// Original C++ solution (slower):
///*بِسْمِ اللَّهِ الرَّحْمَنِ الرَّحِيم*///



//#pragma GCC optimize("Ofast")

//#pragma GCC target("avx,avx2,fma")

//#pragma GCC optimization ("unroll-loops")



#include <bits/stdc++.h>

using namespace std;

#define ln '\n'

#define inp(x) scanf("%lld",&x)

#define inp2(a,b) scanf("%lld %lld",&a,&b)

#define sf scanf

#define pf printf



#define f0(i,b) for(int i=0;i<(b);i++)

#define f1(i,b) for(int i=1;i<=(b);i++)



#define MOD 1000000007

#define PI acos(-1)

#define ll long long int

typedef pair<int,int> pii;

typedef pair<ll, ll> pll;

#define pb push_back

#define F first

#define S second

#define sz size()

#define LCM(a,b) (a*(b/__gcd(a,b)))

//#define harmonic(n) 0.57721566490153286060651209+log(n)+1.0/(2*n)

#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))

#define all(v) v.begin(),v.end()

#define MEM(a, b) memset(a, b, sizeof(a))



#define fastio ios_base::sync_with_stdio(false)



///Inline functions



inline bool EQ(double a, double b) { return fabs(a-b) < 1e-9; }

//inline bool isLeapYearll year) { return (year%400==0) | (year%4==0 && year%100!=0); }

inline void normal(ll &a) { a %= MOD; (a < 0) && (a += MOD); }

inline ll modMul(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); return (a*b)%MOD; }

inline ll modAdd(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); return (a+b)%MOD; }

inline ll modSub(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); a -= b; normal(a); return a; }

inline ll modPow(ll b, ll p) { ll r = 1; while(p) { if(p&1) r = modMul(r, b); b = modMul(b, b); p >>= 1; } return r; }

inline ll modInverse(ll a) { return modPow(a, MOD-2); }

inline ll modDiv(ll a, ll b) { return modMul(a, modInverse(b)); }

inline bool isInside(pii p,ll n,ll m){ return (p.first>=0&&p.first<n&&p.second>=0&&p.second<m); }

inline bool isInside(pii p,ll n){ return (p.first>=0&&p.first<n&&p.second>=0&&p.second<n); }

inline bool isSquare(ll x){ ll s = sqrt(x);    return (s*s==x); }

inline bool isFib(ll x) { return isSquare(5*x*x+4)|| isSquare(5*x*x-4); }

inline bool isPowerOfTwo(ll x){ return ((1LL<<(ll)log2(x))==x); }





/// DEBUG --------------------------------------------------------------------------------->>>>>>



///**

template < typename F, typename S >

ostream& operator << ( ostream& os, const pair< F, S > & p )

{

    return os << "(" << p.first << ", " << p.second << ")";

}



template < typename T >

ostream &operator << ( ostream & os, const vector< T > &v )

{

    os << "{";

    for (auto it = v.begin(); it != v.end(); ++it)

    {

        if ( it != v.begin() )

            os << ", ";

        os << *it;

    }

    return os << "}";

}



template < typename T >

ostream &operator << ( ostream & os, const set< T > &v )

{

    os << "[";

    for (auto it = v.begin(); it != v.end(); ++it)

    {

        if ( it != v.begin())

            os << ", ";

        os << *it;

    }

    return os << "]";

}



template < typename F, typename S >

ostream &operator << ( ostream & os, const map< F, S > &v )

{

    os << "[";

    for (auto it = v.begin(); it != v.end(); ++it)

    {

        if ( it != v.begin() )

            os << ", ";

        os << it -> first << " = " << it -> second ;

    }

    return os << "]";

}



#define dbg(args...) do {cerr << #args << " : "; faltu(args); } while(0)



clock_t tStart = clock();

#define timeStamp dbg("Execution Time: ", (double)(clock() - tStart)/CLOCKS_PER_SEC)



void faltu ()

{

    cerr << endl;

}



template <typename T>

void faltu( T a[], int n )

{

    for (int i = 0; i < n; ++i)

        cerr << a[i] << ' ';

    cerr << endl;

}



template <typename T, typename ... hello>

void faltu( T arg, const hello &... rest)

{

    cerr << arg << ' ';

    faltu(rest...);

}



/// TEMPLATE ----------------------------------------------------------------------->>>>>>





struct func

{

//this is a sample overloading function for sorting stl

    bool operator()(pii const &a, pii const &b)

    {

        if(a.F==b.F)

            return (a.S<b.S);

        return (a.F<b.F);

    }

};

/*------------------------------Graph Moves----------------------------*/

//Rotation: S -> E -> N -> W

//const int fx[] = {0, +1, 0, -1};

//const int fy[] = {-1, 0, +1, 0};

//const int fx[]={+0,+0,+1,-1,-1,+1,-1,+1};   // Kings Move

//const int fy[]={-1,+1,+0,+0,+1,+1,-1,-1};  // Kings Move

//const int fx[]={-2, -2, -1, -1,  1,  1,  2,  2};  // Knights Move

//const int fy[]={-1,  1, -2,  2, -2,  2, -1,  1}; // Knights Move

/*---------------------------------------------------------------------*/



/// Bit Operations

/// count set bit C = (num * 0x200040008001ULL & 0x111111111111111ULL) % 0xf; /// 32 bit integer

/// inline bool checkBit(ll n, int i) { return n&(1LL<<i); }

/// inline ll setBit(ll n, int i) { return n|(1LL<<i); }

/// inline ll resetBit(ll n, int i) { return n&(~(1LL<<i)); }





/// ************************************** Code starts here ****************************************** */



const ll INF = 0x3f3f3f3f3f3f3f3f;

const long double EPS = 1e-9;

const int inf = 0x3f3f3f3f;

const int mx = (int)1e5+9;



ll n,m,a,b,t,i,j,d,cs=0,counT=0,k,ans=0,l=0,sum1=0,sum=0,Max,Min,num;

vector<ll>vc;

map<char,ll>mp;



int main()

{

  //  freopen("in.txt","r",stdin);

  fastio;



      cin >> n ;

      f0(i,n)

      {

          cin >> a ;

          vc.pb(a);

      }

      ans = INF;

      for(i=-300;i<=300;i++)

      {

          counT = 0 ;

          f0(j,n)

          {

              d = vc[j]-i;

              counT += (d*d);

          }

          ans = min(ans,counT);

      }

      cout << ans << ln ;











  /// Comment the debugger section

}


// Optimized solution to the same problem (faster):
#include<stdio.h>

#include<math.h>



int main(){

	

	int n;

	scanf("%d", &n);

	

	int num[n];

	int high = -101;

	int low = 101;

	

	for(int i = 0; i < n; i++){

		scanf("%d", &num[i]);

		if(high < num[i]){

			high = num[i];

		}

		if(low > num[i]){

			low = num[i];

		}

	}

		

	int bayar = 10000000;

	

	for(int i = low; i <= high; i++){

		int total = 0;

		for(int j = 0; j < n; j++){

			total += pow(i - num[j], 2);

		}

		if(total < bayar){

			bayar = total;

		}

	}

	

	printf("%d\n", bayar);

	

	return 0;

	

}

// Fastest known solution for this problem: