Please read the following table in Markdown format and then answer the question according to the table. Table cells in one row are seperated by '|', and different rows are seperated by '
'.

Table:
| Suburb | Population (in 2008) | Median age (in 2006) | Mean household size (in 2006) | Area (km²) | Density (/km²) | Date first settled as a suburb | Gazetted as a Division Name |
| --- | --- | --- | --- | --- | --- | --- | --- |
| Chifley | 2325.0 | 36 years | 2.3 persons | 1.6 | 1453.0 | 1966.0 | 12 May 1966 |
| Curtin | 5133.0 | 41 years | 2.5 persons | 4.8 | 1069.0 | 1962.0 | 20 September 1962 |
| Farrer | 3360.0 | 41 years | 2.7 persons | 2.1 | 1600.0 | 1967.0 | 12 May 1966 |
| Garran | 3175.0 | 39 years | 2.5 persons | 2.7 | 1175.0 | 1966.0 | 12 May 1966 |
| Hughes | 2898.0 | 41 years | 2.5 persons | 1.8 | 1610.0 | 1963.0 | 20 September 1962 |
| Isaacs | 2424.0 | 45 years | 2.6 persons | 3.1 | 781.0 | 1986.0 | 12 May 1966 |
| Lyons | 2444.0 | 38 years | 2.1 persons | 2.3 | 1062.0 | 1965.0 | 20 September 1962 |
| Mawson | 2861.0 | 40 years | 2.2 persons | 2.1 | 1362.0 | 1967.0 | 12 May 1966 |
| O'Malley | 684.0 | 47 years | 3.1 persons | 2.6 | 263.0 | 1973.0 | 12 May 1966 |
| Pearce | 2509.0 | 41 years | 2.3 persons | 1.7 | 1475.0 | 1967.0 | 12 May 1966 |
| Phillip | 1910.0 | 32 years | 1.7 persons | 2.6 | 734.0 | 1966.0 | 12 May 1966 |
Question:
What is the median age where the area is 1.7?
Answer:
41 years