// Slower C++ solution:
#include<set>

#include<map>

#include<cmath>

#include<ctime>

#include<queue>

#include<stack>

#include<cstdio>

#include<string>

#include<vector>

#include<random>

#include<cstdlib>

#include<cstring>

#include<iomanip>

#include<iostream>

#include<algorithm>

#include<unordered_map>

#define endl "\n"

#define fi first

#define se second

#define db double

#define gcd __gcd

#define pb push_back

#define mp make_pair

#define lowbit(x) (x & (-x))

#define PII  pair<int, int> 

#define all(x) x.begin(), x.end()

#define debug(x) cout << #x << " = " << x << endl

#define rep(i, a, b) for(__typeof(b) i = a; i <= (b); i++)

#define Rep(i, a, b) for(__typeof(a) i = a; i >= (b); i--)

#define FAST ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)

template<class T> inline T qmin(T a, T b) { return a < b ? a : b; }

template<class T> inline T qmax(T a, T b) { return a > b ? a : b; }

typedef long long ll;

typedef unsigned long long ull;

const db eps = 1e-9;

const db PI = acos(-1);

const int inf = 0x3f3f3f3f;

const int mod = (int)1e9 + 7;

const int maxn = (int)1e5 + 5;//remember to modify it, No RE or MLE

const ll INF = 0x3f3f3f3f3f3f3f3f;

using namespace std;



ll qpow(ll x, ll y) { ll ret = 1; for( ; y; y >>= 1, x = (x * x) % mod) if(y & 1) ret = (ret * x) % mod; return ret; }



inline int read(){

	char ch = getchar();

	int x = 0, f = 1;

	while(ch < '0' || ch > '9'){

		if(ch == '-') f = -1;

		ch = getchar();

	}

	while('0' <= ch && ch <= '9'){

		x = x * 10 + ch - '0';

		ch = getchar();

	}

	return x * f;

}



int dp[maxn];//0 必败态; 1必胜态; -1尚未确定;

int a[105];

int n, k;

int cnt = 0;



bool dfs(int now){

	if(~dp[now]) return dp[now];

	bool ret = 0;

	rep(i, 1, n){

		if(a[i] > now) break;

		if(!dfs(now - a[i])) ret = 1;

	}

	return dp[now] = ret;

}



int main()

{

	n = read(), k = read();

	rep(i, 1, n) a[i] = read();

	memset(dp, -1, sizeof dp);

	sort(a + 1, a + n + 1);

	dp[0] = 0;

	dfs(k);

	puts(dp[k] ? "First" : "Second");

	return 0;

}

// Faster C++ solution for the same problem (measured speedup: 1.3440912170166717x):
#include <bits/stdc++.h>



#define forn(i, n) for (int i = 0; i < int(n); ++i)

#define for1(i, n) for (int i = 1; i <= int(n); ++i)

#define fore(i, l, r) for (int i = int(l); i <= int(r); ++i)

#define ford(i, n) for (int i = int(n)-1; i >= 0; --i)

#define pb push_back

#define eb emplace_back

#define ms(a, x) memset(a, x, sizeof(a))

#define F first

#define S second

#define endl '\n'

#define de(x) cout<<#x<<" = "<<(x)<<endl

#define de2(x,y) cout<<#x<<" = "<<(x) <<' '<< #y<<" = "<<y<<endl;



using namespace std;



typedef long long ll;

typedef pair<int, int> pii;

const int INF = 0x3f3f3f3f;

mt19937 gen(chrono::high_resolution_clock::now().time_since_epoch().count());



int main() {

    ios::sync_with_stdio(false);

    cin.tie(nullptr);

	int n,k;

	cin>>n>>k;

	vector<int> a(n);

	for(auto& it:a) cin>>it;

	vector<int> sg(k+1);

	for(int i=0;i<=k;i++){

		vector<bool> flag(k+1);

		for(auto it:a){

			if(i-it>=0) flag[sg[i-it]]=1;

		}

		for(int j=0;j<=k;j++){

			if(flag[j]==0){

				sg[i]=j;

				break;

			}

		}

	}

	cout<<(sg[k]?"First":"Second");

    return 0;

}