// Original C++ solution (slower):
#include <vector>

#include <iostream>

#include <cmath>

#include <map>

#include <unordered_map>

#include <algorithm>

#include <fstream>

#include <unistd.h>

#include <string>

#include <numeric>

#include <queue>

#include <deque>

#include <sstream>

#include <iomanip>

#include <set>

#include <stack>

#include <cassert>

using namespace std;

typedef long long ll;

typedef vector<int> vi;

typedef vector<ll> vl;

typedef vector<vl> vvl;

typedef vector<vvl> vvvl;

typedef vector<vi> vvi;

typedef vector<vvi> vvvi;

typedef vector<bool> vb;

typedef vector<vector<bool>> vvb;

typedef vector<string> vs;

typedef vector<vector<string>> vvs;

typedef vector<char> vc;

typedef vector<vector<char>> vvc;

typedef vector<double> vd;

typedef vector<vd> vvd;

typedef vector<vvd> vvvd;

typedef pair<int, int> P;

typedef pair<ll, ll> PL;

typedef vector<P> vp;

typedef vector<PL> vpl;

typedef vector<vector<P>> vvp;

typedef vector<vector<PL>> vvpl;

const int INF = 1001001001;

const ll LINF = 1e18;

const double pi = 3.1415926535897932;

const string endstr = "\n";

#define FOR(i, a, b) for(ll i = (a); i < b; i++)

#define REP(i, n) for(ll i = 0; i < n; i++)

#define FORMAP(it, m) for(auto it = m.begin(); it != m.end(); it++)

#define ff first

#define ss second

#define pb push_back



template <typename T>

T gcd(T a, T b) {

    return (a == 0) ? b : gcd(b%a, a);

}

template <typename T>

T lcm(T a, T b) {

    return a / gcd(a, b) * b;

}



bool p_comp_fs(const PL p1, const PL p2){ return p1.first < p2.first;};

bool p_comp_fg(const PL p1, const PL p2){ return p1.first > p2.first;};

bool p_comp_ss(const PL p1, const PL p2){ return p1.second < p2.second;};

bool p_comp_sg(const PL p1, const PL p2){ return p1.second > p2.second;};

template <typename T>

vector<T> uniquen(vector<T> vec){

    vec.erase(unique(vec.begin(), vec.end()), vec.end());

    return vec;

}



ll sum[410];

ll dp[410][410];



ll cost(ll l, ll r){

    if(l+1 == r) return 0;

    if(dp[l][r] != -1) return dp[l][r];

    

    ll ans = LINF;

    FOR(c, l+1, r){

        ans = min(ans, cost(l, c) + cost(c, r) + sum[r] - sum[l]);

    }

    return (dp[l][r] = ans);

}



int main(){

    ll N; cin >> N;

    vl a(N); REP(i, N) cin >> a[i];

    REP(i, N) sum[i+1] = sum[i] + a[i];

    REP(i, 410) REP(j, 410) dp[i][j] = -1;

    

    cout << cost(0, N) << endl;

    return 0;

}


// Optimized solution to the same problem (faster):
#include <vector>

#include <iostream>

#include <cmath>

#include <map>

#include <unordered_map>

#include <algorithm>

#include <fstream>

#include <unistd.h>

#include <string>

#include <numeric>

#include <queue>

#include <deque>

#include <sstream>

#include <iomanip>

#include <set>

#include <stack>

#include <cassert>

using namespace std;

typedef long long ll;

typedef vector<int> vi;

typedef vector<ll> vl;

typedef vector<vl> vvl;

typedef vector<vvl> vvvl;

typedef vector<vi> vvi;

typedef vector<vvi> vvvi;

typedef vector<bool> vb;

typedef vector<vector<bool>> vvb;

typedef vector<string> vs;

typedef vector<vector<string>> vvs;

typedef vector<char> vc;

typedef vector<vector<char>> vvc;

typedef vector<double> vd;

typedef vector<vd> vvd;

typedef vector<vvd> vvvd;

typedef pair<int, int> P;

typedef pair<ll, ll> PL;

typedef vector<P> vp;

typedef vector<PL> vpl;

typedef vector<vector<P>> vvp;

typedef vector<vector<PL>> vvpl;

const int INF = 1001001001;

const ll LINF = 1e16;

const double pi = 3.1415926535897932;

const string endstr = "\n";

#define FOR(i, a, b) for(ll i = (a); i < b; i++)

#define REP(i, n) for(ll i = 0; i < n; i++)

#define FORMAP(it, m) for(auto it = m.begin(); it != m.end(); it++)

#define ff first

#define ss second

#define pb push_back



template <typename T>

T gcd(T a, T b) {

    return (a == 0) ? b : gcd(b%a, a);

}

template <typename T>

T lcm(T a, T b) {

    return a / gcd(a, b) * b;

}



bool p_comp_fs(const PL p1, const PL p2){ return p1.first < p2.first;};

bool p_comp_fg(const PL p1, const PL p2){ return p1.first > p2.first;};

bool p_comp_ss(const PL p1, const PL p2){ return p1.second < p2.second;};

bool p_comp_sg(const PL p1, const PL p2){ return p1.second > p2.second;};

template <typename T>

vector<T> uniquen(vector<T> vec){

    vec.erase(unique(vec.begin(), vec.end()), vec.end());

    return vec;

}





int main(){

    ll N; cin >> N;

    vl a(N); REP(i, N) cin >> a[i];

    vl sum(N+1, 0); REP(i, N) sum[i+1] = sum[i] + a[i];

    

    vvl dp(N+1, vl(N+1, LINF));

    REP(i, N) dp[i][i+1] = a[i];

    

    FOR(len, 2, N+1){

        REP(l, N-len+1){

            ll r = l+len;

            FOR(c,l,r) dp[l][r] = min(dp[l][r], dp[l][c] + dp[c][r]);

            dp[l][r] += sum[r] - sum[l];

        }

    }

    cout << dp[0][N] - sum[N] << endl;

    return 0;

    return 0;

}


// Fastest known solution for this problem: