// Original C++ solution (slower):
#include <bits/stdc++.h>



using namespace std;



#define l long long

#define ul unsigned long long

#define ui unsigned int

#define PI  3.141592653589793238462643383279502884

#define f(i0,n0) for(long long i0 = 0; i0 < n0; ++i0)

#define f1(i1,n1) for(long long i1 = 1; i1 <= n1; ++i1)

#define finv(i2,n2) for(long long i2=n2;i2>0;--i2)

#define sq(a) (a)*(a)

#define endl "\n"

#define FASTIO ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);







/*Function to left Rotate arr[] of

  size n by 1*/

void leftRotatebyOne(char arr[], int n){

    int temp = arr[0], i;

    for (i = 0; i < n - 1; i++)

        arr[i] = arr[i + 1];



    arr[i] = temp;

}



void reverseArray(char arr[], int start, int end){

    while (start < end)

    {

        std::swap(arr[start], arr[end]);

        start++;

        end--;

    }

}



// Function to right rotate arr[] of size n by d

void rightRotate(char arr[], int d){

    int n=26;

    reverseArray(arr, 0, n-1);

    reverseArray(arr, 0, d-1);

    reverseArray(arr, d, n-1);

}

//Function to left rotate arr[] of size n by d

void leftRotate(char arr[], int d){

    int n=26;

    for (int i = 0; i < d; i++)

        leftRotatebyOne(arr, n);

}

bool isPowerOfTwo(auto n){

   if(n==0)

   return false;



   return (ceil(log2(n)) == floor(log2(n)));

}

bool isprime(auto n) {

    if(n<=1)return false;

    if(n<=3) return true;

    if(n%2==0||n%3==0) return false;

    for(l i=5;i*i<=n;i=i+6) if(n%i==0||n%(i+2)==0) return false;

    return true;

}

bool isVowel(char ch){

    if(ch=='a'||ch=='e'||ch=='i'||ch=='o'|| ch=='u' || ch=='y' || ch=='Y' || ch=='A'||ch=='E'||ch=='I'||ch=='O'|| ch=='U')return true;

    else return false;

}

l fast_power(auto x, auto y){



    if (y == 0)

        return 1;

    l temp = fast_power(x, y / 2) ;

    temp = sq(temp);

    if (y&1)

        temp = (temp*x);

    return temp;



}



void merge(int *a, int s, int e){

    int mid=(s+e)/2;



    int i=s, j=mid+1, k=s;



    int temp[1000];



    //sorting

    while(i<=mid && j<=e)

    {

        if(a[i]<a[j])temp[k++]=a[i++];

        else temp[k++]=a[j++];

    }



    //copying the rest

    while(i<=mid)

    {

        temp[k++]=a[i++];

    }

    while(j<=e)

    {

        temp[k++]=a[j++];

    }



    //copy all the elements in the original array

    for(int i=s;i<=e;i++) a[i]=temp[i];



}

void mergeSort(int a[], int s, int e){

    //base case:

    if(s>=e)return;



    //follow 3 steps:



    //1. divide

    int mid=(s+e)/2;



    //2.recursively sort the arrays

    mergeSort(a,s,mid);

    mergeSort(a,mid+1,e);





    //3.merge the 2 parts

    merge(a,s,e);

}



/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////



//Poker Cards transformer:

int CardToRank(char card){



    switch(card)

    {

        case 'T' :

            return 10;

        case 'J':

            return 11;

        case 'Q':

            return 12;

        case 'K':

            return 13;

        default :

            return card-48;

    }

}







int main()

{



    FASTIO

    #ifdef LOCAL

        freopen("input.txt", "r", stdin);

    #endif



    int n;

    cin>>n;

    string in;

    int arr[4]={};



    f(i,n)

    {

        cin>>in;

        if(in=="AC")

            ++arr[0];



        else if(in=="WA")

            ++arr[1];



        else if(in=="TLE")

            ++arr[2];



        else if(in=="RE")

            ++arr[3];

    }



    cout<<"AC x "<<arr[0]<<endl;

    cout<<"WA x "<<arr[1]<<endl;

    cout<<"TLE x "<<arr[2]<<endl;

    cout<<"RE x "<<arr[3];





    return 0;

}


// Optimized solution to the same problem (faster):
#include <stdio.h>



int main() {

    long int t, ac = 0, wa = 0, tle = 0, re = 0;

    scanf("%ld", &t);

    for (int i = 0; i < t; i++) {

        char temp[4];

        scanf("%s", &temp);

        switch (temp[0]) {

            case 'A':

                ac++;

                break;

            case 'W':

                wa++;

                break;

            case 'T':

                tle++;

                break;

            case 'R':

                re++;

                break;

        }

    }

    printf("AC x %d\nWA x %d\nTLE x %d\nRE x %d", ac, wa, tle, re);

}

// Fastest known solution for this problem: