// Original C++ solution (slower):
#include<queue>

#include<cstdio>

#include<vector>

#include<cstring>

#include<iostream>

#include<algorithm>

#define RG register

#define LL long long

#define fre(a) freopen(a".in","r",stdin);//freopen(a".out","w",stdout);

using namespace std;

const int MAXN=50000;

int n,m,num;

int head[MAXN],to[MAXN],len[MAXN],cost[MAXN],Next[MAXN];

int dis[MAXN],pre[MAXN],pree[MAXN];

bool vis[MAXN],use[MAXN];

queue<int>que;

void add(int f,int t,int l,int c)

{

   Next[++num]=head[f];

   to[num]=t;

   len[num]=l;

   cost[num]=c;

   head[f]=num;

}

void SPFA()

{

   que.push(1);

   dis[1]=0;

   while(!que.empty())

      {

	 int now=que.front();

	 que.pop(); vis[now]=0;

	 for(int i=head[now];i;i=Next[i])

	    {

	       int son=to[i];

	       if(dis[now]+len[i]<dis[son])

		  {

		     dis[son]=dis[now]+len[i];

		     pre[son]=now;

		     pree[son]=i;

		     if(!vis[son])

			{

			   vis[son]=1;

			   que.push(son);

			}

		  }

	       else if(dis[now]+len[i]==dis[son])

		  {

		     if(cost[i]<cost[pree[son]])

			pree[son]=i,pre[son]=now;

		  }

	    }

      }

}

int main()

{

   //fre("1");

   while(1)

      {

	 scanf("%d%d",&n,&m);

	 if(n==0&&m==0)return 0;

	 num=0;

	 memset(head,0,sizeof head);

	 for(int i=1,a,b,c,d;i<=m;i++)

	    {

	       scanf("%d%d%d%d",&a,&b,&c,&d);

	       add(a,b,c,d); add(b,a,c,d);

	    }

	 memset(dis,0x3f3f3f3f,sizeof dis);

	 memset(vis,0,sizeof vis);

	 memset(use,0,sizeof use);

	 //memset(pree,0,sizeof pree);

	 SPFA();

	 //for(int i=1;i<=n;i++)printf("dis[%d]=%d\n",i,dis[i]);printf("----------------\n");

	 int ans=0;

	 for(int i=2;i<=n;i++)

	    for(int j=i;j>1;j=pre[j])

	       if(!use[pree[j]])

		  ans+=cost[pree[j]],use[pree[j]]=1;

	 printf("%d\n",ans);

      }

   return 0;

}

// Optimized solution to the same problem (faster):
#include <cstdio>

#include <cstring>

#include <algorithm>



using namespace std;



const int inf = 0x3f3f3f3f;

const int N = 10414;

const int M = 40414;



struct Edge{

	int u, v, d, c;

	int next;

}edge[M];



int cnt, head[N];

int vis[N], dis[N], cost[N];

int op, tp, link[18014];



void add_edge(int u, int v, int d, int c);

void spfa(int n);



int main(){

	int n, m, i, u, v, d, c;

	while(~scanf("%d %d", &n, &m) && (n || m)){

		cnt = 0;

		memset(head, -1, sizeof(head));

		for(i = 0; i < m; i++){

			scanf("%d %d %d %d", &u, &v, &d, &c);

			add_edge(u, v, d, c);

			add_edge(v, u, d, c);

		}

		spfa(n);

	}

	return 0;

}

void add_edge(int u, int v, int d, int c){

	edge[cnt].u = u;

	edge[cnt].v = v;

	edge[cnt].d = d;

	edge[cnt].c = c;

	edge[cnt].next = head[u];

	head[u] = cnt++;

	return;

}

void spfa(int n){

	int i, u, v, d, c, sum;

	memset(vis, 0, sizeof(vis));

	memset(dis, inf, sizeof(dis));

	memset(cost, inf, sizeof(cost));

	op = tp = 0;

	vis[1] = 1, dis[1] = 0, cost[1] = 0;

	link[tp++] = 1;

	while(op < tp){

		u = link[op++];

		vis[u] = 0;

		for(i = head[u]; ~i; i = edge[i].next){

			v = edge[i].v, d = edge[i].d, c = edge[i].c;



			if(dis[v] > dis[u] + d || (dis[v] == dis[u] + d && cost[v] > c)){

				dis[v] = dis[u] + d;

				cost[v] = c;

				if(!vis[v]){

					vis[v] = 1;

					link[tp++] = v;

				}

			}

		}

	}

	sum = 0;

	for(i = 1; i <= n; i++){

		sum += cost[i];

	}

	printf("%d\n", sum);

	return;

}




// Fastest known solution for this problem: