// Slower C++ solution:
#define _CRT_SECURE_NO_WARNINGS

#include<bits/stdc++.h>

#include<iostream>

#include<algorithm>

#include<iomanip>

#include<string>

#include<cmath>

#include<vector>

#include<set>

#include<queue>

#include<stack>

#include<fstream>

#include<map>

#include<bitset>

#include<unordered_map>

#include<cstring>

#include<cctype>

using namespace std;

#define  ll long long

#define  ull unsigned long long

#define  ul unsigned long

#define all(v) v.begin(),v.end()

#define sz(n) (int)n.size()

#define pb(s) push_back(s);

#define format(n) fixed<<setprecision(n)

#define finl "\n"

#define Mohammed_Atef_Hassan fast();

#define mod 1000000007

#define INF LLONG_MAX

#define PI acos(-1)

#define clr(dp,n) memset(dp,n,sizeof dp)

#define ex(n) return cout<<n<<finl,0;

int dx[] = { 0, 1, 0, -1, 1, 1, -1, -1 };

int dy[] = { 1, 0, -1, 0, 1, -1, 1, -1 };

ll fix_mod(ll x, ll y)

{

	return (y + x % y) % y;

}

void fast() {

	std::ios_base::sync_with_stdio(false);

	cin.tie(nullptr); cout.tie(nullptr);





}

int n;

vector<vector<ll>>v;

ll mem[(int)1e5 + 10][5];

ll solve(int i, int c)

{

	if (i == n)return 0;

	ll& ret = mem[i][c];

	if (~ret)return ret;

	for (int k = 0; k < 3; k++)

	{

		if (k == c)continue;

		ret = max(ret, solve(i+1, k) + v[i][k]);

	}

	return ret;

}

int main()

{

	Mohammed_Atef_Hassan

		cin >> n;

	v = vector<vector<ll>>(n + 1, vector<ll>(3));

	for (int i = 0; i < n; i++)

		cin >> v[i][0] >> v[i][1] >> v[i][2];

	clr(mem, -1);

	ex(solve(0, 4));

}

// Faster C++ solution for the same problem (measured speedup: 5.040759214206176x):
//I solved it before. If I had enough time I wouldn't have submitted old codes.

//If you forbid I won't do this in the upcoming contests

#include <iostream>

#include <vector>

#include <cmath>

#include <set>

#include <queue>

#include <map>

#include <cstdio>

#include <cstring>

#include <string>

#include <stack>

#include <algorithm>

#include <limits.h>

#include <bits/stdc++.h>

#define fw(x) freopen("x.txt","w",stdout)

#define For(i,a,b,c) for(int i = a;i < b;i+=c)

#define REP(i,n) for(int i = 0;i < n;++i)

#define REP1(i,n) for(int i = 1; i<=n;i++)

#define mem(a,s) memset(a,s,sizeof a)

#define fast ios_base::sync_with_stdio(0);cin.tie(NULL)

#define pf printf

#define sc scanf

#define ll long long

#define pii pair<int,int>

#define pll pair<ll,ll>

#define all(v) v.begin(),v.end()

#define vii vector<int>

#define vll vector<ll>

#define vss vector<string>

#define debug(x)  cout<<#x"="<<(x)<<endl

#define pb push_back





using namespace std;





// moves



//int dx[]= {0,0,1,-1};/*4 side move*/

//int dy[]= {-1,1,0,0};/*4 side move*/

//int dx[]= {1,1,0,-1,-1,-1,0,1};/*8 side move*/

//int dy[]= {0,1,1,1,0,-1,-1,-1};/*8 side move*/

//int dx[]={1,1,2,2,-1,-1,-2,-2};/*knight move*/

//int dy[]={2,-2,1,-1,2,-2,1,-1};/*knight move*/





//big_mod



//ll bigmod(ll a,ll b,ll m)

//{if(b == 0) return 1%m;ll x = bigmod(a,b/2,m);x = (x * x) % m;if(b % 2 == 1) x = (x * a)% m;return x;}

//ll BigMod(ll B,ll P,ll M){ ll R=1%M; while(P>0) {if(P%2==1){R=(R*B)%M;}P/=2;B=(B*B)%M;} return R;} /// (B^P)%M



//ll getBit(ll num, int idx) {return ((num >> idx) & 1ll) == 1ll;}

//ll setBit1(ll num, int idx) {return num or (1ll<<idx);}

//ll setBit0(ll num, int idx) {return num & ~(1ll<<idx);}

//ll flipBit(ll num, int idx) {return num ^ (1ll<<idx);}



const int mod = 1000000007;

ll qpow(ll n,ll k)

{

    ll ans=1;

    assert(k>=0);

    n%=mod;

    while(k>0)

    {

        if(k&1)

            ans=(ans*n)%mod;

        n=(n*n)%mod;

        k>>=1;

    }

    return ans%mod;

}

int ar[100009][3];

int sum[100009][3];

void run(int i, int pre, int n){

    if(i>=n) return;

    int sum1=0, sum2=0, sum3=0;

    if(pre!=0){

        if(sum[i+1][0] == -1 ) run(i+1, 0, n);

        sum1 = ar[i][pre] + sum[i+1][0];

    }

    if(pre!=1){

        if(sum[i+1][1] == -1 ) run(i+1, 1, n);

        sum2 = ar[i][pre] + sum[i+1][1];

    }

    if(pre!=2){

        if(sum[i+1][2] == -1 ) run(i+1, 2, n);

        sum3 = ar[i][pre] + sum[i+1][2];

    }

    sum[i][pre] = max(sum1, max(sum2, sum3));

}

int main()

{

    fast;

    int n, a, b, c;

    cin>>n;

    REP1(i, n){

        cin>>a>>b>>c;

        sum[i][0]= -1;

        sum[i][1]= -1;

        sum[i][2]= -1;

        ar[i][0] = a;

        ar[i][1] = b;

        ar[i][2] = c;

    }

    sum[n][0] = ar[n][0];

    sum[n][1] = ar[n][1];

    sum[n][2] = ar[n][2];

    run(1, 0, n);

    run(1, 1, n);

    run(1, 2, n);

    cout<< max(sum[1][0], max(sum[1][1], sum[1][2]) ) <<'\n';

    return 0;

}