stablegradients/pie-gem5-pairs huggingface dataset:
// Slower C++ solution:
#include <iostream>

#include <queue>

#include <string>

using namespace std;

int main()

{

	int h,w,n;

	int sx,sy;

	int dx[4] = {1,0,-1,0},dy[4] = {0,1,0,-1};

	string map[1001];

	int d[1001][1001];

	int x = 0;

	cin >> h >> w >> n;

	for(int i=0;i < h;i++)

	{

		cin >> map[i];

	}

	for(int i=0;i < h;i++)

	{

		for(int j=0;j < w;j++)

		{

			d[j][i] = -1;

			if(map[i][j] == 'S')

			{

				sx = j;

				sy = i;

			}

		}

	}

	d[sx][sy] = 0;

	for(int i=0;i<9;i++)

	{

		queue< pair<int, int> > que;

		for(int j=0;j < h;j++)

		{

			for(int k=0;k < w;k++)

			{

				d[k][j] = -1;

			}

		}

		d[sx][sy] = 0;

		que.push(make_pair(sx,sy));

		while(que.size())

		{

			pair<int, int> p = que.front();

			que.pop();

			if((map[p.second][p.first] - '0') == (i+1))

			{

				sx = p.first;

				sy = p.second;

				x+=d[sx][sy];

				break;

			}

			for(int j=0;j < 4;j++)

			{

				int nx = p.first + dx[j];

				int ny = p.second + dy[j];

				if(0 <= nx && nx < w && 0 <= ny && ny < h && map[ny][nx] != 'X' && d[nx][ny] == -1)

				{

					que.push(make_pair(nx,ny));

					d[nx][ny] = d[p.first][p.second] + 1;

				}

			}

		}

	}

	cout << x << endl;

}

// Faster C++ solution for the same problem (measured speedup: 1.1315132869910078x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<stdio.h>

#include<string.h>

#include<queue>

using namespace std;

const int maxn=1005;

int n,m,k,dx[]={-1,1,0,0},dy[]={0,0,1,-1},vis[maxn][maxn];

char map[maxn][maxn];

struct maze

{

    maze(int xx=0,int yy=0,int tt=0):x(xx),y(yy),time(tt){}

	int x,y,time;

};

maze bfs(int bx,int by,char ch)

{

	memset(vis,0,sizeof(vis));

	queue<maze> q;

	maze st(bx,by,0);

	q.push(st);vis[bx][by]=1;

	while(!q.empty())

	{

		st=q.front();q.pop();

		if(map[st.x][st.y]==ch)

		{

			return st;

		}

		for(int i=0;i<4;++i)

		{

			int tx=st.x+dx[i],ty=st.y+dy[i];

			if(tx<0||tx>=n||ty<0||ty>=m||map[tx][ty]=='X')//越界和?

			{

				continue;

			}

			maze tp(tx,ty,st.time+1);

			if(!vis[tx][ty])

			{

				vis[tx][ty]=1;

				q.push(tp);

			}

		}

	}

}

int main()

{



	while(~scanf("%d%d%d",&n,&m,&k))

	{

		int bx,by;

		for(int i=0;i<n;++i)

		{

			scanf("%s",map[i]);

			for(int j=0;j<m;++j)

			{

				if(map[i][j]=='S')

				{

					bx=i;by=j;

					

					map[i][j]='0'; //第0个起点

				}

			}

		}

		int ans=0;

		for(int i=0;i<k;++i)

		{

			maze tp=bfs(bx,by,map[bx][by]+1);

			ans+=tp.time;

			bx=tp.x;by=tp.y;

		}

		printf("%d\n",ans);

	}

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 4.983801881731922x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<iostream>

#include<cstring>

#include<queue>

using namespace std;

int n,m,k,step[1010][1010],temp[1010][3];

char a[1010][1010];

int dx[]={-1,1,0,0},dy[]={0,0,-1,1};

bool vis[1010][1010];

typedef pair<int,int> P;

int bfs(int x,int y,int ex,int ey)

{

	memset(vis,true,sizeof(vis));

	memset(step,0,sizeof(step));

	queue <P> que;

	que.push(P(x,y));

	vis[x][y]=false;

	while(!que.empty())

	{

		P tmp=que.front();que.pop();

		int b=que.size();

		if(tmp.first==ex&&tmp.second==ey)

		  return step[tmp.first][tmp.second];

		for(int i=0;i<4;i++)

		{

			int tx=tmp.first+dx[i];

			int ty=tmp.second+dy[i];

			if(tx>0&&tx<=n&&ty>0&&ty<=m&&vis[tx][ty]==true&&a[tx][ty]!='X')

			{

				que.push(P(tx,ty));

				vis[tx][ty]=false;

				step[tx][ty]=step[tmp.first][tmp.second]+1;

			}

		}

	}

}

int main()

{

	ios::sync_with_stdio(false);

	cin>>n>>m>>k;

		int sx,sy;

		for(int i=1;i<=n;i++)

		  for(int j=1;j<=m;j++)

		  {

			cin>>a[i][j];

			if(a[i][j]=='S')

			  sx=i,sy=j;

			//temp[0][0]=i;

			//temp[0][1]=j;

		  }

		a[sx][sy]='0';

		int tot=0,ans=0;

		for(int i=1;i<=k;i++)

		{

			for(int j=1;j<=n;j++)

			  for(int l=1;l<=m;l++)

			    if(a[j][l]=='0'+i)

			    {

			    	tot=bfs(sx,sy,j,l);

			    	sx=j,sy=l;

				}

			ans+=tot;

		}

		cout<<ans<<endl;

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 6.208057000784629x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include "cstring"

#include "cstdio"

#include "queue"

using namespace std;



const int maxn=1024;



int dx[4]={0,0,1,-1};

int dy[4]={1,-1,0,0};



char mp[maxn][maxn];

int vis[maxn][maxn];

int wx[10],wy[10];

int n,m,k;



int bfs(int x1,int y1,int x2,int y2)

{

	memset(vis,0,sizeof(vis));

	queue<int>qx;qx.push(x1);

	queue<int>qy;qy.push(y1);

	queue<int>qt;qt.push(0);

	vis[x1][y1]=1;

	

	while(!qx.empty())

	{

		int nx=qx.front();qx.pop();

		int ny=qy.front();qy.pop();

		int nt=qt.front();qt.pop();

		

		if(nx==x2 && ny==y2)return nt;

		

		for(int i=0;i<4;i++)

		{

			int px=nx+dx[i];

			int py=ny+dy[i];

			if(px>=0 && py>=0 && px<n && py<m && mp[px][py]!='X' && !vis[px][py])

			{

				qx.push(px);

				qy.push(py);

				qt.push(nt+1);

				vis[px][py]=1;

			}

		}

		

	}

	

	return 0;

}



int main()

{

	//freopen("f.txt","r",stdin);

	scanf("%d%d%d",&n,&m,&k);

	for(int i=0;i<n;i++)

		for(int j=0;j<m;j++)

		{

			mp[i][j]=getchar();

			while(mp[i][j]=='\n' || mp[i][j]=='\0')mp[i][j]=getchar();

			if(mp[i][j]>='1' && mp[i][j]<='9')

			{

				wx[mp[i][j]-'0']=i;

				wy[mp[i][j]-'0']=j;

			}

			if(mp[i][j]=='S')

			{

				wx[0]=i;

				wy[0]=j;

			}	

		}

	int ans=0;

	for(int i=0;i<k;i++)

		ans+=bfs(wx[i],wy[i],wx[i+1],wy[i+1]);

	printf("%d\n",ans);

	return 0;

} 


// Faster C++ solution for the same problem (measured speedup: 5.154805890375257x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
//AOJ-0558

#include <cstdio>

#include <cstring>

#include <queue>

#include <algorithm>

using namespace std;



char map[1010][1010];

int dx[4] = {1, 0, -1, 0};

int dy[4] = {0, 1, 0, -1};

int vis[1010][1010];

int m, n, N;

struct node{

	int x, y, t;

};



node bfs(int x, int y, char k)

{

	memset(vis, 0, sizeof(vis));

	queue<node> q;

	node s, e, p;

	s = {x, y, 0};

	q.push(s); vis[x][y] = 1;

	while(!q.empty())

	{

		p = q.front(); q.pop();

		if(map[p.x][p.y] == k) return p;

		for(int i = 0; i < 4; i++)

		{

			int nx = p.x + dx[i];

			int ny = p.y + dy[i];

			if(nx >= n || nx < 0 || ny >= m || ny < 0 || map[nx][ny] == 'X') continue;

			if(!vis[nx][ny]){

				vis[nx][ny] = 1;

				e = {nx, ny, p.t + 1};

				q.push(e);

			}	

		}

	}

}





int main()

{

	while(~scanf("%d %d %d", &n, &m, &N))

	{

		node s;

		for(int i = 0; i < n; i++){

			scanf("%s", map[i]);

			for(int j = 0; j < m; j++){

			   if(map[i][j] == 'S'){

			   	 s.x = i; s.y = j; s.t = 0;

			   }

			}	

		}

		int ans = 0;

		char c = '0';

		for(char i = 1; i <= N; i++)

		{

			node t = bfs(s.x, s.y, c + i);

			ans += t.t;

			s.x = t.x; s.y = t.y;

		}

		printf("%d\n", ans);

	}

	return 0; 

}


// Faster C++ solution for the same problem (measured speedup: 5.025334846514604x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<iostream>

#include<algorithm>

#include<math.h>

#include<string.h>

#include<queue>

#include<stdio.h>

using namespace std;



typedef struct{

	int x,y;

}p;

char a[1005][1005];

p acm[11];

p s,g;

int b[1005][1005];

int H,W,N;

int dx[]={1,-1,0,0};

int dy[]={0,0,1,-1};

int bfs(p s,p g)

{

	queue<p> q;

	p n;

	memset(b,-1,sizeof(b));

	q.push(s);

	b[s.x][s.y]=0;

	while(!q.empty())

	{

		p h;

		h=q.front();

		q.pop();

		if(h.x==g.x&&h.y==g.y)

		{

			break;

		}

		for(int i=0;i<4;i++)

		{

			n.x=h.x+dx[i];

			n.y=h.y+dy[i];

			if(n.x>=0&&n.x<H&&n.y>=0&&n.y<W&&a[n.x][n.y]!='X'&&b[n.x][n.y]==-1)

			{

				q.push(n);

				b[n.x][n.y]=b[h.x][h.y]+1;

			}

		}

	}

	return b[g.x][g.y];

}

int main()

{

	int i,j,t,step=0;

	scanf("%d%d%d",&H,&W,&N);

	for(i=0;i<H;i++)

	{

		scanf("%s",a[i]);

	}

	for(i=0;i<H;i++)

	for(j=0;j<W;j++)

	{

		if(a[i][j]>='1'&&a[i][j]<='9')

		{

			t=a[i][j]-'0';

		    acm[t].x=i;

		    acm[t].y=j;

		}

		else if(a[i][j]=='S')

		{

			s.x=i;

			s.y=j;

			a[i][j]='.';

		}

	}

		for(i=1;i<=N;i++)

		{

			g.x=acm[i].x;

			g.y=acm[i].y;

			step+=bfs(s,g);

			s.x=g.x;

			s.y=g.y;

			a[g.x][g.y]='.';

		}

	

	printf("%d\n",step);

	return 0;

 } 


// Faster C++ solution for the same problem (measured speedup: 5.056999405667259x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include<cstdio>

#include<cstdlib>

#include<cmath>

#include<cstring>

#include<iostream>

#include<algorithm>

#include<queue>

#include<stack>

#include<set>

using namespace std;

typedef long long ll;

typedef unsigned long long ull;

const int MAX_N=100000;

const int INF = 0x3f3f3f3f;

int n,m,k;

char map[1010][1010];

bool vis[1010][1010];



struct p{

	int x;

	int y;

	int step;

};

int ans=0;



bool yesorno(p x){

	if(x.x<1||x.x>m||x.y<1||x.y>n||map[x.y][x.x]=='X'||vis[x.y][x.x]==1)

		return 0;

	return 1;

}



int sx[4]={0,0,1,-1};

int sy[4]={1,-1,0,0};

void bfs(p st,int ww){

	memset(vis,0,sizeof(vis));

	if(ww==k)

		return;

	int temp=0;

	queue<p> q;

	q.push(st);

//	cout<<st.step<<" "<<ww<<" "<<k<<endl;

	while(!q.empty()){

		

		p ne=q.front();

		q.pop();

		if(map[ne.y][ne.x]==(char)'0'+ww+1){

			ans=ne.step;

			bfs(ne,ww+1);

			return;

		}

		for(int i=0;i<4;i++){

			p tem=ne;

			tem.x=tem.x+sx[i];

			tem.y=tem.y+sy[i];

			tem.step++;

			if(yesorno(tem)){

				q.push(tem);

				vis[tem.y][tem.x]=1;

			}

				

		}

	}

}

int main(){

	ios::sync_with_stdio(false);

	while(cin>>n>>m>>k){

		memset(vis,0,sizeof(vis));

		p st;

		for(int i=1;i<=n;i++){

			for(int j=1;j<=m;j++){

				cin>>map[i][j];

				if(map[i][j]=='S'){

					st.x=j;

					st.y=i;

					st.step=0;

				}

			}

		}

		bfs(st,0);

		cout<<ans<<endl;

	}





	return 0;

}






// Faster C++ solution for the same problem (measured speedup: 2.2508737794460156x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/
// Slower C++ solution:
#include <stdio.h>

#include <string.h>

#include <iostream>

#include <algorithm>

#include <math.h>

#include <vector>

#include <queue>

using namespace std;

int n,m,p;

int sx,sy;

char s[1505][1505];

struct node{

	int x,y,step;

	node(int sx,int sy,int step)

	{

		this->x=sx;this->y=sy;this->step=step;

	}

};

int dx[4]={0,0,-1,1};

int dy[4]={1,-1,0,0};

int vis[1505][1500];

node bfs(node u,int pos)

{

	queue<node> q;

	while(!q.empty())q.pop();

	q.push(u);

	

	while(!q.empty())

	{

		node v=q.front();q.pop();

		if(s[v.x][v.y]==pos+'0') return v;

		for(int i=0;i<4;i++)

		{

			int x=v.x+dx[i];

			int y=v.y+dy[i];

			if(x>=1&&x<=n&&y>=1&&y<=m&&s[x][y]!='X'&&vis[x][y]==0)

			{

				vis[x][y]=1;

				node now=node(x,y,v.step+1);

				q.push(now);

			}

		}

	}

}

int main()

{

	while(cin>>n>>m>>p)

	{

		int ans=0;

		for(int i=1;i<=n;i++)

		{

			cin>>s[i]+1;

			for(int j=1;j<=m;j++)

			{

				if(s[i][j]=='S') sx=i,sy=j;

			}

		}

		node u=node(sx,sy,0);	

		for(int i=1;i<=p;i++)

		{		

			memset(vis,0,sizeof(vis));

			vis[u.x][u.y]=1;

			u=bfs(u,i);

			ans+=u.step;

			u.step=0;

		}

		cout<<ans<<endl;

	}

	return 0;

}


// Faster C++ solution for the same problem (measured speedup: 10.382821439553878x):
#include <iostream>

#include <queue>



using namespace std;



char mp[1005][1005];

int vis[1005][1005];

int w, h, n;



int dirs[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};

int ans = 0, sx, sy;

int blood = 1;



struct Node{

	int x,y;

	Node(int _x, int _y){

		x = _x, y = _y;

	}

}; 

typedef struct Node Node; 



queue<Node> que;



void bfs(char t){

//	cout<<"sx = "<<sx<<", sy = "<<sy<<endl;

	que.push(Node(sx, sy));

	ans = 0;

	bool flag = true;

	while(!que.empty()){

//		cout<<"ans = "<<ans<<"n = "<<n<<endl;

		int size = que.size();

		for(int i = 0; i < size; i++){

			Node node = que.front();

			que.pop();

			int x = node.x, y = node.y;

//			cout<<"x = "<<x<<", y = "<<y<<endl;

			for(int i = 0; i < 4; i++){

				int tx = x + dirs[i][0], ty = y + dirs[i][1];

				if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 && mp[tx][ty] == t){

					sx = tx, sy = ty;

					ans++;

					flag = false;

					return;

				}else if(tx >= 0 && tx < h && ty >= 0 && ty < w && vis[tx][ty] == 0 &&  mp[tx][ty] != 'X'){

//					cout<<"tx = "<<tx<<", ty = "<<ty<<endl;

					que.push(Node(tx, ty));

					vis[tx][ty] = 1;

				}

			} 

		}

		ans++;

	}

	if(flag) ans = 0;

}



int main(){

	cin>>h>>w>>n;

	for(int i = 0; i < h; i++){

		scanf(" %s", mp[i]);

	}

	for(int i = 0; i < h; i++){

		for(int j = 0; j < w; j++){

			if(mp[i][j] == 'S'){

				sx = i, sy = j;

			}

		}

	}

	int res = 0;

	for(int i = 1; i <= n; i++){

		bfs(i + '0');

		for(int m = 0; m < h; m++)

			for(int k = 0; k < w; k++)

				vis[m][k] = 0;

		while(!que.empty())que.pop();

		res += ans;

	}

	cout<<res<<endl;

	return 0;

}



/**

331

S..

...

..1

*/