// Original C++ solution (slower):
#include <iostream>

#include <cstdio>

#include <cstdlib>

#include <algorithm>

#include <cstring>

#include <queue>

using namespace std;

int r,c,n;

int ans;

char map[1005][1005];

bool book[1005][1005];

int dir[4][2]={{-1,0},{0,-1},{0,1},{1,0}};

struct point

{

    int x,y;

    int step;

}p[11],now,last;

bool check(int x,int y)

{

    if(x<0||x>=r||y<0||y>=c)

        return 0;

    return 1;

}

void bfs(int st)

{

    p[st].step=0;

    queue<point> q;

    now=p[st];

    q.push(now);

    book[now.x][now.y]=1;

    while(!q.empty())

    {

        now=q.front();

        q.pop();

        for(int i=0;i<4;i++)

        {

            last.x=now.x+dir[i][0];

            last.y=now.y+dir[i][1];

            last.step=now.step+1;

            if(!check(last.x,last.y))    continue;

            if(map[last.x][last.y]=='X'|| book[last.x][last.y]==1)    continue;

            if(last.x==p[st+1].x && last.y==p[st+1].y)

            {

                ans+=last.step;

                return;

            }

            book[last.x][last.y]=1;

            q.push(last);

        }

    }

}

int main()

{

    while(~scanf("%d%d%d",&r,&c,&n))

    {

        for(int i=0;i<r;i++)

        {

            getchar();

            for(int j=0;j<c;j++)

            {

                scanf("%c",&map[i][j]);

                if(map[i][j]=='S')

                {

                    p[0].x=i;

                    p[0].y=j;

                }

                if(map[i][j]!='S'&&map[i][j]!='X'&&map[i][j]!='.')

                {

                    p[map[i][j]-'0'].x=i;

                    p[map[i][j]-'0'].y=j;

                }

            }

        }

        ans=0;

        for(int i=0;i<n;i++)

        {

            memset(book,0,sizeof(book));

            bfs(i);

        }

        cout<<ans<<endl;

    }

    //system("pause");

    return 0;

}


// Optimized solution to the same problem (faster):
#include <iostream>

#include <queue>

using namespace std;

const int INF = 100000000;

typedef pair<int,int> Point;

Point AllPoint[1000];

int W,H;

int x[4] = {0,1,0,-1};

int y[4] = {1,0,-1,0};

char map[1000][1000];

int deep[1000][1000];

int N;

void BFS(Point Start,Point Over){

    queue<Point> que;

    int FirstDeep = deep[Start.first][Start.second];

    for (int i = 0;i<H;i++){

        for (int j = 0;j<W;j++){

            deep[i][j] = INF;

        }

    }

    que.push(Start);

    deep[Start.first][Start.second] = FirstDeep;

    while (que.size()){

        Point p = que.front();

        que.pop();

        if (p.first== Over.first&&p.second == Over.second)

            break;

        for (int i = 0;i<4;i++){

            int ix = p.first+x[i];

            int iy = p.second+y[i];

            if (ix>=0&&ix<=H

                &&iy>=0&&iy<=W

                &&deep[ix][iy] == INF

                &&map[ix][iy]!='X'){

                que.push(Point(ix,iy));

                deep[ix][iy] = deep[p.first][p.second]+1;

            }

        }

    }

}







int main(){

    cin >> H >> W;

    cin >> N;

    for (int i = 0;i<H;i++){

        for (int j = 0;j<W;j++){

            cin >> map[i][j];

            if ((int)map[i][j]-48>=1&&(int)map[i][j]-48<=N){

                AllPoint[(int)map[i][j]-48].first = i;

                AllPoint[(int)map[i][j]-48].second = j;



            }

            if (map[i][j] == 'S'){

                AllPoint[0].first = i;

                AllPoint[0].second = j;

            }

        }

    }

    deep[AllPoint[0].first][AllPoint[0].second] = 0;

    for (int i = 0;i<N;i++){

        BFS(AllPoint[i],AllPoint[i+1]);

    }

    cout << deep[AllPoint[N].first][AllPoint[N].second]<<endl;



    return 0;

}

//#....

//S.##.

//###G.

//#####

//#####



//#S######.#

//......#..#

//.#.##.##.#

//.#........

//##.##.####

//....#....#

//.#######.#

//....#.....

//.####.###.

//....#...G#






// Fastest known solution for this problem: