF 0x3f3f3f3f  

#define mod 1000000

#define clean(a,b) memset(a,b,sizeof(a))// 水印 



struct node{

	int to,next,dis,cost;

}edge[40100];

int head[10100];

int dis[10100],cost[10100];

bool vst[10100];

int n,m,k;



void spfa(int x)

{

	clean(dis,INF);

	clean(cost,INF);

	clean(vst,0);

	queue<int> q;

	dis[x]=0;

	cost[x]=0;

	q.push(x);

	while(!q.empty())

	{

		x=q.front();q.pop();

		vst[x]=0;

		for(int i=head[x];i!=-1;i=edge[i].next)

		{

			node b=edge[i];

			if(dis[b.to]>dis[x]+b.dis)

			{

				if(!vst[b.to])

				{

					vst[b.to]=1;

					q.push(b.to);

				}

				dis[b.to]=dis[x]+b.dis;

				cost[b.to]=b.cost;

			}

			else if(dis[b.to]==dis[x]+b.dis)

			{

				if(cost[b.to]>b.cost)

					cost[b.to]=b.cost;

			}

		}

	}

}



void add(int a,int b,int dis,int cost)

{

	edge[k].to=b;

	edge[k].dis=dis;

	edge[k].cost=cost;

	edge[k].next=head[a];

	head[a]=k;

	k++;

}



int main()

{

	while(cin>>n>>m&&n!=0||m!=0)

	{

		clean(head,-1);

		k=0;

		for(int i=0;i<m;++i)

		{

			int a,b,d,c;

			cin>>a>>b>>d>>c;

			add(a,b,d,c);

			add(b,a,d,c);

		}

		spfa(1);

		ll res=0;

		for(int i=1;i<=n;++i)

			res=res+cost[i];

		cout<<res<<endl;

	}

}