// Original C++ solution (slower):
#include <cstdio>

#include <cstring>

#include <algorithm>

#include <cmath>

#include <climits>

#include <queue>

using namespace std;

const int N=1000;

char maze[N][N];

int h,w,n;

int sx,sy,gx,gy;

int dir[4][2]={1,0,-1,0,0,1,0,-1};

int d[N][N];

const int INF=INT_MAX;

int ans;

struct node

{

    node(int xx=0,int yy=0,int tt=0,char ss=0):x(xx),y(yy),t(tt),s(ss){}

    int x;

    int y;

    int t;

    char s;

};

bool read()

{

    memset(maze,0,sizeof(maze));

    scanf("%d%d%d",&h,&w,&n);

    getchar();

    for(int i=0;i<h;i++)

    {

        for(int j=0;j<w;j++)

        {

            scanf("%c",&maze[i][j]);

            if(maze[i][j]=='S') sx=j,sy=i;

            if(maze[i][j]=='0'+n) gy=i,gx=j;

        }

        getchar();

    }

    for(int i=0;i<h;i++)

       for(int j=0;j<w;j++) d[i][j]=INF;

    return 1;

}

void show()

{

    //printf("h:%d w:%d\n",h,w);

    //printf("maze[%d][%d]=%d\n",0,2,maze[0][2]);

    for(int i=0;i<h;i++)

    {

        for(int j=0;j<w;j++)

        {

            if(d[i][j]!=INF) printf("%d ",d[i][j]);

            else printf("- ");

        }

        printf("\n");

    }

    //printf("sy:%d sx:%d\n",sy,sx);

}

void init(int h,int w)

{

    for(int i=0;i<h;i++)

        for(int j=0;j<w;j++) d[i][j]=INF;

}

int bfs()

{

   queue<node> que;

   que.push(node(sx,sy,0,'1'));

   d[sy][sx]=0;

   while(!que.empty())

   {



       node t=que.front();que.pop();

       //printf("%c\n",t.s);

       for(int i=0;i<4;i++)

       {

           int nx=t.x+dir[i][0];

           int ny=t.y+dir[i][1];

           if(0<=nx&&nx<w&&0<=ny&&ny<h&&d[ny][nx]==INF&&maze[ny][nx]!='X'/*(maze[ny][nx]=='.'||maze[ny][nx]==t.s)*/)

           {

               if(maze[ny][nx]=='0'+n&&maze[ny][nx]==t.s)

               {

                   //printf("%c in return",maze[ny][nx]);

                   return ans+=d[t.y][t.x]+1;

               }

               if(maze[ny][nx]==t.s)

               {

                   //printf("%c d\n",maze[ny][nx]);

                   maze[ny][nx]='.';

                    d[ny][nx]=d[t.y][t.x]+1;

                    ans+=d[ny][nx];

                    //show();

                    while(!que.empty()) que.pop();

                    init(h,w);

                    d[ny][nx]=0;

                   que.push(node(nx,ny,0,t.s+1));

                   break;

               }

               else

               {

                   que.push(node(nx,ny,0,t.s));

                    d[ny][nx]=d[t.y][t.x]+1;

               }

           }

       }

       //int size=que.size();

        //printf("size:%d\n",size);

   }

   return 1/*d[gy][gx]*/;

}

int main()

{

    while(~scanf("%d%d%d",&h,&w,&n))

    {

        getchar();

        memset(maze,0,sizeof(maze));

        ans=0;

        for(int i=0;i<h;i++)

        {

            for(int j=0;j<w;j++)

            {

                scanf("%c",&maze[i][j]);

                if(maze[i][j]=='S') sx=j,sy=i;

                if(maze[i][j]=='0'+n) gy=i,gx=j;

            }

            getchar();

        }

        for(int i=0;i<h;i++)

            for(int j=0;j<w;j++) d[i][j]=INF;

        bfs();

        printf("%d\n",ans);

    }

    return 0;

}

// Optimized solution to the same problem (faster):
#include <cstdio>

#include <cstring>

#include <queue>

#include <cctype>



using namespace std;



struct State {

    int step;

    int x;

    int y;



    State() {

        step = 0;

        x = 0;

        y = 0;

    }



    State(int step, int x, int y): step(step), x(x), y(y) {}

};



const int MAX_N = 1000;

const int dir[4][2] = {{0, 1}, {0, -1}, {1, 0}, { -1, 0}};

char board[MAX_N][MAX_N];

int W, H, N;

State pos[10];



void init();

void input();

void solve();

int bfs(State from, State to);

void findPossition();



int main() {

#ifdef LOCAL

    freopen("data.in", "r", stdin);

    freopen("data.out", "w", stdout);

#endif

    init();

    input();

    solve();

    return 0;

}



void init() {

}



void input() {

    scanf("%d %d %d", &H, &W, &N);



    for(int i = 0; i < H; i++) {

        scanf("%s", board[i]);

    }

}





void solve() {

    int moves = 0;

    findPossition();



    for(int i = 0; i < N; i++) {

        moves += bfs(pos[i], pos[i + 1]);

    }



    printf("%d\n", moves);

}



int bfs(State from, State to) {

    queue<State> que;

    bool visit[H][W];

    State cur = from;



    for(int i = 0; i < H; i++) {

        memset(visit[i], false, sizeof(visit[i]));

    }



    que.push(cur);



    while(!que.empty()) {

        cur = que.front();

        que.pop();



        if(visit[cur.x][cur.y]) {

            continue;

        }

        

        visit[cur.x][cur.y] = true;



        if(cur.x == to.x && cur.y == to.y) {

            break;

        }



        for(int i = 0; i < 4; i++) {

            int x = cur.x + dir[i][0];

            int y = cur.y + dir[i][1];



            if(x < 0 || x >= H || y < 0 || y >= W || visit[x][y] || 'X' == board[x][y]) {

                continue;

            }



            que.push(State(cur.step + 1, x, y));

        }

    }



    return cur.step;

}



void findPossition() {

    for(int i = 0; i < H; i++) {

        for(int j = 0; j < W; j++) {

            int c = board[i][j];



            if('S' == c) {

                pos[0] = State(0, i, j);

            }



            if(isdigit(c)) {

                pos[c - '0'] = State(0, i, j);

            }

        }

    }

}

// Fastest known solution for this problem: