// Original C++ solution (slower):
#include <bits/stdc++.h>

using namespace std;



#define ENGZ ios::sync_with_stdio(0);cin.tie(0);ios_base::sync_with_stdio(0);

#define sfi(x) scanf("%d" , &x)

#define sfi2(x, y) scanf("%d%d" , &x,&y)

#define sfl2(x, y) scanf("%I64d%I64d" , &x,&y)

#define sfl(x) scanf("%I64d" , &x)

#define sfl3(x, y, z) scanf("%I64d%I64d%I64d", &x, &y, &z)

#define sfd(x) scanf("%lf", &x)

#define sfd2(x, y) scanf("%lf", &x, &y)

#define sfs(x) scanf("%s", &x)

#define testv(x) cerr << x << ' '

#define wtf(s) freopen((s), "w", stdout)

#define rff(s) freopen((s), "r", stdin)

#define test cerr << "here"

#define fst(x) cout << fixed << setprecision(x)

#define mod 1000000007

#define pi (2 * acos(0))

typedef long double ld;

typedef long long ll;



int par[200005], rnk[200005];



int findp(int x)

{

    if (par[x] == x)

        return x;

    return par[x] = findp(par[x]);

}



bool iscon(int x, int y)

{

    if (findp(x) == findp(y))

        return true;

    return false;

}



void con(int x, int y)

{

    int px = findp(x), py = findp(y);

    if (rnk[px] > rnk[py])

        par[py] = px;

    else if (rnk[px] < rnk[py])

        par[px] = py;

    else

        par[px] = py, rnk[px]++;

}





    pair<pair<ll, ll>, int> a[100005], b[100005];

int main()

{

    ENGZ

    int n;

    ll ans = 0;

    for (int i = 0; i < 100005; i++)

        par[i] = i;

    cin >> n;

    for (int i = 0; i < n; i++)

    {

        cin >> a[i].first.first >> a[i].first.second;

        b[i].first.first = a[i].first.second;

        b[i].first.second = a[i].first.first;

        a[i].second = b[i].second = i;

    }

    sort(a, a + n);

    sort(b, b + n);

    map<ll, vector<pair<int, int>>> mp;

    for (int i = 0; i < n - 1; i++)

    {

        mp[abs(a[i].first.first - a[i + 1].first.first)].push_back({a[i].second, a[i + 1].second});

        mp[abs(b[i].first.first - b[i + 1].first.first)].push_back({b[i].second, b[i + 1].second});

    }

    for (auto it: mp)

    {

        for (auto i: it.second)

        {

            if (!iscon(i.first, i.second))

                con(i.first, i.second), ans += it.first;

        }

    }

    cout << ans;

    return 0;

}

// Optimized solution to the same problem (faster):
#include <bits/stdc++.h>

using namespace std;



typedef long long ll;

typedef pair<int, int> pii;

typedef pair<int, pii> pipii;

typedef pair<pii, pii> piipii;



#define mp make_pair

#define fi first

#define se second

#define all(a) (a).begin(), (a).end()

#define sz(a) (int)(a).size()

#define eb emplace_back

pii p[100005];

int x[100005], y[100005];

int r[100005];

int root(int a){

    return r[a] == a?a:(r[a]=root(r[a]));

}

void merge(int a, int b){

    a = root(a), b = root(b);

    if(a != b) r[a] = b;

}

int main(){

    int n;

    scanf("%d", &n);   

    for(int i=1;i<=n;i++){

        scanf("%d%d", &x[i], &y[i]);

        p[i] = pii(x[i], i);

        r[i] = i;

    }

    sort(p+1, p+1+n);

    vector<pipii> edges;

    for(int i=2;i<=n;i++) edges.eb(pipii(p[i].fi-p[i-1].fi, pii(p[i].se, p[i-1].se)));

    sort(all(edges));

    for(int i=1;i<=n;i++) p[i] = pii(y[i], i);

    sort(p+1, p+1+n);

    for(int i=2;i<=n;i++) edges.eb(pipii(p[i].fi-p[i-1].fi, pii(p[i].se, p[i-1].se)));

    sort(all(edges));

    int ans = 0;

    for(int i=0;i<sz(edges);i++){

        if(root(edges[i].se.fi) != root(edges[i].se.se)){

            merge(edges[i].se.fi, edges[i].se.se);

            ans += edges[i].fi;

        }

    }

    printf("%d\n", ans);

}

// Fastest known solution for this problem: