// Original C++ solution (slower):
#include<iostream>

#include<cstdio>

#include<queue>

#include<cstring>

#include<algorithm>

using namespace std;

typedef long long ll;

typedef pair<int,int>P;

const int Max_n=1100;



int n,m,d;

struct Node{

    int x,y,d;

    Node(int xx,int yy,int dd):x(xx),y(yy),d(dd){}

};

char s[Max_n][Max_n];

bool vis[Max_n][Max_n];

int dx[4]={0,0,1,-1};

int dy[4]={1,-1,0,0};



Node bfs(int x1,int y1,int k){

    memset(vis,0,sizeof(vis));

    queue<Node>que;

    que.push(Node(x1,y1,0));

    vis[x1][y1]=1;

    while(!que.empty()){

        Node node=que.front();que.pop();

        int x=node.x,y=node.y;

        if(k==s[x][y]-'0')return node;

        int d=node.d;

        for(int i=0;i<4;i++){

            int X=x+dx[i],Y=y+dy[i];

            if(!vis[X][Y]&&(s[X][Y]=='S'||s[X][Y]=='.'||(s[X][Y]>='1'&&s[X][Y]<='9'))){

                vis[X][Y]=1;

                que.push(Node(X,Y,d+1));

            }

        }

    }

}



int main()

{

    while(~scanf("%d%d%d",&n,&m,&d)){

        memset(s,0,sizeof(s));

        for(int i=1;i<=n;i++)scanf("%s",s[i]+1);

        int x,y;

        for(int i=1;i<=n;i++){

            for(int j=1;j<=m;j++)

            if(s[i][j]=='S'){x=i;y=j;}

        }

        int sum=0;

        for(int i=1;i<=d;i++){

            Node node=bfs(x,y,i);

            sum+=node.d;

            x=node.x,y=node.y;

        }

        printf("%d\n",sum);

    }

    return 0;

}






// Optimized solution to the same problem (faster):
#include <iostream>

#include <queue>

using namespace std;

const int INF = 100000000;

typedef pair<int,int> Point;

Point AllPoint[1000];

int W,H;

int x[4] = {0,1,0,-1};

int y[4] = {1,0,-1,0};

char map[1000][1000];

int deep[1000][1000];

int N;

void BFS(Point Start,Point Over){

    queue<Point> que;

    int FirstDeep = deep[Start.first][Start.second];

    for (int i = 0;i<H;i++){

        for (int j = 0;j<W;j++){

            deep[i][j] = INF;

        }

    }

    que.push(Start);

    deep[Start.first][Start.second] = FirstDeep;

    while (que.size()){

        Point p = que.front();

        que.pop();

        if (p.first== Over.first&&p.second == Over.second)

            break;

        for (int i = 0;i<4;i++){

            int ix = p.first+x[i];

            int iy = p.second+y[i];

            if (ix>=0&&ix<=H

                &&iy>=0&&iy<=W

                &&deep[ix][iy] == INF

                &&map[ix][iy]!='X'){

                que.push(Point(ix,iy));

                deep[ix][iy] = deep[p.first][p.second]+1;

            }

        }

    }

}







int main(){

    cin >> H >> W;

    cin >> N;

    for (int i = 0;i<H;i++){

        for (int j = 0;j<W;j++){

            cin >> map[i][j];

            if ((int)map[i][j]-48>=1&&(int)map[i][j]-48<=N){

                AllPoint[(int)map[i][j]-48].first = i;

                AllPoint[(int)map[i][j]-48].second = j;



            }

            if (map[i][j] == 'S'){

                AllPoint[0].first = i;

                AllPoint[0].second = j;

            }

        }

    }

    deep[AllPoint[0].first][AllPoint[0].second] = 0;

    for (int i = 0;i<N;i++){

        BFS(AllPoint[i],AllPoint[i+1]);

    }

    cout << deep[AllPoint[N].first][AllPoint[N].second]<<endl;



    return 0;

}

//#....

//S.##.

//###G.

//#####

//#####



//#S######.#

//......#..#

//.#.##.##.#

//.#........

//##.##.####

//....#....#

//.#######.#

//....#.....

//.####.###.

//....#...G#






// Fastest known solution for this problem: