// Original C++ solution (slower):
#include <bits/stdc++.h>

using namespace std;

#define ll long long

struct p {

	int x, y;

	int indx;

};

const int N = 1e5 + 5;

p points[N];

int n;

int par[N];

int get(int n) {

	if (par[n] == n) return n;

	return par[n] = get(par[n]);

}

vector<int> g[N];

void solve() {

	for (int i = 0; i < N; i++)

		par[i] = i;

	vector<pair<int, pair<int, int> >> edg;

	for (int i = 0; i < n; i++) {

//		g[i].clear();

//		g[i].resize(n);

		for (int j = 0; j < g[i].size(); j++) {

//			g[i][j] = j;

			int v = g[i][j];

			ll c = min(abs(points[i].x - points[v].x),

					abs(points[i].y - points[v].y));

			edg.push_back(make_pair(c, make_pair(i, v)));

		}

	}

	sort(edg.begin(), edg.end());

	ll ans = 0;

	for (int i = 0; i < edg.size(); i++) {

		int u = edg[i].second.first;

		int v = edg[i].second.second;

		int r1 = get(u);

		int r2 = get(v);

		if (r1 == r2) continue;

		//cout << u << "  " << v << endl;

		ans += edg[i].first;

		par[r1] = r2;

	}

	cout << ans << endl;

}

void gen(vector<pair<int, int> > &a, vector<pair<int, int> > &b) {



	sort(b.begin(), b.end());



	for (int i = 0; i < a.size(); i++) {



		auto it = lower_bound(b.begin(), b.end(), make_pair(a[i].first, -1));

		if (it != b.end()) {

			g[a[i].second].push_back(it->second);

			g[it->second].push_back(a[i].second);

		}

		if (it != b.begin()) {

			it--;



			g[a[i].second].push_back(it->second);

			g[it->second].push_back(a[i].second);

		}

	}

}

int main() {

	ios_base::sync_with_stdio(0);

	cin.tie(0);

	cin >> n;

	vector<pair<int, pair<int, int> > > v;

	for (int i = 0; i < n; i++) {

		cin >> points[i].x >> points[i].y;

		points[i].indx = i;

		v.push_back(make_pair(points[i].x, make_pair(points[i].y, i)));

	}

	sort(v.begin(), v.end());

	vector<pair<int, int> > last, cur;

	for (int i = 0; i < n;) {

		int X = v[i].first;

		while (i < n && v[i].first == X) {

			cur.push_back(v[i].second);

			i++;

		}

		if (last.size()) gen(last, cur);

		last = cur;

		cur.clear();

	}

	for (int i = 0; i + 1 < n; i++) {

		int u = v[i].second.second;

		int V = v[i + 1].second.second;

		g[u].push_back(V);

		g[V].push_back(u);

	}

	for (int i = 0; i < n; i++)

		swap(v[i].first, v[i].second.first);

	last.clear();

	sort(v.begin(), v.end());

	for (int i = 0; i < n;) {

		int X = v[i].first;



		while (i < n && v[i].first == X) {

			cur.push_back(v[i].second);

			i++;

		}

		if (last.size()) gen(last, cur);

		last = cur;

		cur.clear();

	}

	for (int i = 0; i + 1 < n; i++) {

		int u = v[i].second.second;

		int V = v[i + 1].second.second;

		g[u].push_back(V);

		g[V].push_back(u);

	}



	solve();

	return 0;

}


// Optimized solution to the same problem (faster):
#include <bits/stdc++.h>

using namespace std;



typedef long long ll;

typedef pair<int, int> pii;

typedef pair<int, pii> pipii;

typedef pair<pii, pii> piipii;



#define mp make_pair

#define fi first

#define se second

#define all(a) (a).begin(), (a).end()

#define sz(a) (int)(a).size()

#define eb emplace_back

pii p[100005];

int x[100005], y[100005];

int r[100005];

int root(int a){

    return r[a] == a?a:(r[a]=root(r[a]));

}

void merge(int a, int b){

    a = root(a), b = root(b);

    if(a != b) r[a] = b;

}

int main(){

    int n;

    scanf("%d", &n);   

    for(int i=1;i<=n;i++){

        scanf("%d%d", &x[i], &y[i]);

        p[i] = pii(x[i], i);

        r[i] = i;

    }

    sort(p+1, p+1+n);

    vector<pipii> edges;

    for(int i=2;i<=n;i++) edges.eb(pipii(p[i].fi-p[i-1].fi, pii(p[i].se, p[i-1].se)));

    sort(all(edges));

    for(int i=1;i<=n;i++) p[i] = pii(y[i], i);

    sort(p+1, p+1+n);

    for(int i=2;i<=n;i++) edges.eb(pipii(p[i].fi-p[i-1].fi, pii(p[i].se, p[i-1].se)));

    sort(all(edges));

    int ans = 0;

    for(int i=0;i<sz(edges);i++){

        if(root(edges[i].se.fi) != root(edges[i].se.se)){

            merge(edges[i].se.fi, edges[i].se.se);

            ans += edges[i].fi;

        }

    }

    printf("%d\n", ans);

}

// Fastest known solution for this problem: