// Original C++ solution (slower):
#include<iostream>

#include<queue>

using namespace std;



//-----------------------------------LIBRARY OF INPUT-----------------------------------

void reader(int *x) {

	int k = getchar_unlocked(); *x = k - '0';

	while (true) {

		k = getchar_unlocked();

		if (k < '0' || k > '9') break;

		*x = ((*x) << 1) + ((*x) << 3) + k - '0';

	}

}



int n, m, q, dist[110003], mark[110003], u[210003], v[210003];

vector<pair<int, int>>x[110003], y[110003], z[110003]; bool used[210003];

inline bool isgood(int f) {

	for (int i = 0; i < z[f].size(); i++) {

		if (mark[z[f][i].first] == 0 && used[z[f][i].second] == false)return true;

	}

	return false;

}

int main() {

	reader(&n); reader(&m); reader(&q); queue<int>Q;

	for (int i = 0; i < m; i++) {

		int a = 0, b = 0;

		reader(&a);

		reader(&b);

		u[i + 1] = a; v[i + 1] = b;

		x[a].push_back(make_pair(b, i + 1)); x[b].push_back(make_pair(a, i + 1));

	}

	Q.push(1); for (int i = 1; i <= n; i++)dist[i] = 999999; dist[1] = 0;

	while (!Q.empty()) {

		int a1 = Q.front(); Q.pop();

		for (int i = 0; i < x[a1].size(); i++) {

			if (dist[x[a1][i].first] > dist[a1] + 1) { dist[x[a1][i].first] = dist[a1] + 1; Q.push(x[a1][i].first); }

		}

	}

	for (int i = 1; i <= n; i++) {

		for (int j = 0; j < x[i].size(); j++) {

			if (dist[i] < dist[x[i][j].first]) { y[i].push_back(x[i][j]); }

			if (dist[i] > dist[x[i][j].first]) { z[i].push_back(x[i][j]); }

		}

	}

	int cnt = 0;

	for (int i = 0; i < q; i++) {

		int a = 0;

		reader(&a);

		used[a] = true;

		int E1 = u[a], E2 = v[a];

		if (dist[E1] == dist[E2]) { cnt += 0; }

		else {

			int a1 = 0; if (dist[E1] < dist[E2])a1 = E2; else a1 = E1;

			if (mark[a1] == 0 && isgood(a1) == false) {

				queue<int>Q; Q.push(a1); cnt++; mark[a1] = 1;

				while (!Q.empty()) {

					int a2 = Q.front(); Q.pop();

					for (int j = 0; j < y[a2].size(); j++) {

						if (mark[y[a2][j].first] == 0 && isgood(y[a2][j].first) == false) {

							mark[y[a2][j].first] = 1; Q.push(y[a2][j].first); cnt++;

						}

					}

				}

			}

		}

		printf("%d\n", cnt);

	}

	return 0;

}

// Optimized solution to the same problem (faster):
#include<bits/stdc++.h>

using namespace std;

int n,m,q,a[1<<18],b[1<<18],c,dist[1<<18],T[1<<18],cnt,U[1<<18];

vector<pair<int, int> >x[110000],y[110000];bool used[210000];

int main(){

	scanf("%d%d%d",&n,&m,&q);

	for(int i=0;i<m;i++){scanf("%d%d",&a[i],&b[i]);x[a[i]].push_back(make_pair(b[i],i));x[b[i]].push_back(make_pair(a[i],i));}

	fill(dist,dist+n+1,-1);dist[1]=0;queue<int>Q;Q.push(1);

	while(!Q.empty()){int a1=Q.front();Q.pop();for(pair<int,int>i:x[a1]){if(dist[i.first]==-1){dist[i.first]=dist[a1]+1;Q.push(i.first);}}}

	for(int i=1;i<=n;i++){for(pair<int,int>j:x[i]){if(dist[i]<dist[j.first]){y[i].push_back(j);T[j.first]++;}}}

	for(int i=0;i<q;i++){

		scanf("%d",&c);c--;queue<pair<int,int> >Q1; int ss=-1;

		if(dist[a[c]]<dist[b[c]])ss=b[c];

		if(dist[a[c]]>dist[b[c]])ss=a[c];

		if(ss>=1&&U[ss]==0&&used[c]==false){

			Q1.push(make_pair(ss,c));

			while(!Q1.empty()){

				int a1=Q1.front().first,a2=Q1.front().second;Q1.pop();

				if(U[a1]==1||used[a2]==true)continue;T[a1]--;used[a2]=true;if(T[a1]!=0)continue;cnt++;U[a1]=1;

				for(pair<int,int>j:y[a1]){if(U[j.first]==0)Q1.push(j);}

			}

		}

		printf("%d\n",cnt);

	}

}

// Fastest known solution for this problem: