// Original C++ solution (slower):
#include <cassert>

#include <cstdio>

#include <cmath>

#include <iostream>

#include <iomanip>

#include <sstream>

#include <vector>

#include <set>

#include <map>

#include <queue>

#include <numeric>

#include <algorithm>



using namespace std;

using lint = long long;

constexpr int MOD = 1000000007, INF = 1010101010;

constexpr lint LINF = 1LL << 60;



template <class T>

ostream &operator<<(ostream &os, const vector<T> &vec) {

	for (const auto &e : vec) os << e << (&e == &vec.back() ? "\n" : " ");

	return os;

}



#ifdef _DEBUG

template <class T>

void dump(const char* str, T &&h) { cerr << str << " = " << h << "\n"; };

template <class Head, class... Tail>

void dump(const char* str, Head &&h, Tail &&... t) {

	while (*str != ',') cerr << *str++; cerr << " = " << h << "\n";

	dump(str + (*(str + 1) == ' ' ? 2 : 1), t...);

}

#define DMP(...) dump(#__VA_ARGS__, __VA_ARGS__)

#else 

#define DMP(...) ((void)0)

#endif



template<class T>

vector<T> make_vec(size_t s, T val) { return vector<T>(s, val); }

template<class... Size>

auto make_vec(size_t s, Size... tail) {

	return vector<decltype(make_vec(tail...))>(s, make_vec(tail...));

}



template<class T>

inline bool chmin(T &a, const T b) { return a > b && (a = b, true); }



int main() {



	cin.tie(nullptr);

	ios::sync_with_stdio(false);



	int H, W;

	cin >> H >> W;



	vector<vector<int>> A(H, vector<int>(W));

	vector<vector<int>> B(H, vector<int>(W));

	for (int i = 0; i < H; i++) for (int j = 0; j < W; j++) cin >> A[i][j];

	for (int i = 0; i < H; i++) for (int j = 0; j < W; j++) cin >> B[i][j];



	const int offset = 6500;

	auto dp = make_vec(H + 1, W + 1, offset * 2 + 1, char(0));

	dp[0][0][offset] = 1;

	for (int i = 0; i < H; i++) {



		for (int j = 0; j < W; j++) {



			for (int k = 0; k <= 2 * offset; k++) {



				if (0 <= k + A[i][j] - B[i][j] && k + A[i][j] - B[i][j] <= 2 * offset) {

					dp[i][j + 1][k] |= dp[i][j][k + A[i][j] - B[i][j]];

				}

				if (0 <= k - A[i][j] + B[i][j] && k - A[i][j] + B[i][j] <= 2 * offset) {

					dp[i][j + 1][k] |= dp[i][j][k - A[i][j] + B[i][j]];

				}

				

			}



		}

		DMP(dp);



		if (i == H - 1) break;

		for (int j = 1; j <= W; j++) {

			for (int k = 0; k <= 2 * offset; k++) {

				if (0 <= k + A[i + 1][j - 1] - B[i + 1][j - 1] && k + A[i + 1][j - 1] - B[i + 1][j - 1] <= 2 * offset) {

					dp[i+1][j][k] |= dp[i][j][k + A[i + 1][j - 1] - B[i + 1][j - 1]];

				}

				if (0 <= k - A[i + 1][j - 1] + B[i + 1][j - 1] && k - A[i + 1][j - 1] + B[i + 1][j - 1] <= 2 * offset) {

					dp[i+1][j][k] |= dp[i][j][k - A[i + 1][j - 1] + B[i + 1][j - 1]];

				}

			}

		}



		DMP(dp);



	}



	int ans = INF;

	for (int i = 0; i <= 2 * offset; i++) {

		if(dp[H - 1][W][i]) chmin(ans, abs(i - offset));

	}



	cout << ans << "\n";



	return 0;

}

// Optimized solution to the same problem (faster):
#include <cassert>

#include <cstdio>

#include <cmath>

#include <iostream>

#include <iomanip>

#include <sstream>

#include <vector>

#include <set>

#include <map>

#include <queue>

#include <numeric>

#include <algorithm>

#include <bitset>



using namespace std;

using lint = long long;

constexpr int MOD = 1000000007, INF = 1010101010;

constexpr lint LINF = 1LL << 60;



template <class T>

ostream &operator<<(ostream &os, const vector<T> &vec) {

	for (const auto &e : vec) os << e << (&e == &vec.back() ? "\n" : " ");

	return os;

}



#ifdef _DEBUG

template <class T>

void dump(const char* str, T &&h) { cerr << str << " = " << h << "\n"; };

template <class Head, class... Tail>

void dump(const char* str, Head &&h, Tail &&... t) {

	while (*str != ',') cerr << *str++; cerr << " = " << h << "\n";

	dump(str + (*(str + 1) == ' ' ? 2 : 1), t...);

}

#define DMP(...) dump(#__VA_ARGS__, __VA_ARGS__)

#else 

#define DMP(...) ((void)0)

#endif



template<class T>

vector<T> make_vec(size_t s, T val) { return vector<T>(s, val); }

template<class... Size>

auto make_vec(size_t s, Size... tail) {

	return vector<decltype(make_vec(tail...))>(s, make_vec(tail...));

}



template<class T>

inline bool chmin(T &a, const T b) { return a > b && (a = b, true); }



int main() {



	cin.tie(nullptr);

	ios::sync_with_stdio(false);



	int H, W;

	cin >> H >> W;



	vector<vector<int>> A(H, vector<int>(W));

	vector<vector<int>> B(H, vector<int>(W));

	for (int i = 0; i < H; i++) for (int j = 0; j < W; j++) cin >> A[i][j];

	for (int i = 0; i < H; i++) for (int j = 0; j < W; j++) cin >> B[i][j];



	const int offset = 6500;

	vector<bitset<offset * 2 + 1>> dp(W + 1);

	dp[0][offset] = 1;

	for (int i = 0; i < H; i++) {



		for (int j = 0; j < W; j++) {

int shift = abs(A[i][j] - B[i][j]);

dp[j + 1] |= (dp[j] << shift) | (dp[j] >> shift);



		}

		DMP(dp);

dp[0][offset]=0;

		if (i == H - 1) break;

		for (int j = 1; j <= W; j++) {

int shift = abs(A[i + 1][j - 1] - B[i + 1][j - 1]);

          DMP(shift);

dp[j] = (dp[j] << shift) | (dp[j] >> shift);

		}

		DMP(dp);



	}



	int ans = INF;

	for (int i = 0; i <= 2 * offset; i++) {

		if (dp[W][i]) chmin(ans, abs(i - offset));

	}



	cout << ans << "\n";



	return 0;

}


// Fastest known solution for this problem: