// Original C++ solution (slower):
#include <stdio.h>

#include <complex>

#include <vector>

#include <algorithm>

using namespace std;

#define rep(i, n) for (int i = 0; i < (int)(n); i++)

typedef complex<double> P;

#define EPS (1e-6)



P readP() {

    double x, y;

    scanf("%lf%lf", &x, &y);

    return P(x, y);

}



double radius(const vector<P>& ps) {

    P p = P(0, 0);

    double cur = 1.0;

    rep (dep, 30) {

        rep (_, 100) {

            double mx = norm(ps[0]-p);

            int ix = 0;

            rep (i, ps.size()) {

                const double d = norm(ps[i]-p);

                if (mx < d) mx = d, ix = i;

            }

            p += cur*(ps[ix]-p);

        }

        cur *= 0.5;

    }

    double ans = 0;

    rep (i, ps.size()) ans = max(ans, abs(ps[i]-p));

    return ans;

}



int n, m;

double rs[128], ts[128];

bool used[128];



bool can(int k) {

    vector<double> a, b;

    rep (i, n) if (!used[i]) a.push_back(rs[i]);

    rep (i, m) if (i >= k) b.push_back(ts[i]);

    sort(a.begin(), a.end());

    reverse(a.begin(), a.end());

    sort(b.begin(), b.end());

    reverse(b.begin(), b.end());

    rep (i, b.size()) if (b[i] > a[i]+EPS) return false;

    return true;

}



int main() {

    scanf("%d%d", &n, &m);

    rep (i, n) scanf("%lf", rs+i);

    rep (i, m) {

        int K;

        scanf("%d", &K);

        vector<P> ps;

        rep (_, K) ps.push_back(readP());

        ts[i] = radius(ps);

    }

    if (!can(0)) puts("NG");

    else {

        rep (k, m) rep (i, n) if (!used[i] && ts[k] <= rs[i]+EPS) {

            used[i] = 1;

            if (can(k+1)) { printf("%d\n", i+1); break; }

            used[i] = 0;

        }

    }

    return 0;

}

// Optimized solution to the same problem (faster):
#include <stdio.h>

#include <complex>

#include <vector>

#include <algorithm>

using namespace std;

#define rep(i, n) for (int i = 0; i < (int)(n); i++)

typedef complex<double> P;

#define EPS (1e-6)



P readP() {

    double x, y;

    scanf("%lf%lf", &x, &y);

    return P(x, y);

}



double radius(const vector<P>& ps) {

    P p = P(0, 0);

    double cur = 1.0;

    rep (dep, 30) {

        rep (_, 20) {

            double mx = norm(ps[0]-p);

            int ix = 0;

            rep (i, ps.size()) {

                const double d = norm(ps[i]-p);

                if (mx < d) mx = d, ix = i;

            }

            p += cur*(ps[ix]-p);

        }

        cur *= 0.5;

    }

    double ans = 0;

    rep (i, ps.size()) ans = max(ans, abs(ps[i]-p));

    return ans;

}



int n, m;

double rs[128], ts[128];

bool used[128];



bool can(int k) {

    vector<double> a, b;

    rep (i, n) if (!used[i]) a.push_back(rs[i]);

    rep (i, m) if (i >= k) b.push_back(ts[i]);

    sort(a.begin(), a.end());

    reverse(a.begin(), a.end());

    sort(b.begin(), b.end());

    reverse(b.begin(), b.end());

    rep (i, b.size()) if (b[i] > a[i]+EPS) return false;

    return true;

}



int main() {

    scanf("%d%d", &n, &m);

    rep (i, n) scanf("%lf", rs+i);

    rep (i, m) {

        int K;

        scanf("%d", &K);

        vector<P> ps;

        rep (_, K) ps.push_back(readP());

        ts[i] = radius(ps);

    }

    if (!can(0)) puts("NG");

    else {

        rep (k, m) rep (i, n) if (!used[i] && ts[k] <= rs[i]+EPS) {

            used[i] = 1;

            if (can(k+1)) { printf("%d\n", i+1); break; }

            used[i] = 0;

        }

    }

    return 0;

}

// Fastest known solution for this problem: