Please read the following table in Markdown format and then answer the question according to the table. Table cells in one row are seperated by '|', and different rows are seperated by '
'.

Table:
| Name | Alt name | Launch date | ID | Mass (kg) | Decay date | Perigee (km) | Apogee (km) | Inclination |
| --- | --- | --- | --- | --- | --- | --- | --- | --- |
| SAMOS F2-1 | 1962 Delta 1 | 1962-02-21 | 1962-004A | 1000.0 | 1962-03-09 | 169.0 | 220.0 | 81.9 |
| SAMOS F2-2 | 1962 Omega 1 | 1962-06-18 | 1962-024A | 1500.0 | 1963-10-30 | 370.0 | 394.0 | 82.1 |
| SAMOS F2-3 | OPS-0180 | 1963-01-16 | 1963-003A | 1100.0 | 1969-01-09 | 459.0 | 533.0 | 81.8 |
| SAMOS F2-4 | OPS-1440 | 1963-06-29 | 1963-027A | 1500.0 | 1969-10-26 | 485.0 | 521.0 | 82.3 |
| SAMOS F3-1 | OPS-3722 | 1964-02-28 | 1964-011A | 1500.0 | 1969-02-19 | 493.0 | 509.0 | 82 |
| SAMOS F3-2 | OPS-3395 | 1964-07-02 | 1964-035A | 1500.0 | 1969-08-07 | 494.0 | 530.0 | 82 |
| SAMOS F3-3 | OPS-3062 | 1964-11-04 | 1964-072A | 1500.0 | 1969-11-05 | 507.0 | 526.0 | 82 |
| SAMOS F3-4 | OPS-8411 | 1965-07-17 | 1965-055A | 1500.0 | 1968-12-18 | 469.0 | 511.0 | 70.1 |
| SAMOS F3-5 | OPS-1439 | 1966-02-09 | 1966-009A | 1500.0 | 1969-09-26 | 499.0 | 504.0 | 82 |
| SAMOS F3-6 | OPS-1584 | 1966-12-29 | 1966-118A | 1500.0 | 1969-04-05 | 484.0 | 492.0 | 75 |
| SAMOS F3-7 | OPS-1879 | 1967-07-25 | 1967-071A | 1500.0 | 1969-06-05 | 454.0 | 512.0 | 75 |
| SAMOS F3-8 | OPS-1965 | 1968-01-17 | 1968-004A | 1500.0 | 1970-07-07 | 455.0 | 534.0 | 75.1 |
| SAMOS F3-9 | OPS-0964 | 1968-10-05 | 1968-086A | 2000.0 | 1971-03-26 | 481.0 | 506.0 | 75 |
| SAMOS F3-10 | OPS-8285 | 1969-07-31 | 1969-065A | 1500.0 | 1973-01-04 | 459.0 | 538.0 | 75 |
| SAMOS F3-11 | OPS-8329 | 1970-08-26 | 1970-066A | 2000.0 | 1975-03-26 | 482.0 | 500.0 | 74.9 |
Question:
What is the inclination when the alt name is OPS-1584?
Answer:
75.0