// Original C++ solution (slower):
#include <iostream>

#include <queue>

#include <string>

using namespace std;

int main()

{

	int h,w,n;

	int sx,sy;

	int dx[4] = {1,0,-1,0},dy[4] = {0,1,0,-1};

	string map[1001];

	int d[1001][1001];

	int x = 0;

	cin >> h >> w >> n;

	for(int i=0;i < h;i++)

	{

		cin >> map[i];

	}

	for(int i=0;i < h;i++)

	{

		for(int j=0;j < w;j++)

		{

			d[j][i] = -1;

			if(map[i][j] == 'S')

			{

				sx = j;

				sy = i;

			}

		}

	}

	d[sx][sy] = 0;

	for(int i=0;i<9;i++)

	{

		queue< pair<int, int> > que;

		for(int j=0;j < h;j++)

		{

			for(int k=0;k < w;k++)

			{

				d[k][j] = -1;

			}

		}

		d[sx][sy] = 0;

		que.push(make_pair(sx,sy));

		while(que.size())

		{

			pair<int, int> p = que.front();

			que.pop();

			if((map[p.second][p.first] - '0') == (i+1))

			{

				sx = p.first;

				sy = p.second;

				x+=d[sx][sy];

				break;

			}

			for(int j=0;j < 4;j++)

			{

				int nx = p.first + dx[j];

				int ny = p.second + dy[j];

				if(0 <= nx && nx < w && 0 <= ny && ny < h && map[ny][nx] != 'X' && d[nx][ny] == -1)

				{

					que.push(make_pair(nx,ny));

					d[nx][ny] = d[p.first][p.second] + 1;

				}

			}

		}

	}

	cout << x << endl;

}

// Optimized solution to the same problem (faster):
#include <cstdio>

#include <cstring>

#include <queue>

#include <cctype>



using namespace std;



struct State {

    int step;

    int x;

    int y;



    State() {

        step = 0;

        x = 0;

        y = 0;

    }



    State(int step, int x, int y): step(step), x(x), y(y) {}

};



const int MAX_N = 1000;

const int dir[4][2] = {{0, 1}, {0, -1}, {1, 0}, { -1, 0}};

char board[MAX_N][MAX_N];

int W, H, N;

State pos[10];



void init();

void input();

void solve();

int bfs(State from, State to);

void findPossition();



int main() {

#ifdef LOCAL

    freopen("data.in", "r", stdin);

    freopen("data.out", "w", stdout);

#endif

    init();

    input();

    solve();

    return 0;

}



void init() {

}



void input() {

    scanf("%d %d %d", &H, &W, &N);



    for(int i = 0; i < H; i++) {

        scanf("%s", board[i]);

    }

}





void solve() {

    int moves = 0;

    findPossition();



    for(int i = 0; i < N; i++) {

        moves += bfs(pos[i], pos[i + 1]);

    }



    printf("%d\n", moves);

}



int bfs(State from, State to) {

    queue<State> que;

    bool visit[H][W];

    State cur = from;



    for(int i = 0; i < H; i++) {

        memset(visit[i], false, sizeof(visit[i]));

    }



    que.push(cur);



    while(!que.empty()) {

        cur = que.front();

        que.pop();



        if(visit[cur.x][cur.y]) {

            continue;

        }

        

        visit[cur.x][cur.y] = true;



        if(cur.x == to.x && cur.y == to.y) {

            break;

        }



        for(int i = 0; i < 4; i++) {

            int x = cur.x + dir[i][0];

            int y = cur.y + dir[i][1];



            if(x < 0 || x >= H || y < 0 || y >= W || visit[x][y] || 'X' == board[x][y]) {

                continue;

            }



            que.push(State(cur.step + 1, x, y));

        }

    }



    return cur.step;

}



void findPossition() {

    for(int i = 0; i < H; i++) {

        for(int j = 0; j < W; j++) {

            int c = board[i][j];



            if('S' == c) {

                pos[0] = State(0, i, j);

            }



            if(isdigit(c)) {

                pos[c - '0'] = State(0, i, j);

            }

        }

    }

}

// Fastest known solution for this problem: